Search Results

Search found 27655 results on 1107 pages for 'visual python'.

Page 550/1107 | < Previous Page | 546 547 548 549 550 551 552 553 554 555 556 557  | Next Page >

  • Setting up boost filesystem

    - by brit
    I've been having serious problems trying to set up boost. I must have installed and uninstalled the libraries a dozen times. In my most recent attempt, I followed these instructions: Download the zip and unzip it. Get the prebuilt jam executable and unzip it. Put that directory in your path. (Edit Path by using Control Panel...System..Advanced....Environemnt Variables) Open Visual Studio command prompt. Browse to boost directory. Run: bjam "-sTOOLS=vc-8_0" install The main reason I'm trying to use boost is for boost/filesystem yet nothing is working. I know this question has been asked before, but it only resulted in more errors.. Please Help!

    Read the article

  • Using PyLab to create a 2D graph from two separate lists

    - by user324333
    Hey Guys, This seems like a basic problem with an easy answer but I simply cannot figure it out no matter how much I try. I am trying to create a line graph based on two lists. For my x-axis, I want my list to be a set of strings. x_axis_list = ["Jan-06","Jul-06","Jan-07","Jul-07","Jan-08"] y_axis_list = [5,7,6,8,9] Any suggestions on how to best graph these items?

    Read the article

  • who can help me install osqa on bluehost?

    - by rutger
    hi all, i've tried to install osqa on bluehost but i simply have to admit that my skills and knowledge are not sufficient. I'm not getting anywhere. Is there anyone that would consider helping me install osqa on my bluehost account. I'm willing to offer a fair compensation for it. kind regards, Rutger

    Read the article

  • why my code print this when i read and write..

    - by zjm1126
    def sss(request): handle=open('b.txt','r+') handle.write("I AM NEW FILE") var=handle.read(); return HttpResponse(var) urlpatterns = patterns('', ('^$',sss), ) 1.my b.txt has nothing 2.when i run my code ,it print this : I AM NEW FILE7 ??; ??x ??v1?pZ€0 ?????8N??p? ? ?) ? ?`16?? S6??? ?? ?@ ??p? {?€1?? V ?? @+ ? ? ? ? ???`? >?) ???@? Z!x`%?p??? ?????@?`7???`? ? ???1X ??????#????€0?(Q??H??P?#? ' ?(5 ?, 7??6H? 0??+?? k%8? `? ??"?` ?? ?0?? ?????/? ????8S1`?`????0? ?`????? ?? ?? ?????@]?HE,????+?+???p? @O??? ?? 37€P6?7?@= ?? ? ?+xP?x???70? ?????? €???€ h *??x ?1???€K ? ??8? ?? ?? ?`?? @?? ????? ?€????????8(?P? ??? p(0B????????? ???? P???? ?/?+?? 9 ? ? ????1???????? ; ?€??€? `?(??? ??+ ??0?? ????6 ?1?,??? {0??? X??€D ??&?€?`? ?H{ ???Xw???? ?? ??0?0?)€Q ?? ?? ? @?????? ?XA6??? O ?0 h ?? ??? ? ? j????0? 57?7@?H+ ?? ? `?? 18? ?P ??6?0????6?? ?a ?` ????????? pG8s???@ ? ? (, ? ( ?? ?+&?????7??!0[ 0m ????@??0?????? ??? p?pZ?+?@?€\1?? 0? ?? ??? ?€;?? ??`? ? ? ????*`7?@? 6 R ?????p?????00^#? ??8? h €,h? ? ??x+ ??€37????`+?P?? 1 ? ?????*??6?? ??h: ??83 ? ????0s ????? ?p? ??????" s?( ??x Q s l??x ndies". * If value is 1, cand{{ value|pluralize:"y,ies" }} displays "1 candy". * If value is 2, cand{{ value|pluralize:"y,ies" }} displays "2 candies". u ,i u i ( RE RG R5 R3 R4 ( R R< R t singular_suffixt plural_suffix( ( s? D:\Python25\lib\site-packages\django\template\defaultfilters.pyt pluralize4 s$ c C s d d k l } | | ? S( sD Takes a phone number and converts it in to its numerical equivalent.i????( t phone2numeric( Rc R ( R R why? thanks

    Read the article

  • Is there a way in Sphinx/Pygments to emphasize one or more lines of code in literal includes?

    - by Casey
    In some sphinx docs I am writing, I am including code samples from an ancillary file like so: .. literalinclude:: mymodule.py :pyobject: MyClass :linenos: This particular doc is a tutorial, where the classes are build up step by step. What I would like to do is include the entire class or a single method, and emphasize only the lines of interest to that section. That way the context is preserved but the interesting parts are obvious at a glance. Right now I have resorted to just referring to line numbers in the text, which is ok, but far from ideal. Looking at the docs and code for sphinx and pygments I don't find an obvious way to do this. I'm not opposed to patching them or doing something tricky in conf.py, but I wondered if anyone had solved this.

    Read the article

  • Silence output from SimpleXMLRPCServer

    - by Corey Goldberg
    I am running an xml-rpc server using SimpleXMLRPCServer from the stdlib. My code looks something like this: import SimpleXMLRPCServer import socket class RemoteStarter: def start(self): return 'foo' rs = RemoteStarter() host = socket.gethostbyaddr(socket.gethostname())[0] port = 9000 server = SimpleXMLRPCServer.SimpleXMLRPCServer((host, port)) server.register_instance(rs) server.serve_forever() every time the 'start' method gets called remotely, the server prints an access line like this: <server_name> - - [10/Mar/2010 13:06:20] "POST /RPC2 HTTP/1.0" 200 - I can't figure out a way to silence the output so it doesn't print these access lines to stdout. anyone?

    Read the article

  • wx paste image into panel

    - by Moayyad Yaghi
    hello i need to find a way to copy an image from a software .. ( microsoft paint for example ) and paste it into my own pain tool that i made using wxpython .. how do i read the image that has been loaded into memory ? so i can paste it hope idea is clear enough thanks in advance

    Read the article

  • Refresh decorator

    - by Morgoth
    I'm trying to write a decorator that 'refreshes' after being called, but where the refreshing only occurs once after the last function exits. Here is an example: @auto_refresh def a(): print "In a" @auto_refresh def b(): print "In b" a() If a() is called, I want the refresh function to be run after exiting a(). If b() is called, I want the refresh function to be run after exiting b(), but not after a() when called by b(). Here is an example of a class that does this: class auto_refresh(object): def __init__(self, f): print "Initializing decorator" self.f = f def __call__(self, *args, **kwargs): print "Before function" if 'refresh' in kwargs: refresh = kwargs.pop('refresh') else: refresh = False self.f(*args, **kwargs) print "After function" if refresh: print "Refreshing" With this decorator, if I run b() print '---' b(refresh=True) print '---' b(refresh=False) I get the following output: Initializing decorator Initializing decorator Before function In b Before function In a After function After function --- Before function In b Before function In a After function After function Refreshing --- Before function In b Before function In a After function After function So when written this way, not specifying the refresh argument means that refresh is defaulted to False. Can anyone think of a way to change this so that refresh is True when not specified? Changing the refresh = False to refresh = True in the decorator does not work: Initializing decorator Initializing decorator Before function In b Before function In a After function Refreshing After function Refreshing --- Before function In b Before function In a After function Refreshing After function Refreshing --- Before function In b Before function In a After function Refreshing After function because refresh then gets called multiple times in the first and second case, and once in the last case (when it should be once in the first and second case, and not in the last case).

    Read the article

  • How to exit an if clause

    - by Roman Stolper
    What sorts of methods exist for prematurely exiting an if clause? There are times when I'm writing code and want to put a break statement inside of an if clause, only to remember that those can only be used for loops. Lets take the following code as an example: if some_condition: ... if condition_a: # do something # and then exit the outer if block ... if condition_b: # do something # and then exit the outer if block # more code here I can think of one way to do this: assuming the exit cases happen within nested if statements, wrap the remaining code in a big else block. Example: if some_condition: ... if condition_a: # do something # and then exit the outer if block else: ... if condition_b: # do something # and then exit the outer if block else: # more code here The problem with this is that more exit locations mean more nesting/indented code. Alternatively, I could write my code to have the if clauses be as small as possible and not require any exits. Does anyone know of a good/better way to exit an if clause? If there are any associated else-if and else clauses, I figure that exiting would skip over them.

    Read the article

  • How to remove a tab attribute in ASP .NET AJAX Toolkit using Regular Expression

    - by Nassign
    I have tried to remove the following tag generated by the AJAX Control toolkit. The scenario is our GUI team used the AJAX control toolkit to make the GUI but I need to move them to normal ASP .NET view tag using MultiView. I want to remove all the __designer: attributes Here is the code <asp:TextBox ID="a" runat="server" __designer:wfdid="w540" /> <asp:DropdownList ID="a" runat="server" __designer:wfdid="w541" /> ..... <asp:DropdownList ID="a" runat="server" __designer:wfdid="w786" /> I tried to use the regular expression find replace in Visual Studio using: Find: :__designer\:wfdid="w{([0-9]+)}" Replace with empty space Can any regular expression expert help?

    Read the article

  • How can this verbose, unpythonic routine be improved?

    - by fmark
    Is there a more pythonic way of doing this? I am trying to find the eight neighbours of an integer coordinate lying within an extent. I am interested in reducing its verbosity without sacrificing execution speed. def fringe8((px, py), (x1, y1, x2, xy)): f = [(px - 1, py - 1), (px - 1, py), (px - 1, py + 1), (px, py - 1), (px, py + 1), (px + 1, py - 1), (px + 1, py), (px + 1, py + 1)] f_inrange = [] for fx, fy in f: if fx < x1: continue if fx >= x2: continue if fy < y1: continue if fy >= y2: continue f_inrange.append((fx, fy)) return f_inrange

    Read the article

  • Django: Save data from form in DB

    - by Anry
    I have a model: class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() For the model I created a class form: class CostForm(ModelForm): class Meta: model = Cost fields = ['date', 'cost'] view.py: def cost(request, offset): if request.method == 'POST': #HOW save data in DB? return HttpResponseRedirect('/') else: form = CostForm() In the template file determined: <form action="/cost/{{ project }}/" method="post" accept-charset="utf-8"> <label for="date">Date:</label><input type="text" name="date" value={{ current_date }} id="date" /> <label for="cost">Cost:</label><input type="text" name="cost" value="0" id="cost" /> <p><input type="submit" value="Add"></p> </form> How save data from form in DB? P.S. offset = project name Model: class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) timestamp = models.DateTimeField() I tried to write: def cost(request, offset): if request.method == 'POST': form = CostForm(request.POST) if form.is_valid(): instance = form.save(commit=False) instance.project = Project.objects.filter(title=offset) instance.date = request.date instance.cost = request.cost instance.save() return HttpResponseRedirect('/') else: form = CostForm() But it does not work :(

    Read the article

  • scoping problem in recursive closure

    - by wiso
    why this work: def function1(): a = 10 def function2(): print a function2() but this not: def function1(): a = 10 def function2(): print a a -= 1 if a>0: function2() function2() error: UnboundLocalError: local variable 'a' referenced before assignment

    Read the article

  • Boost 1.4.0, "assert" identifier not found

    - by Adam Haile
    I'm trying to compile an old project that was originally written for linux on windows. It uses boost 1.4.0, and whenever I compile it throws error C3961: "assert" : identifier not found. I'm using Visual Studio 208 SP1 When I drill down into assert.hpp it includes this: # include <assert.h> // .h to support old libraries w/o <cassert> - effect is the same # define BOOST_ASSERT(expr) assert(expr) BOOST_ASSERT is actually what's failing, and VS doesn't seem to recognize assert() even though assert.h is obviously included. As far as I can tell, all the fails are in files that are part of boost, not my own code, but it throws about 1200 of them. Any ideas how to fix this?

    Read the article

  • Convert a sequence of sequences to a dictionary and vice-versa

    - by louis
    One way to manually persist a dictionary to a database is to flatten it into a sequence of sequences and pass the sequence as an argument to cursor.executemany(). The opposite is also useful, i.e. reading rows from a database and turning them into dictionaries for later use. What's the best way to go from myseq to mydict and from mydict to myseq? >>> myseq = ((0,1,2,3), (4,5,6,7), (8,9,10,11)) >>> mydict = {0: (1, 2, 3), 8: (9, 10, 11), 4: (5, 6, 7)}

    Read the article

  • How to add a separator in a PyGTK combobox?

    - by mkotechno
    I'm using gtk.combo_box_new_text() to make combobox list, this uses a gtk.ListStore to store only strings, so there are some way to add a separator between items without use a complex gtk.TreeModel? If this is not possible, what is the simplest way to use a gtk.TreeModel to able secuential widget addition?

    Read the article

  • C1083 : Permission denied on .sbr files

    - by speps
    Hello, I am using Visual Studio 2005 (with SP1) and I am getting weird errors concerning .sbr files. These files, as I read on MSDN, are intermediate files for BSCMAKE to generate a .bsc file. The errors I get are, for example (on different builds) : 11string.cpp : fatal error C1083: Impossible d'ouvrir le fichier généré(e) par le compilateur : '.\debug\String.sbr' : Permission denied 58type.cpp : fatal error C1083: Impossible d'ouvrir le fichier généré(e) par le compilateur : '.\Debug/Type.sbr' : Permission denied Translation : cannot open compiler intermediate file It seems to be consistent (I have at least 5 or 6 examples like this) with a .cpp file being compiled twice in the same project, respectively : 11String.cpp *some warnings, 2 lines* 11String.cpp 58Type.cpp *some warnings and other files compiled, a lot of lines* 58Type.cpp I already checked the .vcproj files for duplicate entries and it does not seem to be the problem. I would appreciate any help regarding this issue. Deactivating the build of .bsc files seems to be a workaround but maybe someone has better information than this. Thanks.

    Read the article

  • Correct way to detect sequence parameter?

    - by noamtm
    I want to write a function that accepts a parameter which can be either a sequence or a single value. The type of value is str, int, etc., but I don't want it to be restricted to a hardcoded list. In other words, I want to know if the parameter X is a sequence or something I have to convert to a sequence to avoid special-casing later. I could do type(X) in (list, tuple) but there may be other sequence types I'm not aware of, and no common base class. -N. Edit: See my "answer" below for why most of these answers don't help me. Maybe you have something better to suggest.

    Read the article

  • How to change *.ico for button in running mode?

    - by karikari
    I am currently doing visual c++ for an Internet Explorer toolbar button. I have a registration script file (*.rgs) that defines or maybe register the features of my button inside the Windows registry. My objective is, I want my button to change its *.ico image, based on certain conditions process from my *.cpp file. My problem is, I don't understand, how can I somehow change the *.ico file for my button in real time, during my application is running? For example, IF f = 1, ico_file = green.ico; ELSE ico_file = red.ico; Any idea, that you guys can point to me, how can I change the *.ico file for my Internet Explorer toolbar button while the IE is running.

    Read the article

  • Drawing a continuous rectangle

    - by JAYMIN
    Hi..i m currently working on visual c++ 2008 express edition.. in my project i have a picturebox which contains an image, now i have to draw a rectangle to enaable the user to select a part of the image.. I have used the "MouseDown" event of the picturebox and the below code to draw a rectangle: Void pictureBox1_MouseDown(System::Object^ sender, Windows::Forms::MouseEventArgs^ e) { Graphics^ g = pictureBox1-CreateGraphics(); Pen^ pen = gcnew Pen(Color::Blue); g-DrawRectangle( pen , e-X ,e-Y,width,ht); } now in the "DrawRectangle" the arguments "width" and "ht" are static, so the above code results in the drawing of a rectangle at the point where the user presses the mouse button on the image in picturebox... i want to allow the user to be able to drag the cursor and draw a rectangle of size that he wishes to.. Plz help me on this.. Thanx..

    Read the article

  • Scraping a page from a secure URL which is possibly using a session ID

    - by VN44CA
    How to scrape a page like this. https://www.procom.ca/JobList.aspx?keywords=&Cities=&reference=&JobType=0 It is secure, and requires a referrer? I can't get anything using wget or httplib2. If you go through this page, you get a list and it works on a browser but not the command line. https://www.procom.ca/jobsearch.aspx I am interested in command line fetching. thx

    Read the article

  • I'm making a simulated tv

    - by Jam
    I need to make a tv that shows the user the channel and the volume, and shows whether or not the television is on. I have the majority of the code made, but for some reason the channels won't switch. I'm fairly unfamiliar with how properties work, and I think that's what my problem here is. Help please. class Television(object): def __init__(self, __channel=1, volume=1, is_on=0): self.__channel=__channel self.volume=volume self.is_on=is_on def __str__(self): if self.is_on==1: print "The tv is on" print self.__channel print self.volume else: print "The television is off." def toggle_power(self): if self.is_on==1: self.is_on=0 return self.is_on if self.is_on==0: self.is_on=1 return self.is_on def get_channel(self): return channel def set_channel(self, choice): if self.is_on==1: if choice>=0 and choice<=499: channel=self.__channel else: print "Invalid channel!" else: print "The television isn't on!" channel=property(get_channel, set_channel) def raise_volume(self, up=1): if self.is_on==1: self.volume+=up if self.volume>=10: self.volume=10 print "Max volume!" else: print "The television isn't on!" def lower_volume(self, down=1): if self.is_on==1: self.volume-=down if self.volume<=0: self.volume=0 print "Muted!" else: print "The television isn't on!" def main(): tv=Television() choice=None while choice!="0": print \ """ Television 0 - Exit 1 - Toggle Power 2 - Change Channel 3 - Raise Volume 4 - Lower Volume """ choice=raw_input("Choice: ") print if choice=="0": print "Good-bye." elif choice=="1": tv.toggle_power() tv.__str__() elif choice=="2": change=raw_input("What would you like to change the channel to?") tv.set_channel(change) tv.__str__() elif choice=="3": tv.raise_volume() tv.__str__() elif choice=="4": tv.lower_volume() tv.__str__() else: print "\nSorry, but", choice, "isn't a valid choice." main() raw_input("Press enter to exit.")

    Read the article

< Previous Page | 546 547 548 549 550 551 552 553 554 555 556 557  | Next Page >