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  • Python Process won't call atexit

    - by Brian M. Hunt
    I'm trying to use atexit in a Process, but unfortunately it doesn't seem to work. Here's some example code: import time import atexit import logging import multiprocessing logging.basicConfig(level=logging.DEBUG) class W(multiprocessing.Process): def run(self): logging.debug("%s Started" % self.name) @atexit.register def log_terminate(): # ever called? logging.debug("%s Terminated!" % self.name) while True: time.sleep(10) @atexit.register def log_exit(): logging.debug("Main process terminated") logging.debug("Main process started") a = W() b = W() a.start() b.start() time.sleep(1) a.terminate() b.terminate() The output of this code is: DEBUG:root:Main process started DEBUG:root:W-1 Started DEBUG:root:W-2 Started DEBUG:root:Main process terminated I would expect that the W.run.log_terminate() would be called when a.terminate() and b.terminate() are called, and the output to be something likeso (emphasis added)!: DEBUG:root:Main process started DEBUG:root:W-1 Started DEBUG:root:W-2 Started DEBUG:root:W-1 Terminated! DEBUG:root:W-2 Terminated! DEBUG:root:Main process terminated Why isn't this working, and is there a better way to log a message (from the Process context) when a Process is terminated? Thank you for your input - it's much appreciated.

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  • Ruby on Rails script/console printing more than expected

    - by Lloyd
    I have a simple model setup in my Ruby on Rails app. (User {name, username, lat, lon}) and am writing a basic extension to the model. I would like the method to return users within a certain distance. It all works just fine in the page view, but as I am debugging I would like to work through some testing using the script/console. My question: It seems to be printing to the screen the entire result set when I run it from the command line and script/console. My model: class User < ActiveRecord::Base def distance_from(aLat, aLon) Math.sqrt((69.1*(aLat - self.lat))**2 + (49*(aLon - self.lon))**2 ) end def distance_from_user(aUser) distance_from(aUser.lat, aUser.lon) end def users_within(distance) close_users = [] users = User.find(:all) users.each do |u| close_users << u if u.distance_from_user(self) < distance end return close_users end end and from the command line I am running >> u = User.find_by_username("someuser") >> print u.users_within(1) So, I guess I would like to know why it's printing the whole result set, and if there is a way to suppress it so as to only print what I want?

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  • How to build a JSON response by combining @foo.to_json(options) and @bars.to_json(options) in Rails

    - by smotchkkiss
    First, the desired result I have User and Item models. I'd like to build a JSON response that looks like this: { "user": {"username":"Bob!","foo":"whatever","bar":"hello!"}, "items": [ {"id":1, "name":"one", "zim":"planet", "gir":"earth"}, {"id":2, "name":"two", "zim":"planet", "gir":"mars"} ] } However, my User and Item model have more attributes than just those. I found a way to get this to work, but beware, it's not pretty... Please help... My hacks home_controller.rb class HomeController < ApplicationController def observe respond_to do |format| format.js { render :json => Observation.new(current_user, @items).to_json } end end end observation.rb # NOTE: this is not a subclass of ActiveRecord::Base # this class just serves as a container to aggregate all "observable" objects class Observation attr_accessor :user, :items def initialize(user, items) self.user = user self.items = items end # The JSON needs to be decoded before it's sent to the `to_json` method in the home_controller otherwise the JSON will be escaped... # What a mess! def to_json { :user => ActiveSupport::JSON.decode(user.to_json(:only => :username, :methods => [:foo, :bar])), :items => ActiveSupport::JSON.decode(auctions.to_json(:only => [:id, :name], :methods => [:zim, :gir])) } end end

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  • Python: query a class's parent-class after multiple derivations ("super()" does not work)

    - by henry
    Hi, I have built a class-system that uses multiple derivations of a baseclass (object-class1-class2-class3): class class1(object): def __init__(self): print "class1.__init__()" object.__init__(self) class class2(class1): def __init__(self): print "class2.__init__()" class1.__init__(self) class class3(class2): def __init__(self): print "class3.__init__()" class2.__init__(self) x = class3() It works as expected and prints: class3.__init__() class2.__init__() class1.__init__() Now I would like to replace the 3 lines object.__init__(self) ... class1.__init__(self) ... class2.__init__(self) with something like this: currentParentClass().__init__() ... currentParentClass().__init__() ... currentParentClass().__init__() So basically, i want to create a class-system where i don't have to type "classXYZ.doSomething()". As mentioned above, I want to get the "current class's parent-class". Replacing the three lines with: super(type(self), self).__init__() does NOT work (it always returns the parent-class of the current instance - class2) and will result in an endless loop printing: class3.__init__() class2.__init__() class2.__init__() class2.__init__() class2.__init__() ... So is there a function that can give me the current class's parent-class? Thank you for your help! Henry -------------------- Edit: @Lennart ok maybe i got you wrong but at the moment i think i didn't describe the problem clearly enough.So this example might explain it better: lets create another child-class class class4(class3): pass now what happens if we derive an instance from class4? y = class4() i think it clearly executes: super(class3, self).__init__() which we can translate to this: class2.__init__(y) this is definitly not the goal(that would be class3.__init__(y)) Now making lots of parent-class-function-calls - i do not want to re-implement all of my functions with different base-class-names in my super()-calls.

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  • Spaceship objects

    - by Jam
    I'm trying to make a program which creates a spaceship and I'm using the status() method to display the ship's name and fuel values. However, it doesn't seem to be working. I think I may have messed something up with the status() method. I'm also trying to make it so that I can change the fuel values, but I don't want to create a new method to do so. I think I've taken a horrible wrong turn somewhere in there. Help please! class Ship(object): def __init__(self, name="Enterprise", fuel=0): self.name=name self.fuel=fuel print "The spaceship", name, "has arrived!" def status(): print "Name: ", self.name print "Fuel level: ", self.fuel status=staticmethod(status) def main(): ship1=Ship(raw_input("What would you like to name this ship?")) fuel_level=raw_input("How much fuel does this ship have?") if fuel_level<0: self.fuel=0 else: self.fuel(fuel_level) ship2=Ship(raw_input("What would you like to name this ship?")) fuel_level2=raw_input("How much fuel does this ship have?") if fuel_level2<0: self.fuel=0 else: self.fuel(fuel_level2) ship3=Ship(raw_input("What would you like to name this ship?")) fuel_level3=raw_input("How much fuel does this ship have?") if fuel_level3<0: self.fuel=0 else: self.fuel(fuel_level3) Ship.status() main() raw_input("Press enter to exit.")

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  • Have error message show when form is created through AJAX

    - by Railslearner
    I have a page called /add that you can add a Dog on and the form is in its own partial. I'm using Simple Form and Twitter Bootstrap. I added the files for the main Bootstrap but use a gem for simple_form to work with it just so you know. DogsController # new.js.erb (deleted new.html.erb) def new @dog = Dog.new respond_to do |format| format.js end end # create.js.erb def create @dog = current_user.dogs.new(params[:dog]) respond_to do |format| if @dog.save format.html { redirect_to add_url, notice: 'Dog was successfully added.' } format.json { render json: @dog, status: :created, location: @dog} format.js else format.html { render 'pages/add' } format.json { render json: @dog.errors, status: :unprocessable_entity } end end end dogs/_form.html.erb <%= simple_form_for(@dog, :remote => true) do |f| %> <%= render :partial => "shared/error_message", :locals => { :f => f } %> <%= f.input :name %> <%= f.button :submit, 'Done' %> <% end %> This line: <%= render :partial => "shared/error_message", :locals => { :f => f } %> Is for bootstrap so it renders the errors html correctly. PagesController def add respond_to do |format| format.html end end pages/add.html.erb <div id="generate-form"> </div> dogs/new.js.erb $("#generate-form").html("<%= escape_javascript(render(:partial => 'dogs/form', locals: { dog: @dog })) %>"); Now how would I get this to render the error partial as if it was still on my dogs/new.html.erb since its being created through AJAX? I don't need client side validations do I?

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  • python thread prob after build

    - by Apache
    hi expert, i'm having task to scan wifi at specific interval and send it to the server, i've it in python and its works fine when i run manually, then build it to package and when run there is no progress at all, i already ask this question before at http://stackoverflow.com/questions/2735410/python-scritp-problem-once-build-and-package-it, then, i re-modify my code as below, then i found that thread is not functioning once i build, #!/usr/bin/env python import subprocess,threading,... configFile = open('/opt/Jemapoh_Wifi/config.txt', 'r') url = configFile.readline().strip() intervalTime = configFile.readline().strip() status = configFile.readline().strip() print "url "+url print "intervalTime "+intervalTime print "Status "+status.strip() def getMacAddress(): proc = subprocess.Popen('ifconfig -a wlan0 | grep HWaddr | sed \'/^.*HWaddr */!d; s///;q\'', shell=True, stdout=subprocess.PIPE, ) macAddress = proc.communicate()[0].strip() return macAddress def getTimestamp(): from time import strftime timeStamp = strftime("%Y-%m-%d %H:%M:%S") return timeStamp def scanWifi(): try: print "Scanning..." proc = subprocess.Popen('iwlist scan 2>/dev/null', shell=True, stdout=subprocess.PIPE, ) stdout_str = proc.communicate()[0] stdout_list=stdout_str.split('\n') essid=[] rssi=[] preQuality=[] for line in stdout_list: line=line.strip() match=re.search('ESSID:"(\S+)"',line) if match: essid.append(match.group(1)) match=re.search('Quality=(\S+)',line) if match: preQuality.append(match.group(1)) for qualityConversion in preQuality: qualityConversion = qualityConversion.split()[0].split('/') temp = str(int(round(float(qualityConversion[0]) / float(qualityConversion[1]) * 100))).rjust(2) rssi.append(temp) dataToPost = '{"userId":"' + getMacAddress() + '","timestamp":"' + getTimestamp() + '","wifi":[' for no in range(len(essid)): dataToPost += '{"ssid":"' + essid[no] + '","rssi":"' + rssi[no] + '"}' if no+1 == len(essid): pass else: dataToPost += ',' dataToPost += ']}' query_args = {"data":dataToPost} request = urllib2.Request(url) request.add_data(urllib.urlencode(query_args)) request.add_header('Content-Type', 'application/x-www-form-urlencoded') print "Waiting for server response..." print urllib2.urlopen(request).read() print "Data Sent @ " + getTimestamp() print "------------------------------------------------------" t = threading.Timer(int(intervalTime), scanWifi).start() except Exception, e: print e t = threading.Timer(int(intervalTime), scanWifi) t.start() once build, its not reaching the thread, do can anyone help, why the thread is not working after build thanks

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  • Using pam_python in a script running with mod_python

    - by markys
    Hi ! I would like to develop a web interface to allow users of a Linux system to do certain tasks related to their account. I decided to write the backend of the site using Python and mod_python on Apache. To authenticate the users, I thought I could use python_pam to query the PAM service. I adapted the example bundled with the module and got this: # out is the output stream used to print debug def auth(username, password, out): def pam_conv(aut, query_list, user_data): out.write("Query list: " + str(query_list) + "\n") # List to store the responses to the different queries resp = [] for item in query_list: query, qtype = item # If PAM asks for an input, give the password if qtype == PAM.PAM_PROMPT_ECHO_ON or qtype == PAM.PAM_PROMPT_ECHO_OFF: resp.append((str(password), 0)) elif qtype == PAM.PAM_PROMPT_ERROR_MSG or qtype == PAM.PAM_PROMPT_TEXT_INFO: resp.append(('', 0)) out.write("Our response: " + str(resp) + "\n") return resp # If username of password is undefined, fail if username is None or password is None: return False service = 'login' pam_ = PAM.pam() pam_.start(service) # Set the username pam_.set_item(PAM.PAM_USER, str(username)) # Set the conversation callback pam_.set_item(PAM.PAM_CONV, pam_conv) try: pam_.authenticate() pam_.acct_mgmt() except PAM.error, resp: out.write("Error: " + str(resp) + "\n") return False except: return False # If we get here, the authentication worked return True My problem is that this function does not behave the same wether I use it in a simple script or through mod_python. To illustrate this, I wrote these simple cases: my_username = "markys" my_good_password = "lalala" my_bad_password = "lololo" def handler(req): req.content_type = "text/plain" req.write("1- " + str(auth(my_username,my_good_password,req) + "\n")) req.write("2- " + str(auth(my_username,my_bad_password,req) + "\n")) return apache.OK if __name__ == "__main__": print "1- " + str(auth(my_username,my_good_password,sys.__stdout__)) print "2- " + str(auth(my_username,my_bad_password,sys.__stdout__)) The result from the script is : Query list: [('Password: ', 1)] Our response: [('lalala', 0)] 1- True Query list: [('Password: ', 1)] Our response: [('lololo', 0)] Error: ('Authentication failure', 7) 2- False but the result from mod_python is : Query list: [('Password: ', 1)] Our response: [('lalala', 0)] Error: ('Authentication failure', 7) 1- False Query list: [('Password: ', 1)] Our response: [('lololo', 0)] Error: ('Authentication failure', 7) 2- False I don't understand why the auth function does not return the same value given the same inputs. Any idea where I got this wrong ? Here is the original script, if that could help you. Thanks a lot !

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  • What am I doing wrong with my Shoes program?

    - by dmonroe4919
    #Shoes.app(:title => "Collinear Points", :width => 450, :height => 350) do def calculate math.sqrt(((@[email protected]_f)**2)+((@[email protected]_f)**2)+((@[email protected]_f)**2)) end def compute math.sqrt(((@[email protected]_f)**2)+((@[email protected]_f)**2)+((@[email protected]_f)**2)) end def capture math.sqrt(((@[email protected]_f)**2)+((@[email protected]_f)**2)+((@[email protected]_f)**2)) end stack(:width => '100%', :margin => 20) do para('Calculate Collinear Points') para(' x y z') end flow(:width => '100%' ) do para('Point A: ') @alphax = edit_line(:width => 100, height => 35) {@collinear.text = calculate} @alphay = edit_line(:width => 100, height => 35) {@collinear.text = calculate} @alphaz = edit_line(:width => 100, height => 35) {@collinear.text = calculate} end flow(:width => '100%' ) do para('Point B: ') @betax = edit_line(:width => 100, height => 35) {@collinear.text = compute} @betay = edit_line(:width => 100, height => 35) {@collinear.text = compute} @betaz = edit_line(:width => 100, height => 35) {@collinear.text = compute} end flow(:width => '100%' ) do para('Point C: ') @gammax = edit_line(:width => 100, height => 35) {@collinear.text = capture} @gammay = edit_line(:width => 100, height => 35) {@collinear.text = capture} @gammaz = edit_line(:width => 100, height => 35) {@collinear.text = capture} end button("Configure") @button.click do c = calculate+compute=capture case c when c=true alert("Points are collinear, equation is ") when c=false alert("Points are non-collinear") end end

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  • Order in many to many relation in Django model

    - by Pietro Speroni
    I am writing a small website to store the papers I have written. The relation papers<- author is important, but the order of the name of the authors (which one is First Author, which one is second order, and so on) is also important. I am just learning Django so I don't know much. In any case so far I have done: from django.db import models class author(models.Model): Name = models.CharField(max_length=60) URLField = models.URLField(verify_exists=True, null=True, blank=True) def __unicode__(self): return self.Name class topic(models.Model): TopicName = models.CharField(max_length=60) def __unicode__(self): return self.TopicName class publication(models.Model): Title = models.CharField(max_length=100) Authors = models.ManyToManyField(author, null=True, blank=True) Content = models.TextField() Notes = models.TextField(blank=True) Abstract = models.TextField(blank=True) pub_date = models.DateField('date published') TimeInsertion = models.DateTimeField(auto_now=True) URLField = models.URLField(verify_exists=True,null=True, blank=True) Topic = models.ManyToManyField(topic, null=True, blank=True) def __unicode__(self): return self.Title This work fine in the sense that I now can define who the authors are. But I cannot order them. How should I do that? Of course I could add a series of relations: first author, second author,... but it would be ugly, and would not be flexible. Any better idea? Thanks

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  • Python subprocess Popen.communicate() equivalent to Popen.stdout.read()?

    - by Christophe
    Very specific question (I hope): What are the differences between the following three codes? (I expect it to be only that the first does not wait for the child process to be finished, while the second and third ones do. But I need to be sure this is the only difference...) I also welcome other remarks/suggestions (though I'm already well aware of the shell=True dangers and cross-platform limitations) Note that I already read Python subprocess interaction, why does my process work with Popen.communicate, but not Popen.stdout.read()? and that I do not want/need to interact with the program after. Also note that I already read Alternatives to Python Popen.communicate() memory limitations? but that I didn't really get it... First code: from subprocess import Popen, PIPE def exe_f(command='ls -l', shell=True): "Function to execute a command and return stuff" process = Popen(command, shell=shell, stdout=PIPE, stderr=PIPE) stdout = process.stdout.read() stderr = process.stderr.read() return process, stderr, stdout Second code: from subprocess import Popen, PIPE from subprocess import communicate def exe_f(command='ls -l', shell=True): "Function to execute a command and return stuff" process = Popen(command, shell=shell, stdout=PIPE, stderr=PIPE) (stdout, stderr) = process.communicate() return process, stderr, stdout Third code: from subprocess import Popen, PIPE from subprocess import wait def exe_f(command='ls -l', shell=True): "Function to execute a command and return stuff" process = Popen(command, shell=shell, stdout=PIPE, stderr=PIPE) code = process.wait() stdout = process.stdout.read() stderr = process.stderr.read() return process, stderr, stdout Thanks.

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  • Getting exception when trying to monkey patch pymongo.connection._Pool

    - by Creotiv
    I use pymongo 1.9 on Ubuntu 10.10 with python 2.6.6 When i trying to monkey patch pymongo.connection._Pool i'm getting error on connection: AutoReconnect: could not find master/primary But when i change _Pool class in pymongo.connection module, it work pretty fine. Even if i copy _Pool implementation from pymongo.connection module and will try to monkey patch by the same code, it still giving same exception. I need to remove threading.local from _Pool class, because i use gevent and i need to implement Pool for all mongo connections(for all threads). I use this code: import pymongo class GPool: """A simple connection pool. Uses thread-local socket per thread. By calling return_socket() a thread can return a socket to the pool. Right now the pool size is capped at 10 sockets - we can expose this as a parameter later, if needed. """ # Non thread-locals __slots__ = ["sockets", "socket_factory", "pool_size","sock"] #sock = None def __init__(self, socket_factory): self.pool_size = 10 if not hasattr(self,"sock"): self.sock = None self.socket_factory = socket_factory if not hasattr(self, "sockets"): self.sockets = [] def socket(self): # we store the pid here to avoid issues with fork / # multiprocessing - see # test.test_connection:TestConnection.test_fork for an example # of what could go wrong otherwise pid = os.getpid() if self.sock is not None and self.sock[0] == pid: return self.sock[1] try: self.sock = (pid, self.sockets.pop()) except IndexError: self.sock = (pid, self.socket_factory()) return self.sock[1] def return_socket(self): if self.sock is not None and self.sock[0] == os.getpid(): # There's a race condition here, but we deliberately # ignore it. It means that if the pool_size is 10 we # might actually keep slightly more than that. if len(self.sockets) < self.pool_size: self.sockets.append(self.sock[1]) else: self.sock[1].close() self.sock = None pymongo.connection._Pool = GPool

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  • Python beginer having trouble running code

    - by Protean
    For some reason this code will not seem to run in the interpreter. When I hit F5 nothing happens, not even the debugger seems to recognize it. I assume it has something to do with the class, as when removed the interpreter seems to recognize the rest of the code. Please tell me what I am doing wrong. Edit: I have restarted the interpreter multiple times, any other piece of code I try to load runs fine, just this one is having trouble. print ('Why won't this work?') class sorting_class: def __init__(self): self.order = ['a', 'b', 'c', 'd'] self.globali = 0 self.orderi = 0 self.sortedlist = [] def sort(self, array): carry, leave = [] for arrayi in array: print ('run', arrayi) if self.order[self.orderi] == arrayi[self.globali]: carry.append(arrayi) else: if self.globali != 0: leave.append(arrayi) return carry, leave def srt(self, array): globalii = 0 carry, leave = my.sort(array) while len(self.sortedlist) != len(array): if len(self.carry) == 1: self.sortedlist.append(carry) arrayt = leave self.globali = 1 self.orderi = 0 carry, leave = my.sort(arrayt) elif len(self.carry) == 0: if len(self.leave) != 0: arrayt = leave self.globali = 1 self.orderi += 1 my.sort(arrayt) else: self.arrayt globalii += 1 self.orderi = globalii self.globali = 0 my.sort(arrayt) self.orderi = 0 else: arrayt = carry carry = [] self.globali += 1 carry, leave += my.sort(arrayt) my = sorting_class() x = ['ac', 'bc' ,'ab', 'da'] my.srt(x)

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  • Trying to set up nested while loops using a boolean switch

    - by thorn100
    First time posting. I'm trying to set up a while loop that will ask the user for the employee name, hours worked and hourly wage until the user enters 'DONE'. Eventually I'll modify the code to calculate the weekly pay and write it to a list, but one thing at a time. The problem is once the main while loop executes once, it just stops. Doesn't error out but just stops. I have to kill the program to get it to stop. I want it to ask the three questions again and again until the user is finished. Thoughts? Please note that this is just an exercise and not meant for any real world application. def getName(): """Asks for the employee's full name""" firstName=raw_input("\nWhat is your first name? ") lastName=raw_input("\nWhat is your last name? ") fullName=firstName.title() + " " + lastName.title() return fullName def getHours(): """Asks for the number of hours the employee worked""" hoursWorked=0 while int(hoursWorked)<1 or int(hoursWorked) > 60: hoursWorked=raw_input("\nHow many hours did the employee work: ") if int(hoursWorked)<1 or int(hoursWorked) > 60: print "Please enter an integer between 1 and 60." else: return hoursWorked def getWage(): """Asks for the employee's hourly wage""" wage=0 while float(wage)<6.00 or float(wage)>20.00: wage=raw_input("\nWhat is the employee's hourly wage: ") if float(wage)<6.00 or float(wage)>20.00: print ("Please enter an hourly wage between $6.00 and $20.00") else: return wage ##sentry variables employeeName="" employeeHours=0 employeeWage=0 booleanDone=False #Enter employee info print "Please enter payroll information for an employee or enter 'DONE' to quit." while booleanDone==False: while employeeName=="": employeeName=getName() if employeeName.lower()=="done": booleanDone=True break print "The employee's name is", employeeName while employeeHours==0: employeeHours=getHours() if employeeHours.lower()=="done": booleanDone=True break print employeeName, "worked", employeeHours, "this week." while employeeWage==0: employeeWage=getWage() if employeeWage.lower()=="done": booleanDone=True break print employeeName + "'s hourly wage is $" + employeeWage

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  • Python __subclasses__() not listing subclasses

    - by Mridang Agarwalla
    I cant seem to list all derived classes using the __subclasses__() method. Here's my directory layout: import.py backends __init__.py --digger __init__.py base.py test.py --plugins plugina_plugin.py From import.py i'm calling test.py. test.py in turn iterates over all the files in the plugins directory and loads all of them. test.py looks like this: import os import sys import re sys.path.append(os.path.join(os.path.abspath(os.path.dirname(os.path.abspath( __file__ ))))) sys.path.append(os.path.join(os.path.abspath(os.path.dirname(os.path.abspath( __file__ ))), 'plugins')) from base import BasePlugin class TestImport: def __init__(self): print 'heeeeello' PLUGIN_DIRECTORY = os.path.join(os.path.abspath(os.path.dirname(os.path.abspath( __file__ ))), 'plugins') for filename in os.listdir (PLUGIN_DIRECTORY): # Ignore subfolders if os.path.isdir (os.path.join(PLUGIN_DIRECTORY, filename)): continue else: if re.match(r".*?_plugin\.py$", filename): print ('Initialising plugin : ' + filename) __import__(re.sub(r".py", r"", filename)) print ('Plugin system initialized') print BasePlugin.__subclasses__() The problem us that the __subclasses__() method doesn't show any derived classes. All plugins in the plugins directory derive from a base class in the base.py file. base.py looks like this: class BasePlugin(object): """ Base """ def __init__(self): pass plugina_plugin.py looks like this: from base import BasePlugin class PluginA(BasePlugin): """ Plugin A """ def __init__(self): pass Could anyone help me out with this? Whatm am i doing wrong? I've racked my brains over this but I cant seem to figure it out Thanks.

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  • Django sitemap intermittent www

    - by Jen Z
    The automatic sitemap for my Django site fluctuates between including the www on urls and leaving it out (I'm aiming to have it in all the time). This has ramifications in google not indexing my pages properly so I'm trying to narrow down what would be causing this issue. I have set PREPEND_WWW = True and my site record in the sites framework is set to include the www e.g. it's set to www.example.com as opposed to example.com. I'm using memcached but pages should expire from the cache after 48 hours so I wouldn't have thought that would be causing the issue? You can see the problem in effect at http://www.livingspaceltd.co.uk/sitemap.xml (refresh the page a few times). My sitemaps setup is fairly prosaic so I'm doubtful that that is the issue, but in case it's something obvious I'm missing here's the code: ***urls.py*** sitemaps = { 'subpages': Subpages_Sitemap, 'standalone_pages': Standalone_Sitemap, 'categories': Categories_Sitemap, } urlpatterns = patterns('', (r'^sitemap\.xml$', 'django.contrib.sitemaps.views.sitemap', {'sitemaps': sitemaps}), ... ***sitemaps.py*** # -*- coding: utf-8 -*- from django_ls.livingspace.models import Page, Category, Standalone_Page, Subpage from django.contrib.sitemaps import Sitemap class Subpages_Sitemap(Sitemap): changefreq = "monthly" priority = 0.4 def items(self): return Subpage.objects.filter(restricted_to__isnull=True) class Standalone_Sitemap(Sitemap): changefreq = "weekly" priority = 1 def items(self): return Standalone_Page.objects.all() class Categories_Sitemap(Sitemap): changefreq = "weekly" priority = 0.7 def items(self): return Category.objects.all()

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  • Slow Python HTTP server on localhost

    - by Abiel
    I am experiencing some performance problems when creating a very simple Python HTTP server. The key issue is that performance is varying depending on which client I use to access it, where the server and all clients are being run on the local machine. For instance, a GET request issued from a Python script (urllib2.urlopen('http://localhost/').read()) takes just over a second to complete, which seems slow considering that the server is under no load. Running the GET request from Excel using MSXML2.ServerXMLHTTP also feels slow. However, requesting the data Google Chrome or from RCurl, the curl add-in for R, yields an essentially instantaneous response, which is what I would expect. Adding further to my confusion is that I do not experience any performance problems for any client when I am on my computer at work (the performance problems are on my home computer). Both systems run Python 2.6, although the work computer runs Windows XP instead of 7. Below is my very simple server example, which simply returns 'Hello world' for any get request. from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer class MyHandler(BaseHTTPRequestHandler): def do_GET(self): print("Just received a GET request") self.send_response(200) self.send_header("Content-type", "text/html") self.end_headers() self.wfile.write('Hello world') return def log_request(self, code=None, size=None): print('Request') def log_message(self, format, *args): print('Message') if __name__ == "__main__": try: server = HTTPServer(('localhost', 80), MyHandler) print('Started http server') server.serve_forever() except KeyboardInterrupt: print('^C received, shutting down server') server.socket.close() Note that in MyHandler I override the log_request() and log_message() functions. The reason is that I read that a fully-qualified domain name lookup performed by one of these functions might be a reason for a slow server. Unfortunately setting them to just print a static message did not solve my problem. Also, notice that I have put in a print() statement as the first line of the do_GET() routine in MyHandler. The slowness occurs prior to this message being printed, meaning that none of the stuff that comes after it is causing a delay.

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  • Python subprocess: 64 bit windows server PIPE doesn't exist :(

    - by Spaceman1861
    I have a GUI that launches selected python scripts and runs it in cmd next to the gui window. I am able to get my launcher to work on my (windows xp 32 bit) laptop but when I upload it to the server(64bit windows iss7) I am running into some issues. The script runs, to my knowledge but spits back no information into the cmd window. My script is a bit of a Frankenstein that I have hacked and slashed together to get it to work I am fairly certain that this is a very bad example of the subprocess module. Just wondering if i could get a hand :). My question is how do i have to alter my code to work on a 64bit windows server. :) from Tkinter import * import pickle,subprocess,errno,time,sys,os PIPE = subprocess.PIPE if subprocess.mswindows: from win32file import ReadFile, WriteFile from win32pipe import PeekNamedPipe import msvcrt else: import select import fcntl def recv_some(p, t=.1, e=1, tr=5, stderr=0): if tr < 1: tr = 1 x = time.time()+t y = [] r = '' pr = p.recv if stderr: pr = p.recv_err while time.time() < x or r: r = pr() if r is None: if e: raise Exception(message) else: break elif r: y.append(r) else: time.sleep(max((x-time.time())/tr, 0)) return ''.join(y) def send_all(p, data): while len(data): sent = p.send(data) if sent is None: raise Exception(message) data = buffer(data, sent) The code above isn't mine def Run(): print filebox.get(0) location = filebox.get(0) location = location.__str__().replace(listbox.get(ANCHOR).__str__(),"") theTime = time.asctime(time.localtime(time.time())) lastbox.delete(0, END) lastbox.insert(END,theTime) for line in CookieCont: if listbox.get(ANCHOR) in line and len(line) > 4: line[4] = theTime else: "Fill In the rip Details to record the time" if __name__ == '__main__': if sys.platform == 'win32' or sys.platform == 'win64': shell, commands, tail = ('cmd', ('cd "'+location+'"',listbox.get(ANCHOR).__str__()), '\r\n') else: return "Please use contact admin" a = Popen(shell, stdin=PIPE, stdout=PIPE) print recv_some(a) for cmd in commands: send_all(a, cmd + tail) print recv_some(a) send_all(a, 'exit' + tail) print recv_some(a, e=0) The Code above is mine :)

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  • heterogeneous comparisons in python3

    - by Matt Anderson
    I'm 99+% still using python 2.x, but I'm trying to think ahead to the day when I switch. So, I know that using comparison operators (less/greater than, or equal to) on heterogeneous types that don't have a natural ordering is no longer supported in python3.x -- instead of some consistent (but arbitrary) result we raise TypeError instead. I see the logic in that, and even mostly think its a good thing. Consistency and refusing to guess is a virtue. But what if you essentially want the python2.x behavior? What's the best way to go about getting it? For fun (more or less) I was recently implementing a Skip List, a data structure that keeps its elements sorted. I wanted to use heterogeneous types as keys in the data structure, and I've got to compare keys to one another as I walk the data structure. The python2.x way of comparing makes this really convenient -- you get an understandable ordering amongst elements that have a natural ordering, and some ordering amongst those that don't. Consistently using a sort/comparison key like (type(obj).__name__, obj) has the disadvantage of not interleaving the objects that do have a natural ordering; you get all your floats clustered together before your ints, and your str-derived class separates from your strs. I came up with the following: import operator def hetero_sort_key(obj): cls = type(obj) return (cls.__name__+'_'+cls.__module__, obj) def make_hetero_comparitor(fn): def comparator(a, b): try: return fn(a, b) except TypeError: return fn(hetero_sort_key(a), hetero_sort_key(b)) return comparator hetero_lt = make_hetero_comparitor(operator.lt) hetero_gt = make_hetero_comparitor(operator.gt) hetero_le = make_hetero_comparitor(operator.le) hetero_ge = make_hetero_comparitor(operator.gt) Is there a better way? I suspect one could construct a corner case that this would screw up -- a situation where you can compare type A to B and type A to C, but where B and C raise TypeError when compared, and you can end up with something illogical like a > b, a < c, and yet b > c (because of how their class names sorted). I don't know how likely it is that you'd run into this in practice.

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  • Python: circular imports needed for type checking

    - by phild
    First of all: I do know that there are already many questions and answers to the topic of the circular imports. The answer is more or less: "Design your Module/Class structure properly and you will not need circular imports". That is true. I tried very hard to make a proper design for my current project, I in my opinion I was successful with this. But my specific problem is the following: I need a type check in a module that is already imported by the module containing the class to check against. But this throws an import error. Like so: foo.py: from bar import Bar class Foo(object): def __init__(self): self.__bar = Bar(self) bar.py: from foo import Foo class Bar(object): def __init__(self, arg_instance_of_foo): if not isinstance(arg_instance_of_foo, Foo): raise TypeError() Solution 1: If I modified it to check the type by a string comparison, it will work. But I dont really like this solution (string comparsion is rather expensive for a simple type check, and could get a problem when it comes to refactoring). bar_modified.py: from foo import Foo class Bar(object): def __init__(self, arg_instance_of_foo): if not arg_instance_of_foo.__class__.__name__ == "Foo": raise TypeError() Solution 2: I could also pack the two classes into one module. But my project has lots of different classes like the "Bar" example, and I want to seperate them into different module files. After my own 2 solutions are no option for me: Has anyone a nicer solution for this problem?

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  • wxpython: adding panel to wx.Frame disables/conflicts with wx.Frame's OnPaint?!

    - by sdaau
    Hi all, I just encountered this strange situation: I found an example, where wx.Frame's OnPaint is overridden, and a circle is drawn. Funnily, as soon as I add even a single panel to the frame, the circle is not drawn anymore - in fact, OnPaint is not called at all anymore ! Can anyone explain me if this is the expected behavior, and how to correctly handle a wx.Frame's OnPaint, if the wx.Frame has child panels ? Small code example is below.. Thanks in advance for any answers, Cheers! The code: #!/usr/bin/env python # http://www.linuxquestions.org/questions/programming-9/wxwidgets-wxpython-drawing-problems-with-onpaint-event-703946/ import wx class MainWindow(wx.Frame): def __init__(self, parent, title, size=wx.DefaultSize): wx.Frame.__init__(self, parent, wx.ID_ANY, title, wx.DefaultPosition, size) self.circles = list() self.displaceX = 30 self.displaceY = 30 circlePos = (self.displaceX, self.displaceY) self.circles.append(circlePos) ## uncommenting either only first, or both of ## the commands below, causes OnPaint *not* to be called anymore! #~ self.panel = wx.Panel(self, wx.ID_ANY) #~ self.mpanelA = wx.Panel(self.panel, -1, size=(200,50)) self.Bind(wx.EVT_PAINT, self.OnPaint) def OnPaint(self, e): print "OnPaint called" dc = wx.PaintDC(self) dc.SetPen(wx.Pen(wx.BLUE)) dc.SetBrush(wx.Brush(wx.BLUE)) # Go through the list of circles to draw all of them for circle in self.circles: dc.DrawCircle(circle[0], circle[1], 10) def main(): app = wx.App() win = MainWindow(None, "Draw delayed circles", size=(620,460)) win.Show() app.MainLoop() if __name__ == "__main__": main()

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  • Ruby - calling constructor without arguments & removal of new line characters

    - by Raj
    I am a newbie at Ruby, I have written down a sample program. I dont understand the following: Why constructor without any arguments are not called in Ruby? How do we access the class variable outside the class' definition? Why does it always append newline characters at the end of the string? How do we strip it? Code: class Employee attr_reader :empid attr_writer :empid attr_writer :name def name return @name.upcase end attr_accessor :salary @@employeeCount = 0 def initiaze() @@employeeCount += 1 puts ("Initialize called!") end def getCount return @@employeeCount end end anEmp = Employee.new print ("Enter new employee name: ") anEmp.name = gets() print ("Enter #{anEmp.name}'s employee ID: ") anEmp.empid = gets() print ("Enter salary for #{anEmp.name}: ") anEmp.salary = gets() theEmpName = anEmp.name.split.join("\n") theEmpID = anEmp.empid.split.join("\n") theEmpSalary = anEmp.salary.split.join("\n") anEmp = Employee.new() anEmp = Employee.new() theCount = anEmp.getCount puts ("New employee #{theEmpName} with employee ID #{theEmpID} has been enrolled, welcome to hell! You have been paid as low as $ #{theEmpSalary}") puts ("Total number of employees created = #{theCount}") Output: Enter new employee name: Lionel Messi Enter LIONEL MESSI 's employee ID: 10 Enter salary for LIONEL MESSI : 10000000 New employee LIONEL MESSI with employee ID 10 has been enrolled, welcome to hell! You have been paid as low as $ 10000000 Total number of employees created = 0 Thanks

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  • How Does One Make Scala Control Abstraction in Repeat Until?

    - by peter_pilgrim
    Hi I am Peter Pilgrim. I watched Martin Odersky create a control abstraction in Scala. However I can not yet seem to repeat it inside IntelliJ IDEA 9. Is it the IDE? package demo class Control { def repeatLoop ( body: = Unit ) = new Until( body ) class Until( body: = Unit ) { def until( cond: = Boolean ) { body; val value: Boolean = cond; println("value="+value) if ( value ) repeatLoop(body).until(cond) // if (cond) until(cond) } } def doTest2(): Unit = { var y: Int = 1 println("testing ... repeatUntil() control structure") repeatLoop { println("found y="+y) y = y + 1 } { until ( y < 10 ) } } } The error message reads: Information:Compilation completed with 1 error and 0 warnings Information:1 error Information:0 warnings C:\Users\Peter\IdeaProjects\HelloWord\src\demo\Control.scala Error:Error:line (57)error: Control.this.repeatLoop({ scala.this.Predef.println("found y=".+(y)); y = y.+(1) }) of type Control.this.Until does not take parameters repeatLoop { In the curried function the body can be thought to return an expression (the value of y+1) however the declaration body parameter of repeatUntil clearly says this can be ignored or not? What does the error mean?

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  • How to create custom omniauth provider (how to return data)

    - by user2803917
    I searched all around the net, how to create a custom provider for omniauth.. and i succedded partly.. I created a gem, and it worked perfectly, except the part, that i cant understand how to return the gathered data to sessions controller, like other providers do.. here is the code in auth gem: require 'multi_json' require 'digest/md5' require 'rest-client' module OmniAuth module Strategies class Providername < OmniAuth::Strategies::OAuth attr_accessor :app_id, :api_key, :auth def initialize(app, app_id = nil, api_key = nil, options = {}) super(app, :providername) @app_id = app_id @api_key = api_key end protected def request_phase redirect "http://valid_url" end def callback_phase if request.params['code'] && request.params['status'] == 'ok' response = RestClient.get("http://valid_url2/?code=#{request.params['auth_code']}") auth = MultiJson.decode(response.to_s) unless auth['error'] @auth_data = auth if @auth_data @return_data = OmniAuth::Utils.deep_merge(super, { 'uid' => @auth_data['uid'], 'nickname' => @auth_data['nick'], 'user_info' => { 'first_name' => @auth_data['name'], 'last_name' => @auth_data['surname'], 'location' => @auth_data['place'], }, 'credentials' => { 'apikey' => @auth_data['apikey'] }, 'extra' => {'user_hash' => @auth_data} }) end end else fail!(:invalid_request) end rescue Exception => e fail!(:invalid_response, e) end end end end and here i call it in my initializers: Rails.application.config.middleware.use OmniAuth::Builder do provider "providername", Settings.providers.providername.app_id, Settings.providers.providername.app_secret end in this code, everything works fine so far, the provider gets called, i get the info from provider, i create a hash (@auth_data) with info, but how do i return it

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  • activemerchant PayPalExpress transaction is invalid

    - by Ameya Savale
    I am trying to integrate activemerchant into my ruby on rails application. This is my controller where I get the purchase attirbutes and create a PaypalExpressResponse object def checkout total_as_cents, purchase_params = get_setup_params(Schedule.find(params[:schedule]), request) setup_response = @gateway.setup_purchase(total_as_cents, purchase_params) redirect_to @gateway.redirect_url_for(setup_response.token) end @gateway is my PaypalExpressGateway object which I create using this method in my controller def assign_gateway @gateway = PaypalExpressGateway.new( :login => api_user, :password => api_pass, :signature => api_signature ) end I got the api_user, api_pass, and api_signature values from my developer.paypal.com account, when I logged in for the first time there was already a sandbox user created as a merchant which is where I got the api credentials from. And finally here is my get_setup_params method: def get_setup_params(schedule, request) purchase_params = { :ip => request.remote_ip, :return_url => url_for(:action => 'review', :only_path => false, :sched => schedule.id), :cancel_return_url => register_path, :allow_note => true, :item => schedule.id } return to_cents(schedule.fee), purchase_params end How ever when I click on the checkout button, I get redirected to a sandbox paypal page saying "This transaction is invalid. Please return to the recipient's website to complete your transaction using their regular checkout flow." I'm not sure exactly what's wrong, I think the problem lies in the credentials but don't know why. Any help will be appreciated. One other point, I'm running this in my development environment so I have put this in my config file config.after_initialize do ActiveMerchant::Billing::Base.mode = :test end UPDATE Found out what the problem was, my return cancel url was invalid instead of using register_path, I used url_for(action: "action-name", :only_path => false) this answer helped me Rails ActiveMerchant - Paypal Express Checkout Error even though I wasn't able to see the output of the response like the person has managed to do

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