Discrepancy in file size on disk and ls output
- by smokinguns
I have a script that checks for gzipped file sizes greater than 1MB and outputs files along with their sizes as a report.
This is the code:
myReport=`ls -ltrh "$somePath" | egrep '\.gz$' | awk '{print $9,"=>",$5}'`
# Count files that exceed 1MB
oversizeFiles=`find "$somePath" -maxdepth 1 -size +1M -iname "*.gz" -print0 | xargs -0 ls -lh | wc -l`
if [ $oversizeFiles -eq 0 ];then
status="PASS"
else
status="CHECK FAILED. FOUND FILES GREATER THAN 1MB"
fi
echo -e $status"\n"$myReport
The problem is that ls command outputs the files sizes as 1.0MB in the report but the status is "FAIL" as "$oversizeFiles" variable's value is 2. I checked the file sizes on disk and 2 files are 1.1MB.
Why this discrepancy? How should I modify the script so that I can generate an accurate report?
BTW, I'm on a Mac.
Here is what man page for "find" says on my Mac OSX:
-size n[ckMGTP]
True if the file's size, rounded up, in 512-byte blocks is n.
If n is followed by a c,then the primary is true if the file's size is n bytes (characters).
Similarly if n is followed by a scale indicator then the file's size is compared to n scaled as:
k kilobytes (1024 bytes)
M megabytes (1024 kilobytes)
G gigabytes (1024 megabytes)
T terabytes (1024 gigabytes)
P petabytes (1024 terabytes)
