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  • "=null" and select statement!

    - by user329820
    Hi I have asked this question before in this forum and they told me that it will retun an empty result set,I want to know that if I set the column with null values it will retun an empty result set?also the ANSI_NULLS is OFF ,thanks SELECT 'A' FROM T WHERE A = NULL;

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  • error defining foreign key PhpMyAdmin

    - by Ngounou lassale
    I am new to PhpMyAdmin. I will like to create a foreign key for my tables. In fact i have create tableI with this structures(A as int(11) autoincrement, B as varchar) TableII ( A_2 as int(11) auto increment, B_2 as varchar, A as int(11). I have declared A as an index in tableII, now when i go to relationship view to precise A as a foreign key i always have this error Erreur lors de la création de la clé étrangère sur ID_Ville (vérifiez le type des colonnes) Erreur ALTER TABLE tb_quartier ADD FOREIGN KEY ( ID_Ville ) REFERENCES ingenieris2.tb_ville ( ID_Ville ) ON DELETE RESTRICT ; Please Help thanks!

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  • Dont know how to select a few records from a table as utf8

    - by kwokwai
    Hi all, I don't have phpMyAdmin installed in my web site. Sometimes I was doing some select SQL command at the backend, but when I typed in this command to show all records from table Users: select * from Users; The records were printed as ???? | ??? ??? ??? |. I don't want to make any permanent changes to the charset in the database, so, how is it possible to temporarily displayed a few records as utf8 when needed?

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  • Return Total Rows from a table.

    - by theband
    while($row=mysql_fetch_array($result)) { $output .= "<Reports>"; $output .= "<ProjectName>"; $output .= $row['ProjectName']; $output .= "</ProjectName>"; $output .= "<ProjectCount>"; $output .= $row=mysql_fetch_array($result) $output .= "</ProjectCount>"; $output .= "</Reports>"; } Can i return the number of rows in table like this, i am getting XML markup error.

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  • Calculating number of online visitors?

    - by Syom
    i need to show the number of online visitors, but there is a problem with selecting algoritm to do it! maybe i must create a table in DB, where i'll store ip addresses of visitors and time of visit! by so i can show the count of ip addresses, which's time = NOW() - 10 minutes, for example...("now()-10 minutes" is just to show the logic, i know that this is not a function:) is this goog way to go? or maybe it's better to use AJAX methods to store the data? please give me an idea. Thanks

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  • Which of these queries is more efficient?

    - by Brian
    Which of these queries are more efficient? select 1 as newAndClosed from sysibm.sysdummy1 where exists ( select 1 from items where new = 1 ) and not exists ( select 1 from status where open = 1 ) select 1 as newAndClosed from items where new = 1 and not exists ( select 1 from status where open = 1 )

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  • How to return result set based on other rows

    - by understack
    I've 2 tables - packages and items. Items table contains all items belonging to the packages along with location information. Like this: Packages table id, name, type(enum{general,special}) 1, name1, general 2, name2, special Items table id, package_id, location 1, 1, America 2, 1, Africa 3, 1, Europe 4, 2, Europe Question: I want to find all 'special' packages belonging to a location and if no special package is found then it should return 'general' packages belonging to same location. So, for 'Europe' : package 2 should be returned since it is special package (Though package 1 also belongs to Europe but not required since its a general package) for 'America' : package 1 should be returned since there are no special packages

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  • How to pass a variable to a IN clause?

    - by Thanu
    Lets say I have a SP that has a SELECT statements as follows, SELECT product_id, product_price FROM product WHERE product_type IN ('AA','BB','CC'); But data goes to that IN clause must be through a single variable that contains the string of values. Something link below SELECT product_id, product_price FROM product WHERE product_type IN (input_variables); But its not working that way. Any idea how to do this?

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  • Is UTF-8 enough for all common languages?

    - by jack
    I just wanted to develop a translation app in a Django projects which enables registered users with certain permissions to translate every single message it appears in latest version. My question is, what character set should I use for database tables in this translation app? Looks like some european language characters cannot be stored in UTF-8?

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  • I can NOT submit the form

    - by buri kuri
    Hey guys Im trying to develop an advance consumer website using php and I stuck somewhere while trying to get the data with submitting to another page. All I want to do is to get the checkbox values which are stored in an array and checked by user. I urgently need your help please here is the code: $sql2="SELECT * FROM alinanfis WHERE alinanfis.fis_id='".$fis."'" ; $resultFis=mysql_query($sql2); if(mysql_num_rows($resultFis)>0) { print "<form method='POST' action='deletionResult.php'>"; print "<table>"; print "<tr>"; print "<th style='background: transparent;'></th>"; print "<th>Fis No</th>"; print "<th>isim</th>"; print "<th>soyisim</th>"; print "<th >Tarih</th>"; print "<th>Fis Tipi</th>"; print "<th>Nerede</th>"; print "<th>Litre</th>"; print "<th>Tutar</th>"; print "</tr>"; while($rowAlinan=mysql_fetch_array($resultFis)) { $sqlFisTipi="SELECT * FROM atype WHERE a_id='".$rowAlinan['a_id']."'" ; $resultFisTipi=mysql_query($sqlFisTipi); $rowFisTipi=mysql_fetch_array($resultFisTipi); $sqlNerede="SELECT * FROM isyeri WHERE i_id='".$rowAlinan['nerde']."'" ; $resultNerede=mysql_query($sqlNerede); $rowNerede=mysql_fetch_array($resultNerede); $sqlMID="SELECT * FROM musteri WHERE m_id='".$rowAlinan['m_id']."'" ; $resultMID1=mysql_query($sqlMID); $rowMID1=mysql_fetch_array($resultMID1); print "<tr>"; print "<td><input name='checkBox[]' type='checkbox' value='".$rowAlinan['fis_id']."' /> php</td>"; print "<td>".$rowAlinan['fis_id']."</td>"; print "<td>".$rowMID1['m_name']."</td>"; print "<td>".$rowMID1['m_lastName']."</td>"; print "<td>".$rowAlinan['alinan_tarih']."</td>"; print "<td>".$rowFisTipi['a_name']."</td>"; print "<td>".$rowNerede['i_name']."</td>"; print "<td>".$rowAlinan['litre']."</td>"; print "<td>".$rowAlinan['tutar']."</td>"; print "</tr>"; } print '<div class="form_settings">'; print "<input class='submit' type='submit' name= 'send' value='Send'>"; / print '</div>'; print "</table>"; print "</form>"; }//end of if(num_rows>0) else echo '*no such receipt found!!'; mysql_close($con);

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  • Android-SQLite: How to Count specific value from Column?

    - by sanpatil
    I have two table (TABLE_EXAM,TABLE_RESULT). Here is value of my TABLE_RESULT. result_id exam_id question_id correct_answer 1 2 4 y 2 2 5 y 3 2 6 n 4 2 7 y I need to count how many correct_answer='y' where exam_id=2. I try following code but it return 0. public int calculateResult(int examId,String confirmAnswer) { int correctAnswer=0; try { SQLiteDatabase db=this.getWritableDatabase(); String selectQuery=("select count(correctAnswer) from result where exam_id ='" + examId + "' and correctAnswer ='" + 'y' +"'" ); // String selectQuery=("SELECT COUNT(*)FROM result WHERE exam_id ='" + examId + "' and correctAnswer ='" + confirmAnswer +"'" ); Cursor cursor = db.rawQuery(selectQuery, null); if(cursor.moveToLast()) { correctAnswer=cursor.getInt(3); } } catch(Exception e) { e.printStackTrace(); } return correctAnswer; } In variable confirm_answer i pass "y". Give me some hint or reference. Any help is appreciated. Thanks in Advance

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  • Return all users from group(s) specified as comma delimited value

    - by todor
    I have the following two table scenario: users id groups 1 1,2,3 2 2,3 3 1,3 4 3 and groups id 1 2 3 How do I return the IDs of all users that belong to group 2 and 1 for example? Should I look into join, a helper group_membership table or function to separate the comma delimited group IDs to get something like this: group_membership user_id group_id 1 1 1 2 1 3 2 2 2 3 ... ...

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  • weird index behavior

    - by TasostheGreat
    I have set up my table with an index only on done_status(done_status =INT), when I use EXPLAIN SELECT * FROM reminder WHERE done_status=2 i get this back id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE reminder ALL done_status NULL NULL NULL 5 Using where but when I give this command EXPLAIN SELECT * FROM reminder WHERE done_status=1 that's what I get back: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE reminder ref done_status done_status 4 const 2 first time it shows me it uses 5 rows second time 2 rows I don't think the index works, if I understood it right first time it should give me 3 rows. What do I do wrong? SHOW INDEX FROM reminder: Table Non_unique Key_name Seq_in_index Column_name Collation Cardinality Sub_part Packed Null Index_type Comment Index_comment reminder 1 done_status 1 done_status A 5 NULL NULL BTREE

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  • Auto-creating a "link" table between 2 main tables (ex table EmployeeProject from Employee and Project tables)

    - by user573382
    Hello! I have these 2 tables, Medication containing: IDMedication, IDCategory, Name, and Supplier, containing: IDSupplier, Name. I want to automatically create a relationship table, MedicationSupplier, containing: IDMedication and IDSupplier as keys, Price, and Quantity. My idea was to have a main page where i request the following data: (Medication)Name, IDCAtegory, (Supplier)Name, Price, Quantity. I'm not sure if i'm doing the right thing here. So this is what i'm receiveing in the .php where i do the insert: $Denumire=$_POST['Denumire']; //Medication Name $IDCategorie=$_POST['IDCategorie']; //IDCategory $Nume=$_POST['Nume']; //Supplier Name $Pret=$_POST['Pret']; //Price $Stoc=$_POST['Stoc']; //Quantity And this is my insert: $q_produse = "INSERT INTO produse VALUES ('','$IDCategorie','$Denumire')"; $q_prodfurniz = "INSERT INTO produsfurnizor VALUES ('','$IDFurnizor','$Pret','$Stoc')"; mysql_query($q_produse) or die($error); mysql_query($q_prodfurniz) or die($error); mysql_close(); My main problem at the moment is that i don't know how to insert IDMedication in the relationship table. Any help / suggestions of improving my code would be greatly appreciated. Thanks!

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