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  • SQL - How to display the students with the same age?

    - by Cristian
    the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

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  • Catching multiple keystrokes simultaneously in Cocoa

    - by Vinod Kumar
    I have used 4 NSButtons and assigned them to the 4 arrow keys separately to move in four different directions. Now I want to use two keystrokes, left arrow and up arrow together simultaneously, for north east movement, how can I do it? I am only able to use one keystroke at a time , I need to catch two key strokes simultaneously, I need it for my game project.

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  • Lua template processor question

    - by PeterMmm
    I'm going to use that template engine LTP . There is not so much doc available. Now i'm stuck how to pass an environment into the render engine. I have basically this: local ltp = require("ltp.template") ltp.render(io.stdout, 1, "index.dhtm", false, {}, "<?lua", "?>", { total="2400" }) What data structure should be the last parameter (env_code), a string, a table with key=val ?

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  • Table for each region in MySQL

    - by King Wu
    There are four regions with more than one million records total. Should I create a table with a region column or a table for each region and combine them to get the top ranks? If I combine all four regions, none of my columns will be unique so I will need to also add an id column for my primary key. Otherwise, name, accountId & characterId would be candidate keys or should I just add an id column anyways. Table: ---------------------------------------------------------------- | name | accountId | iconId | level | characterId | updateDate | ----------------------------------------------------------------

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  • retrive my posted data from facebook

    - by hardik
    hello all i am able to connect to facebook through api key from my native iphone application i can also send my post to the facebook through my application but i want to retrive that same post into my application please guide me how could i do that thanks in advance

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  • spring mvc, css and javascript is not working properly

    - by user2788424
    the css and javascript is not take effect on my page. I google online, people saying this is the magic, but not happening on my page. <mvc:resources mapping="/resources/**" location="/resources/" /> this is the error: Nov 02, 2013 9:19:29 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/myweb/resources/css/styles.css] in DispatcherServlet with name 'dispatcher' Nov 02, 2013 9:19:29 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/myweb/resources/script.js] in DispatcherServlet with name 'dispatcher' Nov 02, 2013 9:19:29 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/myweb/resources/js/jquery-1.10.2.min.js] in DispatcherServlet with name 'dispatcher' here is the applicationContext.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.2.xsd"> <context:component-scan base-package="org.peterhuang.myweb" /> <mvc:resources mapping="/resources/**" location="/resources/" /> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> </bean> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"> </bean> <!-- Hibernate Transaction Manager --> <bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> <mvc:annotation-driven /> <!-- Activates annotation based transaction management --> <tx:annotation-driven /> <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location" value="classpath:jdbc.properties" /> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/"></property> <property name="suffix" value=".jsp"></property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="packagesToScan" value="org.peterhuang.myweb" /> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect"> ${jdbc.dialect} </prop> <prop key="hibernate.show_sql"> ${hibernate.show_sql} </prop> <prop key="hibernate.format_sql"> ${hibernate.format_sql} </prop> </props> </property> </bean> here is the web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <display-name>my web</display-name> <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/applicationContext.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <welcome-file-list> <welcome-file>/WEB-INF/jsp/welcome.jsp</welcome-file> </welcome-file-list> this is the page got displaied: <%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%> <%@ taglib uri="http://www.springframework.org/tags" prefix="spring"%> <link type="text/css" rel="stylesheet" href="<spring:url value='resources/css/styles.css' />" /> <script type="text/javascript" src="<spring:url value='resources/js/jquery-1.10.2.min.js' />"></script> <script type="text/javascript" src="<spring:url value='resources/script.js'/>"</script> <ul id="button"> <c:forEach var="category" items="${categoryList}"> <li><a href="#">${category.categoryName}</a></li> </c:forEach> </ul> the folder structure in eclipse: myweb | | | |----Java Resources | | | | | |-----src/main/resources | | | | | | | | |------js | | | | | | | |-----jquery-1.10.2.min.js | | | | | | | | | | | |-----script.js | | | | | | | | |-----css | | | | | | | |-----style.css | | | | | | | | any tips would be appreciated!! thanks in advanced!

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  • How to compress/decompress a long query string in PHP?

    - by jodeci
    I doubt if this is encryption but I can't find a better phrase. I need to pass a long query string like this: http://test.com/test.php?key=[some_very_loooooooooooooooooooooooong_query_string] The query string contains NO sensitive information so I'm not really concerned about security in this case. It's just...well, too long and ugly. Is there a library function that can let me encode/encrypt/compress the query string into something similar to the result of a md5() (similar as in, always a 32 character string), but decode/decrypt/decompress-able?

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  • MySQL: count enumerated values?

    - by John Isaacks
    If my table looks like this: daily_individual_tracking', 'CREATE TABLE `daily_individual_tracking` ( `daily_individual_tracking_id` int(10) unsigned NOT NULL auto_increment, `daily_individual_tracking_date` date NOT NULL default ''0000-00-00'', `sales` enum(''no'',''yes'') NOT NULL COMMENT ''no'', `repairs` enum(''no'',''yes'') NOT NULL COMMENT ''no'', `shipping` enum(''no'',''yes'') NOT NULL COMMENT ''no'', PRIMARY KEY (`daily_individual_tracking_id`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1 basically the fields can be either yes or no. How can I count how many yes's their are for each column over a date range? Thanks!!

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  • No unique bean of type [javax.persistence.EntityManager] is defined

    - by sebajb
    I am using JUnit 4 to test Dao Access with Spring (annotations) and JPA (hibernate). The datasource is configured through JNDI(Weblogic) with an ORacle(Backend). This persistence is configured with just the name and a RESOURCE_LOCAL transaction-type The application context file contains notations for annotations, JPA config, transactions, and default package and configuration for annotation detection. I am using Junit4 like so: ApplicationContext <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="workRequest"/> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="databasePlatform" value="${database.target}"/> <property name="showSql" value="${database.showSql}" /> <property name="generateDdl" value="${database.generateDdl}" /> </bean> </property> </bean> <bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName"> <value>workRequest</value> </property> <property name="jndiEnvironment"> <props> <prop key="java.naming.factory.initial">weblogic.jndi.WLInitialContextFactory</prop> <prop key="java.naming.provider.url">t3://localhost:7001</prop> </props> </property> </bean> <bean id="txManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <bean class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor"/> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> JUnit TestCase @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = { "classpath:applicationContext.xml" }) public class AssignmentDaoTest { private AssignmentDao assignmentDao; @Test public void readAll() { assertNotNull("assignmentDao cannot be null", assignmentDao); List assignments = assignmentDao.findAll(); assertNotNull("There are no assignments yet", assignments); } } regardless of what changes I make I get: No unique bean of type [javax.persistence.EntityManager] is defined Any hint on what this could be. I am running the tests inside eclipse.

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  • SSAS error when deploying cube in BIDs

    - by user282382
    I am getting the following error when deploying. This is in a cube which was working fine, all that has changed is a key column in one of the dimensions. Internal error: Failed to generate a hash string I have no idea what is causing this but even if I change the dimension back to how it was and try to deploy I get the same error. If anyone has seen this or knows how to fix it please respond.

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  • Pass certificate to j2me

    - by user326096
    I created a certificate on apache server. x.509 public key certificate RSA created using the keytool I need to pass this to a J2me app, via http. So the J2me app can encrypt data How do I do this.

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  • "Forwarding" keypresses from an applet to a JFrame

    - by hansengel
    I have a JFrame which contains a JApplet. There are shortcut keys that I have configured for the JFrame that work fine when the focus is on some panel of it, but once I click into the applet, none of the shortcut keys work anymore. Is there any way that I can forward these key presses to the JFrame so that the events are still fired?

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  • Decoding http response with certificate

    - by Tim
    Hi all, I'm new to php and I need to authenticate to a SSO server. The SSO server is a .Net one, using a SSL certificate. When I go back from the SSO server, the response is encoded. I have the key of the certificate of course, but how could I decrypt the response ? This is very vague for me, don't hesitate to detail your answer :) Many thanks in advance for your help, best regards

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  • How to use Linq To Sql to get Users who has less than 2 photos?

    - by Mike108
    The scenario is I want to get the users who has less than 2 photos. There are two table: [Users] (UserId, UserName) [UserPhotos] (PhotoId, PhotoName, UserId) UserId is a Foreign Key but I do not want to use association like user.Photos. A user may have none photo in the [UserPhotos] table. How to use Linq To Sql to get List<User> who has less than 2 photos?

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  • How to get last full MS SQL Server error message?

    - by JohnM2
    I am aware of: SELECT @@ERROR but it will give me only an ERROR CODE (a number) and I need a full text message like: Cannot insert duplicate key row in object 'dbo.TABLE_NAME' with unique index 'IX_ID_unique'. The statement has been terminated. How can I do that in MS Sql Server 2005 ?

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  • Encrypt file using M2Crypto

    - by Bear
    It is known that I can read the whole file content in memory and encrypt it using the following code. contents = fin.read() cipher = M2Crypto.EVP.Cipher(alg="aes_128_cbc", key = aes_key, iv = aes_iv, op = 1) encryptedContents = cipher.update(contents) encryptedContents += cipher.final() But what if the file size is large, is there a way for me to pass the input stream to M2Crypto instead of reading the whole file first?

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  • gae error:AttributeError: 'NoneType' object has no attribute 'user_is_member'

    - by zjm1126
    class Thread(db.Model): members = db.StringListProperty() def user_is_member(self, user): return str(user) in self.members and thread = Thread.get(db.Key.from_path('Thread', int(id))) is_member = thread.user_is_member(user) but the error is : Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 511, in __call__ handler.get(*groups) File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\util.py", line 62, in check_login handler_method(self, *args) File "D:\zjm_code\forum_blog_gae\main.py", line 222, in get is_member = thread.user_is_member(user) AttributeError: 'NoneType' object has no attribute 'user_is_member' why ? thanks

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  • Does Lua support Unicode?

    - by TimK
    Based on the link below, I'm confused as to whether the Lua programming language supports Unicode. http://lua-users.org/wiki/LuaUnicode It appears it does but has limitations. I simply don't understand, are the limitation anything big/key or not a big deal?

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  • Generating report with MySQL and Rails - how?

    - by Arywista
    Here is my data model from my application: id :integer(4) not null, primary key spam :boolean(1) not null duplicate :boolean(1) not null ignore :boolean(1) not null brand_id :integer(4) not null attitude :string not null posted_at :datetime not null Attitude could have 3 states: negative, positive, neutral. I want to generate resultset in table, this way, for each day between start and end date: date | total | positive | neutral | negative 2009-10-10 | 12 | 4 | 7 | 1 (...) 2009-10-30 | 5 | 2 | 1 | 1 And ignore all records which have: duplicate = true ignore = true spam = true How it's could be done?

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  • Java Double entry table

    - by Tom
    Hi, Does anyone know a double entry table implementation in java I can download ? I need to do something like this 1 2 3 _______ a| x y z b| h l m c| o a k table.get(a,1) would return x Of course, it should use any Object as key, value, etc Thanks in advance

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