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  • CSS : overflow : auto will not work under FireFox 3.6.2

    - by Michael Mao
    Hello everyone: This is a CSS related question, I got one good answer from my previous question, which suggested to use some CSS code like overflow:auto together with a fixed height container. And here is my actual implementation : on uni server Please follow the instructions on screen and buy more than 4 kinds of tickets. If you are using IE8, Opera, Safari, Chrome, you would notice that the lower right corner of the page now has a vertical scroll bar, which scrolls the content inside it and prevent it from overflowing. That's what I want to have in this section. Now the problem is, this would not do in FireFox 3.6.2. Am I doing something not compliant to the CSS standard or FireFox has its own way of overflow control? You can inspect the elements on screen, and all controlling functions are done in one javascript using jQuery. All CSS code are kept in a separated file as well. According to the professor, FireFox would be the target browser, although the version was set to 2.0...

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  • Entry lvl. COBOL Control Breaks

    - by Kyle Benzle
    I'm working in COBOL with a double control break to print a hospital record. The input is one record per line, with, hospital info first, then patient info. There are multiple records per hospital, and multiple services per patient. The idea is, using a double control break, to print one hospital name, then all the patients from that hospital. Then print the patient name just once for all services, like the below. I'm having trouble with my output, and am hoping someone can help me get it in order. I am using AccuCobol to compile experts-exchange does not allow .cob and .dat so the extentions were changed to .txt The files are: the .cob lab5b.cob the input / output: lab5bin.dat, lab5bout.dat The assignment: http://www.cse.ohio-state.edu/~sgomori/314/lab5.html Hospital Number: 001 Hospital Name: Mount Carmel 00001 Griese, Brian Ear Infection 08/24/1999 300.00 Diaper Rash 09/05/1999 25.00 Frontal Labotomy 09/25/1999 25,000.00 Rear Labotomy 09/26/1999 25,000.00 Central Labotomy 09/28/1999 24,999.99 The total amount owed for this patient is: $.......... (End of Hospital) The total amount owed for this hospital is: $......... enter code here IDENTIFICATION DIVISION. PROGRAM-ID. LAB5B. ENVIRONMENT DIVISION. INPUT-OUTPUT SECTION. FILE-CONTROL. SELECT FILE-IN ASSIGN TO 'lab5bin.dat' ORGANIZATION IS LINE SEQUENTIAL. SELECT FILE-OUT ASSIGN TO 'lab5bout.dat' ORGANIZATION IS LINE SEQUENTIAL. DATA DIVISION. FILE SECTION. FD FILE-IN. 01 HOSPITAL-RECORD-IN. 05 HOSPITAL-NUMBER-IN PIC 999. 05 HOSPITAL-NAME-IN PIC X(20). 05 PATIENT-NUMBER-IN PIC 99999. 05 PATIENT-NAME-IN PIC X(20). 05 SERVICE-IN PIC X(30). 05 DATE-IN PIC 9(8). 05 OWED-IN PIC 9(7)V99. FD FILE-OUT. 01 REPORT-REC-OUT PIC X(100). WORKING-STORAGE SECTION. 01 WS-WORK-AREAS. 05 WS-HOLD-HOSPITAL-NUM PIC 999 VALUE ZEROS. 05 WS-HOLD-PATIENT-NUM PIC 99999 VALUE ZEROS. 05 ARE-THERE-MORE-RECORDS PIC XXX VALUE 'YES'. 88 MORE-RECORDS VALUE 'YES'. 88 NO-MORE-RECORDS VALUE 'NO '. 05 FIRST-RECORD PIC XXX VALUE 'YES'. 05 WS-PATIENT-TOTAL PIC 9(9)V99 VALUE ZEROS. 05 WS-HOSPITAL-TOTAL PIC 9(9)V99 VALUE ZEROS. 05 WS-PAGE-CTR PIC 99 VALUE ZEROS. 01 WS-DATE. 05 WS-YR PIC 9999. 05 WS-MO PIC 99. 05 WS-DAY PIC 99. 01 HL-HEADING1. 05 PIC X(49) VALUE SPACES. 05 PIC X(14) VALUE 'OHIO INSURANCE'. 05 PIC X(7) VALUE SPACES. 05 HL-PAGE PIC Z9. 05 PIC X(14) VALUE SPACES. 05 HL-DATE. 10 HL-MO PIC 99. 10 PIC X VALUE '/'. 10 HL-DAY PIC 99. 10 PIC X VALUE '/'. 10 HL-YR PIC X VALUE '/'. 01 HL-HEADING2. 05 PIC XXXXXXXXXX VALUE 'HOSPITAL: '. 05 HL-HOSPITAL PIC 999. 01 HL-HEADING3. 05 PIC X(7) VALUE "Patient". 05 PIC X(3) VALUE SPACES. 05 PIC X(7) VALUE "Patient". 05 PIC X(39) VALUE SPACES. 05 PIC X(7) VALUE "Date of". 05 PIC X(3) VALUE SPACES. 05 PIC X(6) VALUE "Amount". 01 HL-HEADING4. 05 PIC X(6) VALUE "Number". 05 PIC X(4) VALUE SPACES. 05 PIC X(4) VALUE "Name". 05 PIC X(18) VALUE SPACES. 05 PIC X(10) VALUE "Service". 05 PIC X(14) VALUE SPACES. 05 PIC X(8) VALUE "Service". 05 PIC X(2) VALUE SPACES. 05 PIC X(5) VALUE "Owed". 01 DL-PATIENT-LINE. 05 PIC X(28) VALUE SPACES. 05 DL-PATIENT-NUMBER PIC XXXXX. 05 PIC X(21) VALUE SPACES. 05 DL-PATIENT-TOTAL PIC $$$,$$$,$$9.99. 01 DL-HOSPITAL-LINE. 05 PIC X(47) VALUE SPACES. 05 PIC X(16) VALUE 'HOSPITAL TOTAL: '. 05 DL-HOSPITAL-TOTAL PIC $$$,$$$,$$9.99. PROCEDURE DIVISION. 100-MAIN-MODULE. PERFORM 600-INITIALIZATION-RTN PERFORM UNTIL NO-MORE-RECORDS READ FILE-IN AT END MOVE 'NO ' TO ARE-THERE-MORE-RECORDS NOT AT END PERFORM 200-DETAIL-RTN END-READ END-PERFORM PERFORM 400-HOSPITAL-BREAK PERFORM 700-END-OF-JOB-RTN STOP RUN. 200-DETAIL-RTN. EVALUATE TRUE WHEN FIRST-RECORD = 'YES' MOVE PATIENT-NUMBER-IN TO WS-HOLD-PATIENT-NUM MOVE HOSPITAL-NUMBER-IN TO WS-HOLD-HOSPITAL-NUM PERFORM 500-HEADING-RTN MOVE 'NO ' TO FIRST-RECORD WHEN HOSPITAL-NUMBER-IN NOT = WS-HOLD-HOSPITAL-NUM PERFORM 400-HOSPITAL-BREAK WHEN PATIENT-NUMBER-IN NOT = WS-HOLD-PATIENT-NUM PERFORM 300-PATIENT-BREAK END-EVALUATE ADD OWED-IN TO WS-PATIENT-TOTAL. 300-PATIENT-BREAK. MOVE WS-PATIENT-TOTAL TO DL-PATIENT-TOTAL MOVE WS-HOLD-PATIENT-NUM TO DL-PATIENT-NUMBER WRITE REPORT-REC-OUT FROM DL-PATIENT-LINE AFTER ADVANCING 2 LINES ADD WS-PATIENT-TOTAL TO WS-HOSPITAL-TOTAL IF MORE-RECORDS MOVE ZEROS TO WS-PATIENT-TOTAL MOVE PATIENT-NUMBER-IN TO WS-HOLD-PATIENT-NUM END-IF. 400-HOSPITAL-BREAK. PERFORM 300-PATIENT-BREAK MOVE WS-HOSPITAL-TOTAL TO DL-HOSPITAL-TOTAL WRITE REPORT-REC-OUT FROM DL-HOSPITAL-LINE AFTER ADVANCING 2 LINES IF MORE-RECORDS MOVE ZEROS TO WS-HOSPITAL-TOTAL MOVE HOSPITAL-NUMBER-IN TO WS-HOLD-HOSPITAL-NUM PERFORM 500-HEADING-RTN END-IF. 500-HEADING-RTN. ADD 1 TO WS-PAGE-CTR MOVE WS-PAGE-CTR TO HL-PAGE MOVE WS-HOLD-HOSPITAL-NUM TO HL-HOSPITAL WRITE REPORT-REC-OUT FROM HL-HEADING1 AFTER ADVANCING PAGE WRITE REPORT-REC-OUT FROM HL-HEADING2 AFTER ADVANCING 2 LINES. WRITE REPORT-REC-OUT FROM HL-HEADING3 AFTER ADVANCING 2 LINES. 600-INITIALIZATION-RTN. OPEN INPUT FILE-IN OUTPUT FILE-OUT *159 ACCEPT WS-DATE FROM DATE YYYYMMDD MOVE WS-YR TO HL-YR MOVE WS-MO TO HL-MO MOVE WS-DAY TO HL-DAY. 700-END-OF-JOB-RTN. CLOSE FILE-IN FILE-OUT.

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  • Problem passing strings with PHP post

    - by andy
    Hi Guys, Basically I'm developing a (very) simple search engine. You can enter a search term and you are taken to the results page - which works fine. However on the results page, I have a button that will take you to the next 10 results: where $term is the $_POST['term'] value. echo "<input type='hidden' name='term' value='" . $term . "'>"; This causes the following problem with the term is for example "aidan's". When the next 10 button is clicked, the term becomes aidan\ and no further results are found. I am not doing anything to $term. I usually use Java, but am required to use PHP for this uni assignment! Any help would be greatly appreciated.

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  • what is order notation f(n)=O(g(n))?

    - by Lopa
    2 questions: question 1: under what circumstances would this[O(f(n))=O(k.f(n))] be the most appropriate form of time-complexity analysis? question 2: working from mathematical definition of O notation, show that O(f(n))=O(k.f(n)), for positive constant k.? My view: For the first one I think it is average case and worst case form of time-complexity. am i right? and what else do i write in that? for the second one I think we need to define the function mathematically, so is the answer something like because the multiplication by a constant just corresponds to a readjustment of value of the arbitrary constant 'k' in definition of O.

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  • Chatbot client and class modification

    - by blake
    ChatBot Class Modification: Modify the reply() method of the ChatBot class to recognize additional words and phrases. Part 1: Everyone must complete this section. When the userInput parameter value is: The reply method should return: how do I quit enter quit how do I exit enter quit how do I stop enter quit how do I ____ do you really want to do that how are you I'm fine how ______ I don't know Add two additional words or phrases to recognize and respond to. ChatBot Client Modification: Modify the ChatBot client application to loop until the end-user enters "quit". Here is my service class / ** * Java Chatbot Service class * @author Blake * 3/5/2012 */ /** * Default constructor. */ public class Chatbot { private String name; /** Users name */ private String introbot; /** Name of the Chatbot */ private String reply; /** Replies to the input of the string name and string introbot */ /** * Constructs mutebot object * @param mutebow - returns name of mutebot */ public Chatbot() { name = "MuteBot"; } /** * Changes Name * @param name - new name */ public void setName (String n) { name = n; } /** * Accesses name * @return a brand new name */ public String getName() { return name; } /** * Accesses introbot * @return name of mutebot */ public String introbot() { String intro = "Hello! My name is " + name; return intro; } /** * Accesses replay(String newuserinput) * @return introbot reply to user input */ public String getreply(String newuserinput) { String reply = "I'm just learning to talk"; if (newuserinput.equalsIgnoreCase("What")) reply = "Why do you ask?"; else if (newuserinput.equalsIgnoreCase("Why") ) reply = "Why Not"; else if (newuserinput.equalsIgnoreCase("How")) reply = "I don't know!"; else if (newuserinput.equalsIgnoreCase("Where") ) reply = "Anne Arundel Community College"; else if (newuserinput.equalsIgnoreCase("When")) reply = "Tomorrow"; else if (newuserinput.equalsIgnoreCase("how do I quit")) reply = "enter quit"; else if (newuserinput.equalsIgnoreCase("how do I exit")) reply = "enter quit"; else if (newuserinput.equalsIgnoreCase("how do I stop")) reply = "enter quit"; else if (newuserinput.equalsIgnoreCase("how are you")) reply = "I'm fine"; else if (newuserinput.equalsIgnoreCase("how do you do")) reply = "I am doing well"; else if (newuserinput.equalsIgnoreCase("how do I get out")) reply = "By going through the door"; else if (newuserinput.indexOf("how do I" ) ==0) { String substring = newuserinput.substring(8); reply = "do you really want to do that" + substring; } else if (newuserinput.indexOf("how" ) ==0) { String substring = newuserinput.substring(10); reply = "I don't know" + substring ; } return reply; } } Here is my client/application class /** * Java Chatbot Client class * @author Blake * 3/5/2012 */ import java.util.Scanner; public class ChatbotClient { public static void main(String[] args) { Scanner input = new Scanner(System.in); Chatbot t = new Chatbot(); System.out.print("What is your name? "); String name = input.nextLine(); System.out.println(t.introbot()); System.out.print(name + "> "); String reply = input.nextLine(); System.out.println(t.getName() + "> " + t.getreply(reply)); //while (reply < quit) /*{ quit++ i = i + 1 }*/ } } I don't know what I am doing wrong with this part right here Modify the ChatBot client application to loop until the end-user enters "quit". I am trying to create a while loop which will continue until user says quit.

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  • bash : recursive listing of all files problem

    - by Michael Mao
    Run a recursive listing of all the files in /var/log and redirect standard output to a file called lsout.txt in your home directory. Complete this question WITHOUT leaving your home directory. An: ls -R /var/log/ /home/bqiu/lsout.txt I reckon the above bash command is not correct. This is what I've got so far: $ ls -1R .: cal.sh cokemachine.sh dir sort test.sh ./dir: afile.txt file subdir ./dir/subdir: $ ls -R | sed s/^.*://g cal.sh cokemachine.sh dir sort test.sh afile.txt file subdir But this still leaves all directory/sub-directory names (dir and subdir), plus a couple of empty newlines How could I get the correct result without using Perl or awk? Preferably using only basic bash commands(this is just because Perl and awk is out of assessment scope)

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  • Thread scheduling C

    - by MRP
    include <pthread.h> include <stdio.h> include <stdlib.h> #define NUM_THREADS 4 #define TCOUNT 5 #define COUNT_LIMIT 13 int done = 0; int count = 0; int thread_ids[4] = {0,1,2,3}; int thread_runtime[4] = {0,5,4,1}; pthread_mutex_t count_mutex; pthread_cond_t count_threshold_cv; void *inc_count(void *t) { int i; long my_id = (long)t; long run_time = thread_runtime[my_id]; if (my_id==2 && done ==0) { for(i=0; i< 5 ; i++) { if( i==4 ){done =1;} pthread_mutex_lock(&count_mutex); count++; if (count == COUNT_LIMIT) { pthread_cond_signal(&count_threshold_cv); printf("inc_count(): thread %ld, count = %d Threshold reached.\n", my_id, count); } printf("inc_count(): thread %ld, count = %d, unlocking mutex\n", my_id, count); pthread_mutex_unlock(&count_mutex); } } if (my_id==3 && done==1) { for(i=0; i< 4 ; i++) { if(i == 3 ){ done = 2;} pthread_mutex_lock(&count_mutex); count++; if (count == COUNT_LIMIT) { pthread_cond_signal(&count_threshold_cv); printf("inc_count(): thread %ld, count = %d Threshold reached.\n", my_id, count); } printf("inc_count(): thread %ld, count = %d, unlocking mutex\n", my_id, count); pthread_mutex_unlock(&count_mutex); } } if (my_id==4&& done == 2) { for(i=0; i< 8 ; i++) { pthread_mutex_lock(&count_mutex); count++; if (count == COUNT_LIMIT) { pthread_cond_signal(&count_threshold_cv); printf("inc_count(): thread %ld, count = %d Threshold reached.\n",my_id, count); } printf("inc_count(): thread %ld, count = %d, unlocking mutex\n", my_id, count); pthread_mutex_unlock(&count_mutex); } } pthread_exit(NULL); } void *watch_count(void *t) { long my_id = (long)t; printf("Starting watch_count(): thread %ld\n", my_id); pthread_mutex_lock(&count_mutex); if (count<COUNT_LIMIT) { pthread_cond_wait(&count_threshold_cv, &count_mutex); printf("watch_count(): thread %ld Condition signal received.\n", my_id); count += 125; printf("watch_count(): thread %ld count now = %d.\n", my_id, count); } pthread_mutex_unlock(&count_mutex); pthread_exit(NULL); } int main (int argc, char *argv[]) { int i, rc; long t1=1, t2=2, t3=3, t4=4; pthread_t threads[4]; pthread_attr_t attr; pthread_mutex_init(&count_mutex, NULL); pthread_cond_init (&count_threshold_cv, NULL); pthread_attr_init(&attr); pthread_attr_setdetachstate(&attr,PTHREAD_CREATE_JOINABLE); pthread_create(&threads[0], &attr, watch_count, (void *)t1); pthread_create(&threads[1], &attr, inc_count, (void *)t2); pthread_create(&threads[2], &attr, inc_count, (void *)t3); pthread_create(&threads[3], &attr, inc_count, (void *)t4); for (i=0; i<NUM_THREADS; i++) { pthread_join(threads[i], NULL); } printf ("Main(): Waited on %d threads. Done.\n", NUM_THREADS); pthread_attr_destroy(&attr); pthread_mutex_destroy(&count_mutex); pthread_cond_destroy(&count_threshold_cv); pthread_exit(NULL); } so this code creates 4 threads. thread 1 keeps track of the count value while the other 3 increment the count value. the run time is the number of times the thread will increment the count value. I have a done value that allows the first thread to increment the count value first until its run time is up.. so its like a First Come First Serve. my question is, is there a better way of implementing this? I have read about SCHED_FIFO or SCHED_RR.. I guess I dont know how to implement them into this code or if it can be.

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  • An algorithm for pavement usage calculation

    - by student
    Given an area of specific size I need to find out how many pavement stones to use to completely pave the area. Suppose that I have an empty floor of 100 metre squares and stones with 20x10 cm and 30x10 cm sizes. I must pave the area with minimum usage of stones of both sizes. Anyone knows of an algorithm that calculates this? (Sorry if my English is bad) C# is preferred.

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  • How does this code break the Law of Demeter?

    - by Dave Jarvis
    The following code breaks the Law of Demeter: public class Student extends Person { private Grades grades; public Student() { } /** Must never return null; throw an appropriately named exception, instead. */ private synchronized Grades getGrades() throws GradesException { if( this.grades == null ) { this.grades = createGrades(); } return this.grades; } /** Create a new instance of grades for this student. */ protected Grades createGrades() throws GradesException { // Reads the grades from the database, if needed. // return new Grades(); } /** Answers if this student was graded by a teacher with the given name. */ public boolean isTeacher( int year, String name ) throws GradesException, TeacherException { // The method only knows about Teacher instances. // return getTeacher( year ).nameEquals( name ); } private Grades getGradesForYear( int year ) throws GradesException { // The method only knows about Grades instances. // return getGrades().getForYear( year ); } private Teacher getTeacher( int year ) throws GradesException, TeacherException { // This method knows about Grades and Teacher instances. A mistake? // return getGradesForYear( year ).getTeacher(); } } public class Teacher extends Person { public Teacher() { } /** * This method will take into consideration first name, * last name, middle initial, case sensitivity, and * eventually it could answer true to wild cards and * regular expressions. */ public boolean nameEquals( String name ) { return getName().equalsIgnoreCase( name ); } /** Never returns null. */ private synchronized String getName() { if( this.name == null ) { this.name == ""; } return this.name; } } Questions How is the LoD broken? Where is the code breaking the LoD? How should the code be written to uphold the LoD?

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  • big O notation algorithm

    - by niggersak
    Use big-O notation to classify the traditional grade school algorithms for addition and multiplication. That is, if asked to add two numbers each having N digits, how many individual additions must be performed? If asked to multiply two N-digit numbers, how many individual multiplications are required? . Suppose f is a function that returns the result of reversing the string of symbols given as its input, and g is a function that returns the concatenation of the two strings given as its input. If x is the string hrwa, what is returned by g(f(x),x)? Explain your answer - don't just provide the result!

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  • help me to my project [closed]

    - by latha
    hi. plz tel me to how to collect data for my project. as my projct relate to "sustainable urban infrastructure" so help me that what what data should i put to my project.i dont had any idea that how to do vit data analysis .so please direct me .

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  • templates of functions

    - by anotr67
    I'm told to create template of function , that will take 4 arguments : pointer reference pointer to array pointer to function How to perform this task ? I was trying : template<typename TYPE> TYPE biggest(TYPE *L, TYPE $M, TYPE *K[], TYPE *O()) { } but it is wrong.

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  • Can someone help me with this Java Chess game please?

    - by Chris Edwards
    Hey guys, Please can someone have a look at this code and let me know whether I am on the right track with the "check_somefigure_move"s and the "check_black/white_promotion"s please? And also any other help you can give would be greatly appreciated! Thanks! P.S. I know the code is not the best implementation, but its a template I have to follow :( Code: class Moves { private final Board B; private boolean regular; public Moves(final Board b) { B = b; regular = regular_position(); } public boolean get_regular_position() { return regular; } public void set_regular_position(final boolean new_reg) { regular = new_reg; } // checking whether B represents a "normal" position or not; // if not, then only simple checks regarding move-correctness should // be performed, only checking the direct characteristics of the figure // moved; // checks whether there is exactly one king of each colour, there are // no more figures than promotions allow, and there are no pawns on the // first or last rank; public boolean regular_position() { int[] counts = new int[256]; for (char file = 'a'; file <= 'h'; ++file) for (char rank = '1'; rank <= '8'; ++rank) ++counts[(int) B.get(file,rank)]; if (counts[Board.white_king] != 1 || counts[Board.black_king] != 1) return false; if (counts[Board.white_pawn] > 8 || counts[Board.black_pawn] > 8) return false; int count_w_promotions = 0; count_w_promotions += Math.max(counts[Board.white_queen]-1,0); count_w_promotions += Math.max(counts[Board.white_rook]-2,0); count_w_promotions += Math.max(counts[Board.white_bishop]-2,0); count_w_promotions += Math.max(counts[Board.white_knight]-2,0); if (count_w_promotions > 8 - counts[Board.white_pawn]) return false; int count_b_promotions = 0; count_b_promotions += Math.max(counts[Board.black_queen]-1,0); count_b_promotions += Math.max(counts[Board.black_rook]-2,0); count_b_promotions += Math.max(counts[Board.black_bishop]-2,0); count_b_promotions += Math.max(counts[Board.black_knight]-2,0); if (count_b_promotions > 8 - counts[Board.black_pawn]) return false; for (char file = 'a'; file <= 'h'; ++file) { final char fig1 = B.get(file,'1'); if (fig1 == Board.white_pawn || fig1 == Board.black_pawn) return false; final char fig8 = B.get(file,'8'); if (fig8 == Board.white_pawn || fig8 == Board.black_pawn) return false; } return true; } public boolean check_normal_white_move(final char file0, final char rank0, final char file1, final char rank1) { if (! Board.is_valid_white_figure(B.get(file0,rank0))) return false; if (! B.is_empty(file1,rank1) && ! Board.is_valid_black_figure(B.get(file1,rank1))) return false; if (B.get_active_colour() != 'w') return false; if (! check_move_simple(file0,rank0,file1,rank1)) return false; if (! regular) return true; final Board test_board = new Board(B); test_board.normal_white_move_0(file0,rank0,file1,rank1); final Moves test_move = new Moves(test_board); final char[] king_pos = test_move.white_king_position(); assert(king_pos.length == 2); return test_move.black_not_attacking(king_pos[0],king_pos[1]); } public boolean check_normal_black_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED THE CHECK NORMAL BLACK MOVE BASED ON THE CHECK NORMAL WHITE MOVE if (! Board.is_valid_black_figure(B.get(file0,rank0))) return false; if (! B.is_empty(file1,rank1) && ! Board.is_valid_white_figure(B.get(file1,rank1))) return false; if (B.get_active_colour() != 'b') return false; if (! check_move_simple(file0,rank0,file1,rank1)) return false; if (! regular) return true; final Board test_board = new Board(B); test_board.normal_black_move_0(file0,rank0,file1,rank1); final Moves test_move = new Moves(test_board); final char[] king_pos = test_move.black_king_position(); assert(king_pos.length == 2); return test_move.white_not_attacking(king_pos[0],king_pos[1]); } // for checking a normal move by just applying the move-rules private boolean check_move_simple(final char file0, final char rank0, final char file1, final char rank1) { final char fig = B.get(file0,rank0); if (fig == Board.white_king || fig == Board.black_king) return check_king_move(file0,rank0,file1,rank1); if (fig == Board.white_queen || fig == Board.black_queen) return check_queen_move(file0,rank0,file1,rank1); if (fig == Board.white_rook || fig == Board.black_rook) return check_rook_move(file0,rank0,file1,rank1); if (fig == Board.white_bishop || fig == Board.black_bishop) return check_bishop_move(file0,rank0,file1,rank1); if (fig == Board.white_knight || fig == Board.black_knight) return check_knight_move(file0,rank0,file1,rank1); if (fig == Board.white_pawn) return check_white_pawn_move(file0,rank0,file1,rank1); else return check_black_pawn_move(file0,rank0,file1,rank1); } private boolean check_king_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED KING MOVE int fileChange = file0 - file1; int rankChange = rank0 - rank1; return fileChange <= 1 && fileChange >= -1 && rankChange <= 1 && rankChange >= -1; } private boolean check_queen_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED QUEEN MOVE int fileChange = file0 - file1; int rankChange = rank0 - rank1; return fileChange <=8 && fileChange >= -8 && rankChange <= 8 && rankChange >= -8; } private boolean check_rook_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED ROOK MOVE int fileChange = file0 - file1; int rankChange = rank0 - rank1; return fileChange <=8 || fileChange >= -8 || rankChange <= 8 || rankChange >= -8; } private boolean check_bishop_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED BISHOP MOVE int fileChange = file0 - file1; int rankChange = rank0 - rank1; return fileChange <= 8 && rankChange <= 8 || fileChange <= 8 && rankChange >= -8 || fileChange >= -8 && rankChange >= -8 || fileChange >= -8 && rankChange <= 8; } private boolean check_knight_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED KNIGHT MOVE int fileChange = file0 - file1; int rankChange = rank0 - rank1; /* IS THIS THE CORRECT WAY? * return fileChange <= 1 && rankChange <= 2 || fileChange <= 1 && rankChange >= -2 || fileChange <= 2 && rankChange <= 1 || fileChange <= 2 && rankChange >= -1 || fileChange >= -1 && rankChange <= 2 || fileChange >= -1 && rankChange >= -2 || fileChange >= -2 && rankChange <= 1 || fileChange >= -2 && rankChange >= -1;*/ // OR IS THIS? return fileChange <= 1 || fileChange >= -1 || fileChange <= 2 || fileChange >= -2 && rankChange <= 1 || rankChange >= - 1 || rankChange <= 2 || rankChange >= -2; } private boolean check_white_pawn_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED PAWN MOVE int fileChange = file0 - file1; int rankChange = rank0 - rank1; return fileChange == 0 && rankChange <= 1; } private boolean check_black_pawn_move(final char file0, final char rank0, final char file1, final char rank1) { // ADDED PAWN MOVE int fileChange = file0 - file1; int rankChange = rank0 - rank1; return fileChange == 0 && rankChange >= -1; } public boolean check_white_kingside_castling() { // only demonstration code: final char c = B.get_white_castling(); if (c == '-' || c == 'q') return false; if (B.get_active_colour() == 'b') return false; if (B.get('e','1') != 'K') return false; if (! black_not_attacking('e','1')) return false; if (! free_white('f','1')) return false; // XXX return true; } public boolean check_white_queenside_castling() { // only demonstration code: final char c = B.get_white_castling(); if (c == '-' || c == 'k') return false; if (B.get_active_colour() == 'b') return false; // ADDED BASED ON KINGSIDE CASTLING if (B.get('e','1') != 'Q') return false; if (! black_not_attacking('e','1')) return false; if (! free_white('f','1')) return false; // XXX return true; } public boolean check_black_kingside_castling() { // only demonstration code: final char c = B.get_black_castling(); if (c == '-' || c == 'q') return false; if (B.get_active_colour() == 'w') return false; // ADDED BASED ON CHECK WHITE if (B.get('e','8') != 'K') return false; if (! black_not_attacking('e','8')) return false; if (! free_white('f','8')) return false; // XXX return true; } public boolean check_black_queenside_castling() { // only demonstration code: final char c = B.get_black_castling(); if (c == '-' || c == 'k') return false; if (B.get_active_colour() == 'w') return false; // ADDED BASED ON KINGSIDE CASTLING if (B.get('e','8') != 'Q') return false; if (! black_not_attacking('e','8')) return false; if (! free_white('f','8')) return false; // XXX return true; } public boolean check_white_promotion(final char pawn_file, final char figure) { // XXX // ADDED CHECKING FOR CORRECT FIGURE AND POSITION - ALTHOUGH IT SEEMS AS THOUGH // PAWN_FILE SHOULD BE PAWN_RANK, AS IT IS THE REACHING OF THE END RANK THAT // CAUSES PROMOTION OF A PAWN, NOT FILE if (figure == P && pawn_file == 8) { return true; } else return false; } public boolean check_black_promotion(final char pawn_file, final char figure) { // XXX // ADDED CHECKING FOR CORRECT FIGURE AND POSITION if (figure == p && pawn_file == 1) { return true; } else return false; } // checks whether black doesn't attack the field: public boolean black_not_attacking(final char file, final char rank) { // XXX return true; } public boolean free_white(final char file, final char rank) { // XXX return black_not_attacking(file,rank) && B.is_empty(file,rank); } // checks whether white doesn't attack the field: public boolean white_not_attacking(final char file, final char rank) { // XXX return true; } public boolean free_black(final char file, final char rank) { // XXX return white_not_attacking(file,rank) && B.is_empty(file,rank); } public char[] white_king_position() { for (char file = 'a'; file <= 'h'; ++file) for (char rank = '1'; rank <= '8'; ++rank) if (B.get(file,rank) == Board.white_king) { char[] result = new char[2]; result[0] = file; result[1] = rank; return result; } return new char[0]; } public char[] black_king_position() { for (char file = 'a'; file <= 'h'; ++file) for (char rank = '1'; rank <= '8'; ++rank) if (B.get(file,rank) == Board.black_king) { char[] result = new char[2]; result[0] = file; result[1] = rank; return result; } return new char[0]; } public static void main(final String[] args) { // checking regular_position { Moves m = new Moves(new Board()); assert(m.regular_position()); m = new Moves(new Board("8/8/8/8/8/8/8/8 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("KK6/8/8/8/8/8/8/8 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("kk6/8/8/8/8/8/8/8 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kk6/8/8/8/8/8/8/8 w - - 0 1")); assert(m.regular_position()); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/8 w - - 0 1")); assert(m.regular_position()); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/n7 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/N7 w - - 0 1")); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/b7 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/B7 w - - 0 1")); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/r7 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/R7 w - - 0 1")); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/q7 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kk6/qqqqqqqq/QQQQQQQQ/Q7/q7/rrbbnn2/RRBBNN2/Q7 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kkp5/8/8/8/8/8/8/8 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("KkP5/8/8/8/8/8/8/8 w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kk6/8/8/8/8/8/8/7p w - - 0 1")); assert(!m.regular_position()); m = new Moves(new Board("Kk6/8/8/8/8/8/8/7P w - - 0 1")); assert(!m.regular_position()); } // checking check_white/black_king/queenside_castling { Moves m = new Moves(new Board("4k2r/8/8/8/8/8/8/4K2R w Kk - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("4k2r/8/8/8/8/8/8/4K2R b Kk - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("4k2r/4pppp/8/8/8/8/4PPPP/4K2R w KQkq - 0 1")); assert(m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("4k2r/4pppp/8/8/8/8/4PPPP/4K2R b KQkq - 0 1")); assert(!m.check_white_kingside_castling()); assert(m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("r3k3/8/8/8/8/8/8/R3K3 w Qq - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("r3k3/8/8/8/8/8/8/R3K3 b Qq - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("r3k3/p7/8/8/8/8/8/R3K3 w Qq - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("r3k3/p7/8/8/8/8/8/R3K3 b Qq - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(m.check_black_queenside_castling()); m = new Moves(new Board("r3k3/p7/8/8/8/n7/8/R3K3 w Qq - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); m = new Moves(new Board("r3k3/p7/B7/8/8/8/8/R3K3 b Qq - 0 1")); assert(!m.check_white_kingside_castling()); assert(!m.check_black_kingside_castling()); assert(!m.check_white_queenside_castling()); assert(!m.check_black_queenside_castling()); // XXX } } }

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  • Regular expression for a phone number

    - by Zerobu
    Hello, I would like a regular expression in this format. It Must match one of the following formats: * (###)###-#### * ###-###-#### * ###.###.#### * ########## Strip all whitespace. Make sure it's a valid phone number, then (if necessary) translate it to the first format listed above.

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  • forks in C - exercise

    - by Zka
    I try to repeat and learn more advanced uses and options when cutting trees with forks in the jungle of C. But foolishly I find an example which should be very easy as I have worked with forks before and even written some code, but i can't understand it fully. Here comes : main() { if (fork() == 0) { if (fork() == 0) { printf("3"); } else if ((wait(NULL)) > 0) { printf("2"); } } else { if (fork() == 0) { printf("1"); exit(0); } if (fork() == 0) { printf("4"); } } printf("0"); return 0; } Possible solutions are : 3201040 3104200 1040302 4321000 4030201 1403020 where 2, 5 and 6 are correct answers. First of all, shouldn't there be four zeroes in the output? Second... How does one come to the solution at all? Been doing this on paper for almost an hour and I'm not even close to understanding why the given solution are more correct than the false ones (except for nr3 as it can't end with 2 since a 0 must follow). Anyone with his forks in check who can offer some good explanation?

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  • Fread binary file dynamic size string [C]

    - by Blackbinary
    I've been working on this assignment, where I need to read in "records" and write them to a file, and then have the ability to read/find them later. On each run of the program, the user can decide to write a new record, or read an old record (either by Name or #) The file is binary, here is its definition: typedef struct{ char * name; char * address; short addressLength, nameLength; int phoneNumber; }employeeRecord; employeeRecord record; The way the program works, it will store the structure, then the name, then the address. Name and address are dynamically allocated, which is why it is necessary to read the structure first to find the size of the name and address, allocate memory for them, then read them into that memory. For debugging purposes I have two programs at the moment. I have my file writing program, and file reading. My actual problem is this, when I read a file I have written, i read in the structure, print out the phone # to make sure it works (which works fine), and then fread the name (now being able to use record.nameLength which reports the proper value too). Fread however, does not return a usable name, it returns blank. I see two problems, either I haven't written the name to the file correctly, or I haven't read it in correctly. Here is how i write to the file: where fp is the file pointer. record.name is a proper value, so is record.nameLength. Also i am writing the name including the null terminator. (e.g. 'Jack\0') fwrite(&record,sizeof record,1,fp); fwrite(record.name,sizeof(char),record.nameLength,fp); fwrite(record.address,sizeof(char),record.addressLength,fp); And i then close the file. here is how i read the file: fp = fopen("employeeRecord","r"); fread(&record,sizeof record,1,fp); printf("Number: %d\n",record.phoneNumber); char *nameString = malloc(sizeof(char)*record.nameLength); printf("\nName Length: %d",record.nameLength); fread(nameString,sizeof(char),record.nameLength,fp); printf("\nName: %s",nameString); Notice there is some debug stuff in there (name length and number, both of which are correct). So i know the file opened properly, and I can use the name length fine. Why then is my output blank, or a newline, or something like that? (The output is just Name: with nothing after it, and program finishes just fine) Thanks for the help.

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  • How can I reverse a stack?

    - by come pollinate me
    I need to write a VB.NET code to reverse the given characters using a stack. Input: 'S','T','A','C','K' So far I have input the letters, but I don't know how to get the console to reverse it. I'm a beginner to programming so please excuse my ignorance. An explanation as to how it's done would also be greatly appreciated. What I got so far. Module Module1 Sub Main() Dim StackObject As New Stack StackObject.Push("S") Console.WriteLine(StackObject.Peek) StackObject.Push("T") Console.WriteLine(StackObject.Peek) StackObject.Push("A") Console.WriteLine(StackObject.Peek) StackObject.Push("C") Console.WriteLine(StackObject.Peek) StackObject.Push("K") Console.WriteLine(StackObject.Peek) End Sub End Module I just need it to be reversed. I got it!! Module Module1 Sub Main() Dim StackObject As New Stack StackObject.Push("S") StackObject.Push("T") StackObject.Push("A") StackObject.Push("C") StackObject.Push("K") For Each cur As String In StackObject Console.WriteLine(cur) Next End Sub End Module That's how it's done.

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  • pointers to functions

    - by DevAno1
    I have two basic Cpp tasks, but still I have problems with them. First is to write functions mul1,div1,sub1,sum1, taking ints as arguments and returning ints. Then I need to create pointers ptrFun1 and ptrFun2 to functions mul1 and sum1, and print results of using them. Problem starts with defining those pointers. I thought I was doing it right, but devcpp gives me errors in compilation. #include <iostream> using namespace std; int mul1(int a,int b) { return a * b; } int div1(int a,int b) { return a / b; } int sum1(int a,int b) { return a + b; } int sub1(int a,int b) { return a - b; } int main() { int a=1; int b=5; cout << mul1(a,b) << endl; cout << div1(a,b) << endl; cout << sum1(a,b) << endl; cout << sub1(a,b) << endl; int *funPtr1(int, int); int *funPtr2(int, int); funPtr1 = sum1; funPtr2 = mul1; cout << funPtr1(a,b) << endl; cout << funPtr2(a,b) << endl; system("PAUSE"); return 0; } 38 assignment of function int* funPtr1(int, int)' 38 cannot convertint ()(int, int)' to `int*()(int, int)' in assignment Task 2 is to create array of pointers to those functions named tabFunPtr. How to do that ?

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  • Relational Clausal Logic question: what is a Herbrand interpretation

    - by anotherstat
    I'm having a hard time coming to grips with relational clausal logic, and I'm not sure if this is the place to ask but it would be help me so much with revision if anyone could provide guidance with the following questions. Let P be the program: academic(X); student(X); other_staff(X):- works_in(X, university). :-student(john). :-other_staff(john). works_in(john, university) Question: Which are the Herbrand interpreations of P? AS

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  • Scheme sorting a list

    - by John
    Okay so I am trying to take in a list and sort it from greatest to smallest. Example: > (maxheap (list 5 6 2 1 18 7)) ;output: > (18 7 6 5 2 1) So here's what I got so far: (define (mkmaxheap heaplist) (let ((max (mymax(heaplist)))) ;mymax is a func that returns max number, it works (let (( head (car heaplist)) (tail (cdr heaplist))) (if (null? tail) newlist)))) Thats all I could get to compile, all the other code I wrote failed. Any help on solving this would be much appreciated.

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  • Bash and regex problem : check for tokens entered into a Coke vending machine

    - by Michael Mao
    Hi all: Here is a "challenge question" I've got from Linux system programming lecture. Any of the following strings will give you a Coke if you kick: L = { aaaa, aab, aba, baa, bb, aaaa"a", aaaa"b", aab"a", … ab"b"a, ba"b"a, ab"bbbbbb"a, ... } The letters shown in wrapped double quotes indicate coins that would have fallen through (but those strings are still part of the language in this example). Exercise (a bit hard) show this is the language of a regular expression And this is what I've got so far : #!/usr/bin/bash echo "A bottle of Coke costs you 40 cents" echo -e "Please enter tokens (a = 10 cents, b = 20 cents) in a sequence like 'abba' :\c" read tokens #if [ $tokens = aaaa ]||[ $tokens = aab ]||[ $tokens = bb ] #then # echo "Good! now a coke is yours!" #else echo "Thanks for your money, byebye!" if [[ $token =~ 'aaaa|aab|bb' ]] then echo "Good! now a coke is yours!" else echo "Thanks for your money, byebye!" fi Sadly it doesn't work... always outputs "Thanks for your money, byebye!" I believe something is wrong with syntax... We didn't provided with any good reference book and the only instruction from the professor was to consult "anything you find useful online" and "research the problem yourself" :( I know how could I do it in any programming language such as Java, but get it done with bash script + regex seems not "a bit hard" but in fact "too hard" for anyone with little knowledge on something advanced as "lookahead"(is this the terminology ?) I don't know if there is a way to express the following concept in the language of regex: Valid entry would consist of exactly one of the three components : aaaa, aab and bb, regardless of order, followed by an arbitrary sequence of a or b's So this is what is should be like : (a{4}Ua{2}bUb{2})(aUb)* where the content in first braces is order irrelevant. Thanks a lot in advance for any hints and/or tips :)

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