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  • How to optimize this script

    - by marks34
    I have written the following script. It opens a file, reads each line from it splitting by new line character and deleting first character in line. If line exists it's being added to array. Next each element of array is splitted by whitespace, sorted alphabetically and joined again. Every line is printed because script is fired from console and writes everything to file using standard output. I'd like to optimize this code to be more pythonic. Any ideas ? import sys def main(): filename = sys.argv[1] file = open(filename) arr = [] for line in file: line = line[1:].replace("\n", "") if line: arr.append(line) for line in arr: lines = line.split(" ") lines.sort(key=str.lower) line = ''.join(lines) print line if __name__ == '__main__': main()

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  • Can it be a good idea to create a new table for each client of a webapp?

    - by Will
    This is semi-hypothetical, and as I've no experience in dealing with massive database tables, I have no idea if this is horrible for some reason. On to the situation: Imagine a web based application - lets say accounting software - which has 20,000 clients and each client has 1000+ entries in a table. That's 20 million rows which I know can certainly slow down complex queries. In a case like this, does it make more sense to create a new table in the database for each client? How do databases react to having 20k (or more!) tables?

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  • Creating temporary user accounts - Django

    - by RadiantHex
    Hi folks, I need to setup temporary User models for each visitors, where the visitors are obviously tied by session data. I might not be aware of it, but does Django support attaching data to Anonymous users? The only way, I am currently aware of, is to use the session dictionary part of the request object. Help would be very much appreciated!

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  • What motivates people to learn a new programming language?

    - by szabgab
    There are plenty of question asking Which Programming Language Should I Learn? but I have not found an answer yet to the question what really motivates people to learn a specific new language?. There are the people who think they should learn a new language every year for educational purpose. How do they decide on the languages to be learned? Then I guess there are people who learn a new language because people around them told it is a fun language and they can build nice things with it. Of course if the current job requires it people would learn a new language but I think if the language seems to have a potential to earn money (e.g. There are plenty of jobs in Java or ObjectiveC can be used to write apps for the iPhone and make money). So why are you learning a new language or why have you learned the languages you know?

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  • Increment number in string

    - by iform
    Hi, I am stumped... I am trying to get the following output until a certain condition is met. test_1.jpg test_2.jpg .. test_50.jpg The solution (if you could remotely call it that) that I have is fileCount = 0 while (os.path.exists(dstPath)): fileCount += 1 parts = os.path.splitext(dstPath) dstPath = "%s_%d%s" % (parts[0], fileCount, parts[1]) however...this produces the following output. test_1.jpg test_1_2.jpg test_1_2_3.jpg .....etc The Question: How do I get change the number in its current place (without appending numbers to the end)? Ps. I'm using this for a file renaming tool.

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  • command line arg?

    - by kaushik
    This is a module named XYZ. def func(x) ..... ..... if __name__=="__main__": print func(sys.argv[1]) Now I have imported this module in another code and want to use the func. How can i use it? import XYZ After this, where to give the argument, and syntax on how to call it, please?

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  • List filtering: list comprehension vs. lambda + filter

    - by Agos
    I happened to find myself having a basic filtering need: I have a list and I have to filter it by an attribute of the items. My code looked like this: list = [i for i in list if i.attribute == value] But then i thought, wouldn't it be better to write it like this? filter(lambda x: x.attribute == value, list) It's more readable, and if needed for performance the lambda could be taken out to gain something. Question is: are there any caveats in using the second way? Any performance difference? Am I missing the Pythonic Way™ entirely and should do it in yet another way (such as using itemgetter instead of the lambda)? Thanks in advance

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  • Returning all "positions" of a list

    - by Daymor
    I Have a list with "a" and "b" and the "b"'s are somewhat of a path and "a"'s are walls. Im writing a program to make a graph of all the possible moves. I got the code running to check the first "b" for possible moves, but i have NO Idea how im going to find all "b"'s , even less check them all without repeating. Major issue im having is getting the tuple coordinates of the "b"'s out of the list. Any pointers/tips?

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  • Trouble getting QMainWindow to scroll

    - by random
    A minimal example: class MainWindow(QtGui.QMainWindow): def __init__(self, parent = None): QtGui.QMainWindow.__init__(self, parent) winWidth = 683 winHeight = 784 screen = QtGui.QDesktopWidget().availableGeometry() screenCenterX = (screen.width() - winWidth) / 2 screenCenterY = (screen.height() - winHeight) / 2 self.setGeometry(screenCenterX, screenCenterY, winWidth, winHeight) layout = QtGui.QVBoxLayout() layout.addWidget(FormA()) mainWidget = QtGui.QWidget() mainWidget.setLayout(layout) self.setCentralWidget(mainWidget) FormA is a QFrame with a VBoxLayout that can expand to an arbitrary number of entries. In the code posted above, if the entries in the forms can't fit in the window then the window itself grows. I'd prefer for the window to become scrollable. I've also tried the following... replacing mainWidget = QtGui.QWidget() mainWidget.setLayout(layout) self.setCentralWidget(mainWidget) with mainWidget = QtGui.QScrollArea() mainWidget.setLayout(layout) self.setCentralWidget(mainWidget) results in the forms and entries shrinking if they can't fit in the window. Replacing it with mainWidget = QtGui.QWidget() mainWidget.setLayout(layout) scrollWidget = QtGui.QScrollArea() scrollWidget.setWidget(mainWidget) self.setCentralWidget(scrollWidget) results in the mainwidget (composed of the forms) being scrunched in the top left corner of the window, leaving large blank areas on the right and bottom of it, and still isn't scrollable. I can't set a limit on the size of the window because I wish for it to be resizable. How can I make this window scrollable?

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  • Adding custom fields to users in django

    - by Gaurav
    I am the create_user() function that Django provides to create my users. Also I want to store additional information about the users. So I tried following the instructions given at http://docs.djangoproject.com/en/dev/topics/auth/#storing-additional-information-about-users but I cannot get it to work for me. Is there a step-by-step guide that I can follow to get this to work for me? Also, once I have added these custom fields, I would obviously need to add / edit / delete data from them. I cannot seem to find any instructions on how to do this.

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  • Creating readable html with django templates

    - by rileymat
    When using Django for html templating how do I create good html markup formatting. I am trying to make use of content blocks. But the content blocks show up at different levels of indentation in different templates. How do I get the content blocks to show indented like it would be if someone was to hand write the html. I am having the same problem with newlines; I can smash all the blocks together in the template. At that point the html looks better, but the templates are unmaintainable. I guess the question is how to you create pretty html markup with the django templating system?

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  • How does git fetches commits associated to a file ?

    - by liadan
    I'm writing a simple parser of .git/* files. I covered almost everything, like objects, refs, pack files etc. But I have a problem. Let's say I have a big 300M repository (in a pack file) and I want to find out all the commits which changed /some/deep/inside/file file. What I'm doing now is: fetching last commit finding a file in it by: fetching parent tree finding out a tree inside recursively repeat until I get into the file additionally I'm checking hashes of each subfolders on my way to file. If one of them is the same as in commit before, I assume that file was not changed (because it's parent dir didn't change) then I store the hash of a file and fetch parent commit finding file again and check if hash change occurs if yes then original commit (i.e. one before parent) was changing a file And I repeat it over and over until I reach very first commit. This solution works, but it sucks. In worse case scenario, first search can take even 3 minutes (for 300M pack). Is there any way to speed it up ? I tried to avoid putting so large objects in memory, but right now I don't see any other way. And even that, initial memory load will take forever :( Greets and thanks for any help!

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  • Why use threading data race will occur, but will not use gevent

    - by onlytiancai
    My test code is as follows, using threading, count is not 5,000,000 , so there has been data race, but using gevent, count is 5,000,000, there was no data race . Is not gevent coroutine execution will atom "count + = 1", rather than split into a one CPU instruction to execute? # -*- coding: utf-8 -*- import threading use_gevent = True use_debug = False cycles_count = 100*10000 if use_gevent: from gevent import monkey monkey.patch_thread() count = 0 class Counter(threading.Thread): def __init__(self, name): self.thread_name = name super(Counter, self).__init__(name=name) def run(self): global count for i in xrange(cycles_count): if use_debug: print '%s:%s' % (self.thread_name, count) count = count + 1 counters = [Counter('thread:%s' % i) for i in range(5)] for counter in counters: counter.start() for counter in counters: counter.join() print 'count=%s' % count

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  • how to do this problem?

    - by Sachin Tendulkar
    Write an iterative program that finds the largest number of McNuggets that cannot be bought in exact quantity. Your program should print the answer in the following format (where the correct number is provided in place of n): "Largest number of McNuggets that cannot be bought in exact quantity: n"

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  • filter queryset based on list, including None

    - by jujule
    Hi all I dont know if its a django bug or a feature but i have a strange ORM behaviour with MySQL. class Status(models.Model): name = models.CharField(max_length = 50) class Article(models.Model) status = models.ForeignKey(status, blank = True, null=True) filters = Q(status__in =[0, 1,2] ) | Q(status=None) items = Article.objects.filter(filters) this returns Article items but some have other status than requested [0,1,2,None] looking at the sql query : SELECT [..] FROM `app_article` LEFT OUTER JOIN `app_status` ON (`app_article`.`status_id` = `app_status`.`id`) WHERE (`app_article`.`status_id` IN (1, 2) OR `app_status`.`id` IS NULL) ORDER BY [...] the OR app_status.id IS NULL part seems to be the cause. if i change it to OR app_article.status_id IS NULL it works correctly. How to deal with this ? Thanx.

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  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

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  • Removing Item From List - during iteration - what's wrong with this idiom ?

    - by monojohnny
    As an experiment, I did this: letters=['a','b','c','d','e','f','g','h','i','j','k','l'] for i in letters: letters.remove(i) print letters The last print shows that not all items were removed ? (every other was). IDLE 2.6.2 >>> ================================ RESTART ================================ >>> ['b', 'd', 'f', 'h', 'j', 'l'] >>> What's the explanation for this ? How it could this be re-written to remove every item ?

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