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  • git submodule pull and commit automatically on webserver

    - by Lukas Oppermann
    I have the following setup, I am working on a project project with the submodule submodule. Whenever I push changes to github it sends a post request to update.php on the server. This php file executes a git command. Without submodules I can just do a git pull and everything is fine but with submodules it is much more difficult. I have this at the moment, but it does not do what I want. I should git pull the repo and update and pull the latest version of each submodule. <?php echo `git submodule foreach 'git checkout master; git pull; git submodule update --init --recursive; git commit -m "updating"' && git pull && git submodule foreach 'git add -A .' && git commit -m "updating to latest version including submodules" 2>&1s`; EDIT// Okay, I got it half way done. <?php echo `git submodule foreach 'git checkout master; git pull; git submodule update --init --recursive; git commit -am "updating"; echo "updated"' && git pull && git commit -am "updating to latest version including submodules" && echo 'updated'`; The echo prevents the script to stop because of non-zero returned. It works 100% fine when I run it from the console using php update.php. When github initialized the file, or I run it from the browser it still does not work. Any ideas?

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  • Nested Array with one foreach Loop?

    - by streetparade
    I need to have access to a array which looks like this. Array ( [0] => Array ( [54] => Array ( [test] => 54 [tester] => result ) ) ) foreach($array as $key=>$value) { echo $key;// prints 0 echo $value;// prints Array /* now i can iterate through $value but i dont want it solve that way example: foreach($value as $k=>$v) { echo $k;//prints test echo $v; //prints 54 } */ } How can iterate just once ? to get the values of test and tester? I hope i could explain my problem clear

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  • How to remove the first and last character from a file using batch script?

    - by infant programmer
    This is my input file content which I am using to copy to the output file. #sdfs|dfasf|sdfs| sdfs|df!@$%%*&!sdffs| sasdfasfa|dfsdf|#sdfs| What I need to do is to omit the first character '#' and last character '|' in the output file. So the output will be, sdfs|dfasf|sdfs| sdfs|df!@$%%*&!sdffs| sasdfasfa|dfsdf|#sdfs Batch script is new to me, but I tried my best and tried these codes, :: drop first and last char @echo off > xyz.txt & setLocal EnableDelayedExpansion for /f "tokens=* delims=" %%a in (E:\abc1.txt) do ( set str=%%a set str=!str:~1! echo !str!>> xyz.txt ) and @echo off > xyz.txt setLocal EnableDelayedExpansion for /f "tokens=1,2 delims= " %%a in (E:\abc1.txt) do ( set /a N+=1 if !N! gtr 2 ( echo %%a >> xyz.txt ) else ( set str=%%a set str=!str:#=! echo !str! >> xyz.txt ) ) As you can see they are not able to produce the required output.

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  • forcing a download using PHP / jQuery

    - by Dirty-flow
    I know there are already many questions about forcing a download with PHP, but I can't find what I'm doing wrong and what should I do. I'm having an list with filenames, and I want to download one of them by clicking a button. My jQuery: $(".MappeDownload").on("click",function(e){ e.stopPropagation(); fileId=$(this).val() $.post("ajax/DownloadFile.php",{ id : fileId}) }) and on the server side I have a table with the file names and the file path. $sql = "SELECT vUploadPfad, vUploadOriginname FROM tabUpload WHERE zUploadId='$_POST[id]'"; $result = mysql_query($sql) or die(""); $file = mysql_fetch_array($result); $localfile = $file["vUploadPfad"]; $name=$file["vUploadOriginname"]; $fp = fopen($localfile, 'rb'); header("Cache-Control: "); header("Pragma: "); header("Content-Type: application/octet-stream"); header("Content-Length: " . filesize($localfile)); header("Content-Disposition: attachment; filename='".$name."';"); header("Content-Transfer-Encoding: binary\n"); fpassthru($fp); exit; The AJAX request is successful, I'm getting the right header(filesize, filename etc...) but the download are not starting.

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  • How do I find the millionth number in the series: 2 3 4 6 9 13 19 28 42 63 ... ?

    - by HH
    It takes about minute to achieve 3000 in my comp but I need to know the millionth number in the series. The definition is recursive so I cannot see any shortcuts except to calculate everything before the millionth number. How can you fast calculate millionth number in the series? Series Def n_{i+1} = \floor{ 3/2 * n_{i} } and n_{0}=2. Interestingly, only one site list the series according to Google: this one. Too slow Bash code #!/bin/bash function series { n=$( echo "3/2*$n" | bc -l | tr '\n' ' ' | sed -e 's@\\@@g' -e 's@ @@g' ); # bc gives \ at very large numbers, sed-tr for it n=$( echo $n/1 | bc ) #DUMMY FLOOR func } n=2 nth=1 while [ true ]; #$nth -lt 500 ]; do series $n # n gets new value in the function through global value echo $nth $n nth=$( echo $nth + 1 | bc ) #n++ done

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  • jquery load function not working

    - by pradeep
    function newPage(pagenum) { /* load page default from server - pass product name */ $('#data').html("<div id='response'>Loading.....</div>").load( '/college/college_change.php', { product:'college', city:"<?php echo $city ?>", university:"<?php echo $university ?>", programmes:"<?php $programmes ?>", type:"<?php echo $type ?>", entrance_exams:"<?php echo $entrance_exams ?>", pagenum:pagenum }); } I am using this load function, it works well in most browsers, but in IE it does not load the data.

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  • Why is my upload-of-a-file code putting 2 sets of files into my directory? (PHP)

    - by ggfan
    When I upload a file using this code, it puts a copy of the file in the "uploads" folder(which is what I want) but it also puts a copy in my root. I only want the files going to the uploads folder. define ('GW_UPLOADPATH', 'uploads/'); $upfile= GW_UPLOADPATH . $_FILES['userfile']['name']; if(is_uploaded_file($_FILES['userfile']['tmp_name'])) { if(!move_uploaded_file($_FILES['userfile']['tmp_name'], $upfile)) //this is saying if the file isn't moved to $upfile. { echo 'Problem: could not move file to destination directory'; exit; } } else { echo 'Problem: Possible file upload attack. Filename: '; //this could be an attack b/c it might be from localhost. echo $_FILES['userfile']['name']; exit; } echo 'File uploaded successfully<br><br>';

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  • upload form only works in Firefox when uploading ASCII .stl 3D files

    - by NathanPDX
    uploadform.html and upload_file.php (below) works fine in Firefox but fails in Chrome, IE, and Safari when uploading ASCII .stl 3D files. Error message is "Invalid file" and problem occurs with multiple computers and multiple .stl files. When I modify the code to support other file types like JPG and PDF it allows those file types in all three web browsers. Also, Firefox only allows the .stl upload if I include application/octet-stream in the mime types section. Why doesn't this work outside of Firefox? uploadform.html: <!doctype html> <html> <body> <form action="upload_file.php" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> upload_file.php: <!doctype html> <html> <body> <?php $allowedExts = array("stl"); $extension = end(explode(".", $_FILES["file"]["name"])); if ( ( ($_FILES["file"]["type"] == "application/sla") || ($_FILES["file"]["type"] == "application/octet-stream") || ($_FILES["file"]["type"] == "text/plain") || ($_FILES["file"]["type"] == "application/unknown") ) && ($_FILES["file"]["size"] < 2000000) && in_array($extension, $allowedExts) ) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] /1024) . " KB<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "successful upload"; } } } else { echo "Invalid file"; } ?> </body> </html>

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  • Having trouble with php and ajax search function

    - by Andy
    I am still quite new to php/ajax/mysql. In anycase, I'm creating a search function which is returning properly the data I'm looking for. In brief, I have a mysql database set up. A php website that has a search function. I'm now trying to add a link to a mysql database search rather than just showing the results. In my search.php, the echo line is working fine but the $string .= is not returning anything. I'm just trying to get the same as the echo but with the link to the mysql php record. Am I missing something simple? //echo $query; $result = mysqli_query($link, $query); $string = ''; if($result) { if(mysqli_affected_rows($link)!=0) { while($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo '<p> <b>'.$row['title'].'</b> '.$row['post_ID'].'</p>'; $string .= "<p><a href='set-detail.php?recordID=".$row->post_ID."'>".$row->title."</a></p>"; } } else { echo 'No Results for :"'.$_GET['keyword'].'"'; }

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  • How can I have a newline in a string in sh?

    - by juannavarroperez
    This STR="Hello\nWorld" echo $STR produces as output Hello\nWorld instead of Hello World What should I do to have a newline in a string? I'm aware of echo -e, but I'm no sending the string to echo, the string will be used as an argument by another command that doesn't know how to interpret \n as a newline.

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  • Correct to check for a command line flag in bash

    - by BCS
    In the middle of a scrip, I want to check if a given flag was passed on the command line. The following does what I want but seems ugly: if echo $* | grep -e "--flag" -q then echo ">>>> Running with flag" else echo ">>>> Running without flag" fi Is there a better way? Note: I explicitly don't want to list all the flags in a switch/getopt. (And BTW the bodies of the if just set a set of vars)

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • cakephp - form for belongsTo Model

    - by user1511579
    I createt the following model to link 2 relational tables: class Ficha extends AppModel { //public $useTable = 'ficha_seg'; var $primaryKey = 'id_ficha'; var $name = 'Ficha'; var $belongsTo = array( 'Perigo' => array( 'className' => 'Perigo', 'foreignKey' => false, 'conditions' => 'Perigo.id_fichas = Ficha.id_ficha' ) ); } Now, i have a form that requires data from the class Ficha, and then is redirected to another ctp page where i will input the data for the table "Perigos". However, since i'm still a newbie in cakephp i'm having difficult building that second form to insert the data on the table "Perigos". Here goes the code i built at the moment related to the second form: FichasController.php (the method where is it supposed to save the data on the table "Perigos": public function preencher_ficha(){ if ($this->request->is('ficha')) { $this->Ficha->create(); if ($this->Ficha->Perigo->save($this->request->data)) { $last_id=$this->Ficha->getLastInsertID(); $this->Session->setFlash('Your post has been updated '.$last_id.'.'); //$this->redirect(array('action' => 'preencher_ficha')); } else { $this->Session->setFlash('Unable to qualquer coisa your post.'); } } } The preencher_ficha.ctp file with the form: echo $this->Form->create('Ficha->Perigo', array('action' => 'index')); echo $this->Form->input('class_subst', array('label' => 'Classificação:')); echo $this->Form->input('simbolos_perigo', array('label' => 'Símbolos:')); echo $this->Form->input('frases_r', array('label' => 'Frases:')); echo $this->Form->end('Finalizar Ficha'); Here i guess the create part is wrong, but i think i have errors too in the controller part.

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  • MOOTOOLS calling sexy.error() from PHP

    - by Mikey1980
    I am very inexperienced with PHP and I've having trouble calling a mootools function. Here's my code: echo '<script language="JavaScript">'; echo "Sexy.error('Test!');"; echo '</script>'; When I try it with a simple alert('test') it works just fine.. I'm confused?!?

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  • Cron job execute backup.bash

    - by leejava
    Dear all, I wish to let cron executes backup.bash, but when I try to create cron as below: */1 * * * * /var/www/mango_gis/delete_snapshot.bash /dev/null It didn't execute my script at all. Here is my script as below: #!/bin/bash get() { local pos=$1 shift eval 'echo ${'$pos'}'; } length(){ echo $#; } find_snapshots() { echo $(ec2-describe-snapshots | xargs -n1 basename); } snapshots=$(find_snapshots) len=$(length $snapshots) row_count=$(($len/6)) if(($row_count 6)); then delete_count=$(($row_count-6)) for (( i=1; i<=$delete_count; i++ )); do ec2-delete-snapshot $(echo $(get $((2+$((6*$(($i-1)))))) $snapshots)) /dev/null done fi Please advise... Leakhina

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  • Not Inserted into database in PHP script

    - by Aruna
    Hi, i am having an form for uploading an excel file like <form enctype="multipart/form-data" action="http://localhost/joomla/Joomla_1.5.7/index.php?option=com_jumi&fileid=7" method="POST"> Please choose a file: <input name="file" type="file" id="file" /><br /> <input type="submit" value="Upload" /> </form> And in the FIle http://localhost/joomla/Joomla_1.5.7/index.php?option=com_jumi&fileid=7 i have retrived the uploaded file contents by <?php echo "Name". $_FILES['file']['name'] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Stored in: " . $_FILES["file"]["tmp_name"] . "<br />"; $string = file_get_contents( $_FILES["file"]["tmp_name"] ); foreach ( explode( "\n", $string ) as $userString ) { $userString = trim( $userString ); echo $userString; $array = explode( ';', $userString ); $userdata = array ( 'cf_id'=>trim( $array[0] ), 'text_0'=>trim( $array[1] ), 'text_1'=>trim( $array[2] ), 'text_2'=>trim( $array[3] ), 'text_3'=>trim($array[4]), 'text_6'=>trim($array[5]), 'text_7'=>trim($array[6]), 'text_9'=>trim($array[7]), 'text_12'=>trim($array[8])); global $db; $db =& JFactory::getDBO(); $query = 'INSERT INTO #__chronoforms_UploadAuthor VALUES ("'.$userdata['cf_id'].'","'.$userdata['text_0'].'","'.$userdata['text_1'].'","'.$userdata['text_2'].'","'.$userdata['text_3'].'","'.$userdata['text_6'].'","'.$userdata['text_7'].'","'.$userdata['text_9'].'")'; $db->Execute($query); echo "<br>"; } i am trying to insert the contents into the table #__chronoforms_UploadAuthor in Joomla database . it doent shows any error but it is not inserted into the database.. Please help me.. Y the contents are not inserted into the database...And how to make it inserted into the database..

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  • How do I get this php statement that gets all the values from database and outputs as checkboxes to

    - by ggfan
    I am a bit lost in all these "" and '' and . in this statement. Basically this query is to get all the tagname from table "tag" and display them for the users as checkboxes. If they have clicked 'submit' and they missed another field(say the title of a post), it would still have the tag they chose displayed. The part I need help with is the echoing part. It doesn't seem to remember the tag when they click submit. $query4 = "SELECT * FROM tags ORDER BY tagname"; $data4 = mysqli_query($dbc, $query4); while ($row4 = mysqli_fetch_array($data4)) { echo "<li><input type='checkbox' name='postingtag[]'"; if (!empty($postingtag)){ echo "value='$postingtag'"; } else{ echo "value='{$row4['tagID']}'"; } echo ">{$row4['tagname']}</li>"; }

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  • How do I create links in the cells of a PHP generated table?

    - by typoknig
    I have a table generated from some PHP code that lists a SMALL amount of important information for employees. I want to make it so each row, or at least one element in each row can be clicked on so the user will be redirected to ALL of the information (pulled from MySQL database) related to the employee who was clicked on. I am not sure how would be the best way to go about this, but I am open to suggestions. I would like to stick to PHP and/or JavaScript. Below is the code for my table: <table> <tr> <td id="content_heading" width="25px">ID</td> <td id="content_heading" width="150px">Last Name</td> <td id="content_heading" width="150px">First Name</td> <td id="content_heading" width="75px">SSN</td> </tr> <?php $user = 'user'; $pass = 'pass'; $server = 'localhost'; $link = mysql_connect($server, $user, $pass); if (!$link){ die('Could not connect to database!' . mysql_error()); } mysql_select_db('mydb', $link); $query = "SELECT * FROM employees"; $result = mysql_query($query); mysql_close($link); $num = mysql_num_rows($result); for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr class=".$class.">"; echo "<td>".$row[id]."</td>"; echo "<td>".$row[l_name]."</td>"; echo "<td>".$row[f_name]."</td>"; echo "<td>".$row[ssn]."</td>"; echo "</tr>"; } ?> </table>

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  • Batch To Bash Conversion

    - by Steven
    I need to know this Batch Script into Bash : @echo off set /p name= Name? findstr /m "%name%" ndatabase.txt if %errorlevel%==0 ( cls echo The name is found in the database! pause >nul exit ) cls echo. echo Name not found in database. pause >nul exit I am new to the Linux Kernel, so starting off with an easy distro - Ubuntu 12.10. My problem is that I do not really know much of Bash Script, since I am very accustomed to the Batch Script format; which is obviously a bad habit for my C++.

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • Millionth number in the serie 2 3 4 6 9 13 19 28 42 63 ... ?

    - by HH
    It takes about minute to achieve 3000 in my comp but I need to know the millionth number in the serie. The definition is recursive so I cannot see any shortcuts except to calculate everything before the millionth number. How can you fast calculate millionth number in the serie? Serie Def n_{i+1} = \floor{ 3/2 * n_{i} } and n_{0}=2. Interestingly, only one site list the serie according to Goolge: this one. Too slow Bash code #!/bin/bash function serie { n=$( echo "3/2*$n" | bc -l | tr '\n' ' ' | sed -e 's@\\@@g' -e 's@ @@g' ); # bc gives \ at very large numbers, sed-tr for it n=$( echo $n/1 | bc ) #DUMMY FLOOR func } n=2 nth=1 while [ true ]; #$nth -lt 500 ]; do serie $n # n gets new value in the function throught global value echo $nth $n nth=$( echo $nth + 1 | bc ) #n++ done

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  • Display a list of all attributes in opencart

    - by Catalin Dragos Vladulescu
    I want to display a list of all attributes that are added into database but every time I try something it doesn't work. I want to show this inside a div from the from the front page. I tried to insert this into featured.tpl: <?php foreach ($attribute_groups as $attribute_group) { echo $attribute_group['name']; print_r($attribute_group); echo '<select name="listaGrupe">'; foreach ($attribute_groups['attribute'] as $attribute) { echo '<option value="'.$attribute.'">'.$attribute.'</option>'; } echo '</select>'; } ?>

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  • Can this be done in 1 line? [PHP]

    - by Angelo
    Can this be done in 1 line with PHP? Would be awesome if it could: $out = array("foo","bar"); echo $out[0]; Something such as: echo array("foo","bar")[0]; Unfortunately that's not possible. Would it be possible like this? So I can do this for example in 1 line: echo array(rand(1,100), rand(1000,2000))[rand(0,1)];

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