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  • DataSet.GetChanges - Save the updated record in a different table than the source one

    - by John Dev
    I'm doing operation on a dataset containing data from a sql table named Test_1 and then get the updated records using the DataSet.GetChanges(DataRowState.Modified) function. Then i try to save the dataset containing the updated records on a different table than the source one (the table is names Test and has the same structure as Test_1) using the following statement: sqlDataAdapter.Update(changesDataSet,"Test"); I'm getting the following error : Update unable to find TableMapping['Test'] or DataTable 'Test' I'm new to ado.net and don't even know if it"s something possible. Any advice is welcome. Just to provide a bit of context. ETL jobs are importing data in temp table with same structure as the original but with _jobid suffix. Right after a rule engine is doing validation before updating the original table.

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  • Hide or display a button according to row count of a table

    - by kawtousse
    Hi, i have a HTML table and a button send. First of all the send button must have this style: style.display="none". But if the table has at least one row the button should be displayed (block/inline); I still have no idea how to relate between the table and the button. I try to use JavaScript but i should think about a function and I don't found any of it to apply at type table. Thinking about CSS still also hard since I cannot find a relation between the table and the button.

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  • How to display a border-bottom only if table cells are not empty (CSS)

    - by Polarpro
    Hey there, I've got a Filemaker calculation that generates an HTML page with several tables. If the calculation results in values for certain fields the result would be <table> <tr><td>Example value 1</td></tr> <tr><td>Example value 2</td></tr> ... </table> If the calculation finds no values to be displayed, the result would simply be <table> </table> In the first case, I want to the table to display a border at the bottom (or any other horizontal line); in the second case, I don't want to display a border at the bottom. I cannot find a way to get this done using a CSS... Thanks in adavance :-)

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  • Show the specific field on mysql table based on active date

    - by mrjimoy_05
    Suppose that I have 3 tables: A) Table UsrHeader ----------------- UsrID | UsrName ----------------- 1 | Abc 2 | Bcd B) Table UsrDetail ------------------------------- UsrID | UsrLoc | Date ------------------------------- 1 | LocA | 10 Aug 2012 1 | LocB | 15 Aug 2012 2 | LocA | 10 Aug 2012 C) Table Trx ----------------------------- TrxID | TrxDate | UsrID ----------------------------- 1 | 10 Aug 2012 | 1 2 | 16 Aug 2012 | 1 3 | 11 Aug 2012 | 2 What I want to do is to show the table like: --------------------------------------- TrxID | TrxDate | UsrID | UsrLoc --------------------------------------- 1 | 10 Aug 2012 | 1 | LocA 2 | 16 Aug 2012 | 1 | LocB 3 | 11 Aug 2012 | 2 | LocA Notice that there is one user but different location. That's based on the UsrDetail table that the user on a specified date has moved to another location. So, it should be show the user specific location on that date on every transaction. I have try this code but it is no luck: SELECT trx.TrxID, trx.TrxDate, trx.UsrID, User.UsrName, User.UsrLoc FROM trx INNER JOIN ( SELECT UsrHeader.UsrID, UsrHeader.UsrName, UserDetail.UsrLoc FROM UsrHeader INNER JOIN ( SELECT UsrDetail.UsrID, UsrDetail.UsrLoc, UsrDetail.Date FROM UsrDetail ) AS UserDetail ON UserDetail.UsrID = UsrHeader.UsrID ) AS User ON User.UsrID = trx.UsrID AND trx.TrxDate >= User.Date How to do that? Thanks..

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  • Why is it that, table is not printing in the xsl-fo here? please help me guys.

    - by atrueguy
    This is my xml file <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="currency.xsl"?> <currencylist> <title>Currencies By Country</title> <countries> <country>Australia</country> <currency>Australian Dollar</currency> </countries> <countries> <country>Austria</country> <currency>Schilling</currency> </countries> <countries> <country>Belgium</country> <currency>Belgium Franc</currency> </countries> <countries> <country>Canada</country> <currency>Canadian Dollar</currency> </countries> <countries> <country>England</country> <currency>Pound</currency> </countries> <countries> <country>Fiji</country> <currency>Fijian Dollar</currency> </countries> <countries> <country>France</country> <currency>Franc</currency> </countries> <countries> <country>Germany</country> <currency>DMark</currency> </countries> <countries> <country>Hong Kong</country> <currency>Hong Kong Dollar</currency> </countries> <countries> <country>Italy</country> <currency>Lira</currency> </countries> <countries> <country>Japan</country> <currency>Yen</currency> </countries> <countries> <country>Netherlands</country> <currency>Guilder</currency> </countries> <countries> <country>Switzerland</country> <currency>SFranc</currency> </countries> <countries> <country>USA</country> <currency>Dollar</currency> </countries> </currencylist> This is my xsl-fo file: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <fo:root xmlns:fo="http://www.w3.org/1999/XSL/Format"> <fo:layout-master-set> <fo:simple-page-master master-name="Letter" page-height="11in" page-width="8.5in"> <fo:region-body region-name="only_region" margin="0.7in" margin-top="1.2in" margin-left="1.1in"/> <fo:region-before region-name="xsl-region-before" extent="1.5in" /> <fo:region-after region-name="xsl-region-after" extent="1.5in" /> <fo:region-start region-name="xsl-region-after" extent="1.5in" /> </fo:simple-page-master> </fo:layout-master-set> <fo:page-sequence master-reference="Letter"> <fo:flow flow-name="only_region"> <fo:block text-align="left"><xsl:call-template name="show_title"/></fo:block> <fo:table-and-caption> <fo:table> <fo:table-column column-width="25mm"/> <fo:table-column column-width="25mm"/> <fo:table-column column-width="25mm"/> <fo:table-header> <fo:table-row> <fo:table-cell> <fo:block font-weight="bold">SI No</fo:block> </fo:table-cell> <fo:table-cell> <fo:block font-weight="bold">Country</fo:block> </fo:table-cell> <fo:table-cell> <fo:block font-weight="bold">Currency</fo:block> </fo:table-cell> </fo:table-row> </fo:table-header> <fo:table-body> <xsl:for-each select="currencylist/countries"> <fo:table-row> <fo:table-cell> <fo:block> <xsl:value-of select="position()"/> </fo:block> </fo:table-cell> <fo:table-cell> <fo:block> <xsl:value-of select="country"/> </fo:block> </fo:table-cell> <fo:table-cell> <fo:block> <xsl:value-of select="currency"/> </fo:block> </fo:table-cell> </fo:table-row> </xsl:for-each> </fo:table-body> </fo:table> </fo:table-and-caption> </fo:flow> </fo:page-sequence> </fo:root> </xsl:template> <xsl:template name="show_title" match="currencylist"> <xsl:value-of select="currencylist/title"/> </xsl:template> </xsl:stylesheet> Table structure is not printing, but the values are printing, please help guys.

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  • Database Table Prefixes

    - by DoctorMick
    We're having a few discussions at work around the naming of our database tables. We're working on a large application with approx 100 database tables (ok, so it isn't that large), most of which can be categorized in to different functional area, and we're trying to work out the best way of naming/organizing these within an Oracle database. The three current options are: Create the different functional areas in separate schemas. Create everything in the same schema but prefix the tables with the functional area Create everything in the same schema with no prefixes We have various pro's and con's around each one but I'd be interested to hear everyone's opinions on what the best solution is.

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  • How do I align my partition table properly?

    - by Jorge Castro
    I am in the process of building my first RAID5 array. I've used mdadm to create the following set up: root@bondigas:~# mdadm --detail /dev/md1 /dev/md1: Version : 00.90 Creation Time : Wed Oct 20 20:00:41 2010 Raid Level : raid5 Array Size : 5860543488 (5589.05 GiB 6001.20 GB) Used Dev Size : 1953514496 (1863.02 GiB 2000.40 GB) Raid Devices : 4 Total Devices : 4 Preferred Minor : 1 Persistence : Superblock is persistent Update Time : Wed Oct 20 20:13:48 2010 State : clean, degraded, recovering Active Devices : 3 Working Devices : 4 Failed Devices : 0 Spare Devices : 1 Layout : left-symmetric Chunk Size : 64K Rebuild Status : 1% complete UUID : f6dc829e:aa29b476:edd1ef19:85032322 (local to host bondigas) Events : 0.12 Number Major Minor RaidDevice State 0 8 16 0 active sync /dev/sdb 1 8 32 1 active sync /dev/sdc 2 8 48 2 active sync /dev/sdd 4 8 64 3 spare rebuilding /dev/sde While that's going I decided to format the beast with the following command: root@bondigas:~# mkfs.ext4 /dev/md1p1 mke2fs 1.41.11 (14-Mar-2010) /dev/md1p1 alignment is offset by 63488 bytes. This may result in very poor performance, (re)-partitioning suggested. Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=16 blocks, Stripe width=48 blocks 97853440 inodes, 391394047 blocks 19569702 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=0 11945 block groups 32768 blocks per group, 32768 fragments per group 8192 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208, 4096000, 7962624, 11239424, 20480000, 23887872, 71663616, 78675968, 102400000, 214990848 Writing inode tables: ^C 27/11945 root@bondigas:~# ^C I am unsure what to do about "/dev/md1p1 alignment is offset by 63488 bytes." and how to properly partition the disks to match so I can format it properly.

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  • How to easily change columns into rows in Excel?

    - by DavidD
    I have a huge Excel table that I need to transform into paragraphs for a Word report, and I can't find an efficient way to do it The source looks like this: And I would ultimately need something like this, i.e. through a pivot table. Note that "Item C", which doesn't have any description values, is skipped: Now, to get there I believe I need to transform my source to this intermediate format, that has one description per line: How do I get from the source to the intermediate format in an efficient way? Or maybe there is an easier way to produce the target format that I don't know of? Any help is welcome!

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  • Passing data from one database to another database table (Access) (C#)

    - by SAMIR BHOGAYTA
    string conString = "Provider=Microsoft.Jet.OLEDB.4.0 ;Data Source=Backup.mdb;Jet OLEDB:Database Password=12345"; OleDbConnection dbconn = new OleDbConnection(); OleDbDataAdapter dAdapter = new OleDbDataAdapter(); OleDbCommand dbcommand = new OleDbCommand(); try { if (dbconn.State == ConnectionState.Closed) dbconn.Open(); string selQuery = "INSERT INTO [Master] SELECT * FROM [MS Access;DATABASE="+ "\\Data.mdb" + ";].[Master]"; dbcommand.CommandText = selQuery; dbcommand.CommandType = CommandType.Text; dbcommand.Connection = dbconn; int result = dbcommand.ExecuteNonQuery(); } catch(Exception ex) {}

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  • SQL SERVER – Three Methods to Insert Multiple Rows into Single Table – SQL in Sixty Seconds #024 – Video

    - by pinaldave
    One of the biggest ask I have always received from developers is that if there is any way to insert multiple rows into a single table in a single statement. Currently when developers have to insert any value into the table they have to write multiple insert statements. First of all this is not only boring it is also very much time consuming as well. Additionally, one has to repeat the same syntax so many times that the word boring becomes an understatement. In the following quick video we have demonstrated three different methods to insert multiple values into a single table. -- Insert Multiple Values into SQL Server CREATE TABLE #SQLAuthority (ID INT, Value VARCHAR(100)); Method 1: Traditional Method of INSERT…VALUE -- Method 1 - Traditional Insert INSERT INTO #SQLAuthority (ID, Value) VALUES (1, 'First'); INSERT INTO #SQLAuthority (ID, Value) VALUES (2, 'Second'); INSERT INTO #SQLAuthority (ID, Value) VALUES (3, 'Third'); Clean up -- Clean up TRUNCATE TABLE #SQLAuthority; Method 2: INSERT…SELECT -- Method 2 - Select Union Insert INSERT INTO #SQLAuthority (ID, Value) SELECT 1, 'First' UNION ALL SELECT 2, 'Second' UNION ALL SELECT 3, 'Third'; Clean up -- Clean up TRUNCATE TABLE #SQLAuthority; Method 3: SQL Server 2008+ Row Construction -- Method 3 - SQL Server 2008+ Row Construction INSERT INTO #SQLAuthority (ID, Value) VALUES (1, 'First'), (2, 'Second'), (3, 'Third'); Clean up -- Clean up DROP TABLE #SQLAuthority; Related Tips in SQL in Sixty Seconds: SQL SERVER – Insert Multiple Records Using One Insert Statement – Use of UNION ALL SQL SERVER – 2008 – Insert Multiple Records Using One Insert Statement – Use of Row Constructor I encourage you to submit your ideas for SQL in Sixty Seconds. We will try to accommodate as many as we can. If we like your idea we promise to share with you educational material. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Query, SQL Scripts, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology, Video

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  • DATE lookup table (1990/01/01:2041/12/31)

    - by Frank Developer
    I use a DATE's master table for looking up dates and other values in order to control several events, intervals and calculations within my app. It has rows for every single day begining from 01/01/1990 to 12/31/2041. One example of how I use this lookup table is: A customer pawned an item on: JAN-31-2010 Customer returns on MAY-03-2010 to make an interest pymt to avoid forfeiting the item. If he pays 1 months interest, the employee enters a "1" and the app looks-up the pawn date (JAN-31-2010) in date master table and puts FEB-28-2010 in the applicable interest pymt date. FEB-28 is returned because FEB-31's dont exist! If 2010 were a leap-year, it would've returned FEB-29. If customer pays 2 months, MAR-31-2010 is returned. 3 months, APR-30... If customer pays more than 3 months or another period not covered by the date lookup table, employee manually enters the applicable date. Here's what the date lookup table looks like: { Copyright 1990:2010, Frank Computer, Inc. } { DBDATE=YMD4- (correctly sorted for faster lookup) } CREATE TABLE datemast ( dm_lookup DATE, {lookup col used for obtaining values below} dm_workday CHAR(2), {NULL=Normal Working Date,} {NW=National Holiday(Working Date),} {NN=National Holiday(Non-Working Date),} {NH=National Holiday(Half-Day Working Date),} {CN=Company Proclamated(Non-Working Date),} {CH=Company Proclamated(Half-Day Working Date)} {several other columns omitted} dm_description CHAR(30), {NULL, holiday description or any comments} dm_day_num SMALLINT, {number of elapsed days since begining of year} dm_days_left SMALLINT, (number of remaining days until end of year} dm_plus1_mth DATE, {plus 1 month from lookup date} dm_plus2_mth DATE, {plus 2 months from lookup date} dm_plus3_mth DATE, {plus 3 months from lookup date} dm_fy_begins DATE, {fiscal year begins on for lookup date} dm_fy_ends DATE, {fiscal year ends on for lookup date} dm_qtr_begins DATE, {quarter begins on for lookup date} dm_qtr_ends DATE, {quarter ends on for lookup date} dm_mth_begins DATE, {month begins on for lookup date} dm_mth_ends DATE, {month ends on for lookup date} dm_wk_begins DATE, {week begins on for lookup date} dm_wk_ends DATE, {week ends on for lookup date} {several other columns omitted} ) IN "S:\PAWNSHOP.DBS\DATEMAST"; Is there a better way of doing this or is it a cool method?

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  • Two strange efficiency problems in Mathematica

    - by Jess Riedel
    FIRST PROBLEM I have timed how long it takes to compute the following statements (where V[x] is a time-intensive function call): Alice = Table[V[i],{i,1,300},{1000}]; Bob = Table[Table[V[i],{i,1,300}],{1000}]^tr; Chris_pre = Table[V[i],{i,1,300}]; Chris = Table[Chris_pre,{1000}]^tr; Alice, Bob, and Chris are identical matricies computed 3 slightly different ways. I find that Chris is computed 1000 times faster than Alice and Bob. It is not surprising that Alice is computed 1000 times slower because, naively, the function V must be called 1000 more times than when Chris is computed. But it is very surprising that Bob is so slow, since he is computed identically to Chris except that Chris stores the intermediate step Chris_pre. Why does Bob evaluate so slowly? SECOND PROBLEM Suppose I want to compile a function in Mathematica of the form f(x)=x+y where "y" is a constant fixed at compile time (but which I prefer not to directly replace in the code with its numerical because I want to be able to easily change it). If y's actual value is y=7.3, and I define f1=Compile[{x},x+y] f2=Compile[{x},x+7.3] then f1 runs 50% slower than f2. How do I make Mathematica replace "y" with "7.3" when f1 is compiled, so that f1 runs as fast as f2? Many thanks!

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  • SQL Bits X – Temporal Snapshot Fact Table Session Slide & Demos

    - by Davide Mauri
    Already 10 days has passed since SQL Bits X in London. I really enjoyed it! Those kind of events are great not only for the content but also to meet friends that – due to distance – is not possible to meet every day. Friends from PASS, SQL CAT, Microsoft, MVP and so on all in one place, drinking beers, whisky and having fun. A perfect mixture for a great learning and sharing experience! I’ve also enjoyed a lot delivering my session on Temporal Snapshot Fact Tables. Given that the subject is very specific I was not expecting a lot of attendees….but I was totally wrong! It seems that the problem of handling daily snapshot of data is more common than what I expected. I’ve also already had feedback from several attendees that applied the explained technique to their existing solution with success. This is just what a speaker in such conference wish to hear! :) If you want to take a look at the slides and the demos, you can find them on SkyDrive: https://skydrive.live.com/redir.aspx?cid=377ea1391487af21&resid=377EA1391487AF21!1151&parid=root The demo is available both for SQL Sever 2008 and for SQL Server 2012. With this last version, you can also simplify the ETL process using the new LEAD analytic function. (This is not done in the demo, I’ve left this option as a little exercise for you :) )

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  • Store a formula in a table and use the formula in a javascript/PHP function

    - by Muhaimin Abdul
    I have a MySql database where part of it handles instrument's depth of water. Each instrument has its own formula of calculation how depth the water when the operator collect the reading I stored the formula for each instrument in database/MySql. Example formula: [55-57] this is the simple minus operation, where the number is actually represent the id of a row. How do I represent those number with id of a row and later convert it to javascript readable code. I simply want to do keyup event where everytime user key in something into text field then the other part of HTML would reflect changes based on formula that I fetched from database FYI, I'm using BackboneJS together with RequireJS

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  • How do I align my partition table properly?

    - by Jorge Castro
    I am in the process of building my first RAID5 array. I've used mdadm to create the following set up: root@bondigas:~# mdadm --detail /dev/md1 /dev/md1: Version : 00.90 Creation Time : Wed Oct 20 20:00:41 2010 Raid Level : raid5 Array Size : 5860543488 (5589.05 GiB 6001.20 GB) Used Dev Size : 1953514496 (1863.02 GiB 2000.40 GB) Raid Devices : 4 Total Devices : 4 Preferred Minor : 1 Persistence : Superblock is persistent Update Time : Wed Oct 20 20:13:48 2010 State : clean, degraded, recovering Active Devices : 3 Working Devices : 4 Failed Devices : 0 Spare Devices : 1 Layout : left-symmetric Chunk Size : 64K Rebuild Status : 1% complete UUID : f6dc829e:aa29b476:edd1ef19:85032322 (local to host bondigas) Events : 0.12 Number Major Minor RaidDevice State 0 8 16 0 active sync /dev/sdb 1 8 32 1 active sync /dev/sdc 2 8 48 2 active sync /dev/sdd 4 8 64 3 spare rebuilding /dev/sde While that's going I decided to format the beast with the following command: root@bondigas:~# mkfs.ext4 /dev/md1p1 mke2fs 1.41.11 (14-Mar-2010) /dev/md1p1 alignment is offset by 63488 bytes. This may result in very poor performance, (re)-partitioning suggested. Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=16 blocks, Stripe width=48 blocks 97853440 inodes, 391394047 blocks 19569702 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=0 11945 block groups 32768 blocks per group, 32768 fragments per group 8192 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208, 4096000, 7962624, 11239424, 20480000, 23887872, 71663616, 78675968, 102400000, 214990848 Writing inode tables: ^C 27/11945 root@bondigas:~# ^C I am unsure what to do about "/dev/md1p1 alignment is offset by 63488 bytes." and how to properly partition the disks to match so I can format it properly.

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  • ActiveRecord table inheritence using set_table_names

    - by Jinyoung Kim
    Hi, I'm using ActiveRecord in Ruby on Rails. I have a table named documents(Document class) and I want to have another table data_documents(DataDocument) class which is effectively the same except for having different table name. In other words, I want two tables with the same behavior except for table name. class DataDocument < Document #set_table_name "data_documents" self.table_name = "data_documents" end My solution was to use class inheritance as above, yet this resulted in inconsistent SQL statement for create operation where there are both 'documents' table and 'data_documents' table. Can you figure out why and how I can make it work? >> DataDocument.create(:did=>"dd") ActiveRecord::StatementInvalid: Mysql::Error: Unknown column 'data_documents.did' in 'where clause': SELECT `documents`.id FROM `documents` WHERE (`data_documents`.`did` = BINARY 'dd') LIMIT 1 from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract_adapter.rb:212:in `log' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/mysql_adapter.rb:320:in `execute' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/mysql_adapter.rb:595:in `select' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/database_statements.rb:7:in `select_all_without_query_cache' from /Users/lifidea/.gem/ruby/1.8/gems/activerecord-2.3.2/lib/active_record/connection_adapters/abstract/query_cache.rb:62:in `select_all'

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  • Evaluation of CTEs in SQL Server 2005

    - by Jammer
    I have a question about how MS SQL evaluates functions inside CTEs. A couple of searches didn't turn up any results related to this issue, but I apologize if this is common knowledge and I'm just behind the curve. It wouldn't be the first time :-) This query is a simplified (and obviously less dynamic) version of what I'm actually doing, but it does exhibit the problem I'm experiencing. It looks like this: CREATE TABLE #EmployeePool(EmployeeID int, EmployeeRank int); INSERT INTO #EmployeePool(EmployeeID, EmployeeRank) SELECT 42, 1 UNION ALL SELECT 43, 2; DECLARE @NumEmployees int; SELECT @NumEmployees = COUNT(*) FROM #EmployeePool; WITH RandomizedCustomers AS ( SELECT CAST(c.Criteria AS int) AS CustomerID, dbo.fnUtil_Random(@NumEmployees) AS RandomRank FROM dbo.fnUtil_ParseCriteria(@CustomerIDs, 'int') c) SELECT rc.CustomerID, ep.EmployeeID FROM RandomizedCustomers rc JOIN #EmployeePool ep ON ep.EmployeeRank = rc.RandomRank; DROP TABLE #EmployeePool; The following can be assumed about all executions of the above: The result of dbo.fnUtil_Random() is always an int value greater than zero and less than or equal to the argument passed in. Since it's being called above with @NumEmployees which has the value 2, this function always evaluates to 1 or 2. The result of dbo.fnUtil_ParseCriteria(@CustomerIDs, 'int') produces a one-column, one-row table that contains a sql_variant with a base type of 'int' that has the value 219935. Given the above assumptions, it makes sense (to me, anyway) that the result of the expression above should always produce a two-column table containing one record - CustomerID and an EmployeeID. The CustomerID should always be the int value 219935, and the EmployeeID should be either 42 or 43. However, this is not always the case. Sometimes I get the expected single record. Other times I get two records (one for each EmployeeID), and still others I get no records. However, if I replace the RandomizedCustomers CTE with a true temp table, the problem vanishes completely. Every time I think I have an explanation for this behavior, it turns out to not make sense or be impossible, so I literally cannot explain why this would happen. Since the problem does not happen when I replace the CTE with a temp table, I can only assume it has something to do with the functions inside CTEs are evaluated during joins to that CTE. Do any of you have any theories?

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  • Using a PivotTable to Count Items in Access

    - by Sandra
    I have a list of text entries and I want to count how often each entry appears in the list. e.g. Berlin Paris London London Paris Paris Paris The result would be Berlin 1 Paris 4 London 2 This result easy do to achieve with an pivot table in MS Excel (see: Count Items in Excel). My data not in spreadsheet in Excel but in a MS Access database table. So in order to avoid constant switching between Access and Excel and I would like to handle everything in Access (either Access 2007 or 2010). I know there are pivot tables in Access and I know how to display one, but I was unable to find out how to count the number of occurrences. Thank you!

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  • MYSQL Merging 2 results into 1 table

    - by AlphaRomeo69
    Im building a c# program and am currently stuck at fetching data from MYSQL database and bind them to a grid view. I had been researching for a few days now but to no avail. I have 4 table in the database. table 1 - alpha table 2 - bravo table 3 - charlie table 4 - delta attributes of alpha (id, type, user, role ) attributes of bravo (id, type, date, user) attributes of charlie (id,type, cat, doneby, comment) atttibutes of delta (id,type, cat, doneby) * the pk of alpha and bravo is (id) * the pk of charlie and delta is (id, type) i did a query1 before by inner joinning alpha, bravo and charlie which leads to the sucessful result of (id, type, date, user, role, cat, doneby, comment) and i also did a query2 before by inner joinning alpha, bravo and delta which leads to the sucessful result of (id, type, date, user, role, cat, doneby) Right now, im trying to built a query3 which will merge the result from query1 and query2 together. the result of my attempts leads to (id, type, date, user, role, cat, doneby, comment,id, type, date, user, role, cat, doneby) As i do not want the repeated columns, I would like to seek advice on how to get the result to become like the one below by placing the records as a new tuple in the result table. (id, type, date, user, role, cat, doneby, comment) Thanks! P.S: the PK would not pose a problem due to (id, type)

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  • Temp Table Recompiles

    - by Derek D.
    If you landed on this article, then you most likely know that temp tables can cause recompilation. This happens because temp tables are treated just like regular tables by the SQL Server Engine. When the tables (in which underlying queries rely on) change significantly, SQL Server detects this change (using auto update statistics) [...]

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  • SQL SERVER Size of Index Table for Each Index Solution 3 Powershell

    Laerte Junior If you are a Powershell user, the name of the Laerte Junior is not a new name. He is the one man with exceptional knowledge of Powershell. He is not only very knowledgeable, but also very kind and eager to those in need. I have been attempting to setup Powershell for many days, [...]...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • SQL SERVER Size of Index Table for Each Index Solution 3 Powershell

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