Search Results

Search found 2556 results on 103 pages for 'sleep deprivation ninja'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 50/103 | < Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >

  • asp.net mvc 2 multithread

    - by Chris Cap
    I'm getting some weird behavior in asp.net MVC2 (at least it's not what I'm expecting). I have a controller httppost action that processes credit cards. I'm setting a session variable on the server to let me know if a user has attempted to process a card. I clear that session variable when I'm done. I am doing some very quick posts to test the process and the session variable is coming back null everytime because I clear the session variable at the end of the process. I have some debug prints that show me that the all requests are processed synchronously. That is...the first attempt occurs, it fails, session variable is cleared, second attempt tries and fails and the variable is cleared, etc... My first thought was that this was a side effect of debugging and that it just lined requests up for debugging purposes using the local webserver. So I put it on a development server and the same thing is occurring. Multiple submits/posts are processed synchronously. I even put a System.Threading.Sleep in there to make sure it would stop right after I set the session variable and it still won't even START the second request until the first is done. Has anyone else seen this behavior? My understanding was that a worker process was spawned for each request and that these actions could happen asychronously. Here's some psuedo code if (Session["CardCharged"] != null) return RedirectToAction("Index", "Problem"); Session["CardCharged"] = false; //starting the process System.Threading.Thread.Sleep(10000); //charge card here if (!providerResponse.IsApproved) { System.Diagnostics.Debug.WriteLine("failed"); Session["CardCharged"] = null; //have to allow them to charge again since this failed return View(myModel); } Session["CardCharged"] = true; return RedirectToAction("Index", "OrderComplete"); I should mention that my code ALWAYS fails the credit card check for testing purposes. I'm trying to test the situation where processing is STILL occurring and redirect the user elsewhere. I have set a dummy session variable elsewhere to assure that the session id "sticks". So I know the session id is the same for each request. Thanks

    Read the article

  • sigwait in Linux (Fedora 13) vs OS X

    - by Silas
    So I'm trying to create a signal handler using pthreads which works on both OS X and Linux. The code below works on OS X but doesn't work on Fedora 13. The application is fairly simple. It spawns a pthread, registers SIGHUP and waits for a signal. After spawning the signal handler I block SIGHUP in the main thread so the signal should only be sent to the signal_handler thread. On OS X this works fine, if I compile, run and send SIGHUP to the process it prints "Got SIGHUP". On Linux it just kills the process (and prints Hangup). If I comment out the signal_handler pthread_create the application doesn't die. I know the application gets to the sigwait and blocks but instead of return the signal code it just kills the application. I ran the test using the following commands: g++ test.cc -lpthread -o test ./test & PID="$!" sleep 1 kill -1 "$PID" test.cc #include <pthread.h> #include <signal.h> #include <iostream> using namespace std; void *signal_handler(void *arg) { int sig; sigset_t set; sigemptyset(&set); sigaddset(&set, SIGHUP); while (true) { cout << "Wait for signal" << endl; sigwait(&set, &sig); if (sig == SIGHUP) { cout << "Got SIGHUP" << endl; } } } int main() { pthread_t handler; sigset_t set; // Create signal handler pthread_create(&handler, NULL, signal_handler, NULL); // Ignore SIGHUP in main thread sigfillset(&set); sigaddset(&set, SIGHUP); pthread_sigmask(SIG_BLOCK, &set, NULL); for (int i = 1; i < 5; i++) { cout << "Sleeping..." << endl; sleep(1); } pthread_join(handler, NULL); return 0; }

    Read the article

  • How solve consumer/producer task using semaphores

    - by user1074896
    I have SimpleProducerConsumer class that illustrate consumer/producer problem (I am not sure that it's correct). public class SimpleProducerConsumer { private Stack<Object> stack = new Stack<Object>(); private static final int STACK_MAX_SIZE = 10; public static void main(String[] args) { SimpleProducerConsumer pc = new SimpleProducerConsumer(); new Thread(pc.new Producer(), "p1").start(); new Thread(pc.new Producer(), "p2").start(); new Thread(pc.new Consumer(), "c1").start(); new Thread(pc.new Consumer(), "c2").start(); new Thread(pc.new Consumer(), "c3").start(); } public synchronized void push(Object d) { while (stack.size() >= STACK_MAX_SIZE) try { wait(); } catch (InterruptedException e) { e.printStackTrace(); } try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } stack.push(new Object()); System.out.println("push " + Thread.currentThread().getName() + " " + stack.size()); notify(); } public synchronized Object pop() { while (stack.size() == 0) try { wait(); } catch (InterruptedException e) { e.printStackTrace(); } try { Thread.sleep(50); } catch (InterruptedException e) { e.printStackTrace(); } stack.pop(); System.out.println("pop " + Thread.currentThread().getName() + " " + stack.size()); notify(); return null; } class Consumer implements Runnable { @Override public void run() { while (true) { pop(); } } } class Producer implements Runnable { @Override public void run() { while (true) { push(new Object()); } } } } I found simple realization of semaphore(here:http://docs.oracle.com/javase/tutorial/essential/concurrency/guardmeth.html I know that there is concurrency package) How I need to change code to exchange java objects monitors to my custom semaphore. (To illustrate C/P problem using semaphores) Semaphore: class Semaphore { private int counter; public Semaphore() { this(0); } public Semaphore(int i) { if (i < 0) throw new IllegalArgumentException(i + " < 0"); counter = i; } public synchronized void release() { if (counter == 0) { notify(); } counter++; } public synchronized void acquire() throws InterruptedException { while (counter == 0) { wait(); } counter--; } }

    Read the article

  • python interpreter waits for child process to die

    - by Moulik Kallupalam
    Contents of check.py: from multiprocessing import Process import time import sys def slp(): time.sleep(30) f=open("yeah.txt","w") f.close() if __name__=="__main__" : x=Process(target=slp) x.start() sys.exit() In windows 7, from cmd, if I call python check.py, it doesn't immediately exit, but instead waits for 30 seconds. And if I kill cmd, the child dies too- no "yeah.txt" is created. How do I make ensure the child continues to run even if parent is killed and also that the parent doesn't wait for child process to end?

    Read the article

  • Random number in a loop

    - by Sam
    Hi all, having an issue generating random numbers in a loop. Can get around it by using Thread.Sleep but after a more elegant solution. for ... Random r = new Random(); string += r.Next(4); Will end up with 11111... 222... etc. Suggestions?

    Read the article

  • .NET Threading : How to wait for other thread to finish some task

    - by Alex Ilyin
    Assume I have method void SomeMethod(Action callback) This method does some work in background thread and then invokes callback. The question is - how to block current thread until callback is called ? There is an example bool finished = false; SomeMethod(delegate{ finished = true; }); while(!finished) Thread.Sleep(); But I'm sure there should be better way

    Read the article

  • Update View at runtime in Android

    - by seretur
    The example is pretty straightforward: i want to let the user know about what the app is doing by just showing a text (canvas.drawText()). Then, my first message appears, but not the other ones. I mean, i have a "setText" method but it doesn't updates. onCreate(Bundle bundle) { super.onCreate(bundle); setContentView(splash); // splash is the view class loadResources(); splash.setText("this"); boundWebService(); splash.setText("that"): etc(); splash.setText("so on"); } The view's text drawing works by doing just a drawText in onDraw();, so setText changes the text but doesn't show it. Someone recommended me replacing the view with a SurfaceView, but it would be alot of trouble for just a couple of updates, SO... how the heck can i update the view dinamically at runtime? It should be quite simple, just showing a text for say 2 seconds and then the main thread doing his stuff and then updating the text... Thanks! Update: I tried implementing handler.onPost(), but is the same story all over again. Let me put you the code: package coda.tvt; import android.app.Activity; import android.graphics.Canvas; import android.graphics.Paint; import android.os.Bundle; import android.view.View; import android.widget.TextView; import android.widget.Toast; public class ThreadViewTestActivity extends Activity { Thread t; Splash splash; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); splash = new Splash(this); t = new Thread(splash); t.start(); splash.setTextow("OA"); try { Thread.sleep(4000); } catch (InterruptedException e) { } splash.setTextow("LALA"); } } And: public class Splash implements Runnable { Activity activity; final Handler myHandler = new Handler(); public Splash(Activity activity) { this.activity=activity; } @Override public void run() { // TODO Auto-generated method stub } public synchronized void setTextow(final String textow) { // Wrap DownloadTask into another Runnable to track the statistics myHandler.post(new Runnable() { @Override public void run() { TextView t = (TextView)activity.findViewById(R.id.testo); t.setText(textow); t.invalidate(); } }); } } Although splash is in other thread, i put a sleep on the main thread, i use the handler to manage UI and everything, it doesn't changes a thing, it only shows the last update.

    Read the article

  • Php on windows and blocks

    - by zerkms
    My development PC has windows installed. And I've experienced weird php behaviour: <?php file_put_contents('c:/q', microtime(1) . "\r\n", FILE_APPEND); sleep(10); When I run this script in browser simultaneously in two different tabs I get such results 1294713622.125 1294713632.2188 which obviously is not what I expected, although in CLI everything is fine. So the question: what can block execution? (session.auto_start is Off)

    Read the article

  • Python: Run a progess bar and work simultaneously?

    - by DanielTA
    I want to know how to run a progress bar and some other work simultaneously, then when the work is done, stop the progress bar in Python (2.7.x) import sys, time def progress_bar(): while True: for c in ['-','\\','|','/']: sys.stdout.write('\r' + "Working " + c) sys.stdout.flush() time.sleep(0.2) def work(): *doing hard work* How would I be able to do something like: progress_bar() #run in background? work() *stop progress bar* print "\nThe work is done!"

    Read the article

  • Wait set time for user input C# console app

    - by Marlon
    For a Console app, I need to know how to wait at set amount of time (about 10 seconds), for a user to input a key or set of keys, before proceeding with an 'auto run' portion of the application. This is bugging me because I can't quite figure out how the timer works, or threading.sleep, what should I use? Been googling all day.

    Read the article

  • how to cancel an awaiting task c#

    - by user1748906
    I am trying to cancel a task awaiting for network IO using CancellationTokenSource, but I have to wait until TcpClient connects: try { while (true) { token.Token.ThrowIfCancellationRequested(); Thread.Sleep(int.MaxValue); //simulating a TcpListener waiting for request } } any ideas ? Secondly, is it OK to start each client in a separate task ?

    Read the article

  • Thread won't stop when I want it to? (Java)

    - by Stuart
    I have a thread in my screen recording application that won't cooperate: package recorder; import java.awt.AWTException; import java.awt.Insets; import java.io.IOException; import javax.swing.JFrame; public class RepeatThread extends Thread { boolean stop; public volatile Thread recordingThread; JFrame frame; int count = 0; RepeatThread( JFrame myFrame ) { stop = false; frame = myFrame; } public void run() { while( stop == false ) { int loopDelay = 33; // 33 is approx. 1000/30, or 30 fps long loopStartTime = System.currentTimeMillis(); Insets insets = frame.getInsets(); // Get the shape we're recording try { ScreenRecorder.capture( frame.getX() + insets.left, frame.getY() + insets.top, frame.getWidth() - ( insets.left + insets.right ), frame.getHeight() - ( insets.top + insets.bottom ) ); } catch( AWTException e1 ) { // TODO Auto-generated catch block e1.printStackTrace(); } catch( IOException e1 ) { // TODO Auto-generated catch block e1.printStackTrace(); } // Add another picture long loopEndTime = System.currentTimeMillis(); int loopTime = (int )( loopEndTime - loopStartTime ); if( loopTime < loopDelay ) { try { sleep( loopDelay - loopTime ); // If we have extra time, // sleep } catch( Exception e ) { } // If something interrupts it, I don't give a crap; just // ignore it } } } public void endThread() { stop = true; count = 0; ScreenRecorder.reset(); // Once I get this annoying thread to work, I have to make the pictures // into a video here! } } It's been bugging me for ages. It periodically takes screenshots to the specified area. When you start recording, it hides (decativates) the window. On a Mac, when you give an application focus, any hidden windows will activate. In my class WListener (which I have confirmed to work), I have: public void windowActivated(WindowEvent e) { if(ScreenRecorder.recordingThread != null) { ScreenRecorder.recordingThread.endThread(); } } So what SHOULD happen is, the screenshot-taking thread stops when he clicks on the application. However, I must be brutally screwing something up, because when the thread is running, it won't even let the window reappear. This is my first thread, so I expected a weird problem like this. Do you know what's wrong?

    Read the article

  • Streaming HTTP response, flushing to the browser

    - by synic
    I've got a view like the following: from django.views.decorators.http import condition def stream(): for i in range(0, 40): yield " " * 1024 yield "%d" % i time.sleep(1) @condition(etag_func=None): def view(request): return HttpResponse(stream(), mimetype='text/html') However, it definitely doesn't seem to be streaming at all. All the data is dumped at once, at the end, after about 40 seconds. How can I get it to flush correctly?

    Read the article

  • how a thread can signal when it's finished?

    - by Kyle
    #include <iostream> #include <boost/thread.hpp> using std::endl; using std::cout; using namespace boost; mutex running_mutex; struct dostuff { volatile bool running; dostuff() : running(true) {} void operator()(int x) { cout << "dostuff beginning " << x << endl; this_thread::sleep(posix_time::seconds(2)); cout << "dostuff is done doing stuff" << endl; mutex::scoped_lock running_lock(running_mutex); running = false; } }; bool is_running(dostuff& doer) { mutex::scoped_lock running_lock(running_mutex); return doer.running; } int main() { cout << "Begin.." << endl; dostuff doer; thread t(doer, 4); if (is_running(doer)) cout << "Cool, it's running.\n"; this_thread::sleep(posix_time::seconds(3)); if (!is_running(doer)) cout << "Cool, it's done now.\n"; else cout << "still running? why\n"; // This happens! :( return 0; } Why is the output of the above program: Begin.. Cool, it's running. dostuff beginning 4 dostuff is done doing stuff still running? why How can dostuff correctly flag when it is done? I do not want to sit around waiting for it, I just want to be notified when it's done.

    Read the article

  • PHP: Prevent a function from returning value?

    - by Industrial
    Hi everybody, How could I make sure that the startProcess(); function is being called, but without halting the execution for myFunction(). I'll guess that there's a way to call a function and prevent it from returning it's value to thereby accomplishing this? Pseudo-code: function myFunction() { startProcess(); return $something; } function startProcess() { sleep(5); // Do stuff that user doesn't should have to wait for. }

    Read the article

  • IE Problem in jQuery

    - by venkatachalam
    I am using the jQuery plugin Cross Slide. My page is working fine in Chrome and Firefox. But in IE 7, I get: Debug error as Object expected on line 1: $(document).ready(function() { $('#image').crossSlide({sleep:4,fade:1},[{src:'images/1.jpg'},{src:'images/2.jpg'}]); }); How can I fix bug in IE 8 & 7?

    Read the article

  • Named pipe is using 100% CPU

    - by willwill
    I'm starting the script with ./file.py < pipe >> logfile and the script is: while True: try: I = raw_input().strip().split() except EOFError: continue doSomething() How could I better handle named pipe? This script always run at 100% CPU and it need to be real-time so I cannot use time.sleep.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >