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  • Changing background image on accordion change - jQuery Ui

    - by Coughlin
    I am using this code: $('.ui-accordion').bind('accordionchange', function(event, ui) { $(this).next().next().css({'background-image':'images/green-bg.jpg'}); //ui.newHeader // jQuery object, activated header //ui.oldHeader // jQuery object, previous header // ui.newContent // jQuery object, activated content // ui.oldContent // jQuery object, previous content }); To try to change the background image of the PREVIOUS header after it changes. I see that the jquery docs supply the object for oldHeader, but I am trying to change the CSS of that element. Any ideas how I would do that? So You go to the next one it goes green, then the current one is going to be red. Thanks, Ryan

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  • Why bother to limit the types imported from a python package?

    - by Fast Fish
    When using many IDEs that support autocompletion with Python, things like this will show warnings, which I find annoying: from eventlet.green.httplib import BadStatusLine When switching to: rom eventlet.green.httplib * The warnings go away. What's the benefit to limiting imports to a specific set of types you'll use? Is the parsing faster? Reduces collisions? What other point is there? It seems the state of python IDEs and the nature of the typing system makes it hard for many IDEs to fully get right when a type import works and when it doesn't.

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  • In PHP is faster to get a value from an if statement or from an array?

    - by Vittorio Vittori
    Maybe this is a stupid question but what is faster? <?php function getCss1 ($id = 0) { if ($id == 1) { return 'red'; } else if ($id == 2) { return 'yellow'; } else if ($id == 3) { return 'green'; } else if ($id == 4) { return 'blue'; } else if ($id == 5) { return 'orange'; } else { return 'grey'; } } function getCss2 ($id = 0) { $css[] = 'grey'; $css[] = 'red'; $css[] = 'yellow'; $css[] = 'green'; $css[] = 'blue'; $css[] = 'orange'; return $css[$id]; } echo getCss1(3); echo getCss2(3); ?> I suspect is faster the if statement but I prefere to ask!

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  • How can I also add class to the last list for the second list block in IE?

    - by user244394
    Hi All I have 2 list and i want to add a class ="last" to the list item 5 for both. they seem to work fine on firefox. it add green to both list item 5. But in IE7 it adds only the first list item 5, not the second How can I also add class last it to the second list block as well for IE? .last{background-color: green} jQuery( document ).ready( function () { // Add first and last menu item classes $('ul.menu li:first-child').addClass( 'first_item' ); $('#menu li:last-child').addClass( 'last' ); }); list item 1 list item 2 list item 3 list item 4 list item 5 list item 1 list item 2 list item 3 list item 4 list item 5

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  • SQL Query Help Please

    - by DaveC
    Hello, I have an addition SQL question, hopefully someone here can give me a hand. I have the following mysql table: ID Type Result 1 vinyl blue, red, green 1 leather purple, orange 2 leather yellow and i am seeking the following output: ID Row One Row Two 1 vinyl blue, red, green leather purple, orange 2 leather yellow the thing is... type is not static... there are many different types and not all of them have the same ones. They need to follow in order. Any help is greatly appreciated.

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  • Is there a name for this type of algorithm?

    - by rehanift
    I have a 2 dimensional array forming a table: [color][number][shape ] ------------------------- [black][10 ][square ] [black][10 ][circle ] [red ][05 ][triangle] [red ][04 ][triangle] [green][11 ][oval ] and what I want to do is group largest common denominators, such that we get: 3 groups group #1: color=black, number=10, shapes = [square, circle] group #2: color=red, shape=triange, numbers = [05,04] group #3: color=green, number=11, shape = oval I wrote code that will handle a 2 "column" scenario, then I needed to adjusted it for 3 and I was figuring I might as well do it for n. I wanted to check first if there is some literature around this but I can't think of what to start looking for!

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  • Global variables that can be used in multiple jQuery functions

    - by YouBook
    Can you be able to contain variables that can be used in multiple functions in jQuery, example: var self = $(this); var box = self.parents('.box'); $('#title').click(function() { self.css('background', 'red'); box.slideDown('slow'); }).dblclick(function() { self.css('background', 'green'); box.slideUp('slow'); }); So that self and box can be used within these event functions so I don't have to keep doing this: $('#title').click(function() { var self = $(this); var box = self.parents('.box'); self.css('background', 'red'); }).dblclick(function() { var self = $(this); var box = self.parents('.box'); self.css('background', 'green'); }); But question is, is it possible, if so, how can you do that?

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  • How To Query Many-to-Many Table (one table's values becomes column headers)

    - by CRice
    Given this table structure, I want to flatten out the many-to-many relationships and make the values in the Name field of one table into column headers and the quantities from the same table into column values. The current idea which will work is to put the values into a Dictionary (hashtable) and represent this data in code but im wondering if there is a SQL way to do this. I am also using Linq-to-SQL for data access so a Linq-to-SQL solution would be ideal. [TableA] (int Id) [TableB] (int id, string Name) [TableAB] (int tableAId, int tableBId, int Quantity) fk: TableA.Id joins to TableAB.tableAId fk: TableB.Id joins to TableAB.tableBId Is there a way I can query the three tables and return one result for example: TableA [Id] 1 TableB [Id], [Name] 1, "Red" 2, "Green" 3, "Blue" TableAB [TableAId], [TableBId], [Quantity] 1 1 5 1 2 6 1 3 7 Query Result: [TableA.Id], [Red], [Green], [Blue] 1, 5, 6, 7

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  • How to get select radiobutton value using its name in jQuery?

    - by Prashant
    I am having 4 radiobuttons in my web page like below: <label for="theme-grey"><input type="radio" id="theme-grey" name="theme" value="grey" />Grey</label> <label for="theme-grey"><input type="radio" id="theme-grey" name="theme" value="pink" />Pink</label> <label for="theme-grey"><input type="radio" id="theme-grey" name="theme" value="green" />Green</label> Now in jQuery I want to get the value of selected radiobutton on click of any radiobutton out of above three. In jQuery we have id (#) and class (.) selectors but what if I want to put event on radiobutotn using thier names? as below? $("<radiobutton name attribute>").click(function(){}); Please tell me how to solve this problem. Thanks

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  • Find the 5th element with a specified class in a list and add another class in jQuery

    - by Répás
    I'd like to addClass "green" to the 5th li.hr in every ul containers in my site. $("ul li.hr").each(function() { if ($(this).length = 5) { $(this).addClass("green"); } }); PS: if its possible with CSS only, tell me how please. Note that the ul has mixed elements, like: <li class="a">foo</li> <li class="b">foo</li> <li class="hr">foo</li> <li class="c">foo</li> <li class="a">foo</li> <li class="hr">foo</li> I need the 5th li.hr.

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  • R: Plotting a graph with different colors of points based on advanced criteria

    - by balconydoor
    What I would like to do is a plot (using ggplot), where the x axis represent years which have a different colour for the last three years in the plot than the rest. The last three years should also meet a certain criteria and based on this the last three years can either be red or green. The criteria is that the mean of the last three years should be less (making it green) or more (making it red) than the 66%-percentile of the remaining years. So far I have made two different functions calculating the last three year mean: LYM3 <- function (x) { LYM3 <- tail(x,3) mean(LYM3$Data,na.rm=T) } And the 66%-percentile for the remaining: perc66 <- function(x) { percentile <- head(x,-3) quantile(percentile$Data, .66, names=F,na.rm=T) } Here are two sets of data that can be used in the calculations (plots), the first which is an example from my real data where LYM3(df1) < perc66(df1) and the second is just made up data where LYM3 perc66. df1<- data.frame(Year=c(1979:2010), Data=c(347261.87, 145071.29, 110181.93, 183016.71, 210995.67, 205207.33, 103291.78, 247182.10, 152894.45, 170771.50, 206534.55, 287770.86, 223832.43, 297542.86, 267343.54, 475485.47, 224575.08, 147607.81, 171732.38, 126818.10, 165801.08, 136921.58, 136947.63, 83428.05, 144295.87, 68566.23, 59943.05, 49909.08, 52149.11, 117627.75, 132127.79, 130463.80)) df2 <- data.frame(Year=c(1979:2010), Data=c(sample(50,29,replace=T),75,75,75)) Here’s my code for my plot so far: plot <- ggplot(df1, aes(x=Year, y=Data)) + theme_bw() + geom_point(size=3, aes(colour=ifelse(df1$Year<2008, "black",ifelse(LYM3(df1) < perc66(df1),"green","red")))) + geom_line() + scale_x_continuous(breaks=c(1980,1985,1990,1995,2000,2005,2010), limits=c(1978,2011)) plot As you notice it doesn’t really do what I want it to do. The only thing it does seem to do is that it turns the years before 2008 into one level and those after into another one and base the point colour off these two levels. Since I don’t want this year to be stationary either, I made another tiny function: fun3 <- function(x) { df <- subset(x, Year==(max(Year)-2)) df$Year } So the previous code would have the same effect as: geom_point(size=3, aes(colour=ifelse(df1$Year<fun3(df1), "black","red"))) But it still does not care about my colours. Why does it make the years into levels? And how come an ifelse function doesn’t work within another one in this case? How would it be possible to the arguments to do what I like? I realise this might be a bit messy, asking for a lot at the same time, but I hope my description is pretty clear. It would be helpful if someone could at least point me in the right direction. I tried to put the code for the plot into a function as well so I wouldn’t have to change the data frame at all functions within the plot, but I can’t get it to work. Thank you!

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  • color letters in a div

    - by Growler
    I've created a palindrome checker. I want to take it one step further and show the letters being compared as it is being checked. HTML: <p id="typing"></p> <input type="text" id="textBox" onkeyup="pal(this.value);" value="" /> <div id="response"></div> <hr> <div id="palindromeRun"></div> JS: To do this, I run the recursive check... Then if it is a palindrome, I run colorLetters(), which I'm trying to highlight in green each letter as it is being checked. Right now it is just rewriting palindromeRun's HTML with the first letter. I know this is because of the way I'm resetting its HTML. I don't know how to just grab the first and last letter, change only those letters' css, then increment i and j on the next setTimeout loop. var timeout2 = null; function pal (input) { var str = input.replace(/\s/g, ''); var str2 = str.replace(/\W/, ''); if (checkPal(str2, 0, str2.length-1)) { $("#textBox").css({"color" : "green"}); $("#response").html(input + " is a palindrome"); $("#palindromeRun").html(input); colorLetters(str2, 0, str2.length-1); } else { $("#textBox").css({"color" : "red"}); $("#response").html(input + " is not a palindrome"); } if (input.length <= 0) { $("#response").html(""); $("#textBox").css({"color" : "black"}); } } function checkPal (input, i, j) { if (input.length <= 1) { return false; } if (i === j || ((j-i) == 1 && input.charAt(i) === input.charAt(j))) { return true; } else { if (input.charAt(i).toLowerCase() === input.charAt(j).toLowerCase()) { return checkPal(input, ++i, --j); } else { return false; } } } function colorLetters(myinput, i, j) { if (timeout2 == null) { timeout2 = setTimeout(function () { console.log("called"); var firstLetter = $("#palindromeRun").html(myinput.charAt(i)) var secondLetter = $("#palindromeRun").html(myinput.charAt(j)) $(firstLetter).css({"color" : "red"}); $(secondLetter).css({"color" : "green"}); i++; j++; timeout2=null; }, 1000); } } Secondary: If possible, I'd just like to have it colors the letters as the user is typing... I realize this will require a setTimeout on each keyup, but also am not sure how to write this.

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  • How to show string inside string in different color?

    - by Kishore Kumar
    I have one TextBox and One listbox for searching a collection of data. While searching a text inside a Listbox if that matching string found in anywhere in the list it should show in Green color with Bold. eg. I have string collection like "Dependency Property, Custom Property, Normal Property" if i type in the Search Text box "prop" all the Three with "prop" (only the word Prop) should be in Bold and its color should be in green. any idea how it can be done?. Data inside listbox is represented using DataTemplate.

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  • How to display and change an icon inside a python Tk Frame

    - by codingJoe
    I have a python Tkinter Frame that displays several fields. I want to also add an red/yellow/green icon that will display the status of an external device. The icon is loaded from a file called ICON_LED_RED.ico. How do I display the icon in my frame? How do I change the icon at runtime? for example replace BitmapImage('RED.ico') with BitmapImage('GREEN.ico') class Application(Frame): def init(self, master=None): Frame.__init__(self, master) self.pack() self.createWidgets() def createWidgets(self): # ...other frame code.. works just fine. self.OKBTN = Button(self) self.OKBTN["text"] = "OK" self.OKBTN["fg"] = "red" self.OKBTN["command"] = self.ok_btn_func self.OKBTN.pack({"side": "left"}) # when I add the following the frame window is not visible # The process is locked up such that I have to do a kill -9 self.statusFrame = Frame(self, bd=2, relief=RIDGE) Label(self.statusFrame, text='Status:').pack(side=LEFT, padx=5) self.statIcon = BitmapImage('data/ICON_LED_RED.ico') Label (self.statusFrame, image=self.statIcon ).grid() self.statusFrame.pack(expand=1, fill=X, pady=10, padx=5)

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  • Java: How to I change the color of a specific line or row of string in a Text area?

    - by Kevin
    Hi all, the one way I could change the color is by setForground(). However when there are multiple lines of code it makes everything green or black. Is there another method or any way of solving this problem? Thanks! int key = evt.getKeyCode(); if (key == KeyEvent.VK_ENTER) { String tb1EnterdValue = tb1.getText().toString(); if((tb1EnterdValue.equals("yes")) ) { TextArea1.setForeground(Color.green); else { TextArea1.setForeground(Color.lightGray); } this.TextArea1.append(">"+tb1EnterdValue+newline); this.tb1.setText("");

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  • Wrong Editing Controls Displayed in UITableView

    - by CJC
    Hi all, I'm having a strange problem with UITableView. When the user taps the Edit button, the tableview (which is a grouped view with multiple sections) is supposed to show delete buttons for each row--except for the final row in each section, which has a green add button. When a user taps the green button, a new row is inserted, but now the final row gets a delete button. Even stranger, that delete button ACTS like an add button. So it seems there's a drawing glitch, rather than a problem in assigning the correct style. (Extensive NSLogging shows that the last cell is getting the Insert editing style correctly.) I've tried setting setNeedsDisplay on the cell and the tableView, I've tried reloading that section/row/the entire table, but the issue persists. Any ideas on how to get UITableView to explicitly redraw the editing controls?

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  • How can I store a useful value in my ASP.NET MVC site's URL and make it propagate?

    - by joshjs
    Let's say I have a simple ASP.NET MVC site with two views. The views use the following routes: /Foo and /Foo/Bar. Now let's say I want to use the URL to specify (just for the sake of example) the background color of the site. I want my routes to be, for instance, /Blue/Foo or /Green/Foo/Bar. Also, if I call Html.ActionLink from a view, I want the Blue or Green value to propagate. So, e.g., if I call Html.ActionLink("Bar", "Foo") from /Blue/Foo, I want /Blue/Foo/Bar to come back. How best can I do this? (Forgive me if I'm missing an existing post. This is hard for me to articulate concisely, so I'm not quite sure what to search for.)

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  • How can I prevent PerlTidy from aligning my assignments?

    - by nick
    By default, PerlTidy will line up assignments in my code. E.g. PerlTidy changes this... my $red = 1; my $green = 2; my $yellow = 3; my $cyan = 4; ...into this... my $red = 1; my $green = 2; my $yellow = 3; my $cyan = 4; How do I prevent this from happening? I've trawled the manual but I can't find a solution. Thanks!

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  • Icon backdrop on Samsung Galaxy S? how to change this?

    - by AKh
    Hi all, I see a backdrop being added to my launch icon on the Samsung Galaxy S devices. I need this backdrop changed to a custom backdrop which we created. I know this can be changed since apps like"Daily Briefing" have their own cloud like backdrop making the launch icon look really rich. If anyone does know how to change this backdrop please let me know. I am talking about the background image set behind the icons. Eg: in the below image on the 1st row can you notice the yellow backdrop for Memo app, Green backdrop for Mini Diary app, similarily in the 3rd row notice the green backdrop behind the MAIL app.... I need to change these backdrops. Thanks in advance. Appreciate your help.

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  • All the others (not this)

    - by Narcís
    I have different divs repeated in the same page. This is the example simplified: http://jsfiddle.net/8gPCE/ What I try to do is: -Click on a green and only his red fadeOut -The other red fadeIn -And when I click to anywhere else like the background all the red fadeIn I have been hour trying and I don't find the 3 things at the same time. Something like this doesn't work.(and I just try the 2 first things): $(function(){ $("#green").click(function() { $(this).siblings(".red").fadeOut("slow"); $(this).parent().not(this).children(".red").fadeIn("slow"); }); })

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  • Java2D: if statement doesn`t work with java.awt.Color

    - by DarkSun
    I have a getPixelColour function: Color getPixelColor(int x, int y) { if(mazeImage == null) System.out.println(":("); int pixel = mazeImage.getRGB(x, y); int red = (pixel & 0x00ff0000) >> 16; int green = (pixel & 0x0000ff00) >> 8; int blue = pixel & 0x000000ff; return new Color(red,green,blue); } For example a pixel is black, and System.out.println(getPixelColor(x,y) + " " + Color.BLACK); writes "java.awt.Color[r=0,g=0,b=0] java.awt.Color[r=0,g=0,b=0]" But getPixelColor(x,y) == Color.BLACK return false. What's wrong with it?

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  • WPF Button on or off coloured state

    - by wonea
    I'm trying to create a set of button which have an off or on state, much a checkbox without the check. Ideally I want the colour to change to represent the two different states off(red), green(on). I've tried setting a control template but this only changes the colour for a selection, then reverts back to it's original colour once the mouse leaves the button's vicinity. <ControlTemplate.Triggers> <Trigger Property="IsPressed" Value="True"> <Setter Property="Background" TargetName="Background" Value="Green"/> </Trigger> </ControlTemplate.Triggers>

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  • jQuery - Drag of elements in areas - then not draggable any more

    - by Tim
    Hello! I have three div areas. Creating an element, which is draggable() with jQuery UI, I can drag it all over the screen. Dropping it in a special area, then I can not drag it any more. I created a full working demo: http://jsbin.com/enusu4/2/ There you can create a draggable element which is placed into the left green area. Dragging it to the middle or right green area, I can not drag the element. I increment the zIndex of the elements, but it does not work. Does anyone can help me, what's wrong? Best Regards.

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  • In Perl, how can I iterate over the Cartesian product of multiple sets?

    - by nubie2
    I want to do permutation in Perl. For example I have three arrays: ["big", "tiny", "small"] and then I have ["red", "yellow", "green"] and also ["apple", "pear", "banana"]. How do I get: ["big", "red", "apple"] ["big", "red", "pear"] ..etc.. ["small", "green", "banana"] I understand this is called permutation. But I am not sure how to do it. Also I don't know how many arrays I can have. There may be three or four, so I don't want to do nested loop.

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