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  • find the difference between two very large list

    - by user157195
    I have two large list(could be a hundred million items), the source of each list can be either from a database table or a flat file. both lists are of comparable sizes, both unsorted. I need to find the difference between them. so I have 3 scenarios: 1. List1 is a database table(assume each row simply have one item(key) that is a string), List2 is a large file. 2. Both lists are from 2 db tables. 3. both lists are from two files. in case 2, I plan to use: select a.item from MyTable a where a.item not in (select b.item form MyTable b) this clearly is inefficient, is there a better way? Another approach is: I plan to sort each list, and then walk down both of them to find the diff. If the list is from a file, I have to read it into a db table first, then use db sorting to output the list. Is the run time complexity still O(nlogn) in db sorting? either approach is a pain and seems would be very slow when the list involved has hundreds of millions of items. any suggestions?

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  • Android text layout question: two textviews, side-by-side, with different layout alignments and weights

    - by thx1200
    I'm still a bit of an Android noob, forgive me if this is simple and I'm just not seeing it. There are two portions of text in a view that spans the entire width horizontally, but is only as high as one line of text. The left side must always be displayed in full, but should take no more horizontal space than it needs. The right side should be pushed over by the left side and fill up the remainder of the screen width. If the right side text is smaller than this width, the text should be right-aligned horizontally. If the text is greater than the width, it should scroll horizontally. The text on the right side will be updated frequently and should slide up with new text when the app tells it (explaining the TextSwitcher in the layout). I have tried two different layout styles. In both situations, I can get the left side to "push" the layout, the right side to scroll, but I can't figure out how to get the right side to right align. It is always left aligned. Here is a picture showing what is happening... http://img10.imageshack.us/img10/5599/androidlayout.png In addition (but less important), in my layout code I have android:fadingEdge="none" on the TextViews, but it still has a faded edge on the left and right side when it scrolls. Why is that? Here are the two layouts I created, which yield the results shown, but not the results I want. Using a horizontal LinearLayout... <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/LinearLayoutStatusBar" android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2px" android:background="#555555" > <TextView android:id="@+id/TextViewTimer" android:textSize="18px" android:textColor="#FFFFFF" android:layout_gravity="left" android:layout_weight="0" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="0px" android:layout_marginRight="3px" android:text="Left Side" > </TextView> <TextSwitcher android:id="@+id/TextSwitcherDetails" android:inAnimation="@anim/push_up_in" android:outAnimation="@anim/push_up_out" android:layout_weight="1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="right" android:layout_marginLeft="3px" android:layout_marginRight="0px" > <TextView android:id="@+id/TextViewDetails1" android:textSize="18px" android:layout_width="match_parent" android:layout_height="match_parent" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:text="Right Side 1" > </TextView> <TextView android:id="@+id/TextViewDetails2" android:textSize="18px" android:layout_width="match_parent" android:layout_height="match_parent" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:text="Right Side 2 - This is a really long text this is long and fun and fun and long" > </TextView> </TextSwitcher> </LinearLayout> And the RelativeLayout style... <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/LinearLayoutStatusBar" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2px" android:background="#555555" > <TextView android:id="@+id/TextViewTimer" android:textSize="18px" android:textColor="#FFFFFF" android:layout_gravity="left" android:layout_weight="0" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="0px" android:layout_marginRight="3px" android:layout_alignParentLeft="true" android:text="Left Side" > </TextView> <TextSwitcher android:id="@+id/TextSwitcherDetails" android:inAnimation="@anim/push_up_in" android:outAnimation="@anim/push_up_out" android:layout_weight="1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="3px" android:layout_marginRight="0px" android:layout_toRightOf="@+id/TextViewTimer" android:layout_alignParentRight="true" android:fadingEdge="none" android:fadingEdgeLength="0px" > <TextView android:id="@+id/TextViewDetails1" android:textSize="18px" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:fadingEdgeLength="0px" android:text="Right Side 1" > </TextView> <TextView android:id="@+id/TextViewDetails2" android:textSize="18px" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:fadingEdgeLength="0px" android:text="Right Side 2 - This is a really long text this is long and fun and fun and long" > </TextView> </TextSwitcher> </RelativeLayout> So how do I get that text on the right side to right-align. Thanks!

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  • Finding all the shortest paths between two nodes in unweighted directed graphs using BFS algorithm

    - by andra-isan
    Hi All, I am working on a problem that I need to find all the shortest path between two nodes in a given directed unweighted graph. I have used BFS algorithm to do the job, but unfortunately I can only print one shortest path not all of them, for example if they are 4 paths having lenght 3, my algorithm only prints the first one but I would like it to print all the four shortest paths. I was wondering in the following code, how should I change it so that all the shortest paths between two nodes could be printed out? class graphNode{ public: int id; string name; bool status; double weight;}; map<int, map<int,graphNode>* > graph; int Graph::BFS(graphNode &v, graphNode &w){ queue <int> q; map <int, int> map1; // this is to check if the node has been visited or not. std::string str= ""; map<int,int> inQ; // just to check that we do not insert the same iterm twice in the queue map <int, map<int, graphNode>* >::iterator pos; pos = graph.find(v.id); if(pos == graph.end()) { cout << v.id << " does not exists in the graph " <<endl; return 1; } int parents[graph.size()+1]; // this vector keeps track of the parents for the node parents[v.id] = -1; // there is a direct path between these two words, simply print that path as the shortest path if (findDirectEdge(v.id,w.id) == 1 ){ cout << " Shortest Path: " << v.id << " -> " << w.id << endl; return 1; } //if else{ int gn; map <int, map<int, graphNode>* >::iterator pos; q.push(v.id); inQ.insert(make_pair(v.id, v.id)); while (!q.empty()){ gn = q.front(); q.pop(); map<int, int>::iterator it; cout << " Popping: " << gn <<endl; map1.insert(make_pair(gn,gn)); //backtracing to print all the nodes if gn is the same as our target node such as w.id if (gn == w.id){ int current = w.id; cout << current << " - > "; while (current!=v.id){ current = parents[current]; cout << current << " -> "; } cout <<endl; } if ((pos = graph.find(gn)) == graph.end()) { cout << " pos is empty " <<endl; continue; } map<int, graphNode>* pn = pos->second; map<int, graphNode>::iterator p = pn->begin(); while(p != pn->end()) { map<int, int>::iterator it; //map1 keeps track of the visited nodes it = map1.find(p->first); graphNode gn1= p->second; if (it== map1.end()) { map<int, int>::iterator it1; //if the node already exits in the inQ, we do not insert it twice it1 = inQ.find(p->first); if (it1== inQ.end()){ parents[p->first] = gn; cout << " inserting " << p->first << " into the queue " <<endl; q.push(p->first); // add it to the queue } //if } //if p++; } //while } //while } I do appreciate all your great help Thanks, Andra

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  • How to merge two different child nodes in the same XML file

    - by user814698
    I have an XML file and I would like to merge two different CONTACT child nodes. I have checked these websites it shows how to merge two different xml files into a single file. http://www2.informatik.hu-berlin.de/~obecker/XSLT/#merge Merge XML documents In my case this is my first contact in the xml file: <CONTACT> <PDE-Identity>N65539</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Arun_niit</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> This is the second contact in the file: <PDE-Identity>N65567</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Ramanathan</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>gmail</Type> <Value>[email protected]</Value> </EMail> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACT> I know both of the contacts are belongs to the same person. How can i merge these two contacts in the same xml file. Original XML File: <?xml version="1.0" encoding="UTF-8"?> <CONTACTS> <CONTACT> <PDE-Identity>N65539</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Arun_niit</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACT> <PDE-Identity>N65567</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Ramanathan</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>gmail</Type> <Value>[email protected]</Value> </EMail> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACT> <PDE-Identity>N65567</PDE-Identity> <FirstName>Rangarajkarthik</FirstName> <LastName>karthik Rangaraj</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>gmail</Type> <Value>[email protected]</Value> </EMail> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACTS>

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  • Hosting WCF service in IIS 7 (WAS) with net.tcp binding on TWO tcp ports

    - by Yuri
    By default IIS 7 Web site has net.tcp binding with "808:" binding information string. If i add another net.tcp binding with "xxx:" exception occurs: This collection already contains an address with scheme net.tcp. There can be at most one address per scheme in this collection. Parameter name: item How can i solve this problem and listen my service at TWO ports?

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  • Flex 4 Slider with two thumbs

    - by 23tux
    Hi, anybody know how to make a custom hslider in Flex 4 (spark) with two thumbs? Since Flex 4 the thumbcount property of the slider component isn't longer available (at the mx component it was easily to set). I have to style the track and the thumbs. A tutorial would be nice. thx, tux.

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  • Fluent Nhibernate - Mapping two entities to same table

    - by Andy
    Hi, I'm trying to map two domain entities to the same table. We're doing a smart entity for our domain model, so we have the concept of an Editable Address and a readonly Address. I have both mapped using Classmaps, and everything seems to go fine until we try to export the schema using the SchemaExport class from NHibernate. It errors out saying the table already exists. I assume it's something simple that I'm just not seeing. Any ideas? Thanks

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  • Logback to log different messages to two files

    - by Aly
    I am using logback/slf4j to do my logging. I want to parse my log file to analyze some data, so instead of parsing a great big file (mostly consisting of debug statements) I want to have two logger instances which each log to a separate file; one for analytics and one for all purpose logging. Does anyone know if this is possible with Logback, or any other logger for that matter?

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  • iPhone UISlider with two thumbs/indicators?

    - by ChrisW
    Is anyone aware of a version of the iPhone UISlider control with two thumbs? I need a control that will allow specifying a range of values. The UISlider API docs would imply this isn't possible with the standard control, so I was wondering if anyone had a solution for this (or had solved it themselves).

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  • Can overloading is possible with two version of function, constant member function and function with

    - by GG
    Hello, I just came across various overloading methods like type of parameter passed, varying number of parameters, return type etc. I just want to know that can I overload a function with following two version //function which can modify member String& MyClass::doSomething(); //constant member function String& MyClass::doSomething() const; Please let me know the reason behind it. Thanks, GG

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  • Putting two picker control on single UIView.

    - by Amit Jain
    Hi I am having to picker controls on a single view with two outlets for each. Now when I select any of them same delegate methods are get called. How should we distinguish between which picker control has called the delegate ? Another question is can we change the frame size of the pickers to fit in one view? Thanks Amit

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  • Fluent NHibernate - How to map a non nullable foreign key that exists in two joined tables

    - by vakman
    I'm mapping a set of membership classes for my application using Fluent NHibernate. I'm mapping the classes to the asp.net membership database structure. The database schema relevant to the problem looks like this: ASPNET_USERS UserId PK ApplicationId FK NOT NULL other user columns ... ASPNET_MEMBERSHIP UserId PK,FK ApplicationID FK NOT NULL other membership columns... There is a one to one relationship between these two tables. I'm attempting to join the two tables together and map data from both tables to a single 'User' entity which looks like this: public class User { public virtual Guid Id { get; set; } public virtual Guid ApplicationId { get; set; } // other properties to be mapped from aspnetuser/membership tables ... My mapping file is as follows: public class UserMap : ClassMap<User> { public UserMap() { Table("aspnet_Users"); Id(user => user.Id).Column("UserId").GeneratedBy.GuidComb(); Map(user => user.ApplicationId); // other user mappings Join("aspnet_Membership", join => { join.KeyColumn("UserId"); join.Map(user => user.ApplicationId); // Map other things from membership to 'User' class } } } If I try to run with the code above I get a FluentConfiguration exception Tried to add property 'ApplicationId' when already added. If I remove the line "Map(user = user.ApplicationId);" or change it to "Map(user = user.ApplicationId).Not.Update().Not.Insert();" then the application runs but I get the following exception when trying to insert a new user: Cannot insert the value NULL into column 'ApplicationId', table 'ASPNETUsers_Dev.dbo.aspnet_Users'; column does not allow nulls. INSERT fails. The statement has been terminated. And if I leave the .Map(user = user.ApplicationId) as it originally was and make either of those changes to the join.Map(user = user.ApplicationId) then I get the same exception above except of course the exception is related to an insert into the aspnet_Membership table So... how do I do this kind of mapping assuming I can't change my database schema?

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  • Linq find differences in two lists

    - by Salo
    I have two list of members like this: Before: Peter, Ken, Julia, Tom After: Peter, Robert, Julia, Tom As you can see, Ken is is out and Robert is in. What I want is to detect the changes. I want a list of what has changed in both lists. How can linq help me?

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  • Two locations of gacutil.exe

    - by bmw0128
    I'm developing on Windows 2008 R2 Server, 64 bit. I'm learning how to use gacutil.exe I found two copies of this file: C:\Program Files\Microsoft SDKs\Windows\v6.0A\Bin\x64 C:\Program Files\Microsoft SDKs\Windows\v6.0A\Bin\ I built a dll in VS2007, then I added a build post event, that calls gacutil.exe to transfer the dll to GAC. Does it matter which gacutil.exe I use?

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  • Using two embedded fonts on one string

    - by Igor
    Hello, i would like to know how to use two embedded fonts in Flex in tag i am dynamically loading rss description into it and would like to have first character and characters unsupported by other font be in that first font. i limited the range of char of that second font so all unsupported chars and first char should be in that first font. thanks in advance , Igor. if my writing was unclear please let me know.

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  • Connecting to two databases

    - by Pankaj Khurana
    Hi, I have an application in which i want to authenticate a user from a first database & manage other activities from another database. I have created two classes.An object of the classes is defined in a file $objdb1=new db1(),$objdb2=new db2(); But when i try to call $objdb1-fn(). It searches from the $objdb2 & is showing table1 doesnot exists? Can you help me on this? Regards, Pankaj

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  • Can two different browser share on cookie?

    - by Hiscal
    Hi Friends My requirement is pretty interesting, I want to maintain one cookie between two different browser for same domain. so lets say I have create one cookie with name "mydata" and value "hiscal" from IE, then if i browse same website from firefox and trying to read cookie "mydata" then system should give me value "hiscal" but this is not happen in general case so can any one tell me how i can share cookie between to different browser(client) of same domain. Thanks, Hiscal

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