Search Results

Search found 41095 results on 1644 pages for 'empty string'.

Page 56/1644 | < Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >

• "tailing" a binary file based on string location using bash?

  - by ilitirit

  I've got a bunch of binary files, each containing an embedded string near the end of the file but at different places (only occurs once in each file). I need to extract the part of the file starting at the location of the string till the end of the file and dump it into a new file. eg. If the file's contents is "AWREDEDEDEXXXERESSDSDS" and the string of interest is "XXX", then the part of the file I need is "XXXERESSDSDS". What's the easiest way to do this in bash?

  Read the article

• How to iterate loop inside a string searching for any word aftera fixed keyword?

  - by Parth

  Suppose I have a sting as "PHP Paddy,PHP Pranav,PHP Parth", now i have a count as 3,now how should I iterate loop in the string aiming on string after "PHP " to display the all the names? Alright This is the string "BEGIN IF (NEW.name != OLD.name) THEN INSERT INTO jos_menuaudit set menuid=OLD.id, oldvalue = OLD.name, newvalue = NEW.name, field = "name"; END IF; IF (NEW.alias != OLD.alias) THEN INSERT INTO jos_menuaudit set menuid=OLD.id, oldvalue = OLD.alias, newvalue = NEW.alias, field = "alias"; END IF; END" in which i am searching the particular word after " IF (NEW.", and after that particualar others strings should not b displayed, hence whenever in a loop it finds " IF (NEW." I musr get a word just next to it. and in this way an array should b ready for to use.

  Read the article

• Invalid character in a Base-64 string

  - by swetha

  I am getting this error when I am validating the user with sql membership provider this.provider.ValidateUser(userName, password); the password i have used is "freetrial". I tried trimming the spaces but still no luck!!! and the call stack is as follows: [FormatException: Invalid character in a Base-64 string.] System.Convert.FromBase64String(String s) +0 System.Web.Security.MembershipProvider.EncodePassword(String pass, Int32 passwordFormat, String salt) +54 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved, String& salt, Int32& passwordFormat) +169 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved) +42 System.Web.Security.SqlMembershipProvider.ValidateUser(String username, String password) +78

  Read the article

• StremReader.ReadToEnd() returning an empty string

  - by axk

  I have a method private static String DecompressAndDecode(byte[] data) { GZipStream decompressor = new GZipStream(new MemoryStream(data), CompressionMode.Decompress); StreamReader decompressed = new StreamReader(decompressor, Encoding.UTF8); String result = decompressed.ReadToEnd(); return result; } I have some GZipped text as input and the result is supposed to be a String representation of this text. The problem is that the method returns an empty string. What is puzzling me is that when I step trough the method in debug mode and reach the return statement the result variable is an empty string but if I create a watch for the decompressed.ReadToEnd() expression it returns me the text. What I would expect at this point is the result variable to contain the text and the decompressed.ReadToEnd() expression evaluating to an empty string. (Reevaluating the decompressed.ReadToEnd() expression returns an empty string as expected). There must be something obvious I'm missing here.

  Read the article

• Easiest way of checking if a string consists of unique characters?

  - by serg555

  I need to check in Java if a word consists of unique letters (case insensitive). As straight solution is boring, I came up with: For every char in a string check if indexOf(char) == lastIndexOf(char). Add all chars to HashSet and check if set size == string length. Convert a string to a char array, sort it alphabetically, loop through array elements and check if c[i] == c[i+1]. Currently I like #2 the most, seems like the easiest way. Any other interesting solutions?

  Read the article

• What's the most efficient way to format the following string?

  - by Ian P

  I have a very simple question, and I shouldn't be hung up on this, but I am. Haha! I have a string that I receive in the following format(s): 123 123456-753 123455-43 234234-4 123415 The desired output, post formatting, is: 123-455-444 123-455-55 123-455-5 or 123-455 The format is ultimately dependent upon the total number of characters in the original string.. I have several ideas of how to do this, but I keep thing there's a better way than string.Replace and concatenate... Thanks for the suggestions.. Ian

  Read the article

• How to find validity of a string of parentheses, curly brackets and square brackets?

  - by Rajendra

  I recently came in contact with this interesting problem. You are given a string containing just the characters '(', ')', '{', '}', '[' and ']', for example, "[{()}]", you need to write a function which will check validity of such an input string, function may be like this: bool isValid(char* s); these brackets have to close in the correct order, for example "()" and "()[]{}" are all valid but "(]", "([)]" and "{{{{" are not! I came out with following O(n) time and O(n) space complexity solution, which works fine: Maintain a stack of characters. Whenever you find opening braces '(', '{' OR '[' push it on the stack. Whenever you find closing braces ')', '}' OR ']' , check if top of stack is corresponding opening bracket, if yes, then pop the stack, else break the loop and return false. Repeat steps 2 - 3 until end of the string. This works, but can we optimize it for space, may be constant extra space, I understand that time complexity cannot be less than O(n) as we have to look at every character. So my question is can we solve this problem in O(1) space?

  Read the article

• How to iterate into a string for a word after a fixed keyword? [closed]

  - by Parth

  Possible Duplicate: I need to iterate a loop to every time find the string appearing after a particular string say “if(OLD.”, then which PHP function will be helpful for me? This is the string BEGIN IF (NEW.name != OLD.name) THEN INSERT INTO jos_menuaudit set menuid=OLD.id, oldvalue = OLD.name, newvalue = NEW.name, field = "name"; END IF; IF (NEW.alias != OLD.alias) THEN INSERT INTO jos_menuaudit set menuid=OLD.id, oldvalue = OLD.alias, newvalue = NEW.alias, field = "alias"; END IF; END in which I am searching the particular word after " IF (NEW.", and after that particular others strings should not be displayed, hence whenever in a loop it finds " IF (NEW." I must get a word just next to it. And in this way an array should be ready for to use.

  Read the article

• How can I detect if a string contains punctuation marks at the end?

  - by Sheehan Alam

  Lets assume I have the string: "Hello I like your shoes #today...!" I am tokenizing the string by spaces: return [string componentsSeparatedByString:@" "]; So my array contains: Hello I like your shoes #today...! I want to focus on "#today...!" any word that has a # in the prefix I am changing the font color. How can I make sure that only "#today" has its font color changed? I would basically like to figure out if a word has a punctuation mark at the end, and change the color for characters before the punctuation mark.

  Read the article

• How to parse a string to an integer without library functions?

  - by dack

  Hi, I was recently asked this question in an interview: "How could you parse a string of the form '12345' into its integer representation 12345 without using any library functions, and regardless of language?" I thought of two answers, but the interviewer said there was a third. Here are my two solutions: Solution 1: Keep a dictionary which maps '1' = 1, '2' = 2, etc. Then parse the string one character at a time, look up the character in your dictionary, and multiply by place value. Sum the results. Solution 2: Parse the string one character at a time and subtract '0' from each character. This will give you '1' - '0' = 0x1, '2' - '0' = 0x2, etc. Again, multiply by place value and sum the results. Can anyone think of what a third solution might be? Thanks.

  Read the article

• Need to allocate memory before a Delphi string copy?

  - by Duncan

  Do I need to allocate memory when performing a Delphi string copy? I've a function which posts a Windows message to another form in my application. It looks something like this: // Note: PThreadMessage = ^TThreadMessage; TThreadMessage = String; function PostMyMessage( aStr : string ); var gMsgPtr : PThreadMessage; gStrLen : Integer; begin New(gMsgPtr); gStrLen := StrLen(PWideChar(aMsg)); gMsgPtr^ := Copy(aMsg, 0, gStrLen); PostMessage(ParentHandle, WM_LOGFILE, aLevel, Integer(gMsgPtr)); // Prevent Delphi from freeing this memory before consumed. LParam(gMsgPtr) := 0; end;

  Read the article

• C++: Why does space always terminate a string when read?

  - by Nullw0rm

  Using type std::string to accept a sentence, for practise (I haven't worked with strings in C++ much) I'm checking if a character is a vowel or not. I got this: for(i = 0; i <= analyse.length(); i++) { if(analyse[i] == 'a' || analyse[i] == 'e' [..etc..]) { ...vowels++; } else { ... ...consenents++; } This works fine if the string is all one word, but the second I add a space (IE: aeio aatest) it will only count the first block and count the space as a consenent, and quit reading the sentence (exiting the for loop or something). Does a space count as no character == null? Or some oddity with std::string?, It would be helpful to know why that is happening!

  Read the article

• What the best way to convert from String to HashMap?

  - by eugenn

  I would like to serialize a Java HashMap to string representation. The HashMap will contains only primitive values like string and integer. After that this string will be stored to db. How to restore back the HashMap? Is it make sense to use BeanUtils and interface Converter or use JSON? For example: List list = new ArrayList(); list.add(new Long(1)); list.add(new Long(2)); list.add(new Long(4)); Map map = new HashMap(); map.put("cityId", new Integer(1)); map.put("name", "test"); map.put("float", new Float(-3.2)); map.put("ids", list); map.toString() -> {float=-3.2,ids=[1, 2, 4],name=test,cityId=1} map.toJSON -> {"float":-3.2,"ids":[1,2,4],"name":"test","cityId":1}

  Read the article

• how do I check if a c++ string is an int?

  - by user342231

  when I use getline, I would input a bunch of strings or numbers, but I only want the while loop to output the "word" if it is not a number. so is there any way to check if "word" is a number or not, I know I could use atoi() for c-strings but how about for strings of the string class int main () { stringstream ss (stringstream::in | stringstream::out); string word; string str; getline(cin,str); ss<<str; while(ss>>word) { //if( ) cout<<word<<endl; } }

  Read the article

• How can I put the results of Cursor into String[]. For more detail, please refer to the code below

  - by Hicen

  public class DisplayCustomersActivity extends Activity implements Button.OnClickListener { private SalesDB sdb; private ListView lvDCList; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.displaycustomers); lvDCList = (ListView) findViewById(R.id.lvDCList); sdb = new SalesDB(this); SQLiteDatabase db = sdb.getReadableDatabase(); Cursor results = db.query(sdb.TABLE_CUSTOMER, new String[] {sdb.CUSTOMER_ID, sdb.CUSTOMER_NAME, sdb.CUSTOMER_GENDER}, null, null, null, null, null); int resultCount = results.getCount(); String[] customers = new String[resultCount]; if (resultCount == 0 || !results.moveToFirst()) { customers = null; } else { for(int i=0; i<resultCount; i++) { //Process results to String array here ... ... results.moveToNext(); } } }

  Read the article

• [AS 3.0] How to use the string.match method to find multiple occurrences of the same word in a strin

  - by Steven

  In Actionscript and Adobe Flex, I'm using a pattern and regexp (with the global flag) with the string.match method and it works how I'd like except when the match returns multiple occurrences of the same word in the text. In that case, all the matches for that word point only to the index for the first occurrence of that word. For example, if the text is "cat dog cat cat cow" and the pattern is a search for cat*, the match method returns an array of three occurrences of "cat", however, they all point to only the index of the first occurrence of cat when i use indexOf on a loop through the array. I'm assuming this is just how the string.match method is (although please let me know if i'm doing something wrong or missing something!). I want to find the specific indices of every occurrence of a match, even if it is of a word that was already previously matched. I'm wondering if that is just how the string.match method is and if so, if anyone has any idea what the best way to do this would be. Thanks.

  Read the article

• How to parse out html links from a huge string with html links and other text (Java).

  - by Robert

  Hello, my question is how would i be able to go through a string and take out only the links and erase all the rest? I thought about using some type of delemiter, but wouldnt know how to go about using it in java. an example of what i am trying to do: this is my String: String myString = "The file is http: // www. .com/hello.txt and the second file is " + "http: // www. .com/hello2.dat"; I would want the output to be: "http: // www. .com/hello.txt http: // www. .com/hello2.dat" or each could be added to an array, separately. I just want some ideas, id like to write the code myself but am having trouble on how to do it. Any help would be awesome.

  Read the article

• How to get rid of `deprecated conversion from string constant to ‘char*’` warnings in GCC?

  - by Josh Matthews

  So I'm working on an exceedingly large codebase, and recently upgraded to gcc 4.3, which now triggers this warning: warning: deprecated conversion from string constant to ‘char*’ Obviously, the correct way to fix this is to find every declaration like char *s = "constant string"; or function call like void foo(char *s); foo("constant string"); and make them const char pointers. However, that would mean touching 564 files, minimum, which is not a task I wish to perform at this point in time. The problem right now is that I'm running with -werror, so I need some way to stifle these warnings. How can I do that?

  Read the article

• C: Why does gcc allow char array initialization with string literal larger than array?

  - by Ashwin

  int main() { char a[7] = "Network"; return 0; } A string literal in C is terminated internally with a nul character. So, the above code should give a compilation error since the actual length of the string literal Network is 8 and it cannot fit in a char[7] array. However, gcc (even with -Wall) on Ubuntu compiles this code without any error or warning. Why does gcc allow this and not flag it as compilation error? gcc only gives a warning (still no error!) when the char array size is smaller than the string literal. For example, it warns on: char a[6] = "Network"; [Related] Visual C++ 2012 gives a compilation error for char a[7]: 1>d:\main.cpp(3): error C2117: 'a' : array bounds overflow 1> d:\main.cpp(3) : see declaration of 'a'

  Read the article

• sorting set of five string in alphabetical oder throwing warning?

  - by rost rost

  sorting set of five string in alphabetical oder throwing warning ?my code is below please help me to fix it #include<stdio.h> #include<string.h> int main() { char a[5][20],t[20]; int i,j; printf("enter 5 string\n") scanf("%s",a); for(i=1;i<5;i++) { for(j=1;j<5;j++) { if(strcmp(a[j-1],a[j])>0) { strcpy (t,a[j-1]); strcpy (a[j-1],a[j]); strcpy(a[j],t); } } } for(i=1;i<5;i++) printf("%s\n",a[i]); } ~

  Read the article

• Ubuntu Preseed set Norwegian Keyboard?

  - by Vangelis Tasoulas

  It's been a couple of days now that I am trying to make a fully automated unattended installation. I managed to make it work with Ubuntu/Cobbler and a preseed file, but I cannot set the correct keyboard layout which is Norwegian in this case. I am doing the tests on a virtual machine and when I am going with a normal manual installation (no preseed) everything is working fine. When I am using the preseed file, I always end up with an "English (US)" keyboard no matter the many different options I have tried. I can change it manually with the "dpkg-reconfigure keyboard-configuration" command, but that's not the case. It should be handled automatically using the preseed file. I am using DEBCONF_DEBUG=5 when the grub is loading, and as I see in "/var/log/installer/syslog" file after the installation has finished, the preseeding commands are accepted. Can anyone help on this? The preseed file I am using is following: d-i debian-installer/country string NO d-i debian-installer/language string en_US:en d-i debian-installer/locale string en_US.UTF-8 d-i console-setup/ask_detect boolean false d-i keyboard-configuration/layout select Norwegian d-i keyboard-configuration/variant select Norwegian d-i keyboard-configuration/modelcode string pc105 d-i keyboard-configuration/layoutcode string no d-i keyboard-configuration/xkb-keymap select no d-i netcfg/choose_interface select auto d-i netcfg/get_hostname string myhostname d-i netcfg/get_domain string simula.no d-i hw-detect/load_firmware boolean true d-i mirror/country string manual d-i mirror/http/hostname string ftp.uninett.no d-i mirror/http/directory string /ubuntu d-i mirror/http/proxy string http://10.0.1.253:3142/ d-i mirror/codename string precise d-i mirror/suite string precise d-i clock-setup/utc boolean true d-i time/zone string Europe/Oslo d-i clock-setup/ntp boolean true d-i clock-setup/ntp-server string 10.0.1.254 d-i partman-auto/method string lvm partman-auto-lvm partman-auto-lvm/new_vg_name string vg0 d-i partman-auto/purge_lvm_from_device boolean true d-i partman-lvm/device_remove_lvm boolean true d-i partman-md/device_remove_md boolean true d-i partman-lvm/confirm boolean true d-i partman-lvm/confirm_nooverwrite boolean true d-i partman-auto-lvm/guided_size string max d-i partman-auto/choose_recipe select 30atomic d-i partman/default_filesystem string ext4 d-i partman-partitioning/confirm_write_new_label boolean true d-i partman/choose_partition select finish d-i partman/confirm boolean true d-i partman/confirm_nooverwrite boolean true d-i partman/mount_style select uuid d-i passwd/root-login boolean false d-i passwd/make-user boolean true d-i passwd/user-fullname string vangelis d-i passwd/username string vangelis d-i passwd/user-password-crypted password $6$asdafdsdfasdfasdf d-i passwd/user-uid string d-i user-setup/allow-password-weak boolean false d-i passwd/user-default-groups string adm cdrom dialout lpadmin plugdev sambashare d-i user-setup/encrypt-home boolean false d-i apt-setup/restricted boolean true d-i apt-setup/universe boolean true d-i apt-setup/backports boolean true d-i apt-setup/services-select multiselect security d-i apt-setup/security_host string security.ubuntu.com d-i apt-setup/security_path string /ubuntu tasksel tasksel/first multiselect Basic Ubuntu server, OpenSSH server d-i pkgsel/include string build-essential htop vim nmap ntp d-i pkgsel/upgrade select safe-upgrade d-i pkgsel/update-policy select none d-i pkgsel/updatedb boolean true d-i grub-installer/only_debian boolean true d-i grub-installer/with_other_os boolean true d-i finish-install/keep-consoles boolean false d-i finish-install/reboot_in_progress note d-i cdrom-detect/eject boolean true d-i debian-installer/exit/halt boolean false d-i debian-installer/exit/poweroff boolean false

  Read the article

• String contains trailing zeroes when converted from decimal [migrated]

  - by Locke

  I've run into an unusual quirk in a program I'm writing, and I was trying to figure out if anyone knew the cause. Note that fixing the issue is easy enough. I just can't figure out why it is happening in the first place. I have a WinForms program written in VB.NET that is displaying a subset of data. It contains a few labels that show numeric values (the .Text property of the labels are being assigned directly from the Decimal values). These numbers are being returned by a DLL I wrote in C#. The DLL calls a webservice which initially returns the values in question. It returns one as a string, the other as a decimal (I don't have any control over the webservice, I just consume it). The DLL assigns these to properties on an object (both of which are decimals) then returns that object back to the WinForm program that called the DLL. Obviously, there's a lot of other data being consumed from the webservice, but no other operations are happening which could modify these properties. So, the short version is: WinForm requests a new Foo from the DLL. DLL creates object Foo. DLL calls webservice, which returns SomeOtherFoo. //Both Foo.Bar1 and Foo.Bar2 are decimals Foo.Bar1 = decimal.Parse(SomeOtherFoo.Bar1); //SomeOtherFoo.Bar1 is a string equal to "2.9000" Foo.Bar2 = SomeOtherFoo.Bar2; //SomeOtherFoo.Bar2 is a decimal equal to 2.9D DLL returns Foo to WinForm. WinForm.lblMockLabelName1.Text = Foo.Bar1 //Inspecting Foo.Bar1 indicates my value is 2.9D WinForm.lblMockLabelName2.Text = Foo.Bar2 //Inspecting Foo.Bar2 also indicates I'm 2.9D So, what's the quirk? WinForm.lblMockLabelName1.Text displays as "2.9000", whereas WinForm.lblMockLabelname2.Text displays as "2.9". Now, everything I know about C# and VB indicates that the format of the string which was initially parsed into the decimal should have no bearing on the outcome of a later decimal.ToString() operation called on the same decimal. I would expect that decimal.Parse(someDecimalString).ToString() would return the string without any trailing zeroes. Everything I find online seems to corroborate this (there are countless Stack Overflow questions asking exactly the opposite...how to keep the formatting from the initial parsing). At the moment, I've just removed the trailing zeroes from the initial string that gets parsed, which has hidden the quirk. However, I'd love to know why it happens in the first place.

  Read the article

• How to troubleshoot connectivity when curl gets an *empty response*

  - by chad

  I want to know how to proceed in troubleshooting why a curl request to a webserver doesn't work. I'm not looking for help that would be dependent upon my environment, I just want to know how to collect information about exactly what part of the communication is failing, port numbers, etc. chad-integration:~ # curl -v 111.222.159.30 * About to connect() to 111.222.159.30 port 80 (#0) * Trying 111.222.159.30... connected * Connected to 111.222.159.30 (111.222.159.30) port 80 (#0) > GET / HTTP/1.1 > User-Agent: curl/7.19.0 (x86_64-suse-linux-gnu) libcurl/7.19.0 OpenSSL/0.9.8h zlib/1.2.3 libidn/1.10 > Host: 111.222.159.30 > Accept: */* > * Empty reply from server * Connection #0 to host 111.222.159.30 left intact curl: (52) Empty reply from server * Closing connection #0 So, I understand that an empty response means that curl didn't get any response from the server. No problem, that's precisely what I'm trying to figure out. But what more specific info can I derive from cURL here? It was able to successfully "connect", so doesn't that involve some bidirectional communication? If so, then why does the response not come also? Note, I've verified my service is up and returning responses. Note, I'm a bit green at this level of networking, so feel free to provide some general orientation material.

  Read the article

• Trying to delete directory with "rm -rf", but get message that it's not empty

  - by Ben Hocking

  I've tried deleting a directory using "rm -rf" and I'm getting the message "Directory not empty": Bens-MacBook-Pro:please benjaminhocking$ ls -lart empty_directory/ total 16 drwxr-xr-x 5 benjaminhocking staff 170 Aug 27 14:46 . drwxr-xr-x 3 benjaminhocking staff 102 Aug 27 15:28 .. Bens-MacBook-Pro:please benjaminhocking$ rm -rf empty_directory/ rm: empty_directory/: Directory not empty Bens-MacBook-Pro:please benjaminhocking$ rmdir empty_directory/ rmdir: empty_directory/: Directory not empty If I try the same thing using Finder (dragging the folder to the Trash), I get the message The operation can’t be completed because the item “empty_directory” is in use. I've tried doing xattr -d com.apple.quarantine, purely out of superstition, but it did no good. A probably important piece of context is that this directory was initially in a directory that should've been deleted by a "make clean" command I issued prior to Terminal locking up on me, after which a little over half of the other programs I had running also locked up, including Skype, and eventually the OS itself. I ended up having to reboot the computer by pressing and holding the power key. Edit to add: Another important piece of information I left off was that this was happening in an encrypted folder à la encfs. I was able to track down the corresponding folder in the encrypted side of things and delete it there. I still don't know why I couldn't do it from the decrypted side of things like I normally do. I'll leave this unanswered for now in case anyone has a good answer for that.

  Read the article

• logrotate: neither rotate nor compress empty files

  - by Andrew Tobey

  i have just set up an (r)syslog server to receive the logs of various clients, which works fine. only logrotate is still not behaving as intending. i want logrotate to create a new logfile for each day, but only to keep and store i.e. compress non-empty files. my logrotate config looks currently like this # sample configuration for logrotate being a remote server for multiple clients /var/log/syslog { rotate 3 daily missingok notifempty delaycompress compress dateext nomail postrotate reload rsyslog >/dev/null 2>&1 || true endscript } # local i.e. the system's very own logs: keep logs for a whole month /var/log/kern.log /var/log/kernel-info /var/log/auth.log /var/log/auth-info /var/log/cron.log /var/log/cron-info /var/log/daemon.log /var/log/daemon-info /var/log/mail.log /var/log/rsyslog /var/log/rsyslog-info { rotate 31 daily missingok notifempty delaycompress compress dateext nomail sharedscripts postrotate reload rsyslog >/dev/null 2>&1 || true endscript } # received i.e. logs from the clients /var/log/path-to-logs/*/* { rotate 31 daily missingok notifempty delaycompress compress dateext nomail } what i end up with is having is some sort of "summarized" files such as filename-datestampDay-Day and corresponding .gz files. What I do have are empty files, which are eventually zipped. so does the notifempty directive is in fact responsible for these DayX-DayY files, days on which really nothing happened? what would be an efficient way to drop both, empty log files and their .gz files, so that I eventually only keep logs/compressed files that truly contain data?

  Read the article

< Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >