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  • How would make this run with an if statement and one for loop?

    - by Nick Jacobs
    I'm trying to get this to run by using an if statment, a for loop, and a list. The list is part of the parameters. I am not sure how to write the if statement and have the program loop through all of the different words and set everything how it is supposed to be. newSndIdx=0; for i in range (8700, 12600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (15700, 17600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (18750, 22350+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (23700, 27250+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (106950, 115300+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx+=1

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  • Pickling a class definition

    - by Giorgio
    Is there a way to pickle a class definition? What I'd like to do is pickle the definition (which may created dynamically), and then send it over a TCP connection so that an instance can be created on the other end. I understand that there may be dependencies, like modules and global variables that the class relies on. I'd like to bundle these in the pickling process as well, but I'm not concerned about automatically detecting the dependencies because it's okay if the onus is on the user to specify them.

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  • Shuttle control in wxPython

    - by Mridang Agarwalla
    Hi, I'm trying to implement a shuttle control in wxPython but there doesn't seem to be one. I've decided to use two listbox controls. The shuttle control looks like this: I've got two listboxes — one's populated, one's not. Could someone show me how to add a selected item to the second list box when it is double clicked? It should be removed from the first. When it is double clicked in the second, it should be added to the first and removed from the second. The shuttle control implements these by default but it's a pity it isn't there. Thank you.

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  • How to use traceit to report function input variables in stack trace

    - by reckoner
    Hi, I've been using the following code to trace the execution of my programs: import sys import linecache import random def traceit(frame, event, arg): if event == "line": lineno = frame.f_lineno filename = frame.f_globals["__file__"] if filename == "<stdin>": filename = "traceit.py" if (filename.endswith(".pyc") or filename.endswith(".pyo")): filename = filename[:-1] name = frame.f_globals["__name__"] line = linecache.getline(filename, lineno) print "%s:%s:%s: %s" % (name, lineno,frame.f_code.co_name , line.rstrip()) return traceit def main(): print "In main" for i in range(5): print i, random.randrange(0, 10) print "Done." sys.settrace(traceit) main() Using this code, or something like it, is it possible to report the values of certain function arguments? In other words, the above code tells me "which" functions were called and I would like to know "what" the corresponding values of the input variables for those function calls. Thanks in advance.

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  • How do you automatically remove the preview window after autocompletion in Vim?

    - by Ben Davini
    I'm using omnifunc=pythoncomplete. When autocompleting a word (e.g., os.), I get the list of eligible class members and functions, as expected, as well as a scratch buffer preview window with documentation about the selected member or function. This is great, but after selecting the function I want, the preview window remains. I can get rid of it with ":pc", but I'd like it just to automatically disappear after I've selected my function, a la Eclipse. I've played around with "completeopt" but to no avail.

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  • What is the best way to create a wizard in C# for web?

    - by Yan
    Hi , i want to create a wizard the include a few steps ,that in the final steps we need to include all the steps and save on the data base. what is the best design to do this ? there is implemante for a jquery ? i need to save the steps in sessions till the final save ? thanks !!!!

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  • How to bind a double precision using psycopg2

    - by user337636
    I'm trying to bind a float to a postgresql double precision using psycopg2. ele = 1.0/3.0 dic = {'name': 'test', 'ele': ele} sql = '''insert into waypoints (name, elevation) values (%(name)s, %(ele)s)''' cur = db.cursor() cur.execute(sql, dic) db.commit() sql = """select elevation from waypoints where name = 'test'""" cur.execute(sql_out) ele_out = cur.fetchone()[0] ele_out 0.33333333333300003 ele 0.33333333333333331 Obviously I don't need the precision, but I would like to be able to simply compare the values. I could use the struct module and save it as a string, but thought there should be a better way. Thanks

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  • threading.local equivalent for twisted.web?

    - by defnull
    In asynchronous environments, threading.local is not guaranteed to be context-local anymore, because several contexts may coexist within a single thread. Most asynchronous frameworks (gevent, eventlet) provide a get_current_context() functionality to identify the current context. Some offer a way to monkey-patch threading.local so it is local to 'greenthreads' or other framework-specific contexts. I cannot find such a functionality in the twisted documentation. How do I do this?

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  • How to cutomize a modelform widget in django 1.1?

    - by muudscope
    I'm trying to modify a django form to use a textarea instead of a normal input for the "address" field in my house form. The docs seem to imply this changed from django 1.1 (which I'm using) to 1.2. But neither approach is working for me. Here's what I've tried: class HouseForm(forms.ModelForm): address = forms.Textarea() # Should work with django 1.1, but doesn't class Meta: model = House #widgets = { 'address': forms.Textarea() } # 1.2 style - doesn't work either.

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  • Simplifying for-if messes with better structure?

    - by HH
    # Description: you are given a bitwise pattern and a string # you need to find the number of times the pattern matches in the string # any one liner or simple pythonic solution? import random def matchIt(yourString, yourPattern): """find the number of times yourPattern occurs in yourString""" count = 0 matchTimes = 0 # How can you simplify the for-if structures? for coin in yourString: #return to base if count == len(pattern): matchTimes = matchTimes + 1 count = 0 #special case to return to 2, there could be more this type of conditions #so this type of if-conditionals are screaming for a havoc if count == 2 and pattern[count] == 1: count = count - 1 #the work horse #it could be simpler by breaking the intial string of lenght 'l' #to blocks of pattern-length, the number of them is 'l - len(pattern)-1' if coin == pattern[count]: count=count+1 average = len(yourString)/matchTimes return [average, matchTimes] # Generates the list myString =[] for x in range(10000): myString= myString + [int(random.random()*2)] pattern = [1,0,0] result = matchIt(myString, pattern) print("The sample had "+str(result[1])+" matches and its size was "+str(len(myString))+".\n" + "So it took "+str(result[0])+" steps in average.\n" + "RESULT: "+str([a for a in "FAILURE" if result[0] != 8])) # Sample Output # # The sample had 1656 matches and its size was 10000. # So it took 6 steps in average. # RESULT: ['F', 'A', 'I', 'L', 'U', 'R', 'E']

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  • How to print an Objectified Element?

    - by BeeBand
    I have xml of the format: <channel> <games> <game slot='1'> <id>Bric A Bloc</id> <title-text>BricABloc Hoorah</title-text> <link>Fruit Splat</link> </game> </games> </channel> I've parsed this xml using lxml.objectify, via: tree = objectify.parse(file) There will potentially be a number of <game>s underneath <games>. I understand that I can generate a list of <game> objects via: [ tree.games[0].game[0:4] ] My question is, what class are those objects and is there a function to print any object of whatever class these objects belong to?

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  • Function for averages of tuples in a dictionary

    - by Billy Mann
    I have a string, dictionary in the form: ('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) Each parentheses is a tuple which corresponds to (score, standard deviation). I'm taking the average of just the first integer in each tuple. I've tried this: def score(string, d): for word in d: (score, std) = d[word] d[word]=float(score),float(std) if word in string: word = string.lower() number = len(string) return sum([v[0] for v in d.values()]) / float(len(d)) if len(string) == 0: return 0 When I run: print score('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) I should get 5.5 but instead I'm getting 5.875. Can't figure out what in my function is not allowing me to get the correct answer.

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  • why is this dictionary line number count not working?

    - by jad
    i have this piece of code the last bit of the code starting from d = {} im trying to print the words with its line number located in the text but it is not working its only printing the words anyone know why ??? need help ASAP import sys import string text = [] infile = open(sys.argv[1], 'r').read() for punct in string.punctuation: infile = infile.replace(punct, "") text = infile.split() dict = open(sys.argv[2], 'r').read() dictset = [] dictset = dict.split() words = [] words = list(set(text) - set(dictset)) words = [text.lower() for text in words] words.sort() d = {} counter = 0 for lines in text: counter += 1 if word not in d: d[words] = [counter] else: d[words.append[counter] print(word, d)

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  • Detect if 2 HTML fragments have identical hierarchical structure

    - by sergzach
    An example of fragments that have identical hierarchical structure: (1) <div> <span>It's a message</span> </div> (2) <div> <span class='bold'>This is a new text</span> </div> An example of fragments that have different structure: (1) <div> <span><b>It's a message</b></span> </div> (2) <div> <span>This is a new text</span> </div> So, fragments with a similar structure correspond to one hierarchical tree (the same tag names, the same hierarchical structure). How can I detect if 2 elements (html fragments) have the same structure simply with lxml? I have a function that does not work properly for some more difficult case (than the example): def _is_equal( el1, el2 ): # input: 2 elements with possible equal structure and tag names # e.g. root = lxml.html.fromstring( buf ) # el1 = root[ 0 ] # el2 = root[ 1 ] # move from top to bottom, compare elements result = False if el1.tag == el2.tag: # has no children if len( el1 ) == len( el2 ): if len( el1 ) == 0: return True else: # iterate one of them, for example el1 i = 0 for child1 in el1: child2 = el2[ i ] is_equal2 = _is_equal( child1, child2 ) if not is_equal2: return False return True else: return False else: return False The code fails to detect that 2 divs with class='tovar2' have an identical structure: <body> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333193003"> ?????? ?/? </a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333193003,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b> 3 150 </b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"><input value="" type="submit"> </li> </ul> </form> </div> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333124803">?????? ?/?</a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333124803,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b>3 150</b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"> <input value="" type="submit"> </li> </ul> </form> </div> </body>

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  • How do I upload a files to google app engine app when field name is not known

    - by Michael Neale
    I have tried a few options, none of which seem to work (if I have a simple multipart form with a named field, it works well, but when I don't know the name I can't just grab all files in the request...). I have looked at http://stackoverflow.com/questions/81451/upload-files-in-google-app-engine and it doesn't seem suitable (or to actually work, as someone mentioned the code snipped it untested).

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  • Simple App Engine Sessions Implementation

    - by raz0r
    Here is a very basic class for handling sessions on App Engine: """Lightweight implementation of cookie-based sessions for Google App Engine. Classes: Session """ import os import random import Cookie from google.appengine.api import memcache _COOKIE_NAME = 'app-sid' _COOKIE_PATH = '/' _SESSION_EXPIRE_TIME = 180 * 60 class Session(object): """Cookie-based session implementation using Memcached.""" def __init__(self): self.sid = None self.key = None self.session = None cookie_str = os.environ.get('HTTP_COOKIE', '') self.cookie = Cookie.SimpleCookie() self.cookie.load(cookie_str) if self.cookie.get(_COOKIE_NAME): self.sid = self.cookie[_COOKIE_NAME].value self.key = 'session-' + self.sid self.session = memcache.get(self.key) if self.session: self._update_memcache() else: self.sid = str(random.random())[5:] + str(random.random())[5:] self.key = 'session-' + self.sid self.session = dict() memcache.add(self.key, self.session, _SESSION_EXPIRE_TIME) self.cookie[_COOKIE_NAME] = self.sid self.cookie[_COOKIE_NAME]['path'] = _COOKIE_PATH print self.cookie def __len__(self): return len(self.session) def __getitem__(self, key): if key in self.session: return self.session[key] raise KeyError(str(key)) def __setitem__(self, key, value): self.session[key] = value self._update_memcache() def __delitem__(self, key): if key in self.session: del self.session[key] self._update_memcache() return None raise KeyError(str(key)) def __contains__(self, item): try: i = self.__getitem__(item) except KeyError: return False return True def _update_memcache(self): memcache.replace(self.key, self.session, _SESSION_EXPIRE_TIME) I would like some advices on how to improve the code for better security. Note: In the production version it will also save a copy of the session in the datastore. Note': I know there are much more complete implementations available online though I would like to learn more about this subject so please don't answer the question with "use that" or "use the other" library.

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  • Test assertions for tuples with floats

    - by Space_C0wb0y
    I have a function that returns a tuple that, among others, contains a float value. Usually I use assertAlmostEquals to compare those, but this does not work with tuples. Also, the tuple contains other data-types as well. Currently I am asserting every element of the tuple individually, but that gets too much for a list of such tuples. Is there any good way to write assertions for such cases?

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  • BeautifulSoup: just get inside of a tag, no matter how many enclosing tags there are

    - by AP257
    I'm trying to scrape all the inner html from the <p> elements in a web page using BeautifulSoup. There are internal tags, but I don't care, I just want to get the internal text. For example, for: <p>Red</p> <p><i>Blue</i></p> <p>Yellow</p> <p>Light <b>green</b></p> How can I extract: Red Blue Yellow Light green Neither .string nor .contents[0] does what I need. Nor does .extract(), because I don't want to have to specify the internal tags in advance - I want to deal with any that may occur. Is there a 'just get the visible HTML' type of method in BeautifulSoup? ----UPDATE------ On advice, trying: p_tags = page.findAll('p',text=True) for i, p_tag in enumerate(p_tags): print str(p_tag) But that doesn't help - it just prints out: Red <i>Blue</i> Yellow Light <b>green</b>

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  • Django url tag multiple parameters

    - by Overdose
    I have two similar codes. The first one works as expected. urlpatterns = patterns('', (r'^(?P<n1>\d)/test/', test), (r'', test2), {% url testapp.views.test n1=5 %} But adding the second parameter makes the result return empty string. urlpatterns = patterns('', (r'^(?P<n1>\d)/test(?P<n2>\d)/', test), (r'', test2),) {% url testapp.views.test n1=5, n2=2 %} Views signature: def test(request, n1, n2=1):

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  • Is there a replacement for Paste.Template?

    - by Jorge Vargas
    I have grown tired of all the little issues with paste template, it's horrible to maintain the templates, it has no way of updating an old project and it's very hard to test. I'm wondering if someone knows of an alternative for quickstart generators as they have proven to be useful.

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  • Updating section in ConfigParser (or an alternative)

    - by lyrae
    I am making a plugin for another program and so I am trying to make thing as lightweight as possible. What i need to do is be able to update the name of a section in the ConfigParser's config file. [project name] author:john doe email: [email protected] year: 2010 I then have text fields where user can edit project's name, author, email and year. I don't think changing [project name] is possible, so I have thought of two solutions: 1 -Have my config file like this: [0] projectname: foobar author:john doe email: [email protected] year: 2010 that way i can change project's name just like another option. But the problem is, i would need the section # to be auto incremented. And to do this i would have to get every section, sort of, and figure out what the next number should be. The other option would be to delete the entire section and its value, and re-add it with the updated values which would require a little more work as well, such as passing a variable that holds the old section name through functions, etc, but i wouldn't mind if it's faster. Which of the two is best? or is there another way? I am willing to go with the fastest/lightweight solution possible, doesn't matter if it requires more work or not.

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