Search Results

Search found 14302 results on 573 pages for 'saved password'.

Page 542/573 | < Previous Page | 538 539 540 541 542 543 544 545 546 547 548 549  | Next Page >

  • Feedback on Optimizing C# NET Code Block

    - by Brett Powell
    I just spent quite a few hours reading up on TCP servers and my desired protocol I was trying to implement, and finally got everything working great. I noticed the code looks like absolute bollocks (is the the correct usage? Im not a brit) and would like some feedback on optimizing it, mostly for reuse and readability. The packet formats are always int, int, int, string, string. try { BinaryReader reader = new BinaryReader(clientStream); int packetsize = reader.ReadInt32(); int requestid = reader.ReadInt32(); int serverdata = reader.ReadInt32(); Console.WriteLine("Packet Size: {0} RequestID: {1} ServerData: {2}", packetsize, requestid, serverdata); List<byte> str = new List<byte>(); byte nextByte = reader.ReadByte(); while (nextByte != 0) { str.Add(nextByte); nextByte = reader.ReadByte(); } // Password Sent to be Authenticated string string1 = Encoding.UTF8.GetString(str.ToArray()); str.Clear(); nextByte = reader.ReadByte(); while (nextByte != 0) { str.Add(nextByte); nextByte = reader.ReadByte(); } // NULL string string string2 = Encoding.UTF8.GetString(str.ToArray()); Console.WriteLine("String1: {0} String2: {1}", string1, string2); // Reply to Authentication Request MemoryStream stream = new MemoryStream(); BinaryWriter writer = new BinaryWriter(stream); writer.Write((int)(1)); // Packet Size writer.Write((int)(requestid)); // Mirror RequestID if Authenticated, -1 if Failed byte[] buffer = stream.ToArray(); clientStream.Write(buffer, 0, buffer.Length); clientStream.Flush(); } I am going to be dealing with other packet types as well that are formatted the same (int/int/int/str/str), but different values. I could probably create a packet class, but this is a bit outside my scope of knowledge for how to apply it to this scenario. If it makes any difference, this is the Protocol I am implementing. http://developer.valvesoftware.com/wiki/Source_RCON_Protocol

    Read the article

  • Losing session after Login - Java

    - by Patrick Villela
    I'm building an application that needs to login to a certain page and make a navigation. I can login, provided that the response contains a string that identifies it. But, when I navigate to the second page, I can't see the page as a logged user, only as anonymous. I'll provide my code. import java.net.*; import java.security.*; import java.security.cert.*; import javax.net.ssl.*; import java.io.*; import java.util.*; public class PostTest { static HttpsURLConnection conn = null; private static class DefaultTrustManager implements X509TrustManager { @Override public void checkClientTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public void checkServerTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public X509Certificate[] getAcceptedIssuers() { return null; } } public static void main(String[] args) { try { SSLContext ctx = SSLContext.getInstance("TLS"); ctx.init(new KeyManager[0], new TrustManager[] {new DefaultTrustManager()}, new SecureRandom()); SSLContext.setDefault(ctx); String data = URLEncoder.encode("txtUserName", "UTF-8") + "=" + URLEncoder.encode(/*username*/, "UTF-8"); data += "&" + URLEncoder.encode("txtPassword", "UTF-8") + "=" + URLEncoder.encode(/*password*/", "UTF-8"); data += "&" + URLEncoder.encode("envia", "UTF-8") + "=" + URLEncoder.encode("1", "UTF-8"); connectToSSL(/*login url*/); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; String resposta = ""; while((line = rd.readLine()) != null) { resposta += line + "\n"; } System.out.println("valid login -> " + resposta.contains(/*string that assures me I'm looged in*/)); connectToSSL(/*first navigation page*/); rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); while((line = rd.readLine()) != null) { System.out.println(line); } } catch(Exception e) { e.printStackTrace(); } } private static void connectToSSL(String address) { try { URL url = new URL(address); conn = (HttpsURLConnection) url.openConnection(); conn.setHostnameVerifier(new HostnameVerifier() { @Override public boolean verify(String arg0, SSLSession arg1) { return true; } }); } catch(Exception ex) { ex.printStackTrace(); } } } Any further information, just ask. Thanks in advance.

    Read the article

  • how to insert into database from stored procedure in log4net?

    - by Samreen
    I have to log thread context properties like this: string logFilePath = AppDomain.CurrentDomain.BaseDirectory + "log4netconfig.xml"; FileInfo finfo = new FileInfo(logFilePath); log4net.Config.XmlConfigurator.ConfigureAndWatch(finfo); ILog logger = LogManager.GetLogger("Exception.Logging"); log4net.ThreadContext.Properties["MESSAGE"] = exception.Message; log4net.ThreadContext.Properties["MODULE"] = "module1"; log4net.ThreadContext.Properties["COMPONENT"] = "component1"; logger.Debug("test"); and the configuration file is: <configuration> <configSections> <section name="log4net" type="log4net.Config.Log4NetConfigurationSectionHandler,Log4net"/> </configSections> <log4net> <logger name="Exception.Logging" level="Debug"> <appender-ref ref="AdoNetAppender"/> </logger> <appender name="AdoNetAppender" type="log4net.Appender.AdoNetAppender"> <connectionString value="Data Source=xe;User ID=test;Password=test;" /> <connectionType value="System.Data.OracleClient.OracleConnection, System.Data.OracleClient, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" /> <bufferSize value="10000"/> <commandText value="Log_Exception_Pkg.Insert_Log" /> <commandType value="StoredProcedure" /> <parameter> <parameterName value="@p_Error_Message" /> <dbType value="String" /> <size value="255" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{MESSAGE}"/> </layout> </parameter> <parameter> <parameterName value="@p_Module" /> <dbType value="String" /> <size value="225" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{MODULE}"/> </layout> </parameter> <parameter> <parameterName value="@p_Component" /> <dbType value="String" /> <size value="225" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{COMPONENT}"/> </layout> </parameter> </appender> </log4net> </configuration> But its not inserting them in the database. How can I get that to work?

    Read the article

  • current_user.user_type_id = @employer ID

    - by sscirrus
    I am building a system with a User model (authenticated using AuthLogic) and three user types in three models: one of these models is Employer. Each of these three models has_many :users, :as = :authenticable. I start by having a new visitor to the site create their own 'User' record with username, password, which user type they are, etc. Upon creation, the user is sent to the 'new' action for one of the three models. So, if they tell us they are an employer, we redirect_to :controller = "employers, :action = "new". Question: When the employer has submitted, I want to set the current_user.user_type_id equal to the employer ID. This should be simple... but it's not working. # Employers Controller / new def new @employer = Employer.new 1.times {@employer.addresses.build} render :layout => 'forms' end # Employers Controller / create def create @employer = Employer.new(params[:employer]) if @employer.save if current_user.blank? redirect_to :controller => "users", :action => "new" else current_user.user_type_id = @employer.id current_user.user_type = "Employer" redirect_to :action => "home", :id => current_user.user_type_id end else render :action => "new" end end ------UPDATE------ Hi guys. In response: I am using this table structure because each of my three user type models have lots of different fields and each has different relationships to the other models, which is why I've avoided STI. By 1.times (@employer.addresses.build) I'm connecting the employer model to the address polymorphic table in one form, so I'm asking the controller to build a new address to go along with the new employer. Averell: you mentioned encapsulating... something in the model using a 'setter' method. I have no idea what you mean by this - could you please explain how this works (or direct me to an example elsewhere)? With tsdbrown's answer I have managed to create the behavior I want... if there's a more elegant way to accomplish the same thing I'd love to learn how. Thanks very much. Thanks to tsdbrown for answering the current_user.save problem!

    Read the article

  • HttpWebRequest possibly slowing website

    - by Steven Smith
    Using Visual studio 2012, C#.net 4.5 , SQL Server 2008, Feefo, Nopcommerce Hey guys I have Recently implemented a new review service into a current site we have. When the change went live the first day all worked fine. Since then though the sending of sales to Feefo hasnt been working, There are no logs either of anything going wrong. In the OrderProcessingService.cs in Nop Commerce's Service, i call a HttpWebrequest when an order has been confirmed as completed. Here is the code. var email = HttpUtility.UrlEncode(order.Customer.Email.ToString()); var name = HttpUtility.UrlEncode(order.Customer.GetFullName().ToString()); var description = HttpUtility.UrlEncode(productVariant.ProductVariant.Product.MetaDescription != null ? productVariant.ProductVariant.Product.MetaDescription.ToString() : "product"); var orderRef = HttpUtility.UrlEncode(order.Id.ToString()); var productLink = HttpUtility.UrlEncode(string.Format("myurl/p/{0}/{1}", productVariant.ProductVariant.ProductId, productVariant.ProductVariant.Name.Replace(" ", "-"))); string itemRef = ""; try { itemRef = HttpUtility.UrlEncode(productVariant.ProductVariant.ProductId.ToString()); } catch { itemRef = "0"; } var url = string.Format("feefo Url", login, password,email,name,description,orderRef,productLink,itemRef); var request = (HttpWebRequest)WebRequest.Create(url); request.KeepAlive = false; request.Timeout = 5000; request.Proxy = null; using (var response = (HttpWebResponse)request.GetResponse()) { if (response.StatusDescription == "OK") { var stream = response.GetResponseStream(); if(stream != null) { using (var reader = new StreamReader(stream)) { var content = reader.ReadToEnd(); } } } } So as you can see its a simple webrequest that is processed on an order, and all product variants are sent to feefo. Now: this hasnt been happening all week since the 15th (day of the implementation) the site has been grinding to a halt recently. The stream and reader in the the var content is there for debugging. Im wondering does the code redflag anything to you that could relate to the process of website? Also note i have run some SQL statements to see if there is any deadlocks or large escalations, so far seems fine, Logs have also been fine just the usual logging of Bots. Any help would be much appreciated! EDIT: also note that this code is in a method that is called and wrapped in A try catch UPDATE: well forget about the "not sending", thats because i was just told my code was rolled back last week

    Read the article

  • First record does not show in pagination script

    - by whitstone86
    This is my pagination script which extracts info for my TV guide project that I am working on. Currently I've been experimenting with different PHP/MySQL before it becomes a production site. This is my current script: <?php /*********************************** * PhpMyCoder Paginator * * Created By PhpMyCoder * * 2010 PhpMyCoder * * ------------------------------- * * You may use this code as long * * as this notice stays intact and * * the proper credit is given to * * the author. * ***********************************/ // set the default timezone to use. Available since PHP 5.1 putenv("TZ=US/Eastern") ?> <head> <title> Pagination Test - Created By PhpMyCoder</title> <style type="text/css"> #nav { font: normal 13px/14px Arial, Helvetica, sans-serif; margin: 2px 0; } #nav a { background: #EEE; border: 1px solid #DDD; color: #000080; padding: 1px 7px; text-decoration: none; } #nav strong { background: #000080; border: 1px solid #DDD; color: #FFF; font-weight: normal; padding: 1px 7px; } #nav span { background: #FFF; border: 1px solid #DDD; color: #999; padding: 1px 7px; } </style> </head> <?php //Require the file that contains the required classes include("pmcPagination.php"); //PhpMyCoder Paginator $paginator = new pmcPagination(20, "page"); //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, airdate, expiration, episode, setreminder FROM lagunabeach where expiration >= now() order by airdate, 3 ASC LIMIT 0, 100;"); //You can also add reuslts to paginate here mysql_data_seek($queryresult,0) ; while($row = mysql_fetch_array($result)) { $paginator->add(new paginationData($row['programme'], $row['channel'], $row['airdate'], $row['expiration'], $row['episode'], $row['setreminder'])); } ?> <?php //Show the paginated results $paginator->paginate (); ?><? include("pca-footer1.php"); ?> <?php //Show the navigation $paginator->navigation(); ?> Despite me having two records for the programmes airing today, it only shows records from the second one onwards - the programme that airs at 8:35pm UK time GMT does not show, but the later 11:25pm UK time GMT one does show. How should I fix this? Above is my code if that is of any use! Thanks

    Read the article

  • Java ME scorecard with vector and multiple input fields/screens

    - by proximity
    I have made a scorecard with 5 holes, for each a input field (shots), and a image is shown. The input should be saved into a vector and shown on each hole, eg. hole 2: enter shots, underneath it "total shots: 4" (if you have made 4 shots on hole 1). In the end I would need a sum up of all shots, eg. Hole 1: 4 Hole 2: 3 Hole 3: 2 ... Total: 17 Could someone please help me with this task? { f = new Form("Scorecard"); d = Display.getDisplay(this); mTextField = new TextField("Shots:", "", 2, TextField.NUMERIC); f.append(mTextField); mStatus = new StringItem("Hole 1:", "Par 3, 480m"); f.append(mStatus); try { Image j = Image.createImage("/hole1.png"); ImageItem ii = new ImageItem("", j, 3, "Hole 1"); f.append(ii); } catch (java.io.IOException ioe) {} catch (Exception e) {} f.addCommand(mBackCommand); f.addCommand(mNextCommand); f.addCommand(mExitCommand); f.setCommandListener(this); Display.getDisplay(this).setCurrent(f); } public void startApp() { mBackCommand = new Command("Back", Command.BACK, 0); mNextCommand = new Command("Next", Command.OK, 1); mExitCommand = new Command("Exit", Command.EXIT, 2); } public void pauseApp() { } public void destroyApp(boolean unconditional) { } public void commandAction(Command c, Displayable d) { if (c == mExitCommand) { destroyApp(true); notifyDestroyed(); } else if ( c == mNextCommand) { // -> go to next hole input! save the mTextField input into a vector. } } } ------------------------------ Full code --------------------------------- import java.util.; import javax.microedition.midlet.; import javax.microedition.lcdui.*; public class ScorerMIDlet extends MIDlet implements CommandListener { private Command mExitCommand, mBackCommand, mNextCommand; private Display d; private Form f; private TextField mTextField; private Alert a; private StringItem mHole1; private int b; // repeat holeForm for all five holes and add the input into a vector or array. Display the values in the end after asking for todays date and put todays date in top of the list. Make it possible to go back in the form, eg. hole 3 - hole 2 - hole 1 public void holeForm(int b) { f = new Form("Scorecard"); d = Display.getDisplay(this); mTextField = new TextField("Shots:", "", 2, TextField.NUMERIC); f.append(mTextField); mHole1 = new StringItem("Hole 1:", "Par 5, 480m"); f.append(mHole1); try { Image j = Image.createImage("/hole1.png"); ImageItem ii = new ImageItem("", j, 3, "Hole 1"); f.append(ii); } catch (java.io.IOException ioe) {} catch (Exception e) {} // Set date&time in the end long now = System.currentTimeMillis(); DateField df = new DateField("Playing date:", DateField.DATE_TIME); df.setDate(new Date(now)); f.append(df); f.addCommand(mBackCommand); f.addCommand(mNextCommand); f.addCommand(mExitCommand); f.setCommandListener(this); Display.getDisplay(this).setCurrent(f); } public void startApp() { mBackCommand = new Command("Back", Command.BACK, 0); mNextCommand = new Command("OK-Next", Command.OK, 1); mExitCommand = new Command("Exit", Command.EXIT, 2); b = 0; holeForm(b); } public void pauseApp() {} public void destroyApp(boolean unconditional) {} public void commandAction(Command c, Displayable d) { if (c == mExitCommand) { destroyApp(true); notifyDestroyed(); } else if ( c == mNextCommand) { holeForm(b); } } }

    Read the article

  • NHibernate child deletion problem.

    - by JMSA
    Suppose, I have saved some permissions in the database by using this code: RoleRepository roleRep = new RoleRepository(); Role role = new Role(); role.PermissionItems = Permission.GetList(); roleRep .SaveOrUpdate(role); Now, I need this code to delete the PermissionItem(s) associated with a Role when role.PermissionItems == null. Here is the code: RoleRepository roleRep = new RoleRepository(); Role role = roleRep.Get(roleId); role.PermissionItems = null; roleRep .SaveOrUpdate(role); But this is not happening. What should be the correct way to cope with this situation? What/how should I change, hbm-file or persistance code? Role.cs public class Role { public virtual string RoleName { get; set; } public virtual bool IsActive { get; set; } public virtual IList<Permission> PermissionItems { get; set; } } Role.hbm.xml <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="POCO" namespace="POCO"> <class name="Role" table="Role"> <id name="ID" column="ID"> <generator class="native" /> </id> <property name="RoleName" column="RoleName" /> <property name="IsActive" column="IsActive" type="System.Boolean" /> <bag name="PermissionItems" table="Permission" cascade="all" inverse="true"> <key column="RoleID"/> <one-to-many class="Permission" /> </bag> </class> </hibernate-mapping> Permission.cs public class Permission { public virtual string MenuItemKey { get; set; } public virtual int RoleID { get; set; } public virtual Role Role { get; set; } } Permission.hbm.xml <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="POCO" namespace="POCO"> <class name="Permission" table="Permission"> <id name="ID" column="ID"> <generator class="native"/> </id> <property name="MenuItemKey" column="MenuItemKey" /> <property name="RoleID" column="RoleID" /> <many-to-one name="Role" column="RoleID" not-null="true" cascade="all"> </many-to-one> </class> </hibernate-mapping>

    Read the article

  • Question about my sorting algorithm in C++

    - by davit-datuashvili
    i have following code in c++ #include <iostream> using namespace std; void qsort5(int a[],int n){ int i; int j; if (n<=1) return; for (i=1;i<n;i++) j=0; if (a[i]<a[0]) swap(++j,i,a); swap(0,j,a); qsort5(a,j); qsort(a+j+1,n-j-1); } int main() { return 0; } void swap(int i,int j,int a[]) { int t=a[i]; a[i]=a[j]; a[j]=t; } i have problem 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(std::basic_string<_Elem,_Traits,_Alloc> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\xstring(2203) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(std::pair<_Ty1,_Ty2> &,std::pair<_Ty1,_Ty2> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(76) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(_Ty &,_Ty &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(16) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(std::basic_string<_Elem,_Traits,_Alloc> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\xstring(2203) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(std::pair<_Ty1,_Ty2> &,std::pair<_Ty1,_Ty2> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(76) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(_Ty &,_Ty &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(16) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(16) : error C2661: 'qsort' : no overloaded function takes 2 arguments 1>Build log was saved at "file://c:\Users\dato\Documents\Visual Studio 2008\Projects\qsort5\qsort5\Debug\BuildLog.htm" please help

    Read the article

  • NHibernate: How is identity Id updated when saving a transient instance?

    - by bretddog
    If I use session-per-transaction and call: session.SaveOrUpdate(entity) corrected: session.SaveOrUpdateCopy(entity) ..and entity is a transient instance with identity-Id=0. Shall the above line automatically update the Id of the entity, and make the instance persistent? Or should it do so on transaction.Commit? Or do I have to somehow code that explicitly? Obviously the Id of the database row (new, since transient) is autogenerated and saved as some number, but I'm talking about the actual parameter instance here. Which is the business logic instance. EDIT Mappings: public class StoreMap : ClassMap<Store> { public StoreMap() { Id(x => x.Id).GeneratedBy.Identity(); Map(x => x.Name); HasMany(x => x.Staff) // 1:m .Cascade.All(); HasManyToMany(x => x.Products) // m:m .Cascade.All() .Table("StoreProduct"); } } public class EmployeeMap : ClassMap<Employee> { public EmployeeMap() { Id(x => x.Id).GeneratedBy.Identity(); Map(x => x.FirstName); Map(x => x.LastName); References(x => x.Store); // m:1 } } public class ProductMap : ClassMap<Product> { public ProductMap() { Id(x => x.Id).GeneratedBy.Identity(); Map(x => x.Name).Length(20); Map(x => x.Price).CustomSqlType("decimal").Precision(9).Scale(2); HasManyToMany(x => x.StoresStockedIn) .Cascade.All() .Inverse() .Table("StoreProduct"); } } EDIT2 Class definitions: public class Store { public int Id { get; private set; } public string Name { get; set; } public IList<Product> Products { get; set; } public IList<Employee> Staff { get; set; } public Store() { Products = new List<Product>(); Staff = new List<Employee>(); } // AddProduct & AddEmployee is required. "NH needs you to set both sides before // it will save correctly" public void AddProduct(Product product) { product.StoresStockedIn.Add(this); Products.Add(product); } public void AddEmployee(Employee employee) { employee.Store = this; Staff.Add(employee); } } public class Employee { public int Id { get; private set; } public string FirstName { get; set; } public string LastName { get; set; } public Store Store { get; set; } } public class Product { public int Id { get; private set; } public string Name { get; set; } public decimal Price { get; set; } public IList<Store> StoresStockedIn { get; private set; } }

    Read the article

  • Cannot extend a class located in another file, PHP

    - by NightMICU
    I am trying to set up a class with commonly used tasks, such as preparing strings for input into a database and creating a PDO object. I would like to include this file in other class files and extend those classes to use the common class' code. However, when I place the common class in its own file and include it in the class it will be used in, I receive an error that states the second class cannot be found. For example, if the class name is foo and it is extending bar (the common class, located elsewhere), the error says that foo cannot be found. But if I place the code for class bar in the same file as foo, it works. Here are the classes in question - Common Class abstract class coreFunctions { protected $contentDB; public function __construct() { $this->contentDB = new PDO('mysql:host=localhost;dbname=db', 'username', 'password'); } public function cleanStr($string) { $cleansed = trim($string); $cleansed = stripslashes($cleansed); $cleansed = strip_tags($cleansed); return $cleansed; } } Code from individual class include $_SERVER['DOCUMENT_ROOT'] . '/includes/class.core-functions.php'; $mode = $_POST['mode']; if (isset($mode)) { $gallery = new gallery; switch ($mode) { case 'addAlbum': $gallery->addAlbum($_POST['hash'], $_POST['title'], $_POST['description']); } } class gallery extends coreFunctions { private function directoryPath($string) { $path = trim($string); $path = strtolower($path); $path = preg_replace('/[^ \pL \pN]/', '', $path); $path = preg_replace('[\s+]', '', $path); $path = substr($path, 0, 18); return $path; } public function addAlbum($hash, $title, $description) { $title = $this->cleanStr($title); $description = $this->cleanStr($description); $path = $this->directoryPath($title); if ($title && $description && $hash) { $addAlbum = $this->contentDB->prepare("INSERT INTO gallery_albums (albumHash, albumTitle, albumDescription, albumPath) VALUES (:hash, :title, :description, :path)"); $addAlbum->execute(array('hash' => $hash, 'title' => $title, 'description' => $description, 'path' => $path)); } } } The error when I try it this way is Fatal error: Class 'gallery' not found in /home/opheliad/public_html/admin/photo-gallery/includes/class.admin_photo-gallery.php on line 10

    Read the article

  • assign a model's attribute through association

    - by justcode
    I'm new to rails and working on a rails app and I'm stuck pondering this issue. I have three models class product < ActiveRecord::Base attr_accessible :name, :issn, :category validates_presence_of :name, :issn, :category validates_numericality_of :issn, :message => "has to be a number" has_many :user_products has_many :users, :through => :user_products end class UserProduct < ActiveRecord::Base attr_accessible :price, :category validates_presence_of :price, :category validates_numericality_of :price, :message = "has to be a number" belongs_to :user belongs_to :product end class user < ActiveRecord::Base # devise authentication here # Setup accessible (or protected) attributes for your model attr_accessible :email, :password, :password_confirmation, :remember_me has_many :user_products has_many :products, :through = :user_products end here is my new.html.erb <div class="MainBodyWrapper"> <div class="span8"> <div id="listBoxWrapper"> <fieldset> <%= form_for(@product, :html => { :class => "form-inline" }, :style => "margin-bottom: 60px" ) do |f| %> <div class="control-group"> <label class="control-label" for="name">name</label> <div class="controls"> <%= f.text_field :price, :class => 'input-xlarge input-name', :id => "name" %> </div> </div> <div class="listingButtons"> <button class="btn btn-info"></i>Add</button> <a class="btn">Upload Pictures (anytime)</a> </div> </fieldset> </div> </div> There are reasons why I want to setup the models this way. So the question is this: I want the user to enter the info for the product in the form but it also involves putting in the price of the product which exists in a different model/table (user_product) that is associated with product. How can I do this? You can see that my form_for uses @product. Any help will be appreciated.

    Read the article

  • a friendly elaboratation on how iceweasel misses as recent request was discovered in post tut

    - by v3x3n
    I would like to specify what you asked about in how iceweasel misses on in hopes that you are interested in considering the answer to be valid considering the package should run efficient to a novice user especially when getting a first impression on a new software, browser, or package they are given by default. First let me say that I am very grateful for all debian has and continues to do for its user base and I am not complaining, only hoping that in mentioning such it will eventually aid in improving the disappointing experience iceweasel gave me in multiple ways right from the start of using it. I am sure tremendous amounts of hard work went into making it work as well as it does, and tremendous effort continues to go into IW like the rest of the package and distros such as this... Having said that, I do aim to keep my examples simple as possible but also explained in enough detail as to not leave out important info to get a full idea of my issue... (Thanks for understanding if I sound novice to debian, I am but continue to learn and advance by trial and error each day, and of course the wonderful help from all the great minds available here and there)... Well, my bone to pick (unfortunately as I disdain being a complainer when so much has been done for us, the end user) with IW is mainly 3 immediately noticed problems in offering me a smooth test drive (completely normal browsing conduct of your average user, I should indicate) as soon as I started out a task using IW (heading directly to google images and searched for a few web sized images, then saved a few (no more than 800 to 900 in dimensions, typically a normal procedure I would imagine) I experienced a horrendous reoccurring freeze and lag time that almost left me to kill the process more than once on each attempt and continued to compound so that by a few attempts later, even 1 single image save locked up the entire browser, ultimately giving up on my procedure in its simplicity with a bit of aggravation, if there was something I had done wrong on my end pre-attempt or during installation. Secondly, visiting video player sites in this case youtube will not allow for any video feed to play whatsoever and again, experienced a slight freezing that eventually dissipated as long as I didn't attempt to press play or reload another video trial... Very annoying and possibly related to my first issue (which could rely on my own lack of knowledge in setup config, but that troubles me if so).... Lastly as another user has stated already, in which brought you to ask them what exactly seemed to be the problem in the first place is also my final straw that broke the weasel's back, leading me here to find a solution to a updated version of firefox... being that iceweasel (an apparent build of firefox 17.x.x) leaving the user to find themselves out of luck when installing their favorite or much useful add-ons or plugins that aid their task or normal usage online.... As the other user clearly stated... there is almost zero options and barely any luck to find compatible plugins with such an outdated version still being used... I can only imagine if as a novoice or standard user to linux... and beginner to debian (which I am all for btw!) if I am discovering major conductivity issues which hinder normal user conduct right off the bat... that there is probably a bundle or more of security vulnerabilities that would unravel to me if I continued to give mr Hommey's package any further attention, or interest in continuing to use... This is a deal breaker on any account, unless all 3 of these issues stated are due to a very n00berish setting or lack thereof (which if that is the case, such was not properly stated for beginner in any place available by following installation tutorials such as LVM installers, which I felt lacked a clear understanding to someone who is trying to learn why and how, rather than, a fix to a potentially broken out of box installation... I really think that is irrelevant in any case however, as there is much step by step support regarding that kind of thing, just saying... its very challenging, along side a job to keep deadlines on, and the need to learn a better and more costomizible system, that was not as popularized when I became a dev via windows (OK OK I know thats a huge mistake and now I am way off original topic but anyway) Thanks very much for taking the time to read over this, and I hope it honestly gives you a few good and valid reasons for users wanting and seeking a way to get around iceweasel altogether... Finally, if I am missing something vital that renders all I've stated invalid or useless, please feel free to shove that elephant in the room my direction! Thanks for all you do, as I am sure it is very useful and dedicated, being you are a debian maintainer, and super user! Much love for intelligence, freedom and sharing the secrets of the web! May it remain unregulated and a good place to grow and learn for generations to come! Stay true! Take care now! -v3x (v3x @ gmx .com)

    Read the article

  • join 03 table in the database codeIgniter

    - by python
    with my table. person_id serial NOT NULL, firstname character varying(30) NOT NULL, lastname character varying(30), email character varying(50), username character varying(20) NOT NULL, "password" character varying(100) NOT NULL, gender character varying(10), dob date, accesslevel smallint NOT NULL, company_id integer NOT NULL,//Reference to table company position_id integer NOT NULL,//Reference to table position company_id serial NOT NULL, company_name character varying(80) NOT NULL, description character varying(255), address character varying(100) NOT NULL, In my controller ........................ // load data $persons = $this->person_model->get_paged_list(10,0); // generate table data $this->load->library('table'); $this->table->set_empty("&nbsp;"); $this->table->set_heading('No', 'FirstName', 'LastName','E-mail','Company''Gender', 'Date of Birth', 'Actions'); foreach ($persons as $person){ $this->table->add_row(++$i, $person->firstname, $person->lastname, $person->email, $person->company_name, //HOW CAN I GOT THE POSITION TITLE ?, strtoupper($person->gender)=='M'? 'Male':'Female', date('d-m-Y',strtotime($person->dob)), } My model <?php class Person_Model extends Model { private $person= 'person'; function Person(){ parent::Model(); } function list_all(){ $this->db->order_by('person_id','asc'); return $this->db->get($person); } function count_all(){ return $this->db->count_all($this->person); } function get_paged_list($limit = 0, $offset = 0) { $this->db->limit($limit, $offset); $this->db->select("person.*, company.company_name as company"); $this->db->from('person'); $this->db->join('company','person.company_id = company.company_id','left'); //MY QUESTION:? CAN I JOIN MORE WITH TABLE POSITION? $query = $this->db->get(); return $query->result(); } function get_by_id($id){ $this->db->where('person_id', $id); return $this->db->get($this->person); } function save($person){ $this->db->insert($this->person, $person); return $this->db->insert_id(); } function update($id, $person){ $this->db->where('person_id', $id); $this->db->update($this->person, $person); } function delete($id){ $this->db->where('person_id', $id); $this->db->delete($this->person); } } ?>

    Read the article

  • Templated function with two type parameters fails compile when used with an error-checking macro

    - by SirPentor
    Because someone in our group hates exceptions (let's not discuss that here), we tend to use error-checking macros in our C++ projects. I have encountered an odd compilation failure when using a templated function with two type parameters. There are a few errors (below), but I think the root cause is a warning: warning C4002: too many actual parameters for macro 'BOOL_CHECK_BOOL_RETURN' Probably best explained in code: #include "stdafx.h" template<class A, class B> bool DoubleTemplated(B & value) { return true; } template<class A> bool SingleTemplated(A & value) { return true; } bool NotTemplated(bool & value) { return true; } #define BOOL_CHECK_BOOL_RETURN(expr) \ do \ { \ bool __b = (expr); \ if (!__b) \ { \ return false; \ } \ } while (false) \ bool call() { bool thing = true; // BOOL_CHECK_BOOL_RETURN(DoubleTemplated<int, bool>(thing)); // Above line doesn't compile. BOOL_CHECK_BOOL_RETURN((DoubleTemplated<int, bool>(thing))); // Above line compiles just fine. bool temp = DoubleTemplated<int, bool>(thing); // Above line compiles just fine. BOOL_CHECK_BOOL_RETURN(SingleTemplated<bool>(thing)); BOOL_CHECK_BOOL_RETURN(NotTemplated(thing)); return true; } int _tmain(int argc, _TCHAR* argv[]) { call(); return 0; } Here are the errors, when the offending line is not commented out: 1>------ Build started: Project: test, Configuration: Debug Win32 ------ 1>Compiling... 1>test.cpp 1>c:\junk\temp\test\test\test.cpp(38) : warning C4002: too many actual parameters for macro 'BOOL_CHECK_BOOL_RETURN' 1>c:\junk\temp\test\test\test.cpp(38) : error C2143: syntax error : missing ',' before ')' 1>c:\junk\temp\test\test\test.cpp(38) : error C2143: syntax error : missing ';' before '{' 1>c:\junk\temp\test\test\test.cpp(41) : error C2143: syntax error : missing ';' before '{' 1>c:\junk\temp\test\test\test.cpp(48) : error C2143: syntax error : missing ';' before '{' 1>c:\junk\temp\test\test\test.cpp(49) : error C2143: syntax error : missing ';' before '{' 1>c:\junk\temp\test\test\test.cpp(52) : error C2143: syntax error : missing ';' before '}' 1>c:\junk\temp\test\test\test.cpp(54) : error C2065: 'argv' : undeclared identifier 1>c:\junk\temp\test\test\test.cpp(54) : error C2059: syntax error : ']' 1>c:\junk\temp\test\test\test.cpp(55) : error C2143: syntax error : missing ';' before '{' 1>c:\junk\temp\test\test\test.cpp(58) : error C2143: syntax error : missing ';' before '}' 1>c:\junk\temp\test\test\test.cpp(60) : error C2143: syntax error : missing ';' before '}' 1>c:\junk\temp\test\test\test.cpp(60) : fatal error C1004: unexpected end-of-file found 1>Build log was saved at "file://c:\junk\temp\test\test\Debug\BuildLog.htm" 1>test - 12 error(s), 1 warning(s) ========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ========== Any ideas? Thanks!

    Read the article

  • Why can i not upload images to my folder anymore?

    - by Hannah_B
    This was something I had working a few weeks back but after I made some changes to my view file images are now no longer being saved into my assets/uploads folder. I keep getting back the error - You did not select a file to upload. This is despite having made sure the path is definitely correct. What am i doing wrong here? Here is my controller: <?php class HomeProfile extends CI_Controller { function HomeProfile() { parent::__construct(); $this->load->model("profiles"); $this->load->model("profileimages"); $this->load->helper(array('form', 'url')); } function upload() { $config['path'] = './web-project-jb/assets/uploads/'; $config['allowed_types'] = 'gif|jpg|jpeg|png'; $config['max_size'] = '10000'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); $img = $this->session->userdata('img'); $username = $this->session->userdata('username'); $this->profileimages->putProfileImage($username, $this->input->post("profileimage")); //fail show upload form if (! $this->upload->do_upload()) { $error = array('error'=>$this->upload->display_errors()); $username = $this->session->userdata('username'); $viewData['username'] = $username; $viewData['profileText'] = $this->profiles->getProfileText($username); $this->load->view('shared/header'); $this->load->view('homeprofile/homeprofiletitle', $viewData); $this->load->view('shared/nav'); $this->load->view('homeprofile/upload_fail', $error); $this->load->view('homeprofile/homeprofileview', $viewData, array('error' => ' ' )); $this->load->view('shared/footer'); //redirect('homeprofile/index'); } else { //successful upload so save to database $file_data = $this->upload->data(); $data['img'] = base_url().'./web-project-jb/assets/uploads/'.$file_data['file_name']; // you may want to delete the image from the server after saving it to db // check to make sure $data['full_path'] is a valid path // get upload_sucess.php from link above //$image = chunk_split( base64_encode( file_get_contents( $data['file_name'] ) ) ); $this->username = $this->session->userdata('username'); $data['profileimages'] = $this->profileimages->getProfileImage($username); $viewData['username'] = $username; $viewData['profileText'] = $this->profiles->getProfileText($username); $username = $this->session->userdata('username'); } } function index() { $username = $this->session->userdata('username'); $data['profileimages'] = $this->profileimages->getProfileImage($username); $viewData['username'] = $username; $viewData['profileText'] = $this->profiles->getProfileText($username); $this->load->view('shared/header'); $this->load->view('homeprofile/homeprofiletitle', $viewData); $this->load->view('shared/nav'); //$this->load->view('homeprofile/upload_form', $data); $this->load->view('homeprofile/homeprofileview', $data, $viewData, array('error' => ' ' ) ); $this->load->view('shared/footer'); } } Here is my view: <div id="maincontent"> <div id="primary"> <?//=$error;?> <?//=$img;?> <h3><?="Profile Image"?></h3> <img src="<?php echo'$img'?>" width='300' height='300'/> <?=form_open_multipart('homeprofile/upload');?> <input type="file" name="img" value=""/> <?=form_submit('submit', 'upload')?> <?=form_close();?> <?php if (isset($error)) echo $error;?> </div> </div> Your help is much appreciated

    Read the article

  • Authlogic Help! Registering a new user when currently logged-in as a user not working.

    - by looloobs
    Hi Just as a disclaimer I am new to rails and programming in general so apologize for misunderstanding something obvious. I have Authlogic with activation up and running. So for my site I would like my users who are logged in to be able to register other users. The new user would pick their login and password through the activation email, but the existing user needs to put them in by email, position and a couple other attributes. I want that to be done by the existing user. The problem I am running into, if I am logged in and then try and create a new user it just tries to update the existing user and doesn't create a new one. I am not sure if there is some way to fix this by having another session start??? If that is even right/possible I wouldn't know how to go about implementing it. I realize without knowing fully about my application it may be difficult to answer this, but does this even sound like the right way to go about this? Am I missing something here? Users Controller: class UsersController < ApplicationController before_filter :require_no_user, :only => [:new, :create] before_filter :require_user, :only => [:show, :edit, :update] def new @user = User.new end def create @user = User.new if @user.signup!(params) @user.deliver_activation_instructions! flash[:notice] = "Your account has been created. Please check your e-mail for your account activation instructions!" redirect_to profile_url else render :action => :new end end def show @user = @current_user end def edit @user = @current_user end def update @user = @current_user # makes our views "cleaner" and more consistent if @user.update_attributes(params[:user]) flash[:notice] = "Account updated!" redirect_to profile_url else render :action => :edit end end end My User_Session Controller: class UserSessionsController < ApplicationController before_filter :require_no_user, :only => [:new, :create] before_filter :require_user, :only => :destroy def new @user_session = UserSession.new end def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" if @user_session.user.position == 'Battalion Commander' : redirect_to battalion_path(@user_session.user.battalion_id) else end else render :action => :new end end def destroy current_user_session.destroy flash[:notice] = "Logout successful!" redirect_back_or_default new_user_session_url end end

    Read the article

  • Creating a mySQL query using PHP form dropdowns - If user ignores dropdown, do not filter by that pa

    - by user303043
    Hello, I am creating a simple MySQL query that will be built from the user selecting options from 2 dropdowns. The issue I am having is that I would like each drop down to default that if they do not actually choose an option, do not filter by that dropdown parameter. So, if they come in, and simply hit submit without choosing from a dropdown they should see everything. If they come in and pick from only one of the dropdowns, the query will basically ignore filtering by the other dropdown. I tried making <OPTION VALUE='any'>Choose but my query didn't know what to do with the 'any' and just shows no results. Here is my code. Thank you very much for whatever help you can provide. FORM <form method="POST" action="<?php echo $_SERVER['REQUEST_URI']; ?>"> <select name="GameType"> <OPTION VALUE='any'>Choose Game Type <option value="Game1">Option 1</option> <option value="Game2">Option 2</option> <option value="Game3">Option 3</option> </select> <select name="Instructor"> <OPTION VALUE='any'>Choose Instructor <option VALUE="InstructorA">Instructor A</option> <option value="InstructorB">Instructor B</option> <option value="InstructorC">Instructor C</option> </select> <input type='submit' value='Search Videos'> </form> MYSQL <?PHP connection stuff $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM Videos WHERE GameType=\"{$_POST['GameType']}\" AND Instructor=\"{$_POST['Instructor']}\""; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { echo $db_field['ShortDescription'] . ", "; echo $db_field['LongDescription'] . ", "; echo $db_field['GameType'] . ", "; echo $db_field['NumberOfPlayers'] . ", "; echo $db_field['Instructor'] . ", "; echo $db_field['Stakes'] . ", "; echo $db_field['UserPermissionLevel'] . ", "; echo $db_field['DateCreated'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?>

    Read the article

  • An error occurred creating the form. See Exception.InnerException for details. The error is: Object

    - by Ben
    I get this error when attempting to debug my form, I cannot see where at all the error could be (also does not highlight where), anyone have any suggestions? An error occurred creating the form. See Exception.InnerException for details. The error is: Object reference not set to an instance of an object. Public Class Form1 Dim dateCrap As String = "Date:" Dim IPcrap As String = "Ip:" Dim pcCrap As String = "Computer:" Dim programCrap As String = "Program:" Dim textz As String = TextBox1.Text Dim sep() As String = {vbNewLine & vbNewLine} Dim sections() As String = Text.Split(sep, StringSplitOptions.None) Dim NewArray() As String = TextBox1.Text.Split(vbNewLine) Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click For i = 0 To sections.Count - 1 TextBox2.Text = sections(i) Dim text2 As String = TextBox2.Text Dim sep2() As String = {vbNewLine & vbNewLine} Dim sections2() As String = Text.Split(sep, StringSplitOptions.None) Dim FTPinfo() As String = TextBox2.Text.Split(vbNewLine) Dim clsRequest As System.Net.FtpWebRequest = _ DirectCast(System.Net.WebRequest.Create(sections2(0).Replace("Url/Host:", "")), System.Net.FtpWebRequest) clsRequest.Credentials = New System.Net.NetworkCredential(sections2(1).Replace("Login:", ""), (sections2(2).Replace("Password:", ""))) clsRequest.Method = System.Net.WebRequestMethods.Ftp.UploadFile ' read in file... Dim bFile() As Byte = System.IO.File.ReadAllBytes(txtShellDir.Text) ' upload file... Dim clsStream As System.IO.Stream = clsRequest.GetRequestStream() clsStream.Write(bFile, 0, bFile.Length) clsStream.Close() clsStream.Dispose() Next End Sub Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click ListBox1.Items.Clear() Dim fdlg As OpenFileDialog = New OpenFileDialog() fdlg.Title = "Browse for the FTP List you wish to use." fdlg.InitialDirectory = Application.ExecutablePath fdlg.Filter = "All files (*.txt)|*.txt|txt files (*.txt)|*.txt" fdlg.FilterIndex = 2 fdlg.RestoreDirectory = True If fdlg.ShowDialog() = DialogResult.OK Then 'ListBox1.Items.AddRange(Split(My.Computer.FileSystem.ReadAllText(fdlg.FileName), vbNewLine)) TextBox1.Text = My.Computer.FileSystem.ReadAllText(fdlg.FileName) End If Dim tmp() As String = TextBox1.Text.Split(CChar(vbNewLine)) For Each line As String In tmp If line.Length > 1 Then TextBox1.AppendText(line & vbNewLine) End If Next TextBox1.Text = TextBox1.Text.Replace(" ", "") TextBox1.Text = TextBox1.Text.Replace("----------------------------------------------------------", vbNewLine) For Each item As String In NewArray ListBox1.Items.Add(item) Next Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(dateCrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(IPcrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(pcCrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(programCrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try TextBox1.Text = "" For Each thing As Object In ListBox1.Items TextBox1.AppendText(thing.ToString & vbNewLine) Next End Sub Private Sub Button4_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) For i = 0 To ListBox1.SelectedItems.Count - 1 TextBox1.Text = TextBox1.Text & ListBox1.Items.Item(i).ToString() & vbNewLine Next End Sub End Class

    Read the article

  • Rails nested form for belongs_to

    - by user1232533
    I'm new to rails and have some troubles with creating a nested form. My models: class User < ActiveRecord::Base belongs_to :company accepts_nested_attributes_for :company, :reject_if => :all_blank end class Company < ActiveRecord::Base has_many :users end Now i would like to create a new company from the user sign_up page (i use Devise btw) by given only a company name. And have a relation between the new User and new Company. In the console i can create a company for a existing User like this: @company = User.first.build_company(:name => "name of company") @company.save That works, but i can't make this happen for a new user, in my new user sign_up form i tried this (i know its wrong by creating a new User fist but im trying to get something working here..): <%= simple_form_for(resource, :as => resource_name, :html => { :class => 'form-horizontal' }, :url => registration_path(resource_name)) do |f| %> <%= f.error_notification %> <div class="inputs"> <% @user = User.new company = @user.build_company() %> <% f.fields_for company do |builder| %> <%= builder.input :name, :required => true, :autofocus => true %> <% end %> <%= f.input :email, :required => true, :autofocus => true %> <%= f.input :password, :required => true %> <%= f.input :password_confirmation, :required => true %> </div> <div class="form-actions"> <%= f.button :submit, :class => 'btn-primary', :value => 'Sign up' %> </div> I did my best to google for a solution/ example.. found some nested form examples but it's just not clear to me how to do this. Really hope somebody can help me with this. Any help on this would be appreciated. Thanks in advance! Greets, Daniel

    Read the article

  • Invalid Cast Exception with Update Panel

    - by user1593175
    On Button Click Protected Sub btnSubmit_Click(sender As Object, e As System.EventArgs) Handles btnSubmit.Click MsgBox("INSIDE") If SocialAuthUser.IsLoggedIn Then Dim accountId As Integer = BLL.getAccIDFromSocialAuthSession Dim AlbumID As Integer = BLL.createAndReturnNewAlbumId(txtStoryTitle.Text.Trim, "") Dim URL As String = BLL.getAlbumPicUrl(txtStoryTitle.Text.Trim) Dim dt As New DataTable dt.Columns.Add("PictureID") dt.Columns.Add("AccountID") dt.Columns.Add("AlbumID") dt.Columns.Add("URL") dt.Columns.Add("Thumbnail") dt.Columns.Add("Description") dt.Columns.Add("AlbumCover") dt.Columns.Add("Tags") dt.Columns.Add("Votes") dt.Columns.Add("Abused") dt.Columns.Add("isActive") Dim Row As DataRow Dim uniqueFileName As String = "" If Session("ID") Is Nothing Then lblMessage.Text = "You don't seem to have uploaded any pictures." Exit Sub Else **Dim FileCount As Integer = Request.Form(Request.Form.Count - 2)** Dim FileName, TargetName As String Try Dim Path As String = Server.MapPath(BLL.getAlbumPicUrl(txtStoryTitle.Text.Trim)) If Not IO.Directory.Exists(Path) Then IO.Directory.CreateDirectory(Path) End If Dim StartIndex As Integer Dim PicCount As Integer For i As Integer = 0 To Request.Form.Count - 1 If Request.Form(i).ToLower.Contains("jpg") Or Request.Form(i).ToLower.Contains("gif") Or Request.Form(i).ToLower.Contains("png") Then StartIndex = i + 1 Exit For End If Next For i As Integer = StartIndex To Request.Form.Count - 4 Step 3 FileName = Request.Form(i) '## If part here is not kaam ka..but still using it for worst case scenario If IO.File.Exists(Path & FileName) Then TargetName = Path & FileName 'MsgBox(TargetName & "--- 1") Dim j As Integer = 1 While IO.File.Exists(TargetName) TargetName = Path & IO.Path.GetFileNameWithoutExtension(FileName) & "(" & j & ")" & IO.Path.GetExtension(FileName) j += 1 End While Else uniqueFileName = Guid.NewGuid.ToString & "__" & FileName TargetName = Path & uniqueFileName End If IO.File.Move(Server.MapPath("~/TempUploads/" & Session("ID") & "/" & FileName), TargetName) PicCount += 1 Row = dt.NewRow() Row(1) = accountId Row(2) = AlbumID Row(3) = URL & uniqueFileName Row(4) = "" Row(5) = "No Desc" Row(6) = "False" Row(7) = "" Row(8) = "0" Row(9) = "0" Row(10) = "True" dt.Rows.Add(Row) Next If BLL.insertImagesIntoAlbum(dt) Then lblMessage.Text = PicCount & IIf(PicCount = 1, " Picture", " Pictures") & " Saved!" lblMessage.ForeColor = Drawing.Color.Black Dim db As SqlDatabase = Connection.connection Using cmd As DbCommand = db.GetSqlStringCommand("SELECT PictureID,URL FROM AlbumPictures WHERE AlbumID=@AlbumID AND AccountID=@AccountID") db.AddInParameter(cmd, "AlbumID", Data.DbType.Int32, AlbumID) db.AddInParameter(cmd, "AccountID", Data.DbType.Int32, accountId) Using ds As DataSet = db.ExecuteDataSet(cmd) If ds.Tables(0).Rows.Count > 0 Then ListView1.DataSource = ds.Tables(0) ListView1.DataBind() Else lblMessage.Text = "No Such Album Exists." End If End Using End Using 'WebNavigator.GoToResponseRedirect(WebNavigator.URLFor.ReturnUrl("~/Memories/SortImages.aspx?id=" & AlbumID)) Else 'TODO:we'll show some error msg End If Catch ex As Exception MsgBox(ex.Message) lblMessage.Text = "Oo Poop!!" End Try End If Else WebNavigator.GoToResponseRedirect(WebNavigator.URLFor.LoginWithReturnUrl("~/Memories/CreateAlbum.aspx")) Exit Sub End If End Sub The above code works fine.I have added an Update Panel in the page to avoid post back, But when i add the button click as a trigger <Triggers> <asp:AsyncPostBackTrigger ControlID="btnSubmit" /> </Triggers> in the update panel to avoid post back, i get the following error.This happens when i add the button click as a Trigger to the update panel.

    Read the article

  • Criticise/Recommendations for my code

    - by aLk
    Before i go any further it would be nice to know if there is any major design flaws in my program so far. Is there anything worth changing before i continue? Model package model; import java.sql.*; import java.util.*; public class MovieDatabase { @SuppressWarnings({ "rawtypes", "unchecked" }) public List queryMovies() throws SQLException { Connection connection = null; java.sql.Statement statement = null; ResultSet rs = null; List results = new ArrayList(); try { DriverManager.registerDriver(new com.mysql.jdbc.Driver()); connection = DriverManager.getConnection("jdbc:mysql://localhost:3306/test", "root", "password"); statement = connection.createStatement(); String query = "SELECT * FROM movie"; rs = statement.executeQuery(query); while(rs.next()) { MovieBean bean = new MovieBean(); bean.setMovieId(rs.getInt(1)); bean.setTitle(rs.getString(2)); bean.setYear(rs.getInt(3)); bean.setRating(rs.getInt(4)); results.add(bean); } } catch(SQLException e) { } return results; } } Servlet public class Service extends HttpServlet { @SuppressWarnings("rawtypes") protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); out.println("Movies!"); MovieDatabase movies = new MovieDatabase(); try { List results = movies.queryMovies(); Iterator it = results.iterator(); while(it.hasNext()) { MovieBean movie = new MovieBean(); movie = (MovieBean)it.next(); out.println(movie.getYear()); } } catch(SQLException e) { } } } Bean package model; @SuppressWarnings("serial") public class MovieBean implements java.io.Serializable { protected int movieid; protected int rating; protected int year; protected String title; public MovieBean() { } public void setMovieId(int movieidVal) { movieid = movieidVal; } public void setRating(int ratingVal) { rating = ratingVal; } public void setYear(int yearVal) { year = yearVal; } public void setTitle(String titleVal) { title = titleVal; } public int getMovieId() { return movieid; } public int getRating() { return rating; } public int getYear() { return year; } public String getTitle() { return title; } }

    Read the article

  • PHP problems when transfering code from Windows to OS X

    - by Makka95
    I have recently bought a new MacBook Pro. Before I had my MacBook Pro I was working on a website on my desktop computer. And now I want to transfer this code to my new MacBook Pro. The problem is that when I transfered the code (I put it on Dropbox and simply downloaded it on my MacBook Pro) I started to see lots of error messages in my PHP code. The error message I”m receiving is: Warning: Cannot modify header information - headers already sent by (output started at /some/file.php:1) in /some/file.php on line 23 I have done some research on this and it seems that this error is most frequently caused by a new line, simple whitespace or any output before the <?php sign. I have looked through all the places where I have cookies that are being sent in the HTTP request and also where I'm using the header() function. I haven’t detected any output or whitespace that possibly could interfere and cause this problem. Noteworthy is that the error always says that the output is started at line 1. Which got me thinking if there is some kind of coding differences in the way that the Mac OS X and Windows operating systems handle new lines or white spaces? Or could the Dropbox transfer messed something up? The code on one of the sites(login.php) which produces the error: <?php include "mysql_database.php"; login(); $id = $_SESSION['Loggedin']; setcookie("login", $id, (time()+60*60*24*30)); header('Location: ' . $_SERVER['HTTP_REFERER']); ?> login function: function login() { $connection = connecttodatabase(); $pass = ""; $user = ""; $query = ""; if (isset($_POST['user']) && $_POST['user'] != null) { $user = $_POST['user']; if (isset($_POST['pass']) && $_POST['pass'] != null) { $pass = md5($_POST['pass']); $query = "SELECT ID FROM Anvandare WHERE Nickname='$user' AND Password ='$pass'"; } } if ($query != "") { $id = $connection->query($query); $id = mysqli_fetch_assoc($id); $id = $id['ID']; $_SESSION['Loggedin'] = $id; } closeconnection($connection); } Complete error: Warning: Cannot modify header information - headers already sent by (output started at /Users/name/GitHub/website/login.php:1) in /Users/namn/GitHub/website/login.php on line 9

    Read the article

  • pdo connection scope

    - by Scarface
    Hey guys I have a connection class I found for pdo. I am calling the connection method on the page that the file is included on. The problem is that within functions the $conn variable is not defined even though I stated the method was public (bare with me I am very new to OOP), and I was wondering if anyone had an elegant solution other then using global in every function. Any suggestions are greatly appreciated. CONNECTION class PDOConnectionFactory{ // receives the connection public $con = null; // swich database? public $dbType = "mysql"; // connection parameters // when it will not be necessary leaves blank only with the double quotations marks "" public $host = "localhost"; public $user = "user"; public $senha = "password"; public $db = "database"; // arrow the persistence of the connection public $persistent = false; // new PDOConnectionFactory( true ) <--- persistent connection // new PDOConnectionFactory() <--- no persistent connection public function PDOConnectionFactory( $persistent=false ){ // it verifies the persistence of the connection if( $persistent != false){ $this->persistent = true; } } public function getConnection(){ try{ // it carries through the connection $this->con = new PDO($this->dbType.":host=".$this->host.";dbname=".$this->db, $this->user, $this->senha, array( PDO::ATTR_PERSISTENT => $this->persistent ) ); // carried through successfully, it returns connected return $this->con; // in case that an error occurs, it returns the error; }catch ( PDOException $ex ){ echo "We are currently experiencing technical difficulties. We have a bunch of monkies working really hard to fix the problem. Check back soon: ".$ex->getMessage(); } } // close connection public function Close(){ if( $this->con != null ) $this->con = null; } } PAGE USED ON include("includes/connection.php"); $db = new PDOConnectionFactory(); $conn = $db->getConnection(); function test(){ try{ $sql = 'SELECT * FROM topic'; $stmt = $conn->prepare($sql); $result=$stmt->execute(); } catch(PDOException $e){ echo $e->getMessage(); } } test();

    Read the article

  • Please Describe Your Struggles with Minimizing Use of Global Variables

    - by MetaHyperBolic
    Most of the programs I write are relatively flowchartable processes, with a defined start and hoped-for end. The problems themselves can be complex but do not readily lean towards central use of objects and event-driven programming. Often, I am simply churning through great varied batches of text data to produce different text data. Only occasionally do I need to create a class: As an example, to track warnings, errors, and debugging message, I created a class (Problems) with one instantiation (myErr), which I believe to be an example of the Singleton design pattern. As a further factor, my colleagues are more old school (procedural) than I and are unacquainted with object-oriented programming, so I am loath to create things they could not puzzle through. And yet I hear, again and again, how even the Singleton design pattern is really an anti-pattern and ought to be avoided because Global Variables Are Bad. Minor functions need few arguments passed to them and have no need to know of configuration (unchanging) or program state (changing) -- I agree. However, the functions in the middle of the chain, which primarily control program flow, have a need for a large number of configuration variables and some program state variables. I believe passing a dozen or more arguments along to a function is a "solution," but hardly an attractive one. I could, of course, cram variables into a single hash/dict/associative array, but that seems like cheating. For instance, connecting to the Active Directory to make a new account, I need such configuration variables as an administrative username, password, a target OU, some default groups, a domain, etc. I would have to pass those arguments down through a variety of functions which would not even use them, merely shuffle them off down through a chain which would eventually lead to the function that actually needs them. I would at least declare the configuration variables to be constant, to protect them, but my language of choice these days (Python) provides no simple manner to do this, though recipes do exist as workarounds. Numerous Stack Overflow questions have hit on the why? of the badness and the requisite shunning, but do not often mention tips on living with this quasi-religious restriction. How have you resolved, or at least made peace with, the issue of global variables and program state? Where have you made compromises? What have your tricks been, aside from shoving around flocks of arguments to functions?

    Read the article

< Previous Page | 538 539 540 541 542 543 544 545 546 547 548 549  | Next Page >