Search Results

Search found 36506 results on 1461 pages for 'unsigned long long int'.

Page 561/1461 | < Previous Page | 557 558 559 560 561 562 563 564 565 566 567 568  | Next Page >

  • XNA 4.0 Point Vertex Rendering

    - by luis
    I have a buffer of about 134 million particles and a very powerful computer to render them smoothly but I am getting an error when trying to render them as primitive lines it says I cannot render more than around 1 million. I wonder how can I do this, also if is there a better way to render this other than with lines, I'm comfortable with having 1 pixel points or anything as long as the vertices are shown all the time. I'm basically just plotting the points. thanks.

    Read the article

  • Opengl-es picking object

    - by lacas
    I saw a lot of picking code opengl-es, but nothing worked. Can someone give me what am I missing? My code is (from tutorials/forums) Vec3 far = Camera.getPosition(); Vec3 near = Shared.opengl().getPickingRay(ev.getX(), ev.getY(), 0); Vec3 direction = far.sub(near); direction.normalize(); Log.e("direction", direction.x+" "+direction.y+" "+direction.z); Ray mouseRay = new Ray(near, direction); for (int n=0; n<ObjectFactory.objects.size(); n++) { if (ObjectFactory.objects.get(n)!=null) { IObject obj = ObjectFactory.objects.get(n); float discriminant, b; float radius=0.1f; b = -mouseRay.getOrigin().dot(mouseRay.getDirection()); discriminant = b * b - mouseRay.getOrigin().dot(mouseRay.getOrigin()) + radius*radius; discriminant = FloatMath.sqrt(discriminant); double x1 = b - discriminant; double x2 = b + discriminant; Log.e("asd", obj.getName() + " "+discriminant+" "+x1+" "+x2); } } my camera vectors: //cam Vec3 position =new Vec3(-obj.getPosX()+x, obj.getPosZ()-0.3f, obj.getPosY()+z); Vec3 direction =new Vec3(-obj.getPosX(), obj.getPosZ(), obj.getPosY()); Vec3 up =new Vec3(0.0f, -1.0f, 0.0f); Camera.set(position, direction, up); and my picking code: public Vec3 getPickingRay(float mouseX, float mouseY, float mouseZ) { int[] viewport = getViewport(); float[] modelview = getModelView(); float[] projection = getProjection(); float winX, winY; float[] position = new float[4]; winX = (float)mouseX; winY = (float)Shared.screen.width - (float)mouseY; GLU.gluUnProject(winX, winY, mouseZ, modelview, 0, projection, 0, viewport, 0, position, 0); return new Vec3(position[0], position[1], position[2]); } My camera moving all the time in 3d space. and my actors/modells moving too. my camera is following one actor/modell and the user can move the camera on a circle on this model. How can I change the above code to working?

    Read the article

  • How to Build Your Own Website - Learn 3 Mistakes to Avoid

    There are many ways to learn how to build your own web site; however, there are quite a few mistakes that people make when doing so. In this article you will learn of 3 mistakes you need to avoid when creating your own website, avoiding these mistakes will save you a lot of time and energy in the long run.

    Read the article

  • Essential SEO Advice For 2010 After the Google Mayday Update and Caffeine Roll Out

    So Google have made big changes recently with the Mayday update and the Caffeine rollout. Many webmasters on the various SEO forums such as Webmasterworld and SEOchat have been bemoaning these changes and how they have affected their websites Search Engine Ranking Position with many of their long tail rankings taking a major negative hit. This is not the time for whingeing but instead should be a time for re-evaluation.

    Read the article

  • How to get the users set of date format pattern strings? (3 replies)

    I would like to get the current user's set of date format pattern strings as listed in the Control Panel regional settings applet. For my UK English system I see the following patterns listed: Short Date: dd/MM/yyyy dd/MM/yy d/M/yy d.M.yy yyyy MM dd Long Date: dd MMMM yyyy d MMMM yyyy If I use GetDateTimeFormats (d and D) the results match the expected patterns above, but of course they're the for...

    Read the article

  • Using Query Classes With NHibernate

    - by Liam McLennan
    Even when using an ORM, such as NHibernate, the developer still has to decide how to perform queries. The simplest strategy is to get access to an ISession and directly perform a query whenever you need data. The problem is that doing so spreads query logic throughout the entire application – a clear violation of the Single Responsibility Principle. A more advanced strategy is to use Eric Evan’s Repository pattern, thus isolating all query logic within the repository classes. I prefer to use Query Classes. Every query needed by the application is represented by a query class, aka a specification. To perform a query I: Instantiate a new instance of the required query class, providing any data that it needs Pass the instantiated query class to an extension method on NHibernate’s ISession type. To query my database for all people over the age of sixteen looks like this: [Test] public void QueryBySpecification() { var canDriveSpecification = new PeopleOverAgeSpecification(16); var allPeopleOfDrivingAge = session.QueryBySpecification(canDriveSpecification); } To be able to query for people over a certain age I had to create a suitable query class: public class PeopleOverAgeSpecification : Specification<Person> { private readonly int age; public PeopleOverAgeSpecification(int age) { this.age = age; } public override IQueryable<Person> Reduce(IQueryable<Person> collection) { return collection.Where(person => person.Age > age); } public override IQueryable<Person> Sort(IQueryable<Person> collection) { return collection.OrderBy(person => person.Name); } } Finally, the extension method to add QueryBySpecification to ISession: public static class SessionExtensions { public static IEnumerable<T> QueryBySpecification<T>(this ISession session, Specification<T> specification) { return specification.Fetch( specification.Sort( specification.Reduce(session.Query<T>()) ) ); } } The inspiration for this style of data access came from Ayende’s post Do You Need a Framework?. I am sick of working through multiple layers of abstraction that don’t do anything. Have you ever seen code that required a service layer to call a method on a repository, that delegated to a common repository base class that wrapped and ORMs unit of work? I can achieve the same thing with NHibernate’s ISession and a single extension method. If you’re interested you can get the full Query Classes example source from Github.

    Read the article

  • iwconfig, iw not displaying wireless information

    - by Srivatsa Kanchi
    after fresh install to 12.10, the wireless information is not shown by both iwconfig and iw. The wireless sets up successfully and able to connect This is what i get $ iwconfig wlan0 wlan0 IEEE 802.11abgn ESSID:off/any Mode:Managed Access Point: Not-Associated Tx-Power=14 dBm Retry long limit:7 RTS thr:off Fragment thr:off Power Management:off $ iw wlan0 link Not connected. $ uname -a Linux srivatsa-ThinkPad-T61 3.5.0-18-generic #29-Ubuntu SMP Fri Oct 19 10:26:51 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux

    Read the article

  • Image loaded from TGA texture isn't displayed correctly

    - by Ramy Al Zuhouri
    I have a TGA texture containing this image: The texture is 256x256. So I'm trying to load it and map it to a cube: #import <OpenGL/OpenGL.h> #import <GLUT/GLUT.h> #import <stdlib.h> #import <stdio.h> #import <assert.h> GLuint width=640, height=480; GLuint texture; const char* const filename= "/Users/ramy/Documents/C/OpenGL/Test/Test/texture.tga"; void init() { // Initialization glEnable(GL_DEPTH_TEST); glViewport(-500, -500, 1000, 1000); glMatrixMode(GL_PROJECTION); glLoadIdentity(); gluPerspective(45, width/(float)height, 1, 1000); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); gluLookAt(0, 0, -100, 0, 0, 0, 0, 1, 0); // Texture char bitmap[256][256][3]; FILE* fp=fopen(filename, "r"); assert(fp); assert(fread(bitmap, 3*sizeof(char), 256*256, fp) == 256*256); fclose(fp); glGenTextures(1, &texture); glBindTexture(GL_TEXTURE_2D, texture); glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_LINEAR); glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_LINEAR); glTexImage2D(GL_TEXTURE_2D, 0, GL_RGB, 256, 256, 0, GL_RGB, GL_UNSIGNED_BYTE, bitmap); } void display() { glClearColor(0, 0, 0, 0); glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glEnable(GL_TEXTURE_2D); glBindTexture(GL_TEXTURE_2D, texture); glColor3ub(255, 255, 255); glBegin(GL_QUADS); glVertex3f(0, 0, 0); glTexCoord2f(0.0, 0.0); glVertex3f(40, 0, 0); glTexCoord2f(0.0, 1.0); glVertex3f(40, 40, 0); glTexCoord2f(1.0, 1.0); glVertex3f(0, 40, 0); glTexCoord2f(1.0, 0.0); glEnd(); glDisable(GL_TEXTURE_2D); glutSwapBuffers(); } int main(int argc, char** argv) { glutInit(&argc, argv); glutInitDisplayMode(GLUT_RGB | GLUT_DEPTH | GLUT_DOUBLE); glutInitWindowPosition(100, 100); glutInitWindowSize(width, height); glutCreateWindow(argv[0]); glutDisplayFunc(display); init(); glutMainLoop(); return 0; } But this is what I get when the window loads: So just half of the image is correctly displayed, and also with different colors.Then if I resize the window I get this: Magically the image seems to fix itself, even if the colors are wrong.Why?

    Read the article

  • Suddenly the native app is cool again

    <b>The Open Road:</b> "If the future is cloud-based applications, we still have a long way to go to realize that vision. Ironically, we may actually be getting ever further away from it even as the cloud assumes central importance in the computing landscape."

    Read the article

  • SEO Tactics For Google Caffeine - Time to Think Again

    Google Caffeine is the latest change in algorithm of the leading search engine. The changes made will be highly beneficial for those who are looking for long term SEO and online marketing success. If some decisive factors are kept in mind, webmasters can find a great success with the websites they are running.

    Read the article

  • Use Expressions with LINQ to Entities

    - by EltonStoneman
    [Source: http://geekswithblogs.net/EltonStoneman] Recently I've been putting together a generic approach for paging the response from a WCF service. Paging changes the service signature, so it's not as simple as adding a behavior to an existing service in config, but the complexity of the paging is isolated in a generic base class. We're using the Entity Framework talking to SQL Server, so when we ask for a page using LINQ's .Take() method we get a nice efficient SQL query for just the rows we want, with minimal impact on SQL Server and network traffic. We use the maximum ID of the record returned as a high-water mark (rather than using .Skip() to go to the next record), so the approach caters for records being deleted between page requests. In the paged response we include a HasMorePages indicator, computed by comparing the max ID in the page of results to the max ID for the whole resultset - if the latter is bigger, then there are more pages. In some quick performance testing, the paged version of the service performed much more slowly than the unpaged version, which was unexpected. We narrowed it down to the code which gets the max ID for the full resultset - instead of building an efficient MAX() SQL query, EF was returning the whole resultset and then computing the max ID in the service layer. It's easy to reproduce - take this AdventureWorks query:             var context = new AdventureWorksEntities();             var query = from od in context.SalesOrderDetail                         where od.ModifiedDate >= modified                          && od.SalesOrderDetailID.CompareTo(id) > 0                         orderby od.SalesOrderDetailID                         select od;   We can find the maximum SalesOrderDetailID like this:             var maxIdEfficiently = query.Max(od => od.SalesOrderDetailID);   which produces our efficient MAX() SQL query. If we're doing this generically and we already have the ID function in a Func:             Func<SalesOrderDetail, int> idFunc = od => od.SalesOrderDetailID;             var maxIdInefficiently = query.Max(idFunc);   This fetches all the results from the query and then runs the Max() function in code. If you look at the difference in Reflector, the first call passes an Expression to the Max(), while the second call passes a Func. So it's an easy fix - wrap the Func in an Expression:             Expression<Func<SalesOrderDetail, int>> idExpression = od => od.SalesOrderDetailID;             var maxIdEfficientlyAgain = query.Max(idExpression);   - and we're back to running an efficient MAX() statement. Evidently the EF provider can dissect an Expression and build its equivalent in SQL, but it can't do that with Funcs.

    Read the article

  • Delete button in Ubuntu One Notes

    - by Jean MC13
    For the whishlist... The 'delete button' in Ubuntu One Notes is exactly in the same place as the 'save' button. So I saved a long note, but as my finger clicked two times on the save button, the second click was on the 'delete' one ! Lost without return possible. <:-(( This annoying feature could easily be changed : - put the delete button in another place - before deleting : ask for confirmation - offer a way to cancel ('undelete' function)

    Read the article

  • Java - Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

    Read the article

  • SEO Tactics For Google Caffeine - Time to Think Again

    Google Caffeine is the latest change in algorithm of the leading search engine. The changes made will be highly beneficial for those who are looking for long term SEO and online marketing success. If some decisive factors are kept in mind, webmasters can find a great success with the websites they are running.

    Read the article

  • How do I rip a dvd including menus and extras to a menu driven divx file (or any lossy format that supports menus)?

    - by John Baber
    I am asking exactly this question for the same reason, but would like to archive dvds as small, low quality video, while preserving the menu choosing experience. I would like to rip my dvds to something that has the same menus but whose video is in a much more compressed format. I do not want to copy a dvd to an .iso image. How can this be done in the most automatic (hopefully CLI) way possible? Any format is fine so long as playback on linux is possible.

    Read the article

  • How can I test database access methods in Java?

    - by javaStudent
    I want to write a test for a method that accesses a database such as following. public class MyClass{ public String getAddress(Int id){ String query = "Select * from Address where id="+id; //some additional statements resultSet = statement.executeQuery(); return result.getString(ADDRESS); } } How can I test this method? I am using Java.

    Read the article

  • Creating Your First Website

    If you are looking into website creation as a form of business or just as a hobby to give an input of your freedom of expression, check out how creating your first website can be a simple task as long as you follow these simple tips and believe in yourself. The first thing you want to do when you are looking to create your first website is run a search in a search engine for guides that can help you though the process. There are hundreds of guides available online that run you through the process of website creation....

    Read the article

  • career planning advice [closed]

    - by JDB
    Possible Duplicate: Are certifications worth it? I am at the point in my career where people start to veer off into either management-type roles or they focus on solidifying their technical skills to stay in the development game for the long-haul. Here's my story: I've got a degree in economics, an MA in Political Science and an MBA in Finance and Management. In addition, I've done coursework in advanced math and software development (although no degree in math or software). All-in-all, I've got 13 years of post-secondary education under my belt. I, however, currently work as a software developer using C# for desktop, Silverlight, Flex and javascript for web, and objective c for mobile. I've been in software development for the past 3.3 years, and it seems like it comes pretty easy to me. I work in a field called "geospatial information systems," which just involves customization and manipulation of geospatial data. Right now I am looking at one of several certifications. Given this background, which of these certifications has the highest ceiling? CFA PMP various development/technological certifications from Microsoft, etc. Other? My academic and work experience are all heavy on the analytical/development side, esp. so given the MBA and the B.S. in Econ. The political science degree was really a lot of stats. So it seems that I would be good pursuing more of the CFA/analytical role. This is a difficult path, however, because I have no work experience in the financial sector, and the developers in finance are all "quants," which again, I am OK with, but I haven't done much statistical modeling in the past 3.3 years. The PMP would require knowledge of best practices as it pertains explicitly to software development. I also don't enjoy a lot of business travel, a common theme for most PMP jobs I've seen. If certifications is the route, which would you recommend? Anything else? I've thought about going back to try to knock out a B.S. in C.S., but I wasn't sure how long that would take, or what would be involved. Thoughts or recommendations? Thanks in advance! I turn 32 this weekend, which is what has forced me to think about these issues.

    Read the article

  • What is Search Engine Optimization - An Art Or Science?

    As ridiculous and as outrageous as this question might sound, there has been no evident and obvious answer to this. The fact that the process of Search Engine optimization is an art or mere science is something that web scholars have been debating for a long time, and to people's amusement, have still not come to a concrete conclusion. One important step that was taken towards having this question answered or finding an answer to it was asking all the service providers about the way they think of SEO.

    Read the article

  • Do I need to go to a big-name university?

    - by itaiferber
    As a soon-to-be graduating high school senior in the U.S., I'm going to be facing a tough decision in a few months: which college should I go to? Will it be worth it to go to Cornell or Stanford or Carnegie Mellon (assuming I get in, of course) to get a big-name computer science degree, internships, and connections with professors, while taking on massive debt; or am I better off going to SUNY Binghamton (probably the best state school in New York) and still get a pretty decent education while saving myself from over a hundred-thousand dollars worth of debt? Yes, I know questions like this has been asked before (namely here and here), but please bear with me because I haven't found an answer that fits my particular situation. I've read the two linked questions above in depth, but they haven't answered what I want to know: Yes, I understand that going to a big-name college can potentially get me connected with some wonderful professors and leaders in the field, but on average, how does that translate financially? I mean, will good connections pay off so well that I'd be easily getting rid of over a hundred-thousand dollars of debt? And how does the fact that I can get a fifth-years master's degree at Carnegie Mellon play into the equation? Will the higher degree right off the bat help me get a better-paying job just out of college, or will the extra year only put me further into debt? Not having to go to graduate school to get a comparable degree will, of course, be a great financial relief, but will getting it so early give it any greater worth? And if I go to SUNY Binghamton, which is far lesser-known than what I've considered (although if there are any alumni out there who want to share their experience, I would greatly appreciate it), would I be closing off doors that would potentially offset my short-term economic gain with long-term benefits? Essentially, is the short-term benefit overweighed by a potential long-term loss? The answers to these questions all tie in to my final college decision (again, permitting I make it to these schools), so I hope that asking the skilled and knowledgeable people of the field will help me make the right choice (if there is such a thing). Also, please note: I'm in a rather peculiar situation where I can't pay for college without taking out a bunch of loans, but will be getting little to no financial aid (likely federal or otherwise). I don't want to elaborate on this too much (so take it at face value), but this is mainly the reason I'm asking the question. Thanks a lot! It means a lot to me.

    Read the article

  • Is Your Website Booming Or Busting?

    How long has it been since your website's home page has been updated with fresh new text and images? How about your blog? Has it been weeks... months even... since your last entry? What about the last time you sent out a newsletter?

    Read the article

  • How to Make the Kindle Fire Silk Browser *Actually* Fast!

    - by The Geek
    Not that long ago, we reviewed the Kindle Fire, and one of our biggest complaints was how lousy the browser is—but we’ve discovered the trick to making it actually fast. Here’s how to fix it. How to Make the Kindle Fire Silk Browser *Actually* Fast! Amazon’s New Kindle Fire Tablet: the How-To Geek Review HTG Explains: How Hackers Take Over Web Sites with SQL Injection / DDoS

    Read the article

  • Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

    Read the article

< Previous Page | 557 558 559 560 561 562 563 564 565 566 567 568  | Next Page >