Passing multiple aruments to a UNIX shell script
- by Waffles
Hello all,
I have the following (bash) shell script, that I would ideally use to kill multiple processes by name.
#!/bin/bash
kill `ps -A | grep $* | awk '{ print $1 }'`
However, while this script works is one argument is passed:
end chrome
(the name of the script is end)
it does not work if more than one argument is passed:
$end chrome firefox
grep: firefox: No such file or directory
What is going on here? I thought the $* passes multiple arguments to the shell script in sequence. I'm not mistyping anything in my input - and I the programs I wan to kill (chrome and firefox) are open.
Any help is appreciated.
