Search Results

Search found 27396 results on 1096 pages for 'mysql query'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 517/1096 | < Previous Page | 513 514 515 516 517 518 519 520 521 522 523 524  | Next Page >

  • What statistics app should I use for my website?

    - by Camran
    I have my own server (with root access). I need statistics of users who visit my website etc etc... I have looked at an app called Webalyzer... Is this a good choice? I run apache2 on a Ubuntu 9 system... If you know of any good statistics apps for servers please let me know. And a follow-up question: All statistics are saved in log-files right? So how large would these log-files become then? Possibility to split them would be good, dont know if this is possible with Webalyzer though...

    Read the article

  • SELECT Data from multiple tables?

    - by Kyle R
    I have 3 tables, with 3 fields all the same. I basically want to select information from each table For example: userid = 1 I want to select data from all 3 tables, where userid = 1 I am currently using: SELECT r.*, p.*, l.* FROM random r LEFT JOIN pandom p ON r.userid = p.userid LEFT JOIN landom l ON l.userid = r.userid WHERE r.userid = '1' LIMIT 0, 30 But it doesn't seem to work.

    Read the article

  • Return Total Rows from a table.

    - by theband
    while($row=mysql_fetch_array($result)) { $output .= "<Reports>"; $output .= "<ProjectName>"; $output .= $row['ProjectName']; $output .= "</ProjectName>"; $output .= "<ProjectCount>"; $output .= $row=mysql_fetch_array($result) $output .= "</ProjectCount>"; $output .= "</Reports>"; } Can i return the number of rows in table like this, i am getting XML markup error.

    Read the article

  • error defining foreign key PhpMyAdmin

    - by Ngounou lassale
    I am new to PhpMyAdmin. I will like to create a foreign key for my tables. In fact i have create tableI with this structures(A as int(11) autoincrement, B as varchar) TableII ( A_2 as int(11) auto increment, B_2 as varchar, A as int(11). I have declared A as an index in tableII, now when i go to relationship view to precise A as a foreign key i always have this error Erreur lors de la création de la clé étrangère sur ID_Ville (vérifiez le type des colonnes) Erreur ALTER TABLE tb_quartier ADD FOREIGN KEY ( ID_Ville ) REFERENCES ingenieris2.tb_ville ( ID_Ville ) ON DELETE RESTRICT ; Please Help thanks!

    Read the article

  • How to return result set based on other rows

    - by understack
    I've 2 tables - packages and items. Items table contains all items belonging to the packages along with location information. Like this: Packages table id, name, type(enum{general,special}) 1, name1, general 2, name2, special Items table id, package_id, location 1, 1, America 2, 1, Africa 3, 1, Europe 4, 2, Europe Question: I want to find all 'special' packages belonging to a location and if no special package is found then it should return 'general' packages belonging to same location. So, for 'Europe' : package 2 should be returned since it is special package (Though package 1 also belongs to Europe but not required since its a general package) for 'America' : package 1 should be returned since there are no special packages

    Read the article

  • Which of these queries is more efficient?

    - by Brian
    Which of these queries are more efficient? select 1 as newAndClosed from sysibm.sysdummy1 where exists ( select 1 from items where new = 1 ) and not exists ( select 1 from status where open = 1 ) select 1 as newAndClosed from items where new = 1 and not exists ( select 1 from status where open = 1 )

    Read the article

  • Joining two mysql_fetch_arrays

    - by John Harbert
    I am trying to piece two queries together. Below is the code Im using. However the table is splitting up the data. How can I remedy this? Or what better solutions are there? while($row = mysql_fetch_array($result)) { echo "<tr id='centered' >"; echo "<td class='leftalign'>" . $row['Quarter_Name'] . "</td>"; echo "<td>" . $row['Quarterly_yield'] . "</td>"; echo "<td>" . $row['Quarterly_yield'] . "</td>"; echo "<td>" . $row['Quarterly_yield'] . "</td>"; } while($row = mysql_fetch_array($result8)) { echo "<td>" . $row['Quarterly_yield'] . "</td>"; }

    Read the article

  • Calculating number of online visitors?

    - by Syom
    i need to show the number of online visitors, but there is a problem with selecting algoritm to do it! maybe i must create a table in DB, where i'll store ip addresses of visitors and time of visit! by so i can show the count of ip addresses, which's time = NOW() - 10 minutes, for example...("now()-10 minutes" is just to show the logic, i know that this is not a function:) is this goog way to go? or maybe it's better to use AJAX methods to store the data? please give me an idea. Thanks

    Read the article

  • Is UTF-8 enough for all common languages?

    - by jack
    I just wanted to develop a translation app in a Django projects which enables registered users with certain permissions to translate every single message it appears in latest version. My question is, what character set should I use for database tables in this translation app? Looks like some european language characters cannot be stored in UTF-8?

    Read the article

  • Android-SQLite: How to Count specific value from Column?

    - by sanpatil
    I have two table (TABLE_EXAM,TABLE_RESULT). Here is value of my TABLE_RESULT. result_id exam_id question_id correct_answer 1 2 4 y 2 2 5 y 3 2 6 n 4 2 7 y I need to count how many correct_answer='y' where exam_id=2. I try following code but it return 0. public int calculateResult(int examId,String confirmAnswer) { int correctAnswer=0; try { SQLiteDatabase db=this.getWritableDatabase(); String selectQuery=("select count(correctAnswer) from result where exam_id ='" + examId + "' and correctAnswer ='" + 'y' +"'" ); // String selectQuery=("SELECT COUNT(*)FROM result WHERE exam_id ='" + examId + "' and correctAnswer ='" + confirmAnswer +"'" ); Cursor cursor = db.rawQuery(selectQuery, null); if(cursor.moveToLast()) { correctAnswer=cursor.getInt(3); } } catch(Exception e) { e.printStackTrace(); } return correctAnswer; } In variable confirm_answer i pass "y". Give me some hint or reference. Any help is appreciated. Thanks in Advance

    Read the article

  • How to pass a variable to a IN clause?

    - by Thanu
    Lets say I have a SP that has a SELECT statements as follows, SELECT product_id, product_price FROM product WHERE product_type IN ('AA','BB','CC'); But data goes to that IN clause must be through a single variable that contains the string of values. Something link below SELECT product_id, product_price FROM product WHERE product_type IN (input_variables); But its not working that way. Any idea how to do this?

    Read the article

  • I can NOT submit the form

    - by buri kuri
    Hey guys Im trying to develop an advance consumer website using php and I stuck somewhere while trying to get the data with submitting to another page. All I want to do is to get the checkbox values which are stored in an array and checked by user. I urgently need your help please here is the code: $sql2="SELECT * FROM alinanfis WHERE alinanfis.fis_id='".$fis."'" ; $resultFis=mysql_query($sql2); if(mysql_num_rows($resultFis)>0) { print "<form method='POST' action='deletionResult.php'>"; print "<table>"; print "<tr>"; print "<th style='background: transparent;'></th>"; print "<th>Fis No</th>"; print "<th>isim</th>"; print "<th>soyisim</th>"; print "<th >Tarih</th>"; print "<th>Fis Tipi</th>"; print "<th>Nerede</th>"; print "<th>Litre</th>"; print "<th>Tutar</th>"; print "</tr>"; while($rowAlinan=mysql_fetch_array($resultFis)) { $sqlFisTipi="SELECT * FROM atype WHERE a_id='".$rowAlinan['a_id']."'" ; $resultFisTipi=mysql_query($sqlFisTipi); $rowFisTipi=mysql_fetch_array($resultFisTipi); $sqlNerede="SELECT * FROM isyeri WHERE i_id='".$rowAlinan['nerde']."'" ; $resultNerede=mysql_query($sqlNerede); $rowNerede=mysql_fetch_array($resultNerede); $sqlMID="SELECT * FROM musteri WHERE m_id='".$rowAlinan['m_id']."'" ; $resultMID1=mysql_query($sqlMID); $rowMID1=mysql_fetch_array($resultMID1); print "<tr>"; print "<td><input name='checkBox[]' type='checkbox' value='".$rowAlinan['fis_id']."' /> php</td>"; print "<td>".$rowAlinan['fis_id']."</td>"; print "<td>".$rowMID1['m_name']."</td>"; print "<td>".$rowMID1['m_lastName']."</td>"; print "<td>".$rowAlinan['alinan_tarih']."</td>"; print "<td>".$rowFisTipi['a_name']."</td>"; print "<td>".$rowNerede['i_name']."</td>"; print "<td>".$rowAlinan['litre']."</td>"; print "<td>".$rowAlinan['tutar']."</td>"; print "</tr>"; } print '<div class="form_settings">'; print "<input class='submit' type='submit' name= 'send' value='Send'>"; / print '</div>'; print "</table>"; print "</form>"; }//end of if(num_rows>0) else echo '*no such receipt found!!'; mysql_close($con);

    Read the article

  • weird index behavior

    - by TasostheGreat
    I have set up my table with an index only on done_status(done_status =INT), when I use EXPLAIN SELECT * FROM reminder WHERE done_status=2 i get this back id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE reminder ALL done_status NULL NULL NULL 5 Using where but when I give this command EXPLAIN SELECT * FROM reminder WHERE done_status=1 that's what I get back: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE reminder ref done_status done_status 4 const 2 first time it shows me it uses 5 rows second time 2 rows I don't think the index works, if I understood it right first time it should give me 3 rows. What do I do wrong? SHOW INDEX FROM reminder: Table Non_unique Key_name Seq_in_index Column_name Collation Cardinality Sub_part Packed Null Index_type Comment Index_comment reminder 1 done_status 1 done_status A 5 NULL NULL BTREE

    Read the article

  • Should user preferences be included in the users table?

    - by Patrick
    I'm creating a members site, and I'm currently working on the user Preference settings. Should I create a table with all the preference fields (about 17 fields) or should I include them in the main member table along with the account settings? Is there a limit as to how many fields I should have in a table? currently the member table has about 21 fields... not sure if its okay to add another 17 more fields when I can easily just put them in another table. It'll take more coding to pull up the data though... any sugguestions?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 513 514 515 516 517 518 519 520 521 522 523 524  | Next Page >