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  • xcode 4 creating a 2d grid (range and domain)

    - by user1706978
    I'm learning how to program c and i'm trying to make a program the finds the range (using an equation with x as the domain) of a 2d grid...ive already attempted it, but it's giving me all these errors on Xcode, any help?(As you can see, I'm quite stuck!) #include <stdio.h> #include <stdlib.h> float domain; float domain = 2.0; float domainsol(float x ) { domain = x; float func = 1.25 * x + 5.0; return func; } int main(int argc, const char * argv[]) { }

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  • C++ putting a 2d array of floats into a char*

    - by sam
    Hello, I'm trying to take a 2d vector of floats (input) and put them into a char* (output) in c++. void foo(const std::vector<std::vector<float> > &input, char* &output ) { char charBuf[sizeof(output)]; int counter = 0; for(unsigned int i=0; i<input.size(); i++) { for(unsigned int p=0; p<input.at(i).size(); p++) { //what the heck goes here } }

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  • Fill 2D area bound by vertices in XNA

    - by oakskc
    I'm learning XNA by doing and, as the title states, I'm trying to see if there's a way to fill a 2D area that is defined by a collection of vertices on a plane. I want to fill with a color, not a file-based texture. For an example, take a rounded rectangle whose vertices are defined by four quarter-circle triangle fans. The vertices are defined by building a collection of triangles, but the triangles may not be adjacent. Additionally, I would like to fill it with more than a single color -- i.e. divide the bound area into four vertical bands and have each a different color. You don't have to provide me the code, pointing me towards resources will help a great deal. I can be handy with Google (which I did try first, but have failed miserably). This is as much an exploration into "what's appropriate for XNA" as it is the implementation of it. Being pretty new to XNA, I'm wanting to also learn what should and shouldn't be done on top of what can and can't be done.

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  • AndEngine VS Android's Canvas VS OpenGLES - For rendering a 2D indoor vector map

    - by Orchestrator
    This is a big issue for me I'm trying to figure out for a long time already. I'm working on an application that should include a 2D vector indoor map in it. The map will be drawn out from an .svg file that will specify all the data of the lines, curved lines (path) and rectangles that should be drawn. My main requirement from the map are Support touch events to detect where exactly the finger is touching. Great image quality especially when considering the drawings of curved and diagonal lines (anti-aliasing) Optional but very nice to have - Built in ability to zoom, pan and rotate. So far I tried AndEngine and Android's canvas. With AndEngine I had troubles with implementing anti-aliasing for rendering smooth diagonal lines or drawing curved lines, and as far as I understand, this is not an easy thing to implement in AndEngine. Though I have to mention that AndEngine's ability to zoom in and pan with the camera instead of modifying the objects on the screen was really nice to have. I also had some little experience with the built in Android's Canvas, mainly with viewing simple bitmaps, but I'm not sure if it supports all of these things, and especially if it would provide smooth results. Last but no least, there's the option of just plain OpenGLES 1 or 2, that as far as I understand, with enough work should be able to support all the features I require. However it seems like something that would be hard to implement. And I've never programmed in OpenGL or anything like it, but I'm willing very much to learn. To sum it all up, I need a platform that would provide me with the ability to do the 3 things I mentioned before, but also very important - To allow me to implement this feature as fast as possible. Any kind of answer or suggestion would be very much welcomed as I'm very eager to solve this problem! Thanks!

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  • OpenGL - drawing 2D polygons shapes with texture

    - by plonkplonk
    I am trying to make a few effects in a C+GL game. So far I draw all my sprites as a quad, and it works. However, I am trying to make a large ring appear at times, with a texture following that ring, as it takes less memory than a quad with the ring texture inside. The type of ring I want to make is not a round-shaped GL mesh ring (the "tube" type) but a "paper" 2D ring. That way I can modify the "width" of the ring, getting more of the effect than a simple quad+ring texture. So far all my attempts have been...kind of ridiculous, as I don't understand GL's coordinates too well (and I can't really understand the available documentation...I am just a designer with no coder help or background. A n00b, basically). glBegin(GL_POLYGON); for(i = 0;i < 360; i += 10){ glTexCoord2f(0, 0); glVertex2f(Cos(i)*(H-10),Sin(i)H); glTexCoord2f(0, HP); glVertex2f(Sin(i)(H-10),Cos(i)*(H-10)); glTexCoord2f(WP, HP); glVertex2f(Cos(i)H,Sin(i)(H-10)); glTexCoord2f(WP, 0); glVertex2f(Sin(i)*H,Cos(i)*H); } glEnd(); This is my last attempt, and it seems to generate a "sunburst" from the right edge of the circle instead of a ring. It's an amusing effect but definitely not what I want. Other results included the circle looking exactly the same as the quad textured (aka drawing a sprite literally) or something that looked like a pop-art filter, by working on this train of thought. Seems like my logic here is entirely flawed, so, what would be the easiest way to obtain such a ring? No need to reply in code, just some guidance for a non-math-skilled user...

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  • 1D Function into 2D Function Interpolation

    - by Drazick
    Hello. I have a 1D function which I want to interpolate into 2D function. I know the function should have "Polar Symmetry". Hence I use the following code (Matlab Syntax): Assuming the 1D function is LSF of the length 15. [x, y] = meshgrid([-7:7]); r = sqrt(x.^2 + y.^2); PSF = interp1([-7:7], LSF, r(:)); % Sometimes using 'spline' option, same results. PSF = reshape(PSF, [7, 7]); I have few problems: 1. Got some overshoot at the edges (As there some Extrapolation). 2. Can't enforce some assumptions (Monotonic, Non Negative). Is there a better Interpolation method for those circumstances? I couldn't find "Lanczos" based interpolation I can use the same way as interp1 (For a certain vector of points, in "imresize" you can only set the length). Is there such function anywhere? Has anyone encountered a function which allows enforcing some assumptions (Monotonically Decreasing, Non Negative, etc..). Thanks.

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  • Sending 2 dim array using scatter

    - by MPI_Beginner
    I am a beginner in MPI, and i am using C Language, and Simulator for Processors (MPICH2), i wrote the following code to send a 2D array to make 2 processors take a line from it but it produces error when running MPICH2, the code is: int main ( int argc , char *argv[] ) { int rank; int commsize; MPI_Init(&argc, &argv); MPI_Comm_size(MPI_COMM_WORLD,&commsize); MPI_Comm_rank(MPI_COMM_WORLD,&rank); char** name=malloc(2*sizeof(char*)); int i; for(i=0;i<2;i++){ name[i]=malloc(15*sizeof(char)); } name[0]="name"; name[1]="age"; if(rank==0){ char** mArray=malloc(2*sizeof(char*)); MPI_Scatter(&name,1,MPI_CHAR,&mArray,1,MPI_CHAR,0,MPI_COMM_WORLD);//send } else{ char** mArray=malloc(2*sizeof(char*)); int k; for(k=0;k<2;k++){ mArray[k]=malloc(15*sizeof(char)); } MPI_Scatter(&mArray,1,MPI_CHAR,&mArray,1,MPI_CHAR,0,MPI_COMM_WORLD);//receive printf("line is %s \n",mArray[rank-1]); } MPI_Finalize(); }

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  • Overlaying 2D paths on UIImage without scaling artifacts

    - by tat0
    I need to draw a path along the shape of an image in a way that it is always matching its position on the image independent of the image scale. Think of this like the hybrid view of Google Maps where streets names and roads are superimposed on top of the aerial pictures. Furthermore, this path will be drawn by the user's finger movements and I need to be able to retrieve the path keypoints on the image pixel coordinates. The user zooms-in in order to more precisely set the paths location. I manage to somehow make it work using this approach: -Create a custom UIView called CanvasView that handles touches interaction and delivers scaling, rotation, translation values to either the UIImageView or PathsView (see bellow) depending on a flag: deliverToImageOrPaths. -Create a UIImageView holding the base image. This is set as a children of CanvasView -Create a custom UIView called PathsView that keeps track of the 2D paths geometry and draws itself with a custom drawRect. This is set as children of the UIImageView. So hierarchy: CanvasView - UIImageView -PathsView In this way when deliverToImageOrPaths is YES, finger gestures transforms both the UIImageView and its child PathsView. When deliverToImageOrPaths is NO the gestures affect only the PathsView altering its geometry. So far so good. QUESTION: The problem I have is that when scaling the base UIImageView (via its .transform property) the PathsView is scaled with aliasing artifacts. drawRect is still being called on the PathsView but I guess it's performing the drawing using the original buffer size and then interpolating. How can I solve this issue? Are there better ways to implement these features? PS: I tried changing the PathsView layer class to CATiledLayer with levelsOfDetailBias 4 and levelsOfDetail 4. It solves the aliasing problem to some extent but it's unacceptable slow to render.

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  • Detecting one point's location compared to two other points.

    - by WizardOfOdds
    Hi all, you can check my profile, this is not homework. I've got an interesting little problem to solve in a very real software and I'm looking for an easy way to solve it. I've got two fixed points on screen (they're fixed, but I don't know beforehand their position) that are not at the same location. These two fixed points form an imaginary line. Now I've got a third point that is "on one side" of that line (it cannot be on the line). The user can grab the point (the user actually grab an object, whose I track by its center, which is the point I'm interested in) and drag it. But it cannot "cross" the imaginary line. What is the easiest way to detect if the user is crossing the imaginary line? Example: a c / / (c cannot be dragged here) / b Or: c b -------------- a (c cannot be dragged here) So what is an easy to detect if c is staying on the correct "side" of the line (I draw segments here, but it really can be thought of as a line). One way to detect this is to take the destination point d and see if segment (c,d) intersects with line (a,b), but isn't there an easier way? Can't I just do some 2D dot-product magic here and have basically a one or two liner solving my issue?

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  • most efficient method of turning multiple 1D arrays into columns of a 2D array

    - by Ty W
    As I was writing a for loop earlier today, I thought that there must be a neater way of doing this... so I figured I'd ask. I looked briefly for a duplicate question but didn't see anything obvious. The Problem: Given N arrays of length M, turn them into a M-row by N-column 2D array Example: $id = [1,5,2,8,6] $name = [a,b,c,d,e] $result = [[1,a], [5,b], [2,c], [8,d], [6,e]] My Solution: Pretty straight forward and probably not optimal, but it does work: <?php // $row is returned from a DB query // $row['<var>'] is a comma separated string of values $categories = array(); $ids = explode(",", $row['ids']); $names = explode(",", $row['names']); $titles = explode(",", $row['titles']); for($i = 0; $i < count($ids); $i++) { $categories[] = array("id" => $ids[$i], "name" => $names[$i], "title" => $titles[$i]); } ?> note: I didn't put the name = value bit in the spec, but it'd be awesome if there was some way to keep that as well.

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  • Is this 2D array initialization a bad idea?

    - by Brendan Long
    I have something I need a 2D array for, but for better cache performance, I'd rather have it actually be a normal array. Here's the idea I had but I don't know if it's a terrible idea: const int XWIDTH = 10, YWIDTH = 10; int main(){ int * tempInts = new int[XWIDTH * YWIDTH]; int ** ints = new int*[XWIDTH]; for(int i=0; i<XWIDTH; i++){ ints[i] = &tempInts[i*YWIDTH]; } // do things with ints delete[] ints[0]; delete[] ints; return 0; } So the idea is that instead of newing a bunch of arrays (and having them placed in different places in memory), I just point to an array I made all at once. The reason for the delete[] (int*) ints; is because I'm actually doing this in a class and it would save [trivial amounts of] memory to not save the original pointer. Just wondering if there's any reasons this is a horrible idea. Or if there's an easier/better way. The goal is to be able to access the array as ints[x][y] rather than ints[x*YWIDTH+y].

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  • 2D Histogram in R: Converting from Count to Frequency within a Column

    - by Jac
    Would appreciate help with generating a 2D histogram of frequencies, where frequencies are calculated within a column. My main issue: converting from counts to column based frequency. Here's my starting code: # expected packages library(ggplot2) library(plyr) # generate example data corresponding to expected data input x_data = sample(101:200,10000, replace = TRUE) y_data = sample(1:100,10000, replace = TRUE) my_set = data.frame(x_data,y_data) # define x and y interval cut points x_seq = seq(100,200,10) y_seq = seq(0,100,10) # label samples as belonging within x and y intervals my_set$x_interval = cut(my_set$x_data,x_seq) my_set$y_interval = cut(my_set$y_data,y_seq) # determine count for each x,y block xy_df = ddply(my_set, c("x_interval","y_interval"),"nrow") # still need to convert for use with dplyr # convert from count to frequency based on formula: freq = count/sum(count in given x interval) ################ TRYING TO FIGURE OUT ################# # plot results fig_count <- ggplot(xy_df, aes(x = x_interval, y = y_interval)) + geom_tile(aes(fill = nrow)) # count fig_freq <- ggplot(xy_df, aes(x = x_interval, y = y_interval)) + geom_tile(aes(fill = freq)) # frequency I would appreciate any help in how to calculate the frequency within a column. Thanks! jac EDIT: I think the solution will require the following steps 1) Calculate and store overall counts for each x-interval factor 2) Divide the individual bin count by its corresponding x-interval factor count to obtain frequency. Not sure how to carry this out though. .

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  • Reverse-projection 2D points into 3D

    - by ehsan baghaki
    Suppose we have a 3d Space with a plane on it with an arbitary equation : ax+by+cz+d=0 now suppose that we pick 3 random points on that plane: (x0,y0,z0) (x1,y1,z1) (x1,y1,z1) now i have a different point of view(camera) for this plane. i mean i have a different camera that will look at this plane from a different point of view. From that camera point of view these points have different locations. for example (x0,y0,z0) will be (x0',y0') and (x1,y1,z1) will be (x1',y1') and (x2,y2,z2) will be (x2',y2') from the new camera point of view. So here is my a little hard question! I want to pick a point for example (X,Y) from the new camera point of view and tell where it will be on that plane. All i know is that 3 points and their locations on 3d space and their projection locations on the new camera view. Do you know the coefficients of the plane-equation and the camera positions (along with the projection), or do you only have the six points? - Nils i know the location of first 3 points. therefore we can calculate the coefficients of the plane. so we know exactly where the plane is from (0,0,0) point of view. and then we have the camera that can only see the points! So the only thing that camera sees is 3 points and also it knows their locations in 3d space (and for sure their locations on 2d camera view plane). and after all i want to look at camera view, pick a point (for example (x1,y1)) and tell where is that point on that plane. (for sure this (X,Y,Z) point should fit on the plane equation). Also i know nothing about the camera location.

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  • 2d Vector with wrong values

    - by Petris Rodrigo Fernandes
    I'm studing STL, then i thought "i'll make a 2d array!" but whatever... a coded this: vector< vector<int> > vetor; vetor.resize(10); vetor[0].resize(10); for(int i = 0; i < vetor.capacity(); i++){ for(int h = 0; h < vetor[0].capacity();h++){ vetor[i][h] = h; } } Until here, ok. But when i try to show the array value a use this: for(int i = 0; i < vetor.capacity(); i++){ cout << "LINE " << i << ": "; for(int h = 0; h < vetor[0].capacity();h++){ cout << vetor[i][h] <<" "; } cout << "\n"; } And the results are really wrong: LINE 0: 4 5 6 7 8 9 6 7 8 9 LINE 1: 0 1 2 3 0 1 2 3 0 1 LINE 2: 0 1 2 3 0 1 2 3 0 1 LINE 3: 0 1 2 3 0 1 2 3 0 1 LINE 4: 0 1 2 3 0 1 2 3 0 1 LINE 5: 0 1 2 3 0 1 2 3 0 1 LINE 6: 0 1 2 3 0 1 2 3 0 1 LINE 7: 0 1 2 3 0 1 2 3 0 1 LINE 8: 0 1 2 3 0 1 2 3 4 5 LINE 9: 0 1 2 3 4 5 6 7 8 9 What's happening with my program? it isn't printing the right values!

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  • Android OpenGL es "glDrawTexfOES" draws upside down

    - by Alle
    I'm using OpenGL for Android to draw my 2D images. Whenever I draw something using the code: gl.glViewport(aspectRatioOffset, 0, screenWidth, screenHeight); gl.glMatrixMode(GL10.GL_PROJECTION); gl.glLoadIdentity(); GLU.gluOrtho2D(gl, aspectRatioOffset, screenWidth + aspectRatioOffset,screenHeight, 0); gl.glMatrixMode(GL10.GL_MODELVIEW); gl.glLoadIdentity(); gl.glEnable(GL10.GL_TEXTURE_2D); gl.glBindTexture(GL10.GL_TEXTURE_2D, myScene.neededGraphics.get(ID).get(animationID).get(animationIndex)); crop[0] = 0; crop[1] = 0; crop[2] = width; crop[3] = height; ((GL11Ext)gl).glDrawTexfOES(x, y, z, width, height) I get an upside down result. I'v seen people solve this through doing: crop[0] = 0; crop[1] = height; crop[2] = width; crop[3] = -height; This does however hurt the logic in my application, so I would like the result to not be flipped upside down. Does anyone know why it happen, and any way of avoiding or solving it?

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  • Optimized 2D Tile Scrolling in OpenGL

    - by silicus
    Hello, I'm developing a 2D sidescrolling game and I need to optimize my tiling code to get a better frame rate. As of right now I'm using a texture atlas and 16x16 tiles for 480x320 screen resolution. The level scrolls in both directions, and is significantly larger than 1 screen (thousands of pixels). I use glTranslate for the actual scrolling. So far I've tried: Drawing only the on-screen tiles using glTriangles, 2 per square tile (too much overhead) Drawing the entire map as a Display List (great on a small level, way to slow on a large one) Partitioning the map into Display Lists half the size of the screen, then culling display lists (still slows down for 2-directional scrolling, overdraw is not efficient) Any advice is appreciated, but in particular I'm wondering: I've seen Vertex Arrays/VBOs suggested for this because they're dynamic. What's the best way to take advantage of this? If I simply keep 1 screen of vertices plus a bit of overdraw, I'd have to recopy the array every few frames to account for the change in relative coordinates (shift everything over and add the new rows/columns). If I use more overdraw this doesn't seem like a big win; it's like the half-screen display list idea. Does glScissor give any gain if used on a bunch of small tiles like this, be it a display list or a vertex array/VBO Would it be better just to build the level out of large textures and then use glScissor? Would losing the memory saving of tiling be an issue for mobile development if I do this (just curious, I'm currently on a PC)? This approach was mentioned here Thanks :)

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  • How to determine 2D unsigned short pointers array length in c++

    - by tuman
    Hello, I am finding it difficult to determine the length of the columns in a 2D unsigned short pointer array. I have done memory allocation correctly as far as I know. and can print them correctly. plz see the following code segment: int number_of_array_index_required_for_pointer_abc=3; char A[3][16]; strcpy(A[0],"Hello"); strcpy(A[1],"World"); strcpy(A[2],"Tumanicko"); cout<<number_of_array_index_required_for_pointer_abc*sizeof(unsigned short)<<endl; unsigned short ** pqr=(unsigned short **)malloc(number_of_array_index_required_for_pointer_abc*sizeof(unsigned short)); for(int i=0;i<number_of_array_index_required_for_pointer_abc;i++) { int ajira = strlen(A[i])*sizeof(unsigned short); cout<<i<<" = "<<ajira<<endl; pqr[i]=(unsigned short *)malloc(ajira); cout<<"alocated pqr[i]= "<<sizeof pqr<<endl; int j=0; for(j=0;j<strlen(A[i]);j++) { pqr[i][j]=(unsigned short)A[i][j]; } pqr[i][j]='\0'; } for(int i=0;i<number_of_array_index_required_for_pointer_abc;i++) { //ln= (sizeof pqr[i])/(sizeof pqr[0]); //cout<<"Size of pqr["<<i<<"]= "<<ln<<endl; // I want to know the size of the columns i.e. pqr[i]'s length instead of finding '\0' for(int k=0;(char)pqr[i][k]!='\0';k++) cout<<(char)pqr[i][k]; cout<<endl; }

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  • why my iphone device and simulator has different screen resolution?

    - by happyzone8
    i use itouch 4G has my device and i use simulator-4.2 i will just draw a rectangle as an example. i use Quartz-2d to draw - (void)drawRect:(CGRect)rect { // Get a graphics context, saving its state CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSaveGState(context); // Reset the transformation CGAffineTransform t0 = CGContextGetCTM(context); t0 = CGAffineTransformInvert(t0); CGContextConcatCTM(context,t0); // Draw a green rectangle CGContextBeginPath(context); CGContextSetRGBFillColor(context, 0,1,0,1); CGContextAddRect(context, CGRectMake(0,0,320,480)); CGContextClosePath(context); CGContextDrawPath(context,kCGPathFill); CGContextRestoreGState(context); } i run it in the simulator, the whole screen becomes green, then i run this on my device, only the quarter of the screen becomes green, in order to make the whole screen green on my device, i have to draw a larger rectangle CGContextAddRect(context, CGRectMake(0,0,640,960)); seem like my device has twice resolution than the simulator, how can i fix this?

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  • replacing elements horizontally and vertically in a 2D array

    - by wello horld
    the code below ask for the user's input for the 2D array size and prints out something like this: (say an 18x6 grid) .................. .................. .................. .................. .................. .................. code starts here: #include <stdio.h> #define MAX 10 int main() { char grid[MAX][MAX]; int i,j,row,col; printf("Please enter your grid size: "); scanf("%d %d", &row, &col); for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { grid[i][j] = '.'; printf("%c ", grid[i][j]); } printf("\n"); } return 0; } I now ask the user for a string, then ask them where to put it for example: Please enter grid size: 18 6 Please enter word: Hello Please enter location: 0 0 Output: Hello............. .................. .................. .................. .................. .................. Please enter location: 3 4 Output: .................. .................. .................. ..Hello........... .................. .................. program just keeps going. Any thoughts on how to modify the code for this? PS: Vertical seems way hard, but I want to start on horizontal first to have something to work on.

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  • Declaring two large 2d arrays gives segmentation fault.

    - by pfdevil
    Hello, i'm trying to declare and allocate memory for two 2d-arrays. However when trying to assign values to itemFeatureQ[39][16816] I get a segmentation vault. I can't understand it since I have 2GB of RAM and only using 19MB on the heap. Here is the code; double** reserveMemory(int rows, int columns) { double **array; int i; array = (double**) malloc(rows * sizeof(double *)); if(array == NULL) { fprintf(stderr, "out of memory\n"); return NULL; } for(i = 0; i < rows; i++) { array[i] = (double*) malloc(columns * sizeof(double *)); if(array == NULL) { fprintf(stderr, "out of memory\n"); return NULL; } } return array; } void populateUserFeatureP(double **userFeatureP) { int x,y; for(x = 0; x < CUSTOMERS; x++) { for(y = 0; y < FEATURES; y++) { userFeatureP[x][y] = 0; } } } void populateItemFeatureQ(double **itemFeatureQ) { int x,y; for(x = 0; x < FEATURES; x++) { for(y = 0; y < MOVIES; y++) { printf("(%d,%d)\n", x, y); itemFeatureQ[x][y] = 0; } } } int main(int argc, char *argv[]){ double **userFeatureP = reserveMemory(480189, 40); double **itemFeatureQ = reserveMemory(40, 17770); populateItemFeatureQ(itemFeatureQ); populateUserFeatureP(userFeatureP); return 0; }

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  • hash tables and 2d vectors

    - by Sunil
    I want to push a 2d vector into a hash table row by row and later search for a row (vector) in the hash table and want to be able to find it. I want to do something like #include <iostream> #include <set> #include <vector> using namespace std; int main(){ std::set < vector<int> > myset; vector< vector<int> > v; int k = 0; for ( int i = 0; i < 5; i++ ) { v.push_back ( vector<int>() ); for ( int j = 0; j < 5; j++ ) v[i].push_back ( k++ ); } for ( int i = 0; i < 5; i++ ) { std::copy(v[i].begin(),v[i].end(),std::inserter(myset)); // This is not correct but what is the right way ? // and also here, I want to search for a particular vector if it exists in the table. for ex. the second row of vector v. } return 0; } I'm not sure how to insert and look up a vector in a set. So if nybody could guide me, it will be helpful. Thanks

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  • rotate a star in opengl (2D)

    - by nova a
    I have a 2D star, and I don't know how to rotate it around its center, and I also don't know how to do it with a keyboard key. Also how can I make my object bigger or smaller by a certain percentage (because when I tried to do it by changing pixels, the star goes wrong). This is my code: #include <GL/glut.h> #include <GL/gl.h> #include <GL/freeglut.h> void init (void) { glClearColor(0.0,0.0,0.0,00); glMatrixMode(GL_PROJECTION); gluOrtho2D(0.0,200.0,0.0,200.0); } void LineSegment(void) { glClear(GL_COLOR_BUFFER_BIT); glColor3f(1.0,1.0,1.0); glBegin(GL_LINE_LOOP); glVertex2i(20,120); glVertex2i(180,120); glVertex2i(45,20); glVertex2i(100,190); glVertex2i(155,20); glEnd(); glFlush(); } int main(int argc,char** argv) { glutInit(&argc,argv); glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB); glutInitWindowPosition(50,100); glutCreateWindow("STAR"); init(); glutDisplayFunc(LineSegment); glutMainLoop(); return 0; }

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  • printing 2d table (headers)

    - by k0re
    Hi Is there are a better way than this one to print 2d table? std::cout << std::setw(25) << left << "FF.name" << std::setw(25) << left << "BB.name" << std::setw(12) << left << "sw.cycles" << std::setw(12) << left << "hw.cycles" << "\n" << std::setw(25) << left << "------" << std::setw(25) << left << "------" << std::setw(12) << left << "---------" << std::setw(12) << left << "---------" << "\n";

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  • Asking Box2d if a collision happened

    - by Rosarch
    I'm using Box2dx (ported to C#; optimized for XNA). It handles collision resolution, but how can I tell if two objects are currently colliding? This is the function I'm trying to write: public bool IsColliding(GameObjectController collider1, GameObjectController collider2) Where collider1.Model.Body is the Box2d Body, and collider1.Model.BodyDef is the Box2d BodyDef. (The same goes for collider2, of course.) UPDATE: Looks like contact listeners or this could be useful: AABB collisionBox; model.Body.GetFixtureList().GetAABB(out collisionBox); Why does GetFixtureList() return one fixture?

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  • Box2dx: Usage of World.QueryAABB?

    - by Rosarch
    I'm using Box2dx with C#/XNA. I'm trying to write a function that determines if a body could exist in a given point without colliding with anything: /// <summary> /// Can gameObject exist with start Point without colliding with anything? /// </summary> internal bool IsAvailableArea(GameObjectModel model, Vector2 point) { Vector2 originalPosition = model.Body.Position; model.Body.Position = point; // less risky would be to use a deep clone AABB collisionBox; model.Body.GetFixtureList().GetAABB(out collisionBox); // how is this supposed to work? physicsWorld.QueryAABB(x => true, ref collisionBox); model.Body.Position = originalPosition; return true; } Is there a better way to go about doing this? How is World.QueryAABB supposed to work? Here is an earlier attempt. It is broken; it always returns false. /// <summary> /// Can gameObject exist with start Point without colliding with anything? /// </summary> internal bool IsAvailableArea(GameObjectModel model, Vector2 point) { Vector2 originalPosition = model.Body.Position; model.Body.Position = point; // less risky would be to use a deep clone AABB collisionBox; model.Body.GetFixtureList().GetAABB(out collisionBox); ICollection<GameObjectController> gameObjects = worldQueryEngine.GameObjectsForPredicate(x => ! x.Model.Passable); foreach (GameObjectController controller in gameObjects) { AABB potentialCollidingBox; controller.Model.Body.GetFixtureList().GetAABB(out potentialCollidingBox); if (AABB.TestOverlap(ref collisionBox, ref potentialCollidingBox)) { model.Body.Position = originalPosition; return false; // there is something that will collide at this point } } model.Body.Position = originalPosition; return true; }

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