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  • python regular expression for domain names

    - by user230911
    I am trying use the following regression to extract domain name from a text, but it just produce nothing, what's wrong with it? I don't know if this is suitable to ask this "fix code" question, maybe I should read more. I just want to save some time. Thanks pat_url = re.compile(r''' (?:https?://)* (?:[\w]+[\-\w]+[.])* (?P<domain>[\w\-]*[\w.](com|net)([.](cn|jp|us))*[/]*) ''') print re.findall(pat_url,"http://www.google.com/abcde") I want the output to be google.com

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  • Regular Expressions, Checking for a range of occurrences

    - by gmcalab
    I have a phone number I want to match against a regular expression. The format of the phone number must match this: (123) 123-4567 x12345 The extension is optional. Also the extension must contain 1-5 numbers. Below is a regular expression I wrote that works. ^\(\d{3}\) \d{3}-\d{4}( x\d\d?\d?\d?\d?)?$ I was wondering if there is a better way to check for the extension instead of x\d\d?\d?\d?\d? Can I say 1-5 occurrences of \d instead of the above some how ?

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  • Java: using foreach over strings from arrayList does not print anything

    - by HH
    $ javac ArrayListTest.java $ java ArrayListTest $ cat ArrayListTest.java import java.io.*; import java.util.*; public class ArrayListTest{ public static void main(String[] args) { try { String hello ="oeoaseu oeu hsoae sthoaust hoaeut hoasntu"; ArrayList<String> appendMe = null; for(String s : hello.split(" ")) appendMe.add(s+" "); for(String s : appendMe) System.out.println(s); //WHY DOES IT NOT PRINT? }catch(Exception e){ } } }

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  • Visual ++ print from main with inheritance on visual form in listbox

    - by captencrunch
    I´ve made a "main" class lets call it A(Veichle), and i have two classes that inherits from A Lets call them B(Car) and C(MC). i also have a handler lets call it "D" that binds A,B and C. Then i have the Form1 class lets call that E(Visual) I want to print out the private members from A on the visual form "E" in a Listbox If i try ex) this-listbox1-items-add(X.veichles[i]-getBrand()); it complains that veichles is a private member in D. How can i get around that?

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  • Equivalence of boolean expressions

    - by Iulian Serbanoiu
    Hello, I have a problem that consist in comparing boolean expressions ( OR is +, AND is * ). To be more precise here is an example: I have the following expression: "A+B+C" and I want to compare it with "B+A+C". Comparing it like string is not a solution - it will tell me that the expressions don't match which is of course false. Any ideas on how to compare those expressions? Any ideas about how can I tackle this problem? I accept any kind of suggestions but (as a note) the final code in my application will be written in C++ (C accepted of course). An normal expression could contain also parenthesis: (A * B * C) + D or A+B*(C+D)+X*Y Thanks in advance, Iulian

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  • Tinymce print issue with application server

    - by Ashok
    Hi, I have incorporated tinymce into my application. When i execute the jsp standalone, the print size seem consistent to what it should be i.e. 12Pt comes out as 12pt. Whereas when i run the same jsp from oracle developer using oracle application server 12pt comes out to be more like 8pt. Any thoughts. Please share any pointers. Thanks, Ashok

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  • How to print a var inside a script

    - by Pollux Khafra
    Alright I'm trying to use a jplayer script to trigger the player in my template. I need to pass a value to the "mp3" option but I don't get how I get $music to print. $(document).ready(function(){ $("#jquery_jplayer_1").jPlayer({ ready: function () { $(this).jPlayer("setMedia", { var music = $(".album-playlist li").first().find("input").val(); mp3: $music, }).jPlayer(""); }, swfPath: "http://mysite.com/wp-content/themes/beta/libs", supplied: "mp3" }); });

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  • C# LINQ Where Predicate Type Arguments

    - by blu
    I have an XElement with values for mock data. I have an expression to query the xml: Expression<Func<XElement, bool>> simpleXmlFunction = b => int.Parse(b.Element("FooId").Value) == 12; used in: var simpleXml = xml.Elements("Foo").Where(simpleXmlFunction).First(); The design time error is: The type arguments for method 'System.Linq.Enumerable.Where(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly' The delegate supplied to Where should take in an XElement and return a bool, marking if the item matches the query, I am not sure how to add anything more to the delegate or the where clause to mark the type. Also, the parallel method for the real function against the Entity Framework does not have this issue. What is not correct with the LINQ-to-XML version?

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  • [PHP Array] - Sorting data and print out in alphabetic order

    - by kwokwai
    Hi all, I got an array which contains some data like this: $arrs = Array("ABC_efg", "@@zzAG", "@$abc", "ABC_abc") I was trying to print the data out in this way (Printing in alphabetic order): [String begins with character A] ABC_abc ABC_efg [String begins with character other than A to Z] @$abc @@zzAG I don't know how to do it.

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  • Rails: print associations in ActiveRecord inspectors

    - by marienbad
    When I print an ActiveRecord of a Department, I get: Department:0x210ec4c { :id = 3, :name = "Computer Science", ... :school_id = 3 } How can I make it give me the School instead of the School_ID? In other words, call to_s on the school found by the school_id. Just like how when I have a Department d, I can say d.school

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  • Print Alternating Characters From Two Strings (Interleaving) Using Recursion Java

    - by babi2balla
    I'm trying to write a method that uses recursion to print the string formed by "interleaving" the strings str1 and str2. In other words, it should alternate characters from the two strings: the first character from str1, followed by the first character from str2, followed by the second character from str1, followed by the second character from str2, etc. How would I go about this? Any ideas are greatly appreciated!! Thanks

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  • Print XML file and download it

    - by Pankaj
    I am create xml using serialization and trying to print them using this code string xmlDate = xml.GetXML(); string name = string.Format("{0}_HighEST", ProjectName); Response.AddHeader("Content-disposition", "attachment; filename=\"" + name + "_HighEST.xml\""); Response.ContentType = string.Format("application/.xml", name); how can assign my xmldata to Response so that data will write on downloaded xml?

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  • Lxml or Xpath content print

    - by Angelo
    function= def parseTitle(self, post): """ Returns title string with spaces replaced by dots "" return post.xpath('h2')[0].text.replace('.', ' ') i would to see the content of post. Tried all . How can i properly debug the content. ir is an webstite of movies where i rip links and tittle. So this one should parse the title.and i am sure H@ is not existing , how to print/debug it?

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  • Python named print?

    - by Mark
    I know it's a really simple question, but I have no idea how to google it. how can I do print '<a href="%s">%s</a>' % (my_url) So that my_url is used twice? I assume I have to "name" the %s and then use a dict in the params, but I'm not sure of the proper syntax? just FYI, I'm aware I can just use my_url twice in the params, but that's not the point :)

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  • print a picture from php

    - by robertdd
    how i can print a picture from php? when i acces the link: http://localhost/autovi/thumb.php?gsbxdsdc where the gsbxdsdc is the name of the image i have in my html this: <a href=""> <img src="http://localhost/autovi/thumb.php?gsbxdsdc" id="gsbxdsdc"> </a>

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  • Problem with evaluating XPath expression in Java

    - by JSteve
    Can somebody help me find the mistake I am doing in evaluating following XPath expression? I want to get all "DataTable" nodes under the node "Model" in my xml through XPath. Here is my XML doc: <?xml version="1.0" encoding="UTF-8"?> <Root> <Application> <Model> <DataSet name="ds" primaryTable="Members" openRows="1"> <DataTable name="Members" openFor="write"> <DataColumn name="id" type="String" mandatory="true" primaryKey="true" valueBy="user"/> <DataColumn name="name" type="String" mandatory="true" valueBy="user"/> <DataColumn name="address" type="String" mandatory="false" valueBy="user"/> <DataColumn name="city" type="String" mandatory="false" valueBy="user"/> <DataColumn name="country" type="String" mandatory="false" valueBy="user"/> </DataTable> </DataSet> </Model> <View> <Composite> <Grid> <Label value="ID:" row="0" column="0" /> <Label value="Name:" row="1" column="0" /> <Label value="Address:" row="2" column="0" /> <Label value="City:" row="3" column="0" /> <Label value="Country:" row="4" column="0" /> <TextField name="txtId" row="0" column="1" /> <TextField name="txtName" row="1" column="1" /> <TextField name="txtAddress" row="2" column="1" /> <TextField name="txtCity" row="3" column="1" /> <TextField name="txtCountry" row="4" column="1" /> </Grid> </Composite> </View> </Application> </Root> Here the Java code to extract required node list: try { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); domFactory.setIgnoringComments(true); domFactory.setIgnoringElementContentWhitespace(true); DocumentBuilder builder = domFactory.newDocumentBuilder(); Document dDoc = builder.parse("D:\TEST\myFile.xml"); XPath xpath = XPathFactory.newInstance().newXPath(); NodeList nl = (NodeList) xpath.evaluate("//Model//DataTable", dDoc, XPathConstants.NODESET); System.out.println(nl.getLength()); }catch (Exception ex) { System.out.println(ex.getMessage()); } There is no problem in loading and parsing xml file and I can see correct nodes in dDoc. Problem is with xpath that returns nothing on evaluating my expression. I tried many other expressions for testing purpose but every time resulting NodeList "nl" does not have any item

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  • Find last match with python regular expression

    - by SDD
    I wanto to match the last occurence of a simple pattern in a string, e.g. list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2) print "last match: ", list[len(list)-1] however, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurence of "AAAA" or should I use this workaround?

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