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  • Encrypt images before uploading to Dropbox [migrated]

    - by Cherry
    I want to encrypt a file first before the file will be uploaded to the dropbox. So i have implement the encryption inside the uploading of the codes. However, there is an error after i integrate the codes together. Where did my mistake go wrong? Error at putFileOverwriteRequest and it says The method putFileOverwriteRequest(String, InputStream, long, ProgressListener) in the type DropboxAPI is not applicable for the arguments (String, FileOutputStream, long, new ProgressListener(){}) Another problem is that this FileOutputStream fis = new FileOutputStream(new File("dont know what to put in this field")); i do not know where to put the file so that after i read the file, it will call the path and then upload to the Dropbox. Anyone is kind to help me in this? As time is running out for me and i still cant solve the problem. Thank you in advance. The full code is as below. public class UploadPicture extends AsyncTask<Void, Long, Boolean> { private DropboxAPI<?> mApi; private String mPath; private File mFile; private long mFileLen; private UploadRequest mRequest; private Context mContext; private final ProgressDialog mDialog; private String mErrorMsg; public UploadPicture(Context context, DropboxAPI<?> api, String dropboxPath, File file) { // We set the context this way so we don't accidentally leak activities mContext = context.getApplicationContext(); mFileLen = file.length(); mApi = api; mPath = dropboxPath; mFile = file; mDialog = new ProgressDialog(context); mDialog.setMax(100); mDialog.setMessage("Uploading " + file.getName()); mDialog.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL); mDialog.setProgress(0); mDialog.setButton("Cancel", new OnClickListener() { public void onClick(DialogInterface dialog, int which) { // This will cancel the putFile operation mRequest.abort(); } }); mDialog.show(); } @Override protected Boolean doInBackground(Void... params) { try { KeyGenerator keygen = KeyGenerator.getInstance("DES"); SecretKey key = keygen.generateKey(); //generate key //encrypt file here first byte[] plainData; byte[] encryptedData; Cipher cipher = Cipher.getInstance("DES/ECB/PKCS5Padding"); cipher.init(Cipher.ENCRYPT_MODE, key); //File f = new File(mFile); //read file FileInputStream in = new FileInputStream(mFile); //obtains input bytes from a file plainData = new byte[(int)mFile.length()]; in.read(plainData); //Read bytes of data into an array of bytes encryptedData = cipher.doFinal(plainData); //encrypt data FileOutputStream fis = new FileOutputStream(new File("dont know what to put in this field")); //upload to a path first then call the path so that it can be uploaded up to the dropbox //save encrypted file to dropbox // By creating a request, we get a handle to the putFile operation, // so we can cancel it later if we want to //FileInputStream fis = new FileInputStream(mFile); String path = mPath + mFile.getName(); mRequest = mApi.putFileOverwriteRequest(path, fis, mFile.length(), new ProgressListener() { @Override public long progressInterval() { // Update the progress bar every half-second or so return 500; } @Override public void onProgress(long bytes, long total) { publishProgress(bytes); } }); if (mRequest != null) { mRequest.upload(); return true; } } catch (DropboxUnlinkedException e) { // This session wasn't authenticated properly or user unlinked mErrorMsg = "This app wasn't authenticated properly."; } catch (DropboxFileSizeException e) { // File size too big to upload via the API mErrorMsg = "This file is too big to upload"; } catch (DropboxPartialFileException e) { // We canceled the operation mErrorMsg = "Upload canceled"; } catch (DropboxServerException e) { // Server-side exception. These are examples of what could happen, // but we don't do anything special with them here. if (e.error == DropboxServerException._401_UNAUTHORIZED) { // Unauthorized, so we should unlink them. You may want to // automatically log the user out in this case. } else if (e.error == DropboxServerException._403_FORBIDDEN) { // Not allowed to access this } else if (e.error == DropboxServerException._404_NOT_FOUND) { // path not found (or if it was the thumbnail, can't be // thumbnailed) } else if (e.error == DropboxServerException._507_INSUFFICIENT_STORAGE) { // user is over quota } else { // Something else } // This gets the Dropbox error, translated into the user's language mErrorMsg = e.body.userError; if (mErrorMsg == null) { mErrorMsg = e.body.error; } } catch (DropboxIOException e) { // Happens all the time, probably want to retry automatically. mErrorMsg = "Network error. Try again."; } catch (DropboxParseException e) { // Probably due to Dropbox server restarting, should retry mErrorMsg = "Dropbox error. Try again."; } catch (DropboxException e) { // Unknown error mErrorMsg = "Unknown error. Try again."; } catch (FileNotFoundException e) { } return false; } @Override protected void onProgressUpdate(Long... progress) { int percent = (int)(100.0*(double)progress[0]/mFileLen + 0.5); mDialog.setProgress(percent); } @Override protected void onPostExecute(Boolean result) { mDialog.dismiss(); if (result) { showToast("Image successfully uploaded"); } else { showToast(mErrorMsg); } } private void showToast(String msg) { Toast error = Toast.makeText(mContext, msg, Toast.LENGTH_LONG); error.show(); } }

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  • How do I configure upstart to run a script on shutdown when the process takes longer than 10secs?

    - by Tiris
    I am running ubuntu 11.10 in a virtual machine (VirtualBox) to learn more about development in linux. I am using a git repository to save my work and have written a script to bundle my work up and save it to the shared folder for use while the virtual machine is not running. I would like to automatically run this script before shutdown so that my work is always available if the vm is off (currently I have to manually run the script). I don't know if upstart is the best way to accomplish this, but this is the config that I wrote as a test: description "test script to run at shutdown" start on runlevel [056] task script touch /media/sf_LinuxEducation/start sleep 15 touch /media/sf_LinuxEducation/start-long end script pre-start script touch /media/sf_LinuxEducation/pre-start sleep 15 touch /media/sf_LinuxEducation/pre-start-long end script post-start script touch /media/sf_LinuxEducation/post-start sleep 15 touch /media/sf_LinuxEducation/post-start-long end script pre-stop script touch /media/sf_LinuxEducation/pre-stop sleep 15 touch /media/sf_LinuxEducation/pre-stop-long end script post-stop script touch /media/sf_LinuxEducation/post-stop sleep 15 touch /media/sf_LinuxEducation/post-stop-long end script The result is that only one touch is accomplished (the first touch in pre-start). What do I need to change to see one of the touches after the sleep to work? Or Is there an easier way to get this accomplished? Thanks in advance.

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  • Getting timing consistency in Linux

    - by Jim Hunziker
    I can't seem to get a simple program (with lots of memory access) to achieve consistent timing in Linux. I'm using a 2.6 kernel, and the program is being run on a dual-core processor with realtime priority. I'm trying to disable cache effects by declaring the memory arrays as volatile. Below are the results and the program. What are some possible sources of the outliers? Results: Number of trials: 100 Range: 0.021732s to 0.085596s Average Time: 0.058094s Standard Deviation: 0.006944s Extreme Outliers (2 SDs away from mean): 7 Average Time, excluding extreme outliers: 0.059273s Program: #include <stdio.h> #include <stdlib.h> #include <math.h> #include <sched.h> #include <sys/time.h> #define NUM_POINTS 5000000 #define REPS 100 unsigned long long getTimestamp() { unsigned long long usecCount; struct timeval timeVal; gettimeofday(&timeVal, 0); usecCount = timeVal.tv_sec * (unsigned long long) 1000000; usecCount += timeVal.tv_usec; return (usecCount); } double convertTimestampToSecs(unsigned long long timestamp) { return (timestamp / (double) 1000000); } int main(int argc, char* argv[]) { unsigned long long start, stop; double times[REPS]; double sum = 0; double scale, avg, newavg, median; double stddev = 0; double maxval = -1.0, minval = 1000000.0; int i, j, freq, count; int outliers = 0; struct sched_param sparam; sched_getparam(getpid(), &sparam); sparam.sched_priority = sched_get_priority_max(SCHED_FIFO); sched_setscheduler(getpid(), SCHED_FIFO, &sparam); volatile float* data; volatile float* results; data = calloc(NUM_POINTS, sizeof(float)); results = calloc(NUM_POINTS, sizeof(float)); for (i = 0; i < REPS; ++i) { start = getTimestamp(); for (j = 0; j < NUM_POINTS; ++j) { results[j] = data[j]; } stop = getTimestamp(); times[i] = convertTimestampToSecs(stop-start); } free(data); free(results); for (i = 0; i < REPS; i++) { sum += times[i]; if (times[i] > maxval) maxval = times[i]; if (times[i] < minval) minval = times[i]; } avg = sum/REPS; for (i = 0; i < REPS; i++) stddev += (times[i] - avg)*(times[i] - avg); stddev /= REPS; stddev = sqrt(stddev); for (i = 0; i < REPS; i++) { if (times[i] > avg + 2*stddev || times[i] < avg - 2*stddev) { sum -= times[i]; outliers++; } } newavg = sum/(REPS-outliers); printf("Number of trials: %d\n", REPS); printf("Range: %fs to %fs\n", minval, maxval); printf("Average Time: %fs\n", avg); printf("Standard Deviation: %fs\n", stddev); printf("Extreme Outliers (2 SDs away from mean): %d\n", outliers); printf("Average Time, excluding extreme outliers: %fs\n", newavg); return 0; }

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  • Tiff Analyzer

    - by Kevin
    I am writing a program to convert some data, mainly a bunch of Tiff images. Some of the Tiffs seems to have a minor problem with them. They show up fine in some viewers (Irfanview, client's old system) but not in others (Client's new system, Window's picture and fax viewer). I have manually looked at the binary data and all the tags seem ok. Can anyone recommend an app that can analyze it and tell me what, if anything, is wrong with it? Also, for clarity sake, I'm only converting the data about the images which is stored seperately in a database and copying the images, I'm not editting the images myself, so I'm pretty sure I'm not messing them up. UDPATE: For anyone interested, here are the tags from a good and bad file: BAD Tag Type Length Value 256 Image Width SHORT 1 1652 257 Image Length SHORT 1 704 258 Bits Per Sample SHORT 1 1 259 Compression SHORT 1 4 262 Photometric SHORT 1 0 266 Fill Order SHORT 1 1 273 Strip Offsets LONG 1 210 (d2 Hex) 274 Orientation SHORT 1 3 277 Samples Per Pixel SHORT 1 1 278 Rows Per Strip SHORT 1 450 279 Strip Byte Counts LONG 1 7264 (1c60 Hex) 282 X Resolution RATIONAL 1 <194 200 / 1 = 200.000 283 Y Resolution RATIONAL 1 <202 200 / 1 = 200.000 284 Planar Configuration SHORT 1 1 296 Resolution Unit SHORT 1 2 Good Tag Type Length Value 254 New Subfile Type LONG 1 0 (0 Hex) 256 Image Width SHORT 1 1193 257 Image Length SHORT 1 788 258 Bits Per Sample SHORT 1 1 259 Compression SHORT 1 4 262 Photometric SHORT 1 0 266 Fill Order SHORT 1 1 270 Image Description ASCII 45 256 273 Strip Offsets LONG 1 1118 (45e Hex) 274 Orientation SHORT 1 1 277 Samples Per Pixel SHORT 1 1 278 Rows Per Strip LONG 1 788 (314 Hex) 279 Strip Byte Counts LONG 1 496 (1f0 Hex) 280 Min Sample Value SHORT 1 0 281 Max Sample Value SHORT 1 1 282 X Resolution RATIONAL 1 <301 200 / 1 = 200.000 283 Y Resolution RATIONAL 1 <309 200 / 1 = 200.000 284 Planar Configuration SHORT 1 1 293 Group 4 Options LONG 1 0 (0 Hex) 296 Resolution Unit SHORT 1 2

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  • JAVA image transfer problem

    - by user579098
    Hi, I have a school assignment, to send a jpg image,split it into groups of 100 bytes, corrupt it, use a CRC check to locate the errors and re-transmit until it eventually is built back into its original form. It's practically ready, however when I check out the new images, they appear with errors.. I would really appreciate if someone could look at my code below and maybe locate this logical mistake as I can't understand what the problem is because everything looks ok :S For the file with all the data needed including photos and error patterns one could download it from this link:http://rapidshare.com/#!download|932tl2|443122762|Data.zip|739 Thanks in advance, Stefan p.s dont forget to change the paths in the code for the image and error files package networks; import java.io.*; // for file reader import java.util.zip.CRC32; // CRC32 IEEE (Ethernet) public class Main { /** * Reads a whole file into an array of bytes. * @param file The file in question. * @return Array of bytes containing file data. * @throws IOException Message contains why it failed. */ public static byte[] readFileArray(File file) throws IOException { InputStream is = new FileInputStream(file); byte[] data=new byte[(int)file.length()]; is.read(data); is.close(); return data; } /** * Writes (or overwrites if exists) a file with data from an array of bytes. * @param file The file in question. * @param data Array of bytes containing the new file data. * @throws IOException Message contains why it failed. */ public static void writeFileArray(File file, byte[] data) throws IOException { OutputStream os = new FileOutputStream(file,false); os.write(data); os.close(); } /** * Converts a long value to an array of bytes. * @param data The target variable. * @return Byte array conversion of data. * @see http://www.daniweb.com/code/snippet216874.html */ public static byte[] toByta(long data) { return new byte[] { (byte)((data >> 56) & 0xff), (byte)((data >> 48) & 0xff), (byte)((data >> 40) & 0xff), (byte)((data >> 32) & 0xff), (byte)((data >> 24) & 0xff), (byte)((data >> 16) & 0xff), (byte)((data >> 8) & 0xff), (byte)((data >> 0) & 0xff), }; } /** * Converts a an array of bytes to long value. * @param data The target variable. * @return Long value conversion of data. * @see http://www.daniweb.com/code/snippet216874.html */ public static long toLong(byte[] data) { if (data == null || data.length != 8) return 0x0; return (long)( // (Below) convert to longs before shift because digits // are lost with ints beyond the 32-bit limit (long)(0xff & data[0]) << 56 | (long)(0xff & data[1]) << 48 | (long)(0xff & data[2]) << 40 | (long)(0xff & data[3]) << 32 | (long)(0xff & data[4]) << 24 | (long)(0xff & data[5]) << 16 | (long)(0xff & data[6]) << 8 | (long)(0xff & data[7]) << 0 ); } public static byte[] nextNoise(){ byte[] result=new byte[100]; // copy a frame's worth of data (or remaining data if it is less than frame length) int read=Math.min(err_data.length-err_pstn, 100); System.arraycopy(err_data, err_pstn, result, 0, read); // if read data is less than frame length, reset position and add remaining data if(read<100){ err_pstn=100-read; System.arraycopy(err_data, 0, result, read, err_pstn); }else // otherwise, increase position err_pstn+=100; // return noise segment return result; } /** * Given some original data, it is purposefully corrupted according to a * second data array (which is read from a file). In pseudocode: * corrupt = original xor corruptor * @param data The original data. * @return The new (corrupted) data. */ public static byte[] corruptData(byte[] data){ // get the next noise sequence byte[] noise = nextNoise(); // finally, xor data with noise and return result for(int i=0; i<100; i++)data[i]^=noise[i]; return data; } /** * Given an array of data, a packet is created. In pseudocode: * frame = corrupt(data) + crc(data) * @param data The original frame data. * @return The resulting frame data. */ public static byte[] buildFrame(byte[] data){ // pack = [data]+crc32([data]) byte[] hash = new byte[8]; // calculate crc32 of data and copy it to byte array CRC32 crc = new CRC32(); crc.update(data); hash=toByta(crc.getValue()); // create a byte array holding the final packet byte[] pack = new byte[data.length+hash.length]; // create the corrupted data byte[] crpt = new byte[data.length]; crpt = corruptData(data); // copy corrupted data into pack System.arraycopy(crpt, 0, pack, 0, crpt.length); // copy hash into pack System.arraycopy(hash, 0, pack, data.length, hash.length); // return pack return pack; } /** * Verifies frame contents. * @param frame The frame data (data+crc32). * @return True if frame is valid, false otherwise. */ public static boolean verifyFrame(byte[] frame){ // allocate hash and data variables byte[] hash=new byte[8]; byte[] data=new byte[frame.length-hash.length]; // read frame into hash and data variables System.arraycopy(frame, frame.length-hash.length, hash, 0, hash.length); System.arraycopy(frame, 0, data, 0, frame.length-hash.length); // get crc32 of data CRC32 crc = new CRC32(); crc.update(data); // compare crc32 of data with crc32 of frame return crc.getValue()==toLong(hash); } /** * Transfers a file through a channel in frames and reconstructs it into a new file. * @param jpg_file File name of target file to transfer. * @param err_file The channel noise file used to simulate corruption. * @param out_file The name of the newly-created file. * @throws IOException */ public static void transferFile(String jpg_file, String err_file, String out_file) throws IOException { // read file data into global variables jpg_data = readFileArray(new File(jpg_file)); err_data = readFileArray(new File(err_file)); err_pstn = 0; // variable that will hold the final (transfered) data byte[] out_data = new byte[jpg_data.length]; // holds the current frame data byte[] frame_orig = new byte[100]; byte[] frame_sent = new byte[100]; // send file in chunks (frames) of 100 bytes for(int i=0; i<Math.ceil(jpg_data.length/100); i++){ // copy jpg data into frame and init first-time switch System.arraycopy(jpg_data, i*100, frame_orig, 0, 100); boolean not_first=false; System.out.print("Packet #"+i+": "); // repeat getting same frame until frame crc matches with frame content do { if(not_first)System.out.print("F"); frame_sent=buildFrame(frame_orig); not_first=true; }while(!verifyFrame(frame_sent)); // usually, you'd constrain this by time to prevent infinite loops (in // case the channel is so wacked up it doesn't get a single packet right) // copy frame to image file System.out.println("S"); System.arraycopy(frame_sent, 0, out_data, i*100, 100); } System.out.println("\nDone."); writeFileArray(new File(out_file),out_data); } // global variables for file data and pointer public static byte[] jpg_data; public static byte[] err_data; public static int err_pstn=0; public static void main(String[] args) throws IOException { // list of jpg files String[] jpg_file={ "C:\\Users\\Stefan\\Desktop\\Data\\Images\\photo1.jpg", "C:\\Users\\Stefan\\Desktop\\Data\\Images\\photo2.jpg", "C:\\Users\\Stefan\\Desktop\\Data\\Images\\photo3.jpg", "C:\\Users\\Stefan\\Desktop\\Data\\Images\\photo4.jpg" }; // list of error patterns String[] err_file={ "C:\\Users\\Stefan\\Desktop\\Data\\Error Pattern\\Error Pattern 1.DAT", "C:\\Users\\Stefan\\Desktop\\Data\\Error Pattern\\Error Pattern 2.DAT", "C:\\Users\\Stefan\\Desktop\\Data\\Error Pattern\\Error Pattern 3.DAT", "C:\\Users\\Stefan\\Desktop\\Data\\Error Pattern\\Error Pattern 4.DAT" }; // loop through all jpg/channel combinations and run tests for(int x=0; x<jpg_file.length; x++){ for(int y=0; y<err_file.length; y++){ System.out.println("Transfering photo"+(x+1)+".jpg using Pattern "+(y+1)+"..."); transferFile(jpg_file[x],err_file[y],jpg_file[x].replace("photo","CH#"+y+"_photo")); } } } }

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  • Shift count negative or too big error - correct solution?

    - by PeterK
    I have the following function for reading a big-endian quadword (in a abstract base file I/O class): unsigned long long CGenFile::readBEq(){ unsigned long long qT = 0; qT |= readb() << 56; qT |= readb() << 48; qT |= readb() << 40; qT |= readb() << 32; qT |= readb() << 24; qT |= readb() << 16; qT |= readb() << 8; qT |= readb() << 0; return qT; } The readb() functions reads a BYTE. Here are the typedefs used: typedef unsigned char BYTE; typedef unsigned short WORD; typedef unsigned long DWORD; The thing is that i get 4 compiler warnings on the first four lines with the shift operation: warning C4293: '<<' : shift count negative or too big, undefined behavior I understand why this warning occurs, but i can't seem to figure out how to get rid of it correctly. I could do something like: qT |= (unsigned long long)readb() << 56; This removes the warning, but isn't there any other problem, will the BYTE be correctly extended all the time? Maybe i'm just thinking about it too much and the solution is that simple. Can you guys help me out here? Thanks.

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  • Overlay an HTML page with an HTML form

    - by jah
    Hi folks, this is a question about the best way (or least effort of the best ways) to overlay an html page with a form. Best in this context meaning best user experience whilst meeting the functional requirements. Let's say I have a page with a short form on it; the user has to enter some financial details. To assist the user to enter an accurate value for one of the fields there's another, much longer form. The longer form needs to be displayed only if the user requests the help. For users without javascript, clicking a link will submit the short form (persisting already filled fields in a session) and the server will respond with the long form. They'll submit the long form and the server will combine the submitted data with the persisted data and serve the short form again - with the fields populated. For users with javascript I want to overlay the short form page (in a lightbox stylee) with the long form, allow them to populate the long form and then go back to the short form with less round-trips to the server. Do I: Overlay the short form page with an iframe whose target is the long form? Request the long form over ajax and stuff it into a div? Generate the long form entirely on the client-side? Some other wizadry I haven't thought of? A short explanation of the best mechanism will do me very nicely indeed. Thank you very much!

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  • Function approximation with Maclaurin series

    - by marines
    I need to approx (1-x)^0.25 with given accuracy (0.0001 e.g.). I'm using expansion found on Wikipedia for (1+x)^0.25. I need to stop approximating when current expression is less than the accuracy. long double s(long double x, long double d) { long double w = 1; long double n = 1; // nth expression in series long double tmp = 1; // sum while last expression is greater than accuracy while (fabsl(tmp) >= d) { tmp *= (1.25 / n - 1) * (-x); // the next expression w += tmp; // is added to approximation n++; } return w; } Don't mind long double n. :P This works well when I'm not checking value of current expression but when I'm computing 1000 or more expressions. Domain of the function is <-1;1 and s() calculates approximation well for x in <-1;~0.6. The bigger the argument is the bigger is the error of calculation. From 0.6 it exceeds the accuracy. I'm not sure if the problem is clear enough because I don't know English math language well. The thing is what's the matter with while condition and why the function s() doesn't approximate correctly.

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  • using JMock to write unit test for a simple spring JDBC DAO

    - by Quincy
    I'm writing an unit test for spring jdbc dao. The method to test is: public long getALong() { return simpleJdbcTemplate.queryForObject("sql query here", new RowMapper<Long>() { public Long mapRow(ResultSet resultSet, int i) throws SQLException { return resultSet.getLong("a_long"); } }); } Here is what I have in the test: public void testGetALong() throws Exception { final Long result = 1000L; context.checking(new Expectations() {{ oneOf(simpleJdbcTemplate).queryForObject("sql_query", new RowMapper<Long>() { public Long mapRow(ResultSet resultSet, int i) throws SQLException { return resultSet.getLong("a_long"); } }); will(returnValue(result)); }}); Long seq = dao.getALong(); context.assertIsSatisfied(); assertEquals(seq, result); } Naturally, the test doesn't work (otherwise, I wouldn't be asking this question here). The problem is the rowmapper in the test is different from the rowmapper in the DAO. So the expectation is not met. I tried to put with around the sql query and with(any(RowMapper.class)) for the rowmapper. It wouldn't work either, complains about "not all parameters were given explicit matchers: either all parameters must be specified by matchers or all must be specified by values, you cannot mix matchers and values"

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  • jQuery Accordion: IE animation issues

    - by Nathan Long
    Update I am making this a community wiki, for three reasons: I don't feel like I got a definitive answer, but I have long since stopped needing an answer, because I rolled my own accordion function this question gets tons of views, so clearly lots of people are still interested So if anybody wants to change/clarify this question and make it a definitive guide, be my guest. I'm working on a page using jQuery's accordion UI element. I modeled my HTML on that example, except that inside the <li> elements, I have some unordered lists of links. Like this: $(document).ready(function() { $(".ui-accordion-container").accordion( {active: "a.default", alwaysOpen: true, autoHeight: false} ); }); <ul class="ui-accordion-container"> <li> <!-- Start accordion section --> <a href='#' class="accordion-label">A Group of Links</a> <ul class="linklist"> <li><a href="http://example.com">Example Link</a></li> <li><a href="http://example.com">Example Link</a></li> </ul> <!--and of course there's another group --> Problem: IE Animation stinks Although IE7 animates the documentation's example accordion menu just fine, it has problems with mine. Specifically, one accordion menu on the page moves jerkily and has flashes of content. I know that it's not a CSS issue because the same thing happens if I don't include my CSS files. The other accordion menu on the page opens the first section you click and, after that, won't open any of them. Both of these problems are IE-specific, and both go away if I use the option animated: false. But I'd like to keep the default slide animation, since it helps the user understand what the menu is doing. Is there another way?

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  • Performance Difference between HttpContext user and Thread user

    - by atrueresistance
    I am wondering what the difference between HttpContext.Current.User.Identity.Name.ToString.ToLower and Thread.CurrentPrincipal.Identity.Name.ToString.ToLower. Both methods grab the username in my asp.net 3.5 web service. I decided to figure out if there was any difference in performance using a little program. Running from full Stop to Start Debugging in every run. Dim st As DateTime = DateAndTime.Now Try 'user = HttpContext.Current.User.Identity.Name.ToString.ToLower user = Thread.CurrentPrincipal.Identity.Name.ToString.ToLower Dim dif As TimeSpan = Now.Subtract(st) Dim break As String = "nothing" Catch ex As Exception user = "Undefined" End Try I set a breakpoint on break to read the value of dif. The results were the same for both methods. dif.Milliseconds 0 Integer dif.Ticks 0 Long Using a longer duration, loop 5,000 times results in these figures. Thread Method run 1 dif.Milliseconds 125 Integer dif.Ticks 1250000 Long run 2 dif.Milliseconds 0 Integer dif.Ticks 0 Long run 3 dif.Milliseconds 0 Integer dif.Ticks 0 Long HttpContext Method run 1 dif.Milliseconds 15 Integer dif.Ticks 156250 Long run 2 dif.Milliseconds 156 Integer dif.Ticks 1562500 Long run 3 dif.Milliseconds 0 Integer dif.Ticks 0 Long So I guess what is more prefered, or more compliant with webservice standards? If there is some type of a performance advantage, I can't really tell. Which one scales to larger environments easier?

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  • Why StrinUtils Apache class is not recognized in android?

    - by Maxood
    Why import org.apache.commons.lang.StringUtils cannot be imported in android by default. Do i have to include an external library? Then where can i find that library on the web? package com.myapps.urlencoding; import android.app.Activity; import org.apache.commons.lang.StringUtils; public class EncodeIdUtil extends Activity { /** Called when the activity is first created. */ private static Long multiplier=Long.parseLong("1zzzz",36); /** * Encodes the id. * @param id the id to encode * @return encoded string */ public static String encode(Long id) { return StringUtils.reverse(Long.toString((id*multiplier), 35)); } /** * Decodes the encoded id. * @param encodedId the encodedId to decode * @return the Id * @throws IllegalArgumentException if encodedId is not a validly encoded id. */ public static Long decode(String encodedId) throws IllegalArgumentException { long product; try { product = Long.parseLong(StringUtils.reverse(encodedId), 35); } catch (Exception e) { throw new IllegalArgumentException(); } if ( 0 != product % multiplier || product < 0) { throw new IllegalArgumentException(); } return product/multiplier; } }

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  • Wrong answer on c# application, finding the n prime of a list of prime numbers.

    - by user300484
    Hello, I am new to C# and I am practicing by trying to solve this easy C# problem. This application will receive an "n" number. After receiving this number, the program has to show the n prime of the list of primes. For example, if the user enters "3", the program is supposed to display "5", because 5 is the third prime starting at 2. I koow that something is wrong with my code but I dont know where is the problem and how I can fix it. Can you please tell me? Thank you :P using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Console.WriteLine("Determinar el n-esimo primo."); long n = Convert.ToInt64(Console.ReadLine()); // N lugar de primos long[] array = new long[n]; long c=0; while (c >= 2) { if(siprimo(c++) == true) for (long i = 0; i < n; i++) { array[i] = c; } } Console.WriteLine(array[n - 1]); Console.ReadLine(); } static private bool siprimo(long x) { bool sp = true; for (long k = 2; k <= x / 2; k++) if (x % k == 0) sp = false; return sp; } } }

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  • Error: "an object reference is required for the non-static field, method or property..."

    - by user300484
    Hi! Im creating an application on C#. Its function is to evualuate if a given is prime and if the same swapped number is prime as well. When I build my solution on Visual Studio, it says that "an object reference is required for the non-static field, method or property...". Im having this problem with the "volteado" and "siprimo" methods. Can you tell me where is the problem and how i can fix it? thank you! namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Console.Write("Write a number: "); long a= Convert.ToInt64(Console.ReadLine()); // a is the number given by the user long av = volteado(a); // av is "a" but swapped if (siprimo(a) == false && siprimo(av) == false) Console.WriteLine("Both original and swapped numbers are prime."); else Console.WriteLine("One of the numbers isnt prime."); Console.ReadLine(); } private bool siprimo(long a) {// evaluate if the received number is prime bool sp = true; for (long k = 2; k <= a / 2; k++) if (a % k == 0) sp = false; return sp; } private long volteado(long a) {// swap the received number long v = 0; while (a > 0) { v = 10 * v + a % 10; a /= 10; } return v; } } }

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  • how to extract information from JSON using jQuery

    - by Richard Reddy
    Hi, I have a JSON response that is formatted from my C# WebMethod using the JavascriptSerializer Class. I currently get the following JSON back from my query: {"d":"[{\"Lat\":\"51.85036\",\"Long\":\"-8.48901\"},{\"Lat\":\"51.89857\",\"Long\":\"-8.47229\"}]"} I'm having an issue with my code below that I'm hoping someone might be able to shed some light on. I can't seem to get at the information out of the values returned to me. Ideally I would like to be able to read in the Lat and Long values for each row returned to me. Below is what I currently have: $.ajax({ type: "POST", url: "page.aspx/LoadWayPoints", data: "{'args': '" + $('numJourneys').val() + "'}", contentType: "application/json; charset=utf-8", dataType: "json", success: function (msg) { if (msg.d != '[]') { var lat = ""; var long = ""; $.each(msg.d, function () { lat = this['MapLatPosition']; long = this['MapLongPosition']; }); alert('lat =' + lat + ', long =' + long); } } }); I think the issue is something to do with how the JSON is formatted but I might be incorrect. Any help would be great. Thanks, Rich

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  • power and modulo on the fly for big numbers

    - by user unknown
    I raise some basis b to the power p and take the modulo m of that. Let's assume b=55170 or 55172 and m=3043839241 (which happens to be the square of 55171). The linux-calculator bc gives the results (we need this for control): echo "p=5606;b=55171;m=b*b;((b-1)^p)%m;((b+1)^p)%m" | bc 2734550616 309288627 Now calculating 55170^5606 gives a somewhat large number, but since I have to do a modulooperation, I can circumvent the usage of BigInt, I thought, because of: (a*b) % c == ((a%c) * (b%c))%c i.e. (9*7) % 5 == ((9%5) * (7%5))%5 => 63 % 5 == (4 * 2) %5 => 3 == 8 % 5 ... and a^d = a^(b+c) = a^b * a^c, therefore I can divide b+c by 2, which gives, for even or odd ds d/2 and d-(d/2), so for 8^5 I can calculate 8^2 * 8^3. So my (defective) method, which always cut's off the divisor on the fly looks like that: def powMod (b: Long, pot: Int, mod: Long) : Long = { if (pot == 1) b % mod else { val pot2 = pot/2 val pm1 = powMod (b, pot, mod) val pm2 = powMod (b, pot-pot2, mod) (pm1 * pm2) % mod } } and feeded with some values, powMod (55170, 5606, 3043839241L) res2: Long = 1885539617 powMod (55172, 5606, 3043839241L) res4: Long = 309288627 As we can see, the second result is exactly the same as the one above, but the first one looks quiet different. I'm doing a lot of such calculations, and they seem to be accurate as long as they stay in the range of Int, but I can't see any error. Using a BigInt works as well, but is way too slow: def calc2 (n: Int, pri: Long) = { val p: BigInt = pri val p3 = p * p val p1 = (p-1).pow (n) % (p3) val p2 = (p+1).pow (n) % (p3) print ("p1: " + p1 + " p2: " + p2) } calc2 (5606, 55171) p1: 2734550616 p2: 309288627 (same result as with bc) Can somebody see the error in powMod?

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  • C function prototype: void f(). Is it recommended?

    - by ycalleecharan
    Hi, I'm learning C and I saw in a book that a function prototype has the form void f() and in the function declaration or in the calling function, the f function takes arguments. Thus In the function declaration we have something like void f(long double y[], long double A) and in the calling function is f(y, A). The function is doing operations on the array y i.e. when the function is called, some elements in the array y are changing. A is just a constant numerical value that doesn't change. I have two questions: If defining the function prototype at the top in the program as void f() a good practice? Or is it better to put it as void f(long double y[], long double A) as in the function declaration? The called function f is changing elements in the array y. Is void the right return type? The program is working fine as such with the void as described. Or should I change all my "voids" to "long double". I'm working with long double as I need as much precision as possible though on my machine both double and long double gives me 15 precision digits. Thanks a lot

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  • Where is the virtual function call overhead?

    - by Semen Semenych
    Hello everybody, I'm trying to benchmark the difference between a function pointer call and a virtual function call. To do this, I have written two pieces of code, that do the same mathematical computation over an array. One variant uses an array of pointers to functions and calls those in a loop. The other variant uses an array of pointers to a base class and calls its virtual function, which is overloaded in the derived classes to do absolutely the same thing as the functions in the first variant. Then I print the time elapsed and use a simple shell script to run the benchmark many times and compute the average run time. Here is the code: #include <iostream> #include <cstdlib> #include <ctime> #include <cmath> using namespace std; long long timespecDiff(struct timespec *timeA_p, struct timespec *timeB_p) { return ((timeA_p->tv_sec * 1000000000) + timeA_p->tv_nsec) - ((timeB_p->tv_sec * 1000000000) + timeB_p->tv_nsec); } void function_not( double *d ) { *d = sin(*d); } void function_and( double *d ) { *d = cos(*d); } void function_or( double *d ) { *d = tan(*d); } void function_xor( double *d ) { *d = sqrt(*d); } void ( * const function_table[4] )( double* ) = { &function_not, &function_and, &function_or, &function_xor }; int main(void) { srand(time(0)); void ( * index_array[100000] )( double * ); double array[100000]; for ( long int i = 0; i < 100000; ++i ) { index_array[i] = function_table[ rand() % 4 ]; array[i] = ( double )( rand() / 1000 ); } struct timespec start, end; clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &start); for ( long int i = 0; i < 100000; ++i ) { index_array[i]( &array[i] ); } clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &end); unsigned long long time_elapsed = timespecDiff(&end, &start); cout << time_elapsed / 1000000000.0 << endl; } and here is the virtual function variant: #include <iostream> #include <cstdlib> #include <ctime> #include <cmath> using namespace std; long long timespecDiff(struct timespec *timeA_p, struct timespec *timeB_p) { return ((timeA_p->tv_sec * 1000000000) + timeA_p->tv_nsec) - ((timeB_p->tv_sec * 1000000000) + timeB_p->tv_nsec); } class A { public: virtual void calculate( double *i ) = 0; }; class A1 : public A { public: void calculate( double *i ) { *i = sin(*i); } }; class A2 : public A { public: void calculate( double *i ) { *i = cos(*i); } }; class A3 : public A { public: void calculate( double *i ) { *i = tan(*i); } }; class A4 : public A { public: void calculate( double *i ) { *i = sqrt(*i); } }; int main(void) { srand(time(0)); A *base[100000]; double array[100000]; for ( long int i = 0; i < 100000; ++i ) { array[i] = ( double )( rand() / 1000 ); switch ( rand() % 4 ) { case 0: base[i] = new A1(); break; case 1: base[i] = new A2(); break; case 2: base[i] = new A3(); break; case 3: base[i] = new A4(); break; } } struct timespec start, end; clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &start); for ( int i = 0; i < 100000; ++i ) { base[i]->calculate( &array[i] ); } clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &end); unsigned long long time_elapsed = timespecDiff(&end, &start); cout << time_elapsed / 1000000000.0 << endl; } My system is LInux, Fedora 13, gcc 4.4.2. The code is compiled it with g++ -O3. The first one is test1, the second is test2. Now I see this in console: [Ignat@localhost circuit_testing]$ ./test2 && ./test2 0.0153142 0.0153166 Well, more or less, I think. And then, this: [Ignat@localhost circuit_testing]$ ./test2 && ./test2 0.01531 0.0152476 Where are the 25% which should be visible? How can the first executable be even slower than the second one? I'm asking this because I'm doing a project which involves calling a lot of small functions in a row like this in order to compute the values of an array, and the code I've inherited does a very complex manipulation to avoid the virtual function call overhead. Now where is this famous call overhead?

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  • Correct PHP5 DLL for Apache 2.2?

    - by Nathan Long
    I have installed Apache 2.2.14 (Win32) on a Windows XP machine and am trying to add the latest PHP module. I downloaded the ZIP file from here labeled "VC9 x86 Non Thread Safe" and extracted to my Apache directory. I then copied php5.dll to Apache's bin directory and copied php.ini to C:\Windows. In httpd.conf, I added these lines: LoadModule php5_module "C:/Program Files/Apache Software Foundation/Apache2.2/bin/php5.dll" AddType application/x-httpd-php .php Now Apache will not start. error.log says this: "Can't locate API module structure php5_module in file C:/Program Files/Apache Software Foundation/Apache2.2/bin/php5.dll": No error" I think I may have the wrong .dll file, because I found tutorials that use the filename php5apache2.dll and I didn't see that in the PHP package I got. Also, I have seen references to a file called php5ts.dll, but I don't see that either. What exactly do I need to make PHP5 work?

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  • TeamCity EC2 Integration via ISA Server

    - by Tim Long
    I have a TeamCity server which is actually installed on SBS 2003 Premium with ISA Server (firewall/proxy) installed. My ADSL connection has multiple IP addresses, which all resolve directly to my SBS external NIC. The NIC is therefore multi-homed and I have allocated one of the IP addresses specifically to TeamCity. In ISA, I've created an access rule to allow the traffic in. I can access my TeamCity server externally and view the web interface, that all works fine. I want to use the Amazon EC2 integration in TeamCity to launch build agents 'in the cloud'. The problem I am having is that when the agent starts, it sees the server and registers, then just sits there waiting. On the server side, the agent appears as 'disconnected'. Examining the settings, the agent's IP address appears to be that of the external NIC. What I think might be happening is that the traffic is undergoing Network Address Translation (NAT) so that TeamCity always thinks the agent is locally installed and therefore can't communicate with the actual remote agent. This seems to happen even though I have a permanent static IP address dedicated to TeamCity. So, the question is this. How can I make traffic to a specific IP address pass through the ISA server un-NATted?

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  • PowerPoint '10 avoid animation completion on click & advance slide or start new one

    - by ScottS
    Scenario I have PowerPoint 2010 On the "Transitions" tab the "Advance Slide On Mouse Click" check box is checked. I have a long, slow, timed, non-repeating animation working in the background of the slide. I click to advance the slide before the animation is finished, but ... Instead of advancing the slide, the animation moves to the completed state ... Forcing a second click to actually advance the slide. Additionally If I have other animations on the slide that are initiated by a click, the long animation also advances to a finished state before starting the new animation. Desired Behavior On click, I want the slide to advance or the next on-click animation to start whether the long animation is done or not, and without having that long animation first "complete" itself. In the case of another animation, I simply want the long animation to continue, while also doing the new animation. Ultimate Question Is there a way to either: Set an option somewhere to not have that animation complete on click and simply "continue" to animate with the start of a new animation or to advance the slide (as the case may be)? Create a VBA script that will produce the desired behavior for the long animation?

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  • Permanently change IP address on SuSE 10

    - by Long Ngo
    I am trying to change IP address of a SuSE 10 machine that is running Tomcat. I need to create a shell script to do this so could not use YaST. As some sites suggested on my Google search, I edited the files in /etc/sysconfig/network/ifcfg-eth-* to change the IP address. After that, I restarted the network service by calling /etc/init.d/network restart. The network card restarting just fine. I, then, restarted tomcat web service. However, when I browsed the new IP address using browser, I got an "Request denied" message. Can anyone please tell me how I could do this? Thanks

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  • Virtual memory on Linux doesn't add up?

    - by Brendan Long
    I was looking at System Monitor on Linux and noticed that Firefox is using 441 MB of memory, and several other applications are using 274, 257, 232, etc (adding up to over 3 GB of virtual memory). So I switch over to the Resources tab, and it says I'm using 462 MB of memory and not touching swap. I'm confused. What does the virtual memory amount mean then if the programs aren't actually using it. I was thinking maybe memory they've requested but aren't using, but how would the OS know that? I can't think of any "I might need this much memory in the future" function..

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  • Sharing large (multi-Gb) files with clients

    - by Tim Long
    I wasn't sure if this was the best place for this question, but I think it is squarely in the realm of the IT admin so that's the reason I put it here. We need to share large files (several Gigabytes) with external clients. We need a simple way of reliably and automatically publishing these files so that clients can then download them. Our organization has Windows desktops and a Windows SBS 2011 server. Sharing from our server is probably suboptimal from the client's perspective, because of the low upstream bandwidth of typical ADSL (around 1 Mbps) - it would take all day (9 hours for a 4Gb file) for the client to download the file. Uploading to a 3rd party sever is good for the client but painful for us, because we then have to deal with a multi-hour upload. Uploading to a third-part server would be less problematic if it could be made reliable and automatic, e.g. something like a Groove/SharePoint Workspace, simply drop the file in and wait for it to synchronize - but Groove has a 2Gb limit which is not big enough. So ideally I'd like a service with the following attributes: Must work for files of at least 5Gb, preferably 10Gb Once the transfer is started, it must be reliable (i.e. not sensitive to disconnections and service outages) and completely automatic Ideally, the sender would get a notification when the transfer completes. Has to work with Windows based systems. Any suggestions?

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  • How to remove a partition on a USB drive?

    - by Nathan Long
    I got a free promotional USB stick that I want to format for my own purposes. When I inserted it, it automatically opened a browser and launched a web site. I have since disabled autoplay on this computer so that nothing launches when the stick is inserted. But it still shows up as two separate drives, and one of them is a "CD Drive" that I can't format. How can a USB stick contain a "CD Drive?" And more to the point, how can I remove this partition using Windows XP or Ubuntu? Update I previously asked for an XP solution, but finding none, I have tried Ubuntu, also without success. Gparted doesn't see the "CD" portion as a device at all, and from bash, any chmod changes I try tell me that the file system is read-only. Any ideas?

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