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  • can't connect Java client to C server.

    - by nexes
    I have a very simple server written in C and an equally simple client written in Java. When I run them both on the same computer everything works, but when I try to run the server on computer A and the client on computer B, I get the error IOException connection refused from the java client. I can't seem to find out whats happening, any thoughts? I've even turned off the firewalls but the problem still persists. server. #include <stdio.h> #include <unistd.h> #include <string.h> #include <sys/types.h> #include <sys/socket.h> #include <netinet/in.h> #define PORT 3557 #define BUF 256 int main(int argc, char *argv[]) { struct sockaddr_in host, remote; int host_fd, remote_fd; int size = sizeof(struct sockaddr);; char data[BUF]; host.sin_family = AF_INET; host.sin_addr.s_addr = htonl(INADDR_ANY); host.sin_port = htons(PORT); memset(&host.sin_zero, 0, sizeof(host.sin_zero)); host_fd = socket(AF_INET, SOCK_STREAM, 0); if(host_fd == -1) { printf("socket error %d\n", host_fd); return 1; } if(bind(host_fd, (struct sockaddr *)&host, size)) { printf("bind error\n"); return 1; } if(listen(host_fd, 5)) { printf("listen error"); return 1; } printf("Server setup, waiting for connection...\n"); remote_fd = accept(host_fd, (struct sockaddr *)&remote, &size); printf("connection made\n"); int read = recv(remote_fd, data, BUF, 0); data[read] = '\0'; printf("read = %d, data = %s\n", read, data); shutdown(remote_fd, SHUT_RDWR); close(remote_fd); return 0; } client. import java.net.*; import java.io.*; public class socket { public static void main(String[] argv) { DataOutputStream os = null; try { Socket socket = new Socket("192.168.1.103", 3557); os = new DataOutputStream(socket.getOutputStream()); os.writeBytes("phone 12"); os.close(); socket.close(); } catch (UnknownHostException e) { System.out.println("Unkonw exception " + e.getMessage()); } catch (IOException e) { System.out.println("IOException caught " + e.getMessage()); } } }

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  • Curl: How to insert value to a cookie?

    - by Crazy_Bash
    Ho to insert cookies value in curl? from firebug "request headers" i can see in the following "Cookie: PHPSESSID=gg792c2ktu6sch6n8q0udd94o0; was=1; uncheck2=1; uncheck3=1; uncheck4=1; uncheck5=0; hd=1; uncheck1=1" I have tried the following: curl http://site.com/ -s -L -b cookie.c -c cookie.c -d "was=1; uncheck2=1; uncheck3=1; uncheck4=1; uncheck5=0; hd=1; uncheck1=1" > comic and the only thing i see in cookie.c is PHPSESSID=gg792c2ktu6sch6n8q0udd94o0; was=1;

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  • Implemenation of a pass through file system

    - by user3491505
    Can anyone give me inputs on how to implement a pass through filesystem using fuse?? What I mean by this is that you mount your FUSE file system somewhere (say in /mnt) such that the FUSE file system passes all filesystem calls to some other place (say /home/user). For example, when you go into the /mnt directory and run "ls", this would pass the file system calls to execute ls through and run them on /home/user, such that the directory contents of /home/userwould be listed

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  • What is the problem with this code? How to solve it? (fork)

    - by sb2367
    What is the problem with this code? How to solve it? Parent processes goto in if or child process? first code produce zombie process or second code or both or non ? #include <signal.h> #include <sys/wait.h> main() { for (;;) { if (!fork()) { exit(0); } sleep(1); } } what about this code : #include <signal.h> #include <sys/wait.h> main() { for (;;) { if (fork()) { exit(0); } sleep(1); } }

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  • How to run command in the background and notify me via email when done

    - by Abs
    Hello all, I have the following command which will take ages to run (couple of hours). I would like to make it a background process and for it to send me an email when its done. For the cherry on the top, any errors it encountered should write to a text file when an error has occurred? find . -type f -name "*.rm" -exec ./rm2mp3.sh \{} \; -exec rm \{} \; How can I do this with my above command?

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  • Strange mod_rewrite problem; Website works partially

    - by Camran
    I have Ubuntu 9.10 Server... I need to get mod_rewrite working... the mod_rewrite module IS LOADED. On my server, the httpd.conf is empty, instead everything (almost) is in a file called apache2.conf. Anyways, I have also read I have to change the AllowOverride None to AllowOverride All in some file... My httpd.conf is empty as you know, but I have a folder called sites-enabled which contains a 000-default file. This is where I have set: AllowOverride All Now my goal as I stated in the last Q is to turn this link: http://mydomain.com/ad.php?ad_id=Bmw_nice_M3_497379462 into this: http://mydomain.com/Bmw_nice_M3_497379462 So as I got an answer in the last Q i inserted this into the htaccess file: Options +FollowSymLinks Options +Indexes RewriteEngine On RewriteCond %{REQUEST_URI} !^/ad\.php RewriteRule ^(.*)$ ad.php?ad_id=$1 [L] Now, this works (no fully) when entering the url manually in the adress bar, but my website isn't working now for some reason. It is like the website is locked down or something, and unless I change AllowOverride to None it will act like that. Any ideas why? Also another note, the links inside the rewritten url doesn't work properly (images are not shown, while some are shown)...

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  • sip.conf configuration file - add new line to each record

    - by Flukey
    I have a sip configuration file which looks like this: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no For each record I need to add another line (vmxten for each record) for example the above becomes: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1664 [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1679 [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1700 [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1701 What would you say would be the quickest way to do this? there are hundreds of records in the file, therefore modifying all of the records by hand would take a long time. Would you use Regex? Would you use sed? I'm interested to know how you would approach the problem. Thanks

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  • Is pthread_spin_trylock safe inside of sigsegv handler of multithreaded application?

    - by TWMouton
    I am trying to implement a handler that on SIGSEGV will collect some information such as process-id, thread-id and a backtrace and write this information to a file/pipe/socket. The problem lies in that there is the (probably pretty high) possibility that if one thread experienced a SIGSEGV that the others will shortly follow. If two threads happen to make it to the bit of code where they're writing their report out at the same time then they'll interleave their writing (to the same file). I know that I should only be using async-signal-safe functions as detailed in signal(7) I also have seen at least two cases here and video linked in top answer here where others have used pthread_spin_trylock to get around this problem. Is this a safe way to prevent the above problem?

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  • Will Sytem.currentTimeMillis always return a value >= previous calls?

    - by 1984isnotamanual
    http://java.sun.com/j2se/1.4.2/docs/api/java/lang/System.html#currentTimeMillis() says: Returns the current time in milliseconds. Note that while the unit of time of the return value is a millisecond, the granularity of the value depends on the underlying operating system and may be larger. For example, many operating systems measure time in units of tens of milliseconds. It is not clear to me if I am guaranteed that this code will always print ever increasing (or the same) numbers. while (1) { System.out.println(System.currentTimeMillis() ); }

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  • How to automate rsync without asking for password prompt

    - by Rijosh K
    i would like to automate the rsync task as a cron job.. since it needs the passphrase i am not able to do the cronjob. i need to specify the passphrase along with the rsync command or i will store the passphrase in a file and i will read from it. my command will look like this.. rsync -aPe "ssh -i ' . $server-{'ssh_key'} . '" ' . $server_lock_dir; so where do i put the password .. pls help

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  • PyQt4.QtCore doesn't contain many of its classes and attributes

    - by toc777
    Hi everyone, I have built PyQt4 from source and everything went smoothly until I tried to use some of the classes and attributes located in QtCore. For some reason QtCore is missing a lot of functionality and data that should be there. For example from PyQt4.QtCore import QT_VERSION_STR is an import error. There were no errors or warnings given when building the packages and I have also tried with the PyQt packages from yum but I have the same problem. Has anyone else encountered this problem before? Thanks.

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  • Using wget via Python

    - by CoreIs
    How would I download files (video) with Python using wget and save them locally? There will be a bunch of files, so how do I know that one file is downloaded so as to automatically start downloding another one? Thanks.

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  • If I start learning C on Ubuntu will it give me an edge when I start learning Objective-C later this

    - by Anonymous
    I know Ruby right now, however I want to learn a new language. I am running Ubuntu 10.04 right now but I am going to get a Mac later this summer. Anyways I want something more for GUI development. I was wondering if I should learn C on Ubuntu right now, and then learn Objective-C when I get an iMac? Will learning C give me an edge? Or should I just learn Python on Ubuntu and then learn Objective-C when I get a new computer? Please give me your opinions! Thanks!

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  • error : [0.8879153] kernel panic -not syncing VFS unable to mount fs unknow block (8.3)

    - by Fiasco
    hello i installed ubuntu using wubit inside the windows and started working on it then i got this error afer updating [0.8879153] kernel panic -not syncing VFS unable to mount fs unknow block (8.3) and i can't user rescue mode and it's give me another error no filesystem could mount root ..... i looked at grub folder and didn' find any file on disks/boot/grub/ so i tryed to user super grub to fix it but it didn' work and it keep giving me. any idea plz .

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  • Reading a SquashFS archive

    - by p-static
    (SquashFS is a compressed filesystem - http://en.wikipedia.org/wiki/SquashFS) I'm looking for a way to read a SquashFS filesystem from a program. So far, I've know about the in-kernel drivers for it, but I'm sure that a userspace library for it must exist somewhere. Any language would be fine, but C is preferred. Just mounting the filesystem and using it that way is technically possible, but I'd rather avoid that route because the application I'm looking at would involve working with at least a few dozen archives at any given time.

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  • Secure way to run other people code (sandbox) on my server?

    - by amikazmi
    I want to make a web service that run other people code locally... Naturally, I want to limit their code access to certain "sandbox" directory, and that they wont be able to connect to other parts of my server (DB, main webserver, etc) Whats the best way to do it? Run VMware/Virtualbox: (+) I guess it's as secure as it gets.. even if someone manage to "hack".. they only hack the guest machine (+) can limit the cpu & memory the process uses (+) easy to setup.. just create the VM (-) harder to "connect" the sandbox directory from the host to the guest (-) wasting extra memory and cpu for managing the VM Run underprivileged user: (+) doesnt waste extra resources (+) sandbox directory is just a plain directory (?) cant limit cpu and memory? (?) dont know if it's secure enough... Any other way? Server running Fedora Core 8, the "other" codes written in Java & C++

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  • python script argument misinterpreted in Hudson Execute Shell step

    - by chz
    When I run my python script in the shell terminal, it works sudo myscript.py --version=22 --base=252 --hosts="{'hostA':[1],'hostB':[22]}" But when I run in Hudson and Jenkins, using Execute Shell step, somehow, the string --hosts="{'hostA':[1],'hostB':[22]}" is interpreted as sudo myscript.py --version=22 --base=252 '--hosts="{'hostA':[1],'hostB':[22]}"' How do we overcome this so that our script would run in Jenkins and Hudson ? Thank you. Sincerely

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  • Using directory traversal attack to execute commands

    - by gAMBOOKa
    Is there a way to execute commands using directory traversal attacks? For instance, I access a server's etc/passwd file like this http://server.com/..%01/..%01/..%01//etc/passwd Is there a way to run a command instead? Like... http://server.com/..%01/..%01/..%01//ls ..... and get an output? EDIT: To be clear here, I've found the vuln in our company's server. I'm looking to raise the risk level (or bonus points for me) by proving that it may give an attacker complete access to the system

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  • pthread_exit return value

    - by Manty
    This is surprising for me. void * thread_func(void *arg) { pthread_exit(&ret); } int main(void) { pthread_t thr; int *exit_status; pthread_create(&thr, NULL, thread_func, NULL); sleep(2); pthread_join(thr, (void **)&exit_status); printf("value of exit status - %d\n", *exit_status); ret = 20; pthread_join(thr, (void **)&exit_status); printf("value of exit status - %d\n", *exit_status); return 0; } The output is value of exit status - 50 value of exit status - 20 I was expecting both the times the exit_status would be the actual exit value(50 in my case) of the thread. Instead it is just returning the value of the global variable which I used for pthread_exit. Is it not a bug?

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