Search Results

Search found 8965 results on 359 pages for 'print spooler'.

Page 55/359 | < Previous Page | 51 52 53 54 55 56 57 58 59 60 61 62  | Next Page >

  • Passing list and dictionary type parameter with Python

    - by prosseek
    When I run this code def func(x, y, *w, **z): print x print y if w: print w if z: print z else: print "None" func(10,20, 1,2,3,{'k':'a'}) I get the result as follows. 10 20 (1, 2, 3, {'k': 'a'}) None But, I expected as follows, I mean the list parameters (1,2,3) matching *w, and dictionary matching **z. 10 20 (1,2,3) {'k':'a'} Q : What went wrong? How can I pass the list and dictionary as parameters? Added func(10,20, 10,20,30, k='a') seems to be working

    Read the article

  • python- scipy optimization

    - by pear
    In scipy fmin_slsqp (Sequential Least Squares Quadratic Programming), I tried reading the code 'slsqp.py' provided with the scipy package, to find what are the criteria to get the exit_modes 0? I cannot find which statements in the code produce this exit mode? Please help me 'slsqp.py' code as follows, exit_modes = { -1 : "Gradient evaluation required (g & a)", 0 : "Optimization terminated successfully.", 1 : "Function evaluation required (f & c)", 2 : "More equality constraints than independent variables", 3 : "More than 3*n iterations in LSQ subproblem", 4 : "Inequality constraints incompatible", 5 : "Singular matrix E in LSQ subproblem", 6 : "Singular matrix C in LSQ subproblem", 7 : "Rank-deficient equality constraint subproblem HFTI", 8 : "Positive directional derivative for linesearch", 9 : "Iteration limit exceeded" } def fmin_slsqp( func, x0 , eqcons=[], f_eqcons=None, ieqcons=[], f_ieqcons=None, bounds = [], fprime = None, fprime_eqcons=None, fprime_ieqcons=None, args = (), iter = 100, acc = 1.0E-6, iprint = 1, full_output = 0, epsilon = _epsilon ): # Now do a lot of function wrapping # Wrap func feval, func = wrap_function(func, args) # Wrap fprime, if provided, or approx_fprime if not if fprime: geval, fprime = wrap_function(fprime,args) else: geval, fprime = wrap_function(approx_fprime,(func,epsilon)) if f_eqcons: # Equality constraints provided via f_eqcons ceval, f_eqcons = wrap_function(f_eqcons,args) if fprime_eqcons: # Wrap fprime_eqcons geval, fprime_eqcons = wrap_function(fprime_eqcons,args) else: # Wrap approx_jacobian geval, fprime_eqcons = wrap_function(approx_jacobian, (f_eqcons,epsilon)) else: # Equality constraints provided via eqcons[] eqcons_prime = [] for i in range(len(eqcons)): eqcons_prime.append(None) if eqcons[i]: # Wrap eqcons and eqcons_prime ceval, eqcons[i] = wrap_function(eqcons[i],args) geval, eqcons_prime[i] = wrap_function(approx_fprime, (eqcons[i],epsilon)) if f_ieqcons: # Inequality constraints provided via f_ieqcons ceval, f_ieqcons = wrap_function(f_ieqcons,args) if fprime_ieqcons: # Wrap fprime_ieqcons geval, fprime_ieqcons = wrap_function(fprime_ieqcons,args) else: # Wrap approx_jacobian geval, fprime_ieqcons = wrap_function(approx_jacobian, (f_ieqcons,epsilon)) else: # Inequality constraints provided via ieqcons[] ieqcons_prime = [] for i in range(len(ieqcons)): ieqcons_prime.append(None) if ieqcons[i]: # Wrap ieqcons and ieqcons_prime ceval, ieqcons[i] = wrap_function(ieqcons[i],args) geval, ieqcons_prime[i] = wrap_function(approx_fprime, (ieqcons[i],epsilon)) # Transform x0 into an array. x = asfarray(x0).flatten() # Set the parameters that SLSQP will need # meq = The number of equality constraints if f_eqcons: meq = len(f_eqcons(x)) else: meq = len(eqcons) if f_ieqcons: mieq = len(f_ieqcons(x)) else: mieq = len(ieqcons) # m = The total number of constraints m = meq + mieq # la = The number of constraints, or 1 if there are no constraints la = array([1,m]).max() # n = The number of independent variables n = len(x) # Define the workspaces for SLSQP n1 = n+1 mineq = m - meq + n1 + n1 len_w = (3*n1+m)*(n1+1)+(n1-meq+1)*(mineq+2) + 2*mineq+(n1+mineq)*(n1-meq) \ + 2*meq + n1 +(n+1)*n/2 + 2*m + 3*n + 3*n1 + 1 len_jw = mineq w = zeros(len_w) jw = zeros(len_jw) # Decompose bounds into xl and xu if len(bounds) == 0: bounds = [(-1.0E12, 1.0E12) for i in range(n)] elif len(bounds) != n: raise IndexError, \ 'SLSQP Error: If bounds is specified, len(bounds) == len(x0)' else: for i in range(len(bounds)): if bounds[i][0] > bounds[i][1]: raise ValueError, \ 'SLSQP Error: lb > ub in bounds[' + str(i) +'] ' + str(bounds[4]) xl = array( [ b[0] for b in bounds ] ) xu = array( [ b[1] for b in bounds ] ) # Initialize the iteration counter and the mode value mode = array(0,int) acc = array(acc,float) majiter = array(iter,int) majiter_prev = 0 # Print the header if iprint >= 2 if iprint >= 2: print "%5s %5s %16s %16s" % ("NIT","FC","OBJFUN","GNORM") while 1: if mode == 0 or mode == 1: # objective and constraint evaluation requird # Compute objective function fx = func(x) # Compute the constraints if f_eqcons: c_eq = f_eqcons(x) else: c_eq = array([ eqcons[i](x) for i in range(meq) ]) if f_ieqcons: c_ieq = f_ieqcons(x) else: c_ieq = array([ ieqcons[i](x) for i in range(len(ieqcons)) ]) # Now combine c_eq and c_ieq into a single matrix if m == 0: # no constraints c = zeros([la]) else: # constraints exist if meq > 0 and mieq == 0: # only equality constraints c = c_eq if meq == 0 and mieq > 0: # only inequality constraints c = c_ieq if meq > 0 and mieq > 0: # both equality and inequality constraints exist c = append(c_eq, c_ieq) if mode == 0 or mode == -1: # gradient evaluation required # Compute the derivatives of the objective function # For some reason SLSQP wants g dimensioned to n+1 g = append(fprime(x),0.0) # Compute the normals of the constraints if fprime_eqcons: a_eq = fprime_eqcons(x) else: a_eq = zeros([meq,n]) for i in range(meq): a_eq[i] = eqcons_prime[i](x) if fprime_ieqcons: a_ieq = fprime_ieqcons(x) else: a_ieq = zeros([mieq,n]) for i in range(mieq): a_ieq[i] = ieqcons_prime[i](x) # Now combine a_eq and a_ieq into a single a matrix if m == 0: # no constraints a = zeros([la,n]) elif meq > 0 and mieq == 0: # only equality constraints a = a_eq elif meq == 0 and mieq > 0: # only inequality constraints a = a_ieq elif meq > 0 and mieq > 0: # both equality and inequality constraints exist a = vstack((a_eq,a_ieq)) a = concatenate((a,zeros([la,1])),1) # Call SLSQP slsqp(m, meq, x, xl, xu, fx, c, g, a, acc, majiter, mode, w, jw) # Print the status of the current iterate if iprint > 2 and the # major iteration has incremented if iprint >= 2 and majiter > majiter_prev: print "%5i %5i % 16.6E % 16.6E" % (majiter,feval[0], fx,linalg.norm(g)) # If exit mode is not -1 or 1, slsqp has completed if abs(mode) != 1: break majiter_prev = int(majiter) # Optimization loop complete. Print status if requested if iprint >= 1: print exit_modes[int(mode)] + " (Exit mode " + str(mode) + ')' print " Current function value:", fx print " Iterations:", majiter print " Function evaluations:", feval[0] print " Gradient evaluations:", geval[0] if not full_output: return x else: return [list(x), float(fx), int(majiter), int(mode), exit_modes[int(mode)] ]

    Read the article

  • kill -9 + disable messages (standart output) from kill command

    - by yael
    hi all I write the following script this script enable timeout of 20 second if grep not find the relevant string in the file the script working well but the output from the script is like that: ./test: line 11: 30039: Killed how to disable this message from the kill command? how to tell kill command to ignore if process not exist? THX Yael !/bin/ksh ( sleep 20 ; [[ ! -z ps -ef | grep "qsRw -m1" | awk '{print $2}' ]] && kill -9 2/dev/null ps -ef | grep "qsRw -m1" | awk '{print $2}' ; sleep 1 ) & RESULT=$! print "the proccess:"$RESULT grep -qsRw -m1 "monitohhhhhhhr" /var if [[ $? -ne 0 ]] then print "kill "$RESULT kill -9 $RESULT fi print "ENDED" ./test the proccess:30038 ./test: line 11: 30039: Killed kill 3003

    Read the article

  • How to convert raw_input() into a directory?

    - by Azeworai
    Hi everyone, I just picked up IronPython and I've been trying to get this IronPython script going but I'm stuck at trying to get a Path input from raw_input to be a directory path. The first block of code is the broken one that I'm working on. import System from System import * from System.IO import * from System.Diagnostics import * inputDirectory = raw_input("Enter Input Directory's full path [eg. c:\\vid\\]: ") print ("In: "+inputDirectory) outputDirectory = inputDirectory +"ipod\\" print ("Out: "+outputDirectory) #create the default output directory for s in DirectoryInfo(inputDirectory).GetFiles("*.avi"): print s.FullName arg = String.Format('-i "{0}" -t 1 -c 1 -o "{1}" --preset="iPod"' , s.FullName, outputDirectory + s.Name.Replace(".avi", ".mp4")) print arg proc = Process.Start("C:\\Program Files\\Handbrake\\HandBrakeCLI.exe", arg) #path to handbrake goes here proc.WaitForExit() The following code block is what I have working at the moment. import System from System import * from System.IO import * from System.Diagnostics import * for s in DirectoryInfo("F:\\Tomorrow\\").GetFiles("*.avi"): arg = String.Format('-i "{0}" -t 1 -c 1 -o "{1}" --preset="iPod"' , s.FullName, "F:\\Tomorrow\\ipod\\" + s.Name.Replace(".avi", ".mp4")) print arg proc = Process.Start("C:\\Program Files\\Handbrake\\HandBrakeCLI.exe", arg) #path to handbrake goes here proc.WaitForExit() PS: Credit for the above working code goes to Joseph at jcooney.net

    Read the article

  • How do I find out if the variable is declared in Python?

    - by golergka
    I want to use a module as a singleton referenced in other modules. It looks something like this (that's not actually a code I'm working on, but I simplified it to throw away all unrelated stuff): main.py import singleton import printer def main(): singleton.Init(1,2) printer.Print() if __name__ == '__main__': pass singleton.py variable1 = '' variable2 = '' def Init(var1, var2) variable1 = var1 variable2 = var2 printer.py import singleton def Print() print singleton.variable1 print singleton.variable2 I expect to get output 1/2, but instead get empty space. I understand that after I imported singleton to the print.py module the variables got initialized again. So I think that I must check if they were intialized before in singleton.py: if not (variable1): variable1 = '' if not (variable2) variable2 = '' But I don't know how to do that. Or there is a better way to use singleton modules in python that I'm not aware of :)

    Read the article

  • log the http response codes in the file

    - by dexter
    i have created HTTP::Request which looks like this: #!/usr/bin/perl require HTTP::Request; require LWP::UserAgent; require HTTP::Cookies; $request = HTTP::Request->new(GET => 'http://www.google.com/'); $ua = LWP::UserAgent->new; $cookie_jar = HTTP::Cookies->new(); $ua->cookie_jar($cookie_jar); $cookie_jar->set_cookie(0,'testCookie','cookieValue','/','http://www.google.com/',80,0,0,86400,0); $response = $ua->request($request); if($response->is_success){ print "sucess\n"; print $response->code; print "\n"; } else { print "fail\n"; die $response->code; print "\n"; } now, When i send Request: i want to log the http response codes in the file please help thank you

    Read the article

  • Error while trying to parse a website url using python . how to debug it ?

    - by mekasperasky
    #!/usr/bin/python import json import urllib from BeautifulSoup import BeautifulSoup from BeautifulSoup import BeautifulStoneSoup import BeautifulSoup def showsome(searchfor): query = urllib.urlencode({'q': searchfor}) url = 'http://ajax.googleapis.com/ajax/services/search/web?v=1.0&%s' % query search_response = urllib.urlopen(url) search_results = search_response.read() results = json.loads(search_results) data = results['responseData'] print 'Total results: %s' % data['cursor']['estimatedResultCount'] hits = data['results'] print 'Top %d hits:' % len(hits) for h in hits: print ' ', h['url'] resp = urllib.urlopen(h['url']) res = resp.read() soup = BeautifulSoup(res) print soup.prettify() print 'For more results, see %s' % data['cursor']['moreResultsUrl'] showsome('sachin') What is the wrong in this code ? Note all the 4 links that I am getting out of the search , I am feeding it back to extract the contents out of it , and then use BeautifulSoup to parse it . How should I go about it ?

    Read the article

  • crashing out in a while loop python

    - by Edward
    How to solve this error? i want to pass the values from get_robotxya() and get_ballxya() and use it in a loop but it seems that it will crash after awhile how do i fix this? i want to get the values whithout it crashing out of the while loop import socket import os,sys import time from threading import Thread HOST = '59.191.193.59' PORT = 5555 COORDINATES = [] def connect(): globals()['client_socket'] = socket.socket(socket.AF_INET, socket.SOCK_STREAM) client_socket.connect((HOST,PORT)) def update_coordinates(): connect() screen_width = 0 screen_height = 0 while True: try: client_socket.send("loc\n") data = client_socket.recv(8192) except: connect(); continue; globals()['COORDINATES'] = data.split() if(not(COORDINATES[-1] == "eom" and COORDINATES[0] == "start")): continue if (screen_width != int(COORDINATES[2])): screen_width = int(COORDINATES[2]) screen_height = int(COORDINATES[3]) return def get_ballxy(): update_coordinates() ballx = int(COORDINATES[8]) bally = int(COORDINATES[9]) return ballx,bally def get_robotxya(): update_coordinates() robotx = int(COORDINATES[12]) roboty = int(COORDINATES[13]) angle = int(COORDINATES[14]) return robotx,roboty,angle def print_ballxy(bx,by): print bx print by def print_robotxya(rx,ry,a): print rx print ry print a def activate(): bx,by = get_ballxy() rx,ry,a = get_robotxya() print_ballxy(bx,by) print_robotxya(rx,ry,a) Thread(target=update_coordinates).start() while True: activate() this is the error i get:

    Read the article

  • Why it's not "if" and not "else"?

    - by Roman
    I have this code: $link = mysql_connect("localhost", "ctmanager", "pswsafgcsadfgG"); if ( ! $link ) die("I cannot connect to MySQL.<br>\n"); else print "Connection is established.<br>\n"; print "a"; if ( mysql_create_db("ct", $link) ) print "AAA"; else print "BBB"; print "2"; die(); And this is the output: Connection is established. a So, I cannot understand how it's possible that neither "AAA" no "BBB" is outputted. Is it because program dies at mysql_create_db?

    Read the article

  • Python try/except: Showing the cause of the error after displaying my variables

    - by NealWalters
    I'm not even sure what the right words are to search for. I want to display parts of the error object in an except block (similar to the err object in VBScript, which has Err.Number and Err.Description). For example, I want to show the values of my variables, then show the exact error. Clearly, I am causing a divided-by-zero error below, but how can I print that fact? try: x = 0 y = 1 z = y / x z = z + 1 print "z=%d" % (z) except: print "Values at Exception: x=%d y=%d " % (x,y) print "The error was on line ..." print "The reason for the error was ..."

    Read the article

  • Is it possible to have Ant print out the classpath for a particular target? If so, how?

    - by Daryl Spitzer
    I'm trying to get a target to build that has quite a long list of <pathelement location="${xxx}"/> and <path refid="foo.class.path"/> elements in its <path id="bar.class.path"> element (in the build.xml file). I keep getting "package com.somecompany.somepackage does not exist" errors, and I'm having a hard time chasing down these packages and making sure I've synced them from our repository. I'm new to this team so I'm unfamiliar with the build, but I would prefer to figure this out myself if possible (so I don't bother the other very busy team members). I have very limited experience with Ant. I think it would save me quite a bit of time if I could have Ant print out the classpath for the target I'm trying to build.

    Read the article

  • Sending http headers with python

    - by Niklas R
    I've set up a little script that should feed a client with html. import socket sock = socket.socket() sock.bind(('', 8080)) sock.listen(5) client, adress = sock.accept() print "Incoming:", adress print client.recv(1024) print client.send("Content-Type: text/html\n\n") client.send('<html><body></body></html>') print "Answering ..." print "Finished." import os os.system("pause") But it is shown as plain text in the browser. Can you please tell what I need to do ? I just can't find something in google that helps me.. Thanks.

    Read the article

  • shell scripting: nested subshell ++

    - by jhon
    Hi guys, more than a problem, this is a request for "another way to do this" actually, if a want to use the result from a previous command I into another one, I use: R1=$("cat somefile | awk '{ print $1 }'" ) myScript -c $R1 -h123 then, a "better way"is: myScript -c $("cat somefile | awk '{ print $1 }'" ) -h123 but, what if I have to use several times the result, let's say: using several times $R1, well the 2 options: option 1 R1=$("cat somefile | awk '{ print $1}'") myScript -c $R1 -h123 -x$R1 option 2 myScript -c $("cat somefile | awk '{ print $1 }'" ) -h123 -x $("cat somefile | awk '{ print $1 }'" ) do you know another way to "store" the result of a previous command/script and use it as a argument into another command/script? thanks

    Read the article

  • numpy array C api

    - by wiso
    I have a C++ function returning a std::vector and I want to use it in python, so I'm using the C numpy api: static PyObject * py_integrate(PyObject *self, PyObject *args){ ... std::vector<double> integral; cpp_function(integral); // this change integral npy_intp size = {integral.size()}; PyObject *out = PyArray_SimpleNewFromData(1, &size, NPY_DOUBLE, &(integral[0])); return out; } when I call it from python, if I do import matplotlib.pyplot as plt a = py_integrate(parameters) print a fig = plt.figure() ax = fig.add_subplot(111) ax.plot(a) print a the first print is ok, the values are correct, but when I plot a they are not, and in particular in the second print I see very strange values like 1E-308 1E-308 ... or 0 0 0 ... as an unitialized memory. I don't understand why the first print is ok.

    Read the article

  • Does CLOS have an eql specialization dispatch on strings?

    - by mhb
    Examples of what you can do. (defmethod some-fn ((num real)) (print "an integer")) (defmethod some-fn ((num real)) (print "a real")) (defmethod some-fn ((num (eql 0))) (print "zero")) (some-fn 19323923198319) "an integer" (some-fn 19323923198319.3) "a real" (some-fn 0) "zero" It also works with a general 'string type. (defmethod some-fn ((num string)) (print "a string")) (some-fn "asrt") "a string" Not with a specific string, however (defmethod some-fn ((num (eql "A")) (print "a specifict string"))) => doesn't compile I imagine it doesn't work because eql does not work on strings in the way that would be necessary for it to work. (eql "a" "a") => nil Is there a way to do it?

    Read the article

  • Confused by this PHP Exception try..catch nesting

    - by Domenic
    Hello. I'm confused by the following code: class MyException extends Exception {} class AnotherException extends MyException {} class Foo { public function something() { print "throwing AnotherException\n"; throw new AnotherException(); } public function somethingElse() { print "throwing MyException\n"; throw new MyException(); } } $a = new Foo(); try { try { $a->something(); } catch(AnotherException $e) { print "caught AnotherException\n"; $a->somethingElse(); } catch(MyException $e) { print "caught MyException\n"; } } catch(Exception $e) { print "caught Exception\n"; } I would expect this to output: throwing AnotherException caught AnotherException throwing MyException caught MyException But instead it outputs: throwing AnotherException caught AnotherException throwing MyException caught Exception Could anyone explain why it "skips over" catch(MyException $e) ? Thanks.

    Read the article

  • Why are closures broken within exec?

    - by Devin Jeanpierre
    In Python 2.6, >>> exec "print (lambda: a)()" in dict(a=2), {} 2 >>> exec "print (lambda: a)()" in globals(), {'a': 2} Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<string>", line 1, in <module> File "<string>", line 1, in <lambda> NameError: global name 'a' is not defined >>> exec "print (lambda: a).__closure__" in globals(), {'a': 2} None I expected it to print 2 twice, and then print a tuple with a single cell. It is the same situation in 3.1. What's going on?

    Read the article

  • printing using one '\n'

    - by Alex
    I am pretty sure all of you are familiar with the concept of the Big4, and I have several stuffs to do print in each of the constructor, assignment, destructor, and copy constructor. The restriction is this: I CAN'T use more than one newline (e.g., ƒn or std::endl) in any method I can have a method called print, so I am guessing print is where I will put that precious one and only '\n', my problem is that how can the method print which prints different things on each of the element I want to print in each of the Big4? Any idea? Maybe overloading the Big4?

    Read the article

  • Python IPC, popen too slow

    - by UnableToLoad
    i need to run a subprocess (./myProgram) form python script and get output, actually i do this: import subprocess proc = subprocess.Popen('./generate_out', shell=False, stdout=subprocess.PIPE, ) while proc.poll() is None: out = proc.stdout.readline() data = doStuff(out) print(data) but is slow, sometimes pass a lot of time between the output produced by ./generate_out and the print(data), knowing that my doStuff() function is very fast, i think there is some buffer slowing down my pipe... Notes: ./generate_out, generates potentially an unlimited number of lines of finite length each. It seems that when too few chars are put in the pipe between the two processes nothing happens, then when enough is produced i get a huge print (non the expected behaviour!) sometimes i wait many seconds (10-20 and more) between generate_out print and python print) what can i do? maybe communicate() is faster? anithing else? Thank you a lot!

    Read the article

  • Python interpreter invocation with "-c" and indentation issues

    - by alexander
    I'm trying to invoke Python using the "-c" argument to allow me to run some arbitrary python code easily, like this: python.exe -c "for idx in range(10): print idx" Now this code works fine, from within my batch file, however, I'm running into problems when I want to do anything more than this. Consider the following Python code: foo = 'bar' for idx in range(10): print idx this would then give you 0-9 on the stdout. However, if I collapse this into a single line, using semicolons as delimiters, to get the following: foo = 'bar';for idx in range(10): print idx and try to run it using python.exe -c it get a SyntaxError raised: C:\Python>python.exe -c "foo = 'bar';for idx in range(10): print idx" File "<string>", line 1 foo = 'bar';for idx in range(10): print idx ^ SyntaxError: invalid syntax Anyone know how I can actually use this without switching to a separate .py file?

    Read the article

  • Regular expressions in python unicode

    - by Remy
    I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

    Read the article

  • Java static method parameters

    - by Blitzkr1eg
    Why does the following code return 100 100 1 1 1 and not 100 1 1 1 1 ? public class Hotel { private int roomNr; public Hotel(int roomNr) { this.roomNr = roomNr; } public int getRoomNr() { return this.roomNr; } static Hotel doStuff(Hotel hotel) { hotel = new Hotel(1); return hotel; } public static void main(String args[]) { Hotel h1 = new Hotel(100); System.out.print(h1.getRoomNr() + " "); Hotel h2 = doStuff(h1); System.out.print(h1.getRoomNr() + " "); System.out.print(h2.getRoomNr() + " "); h1 = doStuff(h2); System.out.print(h1.getRoomNr() + " "); System.out.print(h2.getRoomNr() + " "); } } Why does it appear to pass Hotel by-value to doStuff() ?

    Read the article

  • HTML javascript form submitted when image input button

    - by DreamU
    I have a form that contains this single input field, which is nothing more than a button to Print the current web page: <div align="center"> <input type="image" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> After the printing, the page re-submits itself (to itself). Why does it do this and can I stop it? If I just change the type to "input", this code does not re-submit itself after printing: <div align="center"> <input type="input" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> Unfortunately, our style conventions require me to use that button image rather than the standard input button.

    Read the article

  • Perl, Array called by scalar doesn't work in foreach loop.

    - by foxhop
    This code outputs the scalars in the row array properly: $line = "This is my favorite test"; @row = split(/ /, $line); print $row[0]; print $row[1]; The same code inside a foreach loop doesn't print any scalar values: foreach $line (@lines){ @row = split(/ /, $line); print $row[0]; print $row[1]; } What could cause this to happen? I am new to perl coming from python. I need to learn perl for my new position.

    Read the article

  • Adding a decorator that converts strings to lowercase in Python

    - by user2905382
    So I am new to learning decorators and I have gone through countless tutorials and while I understand and can mostly follow all of the examples, I think the best way to learn, would be to implement a decorator myself. So I am going to use this example below. I realize a decorator is not at all necessary to do this, but for the sake of learning, I would like to add a decorator that filters the strings like dog name and breed and turns them into lowercase. Any ideas or pointers in the right direction would be appreciated. class Dogs: totalDogs = 0 dogList=[] def __init__(self, breed, color, age): self.breed=breed self.color=color self.age=age Dogs.dogList.append(self.breed) Dogs.totalDogs += 1 def displayDogs(self): print "breed: ", self.breed print "color: ",self.color print "age: ",self.age print "list of breeds:", Dogs.dogList print "total dogs: ", Dogs.totalDogs def somedecorator(*args): #now what terrier=Dogs("TeRrIer", "white", 5) terrier.displayDogs() retriever=Dogs("goldenRETRIEVER", "brown", 10) retriever.displayDogs()

    Read the article

< Previous Page | 51 52 53 54 55 56 57 58 59 60 61 62  | Next Page >