Search Results

Search found 22192 results on 888 pages for 'unique key'.

Page 50/888 | < Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >

  • php array_unique

    - by dotty
    HAy, i have an array Array( [0] => Array ( [0] => 33 [user_id] => 33 [1] => 3 [frame_id] => 3 ) [1] => Array ( [0] => 33 [user_id] => 33 [1] => 3 [frame_id] => 3 ) [2] => Array ( [0] => 33 [user_id] => 33 [1] => 8 [frame_id] => 8 ) [3] => Array ( [0] => 33 [user_id] => 33 [1] => 3 [frame_id] => 3 ) [4] => Array ( [0] => 33 [user_id] => 33 [1] => 3 [frame_id] => 3 ) ) As you can see key 0 is the same as 1,3 and 4. And key 2 is different from them all. When running the array_unique function on them, the only left is Array ( [0] => Array ( [0] => 33 [user_id] => 33 [1] => 3 [frame_id] => 3 ) ) any ideas why array_unique isn't working as expected?

    Read the article

  • keyboard is not working properly

    - by kumar shivam
    i installed ubuntu 12.04 and it was working perfectly, but from yesterday i have a problem, when i am pressing left ctrl key it doesn't responding but when i pressed Fn key it works as a ctrl key and loses its own functioning,same with the delete(del) key it works as a pause/break key and pause/break key is working as a delete key.numlock key is working as a print screen key, after that i updated my os but the problem is still happening. pls tell me what to do.

    Read the article

  • How to make unity unresponsive in Unity session in precise?

    - by Anwar Shah
    Recently I wanted to test the a keyboard shortcut, which is supposed to kill X server (hence very useful when you have a crash). That shortcut is not dependent on any particular window manager (like lxde, unity, kwin etc). So, it must work, even when you have unresponsive window manager (as opposed to Alt+Ctrl+Backspace which kills the session, and bring you a login screen). That's why I interested to make my WM (unity) unresponsive. Is past, it was very easy. Opening a terminal, typing unity --replace and then force close the terminal, was the simplest procedure. But unfortunately, This is not true in Ubuntu 12.04, (they make it very robust) Because whenever I kill the terminal, Unity automagically restart itself. I also tried compiz --replace but wasn't successful. My question is: How can I make Unity unresponsive while I am in Unity session, so that window manager does not recognize any keyboard shortcut.

    Read the article

  • How can I get Kubuntu to use my Multimedia keys

    - by tbruf13
    I have tried to get Kubuntu to use my multimedia keys, and I cannot figure out how to do this. This feature is default in Ubuntu and in Linux Mint. They just work. I have followed the KUbuntu wiki post on Multimedia keys. I tried to enable Multimedia maps with xmodmap. It did not work. I tried to use the KDE GUI and could not seem to make the function I wanted work. The functions I am trying to get to work are fn+F12 = skip song fn+F11 = previous song fn+F10 = stop fn+ F9 = play/pause. I know this is possible because it worked in Ubuntu and in Mint, but it does not work in Kubuntu. I have submitted a bug report on this issue. Disclaimer: I am using Kubuntu 12.04 I have looked at this post, but Is there a way to enable Ubuntu Keyboard shortcuts in Kubuntu? do not know what to call the keys in that program.

    Read the article

  • How can I make gitosis distinguish between two users with the same username

    - by bryan kennedy
    I have a gitosis system that seems to be working correctly except for a common problem we run into where I can't distingush permissions between two users who have the same username, but different hosts. For example: [email protected] 's SSH key is in the key folder. And so is [email protected] 's SSH is also in the key folder. These two jsmith's are two different people on two different computers. However, when I configure them in the gitosis.conf file with the usernames jsmith@computer or jsmith@machine, it seems like each user just gets the same permission. Can gitosis not distinguish the full username (name and host)? If not, how do I deal with multiple users accessing our system with common usernames? Thanks for any help.

    Read the article

  • Text selection CTRL+SHIFT+Cursor Keys?

    - by mark
    Hi, I'm used to this Windows behavior that using CTRL+SHIFT+Cursor Keys I can select text word-wise. CTRL+Cursor Keys jumps word-wise and I use that a lot in combination with SHIFT to select text. This seems to be a "Windows thing" because it just works in all application. Now turning to Ubuntu 10.04, it doesn't work. CTRL+SHIFT+Cursor Keys just behaves like CTRL+Cursor Keys, i.e. I jump between the words but I can't select them that way. Another gotcha: I use CTRL+Cursor Keys to move fast between words, press down SHIFT, release CTRL and move the Cursor Keys to select text char by char and it doesn't work either. I need to release both keys complete. Is there a way to enable this?

    Read the article

  • keymapping when ssh-ing from mac to linux

    - by Yair
    I'm using Lion to ssh -X to a linux machine and work on some code thats located on it. I open up an editor on the remote machine (usually matlab) and program on it. My problem is that in the linux there is no concept of the command key. So if I want to copy some text from a local window to the editor that runs on the remote, I need to to command-c to copy, and then control-v to paste. This obviously drives me nuts. I was wondering if there is a way to change the keymapping such that the command key will be recognized as a control key on the remote processes. Or is this something I need to change on my local (mac) X configuration?

    Read the article

  • Getting error while running apt-get update

    - by pradeepchhetri
    I am getting the following error while running apt-get update on all of the servers. W: A error occurred during the signature verification. The repository is not updated and the previous index files will be used. Release: The following signatures couldn't be verified because the public key is not available: NO_PUBKEY 8B48AA6247928553 W: Some index files failed to download, they have been ignored, or old ones used instead. The solutions available are: To login into each of the server and run the following command to import the gpg key for that repo. sudo gpg --keyserver hkp://subkeys.pgp.net --recv-keys 8B48AA6247928553 sudo gpg --export --armor 8B48AA6247928553 | sudo apt-key add - But this requires logging into all of the individual servers and run the above two commands. I am looking for a way to correct by working on apt-repo server. Is there any way to do that.

    Read the article

  • Launch Rhythmbox using a Keyboard shorcut

    - by palerdot
    I use Rhythmbox all the time in my Ubuntu. Is it possible to have a custom shortcut like Ctrl+R in Ubuntu, which can launch the Rhythmbox window, even if it is playing in the background ? Since, the emphasis of Linux OS flavors is to use keyboards as much as possible instead of mouse, i thought this functionality might tremendously help me in my Ubuntu environment. The Keyboard shortcuts sections asks for a command; So, I'm not able to figure out how to give a custom keyboard shortcut to a program like Rhythmbox. I'm using 12.04 if that helps. Thanks.

    Read the article

  • Creating encrypted database for work

    - by Baldur
    My boss posed this problem to me: Encrypted: We need an encrypted database for miscellanious passwords we use at work that are currently only in people's head. Easily accessable: Someone needs to be able to quickly access specific passwords, possibly at hectic moments. This requires any sort of public key management (keeping it on a USB key in a sealed envelope?) to be relatively easy. Access control: The system should have groups of passwords where only specific people have access to specific groups. Recoverability: We need to make sure passwords from one group aren't lost even if the only users with direct access quit or pass away—hence we need some way where (for example) any two members of senior management may override the system (see the treshold link below) and retrieve all the passwords with their key. The first thing that jumped into my mind was some form of threshold and asymmetric cryptography but I don't want to reinvent the wheel, are there any solutions for this? Any software should preferrably be free and open-source.

    Read the article

  • How to set Fn+F2 to show battery's status throug OSD and not power statistics?

    - by papukaija
    In natty pressing Fn+F2 on my Samsung NC10 opened a new notification with the remaining battery power. After upgrading to Oneiric, it opens the power statistics. Is the a way to revert this change? Checking the battery status with the notification is much faster than finding it from the power statistics. I know that the remaining battery time can be set to be shown on the panel but I'm used to Fn+F2.

    Read the article

  • Create a unique ID by fuzzy matching of names (via agrep using R)

    - by tbrambor
    Using R, I am trying match on people's names in a dataset structured by year and city. Due to some spelling mistakes, exact matching is not possible, so I am trying to use agrep() to fuzzy match names. A sample chunk of the dataset is structured as follows: df <- data.frame(matrix( c("1200013","1200013","1200013","1200013","1200013","1200013","1200013","1200013", "1996","1996","1996","1996","2000","2000","2004","2004","AGUSTINHO FORTUNATO FILHO","ANTONIO PEREIRA NETO","FERNANDO JOSE DA COSTA","PAULO CEZAR FERREIRA DE ARAUJO","PAULO CESAR FERREIRA DE ARAUJO","SEBASTIAO BOCALOM RODRIGUES","JOAO DE ALMEIDA","PAULO CESAR FERREIRA DE ARAUJO"), ncol=3,dimnames=list(seq(1:8),c("citycode","year","candidate")) )) The neat version: citycode year candidate 1 1200013 1996 AGUSTINHO FORTUNATO FILHO 2 1200013 1996 ANTONIO PEREIRA NETO 3 1200013 1996 FERNANDO JOSE DA COSTA 4 1200013 1996 PAULO CEZAR FERREIRA DE ARAUJO 5 1200013 2000 PAULO CESAR FERREIRA DE ARAUJO 6 1200013 2000 SEBASTIAO BOCALOM RODRIGUES 7 1200013 2004 JOAO DE ALMEIDA 8 1200013 2004 PAULO CESAR FERREIRA DE ARAUJO I'd like to check in each city separately, whether there are candidates appearing in several years. E.g. in the example, PAULO CEZAR FERREIRA DE ARAUJO PAULO CESAR FERREIRA DE ARAUJO appears twice (with a spelling mistake). Each candidate across the entire data set should be assigned a unique numeric candidate ID. The dataset is fairly large (5500 cities, approx. 100K entries) so a somewhat efficient coding would be helpful. Any suggestions as to how to implement this?

    Read the article

  • unique log file with log4net

    - by Luca Romagnoli
    hi i'm using log4net for logging my website. Every day a new file is created like "filename.log24-06-2009" this is the code in the web.config file: <log4net> <appender name="RollingLogFileAppender" type="log4net.Appender.RollingFileAppender"> <file value="App_Data\Missioni.log" /> <appendToFile value="true" /> <rollingStyle value="Composite" /> <!--<datePattern value="yyyy-MM-dd" />--> <maxSizeRollBackups value="5" /> <maximumFileSize value="5MB" /> <layout type="log4net.Layout.PatternLayout"> <header value="[Header]&#xA;" /> <footer value="[Footer]&#xA;" /> <conversionPattern value="%date [%thread] %-5level %logger - %message%newline" /> </layout> </appender> <root> <level value="DEBUG" /> <appender-ref ref="RollingLogFileAppender" /> </root> </log4net> How can i do for use a unique log file? thanks

    Read the article

  • CodeGolf: Find the Unique Paths

    - by st0le
    Here's a pretty simple idea, in this pastebin I've posted some pair of numbers. These represent Nodes of a directed graph. The input to stdin will be of the form, (they'll be numbers, i'll be using an example here) c d q r a b b c d e p q so x y means x is connected to y (not viceversa) There are 2 paths in that example. a->b->c->d->e and p->q->r. You need to print all the unique paths from that graph The output should be of the format a->b->c->d->e p->q->r Notes You can assume the numbers are chosen such that one path doesn't intersect the other (one node belongs to one path) The pairs are in random order. They are more than 1 paths, they can be of different lengths. All numbers are less than 1000. If you need more details, please leave a comment. I'll amend as required. Shameless-Plug For those who enjoy Codegolf, please Commit at Area51 for its very own site:) (for those who don't enjoy it, please support it as well, so we'll stay out of your way...)

    Read the article

  • Non distinct Unique ID in MySQL database table.

    - by Geoff
    First of, a simplified version: I am wondering if I can create a trigger to activate during INSERT (it's actually LOAD DATA INFILE) and NOT enter records for an RMA already in my table? I have a table that has no records that are unique. Some may be duplicates but there is one field that I can use to know if the data has been entered or not. For instance RMA Op Days --------------------- 213 Repair 0.10 213 Test 0.20 213 Repair 0.10 So I could do an index on the three columns together but as you see it's possible for an RMA to be in a step for the same amount of time twice so it's possible to have duplicate records. This data comes from a report that I cannot edit and this is all it provides. The key is that an RMA's data is only in the report once so if my database already has that RMA in it's records I want to skip the loading of that RMA's records from the report. By all means please let me know if that didn't make sense, I'll Explain as needed. I'm sure it's not uncommon but I couldn't find anything on the net.

    Read the article

  • Creating one row of information in excel using a unique value

    - by user1426513
    This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

    Read the article

  • Reducing a set of non-unique elements via transformations

    - by Andrey Fedorov
    I have: 1) a "starting set" of not-necessarily-unique elements, e.x. { x, y, z, z }, 2) a set of transformations, e.x. (x,z) = y, (z,z) = z, x = z, y = x, and 3) a "target set" that I am trying to get by applying transformations to the starting set, e.x. { z }. I'd like to find an algorithm to generate the (possibly infinite) possible applications of the transformations to the starting set that result in the target set. For example: { x, y, z, z }, y => x { x, x, z, z }, x => z { z, x, z, z }, x => z { z, z, z, z }, (z, z) => z { z, z, z }, (z, z) => z { z, z }, (z, z) => z { z } This sounds like something that's probably an existing (named) problem, but I don't recognize it. Can anyone help me track it down, or suggest further reading on something similar?

    Read the article

  • Unique prime factors using HashSet

    - by theGreenCabbage
    I wrote a method that recursively finds prime factors. Originally, the method simply printed values. I am currently trying to add them to a HashSet to find the unique prime factors. In each of my original print statements, I added a primes.add() in order to add that particular integer into my set. My printed output remains the same, for example, if I put in the integer 24, I get 2*2*2*3. However, as soon as I print the HashSet, the output is simply [2]. public static Set<Integer> primeFactors(int n) { Set<Integer> primes = new HashSet<Integer>(); if(n <= 1) { System.out.print(n); primes.add(n); } else { for(int factor = 2; factor <= n; factor++) { if(n % factor == 0) { System.out.print(factor); primes.add(factor); if(factor < n) { System.out.print('*'); primeFactors(n/factor); } return primes; } } } return primes; } I have tried debugging via putting print statements around every line, but was unable to figure out why my .add() was not adding some values into my HashSet.

    Read the article

  • In App Purchase Unique Identifying Data

    - by dageshi
    O.K so I'm writing a iPhone travel guide, you purchase a subscription to a travel guide for 3 months, it downloads a fairly hefty database and for 3 months that database gets updated weekly with new stuff. Now what I'd like to do is make the user enter their email address as a one off action before they purchase their first guide, for China say. The purpose for doing this is 1) To allow me to contact the user by email when they add a note/tip for a particular place (the app will allow them to send notes & information to me) 2) To Uniquely identify who has purchased the subscription so that if they wipe their device and reinstall the app they can plug the email address in and pickup their subscriptions again. Or so they can use the same subscription on another device they own. My concerns are 1) Will Apple allow the email method of restoring functionality to a second or restored device? 2) As long as I tell the user what I'm using their email address for (aka I won't sell it to anyone else and use it for X purposes) will it be o.k to ask for said email address? And as a side note, can I tack the devices unique id onto my server comms to track devices or is apple going to through a hissy fit about that as well?

    Read the article

  • Five unique, random numbers from a subset

    - by tau
    I know similar questions come up a lot and there's probably no definitive answer, but I want to generate five unique random numbers from a subset of numbers that is potentially infinite (maybe 0-20, or 0-1,000,000). The only catch is that I don't want to have to run while loops or fill an array. My current method is to simply generate five random numbers from a subset minus the last five numbers. If any of the numbers match each other, then they go to their respective place at the end of the subset. So if the fourth number matches any other number, it will bet set to the 4th from the last number. Does anyone have a method that is "random enough" and doesn't involve costly loops or arrays? Please keep in mind this a curiosity, not some mission-critical problem. I would appreciate it if everyone didn't post "why are you having this problem?" answers. I am just looking for ideas. Thanks a lot!

    Read the article

  • How to get a unique WindowRef in a dockable Qt application on Mac

    - by Robin
    How do I get a unique WindowRef from a Qt application that includes docked windows on the Mac? My code boils down to: int main(int argc, char* argv[]) { QApplication* qtApp = new QApplication(argc, argv); MyQMainWindow mainwin; mainwin.show(); } class MyQMainWindow : public QMainWindow { //... QDockWidget* mDock; MyQWidget* mDrawArea; QStackedWidget* mCentralStack; }; MyQMainWindow::MyQMainWindow() { mDock = new QDockWidget(tr("Docked Widget"), this); mDock->setMaximumWidth(180); //... addDockWidget(Qt::RightDockWidgetArea, mDock); mDrawArea = new MyQWidget(this); mCentralStack = new QStackedWidget(); mCentralStack->addWidget(mDrawArea); // Other widgets added to stack in production code. setCentralWidget(mCentralStack); //... } (Apologies if the above isn't syntactically correct, it's just easier to illustrate than to describe.) I added the following temporary code at the end of the above constructor: HIViewRef view1 = (HIViewRef) mDrawArea->winId(); HIViewRef view2 = (HIViewRef) mDock->winId(); WindowRef win1 = HIViewGetWindow(view1); WindowRef win2 = HIViewGetWindow(view2); My problem is that view1 and view2 are different, but win1 and win2 are the same! I tried the following equivalent on Windows: HWND win1 = (HWND)(mCentralDrawArea->winId()); HWND win2 = (HWND)(mDock1->winId()); This time win1 and win2 are different. I need the window handle to pass on to a 3rd party SDK so that it can draw into the central area only. BTW, I appreciate that the winId() method comes with lots of portability warnings, but a substantial refactor is out of the question for me. The same goes for using Carbon instead of Cocoa. Thanks.

    Read the article

  • Appending unique values only in a linked list in C

    - by LuckySlevin
    typedef struct child {int count; char word[100]; inner_list*next;} child; typedef struct parent { char data [100]; inner_list * head; int count; outer_list * next; } parent; void append(child **q,char num[100],int size) { child *temp,*r,*temp2,*temp3; parent *out=NULL; temp = *q; temp2 = *q; temp3 = *q; char *str; if(*q==NULL) { temp = (child *)malloc(sizeof(child)); strcpy(temp->word,num); temp->count =size; temp->next=NULL; *q=temp; } else { temp = *q; while(temp->next !=NULL) { temp=temp->next; } r = (child *)malloc(sizeof(child)); strcpy(r->word,num); r->count = size; r->next=NULL; temp->next=r; } } This is my append function which I use for adding an element to my child list. But my problem is it only should append unique values which are followed by a string. Which means : Inputs : aaa bbb aaa ccc aaa bbb ccc aaa Append should act : For aaa string there should be a list like bbb->ccc(Not bbb->ccc->bbb since bbb is already there if bbb is coming more than one time it should be increase count only.) For bbb string there should be list like aaa->ccc only For ccc string there should be list like aaa only I hope i could make myself clear. Is there any ideas? Please ask for further info.

    Read the article

  • inserting unique date into txt document

    - by durian
    I'm trying this script to insert only a unique date into a text file, but it isn't working properly: $log_file_name = "logfile.txt"; $log_file_path = "log_files/$id/$log_file_name"; if(file_exists($log_file_path)){ $not = "not"; $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $file_contents = file_get_contents($log_file_path); $file_contents_arry = explode(";",$file_contents); if(!in_array($todaytodaydate,$file_contents_arry)){ $append = fopen($log_file_path, 'a'); $write = fwrite($append,$today); //writes our string to our file. $close = fclose($append); //closes our file } else { $append = fopen($log_file_path, 'a'); $write = fwrite($append,$not); //writes our string to our file. $close = fclose($append); //closes our file } } else{ mkdir("log_files/$id", 0700); $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $create = fopen($log_file_path, "w"); $write = fwrite($create, $today, $strlength); //writes our string to our file. $close = fclose($create); //closes our file } The problem is with the if else statement where it should be written if it's already in the array.

    Read the article

  • Get top 2 rows from each unique field in a column

    - by Sai
    I have a table named tblItemResources in which I want to get the only 2 rows from each unique field in a column named effectiveDate (order by: ascending): tblItemResources Table |   empID   |   effectiveDate    |    Company   |    Description |   0-123    |    2014-01-23     |   DFD Comp  |   Analyst |   0-234    |    2014-01-23     |   ABC Comp   |  Manager |   0-222    |    2012-02-19     |   CDC Comp  |  Janitor |   0-213    |    2012-03-13     |   CBB Comp  |  Teller and so on. Any help would be much appreciated.

    Read the article

  • return unique values from array

    - by Brad
    I have an array that contains cities, I want to return an array of all those cities, but it must be a unique list of the cities. The array below: Array ( [0] => Array ( [eventname] => Wine Tasting [date] => 12/20/2013 [time] => 17:00:00 [location] => Anaheim Convention Center [description] => This is a test description [city] => Anaheim [state] => California ) [1] => Array ( [eventname] => Circus [date] => 12/22/2013 [time] => 18:30:00 [location] => LAX [description] => Description for LAX event [city] => Anaheim [state] => California ) [2] => Array ( [eventname] => Blues Fest [date] => 3/14/2014 [time] => 17:00:00 [location] => Austin Times Center [description] => Blues concert [city] => Austin [state] => Texas ) ) Should return: array('Anaheim', 'Austin'); Any help is appreciated.

    Read the article

< Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >