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  • Valid Dates in AppEngine forms (Beginner)

    - by codingJoe
    In AppEngine, I have a form that prompts a user for a date. The problem is that when the clicks enter there is an error: "Enter a Valid Date" How do I make my Form accept (for example) %d-%b-%Y as the date format? Is there a more elegant way to accomplish this? # Model and Forms class Task(db.Model): name=db.StringProperty() due=db.DateProperty() class TaskForm(djangoforms.ModelForm): class Meta: model = Task # my get function has the following. # using "now" for example. Could just as well be next Friday. tmStart = datetime.now() form = TaskForm(initial={'due': tmStart.strftime("%d-%b-%Y")}) template_values = {'form': form }

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  • jQuery validation plugin doesn't work for me

    - by Idsa
    I have the following code to enable validation work: $(document).ready(function() { $("#eventForm").validate({ rules: { startDate: "required", startTime: "required", endDate: { required: function (element) { var endTimeValue = $('#endTime').val(); return (endTimeValue != null && endTimeValue != ''); } }, endTime: { required: function (element) { var endDateValue = $('#endDate').val(); return (endDateValue != null && endDateValue != ''); } } }, messages: { startDate: "Please enter event local start date", startTime: "Please enter event local start time" }, errorPlacement: function (error, element) { error.appendTo(element.parent().next()); }, submitHandler: function (form) { var options = { dataType: 'json', success: eventCreationSuccess, error: eventCreationError }; alert('submit'); //$(form).ajaxSubmit(options); } }); }); But validation plugin doesn't catch submit - default submit is executed. jQuery and validation plugin scripts are imported.

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  • Visual Studio bug ~ can anyone duplicate?

    - by drachenstern
    In Visual Studio 2010 Pro (Version 10.0.30319.1 RTMRel), I noticed tonight that for some reason I kept getting a wider window for quick find, but thought I was losing my mind. So I exited, restarted, etc to verify. Here's my repro steps Open existing project (I don't think it matters which one) Press ctrlf and give it something to search for (?) Press enter Press ctrlf Press enter goto 4 Can you reproduce a slowly expanding quick find window? Do I have some sort of wacky bugged out system? I'ld obviously like to submit a bug report to MS if this is indeed a viable repro.

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  • jtextfield keyevent handling issue

    - by vamsi
    doesn't .getKeyCode( ) return the key's int value? Because i have set my jtextfield to listen to keylistener, and in the keytyped method, i check what key has been pressed. Here's a snippet of my code: JTextField jtf = new JTextField( ); jtf.addKeyListener( this ); . . . public void keyTyped( KeyEvent e ) { if( e.getKeyCode( ) == KeyEvent.VK_ENTER ) System.out.println( "pressed enter" ); } but everytime i type enter in the jtextfield, nothing happens, ie nothing prints.

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  • ASP.NET Canceling the Default Submit Button

    - by Ryan Smith
    I have an ASP.NET application where there's a few ASP.NET buttons and several plain HTML buttons. Anytime there's a textbox where a user hits enter, the ASP.NET button trys to submit the form. I know I can change the defaultButton, but I don't want there to be any default button. I just want it so when the user presses enter it doesn't do anything. I've tried setting defaultButton to blank, but that doesn't seem to work and I can't seem to find the answer anywhere on the web. What's the code to make this happen? Thanks.

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  • Database Logon Error in crystal report

    - by yasar arafat
    am really very dumb as this problem is being answered so many times but eally its above my head. i dont have any idea about working with crystal reports or asp.net but due to some reason i have to work on it. after trying very hard i m able to design on crystal report connecting it with mysql database. now when i see in the crystalreport preview i am able to see the report and the data ![enter image description here][1] but when i try to run it on server it says database logon failed![enter image description here][2] now i really dont know what to do i am pasting my aspx and aspx.vb code here and please repley in english not computer language believe me i m super dumb enter code here aspx codes <%@ Page Title="" Language="VB" MasterPageFile="~/Master/Site.master"AutoEventWireup="false" CodeFile="ManHourCostExpenditure.aspx.vb" Inherits="ManHourCostExpenditure" %> <%@ Register assembly="CrystalDecisions.Web, Version=13.0.2000.0, Culture=neutral, PublicKeyToken=692fbea5521e1304" namespace="CrystalDecisions.Web" tagprefix="CR" %> <asp:Content ID="Content1" ContentPlaceHolderID="head" Runat="Server"> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" Runat="Server"> <CR:CrystalReportViewer ID="CrystalReportViewer1" runat="server" AutoDataBind="True" EnableDatabaseLogonPrompt="False" EnableParameterPrompt="False" GroupTreeImagesFolderUrl="" Height="1202px" ReportSourceID="CrystalReportSource1" ToolbarImagesFolderUrl="" ToolPanelView="None" ToolPanelWidth="200px" Width="903px" BorderColor="#660033" BorderStyle="Solid" BorderWidth="1px" HasCrystalLogo="False" /> <CR:CrystalReportSource ID="CrystalReportSource1" runat="server"> <Report FileName="CrDiscProjManHoursActVsEst.rpt"> </Report> </CR:CrystalReportSource> </asp:Content> aspxdotvb codes Imports CrystalDecisions.CrystalReports.Engine Imports CrystalDecisions.Shared Imports CrystalDecisions.Enterprise Imports CrystalDecisions.ReportSource Imports CrystalDecisions.Web Imports CrystalDecisions.Windows.Forms Imports MySql Imports MySql.Data Imports MySql.Data.MySqlClient Imports System.Collections Imports System.Collections.Generic Imports System.Text Imports CrystalDecisions Imports CrystalDecisions.CrystalReports Imports CrystalReportsReportDefModelLib Partial Class ManHourCostExpenditure Inherits System.Web.UI.Page Dim CrRpt As New CrystalDecisions.CrystalReports.Engine.ReportDocument Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Dim StrConn As String = "SERVER=localhost;DATABASE=fluor;UID=root; PWD=root;" Dim Conn As New MySqlConnection(StrConn) Conn.Open() Dim CrRpt As New CrystalDecisions.CrystalReports.Engine.ReportDocument 'Session.Add("REPORT_KEY", CrRpt) CrRpt.Load(Server.MapPath("CrManHourCostExpenditure.rpt")) CrRpt.PrintOptions.PaperOrientation = PaperOrientation.Landscape 'If IsPostBack Then ' CrRpt = CType(Session.Item("REPORT_KEY"), Group) ' CrystalReportViewer1.ReportSource = CrRpt 'End If CrystalReportViewer1.ReportSource = CrRpt 'CrystalReportViewer1.DataBind() CrystalReportViewer1.RefreshReport() Conn.Close() 'CrRpt.Close() 'CrRpt.Dispose() End Sub Protected Sub Page_Unload(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Unload 'CrystalReportViewer1.ReportSource.Close() CrRpt.Close() CrRpt.Dispose() End Sub 'Protected Sub CrystalReportViewer1_Unload(ByVal sender As Object, ByVal e As System.EventArgs) Handles CrystalReportViewer1.Unload ' CrRpt.Close() ' CrRpt.Dispose() 'End Sub End Class please help me. thanks in advance.... yasir

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  • Can output from OutputDebugString be viewed in VisualStudio's output window

    - by wageoghe
    I am using C# and VS2010. When I use OutputDebugString to write debug information, should it show up in the output window? I can see the output from OutputDebugString in DebugView, but I thought I would see it in Visual Studio's Output window. I have looked under Tools-Options-Debugging-General and the output is NOT being redirected to the Immediate window. I have also looked under Tools-Options-Debugging-Output Window and all General Output Settings are set to "On". Finally, I have used the drop-down list in the Output window to specify that Debug messages should appear. If I change Tools-Options-Debugging-General to redirect the output to the Immediate window, the OutputDebugString messages do not appear in the immediate window. Here is my entire test program: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Runtime.InteropServices; using System.Diagnostics; namespace OutputDebugString { class Program { [DllImport("kernel32.dll", CharSet = CharSet.Auto)] public static extern void OutputDebugString(string message); static void Main(string[] args) { Console.WriteLine("Main - Enter - Console.WriteLine"); Debug.WriteLine("Main - Enter - Debug.WriteLine"); OutputDebugString("Main - Enter - OutputDebugString"); OutputDebugString("Main - Exit - OutputDebugString"); Debug.WriteLine("Main - Exit - Debug.WriteLine"); Console.WriteLine("Main - Exit - Console.WriteLine"); } } } If I run within the debugger, the Debug.WriteLine output does show up in the output window, but the OutputDebugString output does not. If I run from a console window, both Debug.WriteLine and OutputDebugString show up in DebugView. Why doesn't the OutputDebugString output ever show up in the output window? Ultimately, my intent is not to write a lot of debug output with OutputDebugString, rather I will use System.Diagnostics or NLog or something similar. I am just trying to find out, if I configure a logging platform to write to OutputDebugString, will the output be visible from within the debugger. Edit: I went back to my original program (not the simple test above) which uses TraceSources and TraceListeners configured via the app.config file. If I configure the trace sources to write to the System.Diagnostics.DefaultTraceListener (which is documented as writing to OutputDebugString), then the trace source output DOES go to the debug window. However, lines that write directly with OutputDebugString (such as in my simple example) DO NOT go to the debug window. Also, if I use a different TraceListener that writes to OutputDebugString (I got one from Ukadc.Diagnostics at codeplex), that output DOES NOT go to the debug window. Note that I have seen these questions but they did not provide a working solution: here and here

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  • How To Keep Size Of JTextArea constant?

    - by Supereme
    Hi! I'm using an object of JTextArea in my application which deals with sending sms. I've used a DocumentFilter so as to allow only 160 characters to be typed in the textarea but now, I want the size of the textarea to be constant. it goes on increasing if I keep writing on the same line without pressing 'enter' key or even when I keep on pressing only 'enter' key. I tried once using 'scrollbar' too but the problem remains same. Suggest me something over this.

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  • Problem with a SQL statement

    - by benwad
    I'm trying to enter values into a database table using a form and a PHP function. The PHP seems to be fine as the SQL statement it creates looks okay, but the database always throws up an error. This is the SQL statement that my code has generated (with arbitrary values): INSERT INTO Iteminfo ('itemName', 'itemSeller', 'itemCategory', 'itemDescription', 'itemPrice', 'itemPostage', 'itemBegin', 'itemEnd', 'buynow', 'itemPicture') values ('gorillaz album', 'ben', 'music', 'new one ', '5.00', '1.00', '2010-03-15 14:59:51', '2010-03-16 14:59:51', '0', 'http://www.thefader.com/wp-content/uploads/2010/01/gorillaz-plastic-beach.jpg') This throws up an error both when I use the PHP function to evaluate the query and also when I use phpMyAdmin to enter the query manually. However, I can't see anything wrong with it. Can anyone shed some light on this? All of the fields are VARCHAR values, except for itemPrice and itemPostage (which are stored as DECIMAL(4,2)) and the itemBegin and itemEnd, which are stored as DATETIMEs.

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  • BlueJ Chpt 4 - Auction Project - How to make removeLot method work after entering a new lot

    - by Ellaine Ryan
    Hi All I am learning Java through BlueJ I would like to add a removeLot method to the Auction Class in BlueJ Chpt 4. This involves also returning the lot with the given number or null if there is no such lot. If you enter , say 5 lots and then use the remove method, this codes removes whichever lot you specify. However if you enter a new lot after using the removeLot method - an internal error message comes up regarding lotnumbering . Any ideas? Thanks Elaine public Lot removeLot(int number) { if((number >= 1) ) { } Lot lot = getLot (number); if(lot !=null) { lots.remove(lot); } return lot; }

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  • Understanding the Unix file system and ruby installs without Sudo

    - by JZ
    I'm trying to comprehend the Unix file system on my OSX. I'm following wikipedia Filesystem Hierarchy Standard. I understand when I install ruby gems I must use the command sudo gem install but if I omit sudo, problems may occur. Where are gems installed within the file system when I omit sudo? How can I delete these gems? A Fun side question: When I enter cd ~/.gem my terminal is directed to .gem user$, When I enter cd ~/ and list folders using the ls command I can't find a .gem folder. Where is the .gem folder? How does this fit into the Filesystem?

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  • selecting href not starting with http

    - by sushil bharwani
    using jQuery i am trying to find out all the URLS that user has entered which are not starting with http or https and finally i want to prepend http to all such URLs so that when user clicks on them they are taken to a proper site instead of broken link caused due to entry of URLs without http or https. Also like to mention that User have a field "Websites they Like" where they enter websites of their interest. So if they like stackoverflow, they may end up writing www.stackoverflow.com which will be considered a relative link without http. Also my requirments are such that i cant prompt user to enter http or https before there urls

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  • Visual Studio bug ~ 1 verified repro, 1 verified non-repro, any others?

    - by drachenstern
    In Visual Studio 2010 Pro (Version 10.0.30319.1 RTMRel), I noticed tonight that for some reason I kept getting a wider window for quick find, but thought I was losing my mind. So I exited, restarted, etc to verify. Here's my repro steps Open existing project (I don't think it matters which one) Press ctrlf and give it something to search for (?) in "current document" Press enter Press ctrlf Press enter goto 4 Can you reproduce a slowly expanding quick find window? Do I have some sort of wacky bugged out system? I'ld obviously like to submit a bug report to MS if this is indeed a viable repro.

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  • jQuery Event Keypress: Which key was pressed?

    - by BlaM
    With jQuery, how do I find out which key was pressed when I bind to the keypress event? $('#searchbox input').bind('keypress', function(e) {}); I want to trigger an submit when ENTER is pressed. [Update] Even though I found the (or better: one) answer myself, there seems to be some room for variation ;) Is there a difference between keyCode and which - especially if I'm just looking for ENTER, which will never be a unicode key? Do some browsers provide one property and others provide the other one?

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  • Add/remove UILocalNotification based on changes in my settings bundle

    - by Daniel Chui
    I have an app that sends a notification at the same time everyday, reminding the user to enter data into it. However, I want to give the user teh option to disable this as this could get very annoying, so I have an "Enable alerts" in a custom settings bundle. My question is, when the user toggles the switch in the settings bundle, can I add/remove the notifications that are already scheduled without having to enter the app again? note: I'm building and supporting for iOS 4.2.1, and I don't konw why but under "notifications" in the settings app, my app does not appear. I see it on ios 5.x devices though

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  • jquery button click not firing asp.net button

    - by lloydphillips
    I've got a .net button that has an href attribute value set to 'javascript:WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions("ctl00$cp1$ucInvoiceSearch$btnSearch", "", true, "", "", false, true))'. I've got a textbox that when I press enter I want it to fire this event. Doing the 'Enter' event isn't an issue but I can't get the event on the href to fire using .click(). Here's my function so far: $("[id*='tbInvNo']").keyup(function(event){ var $btn = $(".pnl-invoice-search"); if(event.keyCode == 13) $btn.click(); }); I've got no idea how to get this to fire. Hope someone can help - jQuery and asp.net are driving me up the wall today! :(

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  • Using a Filter to serve a specific page?

    - by user246114
    Hi, I am using a class which implements Filter for my jsp stuff. It looks like this: public class MyFilter implements Filter { public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { request.getRequestDispatcher("mypage.jsp").forward(request, response); } } So the target, "mypage.jsp", is just sitting in my top-level directory. The filter works fine if I'm entering urls like: http://www.mysite.com/foo http://www.mysite.com/boo but if I enter a trailing slash, I'll get a 404: http://www.mysite.com/foo/ http://www.mysite.com/boo/ HTTP ERROR: 404 /foo/mypage.jsp RequestURI=/foo/mypage.jsp it seems if I enter the trailing slash, then the filter thinks I want it to look for mypage.jsp in subfolder foo or boo, but I really always want it to just find it at: http://www.mysite.com/mypage.jsp how can I do that? Thank you

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  • Java.util.scanner error handeling

    - by Hussain
    I'm helping a friend with a java problem. However, we've hit a snag. We're using Java.Util.Scanner.nextInt() to get a number from the user, asking continiously if the user gives anything else. Only problem is, we can't figure out how to do the error handeling. What we've tried: do { int reloop = 0; try { number = nextInt(); } catch (Exception e) { System.out.println ("Please enter a number!"); reloop ++; } } while(reloop != 0); Only problem is, this loops indefinatly if you enter in something not a number. Any help?

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  • how to read character from console in c++?

    - by tsubasa
    I'm struggling with reading characters from console in c++. Here is what I tried to do: char x; char y; char z; cout<<"Please enter your string: "; string s; getline(cin,s); istringstream is(s); is>> x >> y >> z; The problem is if the user enter something like this "1 20 100": x will get 1 y will get 2 z will get 0 What I want to get is x = 1; y = 20; z = 100; Anybody has suggestions?

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  • displaying current minute of a soccer match

    - by zurna
    I could not figure out the logic I would need to display a current minute of a soccer match. I have three fields in the database. DateFirstStarted DateSecondStarted DateFullEnded I should enter DateFirstStarted when the game starts and on the website. i.e. game starts at 7:05pm, on 7:25pm it should display '20 on the website. However, it should stop on the 45th minute. Then, I enter DateSecondStarted when the second half starts and should count from 46 to 90 and freeze there. Do I make sense? How can I do it? Is there a better way to do this?

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  • Threading process in asp.net

    - by Zerotoinfinite
    Hi All, I am using asp.net 3.5 and C#. I have a blog site and I want that whenever user enter any comment, the suscriber related to that post will get the notification. So what I am doing that I am sending mail at the same time as the comment is inserted into the table, which sometimes take time because of the quantity of user. Is their any way that user enter the comment into the database and the send mail function will run asynchornysly which will not interfear user to go ahead with his task. please let me know how to acheieve it in a simplier way. Thanks in advance

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  • IE not triggering keyboard event on a form with ONE FIELD

    - by raj
    I'm seeing my Friend's code here... <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD> <TITLE> Check action </TITLE> <script> function detectEvent(){ if(window.event.keyCode==13) { alert("you hit return!"); } } </script> </HEAD> <BODY> <form name="name1" onkeyup="detectEvent()" action="page2.html"> <p> Field1 <input type="text" id="text1"/> </p> </form> </BODY> </HTML> and when he tried entering a value in the textbox and pressed enter, it did not call the detectEvent(). I said, it'll always call onSubmit on enter button..... and he surprised me, <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD> <TITLE> Check action </TITLE> <script> function detectEvent(){ if(window.event.keyCode==13) { alert("you hit return!"); } } </script> </HEAD> <BODY> <form name="name1" onkeyup="detectEvent()" action="page2.html"> <p> Field1 <input type="text" id="text1"/> </p> <p> Field1 <input type="text" id="text2"/> </p> </form> </BODY> </HTML> Now press enter, The function gets called..... Why so!? Why onKeyUp not called on forms with just one field.!!! am i missing something?

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  • Exception Error in c#

    - by Kumu
    using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.IO; using System.Runtime.Serialization.Formatters.Binary; namespace FoolballLeague { public partial class MainMenu : Form { FootballLeagueDatabase footballLeagueDatabase; Game game; Login login; public MainMenu() { InitializeComponent(); changePanel(1); } public MainMenu(FootballLeagueDatabase footballLeagueDatabaseIn) { InitializeComponent(); footballLeagueDatabase = footballLeagueDatabaseIn; } private void Form_Loaded(object sender, EventArgs e) { } private void gameButton_Click(object sender, EventArgs e) { int option = 0; changePanel(option); } private void scoreboardButton_Click(object sender, EventArgs e) { int option = 1; changePanel(option); } private void changePanel(int optionIn) { gamePanel.Hide(); scoreboardPanel.Hide(); string title = "Football League System"; switch (optionIn) { case 0: gamePanel.Show(); this.Text = title + " - Game Menu"; break; case 1: scoreboardPanel.Show(); this.Text = title + " - Display Menu"; break; } } private void logoutButton_Click(object sender, EventArgs e) { login = new Login(); login.Show(); this.Hide(); } private void addGameButton_Click(object sender, EventArgs e) { if ((homeTeamTxt.Text.Length) == 0) MessageBox.Show("You must enter a Home Team"); else if (homeScoreUpDown.Value > 9 || homeScoreUpDown.Minimum < 0) MessageBox.Show("You must enter one digit between 0 and 9"); else if ((awayTeamTxt.Text.Length) == 0) MessageBox.Show("You must enter a Away Team"); else if (homeScoreUpDown.Value > 9 || homeScoreUpDown.Value < 0) MessageBox.Show("You must enter one digit between 0 to 9"); else { //checkGameInputFields(); game = new Game(homeTeamTxt.Text, int.Parse(homeScoreUpDown.Value.ToString()), awayTeamTxt.Text, int.Parse(awayScoreUpDown.Value.ToString())); MessageBox.Show("Home Team -" + '\t' + homeTeamTxt.Text + '\t' + "and" + '\r' + "Away Team -" + '\t' + awayTeamTxt.Text + '\t' + "created"); footballLeagueDatabase.AddGame(game); //clearCreateStudentInputFields(); } } private void timer1_Tick(object sender, EventArgs e) { displayDateAndTime(); } private void displayDateAndTime() { dateLabel.Text = DateTime.Today.ToLongDateString(); timeLabel.Text = DateTime.Now.ToShortTimeString(); } private void displayResultsButton_Click(object sender, EventArgs e) { Game game = new Game(homeTeamTxt.Text, int.Parse(homeScoreUpDown.Value.ToString()), awayTeamTxt.Text, int.Parse(awayScoreUpDown.Value.ToString())); gameResultsListView.Items.Clear(); gameResultsListView.View = View.Details; ListViewItem row = new ListViewItem(); row.SubItems.Add(game.HomeTeam.ToString()); row.SubItems.Add(game.HomeScore.ToString()); row.SubItems.Add(game.AwayTeam.ToString()); row.SubItems.Add(game.AwayScore.ToString()); gameResultsListView.Items.Add(row); } private void displayGamesButton_Click(object sender, EventArgs e) { Game game = new Game("Home", 2, "Away", 4);//homeTeamTxt.Text, int.Parse(homeScoreUpDown.Value.ToString()), awayTeamTxt.Text, int.Parse(awayScoreUpDown.Value.ToString())); modifyGamesListView.Items.Clear(); modifyGamesListView.View = View.Details; ListViewItem row = new ListViewItem(); row.SubItems.Add(game.HomeTeam.ToString()); row.SubItems.Add(game.HomeScore.ToString()); row.SubItems.Add(game.AwayTeam.ToString()); row.SubItems.Add(game.AwayScore.ToString()); modifyGamesListView.Items.Add(row); } } } This is the whole code and I got same error like previous question. Unhandled Exception has occurred in you application.If you click...............click Quit.the application will close immediately. Object reference not set to an instance of an object. And the following details are in the error message. ***** Exception Text ******* System.NullReferenceException: Object reference not set to an instance of an object. at FoolballLeague.MainMenu.addGameButton_Click(Object sender, EventArgs e) in C:\Users\achini\Desktop\FootballLeague\FootballLeague\MainMenu.cs:line 91 at System.Windows.Forms.Control.OnClick(EventArgs e) at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent) at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.ButtonBase.WndProc(Message& m) at System.Windows.Forms.Button.WndProc(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) at System.Windows.Forms.NativeWindow.Callback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) I need to add the games to using the addGameButton and the save those added games and display them in the list view (gameResultsListView). Now I can add a game and display in the list view.But when I pressed the button addGameButton I got the above error message. If you can please give me a solution to this problem.

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  • KeyCode_Enter to next edittext

    - by soclose
    Hi, In edittext, after typing 'Enter' key, system make a new line inside it. I'd like to focus on next edittext, no new line. how to code? my code in xml is below <EditText android:id="@+id/txtNPCode" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textSize="18sp" android:layout_alignLeft="@+id/lblNPCode" android:layout_below="@+id/lblNPCode" android:layout_centerHorizontal="true" /> <EditText android:id="@+id/txtCNPCode" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textSize="18sp" android:layout_alignLeft="@+id/lblCNPCode" android:layout_below="@+id/lblCNPCode" android:layout_centerHorizontal="true" /> I also caputer key code in setOnKeyListener tCNPCode.setOnKeyListener(new OnKeyListener() { public boolean onKey(View v, int keyCode, KeyEvent event) { // TODO Auto-generated method stub if(keyCode == 66) { Toast.makeText(S_PCode.this, "Enter Key", Toast.LENGTH_LONG).show(); //tNPCode.setFocusable(true); } return false; } });

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