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  • django/apache permissions problem

    - by Kevin
    I'm running a django project on Centos 5.4 and serving it with httpd/mod_wsgi. I can't figure out the correct permissions for /home/website/django_project so that I don't get a 403 error. In my httpd.conf the user and group to run httpd as is apache. The group django is set up with website and apache as members. The owner of /home/website and all subdirs is website:django, and the permissions are rwxrwx---. Right now the project works fine with the dev server, but if I try to view it through apache, I get a 403 error. chmod -R o+rx /home/website/django_project fixes the problem, but this obviously isn't a good solution. Thanks

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  • Django logging in and out - doesn't work if prepend_www set

    - by ropz
    I'm a Django beginner. My site - let's call it abc.com - works fine, letting users log in and out (having originally registered via Django registratiaon). If it's relevant, my virtuahosts file has ServerName abc.com and ServerAlias www.abc.com directives. I don't want my visitors to sense that both abc.com and www.abc.com exist, and so discovered Django's prepend_www setting, which works as intended. In addition to working as intended, however, there's a side effect that disables logging in and out when visiting the www. variant of my site.

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  • Add a right click context menu in certain WIndows folders that will open a web browser URL?

    - by jasondavis
    In a Windows Explorer window where you browse files in Windows 7, I would like to add a new context menu that will allow me to open a file on my local Dev Server. So it would have to open a browser like Google Crome and the URL would have to be the file path but slightly different removing part of it and prepending my localhost URL. For example if the file I am right clicking on, the path for that file might be... E:\Server\htdocs\labs\php\testProject\test.php I would need a button to click in the context menu Open in Browser and it would open my Web Browser with a URL like this... http://localhost/labs/php/testProject/test.php I would love to be able to do this, any ideas or help would greatly be appreciated! To go one step further, would to be able to somehow make the context menu item only show up on File that are under this folder.... ``E:\Server\htdocs` but this is far less important.

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  • SpellBook Parks Bookmarklets in Chrome’s Context Menu

    - by ETC
    If you want your bookmarklets right at your finger tips instead of stashed in your bookmarks menu, SpellBook is a handy Chrome extension that parks them right in the context menu. Install SpellBook and save your favorite bookmarklets in the “Bookmarklets” folder it creates for you. All the saved bookmarklets will be available in Chrome’s right-click context menu (as seen in the screenshot here). SpellBook is a free download and works wherever Chrome does. Hit up the link below to grab a copy. SpellBook [Chrome Extension Gallery via Download Squad] Latest Features How-To Geek ETC How To Make Hundreds of Complex Photo Edits in Seconds With Photoshop Actions How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) How To Remove People and Objects From Photographs In Photoshop Ask How-To Geek: How Can I Monitor My Bandwidth Usage? Internet Explorer 9 RC Now Available: Here’s the Most Interesting New Stuff Never Call Me at Work [Humorous Star Wars Video] Add an Image Properties Listing to the Context Menu in Chrome and Iron Add an Easy to View Notification Badge to Tabs in Firefox SpellBook Parks Bookmarklets in Chrome’s Context Menu Drag2Up Brings Multi-Source Drag and Drop Uploading to Firefox Enchanted Swing in the Forest Wallpaper

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  • [EF + Oracle]Object Context

    - by JTorrecilla
    Prologue After EF episodes I and II, we are going to see the Object Context. What is Object Context? It is a class which manages the DB connection, and the different Entities of our model. When Visual Studio creates the EF model, like I explain previously, also generates a Class that extends ObjectContext. ObjectContext provides: - DB connection - Add, update and delete functions. - Object Sets of Entities. - State of Pending Changes. This class will give a function, for each Entity, like  Esta clase va a contar con una función, para cada entidad, del tipo “AddTo{ENTITY}({Entity_Type } value)”, which are going to add a Entity to the related ObjectSet. In addition, it has a property, for each Entity, like “ObjectSet<TEntity> Entity”, does will keep the related record set. It will be filled with the CreateObjectSet<TEntity> function of Base class (ObjectContext). What is an ObjectSet? It is a class that allows us to manage the Entity Set from a Type. It inherits from: · ObjectQuery<TEntity> · IObjectSet<TEntity> · IQueryAble<TEntity · IEnumerable<TEntity · IQueryAble · IEnumerable An ObjectSet is a class property that allows query, insert, delete and update records from a determinate Entity. In following chapters we will see how to query Entities. LazyLoadingEnabled A very important property of the Context is “LazyLoadingEnabled”. This Boolean property lets indicate if the data loading is lazy, in other words, the Object will not be created and query until not be needed. Finally In this post we have seen what the VS generated context is, some of the characteristics, and where to see Entity data. In next chapters we will see, CRUD operations, and how to query ObjectSets.

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  • How to solve 404 for static files with Django and Nginx?

    - by Lucio
    I setup a Trusty VM with Django + Nginx (other stuffs too). The server is working, I get the "Welcome to Django" page. But when I enter to servername/admin it loads the HTML page but fails to load the static content. And the admin page have this links to static content: <link rel="stylesheet" type="text/css" href="/static/admin/css/base.css" /> <link rel="stylesheet" type="text/css" href="/static/admin/css/login.css" /> Both of the CSS files give me 404, as the Nginx log shows: 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin HTTP/1.1" 301 5 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin/ HTTP/1.1" 200 833 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/base.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/login.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" I think that the error is on my nginx.conf file, but do not know how to solve it.

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  • Trouble getting SSL to work with django + nginx + wsgi

    - by Kevin
    I've followed a couple of examples for Django + nginx + wsgi + ssl, but I can't get them to work. I simply get an error in my browser than I can't connect. I'm running two websites off the host. The config files are identical except for the ip addresses, server names, and directories. When neither use SSL, they work fine. When I try to listen on 443 with one of them, I can't connect to either. My config files are below, and any suggestions would be appreciated. server{ listen xxx.xxx.xxx.xxx:80; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } server{ listen xxx.xxx.xxx.xxx:443; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; ssl on; ssl_certificate sub.domain.com.crt; ssl_certificate_key sub.domain.com.key; ssl_prefer_server_ciphers on; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-Forwarded-Protocol https; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } <VirtualHost *:8080> ServerName xxx.xxx.xxx.xxx ServerAlias xxx.xxx.xxx.xxx LogLevel warn ErrorLog /home/django/logs/apache_customerdb_error.log CustomLog /home/django/logs/apache_customerdb_access.log combined WSGIScriptAlias / /home/django/customerdb/apache/django.wsgi WSGIDaemonProcess customerdb_wsgi processes=4 threads=5 WSGIProcessGroup customerdb_wsgi SetEnvIf X-Forwarded-Protocol "^https$" HTTPS=on </VirtualHost> UDPATE: the existence of two sites (on separate IPs) on the host is the issue. if i delete the other site, the setting above mostly work. doing so also brings up another issue: chrome doesn't accept the site as secure saying that some content is not encrypted.

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  • Django | Apache | Deploy website behind SSL

    - by planet260
    So here are my requirements. I have a website built in Django. I deployed it on Apache Ubuntu. Before there was no SSL involved so the deployment was pretty simple. But now the requirements are changed. Now I have to take a few actions like signup and login behind SSL and present the admin panel and other normally via HTTP. By following the this tutorial I have set-up Apache and SSL and generated certificates for SSL communication. But I am not sure how to proceed, ie. how to serve only a few of my actions through SSL. Below is my configuration. The normal actions are working fine but I don't know how to configure SSL calls. WSGIScriptAlias / /home/ubuntu/myproject/src/myproject/wsgi.py WSGIPythonPath /home/ubuntu/myproject/src <VirtualHost *:80> ServerName mydomain.com <Directory /home/ubuntu/myproject/src/myproject> <Files wsgi.py> order deny,allow Allow from all </Files> </Directory> Alias /static/admin/ "/home/ubuntu/myproject/src/static/admin/" <Directory "/home/ubuntu/myproject/src/static/admin/"> Order allow,deny Options Indexes Allow from all IndexOptions FancyIndexing </Directory> <Location "/login"> RewriteEngine on RewriteRule /admin(.*)$ https://mydomain.com/login$1 [L,R=301] </Location> </VirtualHost> <VirtualHost *:443> ServerName mydomain.com SSLEngine on SSLOptions +StrictRequire SSLCertificateFile /etc/apache2/ssl/apache.crt SSLCertificateKeyFile /etc/apache2/ssl/apache.key <Directory /home/ubuntu/myproject/src/myproject> <Files wsgi.py> order deny,allow Allow from all </Files> </Directory> Alias /static/admin/ "/home/ubuntu/myproject/src/static/admin/" <Directory "/home/ubuntu/myproject/src/static/admin/"> Order allow,deny Options Indexes Allow from all IndexOptions FancyIndexing </Directory> </VirtualHost> Can you please help me out on how to achieve this? What am I doing wrong? I have read a lot of tutorials but honestly I am not really good at configurations. Any help is appreciated.

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  • Load application context problem in Maven managed spring-test TestNg

    - by joejax
    I try to setup a project with spring-test using TestNg in Maven. The code is like: @ContextConfiguration(locations={"test-context.xml"}) public class AppTest extends AbstractTestNGSpringContextTests { @Test public void testApp() { assert true; } } A test-context.xml simply defined a bean: <bean id="app" class="org.sonatype.mavenbook.simple.App"/> I got error for Failed to load ApplicationContext when running mvn test from command line, seems it cannot find the test-context.xml file; however, I can get it run correctly inside Eclipse (with TestNg plugin). So, test-context.xml is under src/test/resources/, how do I indicate this in the pom.xml so that 'mvn test' command will work? Thanks, UPDATE: Thanks for the reply. Cannot load context file error was caused by I moved the file arround in different location since I though the classpath was the problem. Now I found the context file seems loaded from the Maven output, but the test is failed: Running TestSuite May 25, 2010 9:55:13 AM org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadBeanDefinitions INFO: Loading XML bean definitions from class path resource [test-context.xml] May 25, 2010 9:55:13 AM org.springframework.context.support.AbstractApplicationContext prepareRefresh INFO: Refreshing org.springframework.context.support.GenericApplicationContext@171bbc9: display name [org.springframework.context.support.GenericApplicationContext@171bbc9]; startup date [Tue May 25 09:55:13 PDT 2010]; root of context hierarchy May 25, 2010 9:55:13 AM org.springframework.context.support.AbstractApplicationContext obtainFreshBeanFactory INFO: Bean factory for application context [org.springframework.context.support.GenericApplicationContext@171bbc9]: org.springframework.beans.factory.support.DefaultListableBeanFactory@1df8b99 May 25, 2010 9:55:13 AM org.springframework.beans.factory.support.DefaultListableBeanFactory preInstantiateSingletons INFO: Pre-instantiating singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory@1df8b99: defining beans [app,org.springframework.context.annotation.internalCommonAnnotationProcessor,org.springframework.context.annotation.internalAutowiredAnnotationProcessor,org.springframework.context.annotation.internalRequiredAnnotationProcessor]; root of factory hierarchy Tests run: 3, Failures: 2, Errors: 0, Skipped: 1, Time elapsed: 0.63 sec If I use spring-test version 3.0.2.RELEASE, the error becomes: org.springframework.test.context.testng.AbstractTestNGSpringContextTests.springTestContextPrepareTestInstance() is depending on nonexistent method null Here is the structure of the project: simple |-- pom.xml `-- src |-- main | `-- java `-- test |-- java `-- resources |-- test-context.xml `-- testng.xml testng.xml: <suite name="Suite" parallel="false"> <test name="Test"> <classes> <class name="org.sonatype.mavenbook.simple.AppTest"/> </classes> </test> </suite> test-context.xml: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd" default-lazy-init="true"> <bean id="app" class="org.sonatype.mavenbook.simple.App"/> </beans> In the pom.xml, I add testng, spring, and spring-test artifacts, and plugin: <dependency> <groupId>org.testng</groupId> <artifactId>testng</artifactId> <version>5.1</version> <classifier>jdk15</classifier> <scope>test</scope> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring</artifactId> <version>2.5.6</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-test</artifactId> <version>2.5.6</version> <scope>test</scope> </dependency> <build> <finalName>simple</finalName> <plugins> <plugin> <artifactId>maven-compiler-plugin</artifactId> <configuration> <source>1.6</source> <target>1.6</target> </configuration> </plugin> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-surefire-plugin</artifactId> <configuration> <suiteXmlFiles> <suiteXmlFile>src/test/resources/testng.xml</suiteXmlFile> </suiteXmlFiles> </configuration> </plugin> </plugins> Basically, I replaced 'A Simple Maven Project' Junit with TestNg, hope it works.

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  • Can't get python.manage.py syncdb to work

    - by Diego
    I just created my first django app, initialized variables DATABASE_ENGINE and DATABASE_NAME in settings.py, but now when I run python manage.py syncdb, I get the following error Can somebody help? Does this have to do with having two python versions installed? I'm a django/python noob, please help. thanks!! my-computer:~/Django-1.1.1 mycomp$ python manage.py syncdb /Library/Frameworks/Python.framework/Versions/2.6/Resources/Python.app/Contents/MacOS/Python: can't open file 'manage.py': [Errno 2] No such file or directory my-computer:~/Django-1.1.1 mycomp$ export PATH=/Users/mycomp/bin:$PATH

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  • How to serve static files for multiple Django projects via nginx to same domain

    - by thanley
    I am trying to setup my nginx conf so that I can serve the relevant files for my multiple Django projects. Ultimately I want each app to be available at www.example.com/app1, www.example.com/app2 etc. They all serve static files from a 'static-files' directory located in their respective project root. The project structure: Home Ubuntu Web www.example.com ref logs app app1 app1 static bower_components templatetags app1_project templates static-files app2 app2 static templates templatetags app2_project static-files app3 tests templates static-files static app3_project app3 venv When I use the conf below, there are no problems for serving the static-files for the app that I designate in the /static/ location. I can also access the different apps found at their locations. However, I cannot figure out how to serve all of the static files for all the apps at the same time. I have looked into using the 'try_files' command for the static location, but cannot figure out how to see if it is working or not. Nginx Conf - Only serving static files for one app: server { listen 80; server_name example.com; server_name www.example.com; access_log /home/ubuntu/web/www.example.com/logs/access.log; error_log /home/ubuntu/web/www.example.com/logs/error.log; root /home/ubuntu/web/www.example.com/; location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; } location /media/ { alias /home/ubuntu/web/www.example.com/media/; } location /app1/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app1; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app1.sock; } location /app2/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app2; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app2.sock; } location /app3/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app3; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app3.sock; } # what to serve if upstream is not available or crashes error_page 400 /static/400.html; error_page 403 /static/403.html; error_page 404 /static/404.html; error_page 500 502 503 504 /static/500.html; # Compression gzip on; gzip_http_version 1.0; gzip_comp_level 5; gzip_proxied any; gzip_min_length 1100; gzip_buffers 16 8k; gzip_types text/plain text/css application/x-javascript text/xml application/xml application/xml+rss text/javascript; # Some version of IE 6 don't handle compression well on some mime-types, # so just disable for them gzip_disable "MSIE [1-6].(?!.*SV1)"; # Set a vary header so downstream proxies don't send cached gzipped # content to IE6 gzip_vary on; } Essentially I want to have something like (I know this won't work) location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; alias /home/ubuntu/web/www.example.com/app/app2/static-files/; alias /home/ubuntu/web/www.example.com/app/app3/static-files/; } or (where it can serve the static files based on the uri) location /static/ { try_files $uri $uri/ =404; } So basically, if I use try_files like above, is the problem in my project directory structure? Or am I totally off base on this and I need to put each app in a subdomain instead of going this route? Thanks for any suggestions TLDR: I want to go to: www.example.com/APP_NAME_HERE And have nginx serve the static location: /home/ubuntu/web/www.example.com/app/APP_NAME_HERE/static-files/;

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  • Looking for a good example usage of get_or _create in Django views and raising a Form error

    - by Rik Wade
    I am looking for a good example of how to achieve the following: I would like to use get_or_create to check whether an object already exists in my database. If it does not, then it will be created. If it does exist, then I will not create the new object, but need to raise a form error to inform the user that they need to enter different data (for example, a different username). The view contains: p, created = Person.objects.get_or_create( email = registration_form.cleaned_data['email'], defaults = { 'creationDate': datetime.datetime.now(), 'dateOfBirth': datetime.date(1970,1,1) }) So 'p' will contain the existing Person if it exists, or the new Person if not. I would like to act on the boolean value in 'created' in order to skip over saving the Person and re-display the registration_form and raise an appropriate form validation error. The alternative I'm considering is doing a check in a custom Form validation method to see whether a Person exists with the data in the provided 'email' field, and just raising a validation error.

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  • Django QuerySet API: How do I join iexact and icontains?

    - by Zeynel
    Hello, I have this join: lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) This is the site If you try Last Name: Abbas and First Name: Amr it tells you that amr abbas has 1 schoolmates. But if you try First name only it says that there are no lawyers in the database called amr (obviously there is). If I change (last__iexact=last_name) to (last__icontains=last_name) then leaving Last Name blank works fine and amr is found. But with last__icontains=last_name if you search for "collin" you also get "collins" and "collingwood" which is not what I want. Do you know how I can use iexact and also have it ignored if it is blank? Thanks This is the view function: def search_form(request): if request.method == 'POST': search_form = SearchForm(request.POST) if search_form.is_valid(): last_name = search_form.cleaned_data['last_name'] first_name = search_form.cleaned_data['first_name'] lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) if len(lawyers)==0: form = SearchForm() return render_to_response('not_in_database.html', {'last': last_name, 'first': first_name, 'form': form}) if len(lawyers)>1: form = SearchForm(initial={'last_name': last_name}) return render_to_response('more_than_1_match.html', {'lawyers': lawyers, 'last': last_name, 'first': first_name, 'form': form}) q_school = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('school', flat=True) q_year = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('year_graduated', flat=True) lawyers1 = Lawyer.objects.filter(school__iexact=q_school[0]).filter(year_graduated__icontains=q_year[0]).exclude(last__icontains=last_name) form = SearchForm() return render_to_response('search_results.html', {'lawyers': lawyers1, 'last': last_name, 'first': first_name, 'form': form}) else: form = SearchForm() return render_to_response('search_form.html', {'form': form, })

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  • Display a boolean model field in a django form as a radio button rather than the default Checkbox.

    - by Lakshman Prasad
    This is how I went about, to display a Boolean model field in the form as Radio buttons Yes and No. choices = ( (1,'Yes'), (0,'No'), ) class EmailEditForm(forms.ModelForm): #Display radio buttons instead of checkboxes to_send_form = forms.ChoiceField(choices=choices,widget=forms.RadioSelect) class Meta: model = EmailParticipant fields = ('to_send_email','to_send_form') def clean(self): """ A workaround as the cleaned_data seems to contain u'1' and u'0'. There may be a better way. """ self.cleaned_data['to_send_form'] = int(self.cleaned_data['to_send_form']) return self.cleaned_data As you can see in the code above, I need a clean method that converts input string to an integer, which may be unnecessary. Is there a better and/or djangoic way to do this. If so, how? And no, using BooleanField seems to cause a lot more problems. Using that seemed obvious to me; but it isn't. Why is it so.

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  • Django: How can I delete a formset entry if one of it's data is blank?

    - by mkret
    Hi, I have the following scenario: I have a form with data that does not need translation and a formset with a textfield that should be translated into an undefined amount of languages. Both parts are bound to a model. Each translated text is kept in a model with a foreign key that binds it to the untranslatable data. Something like: class Person(models.Model): name = models.CharField(max_length=60) birth_date = models.DateField() class PersonBio(models.Model): person = models.ForeignKey(Person) locale = models.CharField(max_length=10) bio = models.TextField() Each form in the formset has 2 fields: A textfield (with the translated text) A locale field (with the language into which the text was translated) I've got it working with no problems until I tryed to change it's normal behaviour. I wanted to eliminate the need for the DELETE field by deleting an instance of the translated text if the textfield was left blank. I've googled quite a lot now and read the whole documentation for forms, formsets and model validation but had no luck. To be honest, I couldn't even think of a solution. Where should I implement this? On a Form clean() method? On the view? Somewhere in the Fieldset? Fieldset's save() method, maybe? I'll keep trying to find a way to do that, but any help/tip/clue is appreciated. Thanks in advance.

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  • Sorting and indexing into a list in a Django template?

    - by slypete
    How can you perform complex sorting on an object before passing it to the template? For example, here is my view: @login_required def overview(request): physicians = PhysicianGroup.objects.get(pk=physician_group).physicians for physician in physicians.all(): physician.service_patients.order_by('bed__room__unit', 'bed__room__order', 'bed__order') return render_to_response('hospitalists/overview.html', RequestContext(request, {'physicians': physicians,})) The physicians object is not ordered correctly in the template. Why not? Additionally, how do you index into a list inside the template? For example, (this doesn't work): {% for note_type in note_types %} <div><h3>{{ note_type }}</h3> {% for notes in note_sets.index(parent.forloop.counter0) %} #only want to display the notes of this note_type! {% for note in notes %} <p>{{ note }}</p> {% endfor %} {% endfor %} </div> {% endfor %}

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  • Can I filter a django model with a python list?

    - by Rhubarb
    Say I have a model object 'Person' defined, which has a field called 'Name'. And I have a list of people: l = ['Bob','Dave','Jane'] I would like to return a list of all Person records where the first name is not in the list of names defined in l. What is the most pythonic way of doing this?

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  • How do I memoize expensive calculations on Django model objects?

    - by David Eyk
    I have several TextField columns on my UserProfile object which contain JSON objects. I've also defined a setter/getter property for each column which encapsulates the logic for serializing and deserializing the JSON into python datastructures. The nature of this data ensures that it will be accessed many times by view and template logic within a single Request. To save on deserialization costs, I would like to memoize the python datastructures on read, invalidating on direct write to the property or save signal from the model object. Where/How do I store the memo? I'm nervous about using instance variables, as I don't understand the magic behind how any particular UserProfile is instantiated by a query. Is __init__ safe to use, or do I need to check the existence of the memo attribute via hasattr() at each read? Here's an example of my current implementation: class UserProfile(Model): text_json = models.TextField(default=text_defaults) @property def text(self): if not hasattr(self, "text_memo"): self.text_memo = None self.text_memo = self.text_memo or simplejson.loads(self.text_json) return self.text_memo @text.setter def text(self, value=None): self.text_memo = None self.text_json = simplejson.dumps(value)

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  • How do I flag only one of the formsets in django admin ?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). My first solution was to override the validation of the formset but did understand how to do this. (is_correct is displayed as checkbox, and I'd display an error that only one is_correct should be selected.)

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  • How do I modify the HttpResponse object in django ?

    - by Rohit
    I need the html returned using render_to_response to be escaped. I am unable to find any suitable documentation. Can someone point in some direction ? the code is : return render_to_response(template_name, {return render_to_response(template_name, { 'form': form, redirect_field_name: redirect_to, 'site': current_site, 'site_name': current_site.name, }, context_instance=RequestContext(request)) Here I need the response html text to be escaped. I way I know is reading template file in string and escaping it with re.escape() and then rendering it. whats a cleaner and simpler way to do that ??

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  • Django, Redirecting staff from login to the admin site.

    - by Francisco Gomez
    So my site basically has 2 kinds of ways to login, one of them is for the common users, who get the regular screen that asks them for username and password, the other way its for staff. The staff login should redirect them to the admin site after logging in, but for some reason the redirect doesnt happen, it stays on the same login page. I use this condition on the login view. if user is not None and user.is_active and user.is_staff: auth.login(request,user) return HttpResponseRedirect("/admin/") The admin site its up and running in my url configuration and everything, but i dont know if this is the correct way to redirect to the admin site already on session. Thanks, any help would be appreciated.

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  • Django: How to iterate over formsets and access cleaned data?

    - by Mark
    What if I want to do something with my formset other than immediately saving it? How can I do this? for form in vehicles_formset.forms: listing.id = None listing.vehicle_year = form.cleaned_data['year'] listing.vehicle_make = form.cleaned_data['make'] listing.vehicle_model = form.cleaned_data['model'] listing.vin = form.cleaned_data['vin'] listing.vehicle_runs = form.cleaned_data['runs'] listing.vehicle_convertible = form.cleaned_data['convertible'] listing.vehicle_modified = form.cleaned_data['modified'] listing.save() (Thus creating multiple listings) Apparently cleaned_data does not exist. There's a bunch of stuff in the data dict like form-0-year but it's pretty useless to me like that.

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