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  • How do you make a regular expression that matches a word with one randomly inserted character?

    - by Dfowj
    Hey all, i want to use a regular expression to match a word with one specified character randomly placed within it. I also want to keep that 'base' word's characters in their original order. For example, with the 'base' word of test and the specified character of 'y', i want the regular expression to match all the following, and ONLY the following: ytest, tyest, teyst, tesyt, testy Incase it matters, im working in javascript and using the dojo toolkit. Thanks!

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  • [AS 3.0] How to use the string.match method to find multiple occurrences of the same word in a strin

    - by Steven
    In Actionscript and Adobe Flex, I'm using a pattern and regexp (with the global flag) with the string.match method and it works how I'd like except when the match returns multiple occurrences of the same word in the text. In that case, all the matches for that word point only to the index for the first occurrence of that word. For example, if the text is "cat dog cat cat cow" and the pattern is a search for cat*, the match method returns an array of three occurrences of "cat", however, they all point to only the index of the first occurrence of cat when i use indexOf on a loop through the array. I'm assuming this is just how the string.match method is (although please let me know if i'm doing something wrong or missing something!). I want to find the specific indices of every occurrence of a match, even if it is of a word that was already previously matched. I'm wondering if that is just how the string.match method is and if so, if anyone has any idea what the best way to do this would be. Thanks.

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  • MapReduce

    - by kaleidoscope
    MapReduce is a programming model and an associated implementation for processing and generating large data sets. Users specify a map function that processes a key/value pair to generate a set of  intermediate key/value pairs, and a reduce function that merges all intermediate values associated with the same intermediate key. Many real world tasks are expressible in this model, as shown in the paper. Programs written in this functional style are automatically parallelized and executed on a large cluster of commodity machines. The run-time system takes care of the details of partitioning the input data,  scheduling the program's execution across a set of machines, handling machine failures, and managing the required inter-machine communication. This allows programmers without any experience with parallel and distributed systems to easily utilize the resources of a large distributed system. Example: A process to count the appearances of each different word in a set of documents void map(String name, String document):   // name: document name   // document: document contents   for each word w in document:     EmitIntermediate(w, 1); void reduce(String word, Iterator partialCounts):   // word: a word   // partialCounts: a list of aggregated partial counts   int result = 0;   for each pc in partialCounts:     result += ParseInt(pc);   Emit(result); Here, each document is split in words, and each word is counted initially with a "1" value by the Map function, using the word as the result key. The framework puts together all the pairs with the same key and feeds them to the same call to Reduce, thus this function just needs to sum all of its input values to find the total appearances of that word.   Sarang, K

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  • Project Euler 17: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 17.  As always, any feedback is welcome. # Euler 17 # http://projecteuler.net/index.php?section=problems&id=17 # If the numbers 1 to 5 are written out in words: # one, two, three, four, five, then there are # 3 + 3 + 5 + 4 + 4 = 19 letters used in total. # If all the numbers from 1 to 1000 (one thousand) # inclusive were written out in words, how many letters # would be used? # # NOTE: Do not count spaces or hyphens. For example, 342 # (three hundred and forty-two) contains 23 letters and # 115 (one hundred and fifteen) contains 20 letters. The # use of "and" when writing out numbers is in compliance # with British usage. import time start = time.time() def to_word(n): h = { 1 : "one", 2 : "two", 3 : "three", 4 : "four", 5 : "five", 6 : "six", 7 : "seven", 8 : "eight", 9 : "nine", 10 : "ten", 11 : "eleven", 12 : "twelve", 13 : "thirteen", 14 : "fourteen", 15 : "fifteen", 16 : "sixteen", 17 : "seventeen", 18 : "eighteen", 19 : "nineteen", 20 : "twenty", 30 : "thirty", 40 : "forty", 50 : "fifty", 60 : "sixty", 70 : "seventy", 80 : "eighty", 90 : "ninety", 100 : "hundred", 1000 : "thousand" } word = "" # Reverse the numbers so position (ones, tens, # hundreds,...) can be easily determined a = [int(x) for x in str(n)[::-1]] # Thousands position if (len(a) == 4 and a[3] != 0): # This can only be one thousand based # on the problem/method constraints word = h[a[3]] + " thousand " # Hundreds position if (len(a) >= 3 and a[2] != 0): word += h[a[2]] + " hundred" # Add "and" string if the tens or ones # position is occupied with a non-zero value. # Note: routine is broken up this way for [my] clarity. if (len(a) >= 2 and a[1] != 0): # catch 10 - 99 word += " and" elif len(a) >= 1 and a[0] != 0: # catch 1 - 9 word += " and" # Tens and ones position tens_position_value = 99 if (len(a) >= 2 and a[1] != 0): # Calculate the tens position value per the # first and second element in array # e.g. (8 * 10) + 1 = 81 tens_position_value = int(a[1]) * 10 + a[0] if tens_position_value <= 20: # If the tens position value is 20 or less # there's an entry in the hash. Use it and there's # no need to consider the ones position word += " " + h[tens_position_value] else: # Determine the tens position word by # dividing by 10 first. E.g. 8 * 10 = h[80] # We will pick up the ones position word later in # the next part of the routine word += " " + h[(a[1] * 10)] if (len(a) >= 1 and a[0] != 0 and tens_position_value > 20): # Deal with ones position where tens position is # greater than 20 or we have a single digit number word += " " + h[a[0]] # Trim the empty spaces off both ends of the string return word.replace(" ","") def to_word_length(n): return len(to_word(n)) print sum([to_word_length(i) for i in xrange(1,1001)]) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Strange (Undefined?) Behavior of Free in C

    - by Chris Cirefice
    This is really strange... and I can't debug it (tried for about two hours, debugger starts going haywire after a while...). Anyway, I'm trying to do something really simple: Free an array of strings. The array is in the form: char **myStrings. The array elements are initialized as: myString[index] = malloc(strlen(word)); myString[index] = word; and I'm calling a function like this: free_memory(myStrings, size); where size is the length of the array (I know this is not the problem, I tested it extensively and everything except this function is working). free_memory looks like this: void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { free(list[i]); } free(list); } Now here comes the weird part. if (size> strlen(list[i])) then the program crashes. For example, imagine that I have a list of strings that looks something like this: myStrings[0] = "Some"; myStrings[1] = "random"; myStrings[2] = "strings"; And thus the length of this array is 3. If I pass this to my free_memory function, strlen(myStrings[0]) > 3 (4 3), and the program crashes. However, if I change myStrings[0] to be "So" instead, then strlen(myStrings[0]) < 3 (2 < 3) and the program does not crash. So it seems to me that free(list[i]) is actually going through the char[] that is at that location and trying to free each character, which I imagine is undefined behavior. The only reason I say this is because I can play around with the size of the first element of myStrings and make the program crash whenever I feel like it, so I'm assuming that this is the problem area. Note: I did try to debug this by stepping through the function that calls free_memory, noting any weird values and such, but the moment I step into the free_memory function, the debugger crashes, so I'm not really sure what is going on. Nothing is out of the ordinary until I enter the function, then the world explodes. Another note: I also posted the shortened version of the source for this program (not too long; Pastebin) here. I am compiling on MinGW with the c99 flag on. PS - I just thought of this. I am indeed passing numUniqueWords to the free function, and I know that this does not actually free the entire piece of memory that I allocated. I've called it both ways, that's not the issue. And I left it how I did because that is the way that I will be calling it after I get it to work in the first place, I need to revise some of my logic in that function. Source, as per request (on-site): #include <stdio.h> #include <string.h> #include <ctype.h> #include <stdlib.h> #include "words.h" int getNumUniqueWords(char text[], int size); int main(int argc, char* argv[]) { setvbuf(stdout, NULL, 4, _IONBF); // For Eclipse... stupid bug. --> does NOT affect the program, just the output to console! int nbr_words; char text[] = "Some - \"text, a stdin\". We'll have! also repeat? We'll also have a repeat!"; int length = sizeof(text); nbr_words = getNumUniqueWords(text, length); return 0; } void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { // You can see that printing the values is fine, as long as free is not called. // When free is called, the program will crash if (size > strlen(list[i])) //printf("Wanna free value %d w/len of %d: %s\n", i, strlen(list[i]), list[i]); free(list[i]); } free(list); } int getNumUniqueWords(char text[], int length) { int numTotalWords = 0; char *word; printf("Length: %d characters\n", length); char totalWords[length]; strcpy(totalWords, text); word = strtok(totalWords, " ,.-!?()\"0123456789"); while (word != NULL) { numTotalWords ++; printf("%s\n", word); word = strtok(NULL, " ,.-!?()\"0123456789"); } printf("Looks like we counted %d total words\n\n", numTotalWords); char *uniqueWords[numTotalWords]; char *tempWord; int wordAlreadyExists = 0; int numUniqueWords = 0; char totalWordsCopy[length]; strcpy(totalWordsCopy, text); for (int i = 0; i < numTotalWords; i++) { uniqueWords[i] = NULL; } // Tokenize until all the text is consumed. word = strtok(totalWordsCopy, " ,.-!?()\"0123456789"); while (word != NULL) { // Look through the word list for the current token. for (int j = 0; j < numTotalWords; j ++) { // Just for clarity, no real meaning. tempWord = uniqueWords[j]; // The word list is either empty or the current token is not in the list. if (tempWord == NULL) { break; } //printf("Comparing (%s) with (%s)\n", tempWord, word); // If the current token is the same as the current element in the word list, mark and break if (strcmp(tempWord, word) == 0) { printf("\nDuplicate: (%s)\n\n", word); wordAlreadyExists = 1; break; } } // Word does not exist, add it to the array. if (!wordAlreadyExists) { uniqueWords[numUniqueWords] = malloc(strlen(word)); uniqueWords[numUniqueWords] = word; numUniqueWords ++; printf("Unique: %s\n", word); } // Reset flags and continue. wordAlreadyExists = 0; word = strtok(NULL, " ,.-!?()\"0123456789"); } // Print out the array just for funsies - make sure it's working properly. for (int x = 0; x <numUniqueWords; x++) { printf("Unique list %d: %s\n", x, uniqueWords[x]); } printf("\nNumber of unique words: %d\n\n", numUniqueWords); // Right below is where things start to suck. free_memory(uniqueWords, numUniqueWords); return numUniqueWords; }

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  • lnk2019 error in very simple c++ program

    - by Erin
    I have tried removing various parts and building, but nothing makes the lnk2019 error go away, or even produces any normal errors. Everything is in the one file at the moment (it won't be later when it is finished). The program has three lists of words and makes a jargon phrase out of them, and you are supposed to be able to add words, remove words, view the lists, restore defaults, save changes to file, and load changes from file. #include "stdafx.h" #include <iostream> #include <string.h> using namespace std; const int maxlist = 20; string adj1[maxlist], adj2[maxlist], noun[maxlist]; void defaultlist(int list) { if(list == 1) { adj1[0] = "green"; adj1[1] = "red"; adj1[2] = "yellow"; adj1[3] = "blue"; adj1[4] = "purple"; int i = 5; while(i != maxlist) { adj1[i] = ""; i = i + 1; } } if(list == 2) { adj2[0] = "shiny"; adj2[1] = "hard"; adj2[2] = "soft"; adj2[3] = "spiky"; adj2[4] = "furry"; int i = 5; while(i != maxlist) { adj2[i] = ""; i = i + 1; } } if(list == 3) { noun[0] = "cat"; noun[1] = "dog"; noun[2] = "desk"; noun[3] = "chair"; noun[4] = "door"; int i = 5; while(i != maxlist) { noun[i] = ""; i = i + 1; } } return; } void printlist(int list) { if(list == 1) { int i = 0; while(!(i == maxlist)) { cout << adj1[i] << endl; i = i + 1; } } if(list == 2) { int i = 0; while(!(i == maxlist)) { cout << adj2[i] << endl; i = i + 1; } } if(list == 3) { int i = 0; while(!(i == maxlist)) { cout << noun[i] << endl; i = i + 1; } } return; } string makephrase() { int num1 = rand()%maxlist; int num2 = rand()%maxlist; int num3 = rand()%maxlist; int num4 = rand()%1; string word1, word2, word3; if(num4 = 0) { word1 = adj1[num1]; word2 = adj2[num2]; } else { word1 = adj2[num1]; word2 = adj1[num2]; } word3 = noun[num3]; return word1 + " ," + word2 + " " + word3; } string addword(string word, int list) { string result; if(list == 1) { int i = 0; while(!(adj1[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(adj1[i] == "") { adj1[i] = word; result = "Word was entered successfully."; } } if(list == 2) { int i = 0; while(!(adj2[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(adj2[i] == "") { adj2[i] = word; result = "Word was entered successfully."; } } if(list == 3) { int i = 0; while(!(noun[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(noun[i] == "") { noun[i] = word; result = "Word was entered successfully."; } } return result; } string removeword(string word, int list) { string result; if(list == 1) { int i = 0; while(!(adj1[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(adj1[i] == word) { adj1[i] = ""; result = "Word was removed successfully."; } } if(list == 2) { int i = 0; while(!(adj2[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(adj2[i] == word) { adj2[i] = ""; result = "Word was removed successfully."; } } if(list == 3) { int i = 0; while(!(noun[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(noun[i] == word) { noun[i] = ""; result = "Word was removed successfully."; } } return result; } /////////////////////////////main/////////////////////////////////// int main() { string mainselection; string makeselection; string phrase; defaultlist(1); defaultlist(2); defaultlist(3); cout << "This program generates jargon phrases made of two adjectives and one noun,"; cout << " on three lists. Each list may contain a maximum of " << maxlist << "elements."; cout << " Please choose from the following menu by typing the appropriate number "; cout << "and pressing enter." << endl; cout << endl; cout << "1. Make a jargon phrase." << endl; cout << "2. View a list." << endl; cout << "3. Add a word to a list." << endl; cout << "4. Remove a word from a list." << endl; cout << "5. Restore default lists." << endl; cout << "More options coming soon!." << endl; cin mainselection if(mainselection == 1) { phrase = makephrase(); cout << "Your phrase is " << phrase << "." << endl; cout << "To make another phrase, press 1. To go back to the main menu,"; cout << " press 2. To exit the program, press 3." << endl; cin makeselection; while(!(makeselection == "1" || makeselection == "2" || makeselection == "3")) { cout << "You have entered an invalid selection. Please try again." << endl; cin makeselection; } while(makeselection == "1") { phrase = makephrase(); cout << "To make another phrase, press 1. To go back to the main menu,"; cout << " press 2. To exit the program, press 3." << endl; } if(makeselection == "2") main(); if(makeselection == "3") return 0; } return 0; } //Rest of the options coming soon!

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  • What word processor can manage left and right pages separately?

    - by chtfn
    I was after a word processor that can manage left and right pages separately so I can have my text on the right pages and my illustrations on the left pages. I know LibeOffice can set "left page" and "right page" formats, but there is no simple way to make the text jump from right page to right page when writing. I don't know what would be the best way to do that, but I guess I need an app that is designed for writing books and do that kind of thing, or an app that can associate a page format with an object format (so the "illustration" format can be exclusively associated with "left page" format, and "text body" exclusively associated with "right page", for example). Or is there an extension for LO or OOo out there that I didn't hear about? Cheers!

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  • Does having a Google "stop word" in a domain name have less SEO benefit than not having it?

    - by Dan
    Let me explain. Let's say my keyword I want to optimize is "green giraffes". But the domain greengiraffes.com (singular, plural, no hyphen, hyphen, etc.) is not available. I know that the search results for "green giraffes" and "about green giraffes" are essentially the same because "about" is a "stop word". Does that therefore also mean that the domain name "aboutgreengiraffes.com" is as good as "greengiraffes.com" in terms of SEO value? Are all stop words equal in that regard, or a shorter one (such as "e" or "z") is better?

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  • How do you properly word a Google search when you don't even have a solution in mind? [closed]

    - by Bruno Romaszkiewicz
    So, I'm stuck on a problem, looking for a solution, my rubber duck can't help me, my co-workers can't help me. Next natural step is research, right? Google can help me, He always can. Or so I'm told. My problem is, I never found much use for Google when looking for a programming solution, it's very useful for finding how to implement one, but when you don't even know where to start, how do you properly word a Google search? Is there any other option?

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  • What does the English word "for" exactly mean in "for" loops?

    - by kol
    English is not my first language, but since the keywords in programming languages are English words, I usually find it easy to read source code as English sentences: if (x > 10) f(); = "If variable x is greater than 10, then call function f." while (i < 10) ++i; = "While variable i is less than 10, increase i by 1." But how a for loop is supposed to be read? for (i = 0; i < 10; ++i) f(i); = ??? I mean, I know what a for loop is and how it works. My problem is only that I don't know what the English word "for" exactly means in for loops.

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  • Need suggestions on how to extract data from .docx/.doc file then into mssql

    - by DarkPP
    I'm suppose to develop an automated application for my project, it will load past-year examination/exercises paper (word file), detect the sections accordingly, extract the questions and images in that section, and then store the questions and images into the database. (Preview of the question paper is at the bottom of this post) So I need some suggestions on how to extract data from a word file, then inserting them into a database. Currently I have a few methods to do so, however I have no idea how I could implement them when the file contains textboxes with background image. The question has to link with the image. Method One (Make use of ms office interop) Load the word file - Extract image, save into a folder - Extract text, save as .txt - Extract text from .txt then store in db Question: How i detect the section and question. How I link the image to the question. Extract text from word file (Working): private object missing = Type.Missing; private object sFilename = @"C:\temp\questionpaper.docx"; private object sFilename2 = @"C:\temp\temp.txt"; private object readOnly = true; object fileFormat = Word.WdSaveFormat.wdFormatText; private void button1_Click(object sender, EventArgs e) { Word.Application wWordApp = new Word.Application(); wWordApp.DisplayAlerts = Word.WdAlertLevel.wdAlertsNone; Word.Document dFile = wWordApp.Documents.Open(ref sFilename, ref missing, ref readOnly, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing); dFile.SaveAs(ref sFilename2, ref fileFormat, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing,ref missing, ref missing,ref missing,ref missing,ref missing,ref missing, ref missing,ref missing); dFile.Close(ref missing, ref missing, ref missing); } Extract image from word file (Doesn't work on image inside textbox): private Word.Application wWordApp; private int m_i; private object missing = Type.Missing; private object filename = @"C:\temp\questionpaper.docx"; private object readOnly = true; private void CopyFromClipbordInlineShape(String imageIndex) { Word.InlineShape inlineShape = wWordApp.ActiveDocument.InlineShapes[m_i]; inlineShape.Select(); wWordApp.Selection.Copy(); Computer computer = new Computer(); if (computer.Clipboard.GetDataObject() != null) { System.Windows.Forms.IDataObject data = computer.Clipboard.GetDataObject(); if (data.GetDataPresent(System.Windows.Forms.DataFormats.Bitmap)) { Image image = (Image)data.GetData(System.Windows.Forms.DataFormats.Bitmap, true); image.Save("C:\\temp\\DoCremoveImage" + imageIndex + ".png", System.Drawing.Imaging.ImageFormat.Png); } } } private void button1_Click(object sender, EventArgs e) { wWordApp = new Word.Application(); wWordApp.Documents.Open(ref filename, ref missing, ref readOnly, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing); try { for (int i = 1; i <= wWordApp.ActiveDocument.InlineShapes.Count; i++) { m_i = i; CopyFromClipbordInlineShape(Convert.ToString(i)); } } finally { object save = false; wWordApp.Quit(ref save, ref missing, ref missing); wWordApp = null; } } Method Two Unzip the word file (.docx) - Copy the media(image) folder, store somewhere - Parse the XML file - Store the text in db Any suggestion/help would be greatly appreciated :D Preview of the word file: (backup link: http://i.stack.imgur.com/YF1Ap.png)

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  • One letter game problem?

    - by Alex K
    Recently at a job interview I was given the following problem: Write a script capable of running on the command line as python It should take in two words on the command line (or optionally if you'd prefer it can query the user to supply the two words via the console). Given those two words: a. Ensure they are of equal length b. Ensure they are both words present in the dictionary of valid words in the English language that you downloaded. If so compute whether you can reach the second word from the first by a series of steps as follows a. You can change one letter at a time b. Each time you change a letter the resulting word must also exist in the dictionary c. You cannot add or remove letters If the two words are reachable, the script should print out the path which leads as a single, shortest path from one word to the other. You can /usr/share/dict/words for your dictionary of words. My solution consisted of using breadth first search to find a shortest path between two words. But apparently that wasn't good enough to get the job :( Would you guys know what I could have done wrong? Thank you so much. import collections import functools import re def time_func(func): import time def wrapper(*args, **kwargs): start = time.time() res = func(*args, **kwargs) timed = time.time() - start setattr(wrapper, 'time_taken', timed) return res functools.update_wrapper(wrapper, func) return wrapper class OneLetterGame: def __init__(self, dict_path): self.dict_path = dict_path self.words = set() def run(self, start_word, end_word): '''Runs the one letter game with the given start and end words. ''' assert len(start_word) == len(end_word), \ 'Start word and end word must of the same length.' self.read_dict(len(start_word)) path = self.shortest_path(start_word, end_word) if not path: print 'There is no path between %s and %s (took %.2f sec.)' % ( start_word, end_word, find_shortest_path.time_taken) else: print 'The shortest path (found in %.2f sec.) is:\n=> %s' % ( self.shortest_path.time_taken, ' -- '.join(path)) def _bfs(self, start): '''Implementation of breadth first search as a generator. The portion of the graph to explore is given on demand using get_neighboors. Care was taken so that a vertex / node is explored only once. ''' queue = collections.deque([(None, start)]) inqueue = set([start]) while queue: parent, node = queue.popleft() yield parent, node new = set(self.get_neighbours(node)) - inqueue inqueue = inqueue | new queue.extend([(node, child) for child in new]) @time_func def shortest_path(self, start, end): '''Returns the shortest path from start to end using bfs. ''' assert start in self.words, 'Start word not in dictionnary.' assert end in self.words, 'End word not in dictionnary.' paths = {None: []} for parent, child in self._bfs(start): paths[child] = paths[parent] + [child] if child == end: return paths[child] return None def get_neighbours(self, word): '''Gets every word one letter away from the a given word. We do not keep these words in memory because bfs accesses a given vertex only once. ''' neighbours = [] p_word = ['^' + word[0:i] + '\w' + word[i+1:] + '$' for i, w in enumerate(word)] p_word = '|'.join(p_word) for w in self.words: if w != word and re.match(p_word, w, re.I|re.U): neighbours += [w] return neighbours def read_dict(self, size): '''Loads every word of a specific size from the dictionnary into memory. ''' for l in open(self.dict_path): l = l.decode('latin-1').strip().lower() if len(l) == size: self.words.add(l) if __name__ == '__main__': import sys if len(sys.argv) not in [3, 4]: print 'Usage: python one_letter_game.py start_word end_word' else: g = OneLetterGame(dict_path = '/usr/share/dict/words') try: g.run(*sys.argv[1:]) except AssertionError, e: print e

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  • What is the best way to build a database from a MS Word document?

    - by Jayron Soares
    Please advise me on how to approach this problem: I have a sequential list of metadata in a document in MS Word. The basic idea is to create a Python algorithm to iterate over the information, retrieving just the name of the PROCESS, when is made a queue, from a database. Example metadata: Process: Process Walker (1965) Exact reference: Walker Process Equipment., Inc. v. Food Machinery Corp. Link: http://caselaw.lp.findlaw.com/scripts/getcase.pl?court=US&vol=382&invol= Type of procedure: Certiorari to the United States Court of Appeals for the Seventh Circuit. Parties: Walker Process Equipment, Inc. Sector: Systems is ... Start Date: October 12-13 Arguedas, 1965 Summary: Food Machinery Company has initiated a process to stop or slow the entry of competitors through the use of a patent obtained by fraud. The case concerned a patent on "knee action swing diffusers" used in aeration equipment for sewage treatment systems, and the question was whether "the maintenance and enforcement of a patent obtained by fraud before the patent office" may be a basis for antitrust punishment. Report of the evolution process: petitioner, in answer to respond... Importance: a) First case which established an analysis for the diagnosis of dispute… There are about 200 pages containing the information above. I have in mind the idea of implementing an algorithm in Python to be able to break this information sequence and try to store it in a web database (an open source application that I’m looking for) in order to allow for free consultations.

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  • How to connect to a wireless network that has a two word name with a space?

    - by grinan
    Ok, I have searched for some time in earnest for an answer to this question. I have a Beagleboard which has Ubuntu 10.10 Minimal install for Arm running on it. With the default install, minimal tools, no GUI, I am unable to connect to my wireless network. The name of my network is "MYNAME NETWORK". Using a text editor to edit /etc/network/interfaces I can not seem to connect at all. As an experiment, I connected to a friends network, which has a one word name "dystek",and was able to connect with Zero issues, and update and install a full GUI for ubuntu Arm. The problem is that I don't want a full blown gui on the beagleboard, just a minimal install of ubuntu with CLI is all I need or want. Is there anyway to connect to my wireless network via editing the /etc/network/interfaces file. Surely there is... I just don't know how. Right now my interfaces file looks like this: auto lo iface lo inet loopback auto wlan0 iface wlan0 inet static address 192.168.1.200 netmask 255.255.255.0 gateway 192.168.1.1 wireless-essid BARRETT NETWORK wireless-key 46456xxxxxxxx Any help would be appreciated.

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  • How do I use Powershell to print a list of hyperlinks that appear in a Word document?

    - by dwwilson66
    I asked this question last week, and my script cannot find any hyperlinks to change. Now I'm backing up and trying to simply open a single document and list the hyperlinks within. I've verified that the document includes hyperlinks to a number of anchors in the same document, and two hyperlinks to documents in the same directory. However, either Powershell isn't finding links in the doc or I'm outputting the list to the console improperly. Here's my bare-bones code $word = New-Object -ComObject Word.Application $doc ="R:\path\Reporting_Emergency_Or_Hazardous_Situation_-_BC_CC.doc" $hyperlinks = @($doc.Hyperlinks) $hyperlinks $word.quit() or, for line 4 Write-Host $hyperlinks or, again for line 4 $hyperlinks | % {Write-Host $_.address} No errors, just blank results. Not even an object reference to the $hyperlinks array. When I modify line 4 to % $address in $hyperlinks { Write-Host $._address } I get the following error...but it's unclear if I'm trying to read a null array? or if the value is blank. ForEach-Object : Cannot bind parameter 'Process'. Cannot convert the "in" value of type "System.String" to type "System.Management.Automation.ScriptBlock". At F:\path\HyperLinkScrub.ps1:46 char:2 + % <<<< $address in $hyperlinks { + CategoryInfo : InvalidArgument: (:) [ForEach-Object], ParameterBindingException + FullyQualifiedErrorId : CannotConvertArgumentNoMessage,Microsoft.PowerShell.Commands.ForEachObjectCommand What am I missing here? I've verified that the Word doc has hyperlinks, and ultimately, I'm trying to diagnose if my script isn't looking for them properly, or if I'm not outputting them to the console properly.

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  • OData &ndash; The easiest service I can create: now with updates

    - by Jon Dalberg
    The other day I created a simple NastyWord service exposed via OData. It was read-only and used an in-memory backing store for the words. Today I’ll modify it to use a file instead of a list and I’ll accept new nasty words by implementing IUpdatable directly. The first thing to do is enable the service to accept new entries. This is done at configuration time by adding the “WriteAppend” access rule: 1: public class NastyWords : DataService<NastyWordsDataSource> 2: { 3: // This method is called only once to initialize service-wide policies. 4: public static void InitializeService(DataServiceConfiguration config) 5: { 6: config.SetEntitySetAccessRule("*", EntitySetRights.AllRead | EntitySetRights.WriteAppend); 7: config.DataServiceBehavior.MaxProtocolVersion = DataServiceProtocolVersion.V2; 8: } 9: }   Next I placed a file, NastyWords.txt, in the “App_Data” folder and added a few *choice* words to start. This required one simple change to our NastyWordDataSource.cs file: 1: public NastyWordsDataSource() 2: { 3: UpdateFromSource(); 4: } 5:   6: private void UpdateFromSource() 7: { 8: var words = File.ReadAllLines(pathToFile); 9: NastyWords = (from w in words 10: select new NastyWord { Word = w }).AsQueryable(); 11: }   Nothing too shocking here, just reading each line from the NastyWords.txt file and exposing them. Next, I implemented IUpdatable which comes with a boat-load of methods. We don’t need all of them for now since we are only concerned with allowing new values. Here are the methods we must implement, all the others throw a NotImplementedException: 1: public object CreateResource(string containerName, string fullTypeName) 2: { 3: var nastyWord = new NastyWord(); 4: pendingUpdates.Add(nastyWord); 5: return nastyWord; 6: } 7:   8: public object ResolveResource(object resource) 9: { 10: return resource; 11: } 12:   13: public void SaveChanges() 14: { 15: var intersect = (from w in pendingUpdates 16: select w.Word).Intersect(from n in NastyWords 17: select n.Word); 18:   19: if (intersect.Count() > 0) 20: throw new DataServiceException(500, "duplicate entry"); 21:   22: var lines = from w in pendingUpdates 23: select w.Word; 24:   25: File.AppendAllLines(pathToFile, 26: lines, 27: Encoding.UTF8); 28:   29: pendingUpdates.Clear(); 30:   31: UpdateFromSource(); 32: } 33:   34: public void SetValue(object targetResource, string propertyName, object propertyValue) 35: { 36: targetResource.GetType().GetProperty(propertyName).SetValue(targetResource, propertyValue, null); 37: }   I use a simple list to contain the pending updates and only commit them when the “SaveChanges” method is called. Here’s the order these methods are called in our service during an insert: CreateResource – here we just instantiate a new NastyWord and stick a reference to it in our pending updates list. SetValue – this is where the “Word” property of the NastyWord instance is set. SaveChanges – get the list of pending updates, barfing on duplicates, write them to the file and clear our pending list. ResolveResource – the newly created resource will be returned directly here since we aren’t dealing with “handles” to objects but the actual objects themselves. Not too bad, eh? I didn’t find this documented anywhere but a little bit of digging in the OData spec and use of Fiddler made it pretty easy to figure out. Here is some client code which would add a new nasty word: 1: static void Main(string[] args) 2: { 3: var svc = new ServiceReference1.NastyWordsDataSource(new Uri("http://localhost.:60921/NastyWords.svc")); 4: svc.AddToNastyWords(new ServiceReference1.NastyWord() { Word = "shat" }); 5:   6: svc.SaveChanges(); 7: }   Here’s all of the code so far for to implement the service: 1: using System; 2: using System.Collections.Generic; 3: using System.Data.Services; 4: using System.Data.Services.Common; 5: using System.Linq; 6: using System.ServiceModel.Web; 7: using System.Web; 8: using System.IO; 9: using System.Text; 10:   11: namespace ONasty 12: { 13: [DataServiceKey("Word")] 14: public class NastyWord 15: { 16: public string Word { get; set; } 17: } 18:   19: public class NastyWordsDataSource : IUpdatable 20: { 21: private List<NastyWord> pendingUpdates = new List<NastyWord>(); 22: private string pathToFile = @"path to your\App_Data\NastyWords.txt"; 23:   24: public NastyWordsDataSource() 25: { 26: UpdateFromSource(); 27: } 28:   29: private void UpdateFromSource() 30: { 31: var words = File.ReadAllLines(pathToFile); 32: NastyWords = (from w in words 33: select new NastyWord { Word = w }).AsQueryable(); 34: } 35:   36: public IQueryable<NastyWord> NastyWords { get; private set; } 37:   38: public void AddReferenceToCollection(object targetResource, string propertyName, object resourceToBeAdded) 39: { 40: throw new NotImplementedException(); 41: } 42:   43: public void ClearChanges() 44: { 45: pendingUpdates.Clear(); 46: } 47:   48: public object CreateResource(string containerName, string fullTypeName) 49: { 50: var nastyWord = new NastyWord(); 51: pendingUpdates.Add(nastyWord); 52: return nastyWord; 53: } 54:   55: public void DeleteResource(object targetResource) 56: { 57: throw new NotImplementedException(); 58: } 59:   60: public object GetResource(IQueryable query, string fullTypeName) 61: { 62: throw new NotImplementedException(); 63: } 64:   65: public object GetValue(object targetResource, string propertyName) 66: { 67: throw new NotImplementedException(); 68: } 69:   70: public void RemoveReferenceFromCollection(object targetResource, string propertyName, object resourceToBeRemoved) 71: { 72: throw new NotImplementedException(); 73: } 74:   75: public object ResetResource(object resource) 76: { 77: throw new NotImplementedException(); 78: } 79:   80: public object ResolveResource(object resource) 81: { 82: return resource; 83: } 84:   85: public void SaveChanges() 86: { 87: var intersect = (from w in pendingUpdates 88: select w.Word).Intersect(from n in NastyWords 89: select n.Word); 90:   91: if (intersect.Count() > 0) 92: throw new DataServiceException(500, "duplicate entry"); 93:   94: var lines = from w in pendingUpdates 95: select w.Word; 96:   97: File.AppendAllLines(pathToFile, 98: lines, 99: Encoding.UTF8); 100:   101: pendingUpdates.Clear(); 102:   103: UpdateFromSource(); 104: } 105:   106: public void SetReference(object targetResource, string propertyName, object propertyValue) 107: { 108: throw new NotImplementedException(); 109: } 110:   111: public void SetValue(object targetResource, string propertyName, object propertyValue) 112: { 113: targetResource.GetType().GetProperty(propertyName).SetValue(targetResource, propertyValue, null); 114: } 115: } 116:   117: public class NastyWords : DataService<NastyWordsDataSource> 118: { 119: // This method is called only once to initialize service-wide policies. 120: public static void InitializeService(DataServiceConfiguration config) 121: { 122: config.SetEntitySetAccessRule("*", EntitySetRights.AllRead | EntitySetRights.WriteAppend); 123: config.DataServiceBehavior.MaxProtocolVersion = DataServiceProtocolVersion.V2; 124: } 125: } 126: } Next time we’ll allow removing nasty words. Enjoy!

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  • Allow users to view Word documents only and not be able to edit, copy or save them.

    - by Alexander
    Hello In a traditional Windows Server 2003 environment with AD, we have shared a folder for our policy documents (MS Word). These documents get edited/updated now and then by the administrator(principal of college). Users only have read-only access to the folder, but they can still save-as and then change the content. Sharepoint is a possible solution but not easy to implement. We also thought of using a CMS on Linux and installing Joomla to let users only view the docs with a document management system... but is it possible to automatically retrieve the policy folder on the network and convert or put it in a format that users can only view and not copy? We also thought of saving the docs to secure pdf format but the principal wants an automated system. Basically she just wants to work in Word and the policies must be available to staff members on the network. Any ideas? Much appreciated.

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  • How to embed word doc as background picture of an Access report using .EMF or equivalent ?

    - by iDevlop
    My company's standard paper has logo, address and all the details in the right margin with a vertical blue line. I have that as a word template. I want to have the same thing as the background of my Invoices report. I managed to do that 5 years ago by saving to EMF format (vector format, prints out nicely) and putting the file as the background of the report. Now my company is moving, and I need to change the address on my invoices, but I can't find out how I did to convert the word doc to EMF. Any suggestion ? By EMF or another process, but I want to avoid BMP, which is huge and does not print nicely. Thanks !

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  • How can I delete faster? Word boundary backspace?

    - by Yuji Tomita
    I like to type fast. I'm a chronic delete-keyer. I will type first, re-think the output later and hit delete. It seems I'm addicted to always doing something fast. Anyways, I have to tap the delete button very often. Is there a way to do a backspace to word boundary that's native? In a chat box, I can use alt+shift+left to get a word, cmd shift left to get the whole line, etc. but I can't do that in a python shell for example. Any ideas?

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  • Can I use a MIME type declaration to get an HTML file to open in MS Word?

    - by Toph
    Bill James wrote: I was able to render an HTML page with the MIME type set to "application/msword", which caused the browser to spawn Word which imported the html just fine, allowing edits and saving just as if I'd output a real Word doc. That sounds great to me, but I haven't been able to get it to work in any browser (Chrome/FF/Safari/Opera/IE on Win7 running Word 2010 beta). I tried changing the MIME type in the HTTP headers of several pages via Tamper Data to application/msword, and I tried using the http-equiv meta tag <meta http-equiv="Content-type" content="application/msword"> on a local HTML file I tried opening from the browser, but neither appeared to have any effect. I don't really have a clue with regard to HTTP headers and MIME types generally, so - any tips? Many thanks!

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  • Excel Macro to copy an entire row from one sheet to another based upon a single word, within a parag

    - by jason
    Guys i'm looking for a simple excel macro that can copy a row from one sheet to another within excel based upon having a specific word in the cell. I have a sheet one, called "data" and a sheet two called "final". Here is an eaxmple of the data A B C D john mary 555.555.4939 initial reply to phone conversation Jim jack 555.555.5555 floor estimate for bathroom jerry kim 555.555.5553 initial response to phone call I'd like to copy than entire row from sheet "data" to a sheet "final" if the data in column D contains either the word "reply" or the word "response" somewhere within the paragraph. Any tips would be much obliged. thanks, J

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  • [C#] how do I get the height of a rich text content after word wrap?

    - by Led
    Question A. Given 1. A string in rich text format that may have paragraph, tabs, space, line break, indentation, (or even image?) 2. A width for the word wrapping rich text control/editor How do I know the height of the content after it have performed all the word wrapping? Is there something like int MeasureRichTextHeightAfterWordWrap(string aRichTextContent, int aWidth)? Otherwise how does those rich text control know how much to autosize? Do I have to actually place the content on a dummy rich text control and get its height afterwards? Question B. Similar to question A but in plain text onto a plain text memo/control/editor. And manually draw string with manually calculated indentations, breaks, word wrappings. Is it easier or harder?

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