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  • How to determine the difference among dates in the same column?

    - by Vera
    How to determine the difference among dates of birth? +----------+----------+------------+ | id | name | birth | +----------+----------+------------+ | 00001 | Claws | 2010-04-17 | | 00002 | Claws | 2010-01-31 | | 00003 | Claws | 2009-11-31 | | 00004 | Claws | 2009-09-31 | | 00005 | Claws | 2009-07-31 | | 00006 | Claws | 2008-10-31 | +----------+----------+------------+ I would like to obtain this: +----------+----------+------------+------------------------------------------+ | id | name | birth | diff | +----------+----------+------------+------------------------------------------+ | 00001 | Claws | 2010-04-17 | diff (id1-id2) = 2010-01-31 - 2010-04-17 | | 00002 | Claws | 2010-01-31 | diff (id2-id3) = 2010-01-31 - 2009-11-31 | | 00003 | Claws | 2009-11-31 | diff (id3-id4) = 2010-01-31 - 2009-09-31 | If possible, ORDER BY diff DESC Thank you for helping Vera

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  • mysqldump parameter to ensure DROP VIEW IF EXISTS rather than incorrect DROP TABLE IF EXISTS

    - by doublejosh
    Wonder if there is a parameter I can pass in mmysqldump equivalent for SQL Servery mysqldump that will make the incorrect "DROP TABLE IF EXISTS" statements into "DROP VIEW IF EXISTS", so that populating a database in an automated development environment refresh will work? Clarification, I'm getting DROP TABLE IF EXISTS statements in my .sql dump file even though they aren't tables. FYI: This is a Drupal site. The tables in question are ubercart meta statistics tables.

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  • Cloud Database Service Latency/Performance

    - by Gcoop
    Hi All, I am running a heavy traffic site and our server is beginning to get to its limits, at the moment the entire LAMP stack is on one box (not ideal). I would like to move the database onto it's own box or onto a cloud service, but from my previous experience moving the database off the same box as the webserver increases the latency of reads quite dramatically slowing down the site. Is using a cloud service for this going to overcome this problem, because as far as I can tell its essentially the same situation (as moving it onto a separate box in my control)? In which case why is there so much popularity around cloud based database services at the moment? Are cloud based database services so quick that the latency of reads is so low that its almost like having it on the same box in the same datacentre?

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  • Subversion error, but I don't know what it means

    - by DaveDev
    I'm trying to do an Update on my solution but I'm getting the following subversion error: SharpSvn.SvnFileSystemException: Working copy path 'Path_to_image/logo LoRes.jpg' does not exist in repository but I can see that the image is in the repository. The stack trace is as follows: at SharpSvn.SvnClientArgs.HandleResult(SvnClientContext client, SvnException error) at SharpSvn.SvnClientArgs.HandleResult(SvnClientContext client, svn_error_t* error) at SharpSvn.SvnClient.Update(ICollection`1 paths, SvnUpdateArgs args, SvnUpdateResult& result) at SharpSvn.SvnClient.Update(String path, SvnUpdateArgs args, SvnUpdateResult& result) at Ankh.Commands.SolutionUpdateCommand.UpdateRunner.Work(Object sender, ProgressWorkerArgs e) at Ankh.ProgressRunnerService.ProgressRunner.Run(Object arg) Is there something else that could be wrong?

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  • Active User Tracking, PHP Sessions

    - by Nik
    Alright, I'm trying to work on a function for active user counting in an AJAX based application. I want to express the below SQL Query in correct syntax but I'm not sure how to write it. The desired SQL Query is below: SELECT count(*) FROM active WHERE timestamp > time() - 1800 AND nick=(a string that doesn't contain [AFK]) Now, I do understand that time() - 1800 can be assigned to a variable, but how is timestamp > variable and nick that doesn't contain a string written in SQL?

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  • error with gtkmm 3 in ubuntu 12.04

    - by Grohiik
    i install libgtkmm-3.0-dev in ubuntu 12.04 and i try to learn and write program with c++ and gtkmm 3 i go to this link "http://developer.gnome.org/gtkmm-tutorial/unstable/sec-basics-simple-example.html.en" and try to compile simple example program : #include <gtkmm.h> int main(int argc, char *argv[]) { Glib::RefPtr<Gtk::Application> app = Gtk::Application::create(argc, argv, "org.gtkmm.examples.base"); Gtk::ApplicationWindow window; return app->run(window); } my file name is "basic.cc" and i open terminal and type following command to compile: g++ basic.cc -o basic `pkg-config gtkmm-3.0 --cflags --libs` compile completed without any error but when i try to run program with type ./basic in terminal i get following error : ~$ ./simple ./simple: symbol lookup error: ./simple: undefined symbol:_ZN3Gtk11Application6createERiRPPcRKN4Glib7ustringEN3Gio16ApplicationFlagsE ~$ how can i solve this problem ? i can cimpile any gtkmm 2.4 code with this command : " g++ basic.cc -o basic pkg-config gtkmm-3.0 --cflags --libs " and this command : " g++ basic.cc -o basic pkg-config gtkmm-2.4 --cflags --libs " thanks

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  • Can a binary tree or tree be always represented in a Database as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Error in R for missing object

    - by griffin
    I have several nested functions, some of which as called in lapply clauses. In the process, sometimes I don't set a default for a parameter and instead check if it was supplied using the missing function. I'm getting a strange error right now when I'm not passing a value for a parameter, it has no default, yet missing resolves to FALSE. And when I try to use or check the parameter in any other way (using length, exists, etc.), I get an error: Error in try(length(x)) : argument "data" is missing, with no default Has anyone experienced this failure of the missing function before?

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  • LINQ expression precedence with Skip(), Take() and OrderBy()

    - by Robert Koritnik
    I'm using LINQ to Entities and display paged results. But I'm having issues with the combination of Skip(), Take() and OrderBy() calls. Everything works fine, except that OrderBy() is assigned too late. It's executed after result set has been cut down by Skip() and Take(). So each page of results has items in order. But ordering is done on a page handful of data instead of ordering of the whole set and then limiting those records with Skip() and Take(). How do I set precedence with these statements? My example (simplified) var query = ctx.EntitySet.Where(/* filter */).OrderBy(/* expression */); int total = query.Count(); var result = query.Skip(n).Take(x).ToList();

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  • Sql script, create a database

    - by Blanca
    Hi! I have the next file: create_mysql.sql DROP DATABASE IF EXISTS playence_media; CREATE DATABASE playence_media; USE playence_media; GRANT ALL PRIVILEGES ON . TO 'media'@'localhost' IDENTIFIED BY 'media' WITH GRANT OPTION; But I don't know how to create this database. I would like to do it with my terminal, no other graphics interfaces. Thanks

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  • Can anybody help me out with this error.?

    - by kumar
    Error during serialization or deserialization using the JSON JavaScriptSerializer. The length of the string exceeds the value set on the maxJsonLength property. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.InvalidOperationException: Error during serialization or deserialization using the JSON JavaScriptSerializer. The length of the string exceeds the value set on the maxJsonLength property. in jquery gird on button click i am displaying something like 28000 rows? I know some of them are sujjested to define the JsonmaxLength in web config file.. but its not working for me? can anybody tell me about this? thanks

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  • Rails: Generated tokens missing occasionally

    - by Vincent Chan
    We generate an unique token for each user and store it on database. Everything is working fine in the local environment. However, after we upload the codes to the production server on Engine Yard, things become weird. We tried to register an account right after the deploy. It is working fine and we can see the token in the db. But after that, when we register new accounts, we cannot see any tokens. We only have NULL in the db. Not sure what caused this problem because we can't re-produce this in the local machine. Thanks for your help.

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  • How to handle multiple openIDs for the same user

    - by Sinan
    For my site I am using a login system much like the one on SO. A user can login with his Facebook, Google (Gmail openID), Twitter account. This question is not about specific oAuth or openID implementations. The question is how to know if the same user logins with different providers. Let me give an example: Bobo comes to site logins to site by clicking on "Login with Facebook". Because this is his first visit we create an account for him. Later Bobo comes to the site. This time he clicks on "Login with Google". So how do I know if this is the same person so I can add this provider to his account instead of creating a new (and duplicate) account. Can I trust solely on email? What is the best way to handle this. How does SO do it? Any ideas?

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  • Adding to database with multiple text boxes

    - by kira423
    What I am trying to do with this script is allow users to update a url for their websites, and since each user isn't going to have the same amount of websites is is hard for me to just add $_POST['website'] for each of these. Here is the script <?php include("config.php"); include("header.php"); include("functions.php"); if(!isset($_SESSION['username']) && !isset($_SESSION['password'])){ header("Location: pubs.php"); } $getmember = mysql_query("SELECT * FROM `publishers` WHERE username = '".$_SESSION['username']."'"); $info = mysql_fetch_array($getmember); $getsites = mysql_query("SELECT * FROM `websites` WHERE publisher = '".$info['username']."'"); $postback = $_POST['website']; $webname = $_POST['webid']; if($_POST['submit']){ var_dump( $_POST['website'] ); $update = mysql_query("UPDATE `websites` SET `postback` = '$postback' WHERE name = '$webname'"); } print" <div id='center'> <span id='tools_lander'><a href='export.php'>Export Campaigns</a></span> <div id='calendar_holder'> <h3>Please define a postback for each of your websites below. The following variables should be used when creating your postback.<br /> cid = Campaign ID<br /> sid = Sub ID<br /> rate = Campaign Rate<br /> status = Status of Lead. 1 means payable 2 mean reversed<br /> A sample postback URL would be <br /> http://www.example.com/postback.php?cid=#cid&sid=#sid&rate=#rate&status=#status</h3> <table class='balances' align='center'> <form method='POST' action=''>"; while($website = mysql_fetch_array($getsites)){ print" <tr> <input type ='hidden' name='webid' value='".$website['id']."' /> <td style='font-weight:bold;'>".$website['name']."'s Postback:</td> <td><input type='text' style='width:400px;' name='website[]' value='".$website['postback']."' /></td> </tr>"; } print" <td style='float:right;position:relative;left:150px;'><input type='submit' name='submit' style='font-size:15px;height:30px;width:100px;' value='Submit' /></td> </form> </table> </div>"; include("footer.php"); ?> What I am attempting to do insert the what is inputted in the text boxes to their corresponding websites, and I cannot think of any other way to do it, and this obviously does not works and returns a notice stating Array to string conversion If there is a more logical way to do this please let me know.

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  • Managing Foreign Keys

    - by jwzk
    So I have a database with a few tables. The first table contains the user ID, first name and last name. The second table contains the user ID, interest ID, and interest rating. There is another table that has all of the interest ID's. For every interest ID (even when new ones are added), I need to make sure that each user has an entry for that interest ID (even if its blank, or has defaults). Will foreign keys help with this scenario? or will I need to use PHP to update each and every record when I add a new key?

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  • Shopping Cart Database Structure

    - by Paul Atkins
    Hi, I have been studying the database structure for shopping carts and notice that when storing order details the product information is repeated and stored again in the table. I was wondering what the reasoning behind this would be? Here is a small example of what i mean: Product Table product_id name desc price 1 product 1 This is product 1 27.00 Order Table order_id customer id order_total 1 3 34.99 Order Details Table order_details_id product_id product name price qty 1 1 product 1 27.00 1 So as you can see the product name and price are stored again in the order details table. Why is this? The only reason i can think of is because the product details may change after the order has been placed which may cause confusion. Is this correct? Thanks Paul

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  • Selecting a whole database over an individual table to output to file

    - by Daniel Wrigley
    :::::::: EDIT :::::::: New code for people to have a look at, one question I have with this is where do I set were the *.gz file is saved? $backupFile = $dbname . date("Y-m-d-H-i-s") . '.gz'; $command = "mysqldump --opt -h $dbhost -u $dbuser -p $dbpass $dbname | gzip > $backupFile"; system($command); Also why the hell can you not reply yo your own post with answering it? :( :::::::: EDIT :::::::: Ok Im having trouble finding out how to select a full database for backup as an *.sql file rather than only an individual table. On the localhost I have several databases with one named "foo" and it is that which I want to backup and not any of the individual tables inside the database "foo". The code to connect to the database; //Database Information $dbhost = "localhost"; $dbname = "foo"; $dbuser = "bar"; $dbpass = "rulz"; //Connect to database mysql_connect ($dbhost, $dbuser, $dbpass) or die("Could not connect: ".mysql_error()); mysql_select_db($dbname) or die(mysql_error()); The code to backup the database; // Grab the time to know when this post was submitted $time = date('Y-m-d-H-i-s'); $tableName = 'foo'; $backupFile = '/sql/backup/'. $time .'.sql'; $query = "SELECT * INTO OUTFILE '". $backupFile ."' FROM ". $tableName .""; $result = mysql_query($query)or die("Database query died: " . mysql_error()); My brain is hurting near to the end of the day so no doubts i've missed something out very obvious. Thanks in advance to anyone helping me out.

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  • java checked exception in a catch clause compilation error

    - by srandpersonia
    Hi, I was expecting an compilation error in the following program because of the throw statement in the catch block as IOException is a checked exception and it is not caught by another try block within the catch block. But I am getting "Hurray!" printed. Any explanation would be much appreciated. According to JLS 11.2.3, http://java.sun.com/docs/books/jls/third_edition/html/exceptions.html It is a compile-time error if a method or constructor body can throw some exception type E when both of the following hold: * E is a checked exception type * E is not a subtype of some type declared in the throws clause of the method or constructor. import java.io.*; public class Test{ public static void main(String args[]) { System.out.println(method()); } public static int method() { try{ throw new Exception(); } catch(Exception e){ throw new IOException(); //No compile time error } finally{ System.out.println("Hurray!"); } } } Thanks in advance.

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  • please help me in this query

    - by testkhan
    I have three tables (user, friends, posts) and two users (user1 and user2). When user1 adds user2 as friend then user1 can see the posts of user2 just like on Facebook. But only the posts after the date when user1 added user2 as friend. My query is like this: $sql = mysql_query("SELECT * FROM posts p JOIN friends f ON p.currentuserid = f.friendid AND p.time >= f.friend_since OR p.currentuserid='user1id' WHERE f.myid='user1id' ORDER BY p.postid DESC LIMIT 20"); it is working all the way fine but with a little problem.....!! it displays user2, user3 (all the users as friends of user1) posts for single time but shows user1 posts multiple.......i.e user2. hi user1. userssfsfsfsfsdf user1. userssfsfsfsfsdf user3. dddddddd user1. sdfsdsdfsdsfsf user1. sdfsdsdfsdsfsf but i in database it is single entry/post why it is happening........!! How can I fix it?

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  • [WEB] Local/Dev/Live deployment - best workflow

    - by Adam Kiss
    Hello, situation We our little company with 3 people, each has a localhost webserver and most projects (previous and current) are on one PC network shared disk. We have virtual server, where some of our clients' sites and our site. Our standard workflow is: Coder PC ? Programmer localhost ? dev domain (client.company.com) ? live version (client.com) It often happens, that there are two or three guys working on same projects at the same time - one is on dev version, two are on localhost. When finished, we try to synchronize the files on dev version and ideally not to mess (thanks ILMV:]) up any files, which *knock knock * doesn't happen often. And then one of us deploys dev version on live webserver. question we are looking for a way to simplify this workflow while updating websites - ideally some sort of diff uploader or VCS probably (Git/SVN/VCS/...), but we are not completely sure where to begin or what way would be ideal, therefore I ask you, fellow stackoverflowers for your experience with website / application deployment and recommended workflow. We probably will also need to use Mac in process, so if it won't be a problem, that would be even better. Thank you

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