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  • Liftweb Menu customization

    - by DataSurfer
    I want to create a menu that looks like: HOME | FOO | BAR | ABOUT | CONTACT How might I go about doing this? Here is what I have tried: <lift:Menu.builder ul:class="menu" li_item:class="current" /> and ul.menu li { display: inline; list-style-type: none; text-transform: uppercase; border-right: 1px solid white; padding-right: 5px; } li.current span { background: white; color: black; padding: 5px 5px 3px 5px; font-size: 11px; } li.current a, a:visited, a:link { color: white; padding: 5px 5px 3px 5px; font-size: 11px; } This gets close, but it doesn't look quite right. Also you end up with an extra line at the end. I want the lines to be the same height as the text. http://lh5.ggpht.com/_5DxlOp9F12k/S2aFQHfupzI/AAAAAAAAJiY/Ds0IpEyu78I/s800/menu.png

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  • How to direct link to an attribute set?

    - by monocat
    I have created attributes; “Shop by Type” and “Shop by Color”. They work great within the layered navigation and extended search. I’ve designed graphics and placed them in the home page and would like to link to the respective attribute’s assigned products. Been searching the webs, but so far have been unsuccessful. If there’s no direct possible way, the next method would be creating cms pages and linking to it directly. How can I display products that are assigned to a specific attribute? Specifically “Multiple Select” types. I know you guys prefer at least some attempts, but as mentioned, been playing with it with no luck. I would appreciate some kind of starting point. Happy Holidays! Edit: I was able to put together this code that lists all the products assigned to said category id. Tried to filter it down where it only displays products that have an assigned same attribute with no luck yet. Any ideas? <?php $cat_id = 123; // category id $category = Mage::getModel('catalog/category')->load($cat_id); $_products = $category->getProductCollection() ->addAttributeToSelect('shop_by_color'); if (($this->getProductCollection()) && $_products->getSize()): ?> By the way, $cat_id is a sub category of root. Is there an easier way to point to it instead of using direct id number?

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  • Firing through HTTP a Perl script for sending signals to daemons

    - by Eric Fortis
    Hello guys, I'm using apache2 on Ubuntu. I have a Perl script which basically read the files names of a directory, then rewrites a text file, then sends a signal to a daemon. How can this be done, as secure as possible through a web-page? Actually I can run the code below, but not if I remove the comments. I'm looking for advise considering: Using HTTP Requests? How about Apache file permissions on the directory shown in code? Is htaccess enough to enable user/pass access to the cgi? Should I use a database instead of writing to a file and run a cron querying the db with permission granted to write and send the signal? Granting as less permissions as possible to the webserver. Should I set a VPN? #!/usr/bin/perl -wT use strict; use CGI; #@fileList = </home/user/*>; #read a directory listing my $query = CGI->new(); print $query->header( "text/html" ), $query->p( "FirstFileNameInArray" ), #$query->p( $fileList[0] ), #output the first file in directory $query->end_html;

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  • Json get a parameter can't access on it iOS

    - by Usi Usi
    That's an example { "updated":1350213484, "id":"http://www.google.com/reader/api/0/feed-finder?q\u003dProva\u0026output\u003djson", "title":"Risultati di feed per \"Prova\"", "self":[ { "href":"http://www.google.com/reader/api/0/feed-finder?q\u003dProva\u0026output\u003djson" } ], "items":[ { "title":"Home Page - La prova del cuoco", "id":"http://www.laprovadelcuoco.rai.it/", "updated":1350213485, "feed":[ { "href":"http://www.laprovadelcuoco.rai.it/dl/portali/site/page/Page-ffb545b4-9e72-41e5-866f-a465588c43fa-rss.html" } ], "alternate":[ { "href":"http://www.laprovadelcuoco.rai.it/", "type":"text/html" } ], "content":{ "direction":"ltr", "content":"Diventa un cuoco provetto con “La Prova del Cuoco”: le videoricette in un' applicazione di facile e veloce consultazione per il tuo Iphone. Scopri come acquistare ..." } }, { "title":"Le prove Invalsi di matematica e italiano", "id":"http://online.scuola.zanichelli.it/quartaprova/", "updated":1350213486, "feed":[ { "href":"http://online.scuola.zanichelli.it/quartaprova/feed/" } ], "alternate":[ { "href":"http://online.scuola.zanichelli.it/quartaprova/", "type":"text/html" } ], "content":{ "direction":"ltr", "content":"Un sito Zanichelli dedicato alle prove Invalsi di italiano e matematica: esercitazioni, consigli, informazioni utili, novità, aggiornamenti e blog d'autore sulle prove ..." } }, How can I get the feed URL? That's what I do NSString *daParsare=[reader searchFeed:searchText]; NSArray *items = [[daParsare JSONValue] objectForKey:@"items"]; for (NSDictionary *item in items) { NSString *title = [item objectForKey:@"title"]; NSString *feed = [item valueForKeyPath:@"feed.href"]; } [tab reloadData]; With the title everything is ok but when I try to access to the feed paramater I get the error...

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  • [Rails] checkbox to update attribute

    - by Jeff
    [Updated a bit] I have a Task model that has a :completed boolean attribute. If I click on it I want it to execute the 'finish' method. The main problem is that I am displays a series of checkboxes in a list and subsequent checkboxes after the first one are ignored. The method is never called for the given task/checkbox combo. I have this chunk of code in my view: <% current_user.tasks.each do |t|%> <% if t.completed == false %> <%= check_box_tag :completed, true, checked = false %> <%= observe_field :completed, :url => { :controller => 'tasks', :action => :finish , :id => t.id }, :frequency => 0.25, :update => :completed, :with => true %> and my finish method looks like this: def finish @task = Task.find(params[:id]) new = {:completed => true} @task.update_attributes(new) render :update do |page| page.replace_html "taskListing", :partial => 'home/task_listing' end

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  • PHP Function parameters - problem with var not being set

    - by Marty
    So I am obviously not a very good programmer. I have written this small function: function dispAdjuggler($atts) { extract(shortcode_atts(array( 'slot' => '' ), $atts)); $adspot = ''; $adtype = ''; // Get blog # we're on global $blog_id; switch ($blog_id) { case 1: // root blog HOME page if (is_home()) { switch ($slot) { case 'top_leaderboard': $adspot = '855525'; $adtype = '608934'; break; case 'right_halfpage': $adspot = '855216'; $adtype = '855220'; break; case 'right_med-rectangle': $adspot = '858222'; $adtype = '613526'; break; default: throw new Exception("Ad slot is not defined"); break; } When I reference the function on a page like so: <?php dispAdjuggler("top_leaderboard"); ?> The switch is throwing the default exception. What am I doing wrong here? Thanks!!

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  • Why does PEAR get installed to my user directory?

    - by webworm
    I am new to Linux and I am attempting to install the PHP PEAR library on a virtual server which is running Ubuntu. I am following a tutorial that covers installing PEAR but have run up against an area where I am confused. When running the PEAR installation program I am prompted as to what I want the INSTALL_PREFIX to be. Evidently the INSTALL_PREFIX, among other things, determines where PEAR will be installed. The tutorial suggest the value of INSTALL_PREFIX be the following path ... "/home/MY_USER_NAME/pear" where MY_USER_NAME = my user account Having come from a Windows world, applications are installed on the system where everyone can use them. If I install PEAR underneath my user directory will other developers on the system be able to make use of PEAR in their PHP scripts? I want to make PEAR available to all users and not just myself. Could someone explain to me the difference between installing for all users and installing just for myself? Does the install location matter? Should I be installing PEAR in a different location? Thanks for any suggestions. P.S. The tutorial I am following is located at the following URL ... http://articles.sitepoint.com/article/getting-started-with-pear/2

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  • Why does my Perl CGI program fail with "Software error: ..."?

    - by kiran
    When I try to run my Perl CGI program, the returned web page tells me: Software error: For help, please send mail to the webmaster (root@localhost), giving this error message and the time and date of the error. Here is my code in one of the file: #!/usr/bin/perl use lib "/home/ecoopr/ecoopr.com/CPAN"; use CGI; use CGI::FormBuilder; use CGI::Session; use CGI::Carp (fatalsToBrowser); use CGI::Session; use HTML::Template; use MIME::Base64 (); use strict; require "./db_lib.pl"; require "./config.pl"; my $query = CGI-new; my $url = $query-url(); my $hostname = $query-url(-base = 1); my $login_url = $hostname . '/login.pl'; my $redir_url = $login_url . '?d=' . $url; my $domain_name = get_domain_name(); my $helpful_msg = $query-param('m'); my $new_trusted_user_fname = $query-param('u'); my $action = $query-param('a'); $new_trusted_user_fname = MIME::Base64::decode($new_trusted_user_fname); ####### Colin: Added July 12, 2009 ####### my $view = $query-param('view'); my $offset = $query-param('offset'); ####### Colin: Added July , 2009 ####### #print $session-header; #print $new_trusted_user; my $helpful_msg_txt = qq[]; my $helpful_msg_div = qq[]; if ($helpful_msg)

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  • Load more function in Javascript

    - by erastusnjuki
    EDIT: This question was initially too general, I think. So What I really need is a very good tutorial on how to implement the Load More function on Safari for iPhone just like the Twitter website(mobile.twitter.com) does. Just a wordpress plugin won't really help. But if the plugin is well explained, like if it is wptouch, home(that also has this function) that can also do. I know that it doesn't really matter that it is being displayed on a mobile device, but the point I am stressing is that if such a function is well explained, then it will be up to me to know how to customize it to suit me. I am using a javascript function to load entries that come from the database dynamically, so that content opens in the same page (like with twitter(tweets feed) and facebook(news feed)). The php/html version(That opens a page in a new tab) is echo '<a href="http://'. $_SERVER['HTTP_HOST'] .'/'.$domain_page.'?form='.$form_id.'&page='.($page+1).'">Load more entries&rsaquo; </a>'; The javascript/ajax version: <div id="call_hv<?php echo md5($_SERVER['REQUEST_URI']); ?>" class="ajax-load-more"> <img id="spinner<?php echo md5($_SERVER['REQUEST_URI']); ?>" class="spin" src="<?php bloginfo('template_directory'); ?>/images/main-ajax-loader.gif" style="display:none" alt="" /> <a class="ajax" href="javascript:$ajax_hv('#spinner<?php echo md5($_SERVER['REQUEST_URI']); ?>').fadeIn(200); $ajax_hv('#ajaxentries_hv<?php echo md5($_SERVER['REQUEST_URI']); ?>').load('form='<? echo $form_id; ?>&page=<?php echo $page+1;?>', {}, function(){ $ajax_hv('#call_hv<?php echo md5($_SERVER['REQUEST_URI']); ?>').fadeOut();})">Load more entries... </a>

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  • How to remove a "green screen" portrait background

    - by danbystrom
    I'm looking for a way to automatically remove (=make transparent) a "green screen" portrait background from a lot of pictures. My own attempts this far have been... ehum... less successful. I'm looking around for any hints or solutions or papers on the subject. Commercial solutions are just fine, too. And before you comment and say that it is impossible to do this automatically: no it isn't. There actually exists a company which offers exactly this service, and if I fail to come up with a different solution we're going to use them. The problem is that they guard their algorithm with their lives, and therefore won't sell/license their software. Instead we have to FTP all pictures to them where the processing is done and then we FTP the result back home. (And no, they don't have an underpaid staff hidden away in the Philippines which handles this manually, since we're talking several thousand pictures a day...) However, this approach limits its usefulness for several reasons. So I'd really like a solution where this could be done instantly while being offline from the internet.

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  • Call to a member function get_segment() error

    - by hogofwar
    I'm having this problem with this piece of PHP code: class Core { public function start() { require("funk/funks/libraries/uri.php"); $this->uri = new uri(); require("funk/core/loader.php"); $this->load = new loader(); if($this->uri->get_segment(1) != "" and file_exists("funk/pages/".$uri->get_segment(1).".php")){ Only a snippet of the code The best way I can explain it is that it is a class calling upon another class (uri.php) and i am getting the error: Fatal error: Call to a member function get_segment() on a non-object in /home/eeeee/public_html/private/funkyphp/funk/core/core.php on line 11 (the if($this-uri-get_segment(1) part) I'm having this problem a lot and it is really bugging me. the library code is: <?php class uri { private $server_path_info = ''; private $segment = array(); private $segments = 0; public function __construct() { $segment_temp = array(); $this->server_path_info = preg_replace("/\?/", "", $_SERVER["PATH_INFO"]); $segment_temp = explode("/", $this->server_path_info); foreach ($segment_temp as $key => $seg) { if (!preg_match("/([a-zA-Z0-9\.\_\-]+)/", $seg) || empty($seg)) unset($segment_temp[$key]); } foreach ($segment_temp as $k => $value) { $this->segment[] = $value; } unset($segment_temp); $this->segments = count($this->segment); } public function segment_exists($id = 0) { $id = (int)$id; if (isset($this->segment[$id])) return true; else return false; } public function get_segment($id = 0) { $id--; $id = (int)$id; if ($this->segment_exists($id) === true) return $this->segment[$id]; else return false; } } ?>

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  • Maven (EJB) project with client and server artifacts

    - by Cornel Masson
    Here's my variation on the "multiple artifacts from Maven build" question: I'm porting from Ant to Maven. My application is an EJB server that is packaged as an EAR, but it also exposes a client JAR for use by other client apps. This jar contains the EJB interfaces, facade class and some helpers. I know that the Maven way is to have one artifact per project (POM); however, both artifacts (server EAR and client JAR) need to be built from the same source tree - server and client share, for example, the EJB and 'home' interfaces. How do I do this in Maven? Do I have one project containing two POMs, say server-pom.xml & client-pom.xml? I was thinking I could also have a parent POM (pom.xml) that can be used to build both client and server with one foul swoop? However, the lifecycles diverge after the 'package' phase, since the server has to go through assembly (tar/gzip), while the client is done after 'package' and can simply be installed into the repository. Any advice/experience on the best way to approach this?

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  • Time to start a counter on client-side.

    - by Felipe
    Hi everybody, I'm developing an web application using asp.net mvc, and i need to do a stopwatch (chronometer) (with 30 seconds preprogrammed to start in a certain moment) on client-side using the time of the server, by the way, the client's clock can't be as the server's clock. So, i'm using Jquery to call the server by JSon and get the time, but it's very stress because each one second I call the server to get time, something like this: $(function() { GetTimeByServer(); }); function GetTimeByServer() { $.getJSon('/Home/Time', null, function(result) { if (result.SecondsPending < 30) { // call another function to start an chronometer } else { window.SetTimeout(GetTimeByServer, 1000); //call again each 1 second! } }); } It works fine, but when I have more than 3 or 4 call like this, the browser slowly but works! I'd like to know, how improve more performace in client side, or if is there any way to do this... is there any way to client listen the server like a "socket" to know if the chronometer should start... PS: Sorry for my english! thanks Cheers

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  • Model value not being set on return from View to Controller

    - by sagesky36
    I have a boolean model variable who's value is supposed to be set to TRUE in order to perform a process on return back into the Controller. It works absolutely fine on my local machine, but not on the remote web server. Can somebody PLEASE inform me what I am missing? Below is the "proof of the pudding": The boolean value in quesion is "ShouldGeneratePdf"; MODEL: namespace PDFConverterModel.ViewModels { public partial class ViewModelTemplate_Guarantors { public ViewModelTemplate_Guarantors() { Templates = new List<PDFTemplate>(); Guarantors = new List<tGuarantor>(); } public int SelectedTemplateId { get; set; } public List<PDFTemplate> Templates { get; set; } public int SelectedGuarantorId { get; set; } public List<tGuarantor> Guarantors { get; set; } public string LoanId { get; set; } public string DepartmentId { get; set; } public bool isRepeat { get; set; } public string ddlDept { get; set; } public string SelectedDeptText { get; set; } public string LoanTypeId { get; set; } public string LoanType { get; set; } public string Error { get; set; } public string ErrorT { get; set; } public string ErrorG { get; set; } public bool ShowGeneratePDFBtn { get; set; } public bool ShouldGeneratePdf { get; set; } } } MasterPage: <!DOCTYPE html> <html> <head> <title>@ViewBag.Title</title> <link href="@Url.Content("~/Content/Site.css")" rel="stylesheet" type="text/css" /> <link href="@Url.Content("~/Content/kendo/2012.2.913/kendo.common.min.css")" rel="stylesheet" type="text/css" /> <link href="@Url.Content("~/Content/kendo/2012.2.913/kendo.dataviz.min.css")" rel="stylesheet" type="text/css" /> <link href="@Url.Content("~/Content/kendo/2012.2.913/kendo.blueopal.min.css")" rel="stylesheet" type="text/css" /> <script src="@Url.Content("~/Scripts/jquery-1.7.1.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/modernizr-2.5.3.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/kendo/2012.2.913/kendo.all.min.js")"></script> <script src="@Url.Content("~/Scripts/kendo/2012.2.913/kendo.aspnetmvc.min.js")"></script> </head> <body> <div class="page"> <header> <div id="title"> <h1>BHG :: PDF Service Generator</h1> </div> </header> <section id="main"> @RenderBody() </section> <footer> </footer> </div> </body> </html> View: @model PDFConverterModel.ViewModels.ViewModelTemplate_Guarantors @using (Html.BeginForm("ProcessForm", "Home", new AjaxOptions { HttpMethod = "POST" })) { <table style="width: 1000px"> @Html.HiddenFor(x => x.ShouldGeneratePdf) <tr> <td> <img alt="BHG Logo" src="~/Images/logo.gif" /> </td> </tr> <tr> <td> @(Html.Kendo().IntegerTextBox() .Placeholder("Enter Loan Id") .Name("LoanId") .Format("{0:#######}") .Value(Convert.ToInt32(Model.LoanId)) ) </td> </tr> <tr> <td>@Html.Label("Loan Type: ") @Html.DisplayFor(model => Model.LoanType) </td> <td> <label for="ddlDept">Department:</label> @(Html.Kendo().DropDownListFor(model => Model.ddlDept) .Name("ddlDept") .DataTextField("DepartmentName") .DataValueField("DepartmentID") .Events(e => e.Change("Refresh")) .DataSource(source => { source.Read(read => { read.Action("GetDepartments", "Home"); }); }) .Value(Model.ddlDept.ToString()) ) </td> </tr> @if (Model.ShowGeneratePDFBtn == true) { if (Model.ErrorT == string.Empty) { <tr> <td> <u><b>@Html.Label("Templates:")</b></u> </td> </tr> <tr> @for (int i = 0; i < Model.Templates.Count; i++) { <td> @Html.CheckBoxFor(model => Model.Templates[i].IsChecked) @Html.DisplayFor(model => Model.Templates[i].TemplateId) </td> } </tr> } else { <tr> <td> <b>@Html.DisplayFor(model => Model.ErrorT)</b> </td> </tr> } if (Model.ErrorG == string.Empty) { <tr> <td> <u><b>@Html.Label("Guarantors:")</b></u> </td> </tr> <tr> @for (int i = 0; i < Model.Guarantors.Count; i++) { <td> @Html.CheckBoxFor(model => Model.Guarantors[i].isChecked) @Html.DisplayFor(model => Model.Guarantors[i].GuarantorFirstName)&nbsp;@Html.DisplayFor(model => Model.Guarantors[i].GuarantorLastName) </td> } </tr> } else { <tr> <td> <b>@Html.DisplayFor(model => Model.ErrorG)</b> </td> </tr> } } <tr> <td> <input type="submit" name="submitbutton" id="btnRefresh" value='Refresh' /> </td> @if (Model.ShowGeneratePDFBtn == true) { <td> <input type="submit" name="submitbutton" id="btnGeneratePDF" value='Generate PDF' /> </td> } </tr> <tr> <td style="color: red; font: bold"> @Model.Error </td> </tr> </table> } <script type="text/javascript"> $('#btnRefresh').click(function () { Refresh(); }); function Refresh() { var LoanID = $("#LoanID").val(); if (parseInt(LoanID) != 0) { $('#ShouldGeneratePdf').val(false) document.forms[0].submit(); } else { alert("Please enter a LoanId"); } } //$(function () { // //DOM loaded // $('#btnGeneratePDF').click(function () { // DisableGeneratePDF(); // $('#ShouldGeneratePdf').val(true) // }); //}); //function DisableGeneratePDF() { // $('#btnGeneratePDF').attr("disabled", true); // $('#btnRefresh').attr("disabled", true); //} $('#btnGeneratePDF').click(function () { alert("inside click function"); DisableGeneratePDF(); $('#ShouldGeneratePdf').val(true) tof = $('#ShouldGeneratePdf').val(); alert("ShouldGeneratePdf set to " + tof); }); function DisableGeneratePDF() { alert("begin DisableGeneratePDF function"); $('#btnGeneratePDF').attr("disabled", true); $('#btnRefresh').attr("disabled", true); alert("end DisableGeneratePDF function"); } </script> Controller: [HttpPost] public ActionResult ProcessForm(string submitbutton, ViewModelTemplate_Guarantors model, FormCollection collection) if ((submitbutton == "Refresh") || (submitbutton == null) && (model.ShouldGeneratePdf == false)) { } else if ((submitbutton == "Generate PDF") || (model.ShouldGeneratePdf == true)) { } The "Alerts" in the script above come out to exactly what they should be on the remote server. The last alert shows that the value of the bool variable is "true". However, when I do page source views of the hidden variable, below is the result. The values of the hidden variable when the page loads and when the last alert button finishes are as follows: My local machine: The remote machine: As you can see, the value on my machine is set to true when the process executes. However, on the remote machine, it is set to false where it then doesn't excute. Why isn't the value in the model being returned as TRUE on the remote machine?

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  • Wordpress is_front_page if statement

    - by Anders Kitson
    I have the following code below. I am trying to get rid of the box articles div when I am on the home page the code works when the html is outside of the else portion of the IF statement, as soon as I put it inside the page goes blank, I can't seem to figure out where I have broken the code. Any help would be great. <?php if(is_front_page()) { if(function_exists('wp_content_slider')) { wp_content_slider(); } } else{ ?> <div class="box articles"> <div class="block" id="articles"> <h2><?php the_title(); ?></h2> <div class="article"> <div class="entry"> <?php the_content(); ?> </div> <?php edit_post_link('Modifca Contenuto.', '<p>', '</p>'); ?> </div> </div> </div> <?php endwhile; endif; ?> <? } ?>

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  • Ruby on Rails user login form in main layout

    - by Jimmy
    Hey guys I have a simple ror application for some demo stuff. I am running into a problem with trying to move my login form from the users controller and just have it displayed in the main navigation so that a user can easily log in from anywhere. The problem is the form doesn't generate the correct action for the html form. Ruby code: <% form_for(url_for(:action => 'login'), :method => 'post') do |f| %> <li><%= f.text_field("username") %></li> <li><%= f.password_field("password") %></li> <li><%= submit_tag("Login")%></li> <% end %> The problem is depending on the controller I am currently in this generates HTML actions like <form action="/home" method="post">...</form> when it should be generating HTML like so <form action="/login" method="post">...</form> I know I could simply do an HTML form here but I want to keep things as easy to maintain as possible. Any help?

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  • grails question (sample 1 of Grails To Action book) problem with Controller and Service

    - by fegloff
    Hi, I'm doing Grails To Action sample for chapter one. Every was just fine until I started to work with Services. When I run the app I have the following error: groovy.lang.MissingPropertyException: No such property: quoteService for class: qotd.QuoteController at qotd.QuoteController$_closure3.doCall(QuoteController.groovy:14) at qotd.QuoteController$_closure3.doCall(QuoteController.groovy) at java.lang.Thread.run(Thread.java:619) Here is my groovie QuoteService class, which has an error within the definition of GetStaticQuote (ERROR: Groovy:unable to resolve class Quote) package qotd class QuoteService { boolean transactional = false def getRandomQuote() { def allQuotes = Quote.list() def randomQuote = null if (allQuotes.size() > 0) { def randomIdx = new Random().nextInt(allQuotes.size()) randomQuote = allQuotes[randomIdx] } else { randomQuote = getStaticQuote() } return randomQuote } def getStaticQuote() { return new Quote(author: "Anonymous",content: "Real Programmers Don't eat quiche") } } Controller groovie class package qotd class QuoteController { def index = { redirect(action: random) } def home = { render "<h1>Real Programmers do not each quiche!</h1>" } def random = { def randomQuote = quoteService.getRandomQuote() [ quote : randomQuote ] } def ajaxRandom = { def randomQuote = quoteService.getRandomQuote() render "<q>${randomQuote.content}</q>" + "<p>${randomQuote.author}</p>" } } Quote Class: package qotd class Quote { String content String author Date created = new Date() static constraints = { author(blank:false) content(maxSize:1000, blank:false) } } I'm doing the samples using Eclipse with grails addin. Any advice? Regards, Francisco

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  • Spring validation has error in XML document from ServletContext resource

    - by user1441404
    I applied spring validation in my registration page .but the follwing error are shown in my server log of my app engine server. javax.servlet.UnavailableException: org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 22 in XML document from ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml] is invalid; nested exception is org.xml.sax.SAXParseException; lineNumber: 22; columnNumber: 30; cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'property'. My code is given below : <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd > <beans:bean name="/register" class="com.my.registration.NewUserRegistration"> <property name="validator"> <bean class="com.my.validation.UserValidator" /> </property> <beans:property name="formView" value="newuser"></beans:property> <beans:property name="successView" value="home"></beans:property> </beans:bean> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> </beans:beans>

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  • As an Agile Java developer, what should I be looking for when hiring a C++ developer?

    - by agoudzwaard
    I come from an effective team of Agile Java developers. We've had a lot of success in hiring more people like ourselves - people passionate about technology with experience primarily in the Agile Java/J2EE space. We're looking to hire our first C++ developer to serve as an on-shore resource for maintaining and adding to the C++ portion of our code base. Up until now the entirety of our C++ development has been done out of an off-shore location. We consider our interview process to be fairly thorough: A phone screen centered on Object-Oriented Programming and Java A non-trivial at-home code project using Java An in-person interview covering technical and behavioral competency We look for a demonstration of Agile best practices (expressive code, test-driven development, continuous integration) throughout the entire process, however there is a common conception that Agility is primarily practiced by Java developers. If we retrofit our interview process for C++, should we still expect Agile qualities when interviewing for a C++ role? I'm asking on behalf of a team that has worked with Java too long to know what a good C++ developer looks like. Specifically we're looking to answer the following questions: Can we expect a demonstrated understanding of OO design and Separation of Concerns? In the code project we want the candidate to write unit tests. Would a good C++ developer be surprised by this expectation? Are there any "extra" competencies we can look for? For example with Java developers we always look for a familiarity with Dependency Injection.

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  • Starting a code library.

    - by Rob Stevenson-Leggett
    Hi, I've been meaning to start a library of reusable code snippets for a while and never seem to get round to it. I think my main problems are: Where to start. What structure should my library take? Should it be a compiled library (where appropriate or just classes I can drop into any project? Or a library project that can be included? In my experience, a built library will quickly become out of date and the source will get lost. So I'm leaning towards source libraries that I can export from SVN and include in any project. Intellectual property. I am employeed, so a lot of the code I write is not my IP. How can I ensure that I don't give my own IP away using it on projects in work and at home? I'm thinking the best way would be to licence my library with an open source licence and make sure I only add to it in my own time using my own equipment and therefore making sure that if I use it in a work project the same rules apply as if I was using a third party library. I write in many different languages and often would require two or more parts of this library. Should I look at implementing a few template projects and a core project for each of my chosen reusable components and languages? Has anyone else got this sort of library and how do you organise and update it?

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  • Getting the number of posts a user has by the number of rows returned?

    - by transparent
    So I have a question. I have chatting/IM website that I am working on and I was making a user profile page. I wanted to show how many posts that user had. Another issue I had earlier was that when I called a certain value it would return a 'Resource #1' type string. But I got that working by using $totalposts=mysql_query("SELECT * FROM `posts` WHERE Username='" . $username . "'"); $totalposts = mysql_fetch_row($totalposts); $totalposts = $totalposts[0]; But that just returns the last postID of the most recent post. I thought that mysql_num_rows would work. But this code returns an error (example with numbers): 29: $totalposts=mysql_query("SELECT * FROM `posts` WHERE Username='" . $username . "'"); 30: $totalposts = mysql_num_rows($totalposts); 31: $totalposts =mysql_fetch_row($totalposts); 32: $totalposts = $totalposts[0]; That returns this error: Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/a9091503/public_html/im/user.php on line 31 Thanks guys. :) I hope you can figure this out. :D

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  • Save object in CoreData

    - by John
    I am using CoreData with iPhone SDK. I am making a notes app. I have a table with note objects displayed from my model. When a button is pressed I want to save the text in the textview to the object being edited. How do I do this? I've been trying several things but none seem to work. Thanks EDIT: NSManagedObjectContext *context = [fetchedResultsController managedObjectContext]; NSEntityDescription *entity = [[fetchedResultsController fetchRequest] entity]; NSManagedObject *newManagedObject = [NSEntityDescription insertNewObjectForEntityForName:[entity name] inManagedObjectContext:context]; [newManagedObject setValue:detailViewController.textView.text forKey:@"noteText"]; NSError *error; if (![context save:&error]) { /* Replace this implementation with code to handle the error appropriately. abort() causes the application to generate a crash log and terminate. You should not use this function in a shipping application, although it may be useful during development. If it is not possible to recover from the error, display an alert panel that instructs the user to quit the application by pressing the Home button. */ NSLog(@"Unresolved error %@, %@", error, [error userInfo]); abort(); } The above code saves it correctly but it saves it as a new object. I want it to be saved as the one I have selected in my tableView.

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  • GWT with JPA - no persistence provider...

    - by meliniak
    GWT with JPA There are two projects in my eclipse workspace, let's name them: -JPAProject -GWTProject JPAProject contains JPA configuration stuff (persistence.xml, entity classes and so on). GWTProject is an examplary GWT project (taken from official GWT tutorial). Both projects work fine alone. That is, I can create EMF (EntityManagerFactory) in JPAProject and get entities from the database. GWTProject works fine too, I can run it, fill the field text in the browser and get the response. My goal is to call JPAProject from GWTProject to get entities. But the problem is that when calling DAO, I get the following exception: [WARN] Server class 'com.emergit.service.dao.profile.ProfileDaoService' could not be found in the web app, but was found on the system classpath [WARN] Adding classpath entry 'file:/home/maliniak/workspace/emergit/build/classes/' to the web app classpath for this session [WARN] /gwttest/greet javax.persistence.PersistenceException: No Persistence provider for EntityManager named emergitPU at javax.persistence.Persistence.createEntityManagerFactory(Unknown Source) at javax.persistence.Persistence.createEntityManagerFactory(Unknown Source) at com.emergit.service.dao.profile.JpaProfileDaoService.<init>(JpaProfileDaoService.java:19) at pl.maliniak.server.GreetingServiceImpl.<init>(GreetingServiceImpl.java:21) . . . at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488) [ERROR] 500 - POST /gwttest/greet (127.0.0.1) 3812 bytes I guess that the warnings at the beginning can be omitted for now. Do you have any ideas? I guess I am missing some basic point. All hints are highly apprecieable.

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  • Create Session Variable from different datasources?

    - by Szafranamn
    Currently I am developing a dynamic website using Dreamweaver cs5 with ColdFusion 9 and using Access to create my databases along with QuickBooks and QODBC to create database. I have established a login session variable stemming from the login page. This session variable is being drawn from one Datasource "Access" Table "Logininfo" Field "FullName" but I wanted to create another session variable either at this point or further into the member's page to use in a query sequence. This session variable would stem from another Datasoucre "QBs" Table "Invoice" Field "CustomerRefFullName" which is generated through Quickbooks and QODBC. I am not sure if this is possible but if it is how do I do it. I want to do this so I can query the Invoice database to upload the customer's Invoices unique to them onto their page. So it would have to be related to their login credentials. If there is another better route to take I would greatly appreciate the advice. Below is the login code if there is additional information needed let me know. This is my current thinking/plan to do what I wish to intend hence the need to create the session variable: I have another Datasource "QBs" with a Table "Invoice" when I create another webpage for the customer to see their invoice I need to create a recordset that accesses that Table. In order to do so I think the best way would some home convert the session.FullName (which came from Access Datasource, Logininfor Table) into a session.CustomerRefFullName (which would have to come from (Datasource: QBs Table: Invoice Field: CustomerRefFullName) that way I could set the query WHERE CustomerRefFullName and have each logged in user see their specific Invoices. So is there a way to turn the session variable off one datasource/table into a different sessionvariable off a new datasource/table even if it is unique just to that page??? <cfif IsDefined("FORM.username")> SELECT FullName, Username,Password,AccessLevels FROM Logininfo WHERE Username= AND Password=

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  • URL routing in an MVC framework - PHP

    - by Walderman
    I'm developing an MVC framework in PHP from scratch; mostly for the learning experience but this could easily end up in a live project. I went through this tutorial as a base and I've expanded from there. Requests are made like this: examplesite.com/controller/action/param1/param2/ and so on... And this is my .htaccess file: RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php?rt=$1 [L,QSA] So all requests go to index.php and they are routed to the correct controller and action from there. If no controller or action is given, then the default 'index' is assumed for both. I have an index controller with an index action, which is supposed to be the home page of my site. I can access it by going to examplesite.com (since the index part is assumed). It has some images, a link to a stylesheet, and some scripts. They are linked with paths relative to index.php. I thought this would be fine since all request go to index.php and all content is simply included in this page using php. This works if I go to examplesite.com. I will see all of the images and styles, and scripts will run. However, if I go to examplesite.com/index, I am routed to the correct part of the site, but all of the links don't work. Does the browser think I am in a different folder? I would like to be able to use relative paths for all of the content in my site, because otherwise I need to use absolute paths everywhere to make sure things will show up. Is this possible?

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