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  • Stepping thru a plist to get at info

    - by cannyboy
    If I've got a plist set up like this Key Type Value Root Array Item 0 Dictionary -Title String Part One -Description String Welcome to part one. Have fun Item 1 Dictionary -Title String Part Two -Description String Welcome to part two. Fun too. Item 2 Dictionary -Title String Part Three -Description String Welcome to part three. It's free Item 3 Dictionary -Title String Part Four -Description String It's part four. No more How would I step thru to put all the titles in one array, and all the descriptions into another?

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  • How I can locate element depend on it value?

    - by Nikolay Kulakov
    I have some table: Title 1 | Title 2 | Title 3 | -------------------------------------------------- string value 1 | string value 2 | string value 3 | -------------------------------------------------- string value 4 | string value 5 | string value 6 | and some step: "And click on its < name", where < name can be anything from first column. So, how I can found needed element and click on its? Table code <div id="grid" class="k-grid k-widget" data-role="grid" tabindex="0" style=""> <div class="k-grid-header" style="padding-right: 17px;"> <div class="k-grid-header-wrap"> <table cellspacing="0"> <colgroup> <col style="width: 30px;"> <col style="width: 300px;"> <col> <col style="width: 200px;"> </colgroup> <thead> <tr> <th class="k-header" data-title="ID" data-field="id">ID</th> <th class="k-header" data-title="????????????" data-field="name" data-role="sortable" data-dir="asc"> <a class="k-link" href="#"> 2nd part ???????????? <span class="k-icon k-arrow-up"></span> </a> </th> <th class="k-header" data-title="????????" data-field="description">????????</th> <th class="k-header" data-field="undefined" data-role="sortable"> </tr> </thead> </table> </div> </div>

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  • Consing lists with user-defined type in Haskell

    - by user1319603
    I have this type I defined myself: data Item = Book String String String Int -- Title, Author, Year, Qty | Movie String String String Int -- Title, Director, Year, Qty | CD String String String Int deriving Show -- Title, Artist, Year, Qty I've created an empty list all_Items = [] With the following function I am trying to insert a new book of type Item (Book) into the all_Items addBook all_Items = do putStrLn "Enter the title of the book" tit <- getLine putStrLn "Enter the author of the book" aut <- getLine putStrLn "Enter the year this book was published" yr <- getLine putStrLn "Enter quantity of copies for this item in the inventory" qty <- getLine Book tit aut yr (read qty::Int):all_Items return(all_Items) I however am receiving this error: Couldn't match expected type `IO a0' with actual type `[a1]' The error points to the line where I am using the consing operator to add the new book to the list. I can gather that it is a type error but I can't figure out what it is that I am doing wrong and how to fix it. Thanks in Advance!

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  • Looping through an List to select an Element in Selenium

    - by ChrisMcLellan
    I'm attempting to write a Page Class for Links within the Header of the website I'm testing. I have the following link structure below <ul> <li><a href="/" title="Home">Home</a></li> <li><a href="/AboutUs" title="About Us">About Us</a> </li> <li><a href="/Account" title="Account">Account</a></li> <li><a href="/Account/Orders" title="Orders">Orders</a></li> <li><a href="/AdministrationPortal" title="Administration Portal">Administration Portal</a></li> </ul> What I want to do is store these into a List, then when a user select one of the links, it will take then to the page they should go to. I have started with the following code below List<IWebElement> headerElements = new List<IWebElement>(); headerElements.Add(WebDriver.FindElement(By.LinkText("Home"))); headerElements.Add(WebDriver.FindElement(By.LinkText("About Us"))); headerElements.Add(WebDriver.FindElement(By.LinkText("Account"))); headerElements.Add(WebDriver.FindElement(By.LinkText("Orders"))); headerElements.Add(WebDriver.FindElement(By.LinkText("Administration Portal"))); headerElements.Add(WebDriver.FindElement(By.LinkText("Log in / Register"))); headerElements.Add(WebDriver.FindElement(By.LinkText("Log off"))); I was thinking for using a for loop to do this, would this be the best way. I'm trying to avoid writting methods like the one below for each link public void SelectCreateNewReferralLink() { var selectAboutUsLink = ( new WebDriverWait(WebDriver, new TimeSpan(50))).Until (ExpectedConditions.ElementExists(By.CssSelector("#main > a:nth-of-type(1)"))); selectCreateNewReferralLink.Click(); } I'm using C#, with WebDriver attempting to write this Any Help would be great Thanks Chris

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  • Only show non blank attributes for a model in views in Rails

    - by Senthil
    Say I've a user model and there are bunch of user info, like email, birthdate, location, telephone number etc. What's the simplest way of hiding the attributes that are blank? I've doing something like <% if blog.title.empty? -%> <p>Body: <%=h blog.body %></p> <p>Comments: <%=h blog.comments %></p> <% elsif blog.body.empty? %> <p>Title: <%=h blog.title %></p> <p>Comments: <%=h blog.comments %></p> <% else -%> <p>Title: <%=h blog.title %></p> <p>Body: <%=h blog.body %></p> <% end -%> Clearly that is one ugly child. Other than using partials to render, is there a trick to only show non blank fields? I've been trying to write a helpher method to make the view cleaner, but that's even more ugly. Any help is appreciated.

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  • Regarding some Update Stored procedure

    - by Serenity
    I have two Tables as follows:- Table1:- ------------------------------------- PageID|Content|TitleID(FK)|LanguageID ------------------------------------- 1 |abc |101 |1 2 |xyz |102 |1 -------------------------------------- Table2:- ------------------------- TitleID|Title |LanguageID ------------------------- 101 |Title1|1 102 |Title2|1 ------------------------ I don't want to add duplicates in my Table1(Content Table). Like..there can be no two Pages with the same Title. What check do I need to add in my Insert/Update Stored Procedure ? How do I make sure duplicates are never added. I have tried as follows:- CREATE PROC InsertUpdatePageContent ( @PageID int, @Content nvarchar(2000), @TitleID int ) AS BEGIN IF(@PageID=-1) BEGIN IF(NOT EXISTS(SELECT TitleID FROM Table1 WHERE LANGUAGEID=@LANGUAGEID)) BEGIN INSERT INTO Table1(Content,TitleID) VALUES(@Content,@TitleID) END END ELSE BEGIN IF(NOT EXISTS(SELECT TitleID FROM Table1 WHERE LANGUAGEID=@LANGUAGEID)) BEGIN UPDATE Table1 SET Content=@Content,TitleID=@TitleID WHERE PAGEID=@PAGEID END END END Now what is happening is that it is inserting new records alright and won't allow duplicates to be added but when I update its giving me problem. On my aspx Page I have a drop down list control that is bound to DataSource that returns Table 2(Title Table) and I have a text box in which user types Page's content to be stored. When I update, like lets say I have a row in my Table 1 as shown above with PageID=1. Now when I am updating this row, like I didn't change the Title from the drop down and only changed Content in the text box, its not updating the record ..and when Stored procedure's Update Query does not execute it displays a Label that says "Page with this title exists already." So whenever I am updating an existing record that label is displayed on screen.How do I change that IF condition in my Update Stored procedure?? EDIT:- @gbn :: Will that IF condition work in case of update? I mean lets say I am updating the Page with TitleID=1, I changed its content, then when I update, it's gonna execute that IF condition and it still won't update coz TitleID=1 already exits!It will only update if TitleID=1 is not there in Table1. Isn't it? Guess I am getting confused. Please answer.Thanks.

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  • Returning more than one result

    - by Hairr
    I'm using the following code: def recentchanges(bot=False,rclimit=20): """ @description: Gets the last 20 pages edited on the recent changes and who the user who edited it """ recent_changes_data = { 'action':'query', 'list':'recentchanges', 'rcprop':'user|title', 'rclimit':rclimit, 'format':'json' } if bot is False: recent_changes_data['rcshow'] = '!bot' else: pass data = urllib.urlencode(recent_changes_data) response = opener.open('http://runescape.wikia.com/api.php',data) content = json.load(response) pages = tuple(content['query']['recentchanges']) for title in pages: return title['title'] When I do recentchanges() I only get one result. If I print it though, all the pages are printed. Am I just misunderstanding or is this something relating to python? Also, opener is: cj = CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj))

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  • How to turn dynamic URL into static URL

    - by Rafael Carvalho
    I am developing a website using PHP and Apache. I wanna turn my URLs from www.example.com/book.php?book=title into something like this, if it is possible of course: www.example.com/book/title Notice that the title of the books are unique and cannot be repeated. I`ve read about this, but none of the posts were clear enough for a beginner like me. Do you guys know any tutorial that explains that? Thanks.

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  • JSP template inheritance

    - by Ryan
    Coming from a background in Django, I often use "template inheritance", where multiple templates inherit from a common base. Is there an easy way to do this in JSP? If not, is there an alternative to JSP that does this (besides Django on Jython that is :) base template <html> <body> {% block content %} {% endblock %} </body> <html> basic content {% extends "base template" %} {% block content %} <h1>{{ content.title }} <-- Fills in a variable</h1> {{ content.body }} <-- Fills in another variable {% endblock %} Will render as follows (assuming that conten.title is "Insert Title Here", and content.body is "Insert Body Here") <html> <body> <h1>Insert title Here <-- Fills in a variable</h1> Insert Body Here <-- Fills in another variable </body> <html>

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  • custom rss feed suddenly does not work anymore

    - by krike
    I just don't understand what's happening, I haven't change anything to the site for a few months but now suddenly the rss feed doesn't work anymore. I create a php file with the following code: header('Content-type: text/xml'); include("config/config.inc.php"); $result = mysqli_query($link, "SELECT * FROM tutorials ORDER BY tutorial_id DESC LIMIT 50"); ?> <rss version="2.0"> <channel> <title>CMS tutorial site</title> <description>Bringing you the best CMS tutorials from the web</description> <link>http://cmstutorials.org</link> <?php while($row = mysqli_fetch_object($result)) { $user = mysqli_fetch_object(mysqli_query($link, "SELECT * FROM user_extra WHERE userid=".$row->user_id."")); ?> <item> <title><?php echo $row->title; ?></title> <author><?php echo $user->username; ?></author> <description><?php echo $row->description; ?></description> <pubDate><?php echo $row->date; ?></pubDate> <link>http://cmstutorials.org/view_tutorial.php?tutorial_id=<?php echo $row->tutorial_id; ?></link> </item> <?php } ?> </channel> </rss> I checked the query by executing it in phpmyadmin and it works, doesn't give any error. When I delete the header content type and the rss tag it will print out each line from the query but the feed won't display anything this is the link of the feed http://cmstutorials.org/rss (or http://cmstutorials.org/rss.php)

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  • How to print element values when iterating through XML document in PHP

    - by pharma_joe
    I am iterating through the results of a service call to yahoo news thus: //Send service request if (!$yahooResults = file_get_contents($yahooRequest)) { echo 'Error processing service request'; } //Read result into xml document $yahooResultXml = new DOMDocument('1.0', 'UTF-8'); $yahooResultXml-loadXML($yahooResults); //Build page include_once('components/pageHeader.php'); echo 'Search Results'; //echo $yahooResultXml-saveHTML(); //Iterate over each Result node $stories = $yahooResultXml-getElementsByTagName('Result'); foreach ($stories as $story) { //Title //Summary //Url //Source //Language //Publish Date //Modification Date } include_once('components/pageFooter.php'); Each Title is in a Title node within a Result Node. I cannot figure out how to simply echo the content of the Title node!

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  • How to check if something is stored in CoreData

    - by Terrel Gibson
    Hi I want to be able to tore some information in core data and but i am unsure of how to check if the file was saved properly. I tried using NSLog but it returns null when its called. I have a dictionary which has a uniqueID and a title which I want to save. I pass this in along with the context of the database. I then sort the database to check if it has any duplicates or not, if not then I add the file. +(VacationPhoto*) photoWithFlickrInfo: (NSDictionary*) flickrInfo inManagedObjectContext: (NSManagedObjectContext*) context{ //returns the dictionary NSLog(@"Photo To Store =%@", flickrInfo); VacationPhoto * photo = nil; NSFetchRequest *request = [NSFetchRequest fetchRequestWithEntityName:@"VacationPhoto"]; request.predicate = [NSPredicate predicateWithFormat:@"uniqueID = %@", [flickrInfo objectForKey:FLICKR_PHOTO_ID]]; NSSortDescriptor * descriptor = [NSSortDescriptor sortDescriptorWithKey:@"title" ascending:YES]; request.sortDescriptors = [NSArray arrayWithObject:descriptor]; NSError *error = nil; NSArray *matches = [context executeFetchRequest:request error:&error]; if (!matches || [matches count] > 1) { // handle error } else if ( [matches count] == 0){ photo.title = [flickrInfo objectForKey:FLICKR_PHOTO_TITLE]; //Returns NULL when called NSLog(@"title = %@", photo.title); photo.uniqueID = [flickrInfo objectForKey:FLICKR_PHOTO_ID]; //Returns NULL when called NSLog(@"ID = %@", photo.uniqueID); } else { //If photo already exists this is called photo = [matches lastObject]; } return photo; }

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  • how to remove repeated record's from results linq to sql

    - by Sadegh
    hi, i want to remove repeated record's from results but distinct don't do this for me! why??? var results = (from words in _Xplorium.Words join wordFiles in _Xplorium.WordFiles on words.WordId equals wordFiles.WordId join files in _Xplorium.Files on wordFiles.FileId equals files.FileId join urls in _Xplorium.Urls on files.UrlId equals urls.UrlId where files.Title.Contains(query) || files.Description.Contains(query) orderby wordFiles.Count descending select new SearchResultItem() { Title = files.Title, Url = urls.Address, Count = wordFiles.Count, CrawledOn = files.CrawledOn, Description = files.Description, Lenght = files.Lenght, UniqueKey = words.WordId + "-" + files.FileId + "-" + urls.UrlId }).Distinct();

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  • Rails belongs_to issue in the views

    - by Jacobo Tibaquira
    Hi, Im having problems with an association in rails: Currently I have Post and User models, and the relationship is set this way: class User < ActiveRecord::Base attr_accessible :username, :name, :lastname has_many :posts end class Post < ActiveRecord::Base attr_accessible :title, :body belongs_to :user end However, in my app/views/posts/index.html.haml when Im trying to access the username for the post I get this error: undefined method `name' for nil:NilClass This is my view: - title "Posts" %table %tr %th Title %th Body %th Author - for post in @posts %tr %td= h post.title %td= h post.body %td= h post.user.name %td= link_to 'Show', post %td= link_to 'Edit', edit_post_path(post) %td= link_to 'Destroy', post, :confirm => 'Are you sure?', :method => :delete %p= link_to "New Post", new_post_path Any thoughts of what Im doing wrong will be appretiated

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  • Parsing XML wont display all items.

    - by Nauman A
    I have this code but the toast wont display any message what is wrong with my code.. I can get the value from link, linknext but title wont bring out any value. ( I am not very bright with writing code so please suggest anything you may feel like. final Button button = (Button) findViewById(R.id.Button01); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click try { URL url = new URL( "http://somelink.com=" + Link.setFirst_link); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(new InputSource(url.openStream())); doc.getDocumentElement().normalize(); NodeList nodeList = doc.getElementsByTagName("item"); /** Assign textview array lenght by arraylist size */ for (int i = 0; i < nodeList.getLength(); i++) { Node node = nodeList.item(i); Element fstElmnt = (Element) node; NodeList nameList = fstElmnt.getElementsByTagName("link"); Element nameElement = (Element) nameList.item(0); nameList = nameElement.getChildNodes(); String img = (((Node) nameList.item(0)).getNodeValue()); NodeList websiteList = fstElmnt.getElementsByTagName("linknext"); Element websiteElement = (Element) websiteList.item(0); websiteList = websiteElement.getChildNodes(); String nextlink = (((Node) websiteList.item(0)).getNodeValue()); Link.setFirst_link = nextlink; Drawable drawable = LoadImageFromWebOperations(img); imgView.setImageDrawable(drawable); NodeList titleList = fstElmnt.getElementsByTagName("title"); Element titleElement = (Element) titleList.item(0); websiteList = titleElement.getChildNodes(); String title = (((Node) titleList.item(0)).getNodeValue()); Context context = getApplicationContext(); CharSequence text = title; int duration = Toast.LENGTH_SHORT; Toast toast = Toast.makeText(context, text, duration); toast.show(); } } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }); /** Set the layout view to display */ } Here is the xml file <?xml version="1.0"?> <maintag> <item> <link>http://image.com/357769.jpg?40</link> <linknext>http://www.image.com</linknext> <title>imagename</title> </item> </maintag>

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  • jquery child element as trigger

    - by Dan w
    When "forum-title" is clicked, I want "subtopic-frame" within the parent "forum-topics-head" to expand. There are multiple "forum-topics-head" (with all associated children) on this page. The way I have it now, the "forum-topics-head" is the trigger, but I want the "forum-title" to be the trigger. html: <div class="forum-topic-head"> <div class="forum-title">Forum Title</div> <div class="subtopic-frame"> subtopic 1 subtopic 2 </div> </div>

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  • Generating 8000 text files from xml files

    - by Ray
    Hi all, i need to generate the same number of text files as the xml files i have. Within the text files, i need the title and maybe some other tags of it. I can generate text files with the elements i wanted but not all xml files can be generated. Only some of them are generated. Something might be wrong with my parser so help out please thanks. This is my code. Please have a look and give me suggestions. Thanks in advance. import java.io.File; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import org.w3c.dom.*; import java.io.*; public class AccessingXmlFile1 { public static void main(String argv[]) { try { //File file = new File("C:\\MyFile.xml"); // create a file that is really a directory File aDirectory = new File("C:/Documents and Settings/I2R/Desktop/test"); // get a listing of all files in the directory String[] filesInDir = aDirectory.list(); System.out.println(""+filesInDir.length); // sort the list of files (optional) // Arrays.sort(filesInDir); //////////////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////////////// // have everything i need, just print it now for ( int a=0; a<filesInDir.length; a++ ) { String xmlFile = filesInDir[a]; String newLine = System.getProperty("line.separator"); File file = new File(xmlFile); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document document = db.parse(file); document.getDocumentElement().normalize(); //System.out.println("Root element " + document.getDocumentElement().getNodeName()); NodeList node = document.getElementsByTagName("metadata"); System.out.println("Information of Xml File"); System.out.println(xmlFile.substring(0, xmlFile.length() - 4)); //////////////////////////////////////////////////////////////////////////////////// String titleStoreText = ""; String descriptionStoreText = ""; String collectionStoreText = ""; String textToWrite = ""; //////////////////////////////////////////////////////////////////////////////////// for (int i = 0; i < node.getLength(); i++) { Node firstNode = node.item(i); if (firstNode.getNodeType() == Node.ELEMENT_NODE) { Element element = (Element) firstNode; NodeList titleElementList = element.getElementsByTagName("title"); Element titleElement = (Element) titleElementList.item(0); NodeList title = titleElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(titleElement == null) titleStoreText = " There is no title for this file."+ newLine; else titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue() + newLine; //titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Title : " + titleStoreText); NodeList collectionElementList = element.getElementsByTagName("collection"); Element collectionElement = (Element) collectionElementList.item(0); NodeList collection = collectionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(collectionElement == null) collectionStoreText = " There is no collection for this file."+ newLine; else collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue() + newLine; //collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Collection : " + collectionStoreText); NodeList descriptionElementList = element.getElementsByTagName("description"); Element descriptionElement = (Element) descriptionElementList.item(0); NodeList description = descriptionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(descriptionElement == null) descriptionStoreText = " There is no description for this file."+ newLine; else descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Description : " + descriptionStoreText); //////////////////////////////////////////////////////////////////////////////////// textToWrite = "=====Title=====" + newLine + titleStoreText + newLine + "=====Collection=====" + newLine + collectionStoreText + newLine + "=====Description=====" + newLine + descriptionStoreText;// + newLine + "=====Subject=====" + newLine + subjectStoreText; //////////////////////////////////////////////////////////////////////////////////// } } ///////////////////////////////////////////write to file part is here///////////////////////////////////////// Writer output = null; File file2 = new File(xmlFile.substring(0, xmlFile.length() - 4)+".txt"); output = new BufferedWriter(new FileWriter(file2)); output.write(textToWrite); output.close(); System.out.println("Your file has been written"); //////////////////////////////////////////////////////////////////////////////////// } } catch (Exception e) { e.printStackTrace(); } } }

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  • Json to treeview (<ul>)

    - by Pieter
    Hi I get the following data back from my WCF Data Service (I cut out the metadata) { "d" : [ {"CodeId": 6, "Title": "A Child Sub Item", "Parent":}, {"CodeId": 5, "Title": "Another Root Item", "Parent": -1}, {"CodeId": 4, "Title": "Child Item", "Parent": 2}, {"CodeId": 2, "Title": "Root Item", "Parent": -1} ] } I am trying to get this into a <ul> style tree with Parent = -1 as root and then the rest as sub items of their parent id's. Can anyone help me please, preferably in jQuery? I will use this in jstree if someone knows of a better way to do this. Thanks

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  • Styling an Input Field

    - by John
    Hello When I try to alter the CSS for the input field named "title" below, which is classed by "submissionfield", the position changes, but the height, length, and font of the field do not change. How could I make the height of the input field "title" 22 px, the length 550 px, and the font Times New Roman? The CSS below does not do it. Thanks in advance, John echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; The CSS: .submissiontitle { position:absolute; width:100px; left:30px; top:200px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .submissionfield { position:absolute; width:550px; left:50px; top:230px; text-align: left; margin-bottom:3px; padding:0px; font-family: "Times New Roman", Times, serif; font-size: 22px; color:#000000; } .urltitle { position:absolute; width:250px; left:30px; top:300px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .urlfield { position:absolute; width:550px; left:30px; top:330px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submissionbutton { position:absolute; width:250px; left:30px; top:380px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submittitle { position:absolute; width:250px; left:30px; top:150px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; }

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  • Getting started with workflows in sharepoint 2010

    - by Thomas Stock
    Hi, I'm a beginning sharepoint developer asked to implement the following scenario in sharepoint 2010. We're a bit lost on the best approach to get started.. I'm really struggling to find the best practise solution. This is the flow: A user can make a request with a title and a description. A mail gets sent to the representative with a link to a form. A representative can approve or reject the request. If approved: A mail gets sent to Board with a link to form If rejected: A mail gets sent to the user with the message that it has been rejected. when the request was approved by the representative, the board can approve or reject the request. A mail gets sent to the user and the representative with the descision of the board. So the list has the following fields: Request title Request description Representative approval Representative description Board approval Board description The user should see the following form: Request title (editable) Request description (editable) The representative should see the following form: Request title (read-only) Request description (read-only) Representative approval (editable) Representative description (editable) The Board should see the following form: Request title (read-only) Request description (read-only) Representative approval (read-only) Representative description (read-only) Board approval (editable) Board description (editable) My questions: What tool is most appropriate for making the forms? Infopath? SPD? VS2010? How do I handle rights to make sure only the board can access the board edit form? What kind of workflow do I use? When do I start the workflow(s)? What do I use to develop the workflow(s)? How do I handle rights when showing the listview with all requests? How can I build the links in the mails sent to the different groups. Thanks in advance for any advice.

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  • iphone how to customize UITableViewCell cell.textlabel and cell.detailtextlabel programmatically

    - by Prerak
    Hi! In my iPhone App In table view cell I want to dispaly one main title and 5 subtitlessubtitles suppose item1 as main title and item2 , item3 , item4 , item5 and item6 as subtitles, for that i have saperate two arrays for passing the values in table view cell one for cell.textLabel.text= second for cell.detailTextLabel.text now I want the flexibility to make item2 as maintitle and want to add item1 to subtitle How can I set title and subtitle programmatically from single array? and any of them as Please Help and Suggest, Thank You.

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