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  • Calculating estimated data loss with Always on

    - by blakmk
    Ever wondered how calculate estimated data loss (time) for always on. The metric in the always on dashboard shows the metric quite nicely but there does seem to be a lack of documentation about where the metrics ---come from. Heres a script that calculates the data loss ( lag ) so you can set up alerts based on your DR SLA's:       WITH DR_CTE ( replica_server_name, database_name, last_commit_time) AS                 (                                 select ar.replica_server_name, database_name, rs.last_commit_time                                 from master.sys.dm_hadr_database_replica_states  rs                                 inner join master.sys.availability_replicas ar on rs.replica_id = ar.replica_id                                 inner join sys.dm_hadr_database_replica_cluster_states dcs on dcs.group_database_id = rs.group_database_id and rs.replica_id = dcs.replica_id                                 where replica_server_name != @@servername                 ) select ar.replica_server_name, dcs.database_name, rs.last_commit_time, DR_CTE.last_commit_time 'DR_commit_time', datediff(ss,  DR_CTE.last_commit_time, rs.last_commit_time) 'lag_in_seconds' from master.sys.dm_hadr_database_replica_states  rs inner join master.sys.availability_replicas ar on rs.replica_id = ar.replica_id inner join sys.dm_hadr_database_replica_cluster_states dcs on dcs.group_database_id = rs.group_database_id and rs.replica_id = dcs.replica_id inner join DR_CTE on DR_CTE.database_name = dcs.database_name where ar.replica_server_name = @@servername order by lag_in_seconds desc

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  • How can I join two simple home networks together using an ethernet cable?

    - by Ilia Jerebtsov
    I want to join two different home networks together like so: PC A1 PC A2 PC B1 PC B2 \ / \ / Gateway A <----- ethr. cable -----> Gateway B | | ADSL modem A ADSL modem B Both networks are of the basic residential type with identical configuration, with all PCs running Vista/7. The point is to temporarily join two apartments in a building for gaming and file sharing, and the holy grail would be: PCs on network A can access PCs on network B and vice-versa (file shares and gaming). Each network uses its own internet connection. Data between networks shouldn't take a trip through the internet (broadband upload speeds are severely capped) A network's internet access should continue working if the joining cable is disconnected with minimal configuration changes. How closely can this be achieved?

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  • Join us on our Journey to be #1 in SaaS!

    - by jessica.ebbelaar(at)oracle.com
    WHY ORACLE? Oracle is a robust organization that has proven to maintain growth and innovation at all levels with a constant evolving attitude. The main ingredient of Oracles success is the 105.000 talented employees who constantly amaze each other in building a better and more innovative organization. Oracle is a company where YOU can make a difference. What is OD? Oracle Direct is a state-of-the-art, multi-channel EMEA sales operation bringing to life the benefits of Oracle’s complete technology stack. It offers you the unique opportunity to work with the most talented and like-minded sales professionals in the industry.  You will have access to world class training and structured career development programmes allowing you to accelerate your Solution Sales career across a multitude of product lines and a choice of attractive locations. What positions are OD Hiring?   Oracle is on a journey to be the #1 SaaS vendor in EMEA.  Due to recent expansion and acquisitions within our Cloud Business, we are now growing our EMEA Cloud Applications Sales Group in Dublin. We have many exciting NEW opportunities across our CRM and HCM SaaS Sales teams. As a SaaS Sales Account Manager, you will proactively manage an assigned territory / vertical with responsibility for the full sales cycle. This role requires strong business development, solution selling, account management and closing skills. WHY ORACLE? Oracle is a robust organization that has proven to maintain growth and innovation at all levels with a constant evolving attitude. The main ingredient of Oracles success is the 105.000 talented employees who constantly amaze each other in building a better and more innovative organization. Oracle is a company where YOU can make a difference. What is OD? Oracle Direct is a state-of-the-art, multi-channel EMEA sales operation bringing to life the benefits of Oracle’s complete technology stack. It offers you the unique opportunity to work with the most talented and like-minded sales professionals in the industry.  You will have access to world class training and structured career development programmes allowing you to accelerate your Solution Sales career across a multitude of product lines and a choice of attractive locations. What positions are OD Hiring? Oracle is on a journey to be the #1 SaaS vendor in EMEA.  Due to recent expansion and acquisitions within our Cloud Business, we are now growing our EMEA Cloud Applications Sales Group in Dublin. We have many exciting NEW opportunities across our CRM and HCM SaaS Sales teams. As a SaaS Sales Account Manager, you will proactively manage an assigned territory / vertical with responsibility for the full sales cycle. This role requires strong business development, solution selling, account management and closing skills. What is the Business Development Group (BDG) The Business Development Group is the key entry point in Oracle for the future Sales and Management talent of the organisation. We are the Demand Generation engine for Oracle in EMEA. We provide revenue generating, quality sales pipeline to our Inside and Field Sales professionals as well as to our Channel Partners. Our current focus is to provide an agile and flexible service offering to our customers and stakeholders to meet ever changing business needs, whilst constantly striving to improve the customer experience, quality of our pipeline, market coverage and penetration. As a SaaS Business Development Consultant (BDC) you will be the first touch point with new customers. Your goal is to proactively identify and qualify business opportunities leading to revenue for Oracle. You will work closely with your Inside Sales colleagues who will progress your qualified pipeline and opportunities. Work for us Work for the only multi-pillar SaaS vendor in the market Be part of a FUN, fast paced and truly International sales team  Develop you solution sales EXPERTISE Drive your CAREER development within a structured and supportive environment The Profile You have a passion for selling cutting-edge technology You thrive in a fast paced and dynamic work environment where being the best is paramount Your priority is always the customer You live for a challenge and you love to win Join us on our Journey to be #1 in SaaS and be part of our Cloud Success Story! You will find more information about open roles here

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  • How can I join two simple home networks together using an ethernet cable?

    - by Ilia Jerebtsov
    I want to join two different home networks together like so: PC A1 PC A2 PC B1 PC B2 \ / \ / Gateway A <----- ethr. cable -----> Gateway B | | ADSL modem A ADSL modem B Both networks are of the basic residential type with identical configuration, with all PCs running Vista/7. The point is to temporarily join two apartments in a building for gaming and file sharing, and the holy grail would be: PCs on network A can access PCs on network B and vice-versa (file shares and gaming). Each network uses its own internet connection. Data between networks shouldn't take a trip through the internet (broadband upload speeds are severely capped) A network's internet access should continue working if the joining cable is disconnected with minimal configuration changes. How closely can this be achieved?

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  • How do I join two worksheets in Excel as I would in SQL?

    - by Joel Coehoorn
    I have two worksheets in two different Excel files. They both contain a list of names and addresses. One is a master list that includes other fields, and the other is a list that only includes name and address and an id column that was pared down by another office. I want to use the 2nd list to filter the first. I know how I could do this very easily with a database inner join, but I'm less clear on how to do this efficiently in Excel. How can join two worksheets in Excel? Bonus points for showing how to do outer joins as well, and I would greatly prefer konwing how to do this without needing a macro.

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  • Is it necessary for a Windows Server 2008 R2 to join a domain so that its IIS can communicate correctly?

    - by Jack
    I have a Windows Server 2008 R2 that is not join to any domain. I have developed an web application that will display the domain name and the username on the server itself. However, when I publish my web application to IIS, it always fail and display different types of error messages (because I change settings such as Enabled ASP.NET Impersonation, Disable Anonymous Authentication, Set Application Pool to Classic and so on) So, I was wondering if it is necessary for the Server to join in a domain so that I can reduce any unnecessary error message and be able to zoom into the correct direction?

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  • How to implement a left outer join in the Entity Framework.

    - by user206736
    I have the following SQL query:- select distinct * from dbo.Profiles profiles left join ProfileSettings pSet on pSet.ProfileKey = profiles.ProfileKey left join PlatformIdentities pId on pId.ProfileKey = profiles.Profilekey I need to convert it to a LinqToEntities expression. I have tried the following:- from profiles in _dbContext.ProfileSet let leftOuter = (from pSet in _dbContext.ProfileSettingSet select new { pSet.isInternal }).FirstOrDefault() select new { profiles.ProfileKey, Internal = leftOuter.isInternal, profiles.FirstName, profiles.LastName, profiles.EmailAddress, profiles.DateCreated, profiles.LastLoggedIn, }; The above query works fine because I haven't considered the third table "PlatformIdentities". Single left outer join works with what I have done above. How do I include PlatformIdentities (the 3rd table) ? I basically want to translate the SQL query I specified at the beginning of this post (which gives me exactly what I need) in to LinqToEntities. Thanks

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  • How do I do a join in ActiveRecord after records have been returned?

    - by Russ Bradberry
    I am using ActiveRecord in Rails 3 to pull data from two different tables in two different databases. These databases can not join on each other, but I have the need to do a simple join after-the-fact. I would like to preserve the relation so that I can chain it down the line. here is a simplified version of what I am doing browsers = Browser.all # <-- this is fairly small and can reside in memory events = Event.where(:row_date=>Date.today).select(:name, :browser_id) So as you can see, I want to join browsers in on the events relation, where browser_id should equal browsers.name. events is a relation and I can still add clauses to it down the line, so I dont want to run the query on the db just yet. How would I accomplish this?

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  • is NATURAL JOIN any better than SELECT FROM WHERE in terms of performance ?

    - by ashy_32bit
    Today I got into a debate with my project manager about Cartesian products. He says a 'natural join' is somehow much better than using 'select from where' because the later cause the db engine to internally perform a Cartesian product but the former uses another approach that prevents this. As far as I know, the natural join syntax is not any different in anyway than 'select from where' in terms of performance or meaning, I mean you can use either based on your taste. SELECT * FROM table1,table2 WHERE table1.id=table2.id SELECT * FROM table1 NATURAL JOIN table2 please elaborate about the first query causing a Cartesian product but the second one being somehow more smart

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  • How to select form input based on label inner HTML?

    - by Shane
    I have multiple forms that are dynamically created with different input names and id's. The only thing unique they will have is the inner HTML of the label. Is it possible to select the input via the label inner HTML with jQuery? Here is an example of one of my patient date of birth blocks, there are many and all unique except for innerHTML. <div class="iphorm-element-spacer iphorm-element-spacer-text iphorm_1_8-element-spacer"> <label for="iphorm_081a9e2e6b9c83d70496906bb4671904150cf4b43c0cb1_8">events=Object { mouseover=[1], mouseout=[1]}handle=function()data=Object { InFieldLabels={...}} Patient DOB <span class="iphorm-required">*</span> </label> <div class="iphorm-input-wrap iphorm-input-wrap-text iphorm_1_8-input-wrap"> <input id="iphorm_081a9e2e6b9c83d70496906bb4671904150cf4b43c0cb1_8" class="iphorm-element-text iphorm_1_8" type="text" value="" name="iphorm_1_8">events=Object { focus=[1], blur=[1], keydown=[1], more...}handle=function() </div> <div class="iphorm-errors-wrap iphorm-hidden"> </div> This is in a Wordpress Plugin and because we are building to allow employees to edit their sites (this is actually a Wordpress Network), we do not want to alter the plugin if possible. Note that the label "for" and the input "id" share the same dynamic key, so this might be a way to maybe get the id, but wanted to see if there is a shorter way of doing this.

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  • How to access parents' members from a inner class in WPF?

    - by black sensei
    Hello Experts! I'm trying to do scheduled operation let's say to check for user's credit left via web service call and update the user interface. i've tried with quartz.net to implement the scheduling bit.i created an inner class in the window class i need to update.That inner class has the method that calls the webservice and the result needs to be displayed back to the UI. here is an example of what i did. public partial class Window2 : Window { private int i; public Window2() { InitializeComponent(); } public class Myclass :IJob { public void Execute(JobExecutionContext context) { string result = doMyOperation(); //i'll like to call parent label member of name lblNotif //is something like parent.lblNotif.Content = result; //possible? } public string doMyOperation() { //calling the wermethod to retreive user's balance return result = service.GetUsersBalace(user); } } } Well the quartz bit is working and this post is not about quartz. here are my questions Question 1 : How is it possible to access Window2 controls, for instace lable lblNotif? Question 2 : If my thinking about this is wrong, what is done as best practice to solve my kind of problem, where an application need to do an operation let's say every 5mn and update the the UI. Question 3 : i at first tried to use the backgroundworker and i felt like i can't do the scheduling bit with it.Is that correct or i'm wrong. thanks for those who commented already and sorry for those who didn't get the meaning of my post.I hope this will be a bit clearer.Thanks for reading

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  • Another rookie question; How to implement Count() here?

    - by Camran
    I have this query: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id ORDER BY modify_date DESC I need to implement a count here, to just count all rows in combination with the JOINS you see. How should I do this? SELECT COUNT(mt.*, fordon.* etc) FROM ? // This method wont work Thanks

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  • Creating a dynamic linq query

    - by Bas
    I have the following query: from p in dataContext.Repository<IPerson>() join spp1 in dataContext.Repository<ISportsPerPerson>() on p.Id equals spp1.PersonId join s1 in dataContext.Repository<ISports>() on spp1.SportsId equals s1.Id join spp2 in dataContext.Repository<ISportsPerPerson>() on p.Id equals spp2.PersonId join s2 in dataContext.Repository<ISports>() on spp2.SportsId equals s2.Id where s1.Name == "Soccer" && s2.Name == "Tennis" select new { p.Id }; It selects all the person who play Soccer and Tennis. On runtime the user can select other tags to add to the query, for instance: "Hockey". now my question is, how could I dynamically add "Hockey" to the query? If "Hockey" is added to the query, it would look like this: from p in dataContext.Repository<IPerson>() join spp1 in dataContext.Repository<ISportsPerPerson>() on p.Id equals spp1.PersonId join s1 in dataContext.Repository<ISports>() on spp1.SportsId equals s1.Id join spp2 in dataContext.Repository<ISportsPerPerson>() on p.Id equals spp2.PersonId join s2 in dataContext.Repository<ISports>() on spp2.SportsId equals s2.Id join spp3 in dataContext.Repository<ISportsPerPerson>() on p.Id equals spp3.PersonId join s3 in dataContext.Repository<ISports>() on spp3.SportsId equals s3.Id where s1.Name == "Soccer" && s2.Name == "Tennis" && s3.Name == "Hockey" select new { p.Id }; It would be preferable if the query is build up dynamically like: private void queryTagBuilder(List<string> tags) { IDataContext dataContext = new LinqToSqlContext(new L2S.DataContext()); foreach(string tag in tags) { //Build the query? } } Anyone has an idea on how to set this up correctly? Thanks in advance!

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  • Grafting LINQ onto C# 2 library

    - by P Daddy
    I'm writing a data access layer. It will have C# 2 and C# 3 clients, so I'm compiling against the 2.0 framework. Although encouraging the use of stored procedures, I'm still trying to provide a fairly complete ability to perform ad-hoc queries. I have this working fairly well, already. For the convenience of C# 3 clients, I'm trying to provide as much compatibility with LINQ query syntax as I can. Jon Skeet noticed that LINQ query expressions are duck typed, so I don't have to have an IQueryable and IQueryProvider (or IEnumerable<T>) to use them. I just have to provide methods with the correct signatures. So I got Select, Where, OrderBy, OrderByDescending, ThenBy, and ThenByDescending working. Where I need help are with Join and GroupJoin. I've got them working, but only for one join. A brief compilable example of what I have is this: // .NET 2.0 doesn't define the Func<...> delegates, so let's define some workalikes delegate TResult FakeFunc<T, TResult>(T arg); delegate TResult FakeFunc<T1, T2, TResult>(T1 arg1, T2 arg2); abstract class Projection{ public static Condition operator==(Projection a, Projection b){ return new EqualsCondition(a, b); } public static Condition operator!=(Projection a, Projection b){ throw new NotImplementedException(); } } class ColumnProjection : Projection{ readonly Table table; readonly string columnName; public ColumnProjection(Table table, string columnName){ this.table = table; this.columnName = columnName; } } abstract class Condition{} class EqualsCondition : Condition{ readonly Projection a; readonly Projection b; public EqualsCondition(Projection a, Projection b){ this.a = a; this.b = b; } } class TableView{ readonly Table table; readonly Projection[] projections; public TableView(Table table, Projection[] projections){ this.table = table; this.projections = projections; } } class Table{ public Projection this[string columnName]{ get{return new ColumnProjection(this, columnName);} } public TableView Select(params Projection[] projections){ return new TableView(this, projections); } public TableView Select(FakeFunc<Table, Projection[]> projections){ return new TableView(this, projections(this)); } public Table Join(Table other, Condition condition){ return new JoinedTable(this, other, condition); } public TableView Join(Table inner, FakeFunc<Table, Projection> outerKeySelector, FakeFunc<Table, Projection> innerKeySelector, FakeFunc<Table, Table, Projection[]> resultSelector){ Table join = new JoinedTable(this, inner, new EqualsCondition(outerKeySelector(this), innerKeySelector(inner))); return join.Select(resultSelector(this, inner)); } } class JoinedTable : Table{ readonly Table left; readonly Table right; readonly Condition condition; public JoinedTable(Table left, Table right, Condition condition){ this.left = left; this.right = right; this.condition = condition; } } This allows me to use a fairly decent syntax in C# 2: Table table1 = new Table(); Table table2 = new Table(); TableView result = table1 .Join(table2, table1["ID"] == table2["ID"]) .Select(table1["ID"], table2["Description"]); But an even nicer syntax in C# 3: TableView result = from t1 in table1 join t2 in table2 on t1["ID"] equals t2["ID"] select new[]{t1["ID"], t2["Description"]}; This works well and gives me identical results to the first case. The problem is if I want to join in a third table. TableView result = from t1 in table1 join t2 in table2 on t1["ID"] equals t2["ID"] join t3 in table3 on t1["ID"] equals t3["ID"] select new[]{t1["ID"], t2["Description"], t3["Foo"]}; Now I get an error (Cannot implicitly convert type 'AnonymousType#1' to 'Projection[]'), presumably because the second join is trying to join the third table to an anonymous type containing the first two tables. This anonymous type, of course, doesn't have a Join method. Any hints on how I can do this?

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  • How to eliminate NULL fields in TSQL

    - by salvationishere
    I am developing a TSQL query in SSMS 2008 R2. I am trying to develop this query to identify one record / client. Because some of these values are NULL, I am currently doing LEFT JOINS on most of the tables. But the problem with the LEFT JOINs is that now I get 1 record for some clients. But if I change this to INNER JOINs then some clients are excluded entirely because they have NULL values for these columns. How do I limit the query result to just one record / client regardless of NULL values? And if there are non-NULL values then I want it to choose the record with non-NULL values. Here is some of my current output: group_profile_id profile_name license_number is_accepting is_accepting_placement managing_office region vendor_name vendor_id applicant_type Office Address status_description Cert Date2 race ethnicity_desc religion 9CD932F1-6BE1-4F80-AB81-0CE32C565BCF Atreides Foster Home 1 Atreides1 1 Yes Manchester, NH Gulf Atlantic Atreides1 00000007 Treatment Foster Home 4042 Arrakis Avenue, Springfield, VT 05156 Open/Re-opened 2011-06-01 00:00:00.000 NULL NULL NULL DCE354D5-A7CC-409F-B5A3-89BF664B7718 Averitte, Leon and Sandra 00000044 1 Yes Birmingham, AL Gulf Atlantic AL Averitte, Leon and Sandra 00000044 Treatment Foster Home 3816 5th Avenue, Bessemer, AL 35020, (205)482-4307 Open/Re-opened 2011-08-05 00:00:00.000 NULL NULL NULL DCE354D5-A7CC-409F-B5A3-89BF664B7718 Averitte, Leon and Sandra 00000044 1 Yes Birmingham, AL Gulf Atlantic AL Averitte, Leon and Sandra 00000044 Treatment Foster Home 3816 5th Avenue, Bessemer, AL 35020, (205)482-4307 Open/Re-opened 2011-08-05 00:00:00.000 Caucasian/White Non Hispanic NULL AD02A43C-6F38-4F35-8C9E-E12422690BFB Bass, Matthew and Sarah 00000076 1 Yes Jacks on, MS Central Gulf Coast MS Bass, Matthew and Sarah 00000076 Treatment Foster Home 506 Eagelwood Drive, Florence, MS 39073, (601)665-7169 Open/Re-opened 2011-04-01 00:00:00.000 NULL NULL NULL AD02A43C-6F38-4F35-8C9E-E12422690BFB Bass, Matthew and Sarah 00000076 1 Yes Jackson, MS Central Gulf Coast MS Bass, Matthew and Sarah 00000076 Treatment Foster Home 506 Eagelwood Drive, Florence, MS 39073, (601)665-7169 Open/Re-opened 2011-04-01 00:00:00.000 Caucasian/White NULL Baptist You can see that both Averitte and Bass profile names have one record with NULL race, ethnicity, religion. How do I eliminate these rows (rows 2 and 4)? Here is my query currently: select distinct gp.group_profile_id, gp.profile_name, gp.license_number, gp.is_accepting, case when gp.is_accepting = 1 then 'Yes' when gp.is_accepting = 0 then 'No ' end as is_accepting_placement, mo.profile_name as managing_office, regions.[region_description] as region, pv.vendor_name, pv.id as vendor_id, at.description as applicant_type, dbo.GetGroupAddress(gp.group_profile_id, null, 0) as [Office Address], gsv.status_description, ri.[description] as race, ethnicity.description as ethnicity_desc, religion.description as religion from group_profile gp With (NoLock) --Office Information inner join group_profile_type gpt With (NoLock) on gp.group_profile_type_id = gpt.group_profile_type_id and gpt.type_code = 'FOSTERHOME' and gp.agency_id = @agency_id and gp.is_deleted = 0 inner join group_profile mo With (NoLock) on gp.managing_office_id = mo.group_profile_id left outer join payor_vendor pv With (NoLock) on gp.payor_vendor_id = pv.payor_vendor_id left outer join applicant_type at With (NoLock) on gp.applicant_type_id = at.applicant_type_id and at.is_foster_home = 1 inner join group_status_view gsv With (NoLock) on gp.group_profile_id = gsv.group_profile_id and gsv.status_value = 'OPEN' and gsv.effective_date = (Select max(b.effective_date) from group_status_view b With (NoLock) where gp.group_profile_id = b.group_profile_id) left outer join regions With (NoLock) on isnull(mo.regions_id, gp.regions_id) = regions.regions_id left join enrollment en on en.group_profile_id = gp.group_profile_id join event_log el on el.event_log_id = en.event_log_id left join people client on client.people_id = el.people_id left join race With (NoLock) on el.people_id = race.people_id left join group_profile_race gpr with (nolock) on gpr.race_info_id = race.race_info_id left join race_info ri with (nolock) on ri.race_info_id = gpr.race_info_id left join ethnicity With(NoLock) On client.ethnicity = ethnicity.ethnicity_id left join religion on client.religion = religion.religion_id

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  • Mysql - help me optimize this query (improved question)

    - by sandeepan-nath
    About the system: - There are tutors who create classes and packs - A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is the concerned query SELECT SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) AS key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) AS key_2_total_matches, COUNT(DISTINCT( od.id_od )) AS tutor_popularity, CASE WHEN ( IF(( wc.id_wc > 0 ), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date > '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'classes_published', CASE WHEN ( IF(( lp.id_lp > 0 ), ( lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'packs_published', td . *, u . * FROM tutor_details AS td JOIN users AS u ON u.id_user = td.id_user LEFT JOIN learning_packs_tag_relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN learning_packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN learning_packs_categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN learning_packs_categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN learning_pack_content AS lpct ON ( lp.id_lp = lpct.id_lp ) LEFT JOIN webclasses_tag_relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN webclasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN learning_packs_categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN learning_packs_categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN order_details AS od ON td.id_tutor = od.id_author LEFT JOIN orders AS o ON od.id_order = o.id_order LEFT JOIN tutors_tag_relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN tags AS t ON ( t.id_tag = ttagrels.id_tag ) OR ( t.id_tag = lptagrels.id_tag ) OR ( t.id_tag = wtagrels.id_tag ) WHERE ( u.country = 'IE' OR u.country IN ( 'INT' ) ) AND CASE WHEN ( ( t.id_tag = lptagrels.id_tag ) AND ( lp.id_lp 0 ) ) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( ( t.id_tag = wtagrels.id_tag ) AND ( wc.id_wc 0 ) ) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( od.id_od 0 ) THEN od.id_author = td.id_tutor AND o.order_status = 'paid' AND CASE WHEN ( od.id_wc 0 ) THEN od.can_attend_class = 1 ELSE 1 END ELSE 1 END GROUP BY td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 ORDER BY tutor_popularity DESC, u.surname ASC, u.name ASC LIMIT 0, 20 The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query rises alarmingly for heavier data and for the current data I have it is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed. The tag field of tags table is indexed. Is there something faulty with the query? What can be the reason behind 20+ seconds of execution time? How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. The explain query output:- Please see this screenshot - http://www.test.examvillage.com/Explain_query.jpg

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  • create XSD for element with same name

    - by aaa
    how to make xsd for element with same names that only identifyed by attribute value example :- <a> <b n="structure one"> <c n="inner element 1"/> <c n="inner element 2"/> <c n="inner element 3"/> </b> <b n="structure two"> <c n="inner element 1 for structure two"/> <c n="inner element 2 for structure two"/> <c n="inner element 3 for structure two"/> </b> </a> notice that from the XML i have to mention specific value that belong to the inner element same for structure

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  • Speed up this query joining to a table multiple times

    - by Mongus Pong
    Hi, I have this query that (stripped right down) goes something like this : SELECT [Person_PrimaryContact].[LegalName], [Person_Manager].[LegalName], [Person_Owner].[LegalName], [Person_ProspectOwner].[LegalName], [Person_ProspectBDM].[LegalName], [Person_ProspectFE].[LegalName], [Person_Signatory].[LegalName] FROM [Cache] LEFT JOIN [dbo].[Person] AS [Person_Owner] WITH (NOLOCK) ON [Person_Owner].[PersonID] = [Cache].[ClientOwnerID] LEFT JOIN [dbo].[Person] AS [Person_Manager] WITH (NOLOCK) ON [Person_Manager].[PersonID] = [Cache].[ClientManagerID] LEFT JOIN [dbo].[Person] AS [Person_Signatory] WITH (NOLOCK) ON [Person_Signatory].[PersonID] = [Cache].[ClientSignatoryID] LEFT JOIN [dbo].[Person] AS [Person_PrimaryContact] WITH (NOLOCK) ON [Person_PrimaryContact].[PersonID] = [Cache].[PrimaryContactID] LEFT JOIN [dbo].[Person] AS [Person_ProspectOwner] WITH (NOLOCK) ON [Person_ProspectOwner].[PersonID] = [Cache].[ProspectOwnerID] LEFT JOIN [dbo].[Person] AS [Person_ProspectBDM] WITH (NOLOCK) ON [Person_ProspectBDM].[PersonID] = [Cache].[ProspectBDMID] LEFT JOIN [dbo].[Person] AS [Person_ProspectFE] WITH (NOLOCK) ON [Person_ProspectFE].[PersonID] = [Cache].[ProspectFEID] Person is a huge table and each join to it has a pretty significant hit in the execution plan. Is there anyway I can adjust this query so that I am only linking to it once, or at least get SQL Server to scan through it only once?

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  • Why people define class, trait, object inside another object in Scala?

    - by Zwcat
    Ok, I'll explain why I ask this question. I begin to read Lift 2.2 source code these days. In Lift, I found that, define inner class and inner trait are very heavily used. object Menu has 2 inner traits and 4 inner classes. object Loc has 18 inner classes, 5 inner traits, 7 inner objects. There're tons of codes write like this. I wanna to know why the author write it like this. Is it because it's the author's personal taste or a powerful use of language feature?

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  • jQuery Nested Droppables

    - by John
    I have a nested set of jQuery droppables...one outer droppable that encompasses most of the page and an a set of nested inner droppables on the page. The functionality I want is: If a draggable is dropped outside of any of the inner droppables it should be accepted by the outer droppable. If a draggable is dropped onto any of the inner droppables it should NOT be accepted by the outer droppable, regardless of whether the inner droppable accepts the draggable. So that would be easy if I could guarantee 1+ inner droppables would accept the draggable, because the greedy attribute would make sure it would only get triggered once. Unfortunately the majority of the time the inner droppable will also reject the draggable, meaning the greedy option doesn't really help. Summary: The basic functionality is a set of valid/invalid inner droppables to accept the draggable, but when you toss the draggable outside any of the draggables it gets destroyed by the outer droppable. What's the best way of doing this?

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  • SQL SERVER – Example of Performance Tuning for Advanced Users with DB Optimizer

    - by Pinal Dave
    Performance tuning is such a subject that everyone wants to master it. In beginning everybody is at a novice level and spend lots of time learning how to master the art of performance tuning. However, as we progress further the tuning of the system keeps on getting very difficult. I have understood in my early career there should be no need of ego in the technology field. There are always better solutions and better ideas out there and we should not resist them. Instead of resisting the change and new wave I personally adopt it. Here is a similar example, as I personally progress to the master level of performance tuning, I face that it is getting harder to come up with optimal solutions. In such scenarios I rely on various tools to teach me how I can do things better. Once I learn about tools, I am often able to come up with better solutions when I face the similar situation next time. A few days ago I had received a query where the user wanted to tune it further to get the maximum out of the performance. I have re-written the similar query with the help of AdventureWorks sample database. SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID; User had similar query to above query was used in very critical report and wanted to get best out of the query. When I looked at the query – here were my initial thoughts Use only column in the select statements as much as you want in the application Let us look at the query pattern and data workload and find out the optimal index for it Before I give further solutions I was told by the user that they need all the columns from all the tables and creating index was not allowed in their system. He can only re-write queries or use hints to further tune this query. Now I was in the constraint box – I believe * was not a great idea but if they wanted all the columns, I believe we can’t do much besides using *. Additionally, if I cannot create a further index, I must come up with some creative way to write this query. I personally do not like to use hints in my application but there are cases when hints work out magically and gives optimal solutions. Finally, I decided to use Embarcadero’s DB Optimizer. It is a fantastic tool and very helpful when it is about performance tuning. I have previously explained how it works over here. First open DBOptimizer and open Tuning Job from File >> New >> Tuning Job. Once you open DBOptimizer Tuning Job follow the various steps indicates in the following diagram. Essentially we will take our original script and will paste that into Step 1: New SQL Text and right after that we will enable Step 2 for Generating Various cases, Step 3 for Detailed Analysis and Step 4 for Executing each generated case. Finally we will click on Analysis in Step 5 which will generate the report detailed analysis in the result pan. The detailed pan looks like. It generates various cases of T-SQL based on the original query. It applies various hints and available hints to the query and generate various execution plans of the query and displays them in the resultant. You can clearly notice that original query had a cost of 0.0841 and logical reads about 607 pages. Whereas various options which are just following it has different execution cost as well logical read. There are few cases where we have higher logical read and there are few cases where as we have very low logical read. If we pay attention the very next row to original query have Merge_Join_Query in description and have lowest execution cost value of 0.044 and have lowest Logical Reads of 29. This row contains the query which is the most optimal re-write of the original query. Let us double click over it. Here is the query: SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID OPTION (MERGE JOIN) If you notice above query have additional hint of Merge Join. With the help of this Merge Join query hint this query is now performing much better than before. The entire process takes less than 60 seconds. Please note that it the join hint Merge Join was optimal for this query but it is not necessary that the same hint will be helpful in all the queries. Additionally, if the workload or data pattern changes the query hint of merge join may be no more optimal join. In that case, we will have to redo the entire exercise once again. This is the reason I do not like to use hints in my queries and I discourage all of my users to use the same. However, if you look at this example, this is a great case where hints are optimizing the performance of the query. It is humanly not possible to test out various query hints and index options with the query to figure out which is the most optimal solution. Sometimes, we need to depend on the efficiency tools like DB Optimizer to guide us the way and select the best option from the suggestion provided. Let me know what you think of this article as well your experience with DB Optimizer. Please leave a comment. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Partition Wise Joins

    - by jean-pierre.dijcks
    Some say they are the holy grail of parallel computing and PWJ is the basis for a shared nothing system and the only join method that is available on a shared nothing system (yes this is oversimplified!). The magic in Oracle is of course that is one of many ways to join data. And yes, this is the old flexibility vs. simplicity discussion all over, so I won't go there... the point is that what you must do in a shared nothing system, you can do in Oracle with the same speed and methods. The Theory A partition wise join is a join between (for simplicity) two tables that are partitioned on the same column with the same partitioning scheme. In shared nothing this is effectively hard partitioning locating data on a specific node / storage combo. In Oracle is is logical partitioning. If you now join the two tables on that partitioned column you can break up the join in smaller joins exactly along the partitions in the data. Since they are partitioned (grouped) into the same buckets, all values required to do the join live in the equivalent bucket on either sides. No need to talk to anyone else, no need to redistribute data to anyone else... in short, the optimal join method for parallel processing of two large data sets. PWJ's in Oracle Since we do not hard partition the data across nodes in Oracle we use the Partitioning option to the database to create the buckets, then set the Degree of Parallelism (or run Auto DOP - see here) and get our PWJs. The main questions always asked are: How many partitions should I create? What should my DOP be? In a shared nothing system the answer is of course, as many partitions as there are nodes which will be your DOP. In Oracle we do want you to look at the workload and concurrency, and once you know that to understand the following rules of thumb. Within Oracle we have more ways of joining of data, so it is important to understand some of the PWJ ideas and what it means if you have an uneven distribution across processes. Assume we have a simple scenario where we partition the data on a hash key resulting in 4 hash partitions (H1 -H4). We have 2 parallel processes that have been tasked with reading these partitions (P1 - P2). The work is evenly divided assuming the partitions are the same size and we can scan this in time t1 as shown below. Now assume that we have changed the system and have a 5th partition but still have our 2 workers P1 and P2. The time it takes is actually 50% more assuming the 5th partition has the same size as the original H1 - H4 partitions. In other words to scan these 5 partitions, the time t2 it takes is not 1/5th more expensive, it is a lot more expensive and some other join plans may now start to look exciting to the optimizer. Just to post the disclaimer, it is not as simple as I state it here, but you get the idea on how much more expensive this plan may now look... Based on this little example there are a few rules of thumb to follow to get the partition wise joins. First, choose a DOP that is a factor of two (2). So always choose something like 2, 4, 8, 16, 32 and so on... Second, choose a number of partitions that is larger or equal to 2* DOP. Third, make sure the number of partitions is divisible through 2 without orphans. This is also known as an even number... Fourth, choose a stable partition count strategy, which is typically hash, which can be a sub partitioning strategy rather than the main strategy (range - hash is a popular one). Fifth, make sure you do this on the join key between the two large tables you want to join (and this should be the obvious one...). Translating this into an example: DOP = 8 (determined based on concurrency or by using Auto DOP with a cap due to concurrency) says that the number of partitions >= 16. Number of hash (sub) partitions = 32, which gives each process four partitions to work on. This number is somewhat arbitrary and depends on your data and system. In this case my main reasoning is that if you get more room on the box you can easily move the DOP for the query to 16 without repartitioning... and of course it makes for no leftovers on the table... And yes, we recommend up-to-date statistics. And before you start complaining, do read this post on a cool way to do stats in 11.

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