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  • Ajax: Load XML from different domain?

    - by John Isaacks
    I have signed up(paid) for Google site search. They have me a url of a sort of web service where I can send a query to it, it searches my site, and it returns XML of the search results. Well I am trying to load this XML via Ajax from a page on my site but I cannot. I can load from any of my pages on my domain so I am assuming it is because of the XML being on Google's domain. So there has got to be a way to load it though, I don't think they would have given me the URL if I couldn't do anything with it lol. Does anyone know how to do this? Thanks! UPDATE: this is what the page says on google that gave me the XML: How to get XML You can get XML results for your search engine by replacing query+terms with your search query in this URL: http://www.google.com/cse?cx=MY_UNIQUE_KEY&client=google-csbe&output=xml_no_dtd&q=query+terms Where MY_UNIQUE_KEY = my unique key.

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  • How to tell a method has a varargs argument using reflection?

    - by Anthony Kong
    Here is a sample code package org.example; import java.lang.reflect.Method; class TestRef { public void testA(String ... a) { for (String i : a) { System.out.println(i); } } public static void main(String[] args){ Class testRefClass = TestRef.class; for (Method m: testRefClass.getMethods()) { if (m.getName() == "testA") { System.out.println(m); } } } } The output is public void org.example.TestRef.testA(java.lang.String[]) So the signature of the method is reported to take a array of String. Is there any mean in the reflection library I can tell that the method is originally declared to take a varargs?

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  • How would you go about tackling this problem? [SOLVED in C++]

    - by incrediman
    Intro: EDIT: See solution at the bottom of this question (c++) I have a programming contest coming up in about half a week, and I've been prepping :) I found a bunch of questions from this canadian competition, they're great practice: http://cemc.math.uwaterloo.ca/contests/computing/2009/stage2/day1.pdf I'm looking at problem B ("Dinner"). Any idea where to start? I can't really think of anything besides the naive approach (ie. trying all permutations) which would take too long to be a valid answer. Btw, the language there says c++ and pascal I think, but i don't care what language you use - I mean really all I want is a hint as to the direction I should proceed in, and perhpas a short explanation to go along with it. It feels like I'm missing something obvious... Of course extended speculation is more than welcome, but I just wanted to clarify that I'm not looking for a full solution here :) Short version of the question: You have a binary string N of length 1-100 (in the question they use H's and G's instead of one's and 0's). You must remove all of the digits from it, in the least number of steps possible. In each step you may remove any number of adjacent digits so long as they are the same. That is, in each step you can remove any number of adjacent G's, or any number of adjacent H's, but you can't remove H's and G's in one step. Example: HHHGHHGHH Solution to the example: 1. HHGGHH (remove middle Hs) 2. HHHH (remove middle Gs) 3. Done (remove Hs) -->Would return '3' as the answer. Note that there can also be a limit placed on how large adjacent groups have to be when you remove them. For example it might say '2', and then you can't remove single digits (you'd have to remove pairs or larger groups at a time). Solution I took Mark Harrison's main algorithm, and Paradigm's grouping idea and used them to create the solution below. You can try it out on the official test cases if you want. //B.cpp //include debug messages? #define DEBUG false #include <iostream> #include <stdio.h> #include <vector> using namespace std; #define FOR(i,n) for (int i=0;i<n;i++) #define FROM(i,s,n) for (int i=s;i<n;i++) #define H 'H' #define G 'G' class String{ public: int num; char type; String(){ type=H; num=0; } String(char type){ this->type=type; num=1; } }; //n is the number of bits originally in the line //k is the minimum number of people you can remove at a time //moves is the counter used to determine how many moves we've made so far int n, k, moves; int main(){ /*Input from File*/ scanf("%d %d",&n,&k); char * buffer = new char[200]; scanf("%s",buffer); /*Process input into a vector*/ //the 'line' is a vector of 'String's (essentially contigious groups of identical 'bits') vector<String> line; line.push_back(String()); FOR(i,n){ //if the last String is of the correct type, simply increment its count if (line.back().type==buffer[i]) line.back().num++; //if the last String is of the wrong type but has a 0 count, correct its type and set its count to 1 else if (line.back().num==0){ line.back().type=buffer[i]; line.back().num=1; } //otherwise this is the beginning of a new group, so create the new group at the back with the correct type, and a count of 1 else{ line.push_back(String(buffer[i])); } } /*Geedily remove groups until there are at most two groups left*/ moves=0; int I;//the position of the best group to remove int bestNum;//the size of the newly connected group the removal of group I will create while (line.size()>2){ /*START DEBUG*/ if (DEBUG){ cout<<"\n"<<moves<<"\n----\n"; FOR(i,line.size()) printf("%d %c \n",line[i].num,line[i].type); cout<<"----\n"; } /*END DEBUG*/ I=1; bestNum=-1; FROM(i,1,line.size()-1){ if (line[i-1].num+line[i+1].num>bestNum && line[i].num>=k){ bestNum=line[i-1].num+line[i+1].num; I=i; } } //remove the chosen group, thus merging the two adjacent groups line[I-1].num+=line[I+1].num; line.erase(line.begin()+I);line.erase(line.begin()+I); moves++; } /*START DEBUG*/ if (DEBUG){ cout<<"\n"<<moves<<"\n----\n"; FOR(i,line.size()) printf("%d %c \n",line[i].num,line[i].type); cout<<"----\n"; cout<<"\n\nFinal Answer: "; } /*END DEBUG*/ /*Attempt the removal of the last two groups, and output the final result*/ if (line.size()==2 && line[0].num>=k && line[1].num>=k) cout<<moves+2;//success else if (line.size()==1 && line[0].num>=k) cout<<moves+1;//success else cout<<-1;//not everyone could dine. /*START DEBUG*/ if (DEBUG){ cout<<" moves."; } /*END DEBUG*/ }

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  • How to use the textbox value to fetch the records and to display it in the same page

    - by Aruna
    Hi, i am having a Form like <script language="javascript" type="text/javascript"> function formfn() { var str = document.getElementById('TitleSearch').value; alert(str);//displays the keyword like database } </script> <form name="f1" method="post"> <p><label for="TitleSearch">Keywords:</label> <input title="Keyword" size="40" value="" id="TitleSearch"></p> <p> <input type="submit" id="im-search" value="Search" name="im-search" onClick="formfn();"></p> </form> I am having a page where in the top i have this form on search it has to take the value of the textbox TitleSearch and to use this to retrieve the records matching by <?php $db =& JFactory::getDBO(); $query = 'SELECT * from #__chronoforms_Publications where keyword like "%valueretrieved%" '; $db->setQuery($query); $rows = $db->loadObjectList(); //echo $rows; ?> Once the search button is clicked the text box value of the keyword is retrieved . I am trying to use this value in the select query to fetch the records and to display in the same page.. How to do so..

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  • Nested preference screens lose theming

    - by stealthcopter
    I have a preference screen for my application and in the manifest I have given it a theme using: android:theme="@android:style/Theme.Light.WallpaperSettings" However when I nest another preference screen inside this one such as: <?xml version="1.0" encoding="utf-8"?> <PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android" android:title="@string/setting_title" android:key="..."> <PreferenceCategory android:title="@string/title_themes" > <PreferenceScreen android:title="@string/title_themes_opt" > <ListPreference android:key="Setting_BG" android:title="@string/setting_bg" android:summary="@string/setting_bg_summary" android:entries="@array/bg_titles" android:defaultValue="0" android:entryValues="@array/bg_values" /> </PreferenceScreen> </PreferenceCategory> </PreferenceScreen> The nested preference screen loses the theme of the parent. How can this be prevented? Thanks in advance.

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  • How to manually verify a user against the asp.net memberhip database

    - by Ekk
    I would like to know how I can verify a user's credential against an existing asp.net membership database. The short story is that we want provide single sign on access. So what I've done is to connect directly to the membership database and tried to run a sql query against the aspnet_Membership table: private bool CanLogin(string userName, string password) { // Check DB to see if the credential is correct try { string passwordHash = FormsAuthentication.HashPasswordForStoringInConfigFile(password, "SHA1"); string sql = string.Format("select 1 from aspnet_Users a inner join aspnet_Membership b on a.UserId = b.UserId and a.applicationid = b.applicationid where a.username = '{0}' and b.password='{1}'", userName.ToLowerInvariant(), passwordHash); using (SqlConnection sqlConn = new SqlConnection(ConfigurationManager.ConnectionStrings["LocalSqlServer"].ConnectionString)) using (SqlCommand sqlCmd = new SqlCommand(sql, sqlConn)) { sqlConn.Open(); int count = sqlCmd.ExecuteNonQuery(); sqlConn.Close(); return count == 1; } } catch (Exception ex) { return false; } } The problem is the password value, does anyone know how the password it is hashed?

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  • ASP.NET C# Application Object Getters and Setters

    - by kellax
    I have had a hard time finiding a newbie friendly example of accessing Application Object. I have few things ( arrays ) i would like to store in Application Object to keep as persistant data for about 2h till AppRecycle Anyhow i know how to set an Application Object variable this way: // One way String[] users = new String[1000]; Application["users"] = users; // Another way Application.Add("users", users); However i do not know how to access these variables once in Application Object there is a Getter method Get however it requires int index and other one Contents which get's everything. Here i try to retrive my String[] array but gives me a error that i am trying to convert Object to String. String[] usersTable = Application["users"]; // Since this is an object i also tried Application.users but gives error

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  • scanf formatting issue

    - by da_rockwilder
    I have a log file with the following format: INFO 2011-03-09 10:26:15,270 [user] message I want to parse the log file using PHP: // assume file exists and all that $handle = fopen("log_file.txt", "r"); while ($line_data = fscanf($handle, "%s %s %s [%s] %s\n")) { var_dump($line_data); } fclose($handle); When I run this code I get: [0]=> array(5) { [0]=> string(4) "INFO" [1]=> string(10) "2011-03-09" [2]=> string(12) "10:26:15,270" [3]=> string(5) "user]" [4]=> NULL } // snip It appears the closing bracket in the format string ("%s %s %s [%s] %s") is disrupting the rest of the line from getting parsed. I checked the PHP docs for scanf (as suggested by fscanf), and I didn't see anything mentioning having to escape a left bracket. Any suggestions on how to get the 4th and 5th elements to look like "user" and "message" respectively?

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  • Is it a bad idea to use the new Dynamic Keyword as a replacement switch statement?

    - by WeNeedAnswers
    I like the new Dynamic keyword and read that it can be used as a replacement visitor pattern. It makes the code more declarative which I prefer. Is it a good idea though to replace all instances of switch on 'Type' with a class that implements dynamic dispatch. class VistorTest { public string DynamicVisit(object obj) { return Visit((dynamic)obj); } private string Visit(string str) { return "a string was called with value " + str; } private string Visit(int value) { return "an int was called with value " + value; } }

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  • Using charAt in java

    - by ThuL?nå F?rñ?nDö
    This is my assignment: Write a program where the user enters a string, and the program echoes it to the monitor with one character per line: C:\>java LinePerChar Enter a string: Octopus O c t o p u s I have tried, but I'm getting some compilation errors. Here's my code: import java.util.*; class CharactorEcho{ public static void main(String args []){ Scanner sc = new Scanner(System.in); System.out.println("Enter a string :"); try { String inputString = sc.nextLine(); for(int i=0; i < sc.length(); i++) { char c = inputString.charAt(i); System.out.println("" + c); } } catch(IOException e) { } } }

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  • Regexp look-behind to match internet speeds

    - by Sandman
    So the user may search for "10 mbit" after which I want to capture the "10" so I can use it in a speed-search rather than a string-search. This isn't a problem, the below regexp does this fine: if (preg_match("/(\d+)\smbit/", $string)){ ... } But, the user may search for something like "10/10 mbit" or "10-100 mbit". I don't want to match those with the above regexp - they should be handled in another fashion. So I would like a regexp that matches "10 mbit" if the number is all-numeric as a whole word (i.e. contained by whitespace, newline or lineend/linestart) Using lookbehind, I did this: if (preg_match("#(?<!/)(\d+)\s+mbit#i", $string)){ Just to catch those that doesn't have "/" before them, but this matched true for this string: "10/10 mbit" so I'm obviously doing something wrong here, but what?

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  • Repeat over files in a File > Open dialog with Applescript

    - by GotNoSugarBaby
    In the below script I use an Application other than Finder to launch an "Open" browser and perform a search in it. I've got the window into the state I want, but whatever I try can't access the list of files to repeat over. If anyone can help by adding the code to repeat over that file list and log out the file path of each file it'd be a huge help. Thanks a lot. tell application "Preview" -- start the app activate -- let it boot up delay 3 -- ensure it still has focus activate end tell tell application "System Events" tell process "Preview" -- spawn "Open" window keystroke "o" using {command down} delay 0.5 -- spawn "Go to" window keystroke "g" using {command down, shift down} delay 0.5 -- expand scope of search to all of this mac keystroke "/" keystroke return delay 0.5 -- spawn search field keystroke "f" using {command down} delay 0.5 -- perform search keystroke ".jpg OR .jpeg" keystroke return end tell end tell

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  • .htaccess, two consecutive rewrites?

    - by Matthew Haworth
    I need to take a url, "/ServiceSearch/r.php?n=blahblah", and have it go to "/search/blahblah/" so that it appears in the browser as "/search/blahblah", but I actually want it to REALLY be going to "r.php?n=ServiceSearch&n=blahblah".. So I was thinking I'll need to rewrite the first URL to "/ServiceSearch/r.php?n=blahblah" and then the second url, "/search/blahblah/", to the third, "r.php?n=ServiceSearch&n=blahblah". Well, I know this is wrong, but it's my best guess. I'm really struggling with it.

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  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

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  • A column ID occurred more than once in the specification

    - by Puzzle84
    Recently i've picked up my EF 4.1 / MVC 3 project again and started building in actual frontend capabilities. Now i'm developing a "simple" message system but upon going to that page i get the error as stated in the title EDIT It creates the database just not the models. Stack trace: [NullReferenceException: Object reference not set to an instance of an object.] ASP._Page_Views_Inbox_Index_cshtml.Execute() in c:\Development\MVC\DOCCL\Views\Inbox\Index.cshtml:18 System.Web.WebPages.WebPageBase.ExecutePageHierarchy() +197 System.Web.Mvc.WebViewPage.ExecutePageHierarchy() +81 System.Web.WebPages.StartPage.RunPage() +17 System.Web.WebPages.StartPage.ExecutePageHierarchy() +62 System.Web.WebPages.WebPageBase.ExecutePageHierarchy(WebPageContext pageContext, TextWriter writer, WebPageRenderingBase startPage) +76 System.Web.Mvc.RazorView.RenderView(ViewContext viewContext, TextWriter writer, Object instance) +222 System.Web.Mvc.BuildManagerCompiledView.Render(ViewContext viewContext, TextWriter writer) +115 System.Web.Mvc.ViewResultBase.ExecuteResult(ControllerContext context) +295 System.Web.Mvc.ControllerActionInvoker.InvokeActionResult(ControllerContext controllerContext, ActionResult actionResult) +13 System.Web.Mvc.<c_DisplayClass1c.b_19() +23 System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func1 continuation) +242 System.Web.Mvc.<>c__DisplayClass1e.<InvokeActionResultWithFilters>b__1b() +21 System.Web.Mvc.ControllerActionInvoker.InvokeActionResultWithFilters(ControllerContext controllerContext, IList1 filters, ActionResult actionResult) +177 System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName) +324 System.Web.Mvc.Controller.ExecuteCore() +106 System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext) +91 System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext) +10 System.Web.Mvc.<c_DisplayClassb.b_5() +34 System.Web.Mvc.Async.<c_DisplayClass1.b_0() +19 System.Web.Mvc.Async.<c_DisplayClass81.<BeginSynchronous>b__7(IAsyncResult _) +10 System.Web.Mvc.Async.WrappedAsyncResult1.End() +62 System.Web.Mvc.<c_DisplayClasse.b_d() +48 System.Web.Mvc.SecurityUtil.b_0(Action f) +7 System.Web.Mvc.SecurityUtil.ProcessInApplicationTrust(Action action) +22 System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult) +60 System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result) +9 System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +9478661 System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +178 InnerException : {"A column ID occurred more than once in the specification."} The recently added code is. Controller: // // GET: /Inbox/Index/5/1 public ActionResult Index(int? Id, int Page = 1) { try { const int pageSize = 10; var messages = from m in horseTracker.Messages where m.ReceiverId.Equals(Id) select m; var paginatedMessages = new PaginatedList<Message>(messages, Page, pageSize); return View(paginatedMessages); } catch (Exception ex) { } return View(); } Models public class Message { [Key] public int Id { get; set; } [Required(ErrorMessage = "Subject is required")] [Display(Name = "Subject")] public string Subject { get; set; } [Required(ErrorMessage = "Message is required")] [Display(Name = "Message")] public string Content { get; set; } [Required] [Display(Name = "Date")] public DateTime Created { get; set; } public Boolean Read { get; set; } [Required(ErrorMessage = "Can't create a message without a user")] public int SenderId { get; set; } public virtual User Sender { get; set; } [Required(ErrorMessage = "Please pick a recipient")] public int ReceiverId { get; set; } public virtual User Receiver { get; set; } } public class User { [Key] public int Id { get; set; } [Required] [Display(Name = "Username")] public string UserName { get; set; } [Required] [Display(Name = "First Name")] public string FirstName { get; set; } [Required] [Display(Name = "Last Name")] public string LastName { get; set; } [Required] [Display(Name = "E-Mail")] public string Email { get; set; } [Required] [Display(Name = "Password")] public string Password { get; set; } [Required] [Display(Name = "Country")] public string Country { get; set; } public string EMail { get; set; } //Races public virtual ICollection<Message> Messages { get; set; } } modelBuilder.Entity<User>() .HasMany(u => u.Messages) .WithRequired(m => m.Receiver) .HasForeignKey(m => m.ReceiverId) .WillCascadeOnDelete(false); Anyone have a clue on why i might be getting that error? Before i added these classes it was working fine.

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  • Receiving the post response using curl

    - by Larry Battle
    Hello, I'm trying to make a script that will download search results from a HTTPS website using POST. So far, I'm able to download the web page before the submission but not the response page containing the search results. The problem seems to be that curl isn't waiting long enough for the response page to appear. The website behaviors likes this. Website appears- input form data - click submit - progressing icon appears - returns new web page with search results( new data but the url doesn't change ) My code: curl -d "postData" -k url

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  • Java: how to use Google's HashBiMap?

    - by HH
    Keys are a file and a word. The file gives all words inside the file. The word gives all files having the word. I am unsure of the domain and co-domain parts. I want K to be of the type <String> and V to be of type <HashSet<FileObject>>. public HashBiMap<K<String>,V<HashSet<FileObject>>> wordToFiles = new HashBiMap<K<String>,V<HashSet<FileObject>>>(); public HashBiMap<K<String>,V<HashSet<FileObject>>> fileToWords = new HashBiMap<K<String>,V<HashSet<FileObject>>>(); Google's HashBiMap.

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  • Error Instantiating an Inner Class in Parent's Constructor...

    - by stormin986
    In my application's main class (subclass of Application), I have a public inner class that simply contains 3 public string objects. In the parent class I declare an object of that inner class. public class MainApplication extends Application { public class Data { public String x; public String y; public String z; } private Data data; MainApplication() { data = new Data() data.x = "String"; } } After I instantiate the object in the constructor, I get a runtime error when I try to assign any of the inner class object's variables. Any idea what's up here??

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  • Java 7 API design best practice - return Array or return Collection

    - by Shengjie
    I know this question has be asked before generic comes out. Array does win out a bit given Array enforces the return type, it's more type-safe. But now, with latest JDK 7, every time when I design this type of APIs: public String[] getElements(String type) vs public List<String> getElements(String type) I am always struggling to think of some good reasons to return A Collection over An Array or another way around. What's the best practice when it comes to the case of choosing String[] or List as the API's return type? Or it's courses for horses. I don't have a special case in my mind, I am more looking for a generic pros/cons comparison.

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  • Is an ArrayList automaticaly declared static in Java, if it is an instance variable?

    - by Alex
    I'm trying to do something like this: private class aClass { private ArrayList<String> idProd; aClass(ArrayList<String> prd) { this.idProd=new ArrayList<String>(prd); } public ArrayList<String> getIdProd() { return this.idProd; } } So if I have multiple instances of ArrayLIst<String> (st1 ,st2 ,st3) and I want to make new objects of aClass: { aClass obj1,obj2,obj3; obj1=new aClass(st1); obj2=new aClass(st2); obj3=new aClass(st3); } Will all of the aClass objects return st3 if I access the method getIdProd() for each of them(obj1..obj3)? Is an ArrayList as an instance variable automatically declared static?

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  • Error showing is NullPointerException [duplicate]

    - by user3659612
    This question already has an answer here: How to check a string against null in java? 11 answers I was trying to code a wifi scanner which does 20 scans but it shows NullPointerException at if(bssid[j].equals(null)){ My code is slightly huge package com.example.scanner; import java.io.File; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.OutputStreamWriter; import java.text.SimpleDateFormat; import java.util.Date; import java.util.List; import android.annotation.SuppressLint; import android.content.BroadcastReceiver; import android.content.Context; import android.content.Intent; import android.content.IntentFilter; import android.net.wifi.ScanResult; import android.net.wifi.WifiInfo; import android.net.wifi.WifiManager; import android.os.Bundle; import android.os.Environment; import android.support.v7.app.ActionBarActivity; import android.view.Menu; import android.view.View; import android.widget.ArrayAdapter; import android.widget.Button; import android.widget.ListView; import android.widget.Toast; public class MainActivity extends ActionBarActivity { WifiManager wifi; WifiScanReceiver wifireciever; WifiInfo info; Button scan, save; List<ScanResult> wifilist; ListView list; String wifis[]; String name; String[] ssid = new String[100]; String[] bssid = new String[100]; int[] lvl = new int[100]; int[] count = new int[100]; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.fragment_main); list=(ListView)findViewById(R.id.listView1); scan=(Button)findViewById(R.id.button1); save=(Button)findViewById(R.id.button2); scan.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub wifi=(WifiManager)getSystemService(Context.WIFI_SERVICE); if (wifi.isWifiEnabled()==false){ wifi.setWifiEnabled(true); } wifireciever = new WifiScanReceiver(); for (int i=0;i<20;i++){ registerReceiver(wifireciever, new IntentFilter(WifiManager.SCAN_RESULTS_AVAILABLE_ACTION)); wifi.startScan(); if (i==19){ Toast.makeText(getBaseContext(), "Scan Finish", Toast.LENGTH_LONG).show(); } } } }); save.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub savedata(); } }); } protected void savedata() { // TODO Auto-generated method stub try { File sdcard = Environment.getExternalStorageDirectory(); File directory = new File(sdcard.getAbsolutePath() + "/WIFI_RESULT"); directory.mkdirs(); name = new SimpleDateFormat("yyyy-MM-dd HH mm ss").format(new Date()); File file = new File(directory,name + "wifi_data.txt"); FileOutputStream fou = new FileOutputStream(file); OutputStreamWriter osw = new OutputStreamWriter(fou); try { for (int i =0; i < list.getCount(); i++){ osw.append(list.getItemAtPosition(i).toString()); } osw.flush(); osw.close(); Toast.makeText(getBaseContext(), "Saved", Toast.LENGTH_LONG).show(); } catch (IOException e){ e.printStackTrace(); } } catch (FileNotFoundException e){ e.printStackTrace(); } } class WifiScanReceiver extends BroadcastReceiver { @SuppressLint("UseValueOf") public void onReceive(Context c, Intent intent) { int a =0; wifi.startScan(); List<ScanResult> wifilist = wifi.getScanResults(); if (a<wifilist.size()){ a=wifilist.size(); } for(int j=0;j<wifilist.size();j++){ if(bssid[j].equals(null)){ ssid[j] = wifilist.get(j).SSID.toString(); bssid[j] = wifilist.get(j).BSSID.toString(); lvl[j] = wifilist.get(j).level; count[j]++; } else if (bssid[j].equals(wifilist.get(j).BSSID.toString())){ lvl[j] = lvl[j] + wifilist.get(j).level; count[j]++; } } wifis = new String[a]; for (int i =0; i<a; i++){ wifis[i] = ("\n" + ssid[i] + "\n AP Address" + bssid[i] + "\n Signal Strength:" + lvl[i]/count[i]).toString(); } list.setAdapter(new ArrayAdapter<String>(getApplicationContext(), android.R.layout.simple_list_item_1,wifis)); } } protected void onDestroy() { unregisterReceiver(wifireciever); super.onPause(); } protected void onResume() { registerReceiver(wifireciever, new IntentFilter(WifiManager.SCAN_RESULTS_AVAILABLE_ACTION)); super.onResume(); } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.main, menu); return true; } } NullPointerException at that point mean my array bssid isn't initialize. So I just want to know how to initialize it in main activity so that I can use that string bssid anywhere.

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  • create dynamic link buttons in ListView

    - by Sunny
    Hi, I am creating a search using listview. when user enter a word in search, I am generating a listview with the results. Now, there will be tags in each listview row. When, user clicks the tag, again a search happens using the value in the tag. There may be any number of tags for each listview row. I have to generate linkbuttons for these tags. Could anyone please guide me on how to create dynamic linkbuttons and access those values for further search. You can have a look at delicious.com. I need a similar functionality. Thanks in advance.

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  • Jquery current menu

    - by Isis
    Hello I have: var href = window.location.href; if(href.search('/welcome\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('#welcome2').append('<b>?????????? ??????????</b>').find('a').remove(); $('#welcome2').find('img').attr('src', '/static/images/arrow_black.gif'); } if(href.search('/contacts\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('#mcontacts').append('<b>????????</b>').find('a').remove(); $('#mcontacts').find('img').attr('src', '/static/images/arrow_black_down.gif'); } if(href.search('/sindbad_history\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('.menuwelcome:first').append('<b>???????</b>').find('a').remove(); $('.menuwelcome:first').find('img').attr('src', '/static/images/arrow_black.gif'); } if(href.search('/insurance\\/') > 0) { $('.menusafe').css('display', 'block'); $('#msafe').append('<b>???????????</b>').find('a').remove(); $('#msafe').find('img').attr('src', '/static/images/arrow_black_down.gif'); } if(href.search('/insurance_advices\\/') > 0) { $('.menusafe').css('display', 'block'); $('.menusafe:first').append('<b>???????? ??????????</b>').find('a').remove(); $('.menusafe:first').find('img').attr('src', '/static/images/arrow_black.gif'); } How can I minimize this code? Sorry for bad english

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