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  • Java equivalent for database schema changes like South for Django?

    - by gerdemb
    I've been working on a Django project using South to track and manage database schema changes. I'm starting a new Java project using Google Web Toolkit and wonder if there is an equivalent tool. For those who don't know, here's what South does: Automatically recognize changes to my Python database models (add/delete columns, tables etc.) Automatically create SQL statements to apply those changes to my database Track the applied schema migrations and apply them in order Allow data migrations using Python code. For example, splitting a name field into a first-name and last-name field using the Python split() function I haven't decided on my Java ORM yet, but Hibernate looks like the most popular. For me, the ability to easily make database schema changes will be an important factor.

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  • Showing custom model validation exceptions in the Django admin site.

    - by Guy Bowden
    I have a booking model that needs to check if the item being booked out is available. I would like to have the logic behind figuring out if the item is available centralised so that no matter where I save the instance this code validates that it can be saved. At the moment I have this code in a custom save function of my model class: def save(self): if self.is_available(): # my custom check availability function super(MyObj, self).save() else: # this is the bit I'm stuck with.. raise forms.ValidationError('Item already booked for those dates') This works fine - the error is raised if the item is unavailable, and my item is not saved. I can capture the exception from my front end form code, but what about the Django admin site? How can I get my exception to be displayed like any other validation error in the admin site?

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  • How To Collapse Just One Field in Django Admin?

    - by Apreche
    The django admin allows you to specify fieldsets. You properly structure a tuple that groups different fields together. You can also specify classes for certain groups of fields. One of those classes is collapse, which will hide the field under a collapsable area. This is good for hiding rarely used or advanced fields to keep the UI clean. However, I have a situation where I want to hide just one lonesome field on many different apps. This will be a lot of typing to create a full fieldset specification in every admin.py file just to put one field into the collapsed area. It also creates a difficult maintenance situation because I will have to edit the fieldset every time I edit the associated model. I can easily exclude the field entirely using the exclude option. I want something similar for collapse. Is this possible?

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  • django-haystack urlpatterns include('haystack.urls') where does it lead to?

    - by Eugene
    I've recently begun to learn/install django/haystack/solr. Following the tutorial given in haystack site, I have urlpatterns = pattern('', r'^search/', include('haystack.urls')) I found haystack installed in /usr/local/lib/python2.6/dist-packages/haystack and located urls.py there. It has urlpatterns=patterns('haystack.views', url(r'^$', SearchView(), name='haystack_search'),) I thought the second argument of url() should be callable object. I looked at the views.py and SearchView is a class. What is going on here? What's get called eventually?

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  • Django & custom auth backend (web service) + no database. How to save stuff in session?

    - by Infinity
    I've been searching here and there, and based on this answer I've put together what you see below. It works, but I need to put some stuff in the user's session, right there inside authenticate. How would I store acme_token in the user's session, so that it will get cleared if they logged out? class AcmeUserBackend(object): # Create a User object if not already in the database? create_unknown_user = False def get_user(self, username): return AcmeUser(id=username) def authenticate(self, username=None, password=None): """ Check the username/password and return an AcmeUser. """ acme_token = ask_another_site_about_creds(username, password) if acme_token: return AcmeUser(id=username) return None ################## from django.contrib.auth.models import User class AcmeUser(User): objects = None # we cannot really use this w/o local DB def save(self): """saving to DB disabled""" pass def get_group_permissions(self): """If you don't make your own permissions module, the default also will use the DB. Throw it away""" return [] # likewise with the other permission defs def get_and_delete_messages(self): """Messages are stored in the DB. Darn!""" return []

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  • What is the proper way to check the previous value of a field before saving an object? (Using Django

    - by anonymous coward
    I have a Django Model with updated_by and an approved_by fields, both are ForeignKey fields to the built-in (auth) User models. I am aware that with updated_by, it's easy enough to simply over-ride the .save() method on the Model, and shove the request.user in that field before saving. However, for approved_by, this field should only ever be filled in when a related field (date_approved) is first filled in. I'm somewhat certain that I can check this logically, and fill in the field if the previous value was empty. What is the proper way to check the previous value of a field before saving an object? I do not anticipate that date_approved will ever be changed or updated, nor should there be any reason to ever update the approved_by entry. UPDATE: Regarding forms/validation, I should have mentioned that none of the fields in question are seen by or editable by users of the site. If I have misunderstood, I'm sorry, but I'm not sure how forms and validation apply to my question.

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  • gunicorn + django + nginx unix://socket failed (11: Resource temporarily unavailable)

    - by user1068118
    Running very high volume traffic on these servers configured with django, gunicorn, supervisor and nginx. But a lot of times I tend to see 502 errors. So I checked the nginx logs to see what error and this is what is recorded: [error] 2388#0: *208027 connect() to unix:/tmp/gunicorn-ourapp.socket failed (11: Resource temporarily unavailable) while connecting to upstream Can anyone help debug what might be causing this to happen? This is our nginx configuration: sendfile on; tcp_nopush on; tcp_nodelay off; listen 80 default_server; server_name imp.ourapp.com; access_log /mnt/ebs/nginx-log/ourapp-access.log; error_log /mnt/ebs/nginx-log/ourapp-error.log; charset utf-8; keepalive_timeout 60; client_max_body_size 8m; gzip_types text/plain text/xml text/css application/javascript application/x-javascript application/json; location / { proxy_pass http://unix:/tmp/gunicorn-ourapp.socket; proxy_pass_request_headers on; proxy_read_timeout 600s; proxy_connect_timeout 600s; proxy_redirect http://localhost/ http://imp.ourapp.com/; #proxy_set_header Host $host; #proxy_set_header X-Real-IP $remote_addr; #proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; #proxy_set_header X-Forwarded-Proto $my_scheme; #proxy_set_header X-Forwarded-Ssl $my_ssl; } We have configure Django to run in Gunicorn as a generic WSGI application. Supervisord is used to launch the gunicorn workers: home/user/virtenv/bin/python2.7 /home/user/virtenv/bin/gunicorn --config /home/user/shared/etc/gunicorn.conf.py daggr.wsgi:application This is what the gunicorn.conf.py looks like: import multiprocessing bind = 'unix:/tmp/gunicorn-ourapp.socket' workers = multiprocessing.cpu_count() * 3 + 1 timeout = 600 graceful_timeout = 40 Does anyone know where I can start digging to see what might be causing the problem? This is what my ulimit -a output looks like on the server: core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited scheduling priority (-e) 0 file size (blocks, -f) unlimited pending signals (-i) 59481 max locked memory (kbytes, -l) 64 max memory size (kbytes, -m) unlimited open files (-n) 50000 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 8192 cpu time (seconds, -t) unlimited max user processes (-u) 1024 virtual memory (kbytes, -v) unlimited file locks (-x) unlimited

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  • nginx+django serving static files

    - by avalore
    I have followed instruction for setting up django with nginx from the django wiki (https://code.djangoproject.com/wiki/DjangoAndNginx) and have nginx setup as follows (a few name changes to fit my setup). user nginx nginx; worker_processes 2; error_log /var/log/nginx/error_log info; events { worker_connections 1024; use epoll; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] ' '"$request" $status $bytes_sent ' '"$http_referer" "$http_user_agent" ' '"$gzip_ratio"'; client_header_timeout 10m; client_body_timeout 10m; send_timeout 10m; connection_pool_size 256; client_header_buffer_size 1k; large_client_header_buffers 4 2k; request_pool_size 4k; gzip on; gzip_min_length 1100; gzip_buffers 4 8k; gzip_types text/plain; output_buffers 1 32k; postpone_output 1460; sendfile on; tcp_nopush on; tcp_nodelay on; keepalive_timeout 75 20; ignore_invalid_headers on; index index.html; server { listen 80; server_name localhost; location /static/ { root /srv/static/; } location ~* ^.+\.(jpg|jpeg|gif|png|ico|css|zip|tgz|gz|rar|bz2|doc|xls|exe|pdf|ppt|txt|tar|mid|midi|wav|bmp|rtf|js|mov) { access_log off; expires 30d; } location / { # host and port to fastcgi server fastcgi_pass 127.0.0.1:8080; fastcgi_param PATH_INFO $fastcgi_script_name; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param QUERY_STRING $query_string; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_pass_header Authorization; fastcgi_intercept_errors off; fastcgi_param REMOTE_ADDR $remote_addr; } access_log /var/log/nginx/localhost.access_log main; error_log /var/log/nginx/localhost.error_log; } } Static files aren't being served (nginx 404). If I look in the access log it seems nginx is looking in /etc/nginx/html/static... rather than /srv/static/ as specified in the config. I've no clue why it's doing this, any help would be hugely appreciated.

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  • Request data from database using Django

    - by user21901
    I have somehow two variables for example x and y. I have also made a model with 3 fields (longitude,latitude,name) and have it activated in mysql database. I need to send these two variables(x,y) to the django server so as to search if there is an object with longitude=x and latitude=y.If there is one i want to get back it's name. How can i do this?

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  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

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  • How do I relate two models/tables in Django based on non primary non unique keys?

    - by wizard
    I've got two tables that I need to relate on a single field po_num. The data is imported from another source so while I have a little bit of control over what the tables look like but I can't change them too much. What I want to do is relate these two models so I can look up one from the other based on the po_num fields. What I really need to do is join the two tables so I can do a where on a count of the related table. I would like to do filter for all Order objects that have 0 related EDI856 objects. I tried adding a foreign key to the Order model and specified the db_column and to_fields as po_num but django didn't like that the fact that Edi856.po_num wasn't unique. Here are the important fields of my current models that let me display but not filter for the data that I want. class Edi856(models.Model): po_num = models.CharField(max_length=90, db_index=True ) class Order(models.Model): po_num = models.CharField(max_length=90, db_index=True) def in_edi(self): '''Has the edi been processed?''' return Edi856.objects.filter(po_num = self.po_num).count() Thanks for taking the time to read about my problem. I'm not sure what to do from here.

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  • What kind of data do I pass into a Django Model.save() method?

    - by poswald
    Lets say that we are getting POSTed a form like this in Django: rate=10 items= [23,12,31,52,83,34] The items are primary keys of an Item model. I have a bunch of business logic that will run and create more items based on this data, the results of some db lookups, and some business logic. I want to put that logic into a save signal or an overridden Model.save() method of another model (let's call it Inventory). The business logic will run when I create a new Inventory object using this form data. Inventory will look like this: class Inventory(models.Model): picked_items = models.ManyToManyField(Item, related_name="items_picked_set") calculated_items = models.ManyToManyField(Item, related_name="items_calculated_set") rate = models.DecimalField() ... other fields here ... New calculated_items will be created based on the passed in items which will be stored as picked_items. My question is this: is it better for the save() method on this model to accept: the request object (I don't really like this coupling) the form data as arguments or kwargs (a list of primary keys and the other form fields) a list of Items (The caller form or view will lookup the list of Items and create a list as well as pass in the other form fields) some other approach? I know this is a bit subjective, but I was wondering what the general idea is. I've looked through a lot of code but I'm having a hard time finding a pattern I like.

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  • How to create custom rss feed generator (sharepoint 2010)?

    - by user362194
    I need to create RSS, that include all sharepoint lists and pages. Sharepoint gives "http://localhost/_layouts/listfeed.aspx?List={0251B48D-9D09-4C94-8D33-8A4589C57EC8}&Source=http%3A%2F%2Flocalhost%2FPages%2FForms%2FAllItems.aspx" "http://localhost/_layouts/feed.aspx?xsl=1&web=%2F&page=122705e9-4542-4e65-b001-81ea8699c5bd&wp=922036c8-5d01-4a89-8cd6-65b308095451&pageurl=SitePages%2FTempPage.aspx" How to produce one rss for all site content?

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  • Django app that can provide user friendly, multiple / mass file upload functionality to other apps

    - by hopla
    Hi, I'm going to be honest: this is a question I asked on the Django-Users mailinglist last week. Since I didn't get any replies there yet, I'm reposting it on Stack Overflow in the hope that it gets more attention here. I want to create an app that makes it easy to do user friendly, multiple / mass file upload in your own apps. With user friendly I mean upload like Gmail, Flickr, ... where the user can select multiple files at once in the browse file dialog. The files are then uploaded sequentially or in parallel and a nice overview of the selected files is shown on the page with a progress bar next to them. A 'Cancel' upload button is also a possible option. All that niceness is usually solved by using a Flash object. Complete solutions are out there for the client side, like: SWFUpload http://swfupload.org/ , FancyUpload http://digitarald.de/project/fancyupload/ , YUI 2 Uploader http://developer.yahoo.com/yui/uploader/ and probably many more. Ofcourse the trick is getting those solutions integrated in your project. Especially in a framework like Django, double so if you want it to be reusable. So, I have a few ideas, but I'm neither an expert on Django nor on Flash based upload solutions. I'll share my ideas here in the hope of getting some feedback from more knowledgeable and experienced people. (Or even just some 'I want this too!' replies :) ) You will notice that I make a few assumptions: this is to keep the (initial) scope of the application under control. These assumptions are of course debatable: All right, my idea's so far: If you want to mass upload multiple files, you are going to have a model to contain each file in. I.e. the model will contain one FileField or one ImageField. Models with multiple (but ofcourse finite) amount of FileFields/ ImageFields are not in need of easy mass uploading imho: if you have a model with 100 FileFields you are doing something wrong :) Examples where you would want my envisioned kind of mass upload: An app that has just one model 'Brochure' with a file field, a title field (dynamically created from the filename) and a date_added field. A photo gallery app with models 'Gallery' and 'Photo'. You pick a Gallery to add pictures to, upload the pictures and new Photo objects are created and foreign keys set to the chosen Gallery. It would be nice to be able to configure or extend the app for your favorite Flash upload solution. We can pick one of the three above as a default, but implement the app so that people can easily add additional implementations (kinda like Django can use multiple databases). Let it be agnostic to any particular client side solution. If we need to pick one to start with, maybe pick the one with the smallest footprint? (smallest download of client side stuff) The Flash based solutions asynchronously (and either sequentially or in parallel) POST the files to a url. I suggest that url to be local to our generic app (so it's the same for every app where you use our app in). That url will go to a view provided by our generic app. The view will do the following: create a new model instance, add the file, OPTIONALLY DO EXTRA STUFF and save the instance. DO EXTRA STUFF is code that the app that uses our app wants to run. It doesn't have to provide any extra code, if the model has just a FileField/ImageField the standard view code will do the job. But most app will want to do extra stuff I think, like filling in the other fields: title, date_added, foreignkeys, manytomany, ... I have not yet thought about a mechanism for DO EXTRA STUFF. Just wrapping the generic app view came to mind, but that is not developer friendly, since you would have to write your own url pattern and your own view. Then you have to tell the Flash solutions to use a new url etc... I think something like signals could be used here? Forms/Admin: I'm still very sketchy on how all this could best be integrated in the Admin or generic Django forms/widgets/... (and this is were my lack of Django experience shows): In the case of the Gallery/Photo app: You could provide a mass Photo upload widget on the Gallery detail form. But what if the Gallery instance is not saved yet? The file upload view won't be able to set the foreignkeys on the Photo instances. I see that the auth app, when you create a user, first asks for username and password and only then provides you with a bigger form to fill in emailadres, pick roles etc. We could do something like that. In the case of an app with just one model: How do you provide a form in the Django admin to do your mass upload? You can't do it with the detail form of your model, that's just for one model instance. There's probably dozens more questions that need to be answered before I can even start on this app. So please tell me what you think! Give me input! What do you like? What not? What would you do different? Is this idea solid? Where is it not? Thank you!

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  • ASP.NET MVC: How does one add authentication to RSS Feeds?

    - by Mark Redman
    I have seen a few examples of how to create RSS feeds using ASP.NET MVC, either by creating an Action or through an HttpHandler. I need to authenticate feeds and am wondering how this is to be done (and supported by RSS readers rather than just browsing to the page/xml through a browser) and how would authentications differ between an MVC Action or HttpHandler?

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  • What the guidelines around filters and querystring parameters in RSS Feeds?

    - by Chris Henry
    I run a site where users can content that is tagged by a special set of tags. While implementing RSS feeds, I was wondering what, if any, rules or guidelines exist for using a querystring to filter what content an RSS feed shows. For example, the feed that shows all content on the site would be: /feed If someone was interested in all the work that was tagged with fashion, the URL would be /feed?tag=fashion

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  • Transform RSS-Feed into another "standard" XML-Format with PHP

    - by ChrisBenyamin
    Hey friends, quick question: I need to transform a default RSS Structure into another XML-format. The RSS File is like.... Name des RSS Feed Feed Beschreibung de http://xml-rss.de Sat, 1 Jan 2000 00:00:00 GMT Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 ...and I want to extract only the item-elements (with childs and attributes) XML like: <?xml version="1.0" encoding="ISO-8859-1"?> <item> <title>Titel der Nachricht</title> <description>Die Nachricht an sich</description> <link>http://xml-rss.de/link-zur-nachricht.htm</link> <pubDate>Sat, 1. Jan 2000 00:00:00 GMT</pubDate> <guid>01012000-000000</guid> </item> ... It hasn't to be stored into a file. I need just the output. I tried different approaches with DOMNode, SimpleXML, XPath, ... but without success. Thanks chris

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  • Implementing a popularity algorithm in Django

    - by TheLizardKing
    I am creating a site similar to reddit and hacker news that has a database of links and votes. I am implementing hacker news' popularity algorithm and things are going pretty swimmingly until it comes to actually gathering up these links and displaying them. The algorithm is simple: Y Combinator's Hacker News: Popularity = (p - 1) / (t + 2)^1.5` Votes divided by age factor. Where` p : votes (points) from users. t : time since submission in hours. p is subtracted by 1 to negate submitter's vote. Age factor is (time since submission in hours plus two) to the power of 1.5.factor is (time since submission in hours plus two) to the power of 1.5. I asked a very similar question over yonder http://stackoverflow.com/questions/1964395/complex-ordering-in-django but instead of contemplating my options I choose one and tried to make it work because that's how I did it with PHP/MySQL but I now know Django does things a lot differently. My models look something (exactly) like this class Link(models.Model): category = models.ForeignKey(Category) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add = True) modified = models.DateTimeField(auto_now = True) fame = models.PositiveIntegerField(default = 1) title = models.CharField(max_length = 256) url = models.URLField(max_length = 2048) def __unicode__(self): return self.title class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add = True) modified = models.DateTimeField(auto_now = True) karma_delta = models.SmallIntegerField() def __unicode__(self): return str(self.karma_delta) and my view: def index(request): popular_links = Link.objects.select_related().annotate(karma_total = Sum('vote__karma_delta')) return render_to_response('links/index.html', {'links': popular_links}) Now from my previous question, I am trying to implement the algorithm using the sorting function. An answer from that question seems to think I should put the algorithm in the select and sort then. I am going to paginate these results so I don't think I can do the sorting in python without grabbing everything. Any suggestions on how I could efficiently do this? EDIT This isn't working yet but I think it's a step in the right direction: from django.shortcuts import render_to_response from linkett.apps.links.models import * def index(request): popular_links = Link.objects.select_related() popular_links = popular_links.extra( select = { 'karma_total': 'SUM(vote.karma_delta)', 'popularity': '(karma_total - 1) / POW(2, 1.5)', }, order_by = ['-popularity'] ) return render_to_response('links/index.html', {'links': popular_links}) This errors out into: Caught an exception while rendering: column "karma_total" does not exist LINE 1: SELECT ((karma_total - 1) / POW(2, 1.5)) AS "popularity", (S... EDIT 2 Better error? TemplateSyntaxError: Caught an exception while rendering: missing FROM-clause entry for table "vote" LINE 1: SELECT ((vote.karma_total - 1) / POW(2, 1.5)) AS "popularity... My index.html is simply: {% block content %} {% for link in links %} karma-up {{ link.karma_total }} karma-down {{ link.title }} Posted by {{ link.user }} to {{ link.category }} at {{ link.created }} {% empty %} No Links {% endfor %} {% endblock content %} EDIT 3 So very close! Again, all these answers are great but I am concentrating on a particular one because I feel it works best for my situation. from django.db.models import Sum from django.shortcuts import render_to_response from linkett.apps.links.models import * def index(request): popular_links = Link.objects.select_related().extra( select = { 'popularity': '(SUM(links_vote.karma_delta) - 1) / POW(2, 1.5)', }, tables = ['links_link', 'links_vote'], order_by = ['-popularity'], ) return render_to_response('links/test.html', {'links': popular_links}) Running this I am presented with an error hating on my lack of group by values. Specifically: TemplateSyntaxError at / Caught an exception while rendering: column "links_link.id" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...karma_delta) - 1) / POW(2, 1.5)) AS "popularity", "links_lin... Not sure why my links_link.id wouldn't be in my group by but I am not sure how to alter my group by, django usually does that.

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  • List of Django model instance foreign keys losing consistency during state changes.

    - by Joshua
    I have model, Match, with two foreign keys: class Match(model.Model): winner = models.ForeignKey(Player) loser = models.ForeignKey(Player) When I loop over Match I find that each model instance uses a unique object for the foreign key. This ends up biting me because it introduces inconsistency, here is an example: >>> def print_elo(match_list): ... for match in match_list: ... print match.winner.id, match.winner.elo ... print match.loser.id, match.loser.elo ... >>> print_elo(teacher_match_list) 4 1192.0000000000 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 >>> teacher_match_list[0].winner.elo = 3000 >>> print_elo(teacher_match_list) 4 3000 # Object 4 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 # Object 4 >>> I solved this problem like so: def unify_refrences(match_list): """Makes each unique refrence to a model instance non-unique. In cases where multiple model instances are being used django creates a new object for each model instance, even if it that means creating the same instance twice. If one of these objects has its state changed any other object refrencing the same model instance will not be updated. This method ensure that state changes are seen. It makes sure that variables which hold objects pointing to the same model all hold the same object. Visually this means that a list of [var1, var2] whose internals look like so: var1 --> object1 --> model1 var2 --> object2 --> model1 Will result in the internals being changed so that: var1 --> object1 --> model1 var2 ------^ """ match_dict = {} for match in match_list: try: match.winner = match_dict[match.winner.id] except KeyError: match_dict[match.winner.id] = match.winner try: match.loser = match_dict[match.loser.id] except KeyError: match_dict[match.loser.id] = match.loser My question: Is there a way to solve the problem more elegantly through the use of QuerySets without needing to call save at any point? If not, I'd like to make the solution more generic: how can you get a list of the foreign keys on a model instance or do you have a better generic solution to my problem? Please correct me if you think I don't understand why this is happening.

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  • RSS Feeds currently on Simple-Talk

    - by Andrew Clarke
    There are a number of news-feeds for the Simple-Talk site, but for some reason they are well hidden. Whilst we set about reorganizing them, I thought it would be a good idea to list some of the more important ones. The most important one for almost all purposes is the Homepage RSS feed which represents the blogs and articles that are placed on the homepage. Main Site Feed representing the Homepage ..which is good for most purposes but won't always have all the blogs, or maybe it will occasionally miss an article. If you aren't interested in all the content, you can just use the RSS feeds that are more relevant to your interests. (We'll be increasing these categories soon) The newsfeed for SQL articles The .NET section newsfeed The newsfeed for Red Gate books The newsfeed for Opinion articles The SysAdmin section newsfeed if you want to get a more refined feed, then you can pick and choose from these feeds for each category so as to make up your custom news-feed in the SQL section, SQL Training Learn SQL Server Database Administration TSQL Programming SQL Server Performance Backup and Recovery SQL Tools SSIS SSRS (Reporting Services) in .NET there are... ASP.NET Windows Forms .NET Framework ,NET Performance Visual Studio .NET tools in Sysadmin there are Exchange General Virtualisation Unified Messaging Powershell in opinion, there is... Geek of the Week Opinion Pieces in Books, there is .NET Books SQL Books SysAdmin Books And all the blogs have got feeds. So although you can get all the blogs from here.. Main Blog Feed          You can get individual RSS feeds.. AdamRG's Blog       Alex.Davies's Blog       AliceE's Blog       Andrew Clarke's Blog       Andrew Hunter's Blog       Bart Read's Blog       Ben Adderson's Blog       BobCram's Blog       bradmcgehee's Blog       Brian Donahue's Blog       Charles Brown's Blog       Chris Massey's Blog       CliveT's Blog       Damon's Blog       David Atkinson's Blog       David Connell's Blog       Dr Dionysus's Blog       drsql's Blog       FatherJack's Blog       Flibble's Blog       Gareth Marlow's Blog       Helen Joyce's Blog       James's Blog       Jason Crease's Blog       John Magnabosco's Blog       Laila's Blog       Lionel's Blog       Matt Lee's Blog       mikef's Blog       Neil Davidson's Blog       Nigel Morse's Blog       Phil Factor's Blog       red@work's Blog       reka.burmeister's Blog       Richard Mitchell's Blog       RobbieT's Blog       RobertChipperfield's Blog       Rodney's Blog       Roger Hart's Blog       Simon Cooper's Blog       Simon Galbraith's Blog       TheFutureOfMonitoring's Blog       Tim Ford's Blog       Tom Crossman's Blog       Tony Davis's Blog       As well as these blogs, you also have the forums.... SQL Server for Beginners Forum     Programming SQL Server Forum    Administering SQL Server Forum    .NET framework Forum    .Windows Forms Forum   ASP.NET Forum   ADO.NET Forum 

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  • Lost in UTF-8 hell. (Django and Python)

    - by user140314
    I am working through the Django RSS reader project here. The RSS feed will read something like "OKLAHOMA CITY (AP) — James Harden let". The RSS feed's encoding reads encoding="UTF-8" so I believe I am passing utf-8 to markdown in the code snippet below. The em dash is where it chokes. I get the Django error of "'ascii' codec can't encode character u'\u2014' in position 109: ordinal not in range(128)" which is an UnicodeEncodeError. In the variables being passed I see "OKLAHOMA CITY (AP) \u2014 James Harden". The code line that is not working is: content = content.encode(parsed_feed.encoding, "xmlcharrefreplace") I am using markdown 2.0, django 1.1, and python 2.4. What is the magic sequence of encoding and decoding that I need to do to make this work? Thanks.

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