Search Results

Search found 40429 results on 1618 pages for 'change password'.

Page 545/1618 | < Previous Page | 541 542 543 544 545 546 547 548 549 550 551 552  | Next Page >

  • can't use appcfg.py update gae

    - by user353998
    hello, recently i want to upload GAppProxy to GAE. but when i use the appcfg.py to update the files,there comes an error,it was: urllib2.URLError: urlopen error [Errno 8] _ssl.c:480: EOF occurred in violation of protocol i don't know why PS:i live in china,and may be because of the GFW. and when i use the type :appengine.google.com and then input the password,i can't redict to the index page,there is an error too,which says:ssl error

    Read the article

  • Android xml pages

    - by ranjanarr
    where to add the new GUI xml pages in android project, say I have a welcome screen in reslayoutmain.xml layout and when user clicks "next" button, it has to load up a new page with username and password GUI. any help will be appreciated

    Read the article

  • JQuery selector in variable

    - by nagut
    I wanted to ask about using selector from a variable first I have: function check() { $('.info input, .info select').each(function(n, element){ if ($(element).val()=='') alert('empty'); }); } and called it in $('input')change(check); and they worked fine. But now I want to pass some value to the function to make it dynamic, like $('input')change(check('.info')); and changed the function to function check(sel) { $(sel +' input, '+ sel + ' select').each(function(n, element){ if ($(element).val()=='') alert('empty'); }); } but it doesn't work. Any help please.. Thanks, nagut

    Read the article

  • How to override inner class methods if the inner class is defined as a property of the top class

    - by Maddy
    I have a code snippet like this class A(object): class b: def print_hello(self): print "Hello world" b = property(b) And I want to override the inner class b (please dont worry about the lowercase name) behaviour. Say, I want to add a new method or I want to change an existing method, like: class C(A): class b(A.b): def print_hello(self): print "Inner Class: Hello world" b = property(b) Now if I create C's object as c = C(), and call c.b I get TypeError: 'property' object is not callable error. How would I get pass this and call print_hello of the extended inner class? Disclaimer: I dont want to change the code for A class.

    Read the article

  • DOM: how to import nodes and give them different namespace prefix

    - by thomasrutter
    I'm familiar with the DOMDocument::importNode method for importing a tree of nodes from some other document element. However, what I was wondering is if I can automatically change the namespace prefix on a tree of nodes as I import them, that is, specify a new prefix for all nodes of that namespace. Say the nodes, in their existing document, all have names like "name", "identity", and so on. When importing them into my new document they will be alongside other namespaces, so I'd like them to appear as "nicnames:name", "nicnames:identity" and so on. I'd like to be able to change this prefix programmatically so that in another context I may be able to import them as, for instance, "myprefix:name", "myprefix:identity" depending on the document they're imported into. Can anyone help me understand how to do this? Thanks

    Read the article

  • Self Authenticating Links in Django

    - by awolf
    In my web app I would like to be able to email self-authenticating links to users. These links will contain a unique token (uuid). When they click the link the token being present in the query string will be enough to authenticate them and they won't have to enter their username and password. What's the best way to do this?

    Read the article

  • Setting Back Button Tittle in Navigation Controller problem

    - by Rafael
    Hi, I'm trying to change Back Button tittle in a navigation controller in the following way: In the parent controller I put this in vieDidLoad: self.title = @"Calendars"; self.navigationItem.backBarButtonItem.title = @"Previous"; But this controller is in the stack since I initialized the app: -(void)applicationDidFinishLaunching:(UIApplication *)application{ navController.viewControllers= [NSArray arrayWithObjects:aController,aBcontroller,nil]; [window addSubview:navController.view]; } So, the viewDidLoad in aController is not called until I select the back buttom the first time in the bController... Does anyone knows how to call viewDidLoad just when I push it into the stack? Or do you know another way to change the BackButtom title? Thanks in advanced for your help.

    Read the article

  • Why does adding a reference to project targeting .NET Framework 4.0 fail?

    - by Malcolm Post
    We have two projects that are both class libraries. Project 1 is a VS 2008 project and targets the .NET Framework 3.5. Project 2 is a VS 2010 (release candidate) project that targets the .NET Framework 4.0. When I try to add a reference to Project 2 in Project 1, it fails with a less than informative error message. I know that if I change the target Framework for Project 2 to 3.5, then adding the reference will work. My question is, if I don't change the target frameworks, but convert Project 1 to VS 2010, will the referencing work? Stated another way, is there some inherent incompatiblity between class libraries targeting different framework versions, or is it failing for me because VS 2008 doesn't know about the 4.0 framework?

    Read the article

  • failed to load source for

    - by ohana
    hi, I have a php project which used to work well, yesterday it suddenly failed, from the login page i cannot actually get into the system with the right username/password. i checked it in Firebug, it said: failed to load source for the php file that's supposed to load after login.what could be wrong? anyone have any idea? Thanks.

    Read the article

  • When should I write my own Look and Feel for Java Swing instead of customizing one?

    - by Jonas
    I have used a few different Look and Feels for Java Swing, but I don't really like anyone to 100% so I often end up with customizing it a lot. Sometimes I am thinking about if it is a better idea to write my own LaF (by extending an existing one), but I don't really know. For the moment, I mostly use Nimbus, but I change all colors (to darker ones) and rewrite the appearance of some components, like sliders and scrollbars. I also mostly customize all tables and I am thinking about to change the look of a few other components. When is it recommended to create a new Look-and-Feel instead of customizing one? What are the pros and cons? I.e. customize Nimbus or create a new one by extending Nimbus? Related article: Creating a Custom Look and Feel (old)

    Read the article

  • zend_application showing blank page

    - by daniel
    Hi, I'm using Zend_Application to bootstrap my app. class Bootstrap extends Zend_Application_Bootstrap_Bootstrap { public static $frontController = null; public static $registry = null; protected function _initEnvironment() { ini_set('display_errors', true); //date_default_timezone_set('Europe/London'); } protected function _initRegistry() { self::$registry = new Zend_Registry(array(), ArrayObject::ARRAY_AS_PROPS); Zend_Registry::setInstance(self::$registry); } protected function _initConfiguration() { $config = new Zend_Config_Ini( BASE_PATH . '/data/server/settings.ini', APPLICATION_ENV ); self::$registry->configuration = $config; } protected function _initLogging() { $config = self::$registry->configuration; $logger = new Zend_Log(new Zend_Log_Writer_Stream($config->logging->file)); Zend_Registry::set('logger', $logger); } protected function _initFrontController() { self::$frontController = Zend_Controller_Front::getInstance(); self::$frontController->throwExceptions(true); self::$frontController->returnResponse(true); self::$frontController->setControllerDirectory( APPLICATION_PATH .'/controllers' ); self::$frontController->setParam('registry', self::$registry); return self::$frontController; } protected function _initView() { $config = self::$registry->configuration; $view = new Zend_View; $viewRenderer = new Zend_Controller_Action_Helper_ViewRenderer($view); Zend_Controller_Action_HelperBroker::addHelper($viewRenderer); Zend_Layout::startMvc( array( 'layoutPath' => APPLICATION_PATH . "/layouts/scripts", 'layout' => "layout" ) ); return $view; } protected function _initDatabase() { $config = self::$registry->configuration; $params = array('host' => $config->database->hostname, 'username' => $config->database->username, 'password' => $config->database->password, 'dbname' => $config->database->database); $db = Zend_Db::factory($config->database->type, $params); Zend_Registry::set('db', $db); } protected function _initPlaceholders() { $view = $this->getResource('View'); $view->doctype('XHTML1_STRICT'); $view->headTitle('Greplin') ->setSeparator(' / '); $view->headLink()->prependStylesheet('/src/css/header.css'); $view->headScript()->prependFile('/js/site.js'); return $view; } } When I run the app I get a blank page. Filenames / paths are intact. If I add die() to the bottom of my layout.phtml, I get the page. Something is resetting the headers and sending a blank page. My error reporting is on and I get unrelated errors. What could this be?! Thanks!

    Read the article

  • replace values in form.data when form fails validation

    - by John
    Hi I have a form field which requires a json object as its value when it is rendered. When the form is submitted it returns a comma seperated string of ids as its value (not a json string). however if the form does not validate i want to turn this string of ids back into a json string so it will display properly (is uses jquery to render the json object correctly). how would i do this? I was thinking of overwriting the form.clean method but when I tried to change self.data['fieldname'] I got the error 'This QueryDict instance is immutable' and when i tried to change self.cleaned_data['fieldname'] it didn't make a difference to the value of the field. Thanks

    Read the article

  • Set environment variable in Ubuntu

    - by Junho Park
    In Ubuntu, I'd like to switch my JAVA_HOME environment variable back and forth between Java 5 and 6. I open a terminal and type in the following to set the JAVA_HOME environment variable: export JAVA_HOME=/usr/lib/jvm/java-1.5.0-sun And in that same terminal window, I type the following to check that the environment variable has been updated: echo $JAVA_HOME And I see /usr/lib/jvm/java-1.5.0-sun which is what I'm expecting to see. In addition, I modify ~/.profile and set the JAVA_HOME environment variable to /usr/lib/jvm/java-1.5.0-sun. And now for the problem--when I open a new terminal window and I check my JAVA_HOME environment variable by typing in echo $JAVA_HOME I see that my JAVA_HOME environment variable has been reverted back to Java 6. When I reboot my machine (or log out and back in, I suppose) the JAVA_HOME environment variable is set to Java 5 (presumably because of the modification I made in my ~/.profile). Is there a way around this so that I can change my JAVA_HOME environment without having to log out and back in (AND make that environment variable change stick in all new terminal windows)?

    Read the article

  • PowerShell and interactive external programs

    - by CC
    Hi all I'm attempting to write a PowerShell script that, among other things, runs two external programs, harvesting the output of one and providing it to the other. The problem is that the second program is interactive and asks for: - a password - an option (1, 2, or 3) - an option (Y or N) - output of external program 1 Note also that this is on XP with PowerShell v1 and .net v2.0 (no I can't upgrade) Any ideas how I would do this? CC

    Read the article

  • What is the recommended way to handle different user roles in a C# application?

    - by Sergio Tapia
    I'm going to make a small application for a business that will be used locally for scanning, and storing documents in a database located on the local machine or on a machine located in the same LAN. I could create a table called Users with username and password and according to the usertype ID show a form, or another form. But I'm more interested in the recommended approach by seasoned programmers. Any advice?

    Read the article

  • In Selenium, how do I turn off logging?

    - by someguy
    I am using the following method: set_browser_log_level 'off' but my log level continues to include INFOs. I am trying to suppress both logging and the "Last 4 commands" display for when my test enters a login password. http://release.seleniumhq.org/selenium-remote-control/0.9.2/doc/ruby/classes/Selenium/SeleniumDriver.html#M000128

    Read the article

  • different explanation

    - by Delirium tremens
    The following code echoes 5, not 10: $global_obj = null; class my_class { var $value; function my_class() { global $global_obj; $global_obj = &$this; } } $a = new my_class; $a->my_value = 5; $global_obj->my_value = 10; echo $a->my_value; "Upon first examination, it would seem that the constructor of my_class stores a reference to itself inside the $global_obj variable. Therefore, one would expect that, when we later change the value of $global_obj-my_value to 10, the corresponding value in $a would change as well. Unfortunately, the new operator does not return a reference, but a copy of the newly created object." Please, give me a different explanation.

    Read the article

  • How to build the ViewModel in MVVM not to violate the Single Responsibility Principle?

    - by Przemek
    Robert Martin says: "There should never be more than one reason for a class to change". Let's consider the ViewModel class which is bound to a View. It is possible (or even probable) that the ViewModel consists of properties that are not really related to each other. For small views the ViewModel may be quite coherent, but while the application gets more complex the ViewModel will expose data that will be subject to change for different and unrelated reasons. Should we worry about the SRP principle in the case of ViewModel class or not?

    Read the article

  • Modify audio pitch of recorded clip (m4v)

    - by devcube
    I'm writing an app in which I'm trying to change the pitch of the audio when I'm recording a movie (.m4v). Or by modifying the audio pitch of the movie afterwards. I want the end result to be a movie (.m4v) that has the original length (i.e. same visual as original) but with modified sound pitch, e.g. a "chipmunk voice". A realtime conversion is to prefer if possible. I've read alot about changing audio pitch in iOS but most examples focus on playback, i.e. playing the sound with a different pitch. In my app I'm recording a movie (.m4v / AVFileTypeQuickTimeMovie) and saving it using standard AVAssetWriter. When saving the movie I have access to the following elements where I've tried to manipulate the audio (e.g. modify the pitch): audio buffer (CMSampleBufferRef) audio input writer (AVAssetWriterAudioInput) audio input writer options (e.g. AVNumberOfChannelsKey, AVSampleRateKey, AVChannelLayoutKey) asset writer (AVAssetWriter) I've tried to hook into the above objects to modify the audio pitch, but without success. I've also tried with Dirac as described here: Real Time Pitch Change In iPhone Using Dirac And OpenAL with AL_PITCH as described here: Piping output from OpenAL into a buffer And the "BASS" library from un4seen: Change Pitch/Tempo In Realtime I haven't found success with any of the above libs, most likely because I don't really know how to use them, and where to hook them into the audio saving code. There seems to be alot of librarys that have similar effects but focuses on playback or custom recording code. I want to manipulate the audio stream I've already got (AVAssetWriterAudioInput) or modify the saved movie clip (.m4v). I want the video to be unmodifed visually, i.e. played at the same speed. But I want the audio to go faster (like a chipmunk) or slower (like a ... monster? :)). Do you have any suggestions how I can modify the pitch in either real time (when recording the movie) or afterwards by converting the entire movie (.m4v file)? Should I look further into Dirac, OpenAL, SoundTouch, BASS or some other library? I want to be able to share the movie to others with modified audio, that's the reason I can't rely on modifying the pitch for playback only. Any help is appreciated, thanks!

    Read the article

  • Why isn't my Ruby object deleted when the last reference goes out of scope?

    - by Andrew Clegg
    Hi gurus, I've found a weird effect when trying to track down a memory leak in a Rails app. Can anyone explain what's going on here? Save this script as a plain Ruby script (Rails not necessary): class Fnord def to_s 'fnord' end end def test f = Fnord.new end test GC.start sleep 2 ObjectSpace.each_object do |o| puts o if o.is_a? Fnord end When I run this via ruby 1.8.7 (2009-06-12 patchlevel 174) [i486-linux] I get the following: bash $ ruby var_test fnord Although the variable f is out of scope, there are no other references to the single Fnord object, and I've garbage collected, the object still seems to exist. Is this a nefarious memory leak of some sort, or am I completely missing something about Ruby? Further, if I change the test method to this: def test f = Fnord.new f = nil end I get no output. But surely this should not change the semantics here? Many thanks!

    Read the article

< Previous Page | 541 542 543 544 545 546 547 548 549 550 551 552  | Next Page >