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  • What is a good practice to access class attributes in class methods?

    - by Clem
    I always wonder about the best way to access a class attribute from a class method in Java. Could you quickly convince me about which one of the 3 solutions below (or a totally different one :P) is a good practice? public class Test { String a; public String getA(){ return this.a; } public setA(String a){ this.a = a; } // Using Getter public void display(){ // Solution 1 System.out.println(this.a); // Solution 2 System.out.println(getA()); // Solution 3 System.out.println(this.getA()); } // Using Setter public void myMethod(String b, String c){ // Solution 1 this.a = b + c; // Solution 2 setA(b + c); // Solution 3 this.setA(b + c); } }

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  • How would you go about tackling this problem? [SOLVED in C++]

    - by incrediman
    Intro: EDIT: See solution at the bottom of this question (c++) I have a programming contest coming up in about half a week, and I've been prepping :) I found a bunch of questions from this canadian competition, they're great practice: http://cemc.math.uwaterloo.ca/contests/computing/2009/stage2/day1.pdf I'm looking at problem B ("Dinner"). Any idea where to start? I can't really think of anything besides the naive approach (ie. trying all permutations) which would take too long to be a valid answer. Btw, the language there says c++ and pascal I think, but i don't care what language you use - I mean really all I want is a hint as to the direction I should proceed in, and perhpas a short explanation to go along with it. It feels like I'm missing something obvious... Of course extended speculation is more than welcome, but I just wanted to clarify that I'm not looking for a full solution here :) Short version of the question: You have a binary string N of length 1-100 (in the question they use H's and G's instead of one's and 0's). You must remove all of the digits from it, in the least number of steps possible. In each step you may remove any number of adjacent digits so long as they are the same. That is, in each step you can remove any number of adjacent G's, or any number of adjacent H's, but you can't remove H's and G's in one step. Example: HHHGHHGHH Solution to the example: 1. HHGGHH (remove middle Hs) 2. HHHH (remove middle Gs) 3. Done (remove Hs) -->Would return '3' as the answer. Note that there can also be a limit placed on how large adjacent groups have to be when you remove them. For example it might say '2', and then you can't remove single digits (you'd have to remove pairs or larger groups at a time). Solution I took Mark Harrison's main algorithm, and Paradigm's grouping idea and used them to create the solution below. You can try it out on the official test cases if you want. //B.cpp //include debug messages? #define DEBUG false #include <iostream> #include <stdio.h> #include <vector> using namespace std; #define FOR(i,n) for (int i=0;i<n;i++) #define FROM(i,s,n) for (int i=s;i<n;i++) #define H 'H' #define G 'G' class String{ public: int num; char type; String(){ type=H; num=0; } String(char type){ this->type=type; num=1; } }; //n is the number of bits originally in the line //k is the minimum number of people you can remove at a time //moves is the counter used to determine how many moves we've made so far int n, k, moves; int main(){ /*Input from File*/ scanf("%d %d",&n,&k); char * buffer = new char[200]; scanf("%s",buffer); /*Process input into a vector*/ //the 'line' is a vector of 'String's (essentially contigious groups of identical 'bits') vector<String> line; line.push_back(String()); FOR(i,n){ //if the last String is of the correct type, simply increment its count if (line.back().type==buffer[i]) line.back().num++; //if the last String is of the wrong type but has a 0 count, correct its type and set its count to 1 else if (line.back().num==0){ line.back().type=buffer[i]; line.back().num=1; } //otherwise this is the beginning of a new group, so create the new group at the back with the correct type, and a count of 1 else{ line.push_back(String(buffer[i])); } } /*Geedily remove groups until there are at most two groups left*/ moves=0; int I;//the position of the best group to remove int bestNum;//the size of the newly connected group the removal of group I will create while (line.size()>2){ /*START DEBUG*/ if (DEBUG){ cout<<"\n"<<moves<<"\n----\n"; FOR(i,line.size()) printf("%d %c \n",line[i].num,line[i].type); cout<<"----\n"; } /*END DEBUG*/ I=1; bestNum=-1; FROM(i,1,line.size()-1){ if (line[i-1].num+line[i+1].num>bestNum && line[i].num>=k){ bestNum=line[i-1].num+line[i+1].num; I=i; } } //remove the chosen group, thus merging the two adjacent groups line[I-1].num+=line[I+1].num; line.erase(line.begin()+I);line.erase(line.begin()+I); moves++; } /*START DEBUG*/ if (DEBUG){ cout<<"\n"<<moves<<"\n----\n"; FOR(i,line.size()) printf("%d %c \n",line[i].num,line[i].type); cout<<"----\n"; cout<<"\n\nFinal Answer: "; } /*END DEBUG*/ /*Attempt the removal of the last two groups, and output the final result*/ if (line.size()==2 && line[0].num>=k && line[1].num>=k) cout<<moves+2;//success else if (line.size()==1 && line[0].num>=k) cout<<moves+1;//success else cout<<-1;//not everyone could dine. /*START DEBUG*/ if (DEBUG){ cout<<" moves."; } /*END DEBUG*/ }

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  • jQuery e.stopPropagation() - how to use without breaking dropbox functionality altogether?

    - by Knut Ole
    Short story: stopPropagation() prevents a dropdown menu from closing - which is good. But it also prevents the dropbox from opening next time around - which is bad. Long story: I'm using Twitter-Bootstrap and I've put a search box inside the dropdown menu like so: <div id="search_word_menu" style="position:absolute;right:157px;top:60px;"> <ul class="nav nav-pills"> <li class="dropdown" id="menu200"> <a class="dropdown-toggle btn-inverse" data-toggle="dropdown" style="width:117px;position:relative;left:2px" href="#menu200"> <i class="icon-th-list icon-white"></i> Testing <b class="caret"></b> </a> <ul class="dropdown-menu"> <li><a href="#">Retweets</a></li> <li><a href="#">Favourites</a></li> <li class="divider"></li> <li><a href="#">A list</a></li> <li class="divider"></li> <li><a href="#">A saved search</a></li> <li><a href="#">A saved #hashtag</a></li> <li class="divider"></li> <li> <!-- HERE --> <input id="drop_search" type="text" class="search_box_in_menu" value="Search..."> </li> </ul> </li> </ul> When I click inside the searchbox, the default behaviour is obviously to close the dropdown - but that makes it rather hard to write in a search term. So I've tried with the e.stopPropagation(), which does indeed prevent the dropdown from closing. Then, when I press enter in the searchbox, I'm closing the dropdown with a .toggle() - also seems to work fine. The PROBLEM arises when I want to to it all again, because the e.stopPropagation() has now disabled the dropdown alltogether - ie. when I press the dropdown menu, it doesn't open anymore! This is because of stopPropagation(), no doubt - but how can I resolve this, so that I get the aforementioned functionality, but without breaking the rest altogether? jQuery below: $(document).ready(function() { console.log("document.ready - "); //clearing search box on click $(".search_box_in_menu").click(function(e) { e.stopPropagation(); // works for the specific task console.log(".search_box_in_menu - click."); if($(this).val() == 'Search...') { $(this).val(''); console.log(".search_box_in_menu - value removed."); }; //return false; //this is e.preventDefault() and e.stopPropagation() }); // when pressing enter key in search box $('.search_box_in_menu').keypress(function(e) { var keycode = (e.keyCode ? e.keyCode : e.which); if(keycode == '13') { console.log(".search_box_in_menu - enter-key pressed."); console.log($(this).val()); $(this).closest('.dropdown-menu').toggle(); //works } }); $('.dropdown').click(function() { console.log(".dropdown - click."); $(this).closest('.dropdown-toggle').toggle(); //does nothing }); Would greatly appreciate some help! I'm starting to suspect this might be a bootstrapped-only problem, or at least caused by their implementation - but it's beyond me atm.

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  • hash password in SQL Server (asp.net)

    - by ile
    Is this how hashed password stored in SQL Server should look like? This is function I use to hash password (I found it in some tutorial) public string EncryptPassword(string password) { //we use codepage 1252 because that is what sql server uses byte[] pwdBytes = Encoding.GetEncoding(1252).GetBytes(password); byte[] hashBytes = System.Security.Cryptography.MD5.Create().ComputeHash(pwdBytes); return Encoding.GetEncoding(1252).GetString(hashBytes); } EDIT I tried to use sha-1 and now strings seem to look like as they are suppose to: public string EncryptPassword(string password) { return FormsAuthentication.HashPasswordForStoringInConfigFile(password, "sha1"); } // example output: 39A43BDB7827112409EFED3473F804E9E01DB4A8 Result from the image above looks like broken string, but this sha-1 looks normal.... Will this be secure enough?

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  • Is it a bad idea to use the new Dynamic Keyword as a replacement switch statement?

    - by WeNeedAnswers
    I like the new Dynamic keyword and read that it can be used as a replacement visitor pattern. It makes the code more declarative which I prefer. Is it a good idea though to replace all instances of switch on 'Type' with a class that implements dynamic dispatch. class VistorTest { public string DynamicVisit(object obj) { return Visit((dynamic)obj); } private string Visit(string str) { return "a string was called with value " + str; } private string Visit(int value) { return "an int was called with value " + value; } }

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  • Nested preference screens lose theming

    - by stealthcopter
    I have a preference screen for my application and in the manifest I have given it a theme using: android:theme="@android:style/Theme.Light.WallpaperSettings" However when I nest another preference screen inside this one such as: <?xml version="1.0" encoding="utf-8"?> <PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android" android:title="@string/setting_title" android:key="..."> <PreferenceCategory android:title="@string/title_themes" > <PreferenceScreen android:title="@string/title_themes_opt" > <ListPreference android:key="Setting_BG" android:title="@string/setting_bg" android:summary="@string/setting_bg_summary" android:entries="@array/bg_titles" android:defaultValue="0" android:entryValues="@array/bg_values" /> </PreferenceScreen> </PreferenceCategory> </PreferenceScreen> The nested preference screen loses the theme of the parent. How can this be prevented? Thanks in advance.

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  • Eclipse: find resource on classpath

    - by seanizer
    Is there a way in eclipse to search the classpath for arbitrary resource file names (or patterns)? I know I can use either Navigate > Open Type (which will scan the classpath for classes) or Navigate > Open Resource, which will search for any resource type, but only in my project folders. Is there any way to achieve a combination ob both, to do a resource search (something like *.xsd) that searches all jars on the classpath?

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  • ResultSet Already closed error

    - by javatraniee
    why am i getting an error of resultset already closed error public class Server implements Runnable { private static int port=1600, maxConnections=0; public static Connection connnew=null; public static Connection connnew1=null; public static Statement stnew,stnew1,stnew2,stnew3,stnew4; public void getConnection() { try{ Class.forName("org.gjt.mm.mysql.Driver"); connnew= DriverManager.getConnection("jdbc:mysql://localhost/db_alldata","root","flashkit"); connnew1= DriverManager.getConnection("jdbc:mysql://localhost/db_main","root","flashkit"); stnew=connnew.createStatement(); stnew1=connnew.createStatement(); stnew2=connnew1.createStatement(); stnew3=connnew1.createStatement(); stnew4=connnew1.createStatement(); }catch (Exception e) { System.out.print("Get Connection Exception---"+new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(new Date())+"----- "+e); } } public void closeConnection() { try{ if(!(connnew.isClosed())) { stnew.close(); stnew1.close(); connnew.close(); } if(!(connnew1.isClosed())) { stnew2.close(); stnew3.close(); stnew4.close(); connnew1.close(); } }catch (Exception e) { System.out.print("Close Connection Closing Exception-----"+new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(new Date())+"-------"+e); } } Server() { try{ }catch(Exception ee) { System.out.print("Server Exceptions in main connection--"+new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(new Date())+"------"+ee); } } public static void main(String[] args) throws SQLException { int i=0; Server STUD= new Server(); STUD.getConnection(); try { ServerSocket listener = new ServerSocket(port); Socket server; while((i++ < maxConnections) || (maxConnections == 0)) { @SuppressWarnings("unused") doComms connection; server = listener.accept(); try{ ResultSet checkconnection=stnew4.executeQuery("select count(*) from t_studentdetails"); if(checkconnection.next()) { //DO NOTHING IF EXCEPTION THEN CLOSE ALL CONNECTIONS AND OPEN NEW CONNECTIONS } }catch (Exception e) { System.out.print("Db Connection Lost Closing And Re-Opning It--------"+new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(new Date())+"--------"+e); STUD.closeConnection(); STUD.getConnection(); } doComms conn_c= new doComms(server,stnew,stnew1,stnew2,stnew3); Thread t = new Thread(conn_c); t.start(); } }catch (IOException ioe) { System.out.println("Main IOException on socket listen: " + ioe); } } public void run() { } } class doComms implements Runnable { private Socket server; private String input; static Connection conn=null; static Connection conn1=null; static Statement st,st1,st2,st3; doComms(Socket server, Statement st,Statement st1,Statement st2,Statement st3 ) { this.server=server; doComms.st=st; doComms.st1=st1; doComms.st2=st2; doComms.st3=st3; } @SuppressWarnings("deprecation") public void run () { input=""; //char ch; try { DataInputStream in = new DataInputStream (server.getInputStream()); OutputStreamWriter outgoing=new OutputStreamWriter(server.getOutputStream()); while(!(null==(input=in.readLine()))) { savetodatabase(input,server.getPort(),outgoing); } //server.close(); } catch (IOException ioe) { System.out.println("RUN IOException on socket listen:-------"+new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(new Date())+"----- " + ioe); ioe.printStackTrace(); } } public void savetodatabase(String line, int port1, OutputStreamWriter outgoing) { try { String Rollno="-",name="-",div="-",storeddate="-",storedtime="-",mailfrom=""; String newline=line; String unitid="-"; storeddate=new SimpleDateFormat("yyyy-MM-dd").format(new java.util.Date()); storedtime=new SimpleDateFormat("HH:mm:ss").format(new java.util.Date()); String sql2="delete from t_currentport where PortNumber='"+port1+"''"; st2.executeUpdate(sql2); sql2="insert into t_currentport (unitid, portnumber,thedate,thetime) values ('"+unitid+"','"+port1+"','"+storeddate+"','"+storedtime+"')"; st2.executeUpdate(sql2); String tablename=GetTable(); String sql="select * from t_studentdetails where Unitid='"+unitid+"'"; ResultSet rst=st2.executeQuery(sql); if(rst.next()) { Rollno=rst.getString("Rollno"); name=rst.getString("name"); div=rst.getString("div"); } String sql1="insert into studentInfo StoredDate,StoredTime,Subject,UnitId,Body,Status,Rollno,div,VehId,MailDate,MailTime,MailFrom,MailTo,Header,UnProcessedStamps) values('"+storeddate+"','"+storedtime+"','"+unitid+"','"+unitid+"','"+newline+"','Pending','"+Rollno+"','"+div+"','"+name+"','"+storeddate+"','"+storedtime+"','"+mailfrom+"','"+mailfrom+"','-','-')"; st1.executeUpdate(sql1); }catch(Exception e) { System.out.print("Save to db Connection Exception--"+new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(new Date())+"-->"+e); } } }

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  • Processing Text and Binary (Blob, ArrayBuffer, ArrayBufferView) Payload in WebSocket - (TOTD #185)

    - by arungupta
    The WebSocket API defines different send(xxx) methods that can be used to send text and binary data. This Tip Of The Day (TOTD) will show how to send and receive text and binary data using WebSocket. TOTD #183 explains how to get started with a WebSocket endpoint using GlassFish 4. A simple endpoint from that blog looks like: @WebSocketEndpoint("/endpoint") public class MyEndpoint { public void receiveTextMessage(String message) { . . . } } A message with the first parameter of the type String is invoked when a text payload is received. The payload of the incoming WebSocket frame is mapped to this first parameter. An optional second parameter, Session, can be specified to map to the "other end" of this conversation. For example: public void receiveTextMessage(String message, Session session) {     . . . } The return type is void and that means no response is returned to the client that invoked this endpoint. A response may be returned to the client in two different ways. First, set the return type to the expected type, such as: public String receiveTextMessage(String message) { String response = . . . . . . return response; } In this case a text payload is returned back to the invoking endpoint. The second way to send a response back is to use the mapped session to send response using one of the sendXXX methods in Session, when and if needed. public void receiveTextMessage(String message, Session session) {     . . .     RemoteEndpoint remote = session.getRemote();     remote.sendString(...);     . . .     remote.sendString(...);    . . .    remote.sendString(...); } This shows how duplex and asynchronous communication between the two endpoints can be achieved. This can be used to define different message exchange patterns between the client and server. The WebSocket client can send the message as: websocket.send(myTextField.value); where myTextField is a text field in the web page. Binary payload in the incoming WebSocket frame can be received if ByteBuffer is used as the first parameter of the method signature. The endpoint method signature in that case would look like: public void receiveBinaryMessage(ByteBuffer message) {     . . . } From the client side, the binary data can be sent using Blob, ArrayBuffer, and ArrayBufferView. Blob is a just raw data and the actual interpretation is left to the application. ArrayBuffer and ArrayBufferView are defined in the TypedArray specification and are designed to send binary data using WebSocket. In short, ArrayBuffer is a fixed-length binary buffer with no format and no mechanism for accessing its contents. These buffers are manipulated using one of the views defined by one of the subclasses of ArrayBufferView listed below: Int8Array (signed 8-bit integer or char) Uint8Array (unsigned 8-bit integer or unsigned char) Int16Array (signed 16-bit integer or short) Uint16Array (unsigned 16-bit integer or unsigned short) Int32Array (signed 32-bit integer or int) Uint32Array (unsigned 16-bit integer or unsigned int) Float32Array (signed 32-bit float or float) Float64Array (signed 64-bit float or double) WebSocket can send binary data using ArrayBuffer with a view defined by a subclass of ArrayBufferView or a subclass of ArrayBufferView itself. The WebSocket client can send the message using Blob as: blob = new Blob([myField2.value]);websocket.send(blob); where myField2 is a text field in the web page. The WebSocket client can send the message using ArrayBuffer as: var buffer = new ArrayBuffer(10);var bytes = new Uint8Array(buffer);for (var i=0; i<bytes.length; i++) { bytes[i] = i;}websocket.send(buffer); A concrete implementation of receiving the binary message may look like: @WebSocketMessagepublic void echoBinary(ByteBuffer data, Session session) throws IOException {    System.out.println("echoBinary: " + data);    for (byte b : data.array()) {        System.out.print(b);    }    session.getRemote().sendBytes(data);} This method is just printing the binary data for verification but you may actually be storing it in a database or converting to an image or something more meaningful. Be aware of TYRUS-51 if you are trying to send binary data from server to client using method return type. Here are some references for you: JSR 356: Java API for WebSocket - Specification (Early Draft) and Implementation (already integrated in GlassFish 4 promoted builds) TOTD #183 - Getting Started with WebSocket in GlassFish TOTD #184 - Logging WebSocket Frames using Chrome Developer Tools, Net-internals and Wireshark Subsequent blogs will discuss the following topics (not necessary in that order) ... Error handling Custom payloads using encoder/decoder Interface-driven WebSocket endpoint Java client API Client and Server configuration Security Subprotocols Extensions Other topics from the API

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  • Hiding div tag when the user clicks outside the div tag.

    - by Madhu
    Hi friends, I have a div tag and I am populating the search results on a custom grid, which is placed inside this divtag. When a user click on the search button, i am displaying the results in the above mentioned div tag. I have a requirement to close the above div tag when the user clicks outside the div tag. It is similar to google search auto comlete. Thanks in advance.

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  • create dynamic link buttons in ListView

    - by Sunny
    Hi, I am creating a search using listview. when user enter a word in search, I am generating a listview with the results. Now, there will be tags in each listview row. When, user clicks the tag, again a search happens using the value in the tag. There may be any number of tags for each listview row. I have to generate linkbuttons for these tags. Could anyone please guide me on how to create dynamic linkbuttons and access those values for further search. You can have a look at delicious.com. I need a similar functionality. Thanks in advance.

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  • How to Keep the selected value of the select box after Form POST or GET

    - by Rajasekar
    Im trying to implement the search feature in my website. when the search keyword is entered in the textbox, and the category combo is selected, the form will be Posted and the result will be shown on the same page. what i want is to keep the selected category of the combo by default in the form after posted For eg., If i select the category 'Automobiles' in the combo and click search, after form submit, the combo should show the automobiles as default selected option. Please help me. Any help will be appreciated

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  • How to manually verify a user against the asp.net memberhip database

    - by Ekk
    I would like to know how I can verify a user's credential against an existing asp.net membership database. The short story is that we want provide single sign on access. So what I've done is to connect directly to the membership database and tried to run a sql query against the aspnet_Membership table: private bool CanLogin(string userName, string password) { // Check DB to see if the credential is correct try { string passwordHash = FormsAuthentication.HashPasswordForStoringInConfigFile(password, "SHA1"); string sql = string.Format("select 1 from aspnet_Users a inner join aspnet_Membership b on a.UserId = b.UserId and a.applicationid = b.applicationid where a.username = '{0}' and b.password='{1}'", userName.ToLowerInvariant(), passwordHash); using (SqlConnection sqlConn = new SqlConnection(ConfigurationManager.ConnectionStrings["LocalSqlServer"].ConnectionString)) using (SqlCommand sqlCmd = new SqlCommand(sql, sqlConn)) { sqlConn.Open(); int count = sqlCmd.ExecuteNonQuery(); sqlConn.Close(); return count == 1; } } catch (Exception ex) { return false; } } The problem is the password value, does anyone know how the password it is hashed?

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  • UIWebview handle popup view

    - by Tuan Nguyen
    I've a webpage with one text-box and one button. Click on button will show a popup for searching. On popup page,has 2 buttons, "Search" and "Close". Input the text and click Search, the result will display on a list on this popup, click on a row will close the popup and fill the value to text-box on main-page. On Destop browser, it works fine On Safari on iPad, it will open new tab instead of a popup but work fine. UIWebview in my app, on main-page, click the button, I will go to Search page, but when click Search button and close button, nothing happened, I know because 2 buttons will close the popup or the tab, but I don't know how to handle on my Webview, and also I can fill data to main-page or not? Could anyone point me away? Thanks,

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  • Error Instantiating an Inner Class in Parent's Constructor...

    - by stormin986
    In my application's main class (subclass of Application), I have a public inner class that simply contains 3 public string objects. In the parent class I declare an object of that inner class. public class MainApplication extends Application { public class Data { public String x; public String y; public String z; } private Data data; MainApplication() { data = new Data() data.x = "String"; } } After I instantiate the object in the constructor, I get a runtime error when I try to assign any of the inner class object's variables. Any idea what's up here??

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  • How to adjust asp.net URL routing based on domain/host?

    - by DrewF
    What's the best way to adjust the path destination for a routing table created in the global.asax Application_Start event based on the domain/sub domain/host? The following worked in IIS6, but with IIS7 the request object is decoupled from the Application_Start event and therefore does not work anymore: Dim strHost As String = Context.Request.Url.Host Dim strDir As String = "" If strHost.Contains("domain1.com") Then strDir = "area1/" Else strDir = "area2/" End If routes.MapPageRoute("Search", "Search", "~/" & strDir & "search.aspx")

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  • dynamic searchable fields, best practice?

    - by boblu
    I have a Lexicon model, and I want user to be able to create dynamic feature to every lexicon. And I have a complicate search interface that let user search on every single feature (including the dynamic ones) belonged to Lexicon model. I could have used a serialized text field to save all the dynamic information if they are not for searching. In case I want to let user search on all fields, I have created a DynamicField Model to hold all dynamically created features. But imagine I have 1,000,000,000 lexicon, and if one create a dynamic feature for every lexicon, this will result creating 1,000,000,000 rows in DynamicField model. So the sql search function will become quite inefficient while a lot of dynamic features created. Is there a better solution for this situation? Which way should I take? searching for a better db design for dynamic fields try to tuning mysql(add cache fields, add index ...) with current db design

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  • Jquery current menu

    - by Isis
    Hello I have: var href = window.location.href; if(href.search('/welcome\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('#welcome2').append('<b>?????????? ??????????</b>').find('a').remove(); $('#welcome2').find('img').attr('src', '/static/images/arrow_black.gif'); } if(href.search('/contacts\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('#mcontacts').append('<b>????????</b>').find('a').remove(); $('#mcontacts').find('img').attr('src', '/static/images/arrow_black_down.gif'); } if(href.search('/sindbad_history\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('.menuwelcome:first').append('<b>???????</b>').find('a').remove(); $('.menuwelcome:first').find('img').attr('src', '/static/images/arrow_black.gif'); } if(href.search('/insurance\\/') > 0) { $('.menusafe').css('display', 'block'); $('#msafe').append('<b>???????????</b>').find('a').remove(); $('#msafe').find('img').attr('src', '/static/images/arrow_black_down.gif'); } if(href.search('/insurance_advices\\/') > 0) { $('.menusafe').css('display', 'block'); $('.menusafe:first').append('<b>???????? ??????????</b>').find('a').remove(); $('.menusafe:first').find('img').attr('src', '/static/images/arrow_black.gif'); } How can I minimize this code? Sorry for bad english

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  • scanf formatting issue

    - by da_rockwilder
    I have a log file with the following format: INFO 2011-03-09 10:26:15,270 [user] message I want to parse the log file using PHP: // assume file exists and all that $handle = fopen("log_file.txt", "r"); while ($line_data = fscanf($handle, "%s %s %s [%s] %s\n")) { var_dump($line_data); } fclose($handle); When I run this code I get: [0]=> array(5) { [0]=> string(4) "INFO" [1]=> string(10) "2011-03-09" [2]=> string(12) "10:26:15,270" [3]=> string(5) "user]" [4]=> NULL } // snip It appears the closing bracket in the format string ("%s %s %s [%s] %s") is disrupting the rest of the line from getting parsed. I checked the PHP docs for scanf (as suggested by fscanf), and I didn't see anything mentioning having to escape a left bracket. Any suggestions on how to get the 4th and 5th elements to look like "user" and "message" respectively?

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  • Receiving the post response using curl

    - by Larry Battle
    Hello, I'm trying to make a script that will download search results from a HTTPS website using POST. So far, I'm able to download the web page before the submission but not the response page containing the search results. The problem seems to be that curl isn't waiting long enough for the response page to appear. The website behaviors likes this. Website appears- input form data - click submit - progressing icon appears - returns new web page with search results( new data but the url doesn't change ) My code: curl -d "postData" -k url

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  • trying to load css/images in django

    - by tipu
    I looked http://docs.djangoproject.com/en/dev/howto/static-files/ already, but am still confused on how to get css/image files loaded. On my server, the images folder and css file are located at /srv/twingle/search my urls.py 1 from django.conf.urls.defaults import * 2 3 # Uncomment the next two lines to enable the admin: 4 # from django.contrib import admin 5 # admin.autodiscover() 6 7 urlpatterns = patterns('twingle.search.views', 8 url(r'^$', 'index'), 9 url(r'^search/(?P<param>\w+)$', 'index'), 10 ) 11 (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', 12 {'document_root': '/srv/twingle/search'}), 13 I try to access my css as follows, <link rel="stylesheet" type="text/css" href="/site_media/style.css" /> That's exactly how the tutorial says to do it, but it doesn't work. Any suggestions?

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  • how do Google and Yahoo replace the URL in the browser status bar?

    - by Mike W
    On the Google and Yahoo search pages, the URLs of the 10 search result links actually point to google.com or yahoo.com. The URLs have extra arguments that allow google.com or yahoo.com to redirect to the actual search result when the link is clicked. When the user mouses over the link, the search result URL (and not the google.com or yahoo.com URL) is displayed in the browser's status bar. I'm wondering how they do that. Many years ago, this would have been accomplished by having some javascript that sets window.status, but that doesn't seem to work anymore, as is explained by http://stackoverflow.com/questions/876390/reliable-cross-browser-way-of-setting-status-bar-text I have a link that looks like this: <a href="http://somedomain.com/ReallyLongURLThatShouldNotBeSeenInTheStatusBar" onmouseover="window.status='http://niceShourtUrl.com/'" onmouseout="window.status=''">Click Me</a> This link tried to use the window.status strategy, but it doesn't work. How do I fix this link so that it acts like the links on Google's and Yahoo's search result pages? In this example, I want "http://niceShourtUrl.com/" to be displayed in the status bar when the user mouses over the link.

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