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  • Execute codes in a different page but remain on the same actual php page

    - by chupinette
    I have a complicated problem here..I have codes to send mail using PEAR which i have tested in a php page called testmail.php. Now i have my actual application an a page called Cart.php where i have a button called Place Order. When i click on this button, it actually redirects to a url called : http://localhost/final/index.php?OrderSuccessful which actually displays a message on the page and sends an email. The problem is that when i put the code for email in Cart.php, i get errors. But when i put the url http://localhost/final/testmail.php it actually works. So i was thinking, is there a way to execute the codes from that testmail.php by remaining on the page Cart.php? include('Mail.php'); $mail = Mail::factory("mail"); $headers = array("From"=>"[email protected]", "Subject"=>"Your order has been placed "); $body = "lol"; $mail->send("[email protected]", $headers, $body); I get the error Assigning the return value of new by reference is deprecated

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  • PHP on Ubuntu autoload_register and namespacing issue

    - by Tian Loon
    I have a problem here. I have created the namespace for all classes. previously i was using windows 7 to develop current app, everything is fine. now i just moved to ubuntu, the problem comes. index.php spl_autoload_extensions(".php"); /*spl_autoload_register(function ($class) { require __DIR__ . '/../' . $class . '.php'; });*/ //provided i have tried the above method, which works on windows 7 but not Ubuntu spl_autoload_register(function ($class) { require '/../' . $class . '.php'; }); //for your info, i do this //require "../resources/library/Config.php"; //it works, no error use resources\library as LIB; use resources\dal as DAL; //instantiation $config = new LIB\Config(); print_r($config->fbKey()); i got this error PHP Warning: require(../resources\\library\\Config.php): failed to open stream: No such file or directory in /home/user/dir1/dir2/index.php i cannot find the error. hope you guys can help me with this. any question don hesitate to comment i will edit. thanks in advance. UPDATE - Extra Info PHP version 5.4.6 LATEST UPDATE any idea how to solve this without using str_replace ?

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  • PHP rewrite to included file - is this a valid script?

    - by Poni
    Hi all! I've made this question: http://stackoverflow.com/questions/2921469/php-mutual-exclusion-mutex As said there, I want several sources to send their stats once in a while, and these stats will be showed at the website's main page. My problem is that I want this to be done in an atomic manner, so no update of the stats will overlap another one running in the background. Now, I came up with this solution and I want you PHP experts to judge it. stats.php <?php define("my_counter", 12); ?> index.php <?php include "stats.php"; echo constant("my_counter"); ?> update.php <?php $old_error_reporting = error_reporting(0); include "stats.php"; define("my_stats_template",' <?php define("my_counter", %d); ?> '); $fd = fopen("stats.php", "w+"); if($fd) { if (flock($fd, LOCK_EX)) { $my_counter = 0; try { $my_counter = constant("my_counter"); } catch(Exception $e) { } $my_counter++; $new_stats = sprintf(constant("my_stats_template"), $my_counter); echo "Counter should stand at $my_counter"; fwrite($fd, $new_stats); } flock($fd, LOCK_UN); fclose($fd); } error_reporting($old_error_reporting); ?> Several clients will call the "update.php" file once every 60sec each. The "index.php" is going to use the "stats.php" file all the time as you can see. What's your opinion?

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  • Same-directory includes failing on a Fedora server with PHP.

    - by JimmySawczuk
    I have a couple files that look like this: index.php: <?php include('includes/header.php'); ... includes/header.php: <?php include('config.php'); ... The error I get is Warning: require(config.php) [function.require]: failed to open stream: No such file or directory in [dir]/includes/header.php on line 2 Fatal error: require() [function.require]: Failed opening required 'config.php' (include_path='.:/usr/share/pear:/usr/share/php') in [dir]/includes/header.php on line 2 I did some further debugging: when I add the call system('pwd'); to includes/header.php, it shows [dir], where it should say [dir]/includes. Adding the 'includes/' to the include path works, but isn't desirable because that would fail on the production server. The above code works on a production server, and worked fine on my development Fedora server, until I tried to change my development environment so that the Fedora server's document root is a mounted CIFS share. Any ideas? Thanks.

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  • Dynamically add data stored in php to nested json

    - by HoGo
    I am trying to dynamicaly generate data in json for jQuery gantt chart. I know PHP but am totally green with JavaScript. I have read dozen of solutions on how dynamicaly add data to json, and tried few dozens of combinations and nothing. Here is the json format: var data = [{ name: "Sprint 0", desc: "Analysis", values: [{ from: "/Date(1320192000000)/", to: "/Date(1322401600000)/", label: "Requirement Gathering", customClass: "ganttRed" }] },{ name: " ", desc: "Scoping", values: [{ from: "/Date(1322611200000)/", to: "/Date(1323302400000)/", label: "Scoping", customClass: "ganttRed" }] }, <!-- Somoe more data--> }]; now I have all data in php db result. Here it goes: $rows=$db->fetchAllRows($result); $rowsNum=count($rows); And this is how I wanted to create json out of it: var data=''; <?php foreach ($rows as $row){ ?> data['name']="<?php echo $row['name'];?>"; data['desc']="<?php echo $row['desc'];?>"; data['values'] = {"from" : "/Date(<?php echo $row['from'];?>)/", "to" : "/Date(<?php echo $row['to'];?>)/", "label" : "<?php echo $row['label'];?>", "customClass" : "ganttOrange"}; } However this does not work. I have tried without loop and replacing php variables with plain text just to check, but it did not work either. Displays chart without added items. If I add new item by adding it to the list of values, it works. So there is no problem with the Gantt itself or paths. Based on all above I assume the problem is with adding plain data to json. Can anyone please help me to fix it?

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  • PHP in_array() can't even match a single character. Strict is set to true.

    - by solefald
    I've seen a million of these threads here already, and read through every single one already. Including some serious time Googling. Nothing complicated. All I have to do is check if a single character in a loop matches my alphabet array. print_r($alphabet); // all 26 letters Array ( [0] => a [1] => b [2] => c ... [23] => x [24] => y [25] => z ) print_r($emptyLetters); // dynamic array. Array ( [0] => b [1] => s ) foreach($alphabet as $letter): { echo $letter . '<br />' // Correctly prints out every letter from $alphabet. if(in_array($letter, $emptyLetters, true)): // $strict is set // do something endif; } What the hell is going on??? I do not understand what i am doing wrong.... I tried every combination and option possible, but for some reason even array_search() is bit working...

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  • Workaround for PHP SOAP request failure when wsdl defines service port binding as https and port 80?

    - by scooterhanson
    I am consuming a SOAP web service using php5's soap extension. The service' wsdl was generated using Axis java2wsdl, and whatever options are used during generation result in the port binding url being listed as https://xxx.xxx.xxx.xxx**:80** If I download the wsdl to my server, remove the port 80 specification from the port binding location value, and reference the local file in my soapclient call it works fine. However, if I try to reference it remotely (or download it and reference it locally, as-is) the call fails with a soap fault. I have no input into the service side so I can't make them change their wsdl-generation process. So, unless there's a way to make the soapclient ignorant of the port, I'm stuck with using a locally modified copy of someone else' wsdl (which I'd rather not do). Any thoughts on how to make my soapclient ignore the port 80?

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  • Cpu usage from top command

    - by kairyu
    How can i get the result like example following. Any command or scripts? Snapshot u1234 3971 1.9 0.0 0 0 ? Z 20:00 0:00 [php] u1234 4243 3.8 0.2 64128 43064 ? D 20:00 0:00 /usr/bin/php /home/u1234/public_html/index.php u1234 4289 5.3 0.2 64128 43064 ? R 20:00 0:00 /usr/bin/php /home/u1234/public_html/index.php u1234 4312 9.8 0.2 64348 43124 ? D 20:01 0:00 /usr/bin/php /home/u1234/public_html/index.php u1235 4368 0.0 0.0 30416 6604 ? R 20:01 0:00 /usr/bin/php /home/u1235/public_html/index.php u1236 4350 2.0 0.0 34884 13284 ? D 20:01 0:00 /usr/bin/php /home/u1236/public_html/index.php u1237 4353 13.3 0.1 51296 30496 ? S 20:01 0:00 /usr/bin/php /home/u1237/public_html/index.php u1238 4362 63.0 0.0 0 0 ? Z 20:01 0:00 [php] u1238 4366 0.0 0.1 51352 30532 ? R 20:01 0:00 /usr/bin/php /home/u1238/public_html/index.php u1239 4082 3.0 0.0 0 0 ? Z 20:00 0:01 [php] u1239 4361 26.0 0.1 49104 28408 ? R 20:01 0:00 /usr/bin/php /home/u1239/public_html/index.php u1240 1980 0.4 0.0 0 0 ? Z 19:58 0:00 [php] CPU TIME = 8459.71999999992 This result i got from hostgator support :) I was used "top -c" but they do not show "/home/u1239/public_html/index.php Thanks

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  • Linking how PHP/HTML

    - by Azzyh
    Hello. Alright so im done doing pages with frames, and know i splitted up my design to top.php and bottom.php. In top.php it's linking to style.css and ajax_framework.js and such.. Now this works great until i tried to include top.php & bottom.php in videos/index.php (another dirr), i did like this: include "../top.php"; <-- and the originally index.php --> include "../bottom.php"; Now when i enter the site, it wont load style.css, probably because it thinks that style.css needs to be in videos/ directory, same goes with ajax_framework.js that are both files are on the parent ../ directory. Now what do i do? Some method or technique to solve this in a good way? So i dont have to copy style.css and ajax_framework.js into every directory i have, because then later if i want to change something i would need to change in all directories, which would be my last thing i want to do.. hope you got some nice techniques thank you

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  • PHP include doesn't work

    - by Chris
    I'm not sure how simple is this to solve, but I assume I'm doing something wrong. I'm new to PHP, so bear with me, please. When I started learning PHP, I always placed all my project files into the same folder along with index.php and thus included everything like this: <?php include('./translation.php'); ?> Later on in the process of learning as I gained experience and my skill increased, I had to start using folders and place my files into sub folders. I ended up successfully including my files with the following: <?php include('../translation.php'); ?> My trouble-free coding took an unexpected turn when I decided to start using sub-sub folders. After placing all the files even deeper into the file structure I was shocked to find out that I cannot include them anymore, using: <?php include('.../translation.php'); ?> Now I'm lost. What did I do wrong? Am I to understand that I cannot include files deeper than 2 directories in the project? Should I start using a different file system?

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  • What's the best technique to protect my framework from visitors who are not logged in?

    - by Hermet
    First of all, I would like to say that I have used the search box looking for a similar question and was unsuccessful, maybe because of my poor english skills. I have a a 'homemade' framework. I have certain PHP files that must only be visible for the admin. The way I currently do this is check within every single page to see if a session has been opened. If not, the user gets redirected to a 404 page, to seem like the file which has been requested doesn't exist. I really don't know if this is guaranteed to work or if there's a better and more safe way because I'm currently working with kind of confidential data that should never become public. Could you give me some tips? Or leave a link where I could find some? Thank you very much, and again excuse me for kicking the dictionary. EDIT What I usually write in the top of each file is something like this <?php include("sesion.php"); $rs=comprueba(); //'check' if ($rs==1) { ?> And then, at the end <?php } ?> Is it such a butched job, isn't it? EDIT Let's say I have a customers list in a file named customers.php That file may be currently on http://www.mydomain.com/admin/customers.php and it must only be visible for the admin user. Once the admin user has been logged in, I create a session variable. That variable is what I check on the top of each page, and if it exists, the customers list is shown. If not, the user gets redirected to the 404 page. Thank you for your patience. I really appreciate.

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  • trying to backup mysql database using php

    - by user225269
    I got this code from this site: http://www.php-mysql-tutorial.com/wikis/mysql-tutorials/using-php-to-backup-mysql-databases.aspx But I'm just a beginner so I don't know what the config.php and opendb.php suppose to mean. Do I have to create those 2 files in order for this code to work? If yes, then how do I create it, it isn't included in the site how to create it. <?php include 'config.php'; include 'opendb.php'; $tableName = 'mypet'; $backupFile = 'backup/mypet.sql'; $query = "SELECT * INTO OUTFILE '$backupFile' FROM $tableName"; $result = mysql_query($query); include 'closedb.php'; ?> can I just include these lines on the top code so that I will not be putting the include 'opendb.php' anymore: $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Hospital", $con);

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  • Sanitize input before executing at server in php

    - by Interfaith
    I want to let user input two variable, Name and Password in a form. I want to disable any XSS or script insert in the input values. I have the following code in the form method: <form name="form1" method="post" action="checkpw.php"> Your Name: <table> <tr><td><input class="text" name="name" onBlur="capitalize(this);" maxlength=12 type="text" /></td></tr> </table> Password: <table> <tr><td><input class="text" name="passwd" maxlength=8 type="password" /></td></tr> <tr><td align="center"><br/> <input class="text" type="submit" name="submitbt" value="Login" /> </td></tr> </table> and the following checkpw.php: <?php // Clean up the input values $post = filter_input_array(INPUT_POST, array( 'name' => FILTER_SANITIZE_STRING, 'pw' => FILTER_SANITIZE_STRING, )); if (is_null($post) || in_array(null, $post)) { header("location:login.php"); return; // missing fields (or failed filter) } // pw is the password sent from the form $pw=$_POST['passwd']; $name=$_POST['name']; if($pw == 'testpass'){ header("location:index.php"); } else { header("location:wrong.php"); } ?> Is this a secure way to ensure the form is sent to the server and executed ONLY after the input values have been sanitized? Also, the $name value i want to pass it to index.php file. I insert a code in the index.php as follow: <?php echo $name ?> But it's empty. Any idea how to resolve it?

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  • cURL Affects Cookie Retrieval in PHP?

    - by CJ
    I'm not sure if I'm asking this properly. I have two PHP pages located on the same server. The first PHP page sets a cookie with an expiration and the second one checks to see if that cookie was set. if it is set, it returns "on". If it isn't set, it returns "off". If I just run the pages like "www.example.com/set_cookie.php" AND "www.example.com/is_cookie_set.php" I get an "on" from is_cookie_set.php. Heres the problem, on the set_cookie.php file I have a function called is_set. This function executes the following cURL and returns the contents ("on" or "off"). Unfortunately, the contents are always returned as "off". however, if I check the file manually ("www.example.com/is_cookie_set.php") I can see that the cookie was set. Heres the function : <?php function is_set() { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, 'http://example.com/is_cookie_set.php'); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $contents = curl_exec ($ch); curl_close ($ch); echo $contents; } ?> Please note, I'm not using cURL to GET or SET cookies, only to check a page that checks if the cookie was set. I've looked into CURLOPT_COOKIEJAR, and CURLOPT_COOKIEFILE, but I believe those are for setting cookies via cURL and I don't want to do this.

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  • A stupid question about wordpress and php

    - by bubdada
    It may seem stupid question, but i've a serious problem... if you could check out orcik.net the thumbnail images does not appear. I figured out the reason but I don't know how to solve.. http://orcik.net/projects/thumb/orcikthumb.php?src=http://orcik.net/wp-content/uploads/2010/05/mac-safari-search-cache.png If you go to the above link you will get page not found error. However, if you go to the link below you'll get the thumbnail version of the image... http://orcik.net/projects/thumb/orcikthumb.php?src=/wp-content/uploads/2010/05/mac-safari-search-cache.png I'm using this piece of code on wordpress and the line appears like <a href="<?php the_permalink() ?>" rel="bookmark"> <img src="<?php bloginfo('template_directory'); ?>/includes/orcikthumb.php?src=<?php get_thumbnail($post->ID, 'full'); ?>&amp;h=<?php echo get_theme_mod($height); ?>&amp;w=<?php echo get_theme_mod($width); ?>&amp;zc=1" alt="<?php the_title(); ?>" /> </a> Thus, I believe I can't change the directory of image. But I could not figure out why I am getting page not found error. Is that might be CHMOD'es??? or something else?? Thanks

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  • header location won't work in php

    - by Jayden Kelly
    I am making a login page for my website but the header location won't work. here is the code of login.php: <?php include ( './includes/header.php' ); if (isset($_POST['submit'])) { $username = $_POST['username']; $password = $_POST['password']; $check_username = mysql_query("SELECT username FROM users WHERE username='$username'"); $numrows = mysql_num_rows($check_username); if ($numrows != 1) { echo 'That User doesn\'t exist.'; } else { $check_password = mysql_query("SELECT password FROM users WHERE password='$password' && username='$username'"); while ($row = mysql_fetch_assoc($check_password)) { $password_db = $row['password']; if ($password_db == $password) { $_SESSION['username'] = $username; header("Location: members.php"); } } } } ?> <h2>Login to Your Account</h2> <form action='login.php' method='POST'> <input type='text' name='username' value='Username ...' onclick='value=""'/><p /> <input type='password' name='password' value='Password ...' onclick='value=""'/><p /> <input type='submit' name='submit' value='Login to my Account' /> </form> I would really appreciate it if someone could help me, thanks. P.S. If you need the php part of the header file it is here: <?php session_start(); include ( './includes/functions.php' ); include ( './includes/connect_to_mysql.php' ); ?>

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  • PHP Mail() not working on remote server

    - by Amaerth
    I am developing an application and have been testing the mail() function in PHP. The following works just fine on my local machine to send emails to myself, but as soon as I try to send it from the testing environment to my local machine, it silently fails. I will still get the "Mail Sent" message, but no message is sent. I turned on the mail logging in the php.ini file, but even that doesn't seem to be populated after I refresh the page. Again, the .php files and php.ini files are identical in both environments. Port 25 has been opened on the testing environment, and we are using a Microsoft Exchange server. <?php $to = "[email protected]"; $subject = "Test mail"; $message = "Hello! This is a simple email message."; $from = "[email protected]"; $headers = "From:" . $from; mail($to,$subject,$message,$headers); echo "Mail Sent."; ?> SMTP area of the php.ini file: [mail function] ; For Win32 only. ; http://php.net/smtp SMTP = exhange.server.org ; http://php.net/smtp-port smtp_port = 25 ; For Win32 only. ; http://php.net/sendmail-from sendmail_from = [email protected]

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  • PHP Session doesn't get read in next page after login validation, Why?

    - by NetStar
    I have a web site and when my users login it takes them to verify.php (where it connects to the DataBase and matches email and password to the user input and if OK puts client data into sessions and take the client to /memberarea/index.php ELSE back to login page with message "Invalid Email or password!") <?php ob_start(); session_start(); $email=$_POST['email']; $pass=md5($_POST['pass']); include("conn.php"); // connects to Database $sql="SELECT * FROM `user` WHERE email='$email' AND pass='$pass'"; $result=mysql_query($sql); $new=mysql_fetch_array($result); $_SESSION['fname']=$new['fname']; $_SESSION['lname']=$new['lname']; $_SESSION['email1']=$new['email1']; $_SESSION['passwrd']=$new['passwrd']; $no=mysql_num_rows($result); if ($no==1){ header('Location:memberarea/index.php'); }else { header("Location:login.php?m=$msg"); //msg="Invalid Login" } ?> then after email id and password is verified it takes them to ` /memberarea/index.php (This is where the problem happens.) where in index.php it checks if a session has been created in-order to block hackers to enter member area and sends them back to the login page. <? session_start(); isset($_SESSION['email'])` && `isset($_SESSION['passwrd'])` The problem is the client gets verified in verify.php (the code is above) In varify.php only after I put ob_start(); ontop of session_start(); It moves on to /memberarea/index.php , If I remove ob_start() It keeps the client on the verify.php page and displays error header is alredy SENT. after I put ob_start() it goes in to /memberarea/index.php but the session is blank, so it goes back to the login page and displays the error ($msg) "Invalid Login" which I programed to display. Can anyone tell me why the session cant pass values from verify.php to /memberarea/index.php

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  • Image error with wordpress and php

    - by bubdada
    It may seem stupid question, but i've a serious problem... if you could check out orcik.net the thumbnail images does not appear. I figured out the reason but I don't know how to solve.. http://orcik.net/projects/thumb/orcikthumb.php?src=http://orcik.net/wp-content/uploads/2010/05/mac-safari-search-cache.png If you go to the above link you will get page not found error. However, if you go to the link below you'll get the thumbnail version of the image... http://orcik.net/projects/thumb/orcikthumb.php?src=/wp-content/uploads/2010/05/mac-safari-search-cache.png I'm using this piece of code on wordpress and the line appears like <a href="<?php the_permalink() ?>" rel="bookmark"> <img src="<?php bloginfo('template_directory'); ?>/includes/orcikthumb.php?src=<?php get_thumbnail($post->ID, 'full'); ?>&amp;h=<?php echo get_theme_mod($height); ?>&amp;w=<?php echo get_theme_mod($width); ?>&amp;zc=1" alt="<?php the_title(); ?>" /> </a> Thus, I believe I can't change the directory of image. But I could not figure out why I am getting page not found error. Is that might be CHMOD'es??? or something else?? Thanks

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  • PHP rewrite an included file - is this a valid script?

    - by Poni
    Hi all! I've made this question: http://stackoverflow.com/questions/2921469/php-mutual-exclusion-mutex As said there, I want several sources to send their stats once in a while, and these stats will be showed at the website's main page. My problem is that I want this to be done in an atomic manner, so no update of the stats will overlap another one running in the background. Now, I came up with this solution and I want you PHP experts to judge it. stats.php <?php define("my_counter", 12); ?> index.php <?php include "stats.php"; echo constant("my_counter"); ?> update.php <?php $old_error_reporting = error_reporting(0); include "stats.php"; define("my_stats_template",' <?php define("my_counter", %d); ?> '); $fd = fopen("stats.php", "w+"); if($fd) { if (flock($fd, LOCK_EX)) { $my_counter = 0; try { $my_counter = constant("my_counter"); } catch(Exception $e) { } $my_counter++; $new_stats = sprintf(constant("my_stats_template"), $my_counter); echo "Counter should stand at $my_counter"; fwrite($fd, $new_stats); } flock($fd, LOCK_UN); fclose($fd); } error_reporting($old_error_reporting); ?> Several clients will call the "update.php" file once every 60sec each. The "index.php" is going to use the "stats.php" file all the time as you can see. What's your opinion?

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  • Which is faster: in_array() or a bunch of expressions in PHP?

    - by Darryl Hein
    Is it faster to do the following: if ($var != 'test1' && $var != 'test2' && $var != 'test3' && $var != 'test4') { ... } Or: if (!in_array($var, array('test1', 'test2', 'test3', 'test4') { ... } Is there a number of values at which point it's faster to do one or the other? (In this case, the array used in the second option doesn't alreay exist.)

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  • Can't call an object method. PHP reports variable undefined

    - by user1285697
    This is the weirdest bug! It is probably something silly, but I have no idea how to fix it. If anyone could help, I would be most grateful! I have three files, one is called items.php, another is called tableFunctions.php, and the third is called mysql.php. I use two global objects called 'mysql' and 'tableFunctions'. They are stored in the files 'mysql.php', and 'tableFunctions.php', respectively. In each file, I create an instance of its object, assigning it to the global variable $_mysql, or $_table. like this: In the file mysql.php: global $_mysql; $_mysql = new mysql(); In the file tableFunctions.php: global $_table; $_table = new tableFunctions(); Here's how it is supposed to work: The items.php file includes the tableFunctions.php file... Which in turn, needs the mysql.php file, so it includes it too. In the items.php file, I call the method getTable(), which is contained in the object tableFunctions.(and in the variable $_table.) Like this: $t = $_table->getTable('items'); The getTable function calls the method, arrayFromResult(), which is contained within in the object mysql.(and in the variable $_mysql.) Like this: $result = $_mysql->arrayFromResult($r); That's where I get the error. PHP says that the variable '$_mysql' is undefined, but I defined it in the 'mysql.php' file.(see above) I also included mysql.php with the following code: include_once 'mysql.php'; I have no idea what is wrong! If anyone can help that would be much appreciated. The source files can be downloaded with the following link: https://www.dropbox.com/sh/bjj2gyjsybym89r/YLxqyNvQdn

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  • Why doesn't this require_once statement find the file? (PHP)

    - by ggfan
    I not sure what's going on..maybe I missed something simple. In my connectvars.php file, I connect to the database using the variables in my config.php folder. Here's the hierarchy: admin(folder) config.php includes(folder) connectvars.php I want to get information from config.php to use in connectvars.php, so I use: require_once("../admin/config.php"); But everytime I do this I get Warning: require_once(../admin/config.php) [function.require-once]: failed to open stream: No such file or directory in /home/a8879415/public_html/includes/connectvars.php on line 2 BUT when I type: require_once("admin/config.php");, it works. I thought I had to go up a level, then go down to admin, then get config.php. So how come I just need to go into the admin folder then get config.php?

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  • PHP+Apache as forward/reverse proxy: ¿how to process client requests and server responses in PHP?

    - by Lightworker
    Hi! I'm having a lot of troubles with the propper configuration of Apache mod_proxy.so to work as desired... The main idea, is to create a proxy on a local machine in a network wich will have the ability to proces a client request (client connected through this Apache prepared proxy) in PHP. And also, it will have the capacity to process the server responses on PHP too. Those are the 2 funcionalities, and they are independent one from each other. Let me present a little schema of what I need to achive: As you can see here, there're 2 ways: blue one and red one. For the blue one, I basically conected a client (Machine B - cell phone) on my local network (home) and configured it to go thorugh a proxy, wich is the Machine A (personal computer) on the exactly same network. So let's say (not DHCP): Machine A: 192.168.1.40 -- Apache is running on this machine, and configured to listen port 80. Machine B (cell phone): 192.168.1.75 -- configured to go throug a proxy, wich is IP 192.168.1.75 and port 80 (basically, Machine A). After configuring Apache properly, wich is basically to remove the "#" from httpd.conf on the lines for the mod_proxy.so (main worker), mod_proxy_connect.so (SSL, allowCONNECT, ...) and mod_proxy_http.so (needed for handle HTTP request/responses) and having in my case, lines like this: # Implements a proxy/gateway for Apache. Include "conf/extra/httpd-proxy.conf" # Various default settings Include "conf/extra/httpd-default.conf" # Secure (SSL/TLS) connections Include "conf/extra/httpd-ssl.conf" wich gives me the ability to configure the file httpd-proxy.conf to prepare the forward proxy or the reverse proxy. So I'm not sure, if what I need it's a forward proxy or a reverse one. For a forward proxy I've done this: <IfModule proxy_module> <IfModule proxy_http_module> # # FORWARD Proxy # #ProxyRequests Off ProxyRequests On ProxyVia On <Proxy *> Order deny,allow # Allow from all Deny from all Allow from 192.168.1 </Proxy> </IfModule> </IfModule> wich basically passes all the packets normally to the server and back to the client. I can trace it perfectly (and testing that works) looking at the "access.log" from Apache. Any request I make with the cell phone, appears then on the Apache log. So it works. But here come the problem: I need to process those client requests. And I need to do it, in PHP. I have read a lot about this. I've read in detail the oficial site from Apache about mod_proxy. And I've searched a lot on forums, but without luck. So I thought about a first aproximation: 1) Forward proxy in Apache, passes all the packets and it's not possible to process them. This seems to be true, so, what about a reverse proxy? So I envisioned something like: ProxyRequests Off <Proxy *> Order deny,allow Allow from all </Proxy> ProxyPass http://www.google.com http://www.yahoo.com ProxyPassReverse http://www.google.com http://www.yahoo.com which is just a test, but this should cause on my cell phone that when trying to navigate to Google, I should be going to Yahoo, isn't it? But not. It doesn't work. So you really see, that ALL the examples on Apache reverse proxy, goes like: ProxyPass /foo http://foo.example.com/bar ProxyPassReverse /foo http://foo.example.com/bar wich means, that any kind of request in a local context, will be solved on a remote location. But what I needed is the inverse! It's that when asking for a remote site on my phone, I solve this request on my local server (the Apache one) to process it with a PHP module. So, if it's a forward proxy, I need to pass through PHP first. If it's a reverse proxy, I need to change the "going" direction to my local server one to process first on PHP. Then comes in mind second option: 2) I've seen something like: <Proxy http://example.com/foo/*> SetOutputFilter INCLUDES </Proxy> And I started to search for SetOutputFilter, SetInputFilter, AddOutputFilter and AddInputFilter. But I don't really know how can I use it. Seems to be good, or a solution to me, cause with somethin' like this, I should can add an Input filter to process on PHP the client requests and send back to the client what I programed/want (not the remote server response) wich is the BLUE path on schema, and I should have the ability to add an Output filter wich seems to give me the ability to process the remote server response befor sending it to the client, wich should be the RED path on the schema. Red path, it's just to read server responses and play with em. But nothing more. The Blue path, it's the important one. Cause I will send to the client whatever I want after procesing the requests. I so sorry for this amazingly big post, but I needed to explain it as well as I can. I hope someone will understand my problem, and will help me to solve it! Lot of thanks in advance!! :)

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