Search Results

Search found 13454 results on 539 pages for 'left'.

Page 53/539 | < Previous Page | 49 50 51 52 53 54 55 56 57 58 59 60  | Next Page >

  • Getting element position in IE versus other browsers

    - by Channel72
    We all know IE6 is difficult. But there seems to be disparate behavior in positioning in later versions of IE as well, when compared with Firefox or other browsers. I have a simple pair of javascript functions which finds the position of an element, and then displays another element in relation to the first element. The idea is to get the second element, which is somewhat larger, to appear in front of the first element when the mouse hovers over it. It works fine, except on all versions of Internet Explorer, the position of the second element appears different than in Firefox. The code to get the position of an element is: function getPosition(e) { var left = 0; var top = 0; while (e.offsetParent) { left += e.offsetLeft; top += e.offsetTop; e = e.offsetParent; } left += e.offsetLeft; top += e.offsetTop; return {x:left, y:top}; } And the actual rollover display code is: var pos = getPosition(elem1); elem2.style.top = pos.y - 8; elem2.style.left = pos.x - 6; In Firefox, elem2 appears directly over elem1, as I want it to. But in IE7 or IE8 it appears way off. What is the reason this occurs, and is there a way to fix it?

    Read the article

  • Problems with sticky footer html css

    - by CJava
    I'm having trouble making a sticky footer, whatever I do the code completely messes up and re-arranged positioning of other elements. I'm using multiple div elements. I have tried pretty much most tutorials on stickying footers online like http://www.cssstickyfooter.com/using-sticky-footer-code.html Help would be much appreciated. Thanks a lot! html: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta name="generator" content="HTML Tidy for Linux (vers 25 March 2009), see www.w3.org"> <title>Southend-on-Sea Independant Tourist Guide</title> <!--Attached CSS to keep constant throughout site--> <link rel="stylesheet" type="text/css" href="style.css"> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <meta name="description" content="An independant tourist guide on Southend-on-Sea"> <meta name="keywords" content="southend, southend-on-sea, tourist guide, tourist, independant"> <meta name="author" content="Callum Stevens"> <link rel="shortcut icon" type="image/x-icon" href="/favicon.ico"><!--[if !IE 7]> <style type="text/css"> #wrap {display:table;height:100%} </style> <![endif]--> <link rel="stylesheet" type="text/css" href="style.css"> <link rel="stylesheet" type="text/css" href="navigation.css"> </head> <body> <div id="container"> <div id="content"> <div id="header"> <table width="200" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td><img src="southendpiersept2006edit.jpg" width="700" height="389" alt="southend pier site logo"></td> </tr> </table> </div> <div id="navigation"> <ul> <li class="home"><a href="index.htm">Home</a></li> <li class="places"><a href="places.htm">Places to go</a></li> <li class="things"><a href="things.htm">Things to do</a></li> <li class="where"><a href="where.htm">Where to stay</a></li> <li class="getting"><a href="getting.htm">Getting&lt; here/a&gt;</a></li> <li class="about"><a href="getting.htm"></a><a href="getting.htm"></a><a href="about.htm">About the town</a></li> <li class="contact"><a href="contact.htm">Contact us</a></li> </ul> <table width="700" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td></td> </tr> </table> </div> <br> <br> <h1>Southend-On-Sea</h1> <br> <h2>Welcome to Southend-On-Sea Tourist Information Site. You're #1 stop for finding out about Southend!</h2> <br> <h3>This site aims to help you in getting here, finding accomodation, and letting you know whats going on.</h3> <p>paragraph</p> <p id="p2">paragraph2</p> </div> </div> <div id="footer"></div> </body> </html> style.css: html, body { margin: 0px; padding: 0px; text-align:center } body{ background: url(bg.jpg) repeat-x;} #content { text-align:center width:67%; } h2 { text-transform: capitalize;} navigation.css #navigation ul { width: 700px; height: 50px; position: absolute; /** Places image at the top of the page **/ top: 389px; /** Determines the height from the top of the page **/ left: 15.3%; /** Determines the width from the left of the page **/ background: url(menu.jpg) no-repeat 0 0; list-style: none; margin: 0; padding: 0; } #navigation li { display: inline; } #navigation li a:link, #navigation li a:visited { border: none; width: 100px; height: 50px; display: block; position: absolute; top: 0; text-indent: -7000px; outline: none; } #navigation li.home a:link, #navigation li.home a:visited { left: 0; } #navigation li.places a:link, #navigation li.places a:visited { left: 100px } #navigation li.things a:link, #navigation li.things a:visited { left: 200px } #navigation li.where a:link, #navigation li.where a:visited { left: 300px } #navigation li.getting a:link, #navigation li.getting a:visited { left: 400px } #navigation li.about a:link, #navigation li.about a:visited { left: 500px } #navigation li.contact a:link, #navigation li.contact a:visited { left: 600px } #navigation li.home a:hover { background: url(menu.jpg) no-repeat 0 -50px; } #navigation li.places a:hover { background: url(menu.jpg) no-repeat -100px -50px; } #navigation li.things a:hover { background: url(menu.jpg) no-repeat -200px -50px; } #navigation li.where a:hover { background: url(menu.jpg) no-repeat -300px -50px; } #navigation li.getting a:hover { background: url(menu.jpg) no-repeat -400px -50px; } #navigation li.about a:hover { background: url(menu.jpg) no-repeat -500px -50px; } #navigation li.contact a:hover { background: url(menu.jpg) no-repeat -600px -50px; }

    Read the article

  • iPhone/Objective-C struct question my own CGRectZero

    - by Mark
    I am designing a Padding struct as follows: /* Padding. */ struct CGPadding { CGFloat left; CGFloat top; CGFloat right; CGFloat bottom; }; typedef struct CGPadding CGPadding; CG_INLINE CGPadding CGPaddingMake(CGFloat left, CGFloat top, CGFloat right, CGFloat bottom) { CGPadding p; p.left = left; p.top = top; p.right = right; p.bottom = bottom; return p; } This all works perfectly well, the problem is how can I create a const CGPadding CGPaddingZero? If I do like this: const CGPadding CGPaddingZero = (CGPadding){0.0, 0.0, 0.0, 0.0}; It doesnt work. So what am I doing wrong?

    Read the article

  • Multiple Table Join in Linq C# Dynamically

    - by kmkperumal
    I have 3 data table a,b,c In this I need to write Join Query Dynamically using linQ. The Selecting columns given by customer and Condition columns also given customer at run time. So i need to create Querys dynamically.Please check below example.Because i dont which table they want and which column also For example Select a.c1,a.c2,b.c1,b.c2 From a Left Join b on a.c1=b.c1 2.Select c.c1,c.c2,a.c1,a.c2 From c Left Join a on c.c3=a.c1 3.Select a.c1,a.c2,b.c1,b.c2,c.c1,c.c2 From a Left Join b on a.c2=b.c2 Left join c on c.c1=a.c1 Like i need create different set of query's. Please help me on this.

    Read the article

  • How can I css for List/grid in div with border?

    - by Saidul Haque Nayan
    I want to create a list table in DIV with border. When more content of width of a column then line break and border increase but other column border not increase. see the example: Untitled Document /list/ .list_container{ float:left; width: 550px; margin-bottom:10px; font-family: vardana; } .list_row{ float:left; width: 548px; border-bottom:1px #9F9F9F solid; } .list_row:hover{ background-color:#CCCCCC; } .list_rowHeader{ float:left; width: 548px; border-bottom:1px #9F9F9F solid; border-top:1px #9F9F9F solid; font-weight: bold; background-color: #FF0000; color: #FFFFFF; } .list_column{ float:left; padding: 3px; border-left: 1px #9F9F9F solid; } .list_columnLast{ float:left; padding: 3px; border-left: 1px #9F9F9F solid; border-right: 1px #9F9F9F solid; } .even{ background-color:#E0E0E0!important;} .odd{ background-color:#FFFFFF!important;} </style> </head> <body> <div class="list_container" > <div class="list_rowHeader" > <div class="list_column" style="width: 250px;">Name</div> <div class="list_column" style="width: 96px;"> Bid Amount</div> <div class="list_columnLast" style="width: 180px;"> Email </div> </div> <div class="list_row even" > <div class="list_column" style="width: 250px;">Saidul Haque</div> <div class="list_column" style="width: 96px;"> 2131231</div> <div class="list_columnLast" style="width: 180px;"> [email protected]</div> </div> <div class="list_row odd" > <div class="list_column" style="width: 250px;">Saidul Haque, Sonargaon, Bangladesh Dhaka, </div> <div class="list_column" style="width: 96px;"> 2131231</div> <div class="list_columnLast" style="width: 180px;"> [email protected]</div> </div> <div class="list_row even" > <div class="list_column" style="width: 250px;">Saidul Haque</div> <div class="list_column" style="width: 96px;"> 2131231</div> <div class="list_columnLast" style="width: 180px;"> [email protected]</div> </div> </div> </body> Any body solve this problem?

    Read the article

  • Which will be the best query OR there is an another one?

    - by serhan
    SELECT k.id,k.adsoyad, COUNT(DISTINCT(e.id)) as iletisimbilgisisay, COUNT(DISTINCT(f.id)) AS ilangonderensay, COUNT(DISTINCT(g.id)) AS emlaksahibisay, isNULL(MAX(eb.yonetici_kisi),0) AS yoneticiid FROM dbo.kisiler k LEFT OUTER JOIN dbo.emlaklar e ON e.iletisimbilgisi=k.id LEFT OUTER JOIN dbo.emlaklar f ON f.ilangonderen=k.id LEFT OUTER JOIN dbo.emlaklar g ON g.emlaksahibi=k.id LEFT OUTER JOIN dbo.emlakcibilgileri eb ON eb.yonetici_kisi=k.id GROUP BY k.id,k.adsoyad ORDER BY yoneticiid DESC, iletisimbilgisisay DESC, ilangonderensay DESC total execution time (above) 28 SELECT id,adsoyad, (select COUNT(id) FROM dbo.emlaklar WHERE iletisimbilgisi=k.id) AS iletisimbilgisisay, (select COUNT(id) FROM dbo.emlaklar WHERE emlaksahibi=k.id) AS emlaksahibisay, (select COUNT(id) FROM dbo.emlaklar WHERE ilangonderen=k.id) AS ilangonderensay, (Select isNULL(MAX(id),0) FROM dbo.emlakcibilgileri WHERE yonetici_kisi=k.id) AS yoneticiid FROM dbo.kisiler k total execution time 4 my tables are emlaklar: id int, ilangonderen int,iletisimbilgisi int,emlaksahibi int kisiler: id int,kisiadi emlakcibilgileri: id int,yonetici_kisi int,firma and ilangonderen,iletisimbilgisi,emlaksahibi,yonetici_kisi => kisiler.id

    Read the article

  • More efficient comparison of numbers

    - by Pez Cuckow
    I have an array which is part of a small JS game I am working on I need to check (as often as reasonable) that each of the elements in the array haven't left the "stage" or "playground", so I can remove them and save the script load I have coded the below and was wondering if anyone knew a faster/more efficient way to calculate this. This is run every 50ms (it deals with the movement). Where bots[i][1] is movement in X and bots[i][2] is movement in Y (mutually exclusive). for (var i in bots) { var left = parseInt($("#" + i).css("left")); var top = parseInt($("#" + i).css("top")); var nextleft = left + bots[i][1]; var nexttop = top + bots[i][2]; if(bots[i][1]>0&&nextleft>=PLAYGROUND_WIDTH) { remove_bot(i); } else if(bots[i][1]<0&&nextleft<=-GRID_SIZE) { remove_bot(i); } else if(bots[i][2]>0&&nexttop>=PLAYGROUND_HEIGHT) { remove_bot(i); } else if(bots[i][2]<0&&nexttop<=-GRID_SIZE) { remove_bot(i); } else { //alert(nextleft + ":" + nexttop); $("#" + i).css("left", ""+(nextleft)+"px"); $("#" + i).css("top", ""+(nexttop)+"px"); } } On a similar note the remove_bot(i); function is as below, is this correct (I can't splice as it changes all the ID's of the elements in the array. function remove_bot(i) { $("#" + i).remove(); bots[i] = false; } Many thanks for any advice given!

    Read the article

  • SQL Server CTE referred in self joins slow

    - by Kharlos Dominguez
    Hello, I have written a table-valued UDF that starts by a CTE to return a subset of the rows from a large table. There are several joins in the CTE. A couple of inner and one left join to other tables, which don't contain a lot of rows. The CTE has a where clause that returns the rows within a date range, in order to return only the rows needed. I'm then referencing this CTE in 4 self left joins, in order to build subtotals using different criterias. The query is quite complex but here is a simplified pseudo-version of it WITH DataCTE as ( SELECT [columns] FROM table INNER JOIN table2 ON [...] INNER JOIN table3 ON [...] LEFT JOIN table3 ON [...] ) SELECT [aggregates_columns of each subset] FROM DataCTE Main LEFT JOIN DataCTE BananasSubset ON [...] AND Product = 'Bananas' AND Quality = 100 LEFT JOIN DataCTE DamagedBananasSubset ON [...] AND Product = 'Bananas' AND Quality < 20 LEFT JOIN DataCTE MangosSubset ON [...] GROUP BY [ I have the feeling that SQL Server gets confused and calls the CTE for each self join, which seems confirmed by looking at the execution plan, although I confess not being an expert at reading those. I would have assumed SQL Server to be smart enough to only perform the data retrieval from the CTE only once, rather than do it several times. I have tried the same approach but rather than using a CTE to get the subset of the data, I used the same select query as in the CTE, but made it output to a temp table instead. The version referring the CTE version takes 40 seconds. The version referring the temp table takes between 1 and 2 seconds. Why isn't SQL Server smart enough to keep the CTE results in memory? I like CTEs, especially in this case as my UDF is a table-valued one, so it allowed me to keep everything in a single statement. To use a temp table, I would need to write a multi-statement table valued UDF, which I find a slightly less elegant solution. Did some of you had this kind of performance issues with CTE, and if so, how did you get them sorted? Thanks, Kharlos

    Read the article

  • 2-col layout, one col scrolls vertical, other is fixed. Both scroll horizontal.

    - by Victor P
    Im trying to do a 2 column layout where the left column is very long vertically, and the right column is very long horizontally. When I scroll vertically, I want to move up and down the left column while the right one stays fixed. When I scroll horizontally, both columns move left-right (normal behaviour) I hope this drawing explain it more (sorry for the bad quality): Is this possible to do using only css? If not, how can I do it with javascript? Thanks

    Read the article

  • are these css classes names good?

    - by metal-gear-solid
    See section /* Common Classes */ of this page. http://webdesign.about.com/od/css/a/master_stylesht_2.htm are these css classes good, to use in any project? in terms of semantic? /* Common Classes */ .clear { clear: both; } .floatLeft { float: left; } .floatRight { float: right; } .textLeft { text-align: left; } .textRight { text-align: right; } .textCenter { text-align: center; } .textJustify { text-align: justify; } .blockCenter { display: block; margin-left: auto; margin-right: auto; } /* remember to set width */ .bold { font-weight: bold; } .italic { font-style: italic; } .underline { text-decoration: underline; } .noindent { margin-left: 0; padding-left: 0; } .nomargin { margin: 0; } .nopadding { padding: 0; } .nobullet { list-style: none; list-style-image: none; }

    Read the article

  • Trying to fadein divs in a sequence, over time, using JQuery

    - by user346602
    Hi, I'm trying to figure out how to make 4 images fade in sequentially when the page loads. The following is my (amateurish) code: Here is the HTML: <div id="outercorners"> <img id="corner1" src="images/corner1.gif" width="6" height="6" alt=""/> <img id="corner2" src="images/corner2.gif" width="6" height="6" alt=""/> <img id="corner3" src="images/corner3.gif" width="6" height="6" alt=""/> <img id="corner4" src="images/corner4.gif" width="6" height="6" alt=""/> </div><!-- end #outercorners--> Here is the JQuery: $(document).ready(function() { $("#corner1").fadeIn("2000", function(){ $("#corner3").fadeIn("4000", function(){ $("#corner2").fadeIn("6000", function(){ $("#corner4").fadeIn("8000", function(){ }); }); }); }); Here is the css: #outercorners { position: fixed; top:186px; left:186px; width:558px; height:372px; } #corner1 { position: fixed; top:186px; left:186px; display: none; } #corner2 { position: fixed; top:186px; left:744px; display: none; } #corner3 { position: fixed; top:558px; left:744px; display: none; } #corner4 { position: fixed; top:558px; left:186px; display: none; } They seem to just wink at me, rather than fade in in the order I've ascribed to them. Should I be using the queue() function? And, if so, how would I implement it in this case? Thank you for any assistance.

    Read the article

  • What data type should I use for my texture coordinates in OpenGL ES?

    - by Matthew Chen
    I notice that the default data type for texture coordinates in the OpenGL docs is GLfloat, but much of the sample code I see written by experienced iphone developers uses GLshort or GLbyte. Is this an optimization? GLfloat vertices[] = { // Upper left x1, y2, // Lower left x1, y1, // Lower right x2, y1, // Upper right x2, y2, }; glTexCoordPointer(2, GL_FLOAT, 0, iconSTs); vs. GLbyte vertices[] = { // Upper left x1, y2, // Lower left x1, y1, // Lower right x2, y1, // Upper right x2, y2, }; glTexCoordPointer(2, GL_BYTE, 0, iconSTs);

    Read the article

  • Python: Why Does a Method Behave Differently with an Added Parameter?

    - by SteveStifler
    I have a method in a Pygame Sprite subclass, defined as such: def walk(self): """move across screen""" displacement = self.rect.move((self.move, 0)) if self.rect.left < self.area.left or self.rect.right > self.area.right: self.move = -self.move displacement = self.rect.move((self.move, 0)) self.rect = displacement I modified it, adding a parameter speed_x, and now the program is broken. def walk(self, speed_x): """move across screen""" displacement = self.rect.move((speed_x, 0)) if self.rect.left < self.area.left or self.rect.right > self.area.right: speed_x = -speed_x displacement = self.rect.move((speed_x, 0)) self.rect = displacement Before I called the method like this: def update(self): self.walk() Now I do: def update(self): self.walk(self.move) Why doesn't this work?

    Read the article

  • How to add second JOIN clause in Linq To Sql?

    - by Refracted Paladin
    I am having a lot of trouble coming up with the Linq equivalent of this legacy stored procedure. The biggest hurdle is it doesn't seem to want to let me add a second 'clause' on the join with tblAddress. I am getting a Cannot resolve method... error. Can anyone point out what I am doing wrong? Below is, first, the SPROC I need to convert and, second, my LINQ attempt so far; which is FULL OF FAIL! Thanks SELECT dbo.tblPersonInsuranceCoverage.PersonInsuranceCoverageID, dbo.tblPersonInsuranceCoverage.EffectiveDate, dbo.tblPersonInsuranceCoverage.ExpirationDate, dbo.tblPersonInsuranceCoverage.Priority, dbo.tblAdminInsuranceCompanyType.TypeName AS CoverageCategory, dbo.tblBusiness.BusinessName, dbo.tblAdminInsuranceType.TypeName AS TypeName, CASE WHEN dbo.tblAddress.AddressLine1 IS NULL THEN '' ELSE dbo.tblAddress.AddressLine1 END + ' ' + CASE WHEN dbo.tblAddress.CityName IS NULL THEN '' ELSE '<BR>' + dbo.tblAddress.CityName END + ' ' + CASE WHEN dbo.tblAddress.StateID IS NULL THEN '' WHEN dbo.tblAddress.StateID = 'ns' THEN '' ELSE dbo.tblAddress.StateID END AS Address FROM dbo.tblPersonInsuranceCoverage LEFT OUTER JOIN dbo.tblInsuranceCompany ON dbo.tblPersonInsuranceCoverage.InsuranceCompanyID = dbo.tblInsuranceCompany.InsuranceCompanyID LEFT OUTER JOIN dbo.tblBusiness ON dbo.tblBusiness.BusinessID = dbo.tblInsuranceCompany.BusinessID LEFT OUTER JOIN dbo.tblAddress ON dbo.tblAddress.BusinessID = dbo.tblBusiness.BusinessID and tblAddress.AddressTypeID = 'b' LEFT OUTER JOIN dbo.tblAdminInsuranceCompanyType ON dbo.tblPersonInsuranceCoverage.InsuranceCompanyTypeID = dbo.tblAdminInsuranceCompanyType.InsuranceCompanyTypeID LEFT OUTER JOIN dbo.tblAdminInsuranceType ON dbo.tblPersonInsuranceCoverage.InsuranceTypeID = dbo.tblAdminInsuranceType.InsuranceTypeID WHERE tblPersonInsuranceCoverage.PersonID = @PersonID var coverage = from insuranceCoverage in context.tblPersonInsuranceCoverages where insuranceCoverage.PersonID == personID join insuranceCompany in context.tblInsuranceCompanies on insuranceCoverage.InsuranceCompanyID equals insuranceCompany.InsuranceCompanyID join address in context.tblAddresses on insuranceCompany.tblBusiness.BusinessID equals address.BusinessID where address.AddressTypeID = 'b' select new { insuranceCoverage.PersonInsuranceCoverageID, insuranceCoverage.EffectiveDate, insuranceCoverage.ExpirationDate, insuranceCoverage.Priority, CoverageCategory = insuranceCompany.tblAdminInsuranceCompanyType.TypeName, insuranceCompany.tblBusiness.BusinessName, TypeName = insuranceCoverage.InsuranceTypeID, Address = };

    Read the article

  • problem in below table:i had table inside table .my inner table contains some text.

    - by Ayyappan.Anbalagan
    Heading ## <tr style=" width:500px; float:left;"> <td style="border: thin ridge #008000; text-align:left;" align="left"; > <table class="" style=" border: 1px solid #800000; width:200px; float:left; height: 200px;"> <tr> <td>&nbsp;stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow&nbsp; </td> </tr> </table> stackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow statackoverflow sta</td> </tr> </table>

    Read the article

  • CSS Position:Absolute with relative adjustment

    - by Gidiyo
    I am trying to do a vertical dropdown menu. This is my code .menu li:hover>ul{ position:absolute; display:inline; left:120px; top:100px;} I use position: Absolute to remove the sub-menu from the table, once the menu gets hovered. It appears that, if I do not indicate top or left property. The sub-menu will displayed relatively. Now I need to adjust the position relatively but seems that only the left property works. So my sub-menu left position is 120px relatively away from its original position. But the top is 100px away from the top of the window, rather then to the original position. How do I move the list up relative to it original position? I cant use position:relative because I need the sub-menu to be remove from the table.

    Read the article

  • python tkinter gui

    - by Lewis Townsend
    I'm wanting to make a small python program for yearly temperatures. I can get nearly everything working in the standard console but I'm wanting to implement it into a GUI. The program opens a csv file reads it into lists, works out the average, and min & max temps. Then on closing the application will save a summary to a new text file. I am wanting the default start up screen to show All Years. When a button is clicked it just shows that year's data. Here is a what I want it to look like. Pretty simple layout with just the 5 buttons and the out puts for each. I can make up the buttons for the top fine with: Code: class App: def __init__(self, master): frame = Frame(master) frame.pack() self.hi_there = Button(frame, text="All Years", command=self.All) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="2011", command=self.Y1) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="2012", command=self.Y2) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="2013", command=self.Y3) self.hi_there.pack(side=LEFT) self.hi_there = Button(frame, text="Save & Exit", command=self.Exit) self.hi_there.pack(side=LEFT) I'm not sure as to how to make the other elements, such as the title & table. I was going to post the code of the small program but decided not to. Once I have the structure/framework I think I can populate the fields & I might learn better this way. Using Python 2.7.3

    Read the article

  • Container div ignores height of floated elements

    - by Thomas
    Ok, so this seems like a really silly problem but I can't get my container div to inherit the height of the floated elements inside of it. Since I need to center the container div, I can't use float to fix this problem. Here is my css: #container { margin: 0 auto; width: 1000px; border-left: 1px solid #f1f1f1; border-right: 1px solid #f1f1f1; border-bottom: 1px solid #f1f1f1; } #focus { padding-left: 23px; width: 977px; padding-top: 20px; padding-bottom: 23px; border-bottom: 1px solid #f1f1f1; float: left; } .rslider { float: left; width: 600px; margin-left: 15px; } .welcome { float: left; width: 300px; } Html: <div id="container"> <div id="logo_block"> <a href="#"><img src="img/logo.jpg" alt="" /></a> </div> <div id="focus"> <div class="welcome"> <h1>All About This Page</h1> <p>Donec quam felis, ultricies nec, pellentesque eu, pretium quis, sem. Nulla consequat massa quis enim. Donec pede justo, fringilla vel, liquet nec, vulputate eget, arcu. In enim justo, rhoncus ut, imperdiet a, venenatis vitae, justo. Nullam dictum felis eu pede mollis pretium.</p> </div> <div class="rslider"> <img src="img/slider_image.jpg"> </div> </div> </div> Any ideas?

    Read the article

  • CSS Positioning

    - by Davey
    Trying to mess with this wordpress theme and can't figure out why the sidebar is stacking underneath the content block. Any help would be very appreciated. http://www.buffalostreetbooks.com/events CSS: body { font-family: Arial, Helvetica, Verdana, Sans-serif; font-size: 10pt; background-color: #692022; background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/repeatflower.png"); } body,h1#blog-title { margin: 0; padding: 0; } a { color: blue; } a:hover { color: #FF8C00; } a img { border: 0 none; } #wrapper { width: 960px; margin: 0 auto; background-color: #F4FBF4; border-left: 1px solid #ccc; border-right: 1px solid #ccc; } #header { background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/headertime.png"); width:768px; height: 200px; } #inner-header { padding: 125px 1em 0; } h1#blog-title { font-size: 2em; } h1#blog-title a { color: #800000; } .entry-title a { color: #CD853F; } h1#blog-title a, .entry-title a, #footer a { text-decoration: none; } h1#blog-title a:hover, .entry-title a:hover, #footer a:hover { text-decoration: underline; } div.skip-link { display: none; } #menu { border-bottom: 1px solid #ccc; } #menu a { color: #000; } #menu a:hover { text-decoration: underline; } #menu li.current_page_item a, #menu li.current_page_item a:hover { background-color: #DFC28B; text-decoration: none; } #content { padding: 1em; width:600px; } .entry-title { font-size: 1.5em; margin: 1em 0 0 0; } abbr.published { color: #666; border: 0 none; } .entry-meta, .entry-date { color: #666; } #comments-list .avatar { float: left; margin-right: 1em; } #comments-list .n { font-weight: bold; } .entry-meta, .comment-meta { font-style: italic; } #comments-list p { clear: left; } #primary { padding-left: 1em; font-size: 0.9em; border-left: 1px solid #ccc; border-bottom: 1px solid #ccc; background-color: #FFFACD; } #footer { text-align: center; font-size: 0.8em; border-top: 1px solid #ccc; border-bottom: 1px solid #ccc; margin-bottom: 1em; } #inner-footer { padding: 1em 0; } .entry-meta, .entry-meta a, .comment-meta, .comment-meta a, .sidebar, .sidebar a, #footer, #footer a { color: #666; } /* LAYOUT: Two-Column (Right) DESCRIPTION: Two-column fluid layout with one sidebars right of content */ div#container { margin:0 0 0 0; width:960px; height:100%; } div#content { margin:0 0 0 0; } div.sidebar { overflow:hidden; width:280px; min-height:500px; clear:both; } div#secondary { clear:right; } div#footer { clear:both; width:100%; } /* Just some example content */ div#menu { height:2em; width:100%; } div#menu ul,div#menu ul ul { line-height:2em; list-style:none; margin:0; padding:0; } div#menu ul a { display:block; margin-right:1em; padding:0 0.5em; text-decoration:none; } div#menu ul ul ul a { font-style:italic; } div#menu ul li ul { left:-999em; position:absolute; } div#menu ul li:hover ul { left:auto; } .entry-title,.entry-meta { clear:both; } div#primary { } form#commentform .form-label { margin:1em 0 0; } form#commentform span.required { background:#fff; color:#c30; } form#commentform,form#commentform p { padding:0; } input#author,input#email,input#url,textarea#comme nt { padding:0.2em; } div.comments ol li { margin:0 0 3.5em; } textarea#comment { height:13em; margin:0 0 0.5em; overflow:auto; width:66%; } .alignright,img.alignright{ float:right; margin:1em 0 0 1em; } .alignleft,img.alignleft{ float:left; margin:1em 1em 0 0; } .aligncenter,img.aligncenter{ display:block; margin:1em auto; text-align:center; } div.gallery { clear:both; height:180px; margin:1em 0; width:100%; } p.wp-caption-text{ font-style:italic; } div.gallery dl{ margin:1em auto; overflow:hidden; text-align:center; } div.gallery dl.gallery-columns-1 { width:100%; } div.gallery dl.gallery-columns-2 { width:49%; } div.gallery dl.gallery-columns-3 { width:33%; } div.gallery dl.gallery-columns-4 { width:24%; } div.gallery dl.gallery-columns-5 { width:19%; } div#nav-above { margin-bottom:1em; } div#nav-below { margin-top:1em; } div#nav-images { height:150px; margin:1em 0; } div.navigation { height:1.25em; } div.navigation div.nav-next { float:right; text-align:right; } div.sidebar h3 { font-size:1.2em; } div.sidebar input#s { width:7em; } div.sidebar li { list-style:none; margin:0 0 2em; } div.sidebar li form { margin:0.2em 0 0; padding:0; } div.sidebar ul ul { margin:0 0 0 2em; } div.sidebar ul ul li { list-style:disc; margin:0; } div.sidebar ul ul ul { margin:0 0 0 0.5em; } div.sidebar ul ul ul li { list-style:circle; } div#menu ul li,div.gallery dl,div.navigation div.nav-previous { float:left; } input#author,input#email,input#url,div.navigation div { width:50%; } div.gallery *,div.sidebar div,div.sidebar h3,div.sidebar ul { margin:0; padding:0; }

    Read the article

  • How to find largest common sub-tree in the given two binary search trees?

    - by Bhushan
    Two BSTs (Binary Search Trees) are given. How to find largest common sub-tree in the given two binary trees? EDIT 1: Here is what I have thought: Let, r1 = current node of 1st tree r2 = current node of 2nd tree There are some of the cases I think we need to consider: Case 1 : r1.data < r2.data 2 subproblems to solve: first, check r1 and r2.left second, check r1.right and r2 Case 2 : r1.data > r2.data 2 subproblems to solve: - first, check r1.left and r2 - second, check r1 and r2.right Case 3 : r1.data == r2.data Again, 2 cases to consider here: (a) current node is part of largest common BST compute common subtree size rooted at r1 and r2 (b)current node is NOT part of largest common BST 2 subproblems to solve: first, solve r1.left and r2.left second, solve r1.right and r2.right I can think of the cases we need to check, but I am not able to code it, as of now. And it is NOT a homework problem. Does it look like?

    Read the article

  • Blackberry (Java) - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

    Read the article

  • Giving 'TemplateError' can't convert String into Integer

    - by Gagan
    Hi, I recently transfered my app from Rails2 to Rails3. The code in 'app/views/distribution/index.html.erb' is like :- <div style="padding-bottom:10px; padding-left:0px;float:left;display:<%= (!session[:album][@artist.id.to_s].empty? && !session[:album][@artist.id.to_s].nil?)?'block' : 'none' %>" id = "make_payment_enabled"> <%= link_to 'Make Payments',{:action => 'pay', :album=>@album.id}, :class => "button" %> </div> It's giving me TemplateError on line :- <div style="padding-bottom:10px; padding-left:0px;float:left;display:<%= (!session[:album][@artist.id.to_s].empty? && !session[:album][@artist.id.to_s].nil?)?'block' : 'none' %>" id = "make_payment_enabled"> How to resolve the problem ?

    Read the article

  • convert following string into array using explode()

    - by Deepali
    HI, I have a string: NEW ALPINESTAR?S SMX PLUS WHITE MOTORCYCLE BOOTS! 44/9.5$349.95 Time Left 1h 2m NEW AGV BLADE FLAT MATTE WHITE LARGE/LG HELMET$75.53Time Left 1h 2m I want result in array like this: Productname Price time NEW ALPINESTAR?S SMX PLUS WHITE MOTORCYCLE BOOTS! 44/9.5 $349.95 Time Left 1h 2m

    Read the article

  • Blackberry app development - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

    Read the article

  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

    Read the article

< Previous Page | 49 50 51 52 53 54 55 56 57 58 59 60  | Next Page >