Search Results

Search found 34110 results on 1365 pages for 'gdata python client'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 539/1365 | < Previous Page | 535 536 537 538 539 540 541 542 543 544 545 546  | Next Page >

  • Web and stand-alone apps development tendency

    - by Narek
    There is a strong tendency of making web apps and even seems that very soon a lot of features will be available online so that for every day use people will have all necessary software free online and they will not need to install any software locally. Only specific (professional) tools that usually people don’t use at home will not be available as a web app. So my question, how do you imagine selling software that was necessary for everyday use and was not free (seems they can't make money any more by selling their product – no need of those products). And what disadvantages have web apps, that is to say, what is bad to use software online compared with having the same software locally (please list)? Please do not consider this question not connected with programming, as I really would like to have a little statistics from professional programmers who are aware from nowday’s tendency of software and programming. Thanks.

    Read the article

  • Display graph without saving using pydot

    - by user506710
    Hello all I am trying to display a simple graph using pydot. My question is that is there any way to display the graph without writing it to a file as currently I use write function to first draw and then have to use the Image module to show the files. However is there any way that the graph directly gets printed on the screen without being saved ?? Also as an update I would like to ask in this same question that I observe that while the image gets saved very quickly when I use the show command of the Image module it takes noticeable time for the image to be seen .... Also sometimes I get the error that the image could'nt be opened because it was either deleted or saved in unavailable location which is not correct as I am saving it at my Desktop..... Does anyone know what's happening and is there a faster way to get the image loaded..... Thanks a lot....

    Read the article

  • What do I do with a Concrete Syntax Tree?

    - by Cap
    I'm using pyPEG to create a parse tree for a simple grammar. The tree is represented using lists and tuples. Here's an example: [('command', [('directives', [('directive', [('name', 'retrieve')]), ('directive', [('name', 'commit')])]), ('filename', [('name', 'f30502')])])] My question is what do I do with it at this point? I know a lot depends on what I am trying to do, but I haven't been able to find much about consuming/using parse trees, only creating them. Does anyone have any pointers to references I might use? Thanks for your help.

    Read the article

  • How does git fetches commits associated to a file ?

    - by liadan
    I'm writing a simple parser of .git/* files. I covered almost everything, like objects, refs, pack files etc. But I have a problem. Let's say I have a big 300M repository (in a pack file) and I want to find out all the commits which changed /some/deep/inside/file file. What I'm doing now is: fetching last commit finding a file in it by: fetching parent tree finding out a tree inside recursively repeat until I get into the file additionally I'm checking hashes of each subfolders on my way to file. If one of them is the same as in commit before, I assume that file was not changed (because it's parent dir didn't change) then I store the hash of a file and fetch parent commit finding file again and check if hash change occurs if yes then original commit (i.e. one before parent) was changing a file And I repeat it over and over until I reach very first commit. This solution works, but it sucks. In worse case scenario, first search can take even 3 minutes (for 300M pack). Is there any way to speed it up ? I tried to avoid putting so large objects in memory, but right now I don't see any other way. And even that, initial memory load will take forever :( Greets and thanks for any help!

    Read the article

  • efficiently convert string (or tuple) to ctypes array

    - by Mu Mind
    I've got code that takes a PIL image and converts it to a ctypes array to pass out to a C function: w_px, h_px = img.size pixels = struct.unpack('%dI'%(w_px*h_px), img.convert('RGBA').tostring()) pixels_array = (ctypes.c_int * len(pixels))(*pixels) But I'm dealing with big images, and unpacking that many items into function arguments seems to be noticeably slow. What's the simplest thing I can do to get a reasonable speedup? I'm only converting to a tuple as an intermediate step, so if it's unnecessary, all the better.

    Read the article

  • Search one element of a list in another list recursively

    - by androidnoob
    I have 2 lists old_name_list = [a-1234, a-1235, a-1236] new_name_list = [(a-1235, a-5321), (a-1236, a-6321), (a-1234, a-4321), ... ] I want to search recursively if the elements in old_name_list exist in new_name_list and returns the associated value with it, for eg. the first element in old_name_list returns a-4321, second element returns a-5321, and so on until old_name_list finishes. I have tried the following and it doesn't work for old_name, new_name in zip(old_name_list, new_name_list): if old_name in new_name[0]: print new_name[1] Is the method I am doing wrong or I have to make some minor changes to it? Thank you in advance.

    Read the article

  • maching strings

    - by kiran
    Write two functions, called countSubStringMatch and countSubStringMatchRecursive that take two arguments, a key string and a target string. These functions iteratively and recursively count the number of instances of the key in the target string. You should complete definitions for def countSubStringMatch(target,key): and def countSubStringMatchRecursive (target, key): For the remaining problems, we are going to explore other substring matching ideas. These problems can be solved with either an iterative function or a recursive one. You are welcome to use either approach, though you may find iterative approaches more intuitive in these cases of matching linear structures.

    Read the article

  • Creating temporary user accounts - Django

    - by RadiantHex
    Hi folks, I need to setup temporary User models for each visitors, where the visitors are obviously tied by session data. I might not be aware of it, but does Django support attaching data to Anonymous users? The only way, I am currently aware of, is to use the session dictionary part of the request object. Help would be very much appreciated!

    Read the article

  • Is it possibile to modify a link value with Beautifulsoup without recreating the all link?

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo</a> <a href="http://www.bar.com" rel="nofollow">this is bar</a> </p> is it possible to modify the <a> node values ("this i foo" and "this is bar") adding the suffix "PARSED" to the value without recreating the all link? The result need to be like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo_PARSED</a> <a href="http://www.bar.com" rel="nofollow">this is bar_PARSED</a> </p> And code should be something like: from BeautifulSoup import BeautifulSoup soup = BeautifulSoup(html) for link_tag in soup.findAll('a'): link_tag.string = link_tag.string + '_PARSED' #This obviously does not work

    Read the article

  • Removing Item From List - during iteration - what's wrong with this idiom ?

    - by monojohnny
    As an experiment, I did this: letters=['a','b','c','d','e','f','g','h','i','j','k','l'] for i in letters: letters.remove(i) print letters The last print shows that not all items were removed ? (every other was). IDLE 2.6.2 >>> ================================ RESTART ================================ >>> ['b', 'd', 'f', 'h', 'j', 'l'] >>> What's the explanation for this ? How it could this be re-written to remove every item ?

    Read the article

  • How do I most efficienty check the unique elements in a list?

    - by alex
    let's say I have a list li = [{'q':'apple','code':'2B'}, {'q':'orange','code':'2A'}, {'q':'plum','code':'2A'}] What is the most efficient way to return the count of unique "codes" in this list? In this case, the unique codes is 2, because only 2B and 2A are unique. I could put everything in a list and compare, but is this really efficient?

    Read the article

  • Project Euler: problem 8

    - by Marijus
    n = # some ridiculously large number, omitted N = [int(i) for i in str(n)] maxProduct = 0 for i in range(0,len(N)-4): newProduct = 1 is_cons = 0 for j in range(i,i+4): if N[j] == N[j+1] - 1: is_cons += 1 if is_cons == 5: for j in range(i,i+5): newProduct *= N[j] if newProduct > maxProduct: maxProduct = newProduct print maxProduct I've been working on this problem for hours now and I can't get this to work. I've tried doing this algorithm on paper and it works just fine.. Could you give me hints what's wrong ?

    Read the article

  • Creating readable html with django templates

    - by rileymat
    When using Django for html templating how do I create good html markup formatting. I am trying to make use of content blocks. But the content blocks show up at different levels of indentation in different templates. How do I get the content blocks to show indented like it would be if someone was to hand write the html. I am having the same problem with newlines; I can smash all the blocks together in the template. At that point the html looks better, but the templates are unmaintainable. I guess the question is how to you create pretty html markup with the django templating system?

    Read the article

  • element-wise lookup on one ndarray to another ndarray of different shapes

    - by fahhean
    Hi, I am new to numpy. Am wonder is there a way to do lookup of two ndarray of different shapes? for example, i have 2 ndarrays as below: X = array([[0, 3, 6], [3, 3, 3], [6, 0, 3]]) Y = array([[0, 100], [3, 500], [6, 800]]) and would like to lookup each element of X in Y, then be able to return the second column of Y: Z = array([[100, 500, 800], [500, 500, 500], [800, 100, 500]]) thanks, fahhean

    Read the article

  • Increment number in string

    - by iform
    Hi, I am stumped... I am trying to get the following output until a certain condition is met. test_1.jpg test_2.jpg .. test_50.jpg The solution (if you could remotely call it that) that I have is fileCount = 0 while (os.path.exists(dstPath)): fileCount += 1 parts = os.path.splitext(dstPath) dstPath = "%s_%d%s" % (parts[0], fileCount, parts[1]) however...this produces the following output. test_1.jpg test_1_2.jpg test_1_2_3.jpg .....etc The Question: How do I get change the number in its current place (without appending numbers to the end)? Ps. I'm using this for a file renaming tool.

    Read the article

  • TypeError: init_animals() takes 1 positional arguments but 2 were given

    - by libra
    I know this title look familiar to some old questions, but i've looked at every single one of them, none of them solves. And here is my codes: class Island (object):E,W,R,P def __init__(self, x, y): self.init_animals(y) def init_animals(y): pass isle = Island(x,y) However, i got the following error: Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 3, in __init__ TypeError: init_animals() takes 1 positional arguments but 2 were given Please tell me if i got any mistakes, im so confused by this. Best regards

    Read the article

  • Rewriting Live TCP/IP (Layer 4) Streams

    - by user213060
    I want to rewrite TCP/IP streams. Ettercap's etterfilter command lets you perform simple live replacements of TCP/IP data based on fixed strings or regexes. Example: if (ip.proto == TCP && tcp.dst == 80) { if (search(DATA.data, "gzip")) { replace("gzip", " "); msg("whited out gzip\n"); } } if (ip.proto == TCP && tcp.dst == 80) { if (search(DATA.data, "deflate")) { replace("deflate", " "); msg("whited out deflate\n"); } } http://ettercap.sourceforge.net/forum/viewtopic.php?t=2833 I would like to rewrite streams based on my own filter program instead of just simple string replacements. Anyone have an idea of how to do this? Is there anything other than Ettercap that can do live replacement like this, maybe as a plugin to a VPN software or something? The rewriting should occur at the transport layer (Layer 4) as it does in this example, instead of a lower layer packet-based approach. Thanks!

    Read the article

  • Django 1.2: Dates in admin forms don't work with Locales (I10N=True)

    - by equalium
    I have an application in Django 1.2. Language is selectable (I18N and Locale = True) When I select the english lang. in the site, the admin works OK. But when I change to any other language this is what happens with date inputs (spanish example): Correctly, the input accepts the spanish format %d/%m/%Y (Even selecting from the calendar, the date inserts as expected). But when I save the form and load it again, the date shows in the english form: %Y-%m-%d The real problem is that when I load the form to change any other text field and try to save it I get an error telling me to enter a valid date, so I have to write all dates again or change the language in the site to use the admin. I haven't specified anything for DATE_INPUT_FORMATS in settings nor have I overridden forms or models. Surely I am missing something but I can't find it. Can anybody give me a hint?

    Read the article

  • Best way to order by columns in relationships?

    - by Timmy
    im using sqlalchemy, and i have a few polymorphic tables, and i want to sort by a column in one of the relationship. i have tables a,b,c,d, with relationship a to b, b to c, c to d. a to b is one-to-many b to c and c to d are one-to-one, but polymorphic. given an item in table a, i will have a list of items b, c, d (all one to one). how do i use sqlalchemy to sort them by a column in table d?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 535 536 537 538 539 540 541 542 543 544 545 546  | Next Page >