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  • iPhone table header lables not showing up in Release build but show up OK in Debug build

    - by Robert
    My table header shows up ok with Release build or Debug build for the iPhone simulator, but the header labels only show up with debug build on the iPhone. No header labels show up on the iPhone for release build. Any ideas? Thanks, Robert My code for the header is below - (UIView *) tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)sectionNum { @try { // create the parent view that will hold header Label UIView* customView = [[[UIView alloc] initWithFrame:CGRectMake(HEADER_RELX_OFFSET, HEADER_RELY_OFFSET, HEADER_ROW_WIDTH, HEADER_HEIGHT)] autorelease]; UILabel* headerLabel = [[UILabel alloc] initWithFrame:CGRectZero]; headerLabel.backgroundColor = [UIColor clearColor]; headerLabel.opaque = NO; headerLabel.numberOfLines = 0; headerLabel.textColor = [UIColor blackColor]; headerLabel.highlightedTextColor = [UIColor whiteColor]; headerLabel.font = [UIFont boldSystemFontOfSize:HEADER_FONT_SIZE]; headerLabel.textAlignment = UITextAlignmentCenter; headerLabel.lineBreakMode = UILineBreakModeWordWrap; headerLabel.frame = CGRectMake(HEADER_RELX_OFFSET, HEADER_RELY_OFFSET, HEADER_ROW_WIDTH, HEADER_HEIGHT); if(sectionNum == 0) headerLabel.text = @"My Label"; else headerLabel.text = @""; [customView addSubview:headerLabel]; return customView; @catch (NSException* exception) { NSLog(@"viewForHeaderInSection: %@: %@",[exception name],[exception reason]); } }

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  • show image in a CGContextRef

    - by Ishu
    What i am doing, i downloded a code from calender now i want to show images on its tiles(for date). What i am trying shows in code - (void)drawTextInContext:(CGContextRef)ctx { CGContextSaveGState(ctx); CGFloat width = self.bounds.size.width; CGFloat height = self.bounds.size.height; CGFloat numberFontSize = floorf(0.3f * width); CGContextSetFillColorWithColor(ctx, kDarkCharcoalColor); CGContextSetTextDrawingMode(ctx, kCGTextClip); for (NSInteger i = 0; i < [self.text length]; i++) { NSString *letter = [self.text substringWithRange:NSMakeRange(i, 1)]; CGSize letterSize = [letter sizeWithFont:[UIFont boldSystemFontOfSize:numberFontSize]]; CGContextSaveGState(ctx); // I will need to undo this clip after the letter's gradient has been drawn [letter drawAtPoint:CGPointMake(4.0f+(letterSize.width*i), 0.0f) withFont:[UIFont boldSystemFontOfSize:numberFontSize]]; if ([self.date isToday]) { CGContextSetFillColorWithColor(ctx, kWhiteColor); CGContextFillRect(ctx, self.bounds); } else { // CGContextDrawLinearGradient(ctx, TextFillGradient, CGPointMake(0,0), CGPointMake(0, height/3), kCGGradientDrawsAfterEndLocation); CGDataProviderRef dataProvider = CGDataProviderCreateWithFilename("left-arrow.png"); CGImageRef image = CGImageCreateWithPNGDataProvider(dataProvider, NULL, NO, kCGRenderingIntentDefault); //UIImage* image = [UIImage imageNamed:@"left-arrow.png"]; //CGImageRef imageRef = image.CGImage; CGContextDrawImage(ctx, CGRectMake(8.0f+(letterSize.width*i), 0.0f, 5, 5), image); //im.image=[UIImage imageNamed:@"left-arrow.png"]; } CGContextRestoreGState(ctx); // get rid of the clip for the current letter } CGContextRestoreGState(ctx); } In else condition i want to show images on the tile so for that i am converting image objects in the CGContextDrawImage. Please help me. I am not sure this would be done in same manner or in other manner please suggest your way to do this. Thanx a lot.

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  • How to enter text into the "Write something..." box on Facebook and click Submit

    - by Peter Payne
    Hello, I am trying to manipulate Facebook pages in various ways, using Javascript browser elements. I'd need to be able to insert some text into the top "Type something..." box that shows on my site's fan page (or alternately, "click into" the field and I can type the text using GUI scripting), then click the "submit" button as if i'd done it by hand. It's tricky since the page is very Ajax heavy and I can't find the names of the elements I need to manipulate, let alone how to manipulate them as they're not using traditional form fields I'm used to. Can anyone help me figure out how to do this with javascript commands, which I'd be calling from Applescript on the Mac? Many thanks in advance. UPDATE Thanks for the comments below. Believe me, I am not trying to do anything spammy or douchy, mainly posting links to products that have gone live on page facebook page, but do it during the business day when people are on rather than at strange hours of the day. I am located in Japan so my sleep period is right when people are using FB. The solution I came up with for clicking the button was got using UI Browser, an outstanding tool if you're trying to script on the Mac. The script that clicked the button for me was: tell application "Safari" activate set thename to name of (get current tab of window 1) delay 3 tell application "System Events" tell process "Safari" try click button "Share" of group 1 of group 2 of list 3 of group 9 of UI element 1 of scroll area 1 of group 3 of window thename -- this one works on the mini? on error click button "Share" of group 1 of group 2 of list 3 of group 9 of UI element 1 of scroll area 1 of group 2 of window thename -- did not work end try end tell end tell end tell Hope this is useful to anyone.

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  • Significance in R

    - by Gemsie
    Ok, this is quite hard to explain, but I'm at a complete loss what to do. I'm a relative newcomer to R and although I can completely admire how powerful it is, I'm not too good at actually using it.... Basically, I have some very contrived data that I need to analyse (it wasn't me who chose this, I can assure you!). I have the right and left hand lengths of lots of people, as well as some numeric data that shows their sociability. Now I would like to know if people who have significantly different lengths of hand are more or less sociable than those who have the same (leading into the research that 'symmetrical' people are more sociable and intelligent, etc. I have got as far as loading the data into R, then I have no idea where to go from there. How on Earth do I start to separate those who are close to symmetrical to those who aren't to then start to do the analysis? Ok, using Sasha's great advice, I did the cor.test and got the following: Pearson's product-moment correlation data: measurements$l.hand - measurements$r.hand and measurements$sociable t = 0.2148, df = 150, p-value = 0.8302 alternative hypothesis: true correlation is not equal to 0 95 percent confidence interval: -0.1420623 0.1762437 sample estimates: cor 0.01753501 I have never used this test before, so am unsure how to intepret it...you wouldn't think I was on my fourth Scientific degree would you?! :(

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  • LINQ : How to query how to sort result by most similarity/equality

    - by aNui
    I want to do a search for Music instruments which has its informations Name, Category and Origin as I asked in my post. But now I want to sort/group the result by similarity/equality to the keyword such as. If I have the list { Harp, Piano, Drum, Guitar, Guitarrón } and if I queried "p" the result should be { Piano, Harp } but it shows Harp first because of the list's sequence and if I add {Grand Piano} to the list and query "piano" the result shoud be like { Piano, Grand Piano } here's my code static IEnumerable<MInstrument> InstrumentsSearch(IEnumerable<MInstrument> InstrumentsList, string query, MInstrument.Category[] SelectedCategories, MInstrument.Origin[] SelectedOrigins) { var result = InstrumentsList .Where(item => SelectedCategories.Contains(item.category)) .Where(item => SelectedOrigins.Contains(item.origin)) .Where(item => { if ( (" " + item.Name.ToLower()).Contains(" " + query.ToLower()) || item.Name.IndexOf(query) != -1 ) { return true; } return false; } ) .Take(30); return result.ToList<MInstrument>(); } Or the result may be like my old self-invented algorithm that I called "by order of occurence", that is just OK to me. Is there any way to do that, please tell me. Thanks in advance.

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  • Master Detail same View binding controls

    - by pipelinecache
    Hi everyone, say I have a List View with ItemControls. And a Details part that shows the selected Item from List View. Both are in the same xaml page. I tried everything to accomplish it, but what do I miss? <!-- // List --> <ItemsControl ItemsSource="{Binding Path=Model, ElementName=SomeListViewControl, Mode=Default}" SnapsToDevicePixels="True" Focusable="False" IsTabStop="False"> <ItemsControl.ItemTemplate> <DataTemplate> <SomeListView:SomeListItemControl x:Name=listItem/> </DataTemplate> </ItemsControl.ItemTemplate> </ItemsControl> <!-- // Details --> <Label Content="Begindatum" FontSize="16" VerticalAlignment="Center" Grid.Row="1" Margin="2,0,0,0"/> <TextBox x:Name="Begindatum" Grid.Column="1" Grid.Row="1" Text="{Binding Path=BeginDate, ElementName=listItem,Converter={StaticResource DateTimeConverter}, ConverterParameter=dd-MM-yyyy}" IsEnabled="False" Style="{DynamicResource TextBoxStyle}" MaxLength="30"/> public event EventHandler<DataEventArgs<SomeEntity>> OnOpenSomething; public ObservableCollection<SomeEntity> Model { get { return (ObservableCollection<SomeEntity>)GetValue(ModelProperty); } set { Model.CollectionChanged -= new NotifyCollectionChangedEventHandler(Model_CollectionChanged); SetValue(ModelProperty, value); Model.CollectionChanged += new NotifyCollectionChangedEventHandler(Model_CollectionChanged); UpdateVisualState(); } } public static readonly DependencyProperty ModelProperty = DependencyProperty.Register("Model", typeof(ObservableCollection<SomeEntity>), typeof(SomeListView), new UIPropertyMetadata(new ObservableCollection<SomeEntity>(), new PropertyChangedCallback(ChangedModel))); private static void ChangedModel(DependencyObject source, DependencyPropertyChangedEventArgs e) { SomeListView someListView = source as SomeListView; if (someListView.Model == null) { return; } CollectionView cv = (CollectionView)CollectionViewSource.GetDefaultView(someListView.Model); } private void Model_CollectionChanged(object sender, NotifyCollectionChangedEventArgs e) { if (Model == null) { return; } }

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  • Javascript + PHP $_POST array empty

    - by Peterim
    While trying to send a POST request via xmlhttp.open("POST", "url", true) (javascript) to the server I get an empty $_POST array. Firebug shows that the data is being sent. Here is the data string from Firebug: a=1&q=151a45a150.... But $_POST['q'] returns nothing. The interesting thing is that file_get_contents('php://input') does have my data (the string above), but PHP somehow doesn't recognize it. Tried both $_POST and $_REQUEST, nothing works. Headers being sent: POST /test.php HTTP/1.1 Host: website.com User-Agent: Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us;q=0.7,en;q=0.3 Accept-Encoding: gzip,deflate Accept-Charset: utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://website.com/ Content-Length: 156 Content-Type: text/plain; charset=UTF-8 Pragma: no-cache Cache-Control: no-cache Thank you for any suggestions.

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  • Storing and loading a subtitle of an annotation with NSUserDefualts

    - by Krismutt
    Happy new year everybody! Basically, what I try to do is to save a subtitle to an annotation when the application terminates. When the application starts again I want this stored subtitle to show up in the callout of the annotation again. What am I doing wrong? I just can't get it to work... storeLocation.m - (void)setCoordinate:(CLLocationCoordinate2D)coor { MKReverseGeocoder *geocoder = [[[MKReverseGeocoder alloc] initWithCoordinate:coor] autorelease]; geocoder.delegate = self; coordinate = coor; [geocoder start]; NSUserDefaults *userDef = [NSUserDefaults standardUserDefaults]; [userDef setValue:subtitle forKey:@"SavedAddress"]; [userDef synchronize]; NSLog(@"Sparade adress"); } mainViewController.m -(void)viewDidLoad { NSString *savedAddress = [[NSUserDefaults standardUserDefaults] objectForKey:@"SavedAddress"]; if (savedAddress) { // what code should I add here // so that the subtitle shows up // when the application launches? } } Would really appreciate some help with this one... Thanks in advance!

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  • SSRS 2008 - Sending report as email

    - by Mozy
    Hi all, What I want to do is render a SSRS 2008 report as HTML (actually MHTML) and send that as the body in an email. Has anyone done this? I've almost got it (I think) but I seem to have a encoding problem. The email shows up as what looks like some sort of base64 encoding. Like this: MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_NextPart_01C35DB7.4B204430" X-MSSQLRS-ProducerVersion: V10.0.2531.0 This is a multi-part message in MIME format. ------=_NextPart_01C35DB7.4B204430 Content-ID: Content-Disposition: inline; filename="FollowUpNotification" Content-Type: text/html; name="FollowUpNotification"; charset="utf-8" Content-Transfer-Encoding: base64 PCFET0NUWVBFIEhUTUwgUFVCTElDICItLy9XM0MvL0RURCBIVE1MIDQuMDEgVHJhbnNp... Any ideas on what I'm missing? Here is a code snippet: myMail.BodyEncoding = System.Text.Encoding.UTF8; myMail.IsBodyHtml = true; WebClient client = new WebClient(); System.Net.NetworkCredential repAuthenticationInfo = new System.Net.NetworkCredential(@"username", @"password"); client.Credentials = repAuthenticationInfo; client.Encoding = System.Text.Encoding.UTF8; string messageBody = client.DownloadString( "http://<<reportserver>>&rs%3aFormat=MHTML&Parameter=" + Parameter); myMail.Body = messageBody;

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  • Returning XML natively in a .NET (C#) webservice?

    - by James McMahon
    I realize that SOAP webservices in .NET return XML representation of whatever object the web method returns, but if I want to return data formatting in XML what is the best object to store it in? I am using the answer to this question to write my XML, here is the code: XmlWriter writer = XmlWriter.Create(pathToOutput); writer.WriteStartDocument(); writer.WriteStartElement("People"); writer.WriteStartElement("Person"); writer.WriteAttributeString("Name", "Nick"); writer.WriteEndElement(); writer.WriteStartElement("Person"); writer.WriteStartAttribute("Name"); writer.WriteValue("Nick"); writer.WriteEndAttribute(); writer.WriteEndElement(); writer.WriteEndElement(); writer.WriteEndDocument(); writer.Flush(); Now I can return this output as a String to my calling webmethod, but it shows up as <string> XML HERE </string>, is there anyway to just return the full xml? Please in your answer, give an example of how to use said object with either XmlWriter or another internal object (if you consider XmlWriter to be a poor choice). The System.Xml package (namespace) has many objects, but I haven't been able to uncover decent documentation on how to use the objects together, or what to use for what situations.

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  • NSArray containObjects method

    - by Anthony Chan
    Hi, I have a simple question regarding xcode coding but don't know why things are not performing as I think. I have an array of objects (custom objects). I just want to check if this one is within the array. I used the following code: NSArray *collection = [[NSArray alloc] initWithObjects:A, B, C, nil]; //custom "Item" objects Item *tempItem = [[Fruit alloc] initWithLength:1 width:2 height:3]; //3 instance variables in "Item" objects if([collection containsObject:tempItem]) { NSLog(@"collection contains this item"); } I suppose the above checking will give me a positive result but it's not. Further, I checked whether the objects created are the same. NSLog(@"L:%i W:%i H:%i", itemToCheck.length, itemToCheck.width, itemToCheck.height); for (int i = 0, i < [collection count], i++) { Item *itemInArray = [collection objectAtIndex:i]; NSLog(@"collection contains L:%i W:%i H:%i", itemInArray.length, itemInArray.width, itemInArrayheight); } In the console, this is what I got: L:1 W:2 H:3 collection contains L:0 W:0 H:0 collection contains L:1 W:2 H:3 collection contains L:6 W:8 H:2 Obviously the tempItem is inside the collection array but nothing shows up when I use containsObject: to check it. Could anyone give me some direction which part I am wrong? Thanks a lot!

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  • VS2010 error: Unable to start debugging on the web server

    - by GarDavis
    I get error message "Unable to start debugging on the web server" in Visual Studio 2010. I clicked the Help button and followed the related suggestions without success. This happens with a newly created local ASP.Net project when modified to use IIS instead of Cassini (which works for debugging). It prompts to set debug="true" in the web.config and then immediately pops up the error. Nothing shows up in the Event Viewer. I am able to attach to w3wp to debug. It works but is not as convenient as F5. I also have a similar problem with VS2008 on the same PC. Debugging used to work for both. I have re-registered Framework 4 (aspnet_regiis -i). I ran the VS2010 repair (this is the RTM version). I am running on a Windows Server 2008 R2 x64 box. I do have Resharper V5 installed. There must be some configuration setting or registry value that survives the repair causing the problem. I'd appreciate any ideas. Thanks, Gary Davis ([email protected])

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  • SQL Server log backups "stalling"

    - by MattK
    I have interited a box running SQL Server 2008 and Windows 2003, and have had a few events where largeish (35GB) log backups "stall", both before and after the installation of SQL 2008 SP1. The server log ships to a standby, so regular log backups are taken at 15 minute intervals. However, after an index reorg causes the log to grow to about 35GB (on a DB with about 17GB of data), the next log backup runs to ~95% completion, then seems to stop. The process shows as suspended, with a wait state of BACKUPIO. CPU, read, and write activity on the SPID also does not change, and the process stays in this state for hours, when normally a backup of this size should complete in about 20 minutes. This server has a single RAID-1 volume, thus the source database files and destination backup files are on the same volume. However, I cannot determine if another process is blocking the backup. The backup SPID cannot be killed, and the only way to terminate the log backup and clear the lock on the backup file is to cycle the SQL Server service. There was one event where the backup terminated completely, with an error that another process had locked the backup file, but no details about what that process was. Can anyone suggest a cause or diagnostic process to this situation?

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  • How to repeatedly show a Dialog with PyGTK / Gtkbuilder?

    - by Julian
    I have created a PyGTK application that shows a Dialog when the user presses a button. The dialog is loaded in my __init__ method with: builder = gtk.Builder() builder.add_from_file("filename") builder.connect_signals(self) self.myDialog = builder.get_object("dialog_name") In the event handler, the dialog is shown with the command self.myDialog.run(), but this only works once, because after run() the dialog is automatically destroyed. If I click the button a second time, the application crashes. I read that there is a way to use show() instead of run() where the dialog is not destroyed, but I feel like this is not the right way for me because I would like the dialog to behave modally and to return control to the code only after the user has closed it. Is there a simple way to repeatedly show a dialog using the run() method using gtkbuilder? I tried reloading the whole dialog using the gtkbuilder, but that did not really seem to work, the dialog was missing all child elements (and I would prefer to have to use the builder only once, at the beginning of the program). [SOLUTION] As pointed out by the answer below, using hide() does the trick. But one has to take care that the dialog is in fact destroyed if one does not catch its "delete-event". A simple example that works is: import pygtk import gtk class DialogTest: def rundialog(self, widget, data=None): self.dia.show_all() result = self.dia.run() def destroy(self, widget, data=None): gtk.main_quit() def closedialog(self, widget, data=None): self.dia.hide() return True def __init__(self): self.window = gtk.Window(gtk.WINDOW_TOPLEVEL) self.window.connect("destroy", self.destroy) self.dia = gtk.Dialog('TEST DIALOG', self.window, gtk.DIALOG_MODAL | gtk.DIALOG_DESTROY_WITH_PARENT) self.dia.vbox.pack_start(gtk.Label('This is just a Test')) self.dia.connect("delete-event", self.closedialog) self.button = gtk.Button("Run Dialog") self.button.connect("clicked", self.rundialog, None) self.window.add(self.button) self.button.show() self.window.show() if __name__ == "__main__": testApp = DialogTest() gtk.main()

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  • -[UITableViewRowData isEqualToString:]: unrecognized selector sent to instance 0x391dce0

    - by tak
    I have a datatable which shows the list of contacts. when I start the application all the data is loaded correctly.But after selecting a contact, I am sometimes getting this exception :- Program received signal: “EXC_BAD_ACCESS”. and sometimes -[UITableViewRowData isEqualToString:]: unrecognized selector sent to instance 0x391dce0 most probably for this code:- - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } ExpenseTrackerAppDelegate *appDelegate = (ExpenseTrackerAppDelegate *)[[UIApplication sharedApplication] delegate]; Person *person = (Person *)[appDelegate.expensivePersonsList objectAtIndex:indexPath.row]; NSString *name = (NSString *)[NSMutableString stringWithFormat:@"%@ %@" ,person.lastName , person.firstName]; cell.textLabel.text = name; //cell.detailTextLabel.text = person.lastName; // Configure the cell. return cell; } If I replace these lines of code NSString *name = (NSString *)[NSMutableString stringWithFormat:@"%@ %@" ,person.lastName , person.firstName]; cell.textLabel.text = name; with this code cell.textLabel.text = person.lastName; then everything works fine? I dont know what exactly happens?

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  • Facebook not recoginising open graph tags

    - by Pratik Poddar
    My object page looks like: <html xmlns="http://www.w3.org/1999/xhtml" dir="ltr" lang="en-US" xmlns:fb="https://www.facebook.com/2008/fbml"> <head prefix="og: http://ogp.me/ns# cliprin: http://ogp.me/ns/apps/cliprin#"> <meta property="fb:app_id" content="143944345745133" /> <meta property="og:type" content="cliprin:product" /> <meta property="og:url" content="https://itsourstudio.com/" /> <meta property="og:title" content="LED Ice Cubes (Set Of 4)" /> <meta property="og:sitename" content="Its Our Studio" /> <meta property="og:image" content="https://s-static.ak.fbcdn.net/images/devsite/attachment_blank.png" /> <meta property="og:description" content="Blah Blah Blah" /> </head> </html> The JSLink Debugger of the page as shown by the link shows that of:type is website and gives following warnings: Open Graph Warnings That Should Be Fixed Inferred Property: The 'og:url' property should be explicitly provided, even if a value can be inferred from other tags. Inferred Property: The 'og:title' property should be explicitly provided, even if a value can be inferred from other tags. Inferred Property: The 'og:description' property should be explicitly provided, even if a value can be inferred from other tags. Inferred Property: The 'og:image' property should be explicitly provided, even if a value can be inferred from other tags. Tiny og:image: All the images referenced by og:image must be at least 200px in both dimensions. Please check all the images with tag og:image in the given url and ensure that it meets the minimum specification.

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  • Javascript onclick event is not working in internet explorer 8.

    - by Mallika Iyer
    Hi, I have the following line of code that works fine in Firefox, Chrome and Safari, but not in internet explorer 8. <a href="javascript:void(0);" onclick="showHide('reading','type_r','r');">Show me the example</a> The function simply shows and hides a div on clicking the hyperlink. Is there anything I'm missing here? This is the showHide function: function showHide(elementId,parentId,qtype) { if (document.getElementById && !document.all) { var elementParent = document.getElementById(parentId); var element = document.getElementById(elementId); var upArrowId = 'up-arrow-'+qtype; var downArrowId = 'down-arrow-'+qtype; if(element.style.visibility == 'hidden'){ elementParent.style.height = 'auto'; element.style.visibility = 'visible'; document.getElementById(upArrowId).style.visibility = 'visible'; document.getElementById(downArrowId).style.visibility = 'hidden'; } else if(element.style.visibility == 'visible'){ element.style.visibility = 'hidden'; elementParent.style.height = '50px'; document.getElementById(upArrowId).style.visibility = 'hidden'; document.getElementById(downArrowId).style.visibility = 'visible'; } } } Thanks.

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  • Association Mapping Details confusion?

    - by AaronLS
    I have never understood why the associations in EntityFramework look the way they do in the Mapping Details window. When I select the line between 2 tables for an association, for example FK_ApplicationSectionsNodes_FormItems, it shows this: Association Maps to ApplicationSectionNodes FormItems (key symbol) FormItemId:Int32 <--> FormItemId:int ApplicationSectionNodes (key symbol) NodeId:Int32 <--> (key symbol) NodeId : int Fortunately this one was create automatically for me based on the foreign key constraints in my database, but whenever no constraints exist, I have a hard to creating associations manually(when the database doesn't have a diagram setup) because I don't understand the mapping details for associations. FormItems table has a primary key identity column FormItemId, and ApplicationSectionNodes contains a FormItemId column that is the foreign key and has NodeId as a primary key identity column. What really makes no sense to me is why the association has anything listed about the NodeId, when NodeId doesn't have anything to do with the foreign key relationship? (It's even more confusing with self referencing relationships, but maybe if I could understand the above case I'd have a better handle). CREATE TABLE [dbo].[ApplicationSectionNodes]( [NodeID] [int] IDENTITY(1,1) NOT NULL, [OutlineText] [varchar](5000) NULL, [ParentNodeID] [int] NULL, [FormItemId] [int] NULL, CONSTRAINT [PK_ApplicationSectionNodes] PRIMARY KEY CLUSTERED ( [NodeID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY], CONSTRAINT [UQ_ApplicationSectionNodesFormItemId] UNIQUE NONCLUSTERED ( [FormItemId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[ApplicationSectionNodes] WITH NOCHECK ADD CONSTRAINT [FK_ApplicationSectionNodes_ApplicationSectionNodes] FOREIGN KEY([ParentNodeID]) REFERENCES [dbo].[ApplicationSectionNodes] ([NodeID]) GO ALTER TABLE [dbo].[ApplicationSectionNodes] NOCHECK CONSTRAINT [FK_ApplicationSectionNodes_ApplicationSectionNodes] GO ALTER TABLE [dbo].[ApplicationSectionNodes] WITH NOCHECK ADD CONSTRAINT [FK_ApplicationSectionNodes_FormItems] FOREIGN KEY([FormItemId]) REFERENCES [dbo].[FormItems] ([FormItemId]) GO ALTER TABLE [dbo].[ApplicationSectionNodes] NOCHECK CONSTRAINT [FK_ApplicationSectionNodes_FormItems] GO FormItems Table: CREATE TABLE [dbo].[FormItems]( [FormItemId] [int] IDENTITY(1,1) NOT NULL, [FormItemType] [int] NULL, CONSTRAINT [PK_FormItems] PRIMARY KEY CLUSTERED ( [FormItemId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[FormItems] WITH NOCHECK ADD CONSTRAINT [FK_FormItems_FormItemTypes] FOREIGN KEY([FormItemType]) REFERENCES [dbo].[FormItemTypes] ([FormItemTypeId]) GO ALTER TABLE [dbo].[FormItems] NOCHECK CONSTRAINT [FK_FormItems_FormItemTypes] GO

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  • "Access is denied" by executing .hta file with JScript on Windows XP x64

    - by mem64k
    I have a simple HTML (as HTA) application that shows strange behavior on Windows XP x64 machine. I getting periodically (not every time) error message "Access is denied." when i start the application. The same application on Windows XP 32bit runs just fine... Does somebody has any idea or explanation? Error message: Line: 18 Char: 6 Error: Access is denied. Code: 0 URL: file:///D:/test_j.hta Here is the code of my "test_j.hta": <html> <head> <title>Test J</title> <HTA:APPLICATION ID="objTestJ" APPLICATIONNAME="TestJ" SCROLL="no" SINGLEINSTANCE="yes" WINDOWSTATE="normal" > <script language="JScript"> function main() { //window.alert("test"); window.resizeTo(500, 300); } function OnExit() { window.close(); } </script> </head> <body onload="main()"> <input type="button" value="Exit" name="Exit" onClick="OnExit()" title="Exit"> </body> </html>

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  • Why doesn't setting clearTaskOnLaunch="true" cause OnCreate to be called?

    - by cbrauer
    My application works fine, once it is initialized in the OnCreate method of my View class. However, when I open my app after the Droid phone has been sitting idle all night, the OnCreate method is not being called. I use the OnCreate to initialize data, and that in turn initializes the GUI. The GUI clearly shows that OnCreate was not called. I tried setting clearTaskOnLaunch="true" in my Manifest. My Manifest is: <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.hedgetools.trin" android:versionCode="2" android:versionName="1.02"> <application android:icon="@drawable/icon" android:label="@string/app_name" android:clearTaskOnLaunch="true"> <activity android:name=".Trin" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <uses-sdk android:minSdkVersion="6" /> <uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /> </manifest> This did not help. My OnCreate method is not being call after the Droid phone sits idle all night. Why doesn’t clearTaskOnLaunch cause OnCreate to be called? Any help or suggestions will be greatly appreciated. Charles

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  • can someone help me with why my OnClickListener won't work? Android

    - by clayton33
    Is there something simple i might be missing? The "kruis" picture shows up on my ImageButton, so i'm pretty sure my main.xml is good, but when i click on the ImageButton, i get no Toast and testView does not change... been struggling for a few hours on this now, not sure what i'm doing wrong! package com.matchit; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.ImageButton; import android.widget.TextView; import android.widget.Toast; public class matchit extends Activity { OnClickListener cardListener; TextView testView; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); testView = (TextView)findViewById(R.id.test); ImageButton b1 = (ImageButton)findViewById(R.id.card1); b1.setImageResource(R.drawable.kruis); b1.setOnClickListener(cardListener); cardListener = new OnClickListener(){ @Override public void onClick(View v) { testView.setText("its working"); Toast.makeText(getApplicationContext(), "its working", Toast.LENGTH_LONG).show(); } }; } }

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  • Codeigniter achor producing dodgy link in email inbox.. what could the problem be?

    - by Psychonetics
    My application is emailing out fine but the email I receive displays incorrectly. Rather than have text and a simple "click here to activate" link it doesn't. it shows this instead: Hi user1, please click the following link to activate your account <a href="http://mysite.com/activation/fzyZuyxVAzZS2koVg5UFjfVjlcLNcrzp">ssss</a> Here is the code from my model that sends email to user when they request activation email. $this->load->library('email'); $this->email->from('[email protected]', 'my site'); $this->email->to($result[0]->email); $this->email->subject('my site - Activate your account'); $this->email->message('Hi ' . $result[0]->first_name . ', please click the following link to activate your account ' . anchor('http://mysite.com/activation/' . $new_activation_code, 'click here to activate')); $this->email->send(); Also the mail always ends up in my spam folder.

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  • Hide Image Title in Slimbox

    - by Stephen
    My issue is a lot like this solved thread, except I'm using Slimbox 2: http://stackoverflow.com/questions/940994/hide-image-title-tool-tip-popup-on-mouse-rollover-or-hover When you hover over an image, the "Title" attribute pops up. I need HTML in my image title in Slimbox. So, of course, when you're hovering, the "Title" attribute shows all the HTML code. The code works perfectly when you're viewing the image in Slimbox so no problems there. I just need the Title attribute to be hidden/modified not to show this HTML code. I tried to change Q.title in slimbox.js to something else (like captionname). Then changed the HTML to call for: <a href="images/team/large.jpg" title="Joe Smith" captionname="URL" rel="lightbox-team"><img src="images/team/small.jpg" class ="headline" border="1" hspace="2" /></a> "Joe Smith" displays as the Title but when you view the image in Slimbox, captionname does not come up at all and neither does the Title. It's just blank where it should be. What do I need to modify in slimbox2.js to make this work?

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  • Xcode: Display Login View in applicationDidBecomeActive

    - by Patrick
    In my app I would like to show a login screen - which will be displayed when the app starts and when the app becomes active. For reference, I am using storyboards, ARC and it is a tabbed bar application. First off, I have this method which returns the topViewController. - (UIViewController *)topViewController:(UIViewController *)rootViewController { if (rootViewController.presentedViewController == nil) { return rootViewController; } if ([rootViewController.presentedViewController isMemberOfClass:[UINavigationController class]]) { UINavigationController *navigationController = (UINavigationController *)rootViewController.presentedViewController; UIViewController *lastViewController = [[navigationController viewControllers] lastObject]; return [self topViewController:lastViewController]; } UIViewController *presentedViewController = (UIViewController *)rootViewController.presentedViewController; return [self topViewController:presentedViewController]; } And I call this method here: - (void)applicationDidBecomeActive:(UIApplication *)application { if ( ... ) { // if the user needs to login PasswordViewController *passwordView = [[PasswordViewController alloc] init]; UIViewController *myView = [self topViewController:self.window.rootViewController]; [myView presentModalViewController:passwordView animated:NO]; } } To an extent this does work - I can call a method in viewDidAppear which shows an alert view to allow the user to log in. However, this is undesirable and I would like to have a login text box and other ui elements. If I do not call my login method, nothing happens and the screen stays black, even though I have put a label and other elements on the view. Does anyone know a way to resolve this? My passcode view is embedded in a Navigation Controller, but is detached from the main storyboard.

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  • Rails database relationships

    - by Danny McClelland
    Hi Everyone, I have three models that I want to interact with each other. Kase, Person and and Company. I have (I think) setup the relationships correctly: class Kase < ActiveRecord::Base #HAS ONE COMPANY has_one :company #HAS MANY PERSONS has_many :persons class Person < ActiveRecord::Base belongs_to :company class Company < ActiveRecord::Base has_many :persons def to_s; companyname; end I have put the select field on the create new Kase view, and the create new Person view as follows: <li>Company<span><%= f.select :company_id, Company.all %> </span></li> All of the above successfully shows a drop down menu dynamically populated with the company names within Companies. What I am trying to do is display the contact of the Company record within the kase and person show.html.erb. For example, If I have a company called "Acme, Inc." and create a new Kase called "Random Case" and choose within the create new case page "Acme, Inc." from the companies drop down menu. I would then want to display "Acme, Inc" along with "Acme, Inc. Mobile" etc. on the "Random Case" show.html.erb. I hope this makes sense to somebody! Thanks, Danny

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