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  • ASP.NET 4 Hosting :: How to Debug Your ASP.NET Applications

    - by mbridge
    Remote debugging of a process is a privilege, and like all privileges, it must be granted to a user or group of users before its operation is allowed. The Microsoft .NET Framework and Microsoft Visual Studio .NET provide two mechanisms to enable remote debugging support: The Debugger Users group and the "Debug programs" user right. Debugger Users Group When you debug a remote .NET Framework-based application, the Debugger on your computer must communicate with the remote computer using DCOM. The remote server must grant the Debugger access, and it does this by granting access to all members of the Debugger Users group. Therefore, you must ensure that you are a member of the Debugger Users group on that computer. This is a local security group, meaning that it is visible to only the computer where it exists. To add yourself or a group to the Debugger Users group, follow these steps: 1. Right-click the My Computer icon on the Desktop and choose Manage from the context menu. 2. Browse to the Groups node, which is found under the Local Users and Groups node of System Tools. 3. In the right pane, double-click the Debugger Users group. 4. Add your user account or a group account of which you are a member. Debug Programs User Right To debug programs that run under an account that is different from your account, you must be granted the "Debug programs" user right on the computer where the program runs. By default, only the Administrators group is granted this user right. You can check this by opening Local Security Policy on the computer. To do so, follow these steps: 1. Click Start, Administrative Tools, and then Local Security Policy. 2. Browse to the User Rights Assignment node under the Local Policies node. 3. In the right pane, double-click the "Debug programs" user right. 4. Add your user account or a group account of which you are a member.

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  • How can I improve this collision detection logic?

    - by Dan
    I’m trying to make an android game and I’m having a bit of trouble getting the collision detection to work. It works sometimes but my conditions aren’t specific enough and my program gets it wrong. How could I improve the following if conditions? public boolean checkColisionWithPlayer( Player player ) { // Top Left // Top Right // Bottom Right // Bottom Left // int[][] PP = { { player.x, player.y }, { player.x + player.width, player.y }, {player.x + player.height, player.y + player.width }, { player.x, player.y + player.height } }; // TOP LEFT - PLAYER // if( ( PP[0][0] > x && PP[0][0] < x + width ) && ( PP[0][1] > y && PP[0][1] < y + height ) && ( (x - player.x) < 0 ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Right if( PP[0][0] > ( x + width/2 ) && ( PP[0][1] - y < ( x + width ) - PP[0][0] ) ) { Log.i("Colision", "Top Left - Right Side"); player.x = ( x + width ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Bottom else if( PP[0][1] > ( y + height/2 ) ) { Log.i("Colision", "Top Left - Bottom Side"); player.y = ( y + height ) + 1; if( player.Vv > 0 ) player.Vv = 0; } return true; } // TOP RIGHT - PLAYER // else if( ( PP[1][0] > x && PP[1][0] < x + width ) && ( PP[1][1] > y && PP[1][1] < y + height ) && ( (x - player.x) > 0 ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Left if( PP[1][0] < ( x + width/2 ) && ( PP[1][0] - x < PP[1][1] - y ) ) { Log.i("Colision", "Top Right - Left Side"); player.x = ( x ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Bottom else if( PP[1][1] > ( y + height/2 ) ) { Log.i("Colision", "Top Right - Bottom Side"); player.y = ( y + height ) + 1; if( player.Vv > 0 ) player.Vv = 0; } return true; } // BOTTOM RIGHT - PLAYER // else if( ( PP[2][0] > x && PP[2][0] < x + width ) && ( PP[2][1] > y && PP[2][1] < y + height ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Left if( PP[2][0] < ( x + width/2 ) && ( PP[2][0] - x < PP[2][1] - y ) ) { Log.i("Colision", "Bottom Right - Left Side"); player.x = ( x ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Top else if( PP[2][1] < ( y + height/2 ) ) { Log.i("Colision", "Bottom Right - Top Side"); player.y = y - player.height; player.Vv = player.phy.getVelsoityWallColision(player.Vv, player.Cr); //player.Vh = -1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); int rs = x - player.x; Log.i("RS", String.format("%d", rs)); if( rs > 0 ) { player.direction = -1; player.isSpinning = true; player.Vh = -0.5 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } if( rs < 0 ) { player.direction = 1; player.isSpinning = true; player.Vh = 0.5 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } player.rotateSpeed = 1 * rs; } return true; } // BOTTOM LEFT - PLAYER // else if( ( PP[3][0] > x && PP[3][0] < x + width ) && ( PP[3][1] > y && PP[3][1] < y + height ) )//&& ( (x - player.x) > 0 ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Right if( PP[3][0] > ( x + width/2 ) && ( PP[3][1] - y < ( x + width ) - PP[3][0] ) ) { Log.i("Colision", "Bottom Left - Right Side"); player.x = ( x + width ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Top else if( PP[3][1] < ( y + height/2 ) ) { Log.i("Colision", "Bottom Left - Top Side"); player.y = y - player.height; player.Vv = player.phy.getVelsoityWallColision(player.Vv, player.Cr); //player.Vh = -1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); int rs = x - player.x; //Log.i("RS", String.format("%d", rs)); //player.direction = -1; //player.isSpinning = true; if( rs > 0 ) { player.direction = -1; player.isSpinning = true; player.Vh = -1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } if( rs < 0 ) { player.direction = 1; player.isSpinning = true; player.Vh = 1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } player.rotateSpeed = 1 * rs; } //try { Thread.sleep(1000, 0); } //catch (InterruptedException e) {} return true; } else { player.isColided = false; player.isSpinning = true; } return false; }

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  • Microsoft Wireless Keyboard 3000 v2.0 doesnt recognize "Flip Key"

    - by Michael Clare
    The Microsoft Wireless Keyboard 3000 v2.0 has a new key called a "flip key" where the right windows button should be (to the right of the right alt key). This is a picture, the key in question is called "Windows Flip": http://www.microsoft.com/hardware/en-us/p/digital-media-keyboard-3000#details I am using Ubuntu 11.10 and this key is not recognized at all by the system: I have run "sudo showkey" with no results. Any help would be greatly appreciated, I would like to map this to be a Right-Super key as it should be.

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  • Quote of the day – on when NOT to say something

    - by BuckWoody
    I think many of us can say something right at the right time. But there’s a deeper skill: “Remember not only to say the right thing in the right place, but far more difficult still, to leave unsaid the wrong thing at the tempting moment.” - Benjamin Franklin Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • Sound Channel map incorrect on an ION 330 ASRock

    - by math
    I have a ION 330 ASRock just updated on Precise and the sound channel mapping is incorrect. Channel map is set as follow: Front Left = Front left Center = Rear Left Front Right = Font Right Rear Right = LFE Rear Left = Center LFE = Rear Right I am testing the sound channel using speaker-test -c 2 -t wav Can some one tell me how I can remap easily? I have tried several possible changes to /etc/pulse/defaut.pa unsuccessfully.

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  • Quote of the day – on when NOT to say something

    - by BuckWoody
    I think many of us can say something right at the right time. But there’s a deeper skill: “Remember not only to say the right thing in the right place, but far more difficult still, to leave unsaid the wrong thing at the tempting moment.” - Benjamin Franklin Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • CSS Menus having cross browser problems

    - by George
    I am trying to solve a problem with a CSS menu where the menu does not display properly in IE 6 I see that the HTML has some conditional code to make it work with different browsers but I do not understand it well enough. Can someone suggest a fix so the selected tab in order displayed without the grey breaK? Thanks! #pad { height: 140px; } .dropline { position: relative; padding-bottom: 0px; list-style-type: none; margin: 0px 0px 0px 5px; padding-left: 0px; width: 860px; padding-right: 0px; background: url(../images/menus/ulback.gif) repeat-x; height: 40px; top: 0px; list-style-image: none; padding-top: 0px; left: 5px; } .dropline TABLE { margin: -3px -10px; width: 25px; border-collapse: collapse; height: 17px; } .dropline LI { margin-bottom: 0px; float: left; } .dropline LI A { padding-bottom: 0px; line-height: 40px; padding-left: 0px; padding-right: 19px; display: block; font-family: tahoma, sans-serif; float: left; height: 40px; color: #fff; font-size: 12px; text-decoration: none; padding-top: 0px; } .dropline A { text-align: right; padding-bottom: 0px; line-height: 40px; padding-left: 0px; padding-right: 19px; font-family: tahoma, sans-serif; float: right; height: 40px; color: #fff; font-size: 12px; text-decoration: none; padding-top: 0px; } .dropline A:hover { color: yellow; } .welcomeuser { text-align: right; padding-bottom: 0px; line-height: 40px; padding-left: 20px; padding-right: 0px; font-family: tahoma, sans-serif; float: right; height: 40px; color: #fff; clear: inherit; font-size: 12px; text-decoration: none; padding-top: 0px; } .dropline LI A B { padding-bottom: 0px; padding-left: 20px; padding-right: 0px; display: block; float: left; height: 40px; cursor: pointer; padding-top: 0px; } .dropline UL { z-index: 10; border-bottom: #fff 1px solid; position: absolute; padding-bottom: 0px; list-style-type: none; margin: 0px; padding-left: 0px; width: 860px; padding-right: 0px; background: #f8f8f8; height: 25px; border-top: #ff9933 3px solid; top: 40px; list-style-image: none; padding-top: 0px; left: -9999px; } .dropline UL LI { line-height: 25px; height: 25px; } .dropline UL.right LI { float: right; } .dropline UL LI A { padding-bottom: 0px; line-height: 25px; padding-left: 10px; padding-right: 10px; height: 25px; color: #000; font-size: 11px; font-weight: bold; border-right: #e60 1px solid; padding-top: 0px; } .dropline UL LI A:hover { line-height: 25px; background: none transparent scroll repeat 0% 0%; height: 25px; color: #c60; } .dropline UL.right LI A { border-left: #e60 1px solid; border-right: 0px; } .dropline UL LI A.last { border-bottom: 0px; border-left: 0px; border-top: 0px; border-right: 0px; } .dropline :hover UL { left: 0px; } .dropline LI.current UL { z-index: 1; left: 0px; } .dropline LI.current A { line-height: 36px; background: url(../images/menus/tab_a.gif) no-repeat right top; height: 44px; } .dropline LI.current A B { line-height: 36px; background: url(../images/menus/tab_b.gif) no-repeat left top; } .dropline LI.current UL LI A { padding-bottom: 0px; line-height: 25px; padding-left: 10px; padding-right: 10px; background: none transparent scroll repeat 0% 0%; height: 25px; color: #000; padding-top: 0px; } .dropline LI.current UL LI.current_sub A { color: #c60; } .dropline LI.current UL LI A:hover { color: #c60; } <div id="top_nav"> <asp:ContentPlaceHolder ID="phTopNav" runat="server"> <!-- MENU --> <ul id="dropline" class="dropline" runat="server" style="left: -6px; top: -2px; width:1000px;" clientidmode="Static"> <li runat="server" id="Home"> <a runat="server" id="lnkHome" href="../Default.aspx" title="Go to the Home page"><b>Home</b> <!--[if gte IE 7]><!--></a> <!--<![endif]--> <!--[if lte IE 6]> <table> <tr> <td> <![endif]--><!--[if lte IE 6]> </td> </tr> </table> </a><![endif]--> </li> <li runat="server" id="ApplyNow"> <a runat="server" id="lnkEditOrder" href="../OrderChinaVisa.aspx" title="Use our Price Calculator and simultaneously begin the China Visa application process!"><b>Apply Now!</b> <!--[if gte IE 7]><!--></a> <!--<![endif]--> <!--[if lte IE 6]> <table> <tr> <td> <![endif]--><!--[if lte IE 6]> </td> </tr> </table> </a><![endif]--> </li> <li runat="server" id="CheckStatus"> <a id="lnkCheckStatus" runat="server" href="../Check_Status.aspx" title="Check on the status of a placed order"><b>Check Status</b><!--[if gte IE 7]><!--></a><!--<![endif]--> <!--[if lte IE 6]> <table> <tr> <td> <![endif]--><!--[if lte IE 6]> </td> </tr> </table> </a><![endif]--></li> <li runat="server" id="Affiliate"> <a id="lnkAffiliate" runat="server" href="../Secure/VisaActivity.aspx" title=""><b>Affiliate</b><!--[if gte IE 7]><!--></a><!--<![endif]--> <!--[if lte IE 6]> <table> <tr> <td> <![endif]--><!--[if lte IE 6]> </td> </tr> </table> </a><![endif]--></li> </ul> </asp:ContentPlaceHolder> </div>

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  • Tuesday at OpenWorld: Identity Management

    - by Tanu Sood
    At Oracle OpenWorld? From keynotes, general sessions to product deep dives and executive events, this Tuesday is full of informational, educational and networking opportunities for you. Here’s a quick run-down of what’s happening today: Tuesday, October 2, 2012 KEYNOTE: The Oracle Cloud: Oracle’s Cloud Platform and Applications Strategy 8:00 a.m. – 9:45 a.m., Moscone North, Hall D Leading customers will join Oracle Executive Vice President Thomas Kurian to discuss how Oracle’s innovative cloud solutions are transforming how they manage their business, excite and retain their employees, and deliver great customer experiences through Oracle Cloud. GENERAL SESSION: Oracle Fusion Middleware Strategies Driving Business Innovation 10:15 a.m. – 11:15 a.m., Moscone North - Hall D Join Hasan Rizvi, Executive Vice President of Product in this strategy and roadmap session to hear how developers leverage new innovations in their applications and customers achieve their business innovation goals with Oracle Fusion Middleware. CON9437: Mobile Access Management 10:15 a.m. – 11:15 a.m., Moscone West 3022 The session will feature Identity Management evangelists from companies like Intuit, NetApp and Toyota to discuss how to extend your existing identity management infrastructure and policies to securely and seamlessly enable mobile user access. CON9162: Oracle Fusion Middleware: Meet This Year's Most Impressive Customer Projects 11:45 a.m. – 12:45 a.m., Moscone West, 3001 Hear from the winners of the 2012 Oracle Fusion Middleware Innovation Awards and see which customers are taking home a trophy for the 2012 Oracle Fusion Middleware Innovation Award.  Read more about the Innovation Awards here. CON9491: Enhancing the End-User Experience with Oracle Identity Governance applications 11:45 a.m. – 12:45 p.m., Moscone West 3008 Join experts from Visa and Oracle as they explore how Oracle Identity Governance solutions deliver complete identity administration and governance solutions with support for emerging requirements like cloud identities and mobile devices. CON9447: Enabling Access for Hundreds of Millions of Users 1:15 p.m. – 2:15 p.m., Moscone West 3008 Dealing with scale problems? Looking to address identity management requirements with million or so users in mind? Then take note of Cisco’s implementation. Join this session to hear first-hand how Cisco tackled identity management and scaled their implementation to bolster security and enforce compliance. CON9465: Next Generation Directory – Oracle Unified Directory 5:00 p.m. – 6:00 p.m., Moscone West 3008 Get the 360 degrees perspective from a solution provider, implementation services partner and the customer in this session to learn how the latest Oracle Unified Directory solutions can help you build a directory infrastructure that is optimized to support cloud, mobile and social networking and yet deliver on scale and performance. EVENTS: Executive Edge @ OpenWorld: Chief Security Officer (CSO) Summit 10:00 a.m. – 3:00 p.m. If you are attending the Executive Edge at Open World, be sure to check out the sessions at the Chief Security Officer Summit. Former Sr. Counsel for the National Security Agency, Joel Brenner, will be speaking about his new book "America the Vulnerable". In addition, PWC will present a panel discussion on "Crisis Management to Business Advantage: Security Leadership". See below for the complete agenda. PRODUCT DEMOS: And don’t forget to see Oracle identity Management solutions in action at Oracle OpenWorld DEMOgrounds. DEMOS LOCATION EXHIBITION HALL HOURS Access Management: Complete and Scalable Access Management Moscone South, Right - S-218 Monday, October 1 9:30 a.m.–6:00 p.m. 9:30 a.m.–10:45 a.m. (Dedicated Hours) Tuesday, October 2 9:45 a.m.–6:00 p.m. 2:15 p.m.–2:45 p.m. (Dedicated Hours) Wednesday, October 3 9:45 a.m.–4:00 p.m. 2:15 p.m.–3:30 p.m. (Dedicated Hours) Access Management: Federating and Leveraging Social Identities Moscone South, Right - S-220 Access Management: Mobile Access Management Moscone South, Right - S-219 Access Management: Real-Time Authorizations Moscone South, Right - S-217 Access Management: Secure SOA and Web Services Security Moscone South, Right - S-223 Identity Governance: Modern Administration and Tooling Moscone South, Right - S-210 Identity Management Monitoring with Oracle Enterprise Manager Moscone South, Right - S-212 Oracle Directory Services Plus: Performant, Cloud-Ready Moscone South, Right - S-222 Oracle Identity Management: Closed-Loop Access Certification Moscone South, Right - S-221 For a complete listing, keep the Focus on Identity Management document handy. And don’t forget to converse with us while at OpenWorld @oracleidm. We look forward to hearing from you.

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  • Rotating text using CSS

    - by Renso
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Goal: Rotating text using css only. How: Surprisingly IE supports this feature rather well. You could use property filters in IE, but since this is only supported on IE browsers, I would not recommend it. CSS3, still in proposal state, has a "writing-mode" property for doing this. It has been part of IE's browser engine since IE5.5. Now that it is part of the CSS3 draft specification, would be the best way to implement this going forward. Webkit based browsers; Firefox 3.5+, Opera 11 and IE9 implement this feature differently by utilizing the transform property. Without using third-party JavaScript or CSS properties, we can use the CSS3 "writing-mode" property, supported from IE5.5 up to IE8, the latter adding addition formatting options through -ms extensions. <style type="text/css"> .rightToLeft{ writing-mode: tb-rl; } </style> <p class="rightToLeft">This is my text</p> This will rotate the text 90 degrees, starting from the right to the left. Here are all the options: ·         lr-tb – Default value, left to right, top to bottom ·         rl-tb – Right to left, top to bottom ·         tb-rl – Vertically; top to bottom, right to left ·         bt-rl – Vertically; bottom to top, right to left ·         tb-lr – Available in IE8+: -ms-writing-mode; top to bottom, left to right ·         bt-lr – Bottom to top, left to right ·         lr-bt – Left to right, bottom to top What about Firefox, Safari, etc.? The following techniques need to be used on Webkit browsers like Firefox, Opera 11, Google Chrome and IE9. These browsers require their proprietary vendor extensions: -moz-, -webkit-, -o- and -ms-. -webkit-transform: rotate(90deg);    -moz-transform: rotate(90deg); -ms-transform: rotate(90deg); -o-transform: rotate(90deg); transform: rotate(90deg);

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  • How to control the text inside DIV tag by not allowing the text to be increased?

    - by SzamDev
    Hi I have this CSS code : #d_image { float: left; width: 320px; margin-top: 20px; margin-left: 25px; } #d_coll { width: 320px; float: left; } #n_div { width: 240px; text-align: right; padding-top: 10px; float: left; padding-right: 10px; padding-left: 0px; } #n_text { text-align: right; float: left; clear: both; } #im { height: 50px; width: 50px; float: right; padding-right: 15px; } #n_col { clear: both; width: 310px; float: right; border-bottom-width: 2px; border-bottom-style: solid; border-bottom-color: #CCC; padding-bottom: 10px; } #n_tittle { text-decoration: none; text-align: right; padding-bottom: 10px; padding-right: 15px; } #n_tittle a { text-decoration: none; text-align: right; color: #1C60B3; } #n_tittle a:hover { text-decoration: underline; text-align: right; color: #FF0000; } I have this HTML code : <div id="d_coll"> <div id="d_image">sample text</div> <div id="n_text">Here will be photo</div> </div> <div id="n_col"> <div id="n_tittle">sample text</div> <div id="im">small photo will be here</div> <div id="n_div">long text</div> </div> I have proplem in n_div, if I put in it a very long text it will be under im div and I want the text inside it to go to new line when it reach the end because the image should be to the right of the text in im div . How I can do that? Thanks in Advance.

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  • How to align Buttons in a TableLayout to different directions?

    - by Bevor
    Hello, probably I don't understand the layout properties of TableLayout yet. It doesn't seem to be possible to achieve such a flexible table like in HTML, because there are no cells. My target is it to achieve such a layout: Link to draft How can I do that? I thought about using a GridView but this doesn't seem to be useful in XML. My efforts look like this: <TableLayout android:id="@+id/tableLayout" android:layout_width="320sp" android:layout_height="fill_parent" android:layout_gravity="center_horizontal" android:gravity="bottom" android:layout_alignParentBottom="true"> <TableRow android:background="#333333" android:gravity="bottom" android:layout_width="fill_parent"> <Button android:id="@+id/btnUp" android:layout_width="60sp" android:layout_height="50sp" android:gravity="left" android:text="Lift U" /> <Button android:id="@+id/btnScreenUp" android:gravity="right" android:layout_gravity="right" android:layout_width="60sp" android:layout_height="50sp" android:text="Scrn U" /> </TableRow> <TableRow android:background="#444444" android:gravity="bottom" android:layout_gravity="right"> <Button android:id="@+id/btnDown" android:layout_width="60sp" android:layout_height="50sp" android:text="Lift D" /> <Button android:id="@+id/btnScreenLeft" android:layout_width="60sp" android:layout_height="50sp" android:gravity="right" android:layout_gravity="right" android:text="Scrn L" /> <Button android:id="@+id/btnScreenDown" android:layout_width="60sp" android:layout_height="50sp" android:gravity="right" android:layout_gravity="right" android:text="Scrn D" /> <Button android:id="@+id/btnScreenRight" android:layout_width="60sp" android:layout_height="50sp" android:gravity="right" android:layout_gravity="right" android:text="Scrn R" /> </TableRow> </TableLayout>

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  • Why am I getting a " instance has no attribute '__getitem__' " error?

    - by Kevin Yusko
    Here's the code: class BinaryTree: def __init__(self,rootObj): self.key = rootObj self.left = None self.right = None root = [self.key, self.left, self.right] def getRootVal(root): return root[0] def setRootVal(newVal): root[0] = newVal def getLeftChild(root): return root[1] def getRightChild(root): return root[2] def insertLeft(self,newNode): if self.left == None: self.left = BinaryTree(newNode) else: t = BinaryTree(newNode) t.left = self.left self.left = t def insertRight(self,newNode): if self.right == None: self.right = BinaryTree(newNode) else: t = BinaryTree(newNode) t.right = self.right self.right = t def buildParseTree(fpexp): fplist = fpexp.split() pStack = Stack() eTree = BinaryTree('') pStack.push(eTree) currentTree = eTree for i in fplist: if i == '(': currentTree.insertLeft('') pStack.push(currentTree) currentTree = currentTree.getLeftChild() elif i not in '+-*/)': currentTree.setRootVal(eval(i)) parent = pStack.pop() currentTree = parent elif i in '+-*/': currentTree.setRootVal(i) currentTree.insertRight('') pStack.push(currentTree) currentTree = currentTree.getRightChild() elif i == ')': currentTree = pStack.pop() else: print "error: I don't recognize " + i return eTree def postorder(tree): if tree != None: postorder(tree.getLeftChild()) postorder(tree.getRightChild()) print tree.getRootVal() def preorder(self): print self.key if self.left: self.left.preorder() if self.right: self.right.preorder() def inorder(tree): if tree != None: inorder(tree.getLeftChild()) print tree.getRootVal() inorder(tree.getRightChild()) class Stack: def __init__(self): self.items = [] def isEmpty(self): return self.items == [] def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): return self.items[len(self.items)-1] def size(self): return len(self.items) def main(): parseData = raw_input( "Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) " ) tree = buildParseTree(parseData) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + preorder(tree)) print( "The post order is: ", + inorder(tree)) main() And here is the error: Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) ( 1 + 2 ) Traceback (most recent call last): File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 108, in main() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 102, in main tree = buildParseTree(parseData) File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 46, in buildParseTree currentTree = currentTree.getLeftChild() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 15, in getLeftChild return root[1] AttributeError: BinaryTree instance has no attribute '__getitem__'

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  • how to dynamically replace css?

    - by photographer
    I've got an image on the page (class='image') within the div (class='galleria_wrapper') and want to place a caption (class='caption') at the lower right corner under that image. The image could be vertical or horizontal, and making a fixed padding-right value let's say .caption<{float:right;padding-top:5px;padding-right:90px;} is not working for one or another. I need to switch on the fly padding-right value depending on horizontal or vertical image is currently on the page. I can theoretically access image's width through document.getElementByName('image').width although don't understand where to put that code. So, I probably need something like that: document.getElementByClass('caption').padding-right = (document.getElementByName('galleria_wrapper').width - document.getElementByName('image').width)/2 Where do I put this code? I do have that in my css file: .caption{float:right;padding-top:5px;} which places the caption below the image, but to far to the right (div 'galleria_wrapper' is wider than most of the images supposed to be displayed within that area). I have an img tag in the html: <img src=image title='this is caption' /></li> ...and some JavaScript which makes title displayed styled by the "caption" css definition. How do I assign variable value for the padding-right without in-advance knowledge of particular image's width?

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  • awk + sorting file according to values in the file and write two diffrent files

    - by yael
    hi I have in file file_test values of right eye and left eye How to separate the file_test to file1 and file2 by awk in order to write the equal values on file1 and different values on file2 as the following example down THX file_test: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file1: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file2: NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|<

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  • How can I make this method more Scalalicious

    - by Neil Chambers
    I have a function that calculates the left and right node values for some collection of treeNodes given a simple node.id, node.parentId association. It's very simple and works well enough...but, well, I am wondering if there is a more idiomatic approach. Specifically is there a way to track the left/right values without using some externally tracked value but still keep the tasty recursion. /* * A tree node */ case class TreeNode(val id:String, val parentId: String){ var left: Int = 0 var right: Int = 0 } /* * a method to compute the left/right node values */ def walktree(node: TreeNode) = { /* * increment state for the inner function */ var c = 0 /* * A method to set the increment state */ def increment = { c+=1; c } // poo /* * the tasty inner method * treeNodes is a List[TreeNode] */ def walk(node: TreeNode): Unit = { node.left = increment /* * recurse on all direct descendants */ treeNodes filter( _.parentId == node.id) foreach (walk(_)) node.right = increment } walk(node) } walktree(someRootNode) Edit - The list of nodes is taken from a database. Pulling the nodes into a proper tree would take too much time. I am pulling a flat list into memory and all I have is an association via node id's as pertains to parents and children. Adding left/right node values allows me to get a snapshop of all children (and childrens children) with a single SQL query. The calculation needs to run very quickly in order to maintain data integrity should parent-child associations change (which they do very frequently). In addition to using the awesome Scala collections I've also boosted speed by using parallel processing for some pre/post filtering on the tree nodes. I wanted to find a more idiomatic way of tracking the left/right node values. After looking at the answers listed I have settled on this synthesised version: def walktree(node: TreeNode) = { def walk(node: TreeNode, counter: Int): Int = { node.left = counter node.right = treeNodes .filter( _.parentId == node.id) .foldLeft(counter+1) { (counter, curnode) => walk(curnode, counter) + 1 } node.right } walk(node,1) }

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  • Sorting arrays in java

    - by user360706
    Write a static method in Java : public static void sortByFour (int[] arr) That receives as a paramater an array full of non-negative numbers (zero or positive) and sorts the array in the following way : In the beginning of the array all the numbers that devide by four without a remainder will appear. After them all the numbers in the array that devide by 4 with a remainder of 1 will appear. After them all the numbers in the array that devide by 4 with a remainder of 2 will appear. In the end of the array all the rest numbers (those who divide by 4 with the remainder 3) will appear. (The order of the numbers in each group doesn't matter) The method must be the most efficient it can. This is what I wrote but unfortunately it doesn't work well... :( public static void swap( int[] arr, int left, int right ) { int temp = arr[left]; arr[left] = arr[right]; arr[right] = temp; } public static void sortByFour( int[] arr ) { int left = 0; int right = ( arr.length - 1 ); int mid = ( arr.length / 2 ); while ( left < right ) { if ( ( arr[left] % 4 ) > ( arr[right] % 4 ) ) { swap( arr, left, right ); right--; } if ( ( arr[left] % 4 ) == ( arr[right] % 4 ) ) left++; else left++; } } Can someone please help me by fixing my code so that it will work well or rewriting it?

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  • CSS with Aligned LI within a UL

    - by Alex
    I am trying to have some LIs within a UL align left, right, and center within a page. For the life of me, I can't figure out how to keep something "centered" on the same line as a left and right aligned LI. <style> ul { margin:1em 0; padding:0 } ul li{ display:inline-block; white-space:nowrap; margin:5px } ul li.left{ float: left; text-align:left; } ul li.center{ float:left; text-align: center; } ul li.right{ float: right; text-align:right; } </style> <ul> <li class="left">left</li> <li class="center">center</li> <li class="right">right</li> </ul> <ul> <li class="left">left</li> <li class="right">right</li> </ul> <ul> <li class="left">left</li> </ul> Can anyone help? BTW, I've trying to avoid DIVs. Thanks!

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  • Animate absolutely positioned div, but stop if a condition is true?

    - by Alex
    Hello all, I have a div which I place at the top right-hand corner of a website, absolutely positioned at top: 0px and right : 0px. I want to use jquery's animate function to animate the div left or right a certain amount when a button is clicked, but stop the animation if at anytime, the div's offset to the left or right is less than a certain number. I want to do this to accomodate users who click the left or right buttons more than once, so that the div does not fly out of sight. How does one accomplish this? Below is my relevant css, html, and jquery code: CSS: #scorecardTwo { position:absolute; padding:5px; width: 300px; background-color:#E1E1E1; right:0px; top:0px; display:none; } HTML: <div id = "scorecardTwo"> <span id = "dealHolder"><a href="some/link">some text</a></span> <br /> <span id = "scoreHolder">some text</span> <br /> <button type="button" id="moveLeft">Left</button>&nbsp;<button type="button" id="moveRight">Right</button> </div> jQuery (at the moment): $("#scorecardTwo").fadeIn("slow"); $("#moveLeft").bind("click", function() { $("#scorecardTwo").animate({"right":"+=76%"}, "slow"); // how to stop animation if offset is less than appropriate number? }); $("#moveRight").bind("click", function() { $("#scorecardTwo").animate({"right" : "-=76%"}, "slow"); // how to stop animation if offset is less than appropriate number? });

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  • Android Can't get two virtual joysticks to move independently and at the same time

    - by Cole
    @Override public boolean onTouch(View v, MotionEvent event) { // TODO Auto-generated method stub float r = 70; float centerLx = (float) (screenWidth*.3425); float centerLy = (float) (screenHeight*.4958); float centerRx = (float) (screenWidth*.6538); float centerRy = (float) (screenHeight*.4917); float dx = 0; float dy = 0; float theta; float c; int action = event.getAction(); int actionCode = action & MotionEvent.ACTION_MASK; int pid = (action & MotionEvent.ACTION_POINTER_INDEX_MASK) >> MotionEvent.ACTION_POINTER_INDEX_SHIFT; int fingerid = event.getPointerId(pid); int x = (int) event.getX(pid); int y = (int) event.getY(pid); c = FloatMath.sqrt(dx*dx + dy*dy); theta = (float) Math.atan(Math.abs(dy/dx)); switch (actionCode) { case MotionEvent.ACTION_DOWN: case MotionEvent.ACTION_POINTER_DOWN: //if touching down on left stick, set leftstick ID to this fingerid. if(x < screenWidth/2 && c<r*.8) { lsId = fingerid; dx = x-centerLx; dy = y-centerLy; touchingLs = true; } else if(x > screenWidth/2 && c<r*.8) { rsId = fingerid; dx = x-centerRx; dy = y-centerRy; touchingRs = true; } break; case MotionEvent.ACTION_MOVE: if (touchingLs && fingerid == lsId) { dx = x - centerLx; dy = y - centerLy; }else if (touchingRs && fingerid == rsId) { dx = x - centerRx; dy = y - centerRy; } c = FloatMath.sqrt(dx*dx + dy*dy); theta = (float) Math.atan(Math.abs(dy/dx)); //if touching outside left radius and moving left stick if(c >= r && touchingLs && fingerid == lsId) { if(dx>0 && dy<0) { //top right quadrant lsX = r * FloatMath.cos(theta); lsY = -(r * FloatMath.sin(theta)); Log.i("message", "top right"); } if(dx<0 && dy<0) { //top left quadrant lsX = -(r * FloatMath.cos(theta)); lsY = -(r * FloatMath.sin(theta)); Log.i("message", "top left"); } if(dx<0 && dy>0) { //bottom left quadrant lsX = -(r * FloatMath.cos(theta)); lsY = r * FloatMath.sin(theta); Log.i("message", "bottom left"); } else if(dx > 0 && dy > 0){ //bottom right quadrant lsX = r * FloatMath.cos(theta); lsY = r * FloatMath.sin(theta); Log.i("message", "bottom right"); } } if(c >= r && touchingRs && fingerid == rsId) { if(dx>0 && dy<0) { //top right quadrant rsX = r * FloatMath.cos(theta); rsY = -(r * FloatMath.sin(theta)); Log.i("message", "top right"); } if(dx<0 && dy<0) { //top left quadrant rsX = -(r * FloatMath.cos(theta)); rsY = -(r * FloatMath.sin(theta)); Log.i("message", "top left"); } if(dx<0 && dy>0) { //bottom left quadrant rsX = -(r * FloatMath.cos(theta)); rsY = r * FloatMath.sin(theta); Log.i("message", "bottom left"); } else if(dx > 0 && dy > 0) { rsX = r * FloatMath.cos(theta); rsY = r * FloatMath.sin(theta); Log.i("message", "bottom right"); } } else { if(c < r && touchingLs && fingerid == lsId) { lsX = dx; lsY = dy; } if(c < r && touchingRs && fingerid == rsId){ rsX = dx; rsY = dy; } } break; case MotionEvent.ACTION_UP: case MotionEvent.ACTION_POINTER_UP: if (fingerid == lsId) { lsId = -1; lsX = 0; lsY = 0; touchingLs = false; } else if (fingerid == rsId) { rsId = -1; rsX = 0; rsY = 0; touchingRs = false; } break; } return true; } There's a left joystick and a right joystick. Right now only one will move at a time. If someone could set me on the right track I would be incredibly grateful cause I've been having nightmares about this problem.

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  • enable all touchpad functions

    - by user118136
    When I had been using Windows 8 my touchpad had multiple gestures: 2 fingers direction top-bottom = vertical revers scrolling(if I scrolled top than page have scrolled bottom); 2 finger direction left-right = horizontal revers scrolling zoom in and zoom out like smartphones with 2 fingers 2 finger rotation = rotate image in image viewer (+ 90 deg or -90 deg) place a finger in the left edge and drag it to right = change windows application, in Ubuntu I want to change the active program to left like Ctrl+Shift+Tab place a finger in the right edge and drag it to left = open right menu and select the option moving finger on direction top-bottom, in Ubuntu I want to change the active program to right like Alt+Tab I succeed enable 2 finger vertical scrolling of System Setings, but I want that it do not work in revers sense. Do it exist a method to enable the rest of gestures and revers the vertical scrolling? edit: It's a Synaptics touchpad.

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  • Two divs, one fixed width, the other, the rest

    - by Shamil
    I've got two div containers. Whilst one needs to be a specific width, I need to adjust it, so that, the other div takes up the rest of the space. Is there any way I can do this? <div class="left"></div> <div class="right"></div> // needs to be 250px .left { float: left; width: 83%; display: table-cell; vertical-align: middle; min-height: 50px; margin-right: 10px; overflow: auto } .right { float: right; width: 16%; text-align: right; display: table-cell; vertical-align: middle; min-height: 50px; height: 100%; overflow: auto } Thanks

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  • HP mini 210 touchpad issues

    - by user4041
    Need help in getting the right mouse click to work on a HP mini 210-1015TU when using the touchpad. If I plug in a USB mouse, both left click and right click function as normal. Using the touchpad however I can only get the left click to work. Attempting to right click gives the result expected from a left click. As per some comments on a forum I added a file 11-touchpad.conf to /usr/share/X11/xorg.conf.d. I can provide further details if required. This made touchpad operation noticeably smoother but the problem with the right mouse click remains. Not a hardware problem as right clicked worked with 10.04 and still works with Windows 7 starter. 10.10 installed using wubi.

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  • Container fix width. Center div dynamic width. want left right divs to fill out remaining width equally

    - by james
    Have Three columns..Combine width of all three is fixed.. 2nd ( center ) column will have dynamic content.. I need left and right column to fill out remaining space ( container width - center column dynamic width )equally. Example: http://jsfiddle.net/htKje/ <div class="container"> <div class="bg"></div> <div>Lorem Ipsum</div> <div class="bg"></div> </div> CSS : .container { width:500px; } .bg {backgrould:#CCC; }

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  • opening a div closing the others

    - by Mael
    I'm trying to make a sliding panel using .animate function because I want it to slide left/right (jQuery allow slideUp and slideDown, but no other directions). I made the animation like this : jQuery('#slide1-button').toggle( function(){jQuery('#slide1').animate({right: 700},600);}, function(){jQuery('#slide1').animate({right: -700},600);} ); jQuery('#slide2-button').toggle( function(){jQuery('#slide2').animate({right: 700},600);}, function(){jQuery('#slide2').animate({right: -700},600);} ); jQuery('#slide3-button').toggle( function(){jQuery('#slide3').animate({right: 700},600);}, function(){jQuery('#slide3').animate({right: -700},600);} ); Now I would like the opened panel to hide when I open an other one.

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