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  • Tkinter change all color when variable change

    - by Morten Larsen
    hi i have a simpel tkinter window. consists of a small window, a timer, and a button for set timer. dont want to go in details with the code... Now all the widgets in my windows eg. button, Label Ect. will have to change color. EG. i Have a global variabel wich i will set as color "red" fx... All the widgets BACKGROUND option is associated with the global variabel. Now on button press i will change the global variable to "green" so that the background of all widgets ect. will change color, but they DONT. i thought the .mainloop() sort of UPDATED the window. how can i have the widgets to change background color when my variable change WITHOUT restarting my application??? ty Xanthar

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  • why is this dictionary line number count not working?

    - by jad
    i have this piece of code the last bit of the code starting from d = {} im trying to print the words with its line number located in the text but it is not working its only printing the words anyone know why ??? need help ASAP import sys import string text = [] infile = open(sys.argv[1], 'r').read() for punct in string.punctuation: infile = infile.replace(punct, "") text = infile.split() dict = open(sys.argv[2], 'r').read() dictset = [] dictset = dict.split() words = [] words = list(set(text) - set(dictset)) words = [text.lower() for text in words] words.sort() d = {} counter = 0 for lines in text: counter += 1 if word not in d: d[words] = [counter] else: d[words.append[counter] print(word, d)

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  • differences between "d.clear()" and "d={}"

    - by Tshepang
    On my machine, the execution speed between "d.clear()" and "d={}" is over 100ns so am curious why one would use one over the other. import timeit def timing(): d = dict() if __name__=='__main__': t = timeit.Timer('timing()', 'from __main__ import timing') print t.repeat()

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  • Unable to plot graph using matplotlib

    - by Aman Deep Gautam
    I have the following code which searches all the directory in the current directory and then takes data from those files to plot the graph. The data is read correctly as verified by printing but there are no points plotted on graph. import argparse import os import matplotlib.pyplot as plt #find the present working directory pwd=os.path.dirname(os.path.abspath(__file__)) #find all the folders in the present working directory. dirs = [f for f in os.listdir('.') if os.path.isdir(f)] plt.figure() plt.xlim(0, 20000) plt.ylim(0, 1) for directory in dirs: os.chdir(os.path.join(pwd, directory)); chd_dir = os.path.dirname(os.path.abspath(__file__)) files = [ fl for fl in os.listdir('.') if os.path.isfile(fl) ] print files for f in files: f_obj = open(os.path.join(chd_dir, f), 'r') list_x = [] list_y = [] for i in xrange(0,4): f_obj.next() for line in f_obj: temp_list = line.split() print temp_list list_y.append(temp_list[0]) list_x.append(temp_list[1]) print 'final_lsit' print list_x print list_y plt.plot(list_x, list_y, 'r.') f_obj.close() os.chdir(pwd) plt.savefig("test.jpg") The input files look like the following: 5 865 14709 15573 14709 1.32667e-06 664 0.815601 14719 1.55333e-06 674 0.813277 14729 1.82667e-06 684 0.810185 14739 1.4e-06 694 0.808459 Can anybody help me with why this is happening? Being new I would like to know some tutorial where I can get help with kind of plotting as the tutorial I was following made me end up here. Any help appreciated.

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  • How to update Geo-Location in fireeagle

    - by Ganesh
    Hi Every One, I am developing an application on fireeagle, there i need to update the users exact location, with out asking any information from the user (i.e) lat, long e.t.c., If it is not possible using yahoo fireeagle, please let me know if there exists any other api's other than yahoo fireeagle. If they can get the exact location of web user in 'Lat' and 'Long', either from 'Pc' or from 'Mobile' browser. Thanks in advance.

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  • How to bind a double precision using psycopg2

    - by user337636
    I'm trying to bind a float to a postgresql double precision using psycopg2. ele = 1.0/3.0 dic = {'name': 'test', 'ele': ele} sql = '''insert into waypoints (name, elevation) values (%(name)s, %(ele)s)''' cur = db.cursor() cur.execute(sql, dic) db.commit() sql = """select elevation from waypoints where name = 'test'""" cur.execute(sql_out) ele_out = cur.fetchone()[0] ele_out 0.33333333333300003 ele 0.33333333333333331 Obviously I don't need the precision, but I would like to be able to simply compare the values. I could use the struct module and save it as a string, but thought there should be a better way. Thanks

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  • Simple App Engine Sessions Implementation

    - by raz0r
    Here is a very basic class for handling sessions on App Engine: """Lightweight implementation of cookie-based sessions for Google App Engine. Classes: Session """ import os import random import Cookie from google.appengine.api import memcache _COOKIE_NAME = 'app-sid' _COOKIE_PATH = '/' _SESSION_EXPIRE_TIME = 180 * 60 class Session(object): """Cookie-based session implementation using Memcached.""" def __init__(self): self.sid = None self.key = None self.session = None cookie_str = os.environ.get('HTTP_COOKIE', '') self.cookie = Cookie.SimpleCookie() self.cookie.load(cookie_str) if self.cookie.get(_COOKIE_NAME): self.sid = self.cookie[_COOKIE_NAME].value self.key = 'session-' + self.sid self.session = memcache.get(self.key) if self.session: self._update_memcache() else: self.sid = str(random.random())[5:] + str(random.random())[5:] self.key = 'session-' + self.sid self.session = dict() memcache.add(self.key, self.session, _SESSION_EXPIRE_TIME) self.cookie[_COOKIE_NAME] = self.sid self.cookie[_COOKIE_NAME]['path'] = _COOKIE_PATH print self.cookie def __len__(self): return len(self.session) def __getitem__(self, key): if key in self.session: return self.session[key] raise KeyError(str(key)) def __setitem__(self, key, value): self.session[key] = value self._update_memcache() def __delitem__(self, key): if key in self.session: del self.session[key] self._update_memcache() return None raise KeyError(str(key)) def __contains__(self, item): try: i = self.__getitem__(item) except KeyError: return False return True def _update_memcache(self): memcache.replace(self.key, self.session, _SESSION_EXPIRE_TIME) I would like some advices on how to improve the code for better security. Note: In the production version it will also save a copy of the session in the datastore. Note': I know there are much more complete implementations available online though I would like to learn more about this subject so please don't answer the question with "use that" or "use the other" library.

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  • argparse coding issue

    - by Carl Skonieczny
    write a script that takes two optional boolean arguments,"--verbose‚" and ‚"--live", and two required string arguments, "base"and "pattern". Please set up the command line processing using argparse. This is the code I have so far for the question, I know I am getting close but something is not quite right. Any help is much appreciated.Thanks for all the quick useful feedback. def main(): import argparse parser = argparse.ArgumentParser(description='') parser.add_argument('base', type=str) parser.add_arguemnt('--verbose', action='store_true') parser.add_argument('pattern', type=str) parser.add_arguemnt('--live', action='store_true') args = parser.parse_args() print(args.base(args.pattern))

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  • Detect if 2 HTML fragments have identical hierarchical structure

    - by sergzach
    An example of fragments that have identical hierarchical structure: (1) <div> <span>It's a message</span> </div> (2) <div> <span class='bold'>This is a new text</span> </div> An example of fragments that have different structure: (1) <div> <span><b>It's a message</b></span> </div> (2) <div> <span>This is a new text</span> </div> So, fragments with a similar structure correspond to one hierarchical tree (the same tag names, the same hierarchical structure). How can I detect if 2 elements (html fragments) have the same structure simply with lxml? I have a function that does not work properly for some more difficult case (than the example): def _is_equal( el1, el2 ): # input: 2 elements with possible equal structure and tag names # e.g. root = lxml.html.fromstring( buf ) # el1 = root[ 0 ] # el2 = root[ 1 ] # move from top to bottom, compare elements result = False if el1.tag == el2.tag: # has no children if len( el1 ) == len( el2 ): if len( el1 ) == 0: return True else: # iterate one of them, for example el1 i = 0 for child1 in el1: child2 = el2[ i ] is_equal2 = _is_equal( child1, child2 ) if not is_equal2: return False return True else: return False else: return False The code fails to detect that 2 divs with class='tovar2' have an identical structure: <body> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333193003"> ?????? ?/? </a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333193003,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b> 3 150 </b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"><input value="" type="submit"> </li> </ul> </form> </div> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333124803">?????? ?/?</a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333124803,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b>3 150</b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"> <input value="" type="submit"> </li> </ul> </form> </div> </body>

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  • What does "str indices must be integers" mean?

    - by digitala
    I'm working with dicts in jython which are created from importing/parsing JSON. Working with certain sections I see the following message: TypeError: str indices must be integers This occurs when I do something like: if jsondata['foo']['bar'].lower() = 'baz': ... Where jsondata looks like: {'foo': {'bar':'baz'} } What does this mean, and how do I fix it?

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  • Trie Backtracking in Recursion

    - by Darksky
    I am building a tree for a spell checker with suggestions. Each node contains a key (a letter) and a value (array of letters down that path). So assume the following sub-trie in my big trie: W / \ a e | | k k | | is word--> e e | ... This is just a subpath of a sub-trie. W is a node and a and e are two nodes in its value array etc... At each node, I check if the next letter in the word is a value of the node. I am trying to support mistyped vowels for now. So 'weke' will yield 'wake' as a suggestion. Here's my searchWord function in my trie: def searchWord(self, word, path=""): if len(word) > 0: key = word[0] word = word[1:] if self.values.has_key(key): path = path + key nextNode = self.values[key] return nextNode.searchWord(word, path) else: # check here if key is a vowel. If it is, check for other vowel substitutes else: if self.isWord: return path # this is the word found else: return None Given 'weke', at the end when word is of length zero and path is 'weke', my code will hit the second big else block. weke is not marked as a word and so it will return with None. This will return out of searchWord with None. To avoid this, at each stack unwind or recursion backtrack, I need to check if a letter is a vowel and if it is, do the checking again. I changed the if self.values.has_key(key) loop to the following: if self.values.has_key(key): path = path + key nextNode = self.values[key] ret = nextNode.searchWord(word, path) if ret == None: # check if key == vowel and replace path # return nextNode.searchWord(... return ret What am I doing wrong here? What can I do when backtracking to achieve what I'm trying to do?

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  • A good data model for finding a user's favorite stories

    - by wings
    Original Design Here's how I originally had my Models set up: class UserData(db.Model): user = db.UserProperty() favorites = db.ListProperty(db.Key) # list of story keys # ... class Story(db.Model): title = db.StringProperty() # ... On every page that displayed a story I would query UserData for the current user: user_data = UserData.all().filter('user =' users.get_current_user()).get() story_is_favorited = (story in user_data.favorites) New Design After watching this talk: Google I/O 2009 - Scalable, Complex Apps on App Engine, I wondered if I could set things up more efficiently. class FavoriteIndex(db.Model): favorited_by = db.StringListProperty() The Story Model is the same, but I got rid of the UserData Model. Each instance of the new FavoriteIndex Model has a Story instance as a parent. And each FavoriteIndex stores a list of user id's in it's favorited_by property. If I want to find all of the stories that have been favorited by a certain user: index_keys = FavoriteIndex.all(keys_only=True).filter('favorited_by =', users.get_current_user().user_id()) story_keys = [k.parent() for k in index_keys] stories = db.get(story_keys) This approach avoids the serialization/deserialization that's otherwise associated with the ListProperty. Efficiency vs Simplicity I'm not sure how efficient the new design is, especially after a user decides to favorite 300 stories, but here's why I like it: A favorited story is associated with a user, not with her user data On a page where I display a story, it's pretty easy to ask the story if it's been favorited (without calling up a separate entity filled with user data). fav_index = FavoriteIndex.all().ancestor(story).get() fav_of_current_user = users.get_current_user().user_id() in fav_index.favorited_by It's also easy to get a list of all the users who have favorited a story (using the method in #2) Is there an easier way? Please help. How is this kind of thing normally done?

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  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

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  • How to cutomize a modelform widget in django 1.1?

    - by muudscope
    I'm trying to modify a django form to use a textarea instead of a normal input for the "address" field in my house form. The docs seem to imply this changed from django 1.1 (which I'm using) to 1.2. But neither approach is working for me. Here's what I've tried: class HouseForm(forms.ModelForm): address = forms.Textarea() # Should work with django 1.1, but doesn't class Meta: model = House #widgets = { 'address': forms.Textarea() } # 1.2 style - doesn't work either.

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  • Removing the port number from URL

    - by DrewSSP
    I'm new to anything related to servers and am trying to deploy a django application. Today I bought a domain name for the app and am having trouble configuring it so that the base URL does not need the port number at the end of it. I have to type www.trackthecharts.com:8001 to see the website when I only want to use www.trackethecharts.com. I think the problem is somewhere in my nginx, gunicorn or supervisor configuration. gunicorn_config.py command = '/opt/myenv/bin/gunicorn' pythonpath = '/opt/myenv/top-chart-app/' bind = '162.243.76.202:8001' workers = 3 root@django-app:~# nginx config server { server_name 162.243.76.202; access_log off; location /static/ { alias /opt/myenv/static/; } location / { proxy_pass http://127.0.0.1:8001; proxy_set_header X-Forwarded-Host $server_name; proxy_set_header X-Real-IP $remote_addr; add_header P3P 'CP="ALL DSP COR PSAa PSDa OUR NOR ONL UNI COM NAV"'; } } supervisor config [program:top_chart_gunicorn] command=/opt/myenv/bin/gunicorn -c /opt/myenv/gunicorn_config.py djangoTopChartApp.wsgi autostart=true autorestart=true stderr_logfile=/var/log/supervisor_gunicorn.err.log stdout_logfile=/var/log/supervisor_gunicorn.out.log Thanks for taking a look.

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  • OpenCV performance in different languages

    - by h0b0
    I'm doing some prototyping with OpenCV for a hobby project involving processing of real time camera data. I wonder if it is worth the effort to reimplement this in C or C++ when I have it all figured out or if no significant performance boost can be expected. The program basically chains OpenCV functions, so the main part of the work should be done in native code anyway.

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  • just-in-time list

    - by intuited
    I'd like to know if there is a class available, either in the standard library or in pypi, that fits this description. The constructor would take an iterator. It would implement the container protocol (ie _getitem_, _len_, etc), so that slices, length, etc., would work. In doing so, it would iterate and retain just enough values from its constructor argument to provide whatever information was requested. So if jitlist[6] was requested, it would call self.source.next() 7 times, save those elements in its list, and return the last one. This would allow downstream code to use it as a list, but avoid unnecessarily instantiating a list for cases where list functionality was not needed, and avoid allocating memory for the entire list if only a few members ended up being requested. It seems like a pretty easy one to write, but it also seems useful enough that it's likely that someone would have already made it available in a module.

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