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  • Is there a maximum of open files per process in Linux?

    - by Malax
    My question is pretty simple and is actually stated in the title. One of my applications throws errors regarding "too many open files" at me, even tho the limit for the user the application runs with is higher than the default of 1024 (lsof -u $USER reports 3000 open fds). Because I cannot imagine why this happens, I guess there might be a maximum per process. Any idea is very appreciated! Edit: Some values that might help... root@Debian-60-squeeze-64-minimal ~ # ulimit -n 100000 root@Debian-60-squeeze-64-minimal ~ # tail -n 4 /etc/security/limits.conf myapp soft nofile 100000 myapp hard nofile 1000000 root soft nofile 100000 root hard nofile 1000000 root@Debian-60-squeeze-64-minimal ~ # lsof -n -u myapp | wc -l 2708

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  • Windows Live Writer fails to start

    - by Albert Bori
    I installed windows live writer and configured it to connect to my xmlrpc enabled blog engine. After doing so, it threw an unrecoverable error and closed down. After attempting to restart windows live writer, it throws the following exception each time: Description: Windows Live Writer has encountered a problem: Invalid URI: The hostname could not be parsed. Problem signature: Problem Event Name: WindowsLiveWriter Problem Signature 01: CreateThis Problem Signature 02: 115 Problem Signature 03: System.UriFormatException Problem Signature 04: 15.4.3555.308 Problem Signature 05: 2.0.50727.5456 Problem Signature 06: Windows Live Writer OS Version: 6.1.7601.2.1.0.256.1 Locale ID: 1033 Since I was unable to start windows live writer at all, I tried uninstalling it and removing all files associated with it in my "C:/users/[username]/appdata" folder. After that, I re-installed it and still get the error every time I try to launch the application. Does anyone know how I can get around this?

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  • HAProxy with 'backup' failure

    - by A.RG
    I have a simple configuration of 2 MySQL being load balanced by HAProxy. For an unfortunate reason I need to use them in Passive\Active mode. So I thought I'd configure one DB as 'backup' and go to sleep. But I was wrong. Whenever I add the 'backup' to the server line HAProxy throws a communication link error (essentially saying 'no DB available" (with the 'backup' it works great). It just doesnt consider that server as a valid option any more... I have tried this configuration: listen mysql 10.0.0.109:3307 mode tcp balance roundrobin option httpchk server db01 10.0.0.236:3306 server db02 10.0.0.68:3306 backup and also this configuration: frontend mysql_proxy bind 10.0.0.109:3307 default_backend mysql backend mysql mode tcp balance roundrobin option httpchk server db01 10.0.0.236:3306 server db02 10.0.0.68:3306 backup Nothing worked! Can anyone point me in the right direction? Thanks

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  • How to either completely remove SQL Server 2008 R2 Installation or repair it?

    - by Nico
    I've installed MSSQL server correctly, then I took some wrong turns and I'm now left in a pretty undesirable state. I wanted to change the server instance to another drive, so I uninstalled SQL server and all of it's features from the Programs and Features control panel. Now when I tried to install a new instance, I got a few errors, but it still installed most of them: Then I tried to run a repair, which I figured would fix things, but it throws an exception about not being able to read something from the CD (tried more than once always the same exception) Error 1316.A network error occurred while attempting to read from the file R:\1033_ENU_LP\x64\setup\SSCERuntime_x86-enu.msi , and it fails to repair a few of the features: And I don't have the server instance installed either. So I'm left with no MSSQLMS, no server instance, and no happiness. What would be the best course of action here?

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  • LDAP :Failed to find add in mandatory or optional attribute list

    - by Manju Prabhu
    I am trying to import an ldif file which has following content- DN: cn=myUser,cn=Users,dc=us,dc=oracle,dc=com objectclass: top objectclass: person objectclass: organizationalPerson objectclass: inetorgperson objectclass: orcluser objectclass: orcluserV2 cn: myUser givenname: myUser mail: myUser orclsamaccountname: myUser sn: myUser uid: myUser userpassword:: somepassword dn: cn=Administrator,cn=Groups,dc=us,dc=oracle,dc=com objectclass: person changetype: modify add: uniquemember uniquemember: cn=myUser,cn=Users,dc=us,dc=oracle,dc=com When I do this, LDAP throws follwing error javax.naming.directory.SchemaViolationException: [LDAP: error code 65 - Failed to find add in mandatory or optional attribute list.]; remaining name 'cn=Administrator,cn=Groups,dc=us,dc=oracle,dc=com' The user gets imported, but it is not added to the group(Group exists). What am i missing ?

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  • Several Server Errors (No database connect, can't create TCP/IP socket etc

    - by Tobias Baumeister
    My server stops taking requests on my website today. It works for some time, but then the server just stops working and throws several errors: 500 Internal Server Error Warning: mysql_connect(): Can't create TCP/IP socket (105) in [...] on line 7 Couldn't connect to database. Please try again. mysql_connect(): Host [...] is blocked because of many connection errors; unblock with 'mysqladmin flush-hosts' mod_fcgid: can't apply process slot for /var/www/cgi-bin/cgi_wrapper/cgi_wrapper (this is from Error Log) Any ideas what might cause it? operating system is Ubuntu

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  • Unable to load PHP5 with a new installation of Apache?

    - by Doug
    Cannot load /usr/lib/apache2/modules/libphp5.so into server: /usr/lib/apache2/modules/libphp5.so: undefined symbol: unixd_config I spent the last hour or so googling, and it seems that I have to create a new PHP5 after installing my new Apache (2.4.2). Debian didn't have Apache 2.4.2 and it's a requirement I was given. I still have the PHP 5.4.4 from Debian wheezy repository. I tried including it in the new Apache 2.4.2 that I installed, but it throws the error you see above. Is there a way to "reglue" everything? I was going to just install a fresh PHP, but I ran into some errors on ./configure, so I wanted to see if there were easier ways before I spend more time on installing a new copy.

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  • Mapping a Piped Shell Command in Vim

    - by michaelmichael
    In a previous question I asked about mapping evaluated code to a new window in MacVim. I got a great solution, but it presented another question: How can I map a key command in my .vimrc that involves piping output in the shell? As a simple example, let's say I wanted to pipe the results of ls -a to a new MacVim window. From the Vim command line I can enter !ls -a | mvim -, and the results will appear in a new window. Great! Now, I add that to my .vimrc: nmap <Leader>r :w !ls | mvim<CR> Vim now throws an error every time I try to source my .vimrc, which reads as follows: E492: Not an editor command: mvim<CR> Any ideas on how to overcome this?

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  • On a Mac, how can I find all files on a NTFS partition that have the same name, given case *in*sensi

    - by SCdF
    Here's the deal, I have a huge mess of files on an external drive that is formatted as NTFS. I wish to copy all of these files onto my MacBook Pro. NTFS, like sane filesystems, is case sensitive. HFS is not. There is, somewhere in the mess of tens of thousands of files and directories, one or more 'duplicates' in the eyes of HFS. Theses are preventing me from copying the entire directory of data onto my mac. (MacOSX rather unhelpfully throws a general error explaining the problem, but not the exact file. It also doesn't give you an option to skip) What is the best approach to solve this? Does anyone know a tool that can find files and directories that have the same case-insensitive name?

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  • how to get the result query one by one in jsp and mysql

    - by user261002
    I am trying to implement as Online Mock exam in JSP, but I have a problem to get the questions one by one, it get connceted for the first time, and show me the first question and answers, but when I click on "next" again, it still show me the first question, I think by clicking on "next" it start querying again. please help me. this is my bean : database.SQLSelectStatement sqlselect; database.SQLSelectStatement sqlselect2; static ResultSet questions; static ResultSetMetaData rsm; static ResultSet answers; public void setConnection() throws SQLException { if (database.DatabaseManager.getInstance().connectionOK()) { sqlselect = new database.SQLSelectStatement("question", "question", "0"); sqlselect2 = new database.SQLSelectStatement("answers", "question_id", "0"); questions = sqlselect.executeWithNoCondition(); } } public int i=0; public String getQuestions() throws SQLException { String result = ""; rsm = questions.getMetaData(); for (int i = 0; i < rsm.getColumnCount(); i++) { result += "<th>" + rsm.getColumnName(i + 1) + "</th>"; } if (!questions.isLast()) { questions.next(); System.out.println(i+1); result += "<tr>"; result += "<td>" + questions.getInt(1) + "</td>"; result += "<td>" + questions.getString(2) + "</td>"; result += "</tr>"; result += "<tr>"; sqlselect2.setValue(String.valueOf(questions.getInt(1))); answers = sqlselect2.Execute(); while (answers.next()) { result += "<tr> <td colspan='2'><input type='radio' name='answer' value='" + answers.getString(2) + "'> " + answers.getString(2) + "</td></tr>"; } result += "</tr>"; answers.close(); } return result; } this is the HTML: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>JSP Page</title> </head> <body> <h1>JSP Page</h1> <jsp:useBean id="exam" class="exam.ExamQuestions"></jsp:useBean> <% exam.setConnection(); %> <form method="post"> <table > <%=exam.getQuestions()%> </table> <input type="submit" name="action" value="next"/> </form> <% String action = request.getParameter("action"); if ("next".equals(action)) { out.println(request.getParameter("answer")); } %> </body> </html>

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  • AES Cipher not picking up IV

    - by timothyjc
    I am trying to use an IV with AES so that the encrypted text is unpredictable. However, the encrypted hex string is always the same. I have actually tried a few methods of attempting to add some randomness by passing some additional parameters to the cipher init call: 1) Manual IV generation byte[] iv = generateIv(); IvParameterSpec ivspec = new IvParameterSpec(iv); 2) Asking cipher to generate IV AlgorithmParameters params = cipher.getParameters(); params.getParameterSpec(IvParameterSpec.class); 3) Using a PBEParameterSpec byte[] encryptionSalt = generateSalt(); PBEParameterSpec pbeParamSpec = new PBEParameterSpec(encryptionSalt, 1000); All of these seem to have no influence on the encrypted text.... help!!! My code: package com.citc.testencryption; import java.security.NoSuchAlgorithmException; import java.security.SecureRandom; import javax.crypto.Cipher; import javax.crypto.SecretKey; import javax.crypto.SecretKeyFactory; import javax.crypto.spec.IvParameterSpec; import javax.crypto.spec.PBEKeySpec; import android.app.Activity; import android.os.Bundle; import android.util.Log; public class Main extends Activity { public static final int SALT_LENGTH = 20; public static final int PBE_ITERATION_COUNT = 1000; private static final String RANDOM_ALGORITHM = "SHA1PRNG"; private static final String PBE_ALGORITHM = "PBEWithSHA256And256BitAES-CBC-BC"; private static final String CIPHER_ALGORITHM = "PBEWithSHA256And256BitAES-CBC-BC"; private static final String TAG = Main.class.getSimpleName(); @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); try { String password = "password"; String plainText = "plaintext message to be encrypted"; // byte[] salt = generateSalt(); byte[] salt = "dfghjklpoiuytgftgyhj".getBytes(); Log.i(TAG, "Salt: " + salt.length + " " + HexEncoder.toHex(salt)); PBEKeySpec pbeKeySpec = new PBEKeySpec(password.toCharArray(), salt, PBE_ITERATION_COUNT); SecretKeyFactory keyFac = SecretKeyFactory.getInstance(PBE_ALGORITHM); SecretKey secretKey = keyFac.generateSecret(pbeKeySpec); byte[] key = secretKey.getEncoded(); Log.i(TAG, "Key: " + HexEncoder.toHex(key)); // PBEParameterSpec pbeParamSpec = new PBEParameterSpec(salt, ITERATION_COUNT); Cipher encryptionCipher = Cipher.getInstance(CIPHER_ALGORITHM); // byte[] encryptionSalt = generateSalt(); // Log.i(TAG, "Encrypted Salt: " + encryptionSalt.length + " " + HexEncoder.toHex(encryptionSalt)); // PBEParameterSpec pbeParamSpec = new PBEParameterSpec(encryptionSalt, 1000); // byte[] iv = params.getParameterSpec(IvParameterSpec.class).getIV(); // Log.i(TAG, encryptionCipher.getParameters() + " "); byte[] iv = generateIv(); IvParameterSpec ivspec = new IvParameterSpec(iv); encryptionCipher.init(Cipher.ENCRYPT_MODE, secretKey, ivspec); byte[] encryptedText = encryptionCipher.doFinal(plainText.getBytes()); Log.i(TAG, "Encrypted: " + HexEncoder.toHex(encryptedText)); // <== Why is this always the same :( Cipher decryptionCipher = Cipher.getInstance(CIPHER_ALGORITHM); decryptionCipher.init(Cipher.DECRYPT_MODE, secretKey, ivspec); byte[] decryptedText = decryptionCipher.doFinal(encryptedText); Log.i(TAG, "Decrypted: " + new String(decryptedText)); } catch (Exception e) { e.printStackTrace(); } } private byte[] generateSalt() throws NoSuchAlgorithmException { SecureRandom random = SecureRandom.getInstance(RANDOM_ALGORITHM); byte[] salt = new byte[SALT_LENGTH]; random.nextBytes(salt); return salt; } private byte[] generateIv() throws NoSuchAlgorithmException { SecureRandom random = SecureRandom.getInstance(RANDOM_ALGORITHM); byte[] iv = new byte[16]; random.nextBytes(iv); return iv; } }

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  • JPA IndirectSet changes not reflected in Spring frontend

    - by Jon
    I'm having an issue with Spring JPA and IndirectSets. I have two entities, Parent and Child, defined below. I have a Spring form in which I'm trying to create a new Child and link it to an existing Parent, then have everything reflected in the database and in the web interface. What's happening is that it gets put into the database, but the UI doesn't seem to agree. The two entities that are linked to each other in a OneToMany relationship like so: @Entity @Table(name = "parent", catalog = "myschema", uniqueConstraints = @UniqueConstraint(columnNames = "ChildLinkID")) public class Parent { private Integer id; private String childLinkID; private Set<Child> children = new HashSet<Child>(0); @Id @GeneratedValue(strategy = IDENTITY) @Column(name = "id", unique = true, nullable = false) public Integer getId() { return this.id; } public void setId(Integer id) { this.id = id; } @Column(name = "ChildLinkID", unique = true, nullable = false, length = 6) public String getChildLinkID() { return this.childLinkID; } public void setChildLinkID(String childLinkID) { this.childLinkID = childLinkID; } @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "parent") public Set<Child> getChildren() { return this.children; } public void setChildren(Set<Child> children) { this.children = children; } } @Entity @Table(name = "child", catalog = "myschema") public class Child extends private Integer id; private Parent parent; @Id @GeneratedValue(strategy = IDENTITY) @Column(name = "id", unique = true, nullable = false) public Integer getId() { return this.id; } public void setId(Integer id) { this.id = id; } @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "ChildLinkID", referencedColumnName = "ChildLinkID", nullable = false) public Parent getParent() { return this.parent; } public void setParent(Parent parent) { this.parent = parent; } } And of course, assorted simple properties on each of them. Now, the problem is that when I edit those simple properties from my Spring interface, everything works beautifully. I can persist new entities of these types and they'll appear when using the JPATemplate to do a find on, say, all Parents (getJpaTemplate().find("select p from Parent p")) or on individual entities by ID or another property. The problem I'm running into is that now, I'm trying to create a new Child linked to an existing Parent through a link from the Parent's page. Here's the important bits of the Controller (note that I've placed the JPA foo in the controller here to make it clearer; the actual JpaDaoSupport is actually in another class, appropriately tiered): protected Object formBackingObject(HttpServletRequest request) throws Exception { String parentArg = request.getParameter("parent"); int parentId = Integer.parseInt(parentArg); Parent parent = getJpaTemplate().find(Parent.class, parentId); Child child = new Child(); child.setParent(parent); NewChildCommand command = new NewChildCommand(); command.setChild(child); return command; } protected ModelAndView onSubmit(Object cmd) throws Exception { NewChildCommand command = (NewChildCommand)cmd; Child child = command.getChild(); child.getParent().getChildren().add(child); getJpaTemplate().merge(child); return new ModelAndView(new RedirectView(getSuccessView())); } Like I said, I can run through the form and fill in the new values for the Child -- the Parent's details aren't even displayed. When it gets back to the controller, it goes through and saves it to the underlying database, but the interface never reflects it. Once I restart the app, it's all there and populated appropriately. What can I do to clear this up? I've tried to call extra merges, tried refreshes (which gave a transaction exception), everything short of just writing my own database access code. I've made sure that every class has an appropriate equals() and hashCode(), have full JPA debugging on to see that it's making appropriate SQL calls (it doesn't seem to make any new calls to the Child table) and stepped through in the debugger (it's all in IndirectSets, as expected, and between saving and displaying the Parent the object takes on a new memory address). What's my next step?

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  • Email solution for new domain [on hold]

    - by user196286
    I registered my domain at NameCheap, and have it hosted now at AWS Route 53. However, I'm at a loss for how now to set up sending transactional email. I hear Amazon SES is a good solution, but that requires me to verify my e-mail. I don't have email set up (no e-mail addresses at my domain nor a email client to receive the email verification). As an added wrinkle, I have my sitename.com bucket redirecting to www.sitename.com, and I'm hosting my site on Route 53 using www.sitename.com. However, does this screw things up if I need to switch my MX records since perhaps the 'www' throws things off (would it point to mail.www.sitename.com)?

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  • UAC prompt won't allow non-administrator to access IIS 7 Manager.

    - by Triynko
    The IIS 7 Manager seems to throw up a UAC prompt requiring administrative elevation as soon as the shortcut is clicked. This makes it impossible for a non-admin to use it. When I first created the user account, I could open IIS 7 Manager, but could not connect. I temporarily made the user account an Admin, then opened IIS 7 Manager again. Now that I've removed user from Admin, every time I open IIS 7 Manager it throws up the UAC prompt, making it impossible to do anything with it as a non-Admin. Is this a bug? Is there a way to reset the settings for this user so that IIS 7 Manager is back in some kind of first-run state?

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  • Sending mail to local address crashes web server (sendmail)

    - by deceze
    When trying to send mail automatically from a script at example.com via PHP's mail() to [email protected], the Apache server throws an Internal Error. I believe internally it is configured to use sendmail. The message gets dropped into ~/dead.letter and the general error log reads: [Wed May 12 11:26:45 2010] [error] [client xxx.xxx.xxx.xxx] malformed header from script. Bad header=/home/example/dead.letter... S: /home/example/www/test.php Trying any other address, not @example.com, works just fine. I have googled and serverfaulted for solutions, but they all require to edit configuration files in /etc/mail and similar system places, which is not an option, since this problem occurs on a shared host in which I only have access to ~/. Does anyone have a suggestion?

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  • servlet does not envoke when I call a from method.

    - by saloni
    My web.xml is like <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <display-name>sample</display-name> <servlet> <servlet-name>Sampleclass</servlet-name> <servlet-class>sample.SampleClass</servlet-class> </servlet> <servlet-mapping> <servlet-name>Sampleclass</servlet-name> <url-pattern>/SampleClass</url-pattern> </servlet-mapping> <welcome-file-list> <welcome-file>/page/form.jsp</welcome-file> </welcome-file-list> </web-app> and form.jsp <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> </head> <body> <h1>A simple web application</h1> <form method="POST" name="Sampleclass" action="SampleClass"> <label for="name">Enter your name </label> <input type="text" id="name" name="name"/><br><br> <input type="submit" value="Submit Form"/> <input type="reset" value="Reset Form"/> </form> </body> </html> and SampleClass.java is public class SampleClass extends HttpServlet { public void init(ServletConfig config) throws ServletException { super.init(config); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String name = request.getParameter("name"); String age = request.getParameter("age"); PrintWriter out = response.getWriter(); out.write("<html>Hello Your name is "+name +", and your age is "+age+"</html>"); } public void destroy() { } } but I am getting error when I entered to submit button of form.jsp and error is type Status report message HTTP method POST is not supported by this URL description The specified HTTP method is not allowed for the requested resource (HTTP method POST is not supported by this URL). I am not understanding that what is the problem exactly ? Please help..

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  • How to turn SSLCompression off in Apache 2.4.3?

    - by kumar
    I have installed Apache 2.4.3(OpenSSL 1.0.0j) on a machine and trying to do SSLCompression off in the ssl.conf file throws an error: Syntax error on line 219 of /etc/httpd/conf.d/ssl.conf: Invalid command 'SSLCompression', perhaps misspelled or defined by a module not included in the server configuration What could be wrong here? If it helps, I installed mod_ssl(2.4). Is that enough or is something more to be done to configure Apache with mod_ssl. I tried phpinfo() in php, and mod_ssl is reflected in the Loaded Modules section.

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  • OS X 10.7.5 - telnet: connect to address 10.0.0.12: Operation not permitted

    - by user2169619
    I have troubles to connect from macos to reach windows shares and I hit some general problem with my macos. When I try to telnet to 445 port to my windows share server the macos throws "Operation not permitted". I have no firewall rule and I'm not able to google anything. sh-3.2# telnet 10.0.0.12 445 Trying 10.0.0.12... telnet: connect to address 10.0.0.12: Operation not permitted telnet: Unable to connect to remote host Any idea what can be the reason?

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  • rsync bash script to backup specific directories nightly to remote server

    - by Janice Young
    Hello, I am looking for a rsync script that will backup specific directories from my home machine to a remote server nightly. So say: /home/me/Pictures to ssh -p 6587 [email protected]/Pictures. It would be nice if it can look for changes but im not worried so much about the changes aspect is having a script that runs at a certain time of night with cron or however. I have googled and found scripts but those scripts were specific to the operations of those creators. Any help would be happily accepted as the scripted part really throws me off. Thank you, Janice

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  • Coldfusion multiserver instance hangs

    - by David Sedeño
    I have a coldfusion 8 multiserver setup with IIS in Windows 2008 Standard SP2 and when one instance "hangs" (I can't connect to the instance from fusion reactor) the web server throws a "503 service unavailable". The remains instance seems to works ok in fusion reactor but the website have only the 503. I have to restart jvm processes and IIS to get the website work again. The jvm processes have the option -Xmx2048m and the instanaces have 2.5Gb allocated. Maybe the jvm process reach the 2Gb limit and stop working? Can be a problem between IIS and CF instances? I'm new to CF debugging process, how can I find why the instance hangs? Thanks

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  • Unable to connect to mysql through JDBC connector through Tomcat or externally

    - by Stefan Kendall
    I've installed a stock mysql 5.5 installation, and while I can connect to the mysql service via the mysql command, and the service seems to be running, I cannot connect to it through spring+tomcat or from an external jdbc connector. I'm using the following URL: jdbc:mysql://myserver.com:myport/mydb with proper username/password, but I receive the following message: server.com: Communications link failure The last packet sent successfully to the server was 0 milliseconds ago. the driver has not received any packets from the server. and tomcat throws: com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: Communications link failure The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server. sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:57) Which seems to be the same issue as if I try to connect externally.

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  • SVN: Error validating server certificate for svn hook linux

    - by Dr Casper Black
    Hi, I managed to setup a SVN (over SSL) server and TortoiseSVN client on Win. I made a Post-Commit Hook for test project. The Post-Commit will update the web dir so the App in PHP can be executed with the newest version. It all works when done over shell. The only problem is, when i commit the changes over the client in Win the change is commited but HOOK throws error post-commit hook failed (exit code 1) with output: Error validating server certificate for 'https://SERVER_IP:443': - The certificate is not issued by a trusted authority. Use the fingerprint to validate the certificate manually! - The certificate hostname does not match. Certificate information: - Hostname: DEVSRVR - Valid: from Fri, 28 Jan 2011 09:22:45 GMT until Sat, 28 Jan 2012 09:22:45 GMT - Issuer: PHP, SS, SS, SRB - Fingerprint: 5f:d0:50:d6:dd:a6:d4:64:a5:ac:3a:4b:7c:7d:33:e3:75:dd:23:9f (R)eject, accept (t)emporarily or accept (p)ermanently? svn: OPTIONS of 'https://SERVER_IP/svn/myproject/trunk': Server certificate verification failed: certificate issued for a different hostname, issuer is not trusted (https://SERVER_IP)

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  • Exchange 2003 HTTP Account Error

    - by Ryaner
    We are trying to get one of our users connected to our Exchange 2003 server using the HTTP method as they already have an existing Exchange account on another server. The setup goes through and they appear to get connected fine however none of the subfolders are listed. Instead we get one folder of "Error-Pls file a Bug". The usual Google search just throws up nothing useful. Does anyone know how to fix this? Or has anyone actually gotten Outlook (2003 or 2007) to connect to an Exchange 2003 server?

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  • How to require a cell input if another cell has a value

    - by Connor
    I'm trying to edit the VBA for one of my workbooks so that If there is a value in column A, then a value for column C is required or else the file won't save, but i'm having some trouble with this. I can get excel to check a cell for any input and require it have input, but I need it to check if a different cell has an input before requiring input. This is because not all of the lines in my spreadsheet will be used all of the time, but some people forget to put very important pieces of information in the spreadsheet which throws some of our balances off. An SKU is entered on the sheet when we switch to a new one, and I want the program to make sure there is an amount of product in a given cell every time a new SKU is entered onto the sheet. Thanks.

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  • Spring Security and the Synchronizer Token J2EE pattern, problem when authentication fails.

    - by dfuse
    Hey, we are using Spring Security 2.0.4. We have a TransactionTokenBean which generates a unique token each POST, the bean is session scoped. The token is used for the duplicate form submission problem (and security). The TransactionTokenBean is called from a Servlet filter. Our problem is the following, after a session timeout occured, when you do a POST in the application Spring Security redirects to the logon page, saving the original request. After logging on again the TransactionTokenBean is created again, since it is session scoped, but then Spring forwards to the originally accessed url, also sending the token that was generated at that time. Since the TransactionTokenBean is created again, the tokens do not match and our filter throws an Exception. I don't quite know how to handle this elegantly, (or for that matter, I can't even fix it with a hack), any ideas? This is the code of the TransactionTokenBean: public class TransactionTokenBean implements Serializable { public static final int TOKEN_LENGTH = 8; private RandomizerBean randomizer; private transient Logger logger; private String expectedToken; public String getUniqueToken() { return expectedToken; } public void init() { resetUniqueToken(); } public final void verifyAndResetUniqueToken(String actualToken) { verifyUniqueToken(actualToken); resetUniqueToken(); } public void resetUniqueToken() { expectedToken = randomizer.getRandomString(TOKEN_LENGTH, RandomizerBean.ALPHANUMERICS); getLogger().debug("reset token to: " + expectedToken); } public void verifyUniqueToken(String actualToken) { if (getLogger().isDebugEnabled()) { getLogger().debug("verifying token. expected=" + expectedToken + ", actual=" + actualToken); } if (expectedToken == null || actualToken == null || !isValidToken(actualToken)) { throw new IllegalArgumentException("missing or invalid transaction token"); } if (!expectedToken.equals(actualToken)) { throw new InvalidTokenException(); } } private boolean isValidToken(String actualToken) { return StringUtils.isAlphanumeric(actualToken); } public void setRandomizer(RandomizerBean randomizer) { this.randomizer = randomizer; } private Logger getLogger() { if (logger == null) { logger = Logger.getLogger(TransactionTokenBean.class); } return logger; } } and this is the Servlet filter (ignore the Ajax stuff): public class SecurityFilter implements Filter { static final String AJAX_TOKEN_PARAM = "ATXTOKEN"; static final String TOKEN_PARAM = "TXTOKEN"; private WebApplicationContext webApplicationContext; private Logger logger = Logger.getLogger(SecurityFilter.class); public void init(FilterConfig config) { setWebApplicationContext(WebApplicationContextUtils.getWebApplicationContext(config.getServletContext())); } public void destroy() { } public void doFilter(ServletRequest req, ServletResponse response, FilterChain chain) throws IOException, ServletException { HttpServletRequest request = (HttpServletRequest) req; if (isPostRequest(request)) { if (isAjaxRequest(request)) { log("verifying token for AJAX request " + request.getRequestURI()); getTransactionTokenBean(true).verifyUniqueToken(request.getParameter(AJAX_TOKEN_PARAM)); } else { log("verifying and resetting token for non-AJAX request " + request.getRequestURI()); getTransactionTokenBean(false).verifyAndResetUniqueToken(request.getParameter(TOKEN_PARAM)); } } chain.doFilter(request, response); } private void log(String line) { if (logger.isDebugEnabled()) { logger.debug(line); } } private boolean isPostRequest(HttpServletRequest request) { return "POST".equals(request.getMethod().toUpperCase()); } private boolean isAjaxRequest(HttpServletRequest request) { return request.getParameter("AJAXREQUEST") != null; } private TransactionTokenBean getTransactionTokenBean(boolean ajax) { return (TransactionTokenBean) webApplicationContext.getBean(ajax ? "ajaxTransactionTokenBean" : "transactionTokenBean"); } void setWebApplicationContext(WebApplicationContext context) { this.webApplicationContext = context; } }

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