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  • Utility App with Navigation Controller and Table View on FlipSide.

    - by wdt
    Hi All. I am relatively new to the whole MVC way of looking at things. I have an application that is based on the "Utility" Application template. Everything in the MainView and FlipsideView is working great but now I need to add a TableView and Navigation Controller to the flipside. Without the navigation bar being on the MainView. So only once the user has tapped the info light button will the nav bar display on the flipside with a table view. I have been able to impliment the Table View on the side and populate it with data from an array. I am now struggling to link in a navigation controller so that the tableview can become interactive. When I place the nav bar code into the app delegate it appears on the MainView and not the flipside view. Where do I place the navigation bar code so that it will display on the flipsideview. I cannt seem to get the code in the right place. Also I am not sure I have the right code, do I put the UINavigationController code in the FlipSideViewController.m ? I am not grasping the concept of the naivgation controller fully I think . . . Here is the code to bring up the FlipView - (IBAction)showInfo { TableViewController *controller = [[TableViewController alloc] initWithNibName:@"TableViewController" bundle:nil]; controller.delegate = self; controller.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:controller animated:YES]; [controller release]; } Now I need to get the TableViewController to have a navigation controller and a table view Thanks in advance.

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  • Jquery show div on hover then when user hovers out of div hide it help?

    - by user342391
    I have a menu and when I hover one of the links a div shows. I want the user to be able to hover over this div but when the user hovers out of the div (mouseout i think its called) I want it to hide. Imagine a dropdown menu in css, the user hovers over the link and the sub nav is shown, when the user hovers out or away from the link and sub nav the sub nav dissapears. How can this be done with jquery??? this is what I have: $(document).ready(function(){ //when user hovers over plans the mainnavbottom is shown $(".plans").hover( function() { $(".mainnavbottom").show("fast"); }, function(){ $(".mainnavbottom").mouseout.hide("slow"); }); });

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  • Processing a method after the view has loaded..

    - by Susanth
    Hi ! I have implemented a subview which is supposed to load immediately when I click a button in the parent view. After loading the subview(which is basically holding an activityindicator), the program is supposed to process a method(which gets data from a server, so takes time) in it. However, I am unable to do it. What happens now is, when I click the button on the parent view, it processes the method first and only after that does the subview load on screen. Why is this so? Is there any specific functions I could use to make my method load only after the view has loaded?

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  • Prev and next button

    - by daniel
    My website has previous and next buttons. When the page loads id like the previous button to be invisible.(on the first panel) After the user clicks the next button (to go to 2nd panel), id like the previous button to appear. Is there some javascript that will do this?

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  • Is it possible to integrate Google Maps with the directions and the Transit layer into an iPhone app

    - by t4v
    Sorry if this question is obvious for some of you. I know we can link to the existing Goggle Maps app, but I would like to have an app that does not exit and provides the direction within. I intend using GTFS for public transit. On the other hand, would it be possible to plot a line inside the iPhone app the results as returned by Google Transit? (say, I send it the arrival and departure addresses) Thank you so much!

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  • Newbie database index question

    - by RenderIn
    I have a table with multiple indexes, several of which duplicate the same columns: Index 1 columns: X, B, C, D Index 2 columns: Y, B, C, D Index 3 columns: Z, B, C, D I'm not very knowledgeable on indexing in practice, so I'm wondering if somebody can explain why X, Y and Z were paired with these same columns. B is an effective date. C is a semi-unique key ID for this table for a specific effective date B. D is a sequence that identifies the priority of this record for the identifier C. Why not just create 6 indexes, one for each X, Y, Z, B, C, D? I want to add an index to another column T, but in some contexts I'll only be querying on T alone while in others I will also be specifying the B, C and D columns... so should I create just one index like above or should I create one for T and one for (T, B, C, D)? I've not had as much luck as expected when googling for comprehensive coverage of indexing. Any resources where I can get a through explanation and lots of examples of B-tree indexing?

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  • Out of Core Implementation of a Quadtree

    - by Nima
    Hi, I am trying to build a Quadtree data structure(or let's just say a tree) on the secondary memory(Hard Disk). I have a C++ program to do so and I use fopen to create the files. Also, I am using tesseral coding to store each cell in a file named with its corresponding code to store it on the disk in one directory. The problem is that after creating about 1,100 files, fopen just returns NULL and stops creating new files. I can create further files manually in that directory, but using C++ it can not create any further files. I know about max limit of inode on ext3 filesystem which is (from Wikipedia) 32,000 but mine is way less than that, also note that I can create files manually on the disk; just not through fopen. Also, I really appreciate any idea regarding the best way to store a very dynamic quadtree on disk(I need the nodes to be in separate files and the quadtree might have a depth of 50). Using nested directories is one idea, but I think it will slow down the performance because of following the links on the filesystem to access the file. Thanks, Nima

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  • Installing sfJqueryTreeDoctrineManagerPlugin to Symfony 1.4

    - by Christine Q.
    I have faced serious difficulties while installing sfJqueryTreeDoctrineManagerPlugin to Symfony 1.4 w/ Doctrine ORM. The installation directly from the server did not work out like with previous plugins that I have installed: C:\pathsymfony plugin:install sfJqueryTreeDoctrineManagerPlugin plugin installing plugin "sfJqueryTreeDoctrineManagerPlugin" No release available for plugin "sfJqueryTreeDoctrineManagerPlugin" This is why I needed to install the plugin by downloading the tgz-archive and install it manually like this: C:\pathsymfony plugin:install "C:\path\to\downloads\sfJqueryTreeDoctrineManagerPlugin-1.2.4.tgz" plugin installing plugin "C:\path\to\downloads\sfJqueryTreeDoctrineManagerPlugin-1.2.4.tgz" sfSymfonyPluginManager Installing web data for plugin I guess everything should be fine this far? After that I edited \apps\admin\config\settings.yml like instructed in the plugins readme file. all: .settings: enabled_modules: [default, sfJqueryTreeDoctrineManager] I also checked that the plugin was enabled in \config\ProjectConfiguration.class.php like this: $this->enablePlugins(array( // other plugins, 'sfJqueryTreeDoctrineManagerPlugin' )); I published assets and cleared cache: C:\pathsymfony plugin:publish-assets >> plugin Configuring plugin - sfJqueryTreeDoctrineManagerPlugin C:\pathsymfony cc Finally I added the required helper to the newly created apps\admin\modules\category\templates\indexSuccess.php <?php use_helper("sfJqueryTreeDoctrine"); echo get_nested_set_manager("Category", "name"); When loading the page I unfortunately get the following error: 500 | Internal Server Error | InvalidArgumentException Unable to load "sfJqueryTreeDoctrineHelper.php" helper in: SF_ROOT_DIR\apps\admin\modules/businessunitgroup/lib/helper, SF_ROOT_DIR\apps\admin\lib/helper, SF_ROOT_DIR\lib/helper, SF_SYMFONY_LIB_DIR/helper. The file sfJqueryTreeDoctrineHelper.php exists indeed but not in any previously mentioned folder. The file can only be found in the folder \plugins\sfJqueryTreeDoctrineManagerPlugin\lib\helper. I guess that Symfony doesn't look to that folder while finding helpers? I have tried to move the helper file to one of the previously mentioned folders. As expected, that changes the error. Now I get: 500 | Internal Server Error | sfConfigurationException The component does not exist: "sfJqueryTreeDoctrineManager", "manager". Unfortunately I can't figure out how should I be able to retrieve the "missing" component from the correct folder. I would be very grateful for any advice to help me forward. By the way, I am aware that there are other nested-set / tree plugins available for Symfony (like sfDoctrineTreePlugin and caPropelTreePlugin) but unluckily those are either uncompatible or too limited for my needs.

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  • Generic unit test scheduling

    - by Raphink
    Hello, I'm (re)writing a program that does generic unit test scheduling. The current program is a mono-threaded Perl program, but I'm willing to modularize it and parallelize the tests. I'm also considering rewriting it in Python. Here is what I need to do: I have a list of tests, with the following attributes: uri: a URI to test (could be HTTP/HTTPS/SSH/local) ; depends: an associative array of tests/values that this test depends on ; join: a list of DB joints to be added when selecting items to process in this test ; depends_db: additional conditions to add to the DB request when selecting items to process in this test. The program builds a dependency tree, beginning with the tests that have no dependencies ; for each test: a list of items is selected from the database using the conditions (results of depending tests, joints and depends_db) ; the list of items is sent to the URI (using POST or stdin) ; the result is retrived as a YAML file listing the state and comments for the test for each tested item ; the results are stored in the DB ; the test returns, allowing depending tests to be performed. the program generates reports (CSV, DB, graphviz) of the performed tests. The primary use of this program currently is to test a fleet of machines against services such as backup, DNS, etc. The tests can then be: - backup: hosted on the backup machine(s), called through HTTP, checks if the machines' backup went well ; - DNS: hosted on the local machine, called via stdin, checks if the machines' fqdn have a valid DNS entry. Does such a tool/module already exist? What would be the best implementation to achieve this (using Perl or Python)?

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  • Syncing two separate structures to the same master data

    - by Mike Burton
    I've got multiple structures to maintain in my application. All link to the same records, and one of them could be considered the "master" in that it reflects actual relationships held in files on disk. The other structures are used to "call out" elements of the main design for purchase and work orders. I'm struggling to come up with a pattern that deals appropriately with changes to the master data. As an example, the following trees might refer to the same data: A |_ B |_ C |_ D |_ E |_ B |_ C |_ D A |_ B E C |_ D A |_ B C D E These secondary structures follow internal rules, but their overall structure is usually user-determined. In all cases (including the master), any element can be used in multiple locations and in multiple trees. When I add a child to any element in the tree, I want to either automatically build the secondary structure for each instance of the "master" element or at least advertise the situation to the user and allow them to manually generate the data required for the secondary trees. Is there any pattern which might apply to this situation? I've been treating it as a view problem, but it turns out to be more complicated than that when you look at the initial generation of the data.

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  • Checking inherited attributes in an 'ancestry' based SQL table

    - by Brendon Muir
    I'm using the ancestry gem to help organise my app's tree structure in the database. It basically writes a childs ancestor information to a special column called 'ancestry'. The ancestry column for a particular child might look like '1/34/87' where the parent of this child is 87, and then 87's parent is 34 and 34's is 1. It seems possible that we could select rows from this table each with a subquery that checks all the ancestors to see if a certain attribute it set. E.g. in my app you can hide an item and its children just by setting the parent element's visibility column to 0. I want to be able to find all the items where none of their ancestors are hidden. I tried converting the slashes to comma's with the REPLACE command but IN required a set of comma separated integers rather than one string with comma separated string numbers. It's funny, because I can do this query in two steps, e.g. retrieve the row, then take its ancestry column, split out the id's and make another query that checks that the id is IN that set of id's and that visibility isn't ever 0 and whala! But joining these into one query seems to be quite a task. Much searching has shown a few answers but none really do what I want. SELECT * FROM t1 WHERE id = 99; 99's ancestry column reads '1/34/87' SELECT * FROM t1 WHERE visibility = 0 AND id IN (1,34,87); kind of backwards, but if this returns no rows then the item is visible. Has anyone come across this before and come up with a solution. I don't really want to go the stored procedure route. It's for a rails app.

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  • Any software for pattern-matching and -rewriting source code?

    - by Steven A. Lowe
    I have some old software (in a language that's not dead but is dead to me ;-)) that implements a basic pattern-matching and -rewriting system for source code. I am considering resurrecting this code, translating it into a modern language, and open-sourcing the project as a refactoring power-tool. Before I go much further, I want to know if anything like this exists already (my google-fu is fanning air on this tonight). Here's how it works: the pattern-matching part matches source-code patterns spanning multiple lines of code using a template with binding variables, the pattern-rewriting part uses a template to rewrite the matched code, inserting the contents of the bound variables from the matching template matching and rewriting templates are associated (1:1) by a simple (unconditional) rewrite rule the software operates on the abstract syntax tree (AST) of the input application, and outputs a modified AST which can then be regenerated into new source code for example, suppose we find a bunch of while-loops that really should be for-loops. The following template will match the while-loop pattern: Template oldLoopPtrn int @cnt@ = 0; while (@cnt@ < @max@) { … @body@ ++@cnt@; } End_Template while the following template will specify the output rewrite pattern: Template newLoopPtrn for(int @cnt@ = 0; @cnt@ < @max@; @cnt@++) { @body@ } End_Template and a simple rule to associate them Rule oldLoopPtrn --> newLoopPtrn so code that looks like this int i=0; while(i<arrlen) { printf("element %d: %f\n",i,arr[i]); ++i; } gets automatically rewritten to look like this for(int i = 0; i < arrlen; i++) { printf("element %d: %f\n",i,arr[i]); } The closest thing I've seen like this is some of the code-refactoring tools, but they seem to be geared towards interactive rewriting of selected snippets, not wholesale automated changes. I believe that this kind of tool could supercharge refactoring, and would work on multiple languages (even HTML/CSS). I also believe that converting and polishing the code base would be a huge project that I simply cannot do alone in any reasonable amount of time. So, anything like this out there already? If not, any obvious features (besides rewrite-rule conditions) to consider? EDIT: The one feature of this system that I like very much is that the template patterns are fairly obvious and easy to read because they're written in the same language as the target source code, not in some esoteric mutated regex/BNF format.

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  • How can I move a library inside a project's source tree and compiling static binaries?

    - by AbrahamVanHelpsing
    How can I move a library inside a project's source tree and compiling static binaries? I want to use a particular tool that utilizes ANCIENT binaries without upgrading it's API usage. This way I can use the old libraries inside the single binary without wrecking the local host environment. I am on nix with netbeans/eclipse/code::blocks. I don't have a problem reading, just looking for a starting point. Any thoughts?

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  • Handling inheritance with overriding efficiently

    - by Fyodor Soikin
    I have the following two data structures. First, a list of properties applied to object triples: Object1 Object2 Object3 Property Value O1 O2 O3 P1 "abc" O1 O2 O3 P2 "xyz" O1 O3 O4 P1 "123" O2 O4 O5 P1 "098" Second, an inheritance tree: O1 O2 O4 O3 O5 Or viewed as a relation: Object Parent O2 O1 O4 O2 O3 O1 O5 O3 O1 null The semantics of this being that O2 inherits properties from O1; O4 - from O2 and O1; O3 - from O1; and O5 - from O3 and O1, in that order of precedence. NOTE 1: I have an efficient way to select all children or all parents of a given object. This is currently implemented with left and right indexes, but hierarchyid could also work. This does not seem important right now. NOTE 2: I have tiggers in place that make sure that the "Object" column always contains all possible objects, even when they do not really have to be there (i.e. have no parent or children defined). This makes it possible to use inner joins rather than severely less effiecient outer joins. The objective is: Given a pair of (Property, Value), return all object triples that have that property with that value either defined explicitly or inherited from a parent. NOTE 1: An object triple (X,Y,Z) is considered a "parent" of triple (A,B,C) when it is true that either X = A or X is a parent of A, and the same is true for (Y,B) and (Z,C). NOTE 2: A property defined on a closer parent "overrides" the same property defined on a more distant parent. NOTE 3: When (A,B,C) has two parents - (X1,Y1,Z1) and (X2,Y2,Z2), then (X1,Y1,Z1) is considered a "closer" parent when: (a) X2 is a parent of X1, or (b) X2 = X1 and Y2 is a parent of Y1, or (c) X2 = X1 and Y2 = Y1 and Z2 is a parent of Z1 In other words, the "closeness" in ancestry for triples is defined based on the first components of the triples first, then on the second components, then on the third components. This rule establishes an unambigous partial order for triples in terms of ancestry. For example, given the pair of (P1, "abc"), the result set of triples will be: O1, O2, O3 -- Defined explicitly O1, O2, O5 -- Because O5 inherits from O3 O1, O4, O3 -- Because O4 inherits from O2 O1, O4, O5 -- Because O4 inherits from O2 and O5 inherits from O3 O2, O2, O3 -- Because O2 inherits from O1 O2, O2, O5 -- Because O2 inherits from O1 and O5 inherits from O3 O2, O4, O3 -- Because O2 inherits from O1 and O4 inherits from O2 O3, O2, O3 -- Because O3 inherits from O1 O3, O2, O5 -- Because O3 inherits from O1 and O5 inherits from O3 O3, O4, O3 -- Because O3 inherits from O1 and O4 inherits from O2 O3, O4, O5 -- Because O3 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 O4, O2, O3 -- Because O4 inherits from O1 O4, O2, O5 -- Because O4 inherits from O1 and O5 inherits from O3 O4, O4, O3 -- Because O4 inherits from O1 and O4 inherits from O2 O5, O2, O3 -- Because O5 inherits from O1 O5, O2, O5 -- Because O5 inherits from O1 and O5 inherits from O3 O5, O4, O3 -- Because O5 inherits from O1 and O4 inherits from O2 O5, O4, O5 -- Because O5 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 Note that the triple (O2, O4, O5) is absent from this list. This is because property P1 is defined explicitly for the triple (O2, O4, O5) and this prevents that triple from inheriting that property from (O1, O2, O3). Also note that the triple (O4, O4, O5) is also absent. This is because that triple inherits its value of P1="098" from (O2, O4, O5), because it is a closer parent than (O1, O2, O3). The straightforward way to do it is the following. First, for every triple that a property is defined on, select all possible child triples: select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value from TriplesAndProperties tp -- Select corresponding objects of the triple inner join Objects as Objects1 on Objects1.Id = tp.O1 inner join Objects as Objects2 on Objects2.Id = tp.O2 inner join Objects as Objects3 on Objects3.Id = tp.O3 -- Then add all possible children of all those objects inner join Objects as Children1 on Objects1.Id [isparentof] Children1.Id inner join Objects as Children2 on Objects2.Id [isparentof] Children2.Id inner join Objects as Children3 on Objects3.Id [isparentof] Children3.Id But this is not the whole story: if some triple inherits the same property from several parents, this query will yield conflicting results. Therefore, second step is to select just one of those conflicting results: select * from ( select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value, row_number() over( partition by Children1.Id, Children2.Id, Children3.Id, tp.Property order by Objects1.[depthInTheTree] descending, Objects2.[depthInTheTree] descending, Objects3.[depthInTheTree] descending ) as InheritancePriority from ... (see above) ) where InheritancePriority = 1 The window function row_number() over( ... ) does the following: for every unique combination of objects triple and property, it sorts all values by the ancestral distance from the triple to the parents that the value is inherited from, and then I only select the very first of the resulting list of values. A similar effect can be achieved with a GROUP BY and ORDER BY statements, but I just find the window function semantically cleaner (the execution plans they yield are identical). The point is, I need to select the closest of contributing ancestors, and for that I need to group and then sort within the group. And finally, now I can simply filter the result set by Property and Value. This scheme works. Very reliably and predictably. It has proven to be very powerful for the business task it implements. The only trouble is, it is awfuly slow. One might point out the join of seven tables might be slowing things down, but that is actually not the bottleneck. According to the actual execution plan I'm getting from the SQL Management Studio (as well as SQL Profiler), the bottleneck is the sorting. The problem is, in order to satisfy my window function, the server has to sort by Children1.Id, Children2.Id, Children3.Id, tp.Property, Parents1.[depthInTheTree] descending, Parents2.[depthInTheTree] descending, Parents3.[depthInTheTree] descending, and there can be no indexes it can use, because the values come from a cross join of several tables. EDIT: Per Michael Buen's suggestion (thank you, Michael), I have posted the whole puzzle to sqlfiddle here. One can see in the execution plan that the Sort operation accounts for 32% of the whole query, and that is going to grow with the number of total rows, because all the other operations use indexes. Usually in such cases I would use an indexed view, but not in this case, because indexed views cannot contain self-joins, of which there are six. The only way that I can think of so far is to create six copies of the Objects table and then use them for the joins, thus enabling an indexed view. Did the time come that I shall be reduced to that kind of hacks? The despair sets in.

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  • Universal navigation menu across domains - would it be considered duplicate content?

    - by Jon Harley
    Across different sites on different second-level domains exists a universal navigation bar with a collection of roughly 30 links. This universal bar is exactly the same for every page on each domain. The bar's HTML, CSS and JavaScript are all stored in a subfolder for each domain and the HTML is embedded upon serving the page and is not being injected on the client side. None of the links use any rel directives and are as vanilla as can be. My question is about Google's duplicate content rule. Would something like this be considered duplicate content? Matt Cutt's blog post about duplicate content mentions boilerplate repetition, but then he mentions lengthy legalese. Since the text in this universal bar is brief and uses common terms, I wonder if this same rule applies. If this is considered duplicate content, what would be a good way to correct the problem?

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  • Firefox 23 bêta : partage et navigation simplifiés, le navigateur adopte un nouveau logo pour « une nouvelle ère »

    Firefox 23 bêta : partage et navigation simplifiée le navigateur adopte un nouveau logo pour « une nouvelle ère »Le développement de Firefox 23 se poursuit avec une nouvelle version bêta disponible en téléchargement depuis le site officiel de l'éditeur du navigateur. Quels sont les changements apportés par cette nouvelle version ? D'entrée de jeu, on peut déjà remarquer que le logo de Firefox a subi quelques petits changements. Sur la page officielle, on peut lire le slogan : « Un nouveau logo pour une nouvelle ère » Côté sécurité, une nouvelle fonctionnalité voit le jour. « Mixed content blocking...

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  • Les tests d'interopérabilités sur HTTP 2.0 bientôt amorcés, la navigation internet sera plus rapide grâce au multiplexage

    Les tests d'interopérabilités sur HTTP 2.0 bientôt amorcés, la navigation internet sera plus rapide grâce au multiplexageLe web est susceptible de changer fondamentalement bientôt. L'IETF (Internet Engineering Task Force) prépare la version 2.0 du protocole HTTP, a expliqué Mark Nottingham qui dirige actuellement l'équipe d'IETF HTTPBIS. Pour sa première ébauche, HTTP 2.0 s'appuiera sur SPDY, le protocole développé par Google. Le responsable de l'équipe de travail prévoit toutefois des changements significatifs. Parmi eux, un nouvel algorithme de compression d'en-tête. Il faut aussi noter que bien que SPDY n'autorise que les connexions chiffrées, pour HTTP 2.0 elles seront facultatives. HTTP 2.0...

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  • Why is insertion into my tree faster on sorted input than random input?

    - by Juliet
    Now I've always heard binary search trees are faster to build from randomly selected data than ordered data, simply because ordered data requires explicit rebalancing to keep the tree height at a minimum. Recently I implemented an immutable treap, a special kind of binary search tree which uses randomization to keep itself relatively balanced. In contrast to what I expected, I found I can consistently build a treap about 2x faster and generally better balanced from ordered data than unordered data -- and I have no idea why. Here's my treap implementation: http://pastebin.com/VAfSJRwZ And here's a test program: using System; using System.Collections.Generic; using System.Linq; using System.Diagnostics; namespace ConsoleApplication1 { class Program { static Random rnd = new Random(); const int ITERATION_COUNT = 20; static void Main(string[] args) { List<double> rndTimes = new List<double>(); List<double> orderedTimes = new List<double>(); rndTimes.Add(TimeIt(50, RandomInsert)); rndTimes.Add(TimeIt(100, RandomInsert)); rndTimes.Add(TimeIt(200, RandomInsert)); rndTimes.Add(TimeIt(400, RandomInsert)); rndTimes.Add(TimeIt(800, RandomInsert)); rndTimes.Add(TimeIt(1000, RandomInsert)); rndTimes.Add(TimeIt(2000, RandomInsert)); rndTimes.Add(TimeIt(4000, RandomInsert)); rndTimes.Add(TimeIt(8000, RandomInsert)); rndTimes.Add(TimeIt(16000, RandomInsert)); rndTimes.Add(TimeIt(32000, RandomInsert)); rndTimes.Add(TimeIt(64000, RandomInsert)); rndTimes.Add(TimeIt(128000, RandomInsert)); string rndTimesAsString = string.Join("\n", rndTimes.Select(x => x.ToString()).ToArray()); orderedTimes.Add(TimeIt(50, OrderedInsert)); orderedTimes.Add(TimeIt(100, OrderedInsert)); orderedTimes.Add(TimeIt(200, OrderedInsert)); orderedTimes.Add(TimeIt(400, OrderedInsert)); orderedTimes.Add(TimeIt(800, OrderedInsert)); orderedTimes.Add(TimeIt(1000, OrderedInsert)); orderedTimes.Add(TimeIt(2000, OrderedInsert)); orderedTimes.Add(TimeIt(4000, OrderedInsert)); orderedTimes.Add(TimeIt(8000, OrderedInsert)); orderedTimes.Add(TimeIt(16000, OrderedInsert)); orderedTimes.Add(TimeIt(32000, OrderedInsert)); orderedTimes.Add(TimeIt(64000, OrderedInsert)); orderedTimes.Add(TimeIt(128000, OrderedInsert)); string orderedTimesAsString = string.Join("\n", orderedTimes.Select(x => x.ToString()).ToArray()); Console.WriteLine("Done"); } static double TimeIt(int insertCount, Action<int> f) { Console.WriteLine("TimeIt({0}, {1})", insertCount, f.Method.Name); List<double> times = new List<double>(); for (int i = 0; i < ITERATION_COUNT; i++) { Stopwatch sw = Stopwatch.StartNew(); f(insertCount); sw.Stop(); times.Add(sw.Elapsed.TotalMilliseconds); } return times.Average(); } static void RandomInsert(int insertCount) { Treap<double> tree = new Treap<double>((x, y) => x.CompareTo(y)); for (int i = 0; i < insertCount; i++) { tree = tree.Insert(rnd.NextDouble()); } } static void OrderedInsert(int insertCount) { Treap<double> tree = new Treap<double>((x, y) => x.CompareTo(y)); for(int i = 0; i < insertCount; i++) { tree = tree.Insert(i + rnd.NextDouble()); } } } } And here's a chart comparing random and ordered insertion times in milliseconds: Insertions Random Ordered RandomTime / OrderedTime 50 1.031665 0.261585 3.94 100 0.544345 1.377155 0.4 200 1.268320 0.734570 1.73 400 2.765555 1.639150 1.69 800 6.089700 3.558350 1.71 1000 7.855150 4.704190 1.67 2000 17.852000 12.554065 1.42 4000 40.157340 22.474445 1.79 8000 88.375430 48.364265 1.83 16000 197.524000 109.082200 1.81 32000 459.277050 238.154405 1.93 64000 1055.508875 512.020310 2.06 128000 2481.694230 1107.980425 2.24 I don't see anything in the code which makes ordered input asymptotically faster than unordered input, so I'm at a loss to explain the difference. Why is it so much faster to build a treap from ordered input than random input?

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  • How to create a complete binary tree of height 'h' using Python?

    - by Jack
    Here is the node structure class Node: def __init__(self, data): # initializes the data members self.left = None self.right = None self.parent = None self.data = data complete binary tree Definition: A binary tree in which every level, except possibly the deepest, is completely filled. At depth n, the height of the tree, all nodes must be as far left as possible. -- http://www.itl.nist.gov/div897/sqg/dads/HTML/completeBinaryTree.html I am looking for an efficient algorithm.

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  • In GWT, how to known from a SelectionEvent in a Tree if the Shift button is pressed

    - by Vinze
    Hi, I try in GWT to create a Tree with multiple selection for the nodes and ran into a problem similar to this question http://stackoverflow.com/questions/1411752/shift-key-in-gwt. When a selectionEvent is raised from the Tree, I would like to know if the Shift key is pressed or not. SelectionHandler<TreeItem> getSelectionHandler() { return new SelectionHandler<TreeItem>(){ @Override public void onSelection(SelectionEvent<TreeItem> event) { // is shift key pressed ? } }; } The solution in the question above cannot apply in this case as the SelectionHandler class does not inherit from DOMEvent and then does not have a getNativeEvent() function. I tried a dirty solution by adding keyDownEventHandler and keyUpEventHandler to the Tree with a boolean flag but the handlers are only called when the focus is on the tree so this doesn't work. Is there a simple solution (or just a solution even if it's not simple) ? Thanks.

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  • How can I find the common ancestor of two nodes in a binary tree?

    - by Siddhant
    The Binary Tree here is not a Binary Search Tree. Its just a Binary Tree. The structure could be taken as - struct node { int data; struct node *left; struct node *right; }; The maximum solution I could work out with a friend was something of this sort - Consider this binary tree (from http://lcm.csa.iisc.ernet.in/dsa/node87.html) : The inorder traversal yields - 8, 4, 9, 2, 5, 1, 6, 3, 7 And the postorder traversal yields - 8, 9, 4, 5, 2, 6, 7, 3, 1 So for instance, if we want to find the common ancestor of nodes 8 and 5, then we make a list of all the nodes which are between 8 and 5 in the inorder tree traversal, which in this case happens to be [4, 9, 2]. Then we check which node in this list appears last in the postorder traversal, which is 2. Hence the common ancestor for 8 and 5 is 2. The complexity for this algorithm, I believe is O(n) (O(n) for inorder/postorder traversals, the rest of the steps again being O(n) since they are nothing more than simple iterations in arrays). But there is a strong chance that this is wrong. :-) But this is a very crude approach, and I'm not sure if it breaks down for some case. Is there any other (possibly more optimal) solution to this problem?

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  • Can anyone provide Java program for btree or b+tree???

    - by rohit
    Hi, I am doing a project in which i require btree or b+tree data structure. but its not an important part of project. it would take my time to write a code for it. I googled it but didn't get anything.... So, can anyone provide java code for btree or b+tree implementation (with insert, delete, search algorithms)?????? it should accept string as input and form btree or b+tree of these string.

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