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  • Symfony 1.4: Is it possible to prevent escaping of a redirect URL?

    - by Tom
    Hi, If I do a redirect in action as normal: $this->redirect('@mypage?apple=1&banana=2&orange=3'); ... Symfony produces the correct URL: /something/something?apple=1&banana=2&orange=3 However, the following gets escaped for some bizarre reason: $string = 'apple=1&banana=2&orange=3'; $this->redirect('@mypage?'.$string); ... and the following URL is produced: /something/something?apple=1&amp;banana=2&amp;orange=3 Is there a way to avoid this escaping and have the ampersands appear correctly in the URL? I've tried everything I can think of and it's driving me mad. I need this for a situation where I'm pulling a saved query as a string from the database and would just like to latch it onto the URL. I'm aware that I could generate an array from the string and then generate a brand new URL from the array, but it just seems like a lot of overhead because of this silly escaping. Thanks.

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  • Check if checkbox is checked or not (ASPX)

    - by cthulhu
    I have the following code: (some.aspx.cs) if(Page.IsPostBack) { bool apple2 = false; bool pizza2 = false; bool orange2 = false; if (apple.Checked) apple2 = true; if (pizza.Checked) pizza2 = true; if (orange.Checked) orange2 = true; } (some.aspx) <tr> <td>Food:</td> <td>Apple <input type="checkbox" name="food" id="apple" value="apple" runat="server" />Pizza <input type="checkbox" name="food" id="pizza" value="pizza" runat="server" />Orange <input type="checkbox" name="food" id="orange" value="orange" runat="server" /></td> Now, i send the Boolean variables to SQL database. The problem is only with unchecked boxes. I mean, when you check some checkboxes it sends it as true (and that's right) but when i uncheck them it remains the same (true).

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  • Finding matches between multiple JavaScript Arrays

    - by Chris Barr
    I have multiple arrays with string values and I want to compare them and only keep the matching results that are identical between ALL of them. Given this example code: var arr1 = ['apple', 'orange', 'banana', 'pear', 'fish', 'pancake', 'taco', 'pizza']; var arr2 = ['taco', 'fish', 'apple', 'pizza']; var arr3 = ['banana', 'pizza', 'fish', 'apple']; I would like to to produce the following array that contains matches from all given arrays: ['apple', 'fish', 'pizza'] I know I can combine all the arrays with var newArr = arr1.concat(arr2, arr3); but that just give me an array with everything, plus the duplicates. Can this be done easily without needing the overhead of libraries such as underscore.js? (Great, and now i'm hungry too!) EDIT I suppose I should mention that there could be an unknown amount of arrays, I was just using 3 as an example.

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  • list or container O(1)-ish insertion/deletion performance, with array semantics

    - by Chris Kaminski
    I'm looking for a collection that offers list semantics, but also allows array semantics. Say I have a list with the following items: apple orange carrot pear then my container array would: container[0] == apple container[1] == orangle container[2] == carrot Then say I delete the orange element: container[0] == apple container[1] == carrot I don't particularly care if sort order is maintained, I'd just like the array values to function as accelerators to the list items, and I want to collapse gaps in the array without having to do an explicit resizing.

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  • make a thread which recieves values from other threads

    - by farteaga88
    This program in Java creates a list of 15 numbers and creates 3 threads to search for the maximum in a given interval. I want to create another thread that takes those 3 numbers and get the maximum. but i don't know how to get those values in the other thread. public class apple implements Runnable{ String name; int time, number, first, last, maximum; int[] array = {12, 32, 54 ,64, 656, 756, 765 ,43, 34, 54,5 ,45 ,6 , 5, 65}; public apple(String s, int f, int l){ name = s; first = f; last = l; maximum = array[0]; } public void run(){ try{ for(int i = first; i < last; i++ ) { if(maximum < array[i]) { maximum = array[i]; } } System.out.println("Thread"+ name + "maximum = " + maximum); }catch(Exception e){} } public static void main(String[] args){ Thread t1 = new Thread(new apple("1 ", 0, 5)); Thread t2 = new Thread(new apple("2 ", 5, 10 )); Thread t3 = new Thread(new apple("3 ", 10, 15)); try{ t1.start(); t2.start(); t3.start(); }catch(Exception e){} } }

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  • All UITableCells rendered at once... why?

    - by Greg
    I'm extremely confused by the proper behavior of UITableView cell rendering. Here's the situation: I have a list of 250 items that are loading into a table view, each with an image. To optimize the image download, I followed along with Apple's LazyTableImages sample code... pretty much following it exactly. Really good system... for reference, here's the cell renderer within the Apple sample code: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { // customize the appearance of table view cells // static NSString *CellIdentifier = @"LazyTableCell"; static NSString *PlaceholderCellIdentifier = @"PlaceholderCell"; // add a placeholder cell while waiting on table data int nodeCount = [self.entries count]; if (nodeCount == 0 && indexPath.row == 0) { UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:PlaceholderCellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:PlaceholderCellIdentifier] autorelease]; cell.detailTextLabel.textAlignment = UITextAlignmentCenter; cell.selectionStyle = UITableViewCellSelectionStyleNone; } cell.detailTextLabel.text = @"Loading…"; return cell; } UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier] autorelease]; cell.selectionStyle = UITableViewCellSelectionStyleNone; } // Leave cells empty if there's no data yet if (nodeCount > 0) { // Set up the cell... AppRecord *appRecord = [self.entries objectAtIndex:indexPath.row]; cell.textLabel.text = appRecord.appName; cell.detailTextLabel.text = appRecord.artist; // Only load cached images; defer new downloads until scrolling ends if (!appRecord.appIcon) { if (self.tableView.dragging == NO && self.tableView.decelerating == NO) { [self startIconDownload:appRecord forIndexPath:indexPath]; } // if a download is deferred or in progress, return a placeholder image cell.imageView.image = [UIImage imageNamed:@"Placeholder.png"]; } else { cell.imageView.image = appRecord.appIcon; } } return cell; } So – my implementation of Apple's LazyTableImages system has one crucial flaw: it starts all downloads for all images immediately. Now, if I remove this line: //[self startIconDownload:appRecord forIndexPath:indexPath]; Then the system behaves exactly like you would expect: new images load as their placeholders scroll into view. However, the initial view cells do not automatically load their images without that prompt in the cell renderer. So, I have a problem: with the prompt in the cell renderer, all images load at once. Without the prompt, the initial view doesn't load. Now, this works fine in Apple sample code, which got me wondering what was going on with mine. It's almost like it was building all cells up front rather than just the 8 or so that would appear within the display. So, I got looking into it, and this is indeed the case... my table is building 250 unique cells! I didn't think the UITableView worked like this, I guess I thought it only built as many items as were needed to populate the table. Is this the case, or is it correct that it would build all 250 cells up front? Also – related question: I've tried to compare my implementation against the Apple LazyTableImages sample, but have discovered that NSLog appears to be disabled within the Apple sample code (which makes direct behavior comparisons extremely difficult). Is that just a simple publish setting somewhere, or has Apple somehow locked down their samples so that you can't log output at runtime? Thanks!

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  • Overriding rubies spaceship operator <=>

    - by ericsteen1
    I am trying to override rubies <= (spaceship) operator to sort apples and oranges so that apples come first sorted by weight, and oranges second, sorted by sweetness. Like so: module Fruity attr_accessor :weight, :sweetness def <=>(other) # use Array#<=> to compare the attributes [self.weight, self.sweetness] <=> [other.weight, other.sweetness] end include Comparable end class Apple include Fruity def initialize(w) self.weight = w end end class Orange include Fruity def initialize(s) self.sweetness = s end end fruits = [Apple.new(2),Orange.new(4),Apple.new(6),Orange.new(9),Apple.new(1),Orange.new(22)] p fruits #should work? p fruits.sort But this does not work, can someone tell what I am doing wrong here, or a better way to do this?

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  • Am I allowed to subclass UIWebView?

    - by Raja.Integrass
    I just want to clear this up once and for all, is it ok to subclass a UIWebView? Will I ever have to be nervous about apple rejecting the app because of a UIWebView subclass? The documentation states: Subclassing Notes The UIWebView class should not be subclassed. But at the same time Apple contradicts itself with this WWDC video: https://developer.apple.com/videos/wwdc/2011/?id=511#rich-text-editing-in-safari-on-ios In slide 41 they specifically talk about subclassing a UIWebView Thanks in advance!

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  • shouldAutorotateToInterfaceOrientation always get called more than once.

    - by lovecactus
    (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation My code get this event more than once while device is rotating. I'm searching in apple docs for reference but seems no lucky. Could any one offer a hint why this is happening? My code is an apple doc sample code, without any change but some logs. http://developer.apple.com/iphone/library/samplecode/AlternateViews/Introduction/Intro.html#//apple_ref/doc/uid/DTS40008755

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  • Why is multitasking not supported on the iPhone ?

    - by srikanth rongali
    Many people are saying that Apple has restricted it for better performance. If so Apple should increase the size of RAM to support multitasking. So Apple is not allowing it. Others say that Cocoa Touch applications can't be multitasking as the iPhone has only one window and views on it. I can not understand which is the actual reason for this ? Please clarify me.

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  • Is there any way to get the combine two xml into one xml in Linux.

    - by Tattat
    XML one is something like that: <dict> <key>2</key> <array> <string>A</string> <string>B</string> </array> <key>3</key> <array> <string>C</string> <string>D</string> <string>E</string> </array> </dict> XML Two is something like that: <dict> <key>A</key> <array> <string>A1</string> <false/> <false/> <array> <string>Apple</string> <string>This is an apple</string> </array> <array> <string>Apple Pie</string> <string>I love Apple Pie.</string> </array> </array> <key>B</key> <array> <string>B7</string> <false/> <false/> <array> <string>Boy</string> <string>I am a boy.</string> </array> </array> </dict> I want to convert to this: <dict> <key>2</key> <array> <string>A, Apple, Apple Pie</string> <string>B, Boy</string> </array> ... </dict>

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  • Reducing a normalized table to one value

    - by Dio
    Hello, I'm sure this has been asked but I'm not quite sure how to properly search for this question, my apologies. I have two tables, Foo and Bar. For has one row per Food, bar has many rows per food matching descriptors. Foo name id Apple 1 Orange 2 Bar id description 1 Tasty 1 Ripe 2 Sweet etc (sorry for the somewhat contrived example). I'm trying to return a query where if, for each row in Foo, Bar contains a descriptor in ('Tasty', 'Juicy') return true ex: Output Apple True Orange False I had been solving this somewhat trivially with a case when I only had one item to match select Foo.name, case bar.description when 'Tasty' then True else 'False' end from Foo left join Bar on foo.id = bar.id where bar.description = 'Tasty' But with multiple items, I keep ending up with extra rows: Output Apple True Apple False etc etc Can someone point me in the right direction on how to think about this problem or what I should be doing? Thank you.

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  • Counting amount of items in Pythons 'for'

    - by Markum
    Kind of hard to explain, but when I run something like this: fruits = ['apple', 'orange', 'banana', 'strawberry', 'kiwi'] for fruit in fruits: print fruit.capitalize() It gives me this, as expected: Apple Orange Banana Strawberry Kiwi How would I edit that code so that it would "count" the amount of times it's performing the for, and print this? 1 Apple 2 Orange 3 Banana 4 Strawberry 5 Kiwi

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  • Overriding Ruby's spaceship operator <=>

    - by ericsteen1
    I am trying to override Ruby's <= (spaceship) operator to sort apples and oranges so that apples come first sorted by weight, and oranges second, sorted by sweetness. Like so: module Fruity attr_accessor :weight, :sweetness def <=>(other) # use Array#<=> to compare the attributes [self.weight, self.sweetness] <=> [other.weight, other.sweetness] end include Comparable end class Apple include Fruity def initialize(w) self.weight = w end end class Orange include Fruity def initialize(s) self.sweetness = s end end fruits = [Apple.new(2),Orange.new(4),Apple.new(6),Orange.new(9),Apple.new(1),Orange.new(22)] p fruits #should work? p fruits.sort But this does not work, can someone tell what I am doing wrong here, or a better way to do this?

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  • Order a sentence alphabetically and count the number of times each words appears and print in a table

    - by JaAnTr
    I am struggling with the print in a table part of the question. So far I have managed to order the user inputted sentence alphabetically and count the number of times each word occurs. Here is the code: thestring = (raw_input()) sentence = thestring.split(" ") sentence.sort() count = {} for word in thestring.split(): try: count[word] += 1 except KeyError: count[word] = 1 print sentence print count And when I run the code I get this: ['apple', 'apple', 'banana', 'mango', 'orange', 'pear', 'pear', 'strawberry'] {'apple': 2, 'pear': 2, 'strawberry': 1, 'mango': 1, 'orange': 1, 'banana': 1} However, ideally I want it printed in a table that looks something like: apple.....|.....2 banana....|.....1 mango.....|.....1 orange....|.....1 pear......|.....2 strawberry|.....1 Thanks for any help!

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  • how to combine the related version in group by

    - by randeepsp
    select count(a),b,c from APPLE join MANGO on (APPLE.link=MANGO.link) join ORANGE on (APPLE.link=ORANGE.link) where id='camel' group by b,c; the column b gives values like 1.0 1.0,R 1.0,B 2.0 2.0,B 2.0,R 3.0,C 3.0,R is there a way to modify the above quer so that all 1.0 and 1.0,R and 1.0,B are merged as 1.0 and 2.0,2.0,B are merged as 2.0 and same way for 3.0 and 4.0

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  • Picking apples off a tree

    - by John Retallack
    I have the following problem: I am given a tree with N apples, for each apple I am given it's weight and height. I can pick apples up to a given height H, each time I pick an apple the height of every apple is increased with U. I have to find out the maximum weight of apples I can pick. 1 = N = 100000 0 < {H, U, apples' weight and height, maximum weight} < 231 Example: N=4 H=100 U=10 height weight 82 30 91 10 93 5 94 15 The answer is 45: first pick the apple with the weight of 15 then the one with the weight of 30. Could someone help me approach this problem?

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  • Overloading on return type ???

    - by Green Hyena
    scala> val shares = Map("Apple" -> 23, "MicroSoft" -> 50, "IBM" -> 17) shares: scala.collection.immutable.Map[java.lang.String,Int] = Map(Apple -> 23, MicroSoft -> 50, IBM -> 17) scala> val shareholders = shares map {_._1} shareholders: scala.collection.immutable.Iterable[java.lang.String] = List(Apple, MicroSoft, IBM) scala> val newShares = shares map {case(k, v) => (k, 1.5 * v)} newShares: scala.collection.immutable.Map[java.lang.String,Double] = Map(Apple -> 34.5, MicroSoft -> 75.0, IBM -> 25.5) From this example it seems like the map method is overloaded on return type. Overloading on return type is not possible right? Would somebody please explain what's going on here?

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  • trying to put an mysql result into a string

    - by user1583432
    I'm trying to put an mysql query result into an string I tried to find an answer but all the similar posts were getting subquery answers which is not what I'm trying to do. for example Fruits_tbl ID Fruit Color Number __________________________________ 2 Apple Red 5 $sql = "select Fruits,Color,Number from Fruits_tbl where ID = 2"; $result = $pdo->query($sql); $row = $result->fetch(); print_r($row); This will give me something like Array([0]="Apple", [1]="Red", [2]="5", [Fruit]="Apple", [Color]="Red", [Number]="5") implode will give me 2 of each I want just need a string = "Apple, Red, 5" what I currently have is $string = $row[Fruit].", ".$row[Color].", ".$row['Number'] As you can see that's rather tedious. Is there something like implode but only return the index array or something?

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  • Newbie SQL joining question: houses, refrigerators, and apples

    - by Philip Brocoum
    There are three tables in my database: apples, refrigerators, and houses. Each apple belongs to a refrigerator (it has a column that references the refrigerator that it's in), and each refrigerator belongs to a house. The problem is, each apple ALSO belongs to a house. I guess this isn't "normalized" or whatever, but it's the way it is. Obviously, each apple should belong to the house that its refrigerator belongs to. An apple can't be in two different places at once, after all. So, my question is this: what SQL statement will allow me to find all of the "bad apples" that for some reason incorrectly reference a different house than the refrigerator that they are supposedly in. In other words, I need to find the apples that contain contradictory information. I don't know if this is a "join" question or not, but I'm sure there's probably a very straightforward way of figuring this out. I just don't know what it is. Thanks for your help!

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  • iTunes RSS Feed returning max. 100 items instead of 300

    - by TheEye
    I tried the iTunes RSS generator at http://itunes.apple.com/rss/generator/ to download the newest 300 games, which gave me the RSS Feed URL http://itunes.apple.com/us/rss/newapplications/limit=300/genre=6014/xml. However, only 100 are returned, and alphabetically sorted, so the list stops at the letter E ... Did Apple restrict the amount of items one could get without updating their RSS Feed Generator? Or am I missing something?

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  • How to $.extend 2 objects by adding numerical values together from keys with the same name?

    - by muudless
    I currently have 2 obj and using the jquery extend function, however it's overriding value from keys with the same name. How can I add the values together instead? obj1 = {"orange":2,"apple":1, "grape":1} obj2 = {"orange":5,"apple":1, "banana":1} mergedObj = $.extend({}, obj1, obj2); var printObj = typeof JSON != "undefined" ? JSON.stringify : function(obj) { var arr = []; $.each(obj, function(key, val) { var next = key + ": "; next += $.isPlainObject(val) ? printObj(val) : val; arr.push( next ); }); return "{ " + arr.join(", ") + " }"; }; console.log('all together: '+printObj(mergedObj) ); And I get obj1 = {"orange":5,"apple":1, "grape":1, "banana":1} What I need is obj1 = {"orange":7,"apple":2, "grape":1, "banana":1}

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  • How to resolve `bootpd` crashing constantly on Mac OS X 10.6.4 Snow Leopard Server?

    - by morgant
    I've got a Mac Pro running Mac OS X 10.6.4 Snow Leopard Server and it's recently started getting numerous 'kNetworkError's in Server Admin.app when viewing services. It's acting as a gateway w/NAT and has been so for quite some time. There is one glaring issue, bootpd crashes all the time with the following errors in `/var/log/system.log/: Aug 12 16:54:59 servername bootpd[3572]: server starting Aug 12 16:54:59 servername bootpd[3572]: server name servername.domain.tld Aug 12 16:54:59 servername bootpd[3572]: interface en0: ip 10.0.1.9 mask 255.255.255.0 Aug 12 16:54:59 servername bootpd[3572]: bsdpd: re-reading configuration Aug 12 16:54:59 servername bootpd[3572]: bsdpd: shadow file size will be set to 48 megabytes Aug 12 16:54:59 servername bootpd[3572]: bsdpd: age time 00:15:00 Aug 12 16:54:59 servername bootpd[3572]: [3572] detected buffer overflow Aug 12 16:54:59 servername com.apple.launchd[1] (com.apple.bootpd[3572]): Job appears to have crashed: Abort trap Aug 12 16:54:59 servername com.apple.ReportCrash.Root[3571]: 2010-08-12 16:54:59.828 ReportCrash[3571:2807] Saved crash report for bootpd[3572] version ??? (???) to /Library/Logs/DiagnosticReports/bootpd_2010-08-12-165459_localhost.crash It is correctly configured to serve DHCP through en1 (not en0), the "LAN" port. This happens even with no hardware (even switches) connected to the "LAN" port. There are no DHCP clients listed. Oddly, the "Overview" shows 1 static map, but nothing is listed under "Static Maps" and there are no "Computers" in Open Directory. /var/db/dhcp_leases is empty. /Library/Logs/DiagnosticReports/bootpd_2010-08-12-165459_localhost.crash is as follows: Process: bootpd [3572] Path: /usr/libexec/bootpd Identifier: bootpd Version: ??? (???) Code Type: X86-64 (Native) Parent Process: launchd [1] Date/Time: 2010-08-12 16:54:59.713 -0400 OS Version: Mac OS X Server 10.6.4 (10F569) Report Version: 6 Exception Type: EXC_CRASH (SIGABRT) Exception Codes: 0x0000000000000000, 0x0000000000000000 Crashed Thread: 0 Dispatch queue: com.apple.main-thread Application Specific Information: __abort() called Thread 0 Crashed: Dispatch queue: com.apple.main-thread 0 libSystem.B.dylib 0x00007fff803c13d6 __kill + 10 1 libSystem.B.dylib 0x00007fff80461913 __abort + 103 2 libSystem.B.dylib 0x00007fff80456157 mach_msg_receive + 0 3 libSystem.B.dylib 0x00007fff803b92cf __strncpy_chk + 14 4 bootpd 0x0000000100014e5d PLCache_read + 782 5 bootpd 0x0000000100004a3d BSDPClients_init + 68 6 bootpd 0x00000001000053b5 bsdp_init + 2396 7 bootpd 0x000000010000200b S_update_services + 1228 8 bootpd 0x0000000100002344 S_server_loop + 571 9 bootpd 0x0000000100003963 main + 1766 10 bootpd 0x0000000100000984 start + 52 Thread 0 crashed with X86 Thread State (64-bit): rax: 0x0000000000000000 rbx: 0x00007fff5fbfe220 rcx: 0x00007fff5fbfe218 rdx: 0x0000000000000000 rdi: 0x0000000000000df4 rsi: 0x0000000000000006 rbp: 0x00007fff5fbfe240 rsp: 0x00007fff5fbfe218 r8: 0x0000000000000001 r9: 0x0000000100114280 r10: 0x00007fff803bd412 r11: 0xffffff80002e1680 r12: 0xffffffffffffffff r13: 0x00007fff5fbfe330 r14: 0x00007fff5fbfe33b r15: 0x00007fff7009bec0 rip: 0x00007fff803c13d6 rfl: 0x0000000000000202 cr2: 0x000000010004c000 Any thoughts or suggestions as to resolving this?

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