Can I access type int (*)[] with [][]?
- by Framester
Hi
coming from this question "What does (int (*)[])var1 stand for?" I tried to access the result of the cast like a multidimensional array. But I get following error: "assignment from incompatible pointer type" followed by a segmentation fault. I tried also some other variations, but none of them worked. How can I access the elements in var1 in the function example directly?
Thank you!
#include <stdlib.h>
int i(int n,int m,int var1[n][m]) {
var1[0][0]=5;
return var1[0][0];
}
int example() {
int *var1 = malloc(100);
// works
int var2;
var2 = i(10,10,(int (*)[])var1);
printf("var2=%i",var2);
//doesn't work I
int *var3;
var3=(int (*)[])var1; //"assignment from incompatible pointer type"
printf("var3[0][0]=%i",var3[0][0]);
//doesn't work II
int *var4;
var4=var1;
printf("var4[0][0]=%i",var4[0][0]); //" error: subscripted value is neither array nor pointer"
//doesn't work III
int **var5;
var5=var1;
printf("var5[0][0]=%i",var5[0][0]); // assignment from incompatible pointer type
return(1);
}
int main(){
int a;
a=example();
return(1);
}
