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  • Simple Search and Replace use of Regular Expression

    - by nunos
    So, I am adapting some code I found online to suit my needs. However, my set_pixel function has two more parameters. Since there are lots of calls to this function even doing a quick paste over would be very tedious. So, I thought this would be a good time for me to learn some simple regular expressions. So, I have calls of this type: set_pixel(arg1, arg2); which I want to change to something like: set_pixel(arg1, arg2, arg3, arg4); Note: arg1 and and 2 should be preserved, whereas arg3 and arg4 are most of the time the same. How can I achieve this?

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  • regular expression on replace method of js not working

    - by user950146
    why this is not working var value = arr[row][col].replace(new RegExp('"', 'g'),'""'); Error : Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; Tablet PC 2.0) Timestamp: Tue, 10 Apr 2012 11:22:01 UTC Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Note: : Error copied directly from debugger of IE8

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  • Help to write regular expression

    - by Ockonal
    Hello, I have to get any text between: Final-Recipient: RFC822; !HERE! Action I need !HERE! from this example. There could be any string. I tried something like: $Pattern = '/Final-Recipient: RFC822; (.*) Action/'; But it doesn't work. upd Here is the string I'm trying to parse: http://dpaste.com/187638/

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  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

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  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

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  • regular expression for validation not working

    - by Camran
    I have a "description textarea" inside a form where user may enter a description for an item. This is validated with javascript before the form beeing submitted. One of the validation-steps is this: else if (!fld.value.match(desExp)){ And desExp: var desExp = /^\s*(\w[^\w]*){3}.*$/gm; Now my problem, this works fine on all cases except for descriptions where the description BEGINS with a special character of the swedish language (å, ä, ö). This wont work: åäö hello world But this will: hello world åäö Any fixes? Thanks

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  • Multiline Regular Expression search and replace!

    - by Scott
    I've hit a wall. Does anybody know a good text editor that has search and replace like Notepad++ but can also do multi-line regex search and replace? Basically, I am trying to find something that can match a regex like: search oldlog\(.*\n\s+([\r\n.]*)\);replace newlog\(\1\) Any ideas?

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • How to replace the string based on an expression

    - by deepak
    I'm having a string where i'm using some placeholders to replace it with some values based on an object. It is like the following: Hello User <#= UserName #> I need to replace the <#= UserName # with a value. How can this be done with a regex? Please help. I dont want a string replace solution. There are somany placeholders and hardcoding the <#= UserName # and replace with the value is pointless

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  • Regular Expression: Match untill pattern is found

    - by ZafarYousafi
    Hi, I want to extract the status from the string untill I found a timespan. My input is something like "Something in start but not with this keyword of sure. STATUS: My Status Is Here Which can be anything but timespan 23:59:01 and so on. I want to extract the string after STATUS: untill 23:59:01 is found. How can i achieve this through regex. this 23:59:01 is a timespan and it is always in this format hh:mm:ss

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  • Regular Expression

    - by Blanca
    Hi! i would like to avoid texts like this one: height="49" with a regular expresion. I tought in .replaceAll("\s*="*"",""); (replaceAll is used as a method in a java class), but eclipse don't allowed me to do that. Any other suggestion?? tx!

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  • Substitute all matches with values in Ruby regular expression

    - by Lewisham
    Hi all, I'm having a problem with getting a Ruby string substitution going. I'm writing a preprocessor for a limited language that I'm using, that doesn't natively support arrays, so I'm hacking in my own. I have a line: x[0] = x[1] & x[1] = x[2] I want to replace each instance with a reformatted version: x__0 = x__1 & x__1 = x__2 The line may include square brackets elsewhere. I've got a regex that will match the array use: array_usage = /(\w+)\[(\d+)\]/ but I can't figure out the Ruby construct to replace each instance one by one. I can't use .gsub() because that will match every instance on the line, and replace every array declaration with whatever the first one was. .scan() complains that the string is being modified if you try and use scan with a .sub()! inside a block. Any ideas would be appreciated!

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  • Sed: regular expression match lines without <!--

    - by sixtyfootersdude
    I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

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  • dropping characters from regular expression groups

    - by tcurdt
    The goal: I want to convert a number from the format "10.234,56" to "10234.56" Using this simple approach almost gets us there /([\d\.]+),(\d\d)/ => '\1.\2' The problem is that the first group of the match (of course) still contains the '.' character. So questions are: Is it possible to exclude a character from the group somehow? How would you solve this with a single regexp (I know this is a trivial problem when not using a single regexp)

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  • jQuery validation required( dependency-expression ) only 1 input validating

    - by user331884
    <script type="text/javascript"> $(function () { $("#form1").validate(); $("#survey1 .response").rules("add", { required: function () { return $('#choices').val() != '' } }); }); </script> <form id="form1" runat="server"> <div id="survey1"> <asp:DropDownList ID="choices" runat="server"> <asp:ListItem Value="">--Select--</asp:ListItem> <asp:ListItem>1</asp:ListItem> <asp:ListItem>2</asp:ListItem> </asp:DropDownList> <hr /> Response 1<br /> <asp:TextBox ID="TextBox1" runat="server" TextMode="MultiLine" Rows="6" CssClass="response"></asp:TextBox> <hr /> Response 2<br /> <asp:TextBox ID="TextBox2" runat="server" TextMode="MultiLine" Rows="6" CssClass="response"></asp:TextBox> </div></form> Only the first textbox gets validated. Am I missing something?

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