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  • Automatically change div on mouseover and on timer

    - by IrishSaffa
    I'm a bit o a noob so any help would be great... What I need to do is have it so that the div associated to a specific li can change on hover as well as automatically change on a timer so that it scrolls through the option. here is my code: <script type="text/javascript"> $(function () { $("#switches li").mouseover(function () { var $this = $(this); $("#slides div").hide(); $("#slide" + $this.attr("id").replace(/switch/, "")).show(); }); }); </script> <div id="featured"> <ul id="switches"> <li id="switch1"><a href="activity_spa.html">Spa &amp; Wellness</a></li> <li id="switch2"><a href="#">Gala Venues</a></li> <li id="switch3"><a href="#">Dining</a></li> <li id="switch4"><a href="#">Shopping</a></li> <li id="switch5"><a href="#">Golf</a></li> <li id="switch6"><a href="#">Team Building</a></li> <li id="switch7"><a href="#">Equestrian</a></li> </ul> <div id="slides"> <div id="slide1"><img src="images/image2.jpg" alt="" /></div> <div id="slide2" style="display:none;"><img src="images/image6.jpg" alt="" /></div> <div id="slide3" style="display:none;"><img src="images/image1.jpg" alt="" /></div> <div id="slide4" style="display:none;"><img src="images/image3.jpg" alt="" /></div> <div id="slide5" style="display:none;"><img src="images/image5.jpg" alt="" /></div> <div id="slide6" style="display:none;"><img src="images/image7.jpg" alt="" /></div> <div id="slide7" style="display:none;"><img src="images/image4.jpg" alt="" /></div> </div> </div>

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  • How to check of which user-defined type a current JSON element is during $.each()?

    - by Bob
    I have the following structure for a JSON file: ({condos:[{Address:'123 Fake St.', Lat:'56.645654', Lng:'23.534546'},{... another condo ...},{...}],houses:[{Address:'1 Main Ave.', Lat:'34.765766', Lng:'27.8786674'},{... another house ...}, {...}]}) So, I have a list of condos and houses in one big JSON array. I want to plot them all on my map, but I want to give condos and houses different marker icons( blue marker for condos, green marker for houses ). Problem I have is - figuring out how to distinguish between types of markers when I $.each() through them. How would I use if to check whether I'm working with a condo or a house at the moment? var markers = null; $('#map').gmap(mapOptions).bind('init', function(){ $.post('getMarkers.php', function(json){ markers = json; $.each(markers, function(type, dataMembers) { $.each(dataMembers, function(i, j){ //if house use house.png to create marker $('#map').gmap('addMarker', { 'position': new google.maps.LatLng(parseFloat(Lat), parseFloat(Lng)), 'bounds':true, 'icon':'house.png' } ); //if condo use condo.png $('#map').gmap('addMarker', { 'position': new google.maps.LatLng(parseFloat(Lat), parseFloat(Lng)), 'bounds':true, 'icon':'condo.png' } ); }); }); }); });

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  • Radio Button Validation u

    - by Sirojan Gnanaretnam
    I am trying validate the radio button using Javascript . But I couldn't get it. Can any one please help me to fix this Issue. I Have attached My Code Below. Thanks. <form action="submitAd.php" method="POST" enctype="multipart/form-data" name="packages" onsubmit="return checkForm()"> <div id="plans_pay"> <input type="radio" name="group1" id="r1" value="Office" onchange="click_Pay_Office()" style="float:left;margin-top:20px;font-size:72px;"> <label style="float:left; margin-top:20px;" for="pay_office">At Our Office</label> <img style="float:left;margin-bottom:10px;" src="images/Pay-at-office.png" /> </div> <div id="plans_pay"> <input style="float:left;margin-top:20px;font-size:72px;" type="radio" name="group1" id="r2" value="HNB" onchange="click_Pay_Hnb()"> <label style="float:left; margin-top:20px;" for="pay_hnb">At Any HNB Branch</label> <img style="float:left;margin-bottom:10px;" src="images/HNB.png" /> </div> </form> Javascript function checkForm(){ if( document.packages.pso.checked == false && document.packages.pso1.checked == false && document.packages.ph.checked == false && document.packages.ph2.checked == false && document.packages.ph3.checked == false && document.packages.pl.checked == false && document.packages.p3.checked == false && document.packages.p4.checked == false && document.packages.p5.checked == false && document.packages.p6.checked == false ){ alert('Please Select At Least One Package'); return false; } if( document.packages.pso.checked == false && document.packages.pso1.checked == false && document.packages.ph.checked == false && document.packages.ph.checked == false && document.packages.ph2.checked == false && document.packages.ph3.checked == false && document.packages.pl.checked == false && document.packages.p3.checked == false && document.packages.p4.checked == false && document.packages.p5.checked == false && document.packages.p6.checked == false){ alert('Please Select At Least One with the Advertise online option in premium package'); return false; } if(document.getElementById('words').value==''){ alert("Please Enter the Texts"); return false; } if(document.getElementById('r1').checked==false && document.getElementById('r2').checked==false){ alert("Please Select a Payment Method"); return false; } }

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  • Why ajax doesn't work unless I refresh or use location.href?

    - by Connor Tang
    I am working on a html project, which will eventually package by Phonegap. So I am trying to encode the data from html form to JSON format, then use ajax send to a php file resides on server, and receive the response to do something else. Now I use <a href='login.html'> in my index.html to open the login page. In my login page, I have this <script> $(document).ready(function(e) { $('#loginform').submit(function(){ var jData = { "email": $('#emailLogin').val(), "password": $('#Password').val()}; $.ajax({ url: 'PHP/login.php', type:'POST', data: jData, dataType: 'json', async: false, error: function(xhr,status){ //reload(); location.href='index.html'; alert('Wrong email and password'); }, success: function(data){ if(data[1] == 1){ var Id_user = data[0]; location.href='loginSuccess.html'; } } }); }); }); </script> to send my data to server. But I found that it won't work, it's still in the login page. I tried to enter data and submit again, it's still nothing happen. Until I refresh the login page and enter data again, it can give an error message or go to the loginsuccess page. However, when I use <script> function loadLogin(){ location.href='login.html'; } </script> to open the login page, everything works well. So what cause this? How can I modify this piece of code to make it better?

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  • Find an element by class name, from a known parent element

    - by user246114
    Hi, I want to find an element by class name. I know it will appear in a particular parent div, so rather than search the entire dom, I'd like to search only the particular div. I am trying this, but does not seem to be the correct syntax: var element = $("#parentDiv").(".myClassNameOfInterest"); what's the right way to do that? Thanks

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  • AppendTo does not work as desired

    - by Gokul
    When I say, msg.appendTo(ele.parent().next()), the msg successfully gets appended to a <p> with class=foo How can I specify it explicitly in the statement? I tried msg.appendTo(ele.parent().next().find('.foo')); but it doesn't work

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  • Select lowest nested selector when clicked

    - by rikAtee
    I would like to click $('.sub-menu') selector and return the lowerst nested item that was clicked, rather than the highest. e.g., when I click "enlish", "root" is returned becasue "english" is a child of "root". I want "english" returned when I select "english". <div ID="browse_container"> <div class="sub-menu">Root <div class="sub-menu">English</div> <div class="sub-menu">Maths <div class="sub-menu">Year 1</div> <div class="sub-menu">Year 2</div> </div> <div class="sub-menu">? Science</div> </div> </div> my script is simply: $('.sub-menu, #root').on('click', function(event){ alert($(this).text()) });

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  • it's not possible to loop .click function (To create multipple buttons)

    - by user1542680
    Im Trying to create multiple buttons that each one of them doing something else. It working great outside of the "each" loop, But in the moment I'm inserting the .click function in the .each function it doesn't work... Here is the Code: $.each(data.arr, function(i, s){ html += '<div id="mybtn'+s.id+'"><button class="first">Btn1</button><button class="second">Btn2</button></div>'; var btnclass="#mybtn"+s.id+" .first"; $(btnclass).click(function(){ //do something }); }); Please Let me know what is wrong... Thank you very much!!! Eran.

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  • How to focus next field if user clicked on the link?

    - by LA_
    I have a number of fields with labels-links like below: <div class="control-group"> <label class="control-label" for="some-id-1"><a href="http://example.com/some-id-1" target="_blank">Text1</a></label> <div class="controls"> <input type="text" id="some-id-1" name="some-id-1"><br> </div> </div> <div class="control-group"> <label class="control-label" for="some-id-2"><a href="http://example.com/some-id-2" target="_blank">Text2</a></label> <div class="controls"> <input type="text" id="some-id-2" name="some-id-2"><br> </div> </div> If user clicks on the link, how can I focus according field (without preventing default action)? I.e. if user clicks on Text1, then I should open http://example.com/some-id-1 in new window and set focus at input with id some-id-1.

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  • $.ajax is not working

    - by Geetha
    Hi All, In my web page there is a textbox to get the scanned barcode value. Once we scan the barcode it has to get details from the database. I am creating the change event for the textbox. Problem: $.ajax is not working. Code: var target = $('#txtBarcode'), val = target.val(); target.change(monitor()); function monitor() { var xx = $('#txtBarcode').val(); $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", data: "{}", url: "HomePage.aspx/SearchProduct", dataType: "json", success: function(data) { alert("Success!!!"); } }); }

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  • How to take value from radio selection and pass that value into a hidden inputs value attribute?

    - by Matthew
    Hello guys, I need to know if this can be done and if so can someone push me in the right direction. Okay I have a series of radio buttons: <input type="radio" name="level_id" id="radio1" value="XXXX" class="radio1" /> <label for="radio1">choice 1</label> <input type="radio" name="level_id" id="radio2" value="XXXX" class="radio2" /> <label for="radio2">choice 2</label> <input type="radio" name="level_id" id="radio3" value="XXXX" class="radio3" /> <label for="radio3">choice 3</label> <label for="radio4">second choice1</label> <input type="radio" name="level_id" id="radio4" value="1" class="radio4" /> <label for="radio5">second choice2</label> <input type="radio" name="level_id" id="radio5" value="2" class="radio5" /> <label for="radio6">second choice3</label> <input type="radio" name="level_id" id="radio6" value="3" class="radio6" /> Now what I am looking to do is if someone selects CHOICE 1 and then selects SECOND CHOICE1 I would like to pass the value of SECOND CHOICE1 into the value of a hidden input. <input type="hidden" name="sub_source" id="sub_source" value="" /> So that when the form is ready to submit the value that gets passed would be: <input type="hidden" name="sub_source" id="sub_source" value="1" />

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  • MVC Validator numberOfInvalids not working

    - by user965445
    I dynamically add some elements to a form so I know I need to re-parse the form. Even if I have old invalid elements they don't get identified in numberOfInvalids It always comes back = 0 even though the invalid fields are highlighted on the page. var form = $("#form"); //Form Savingform.submit(function (e) { e.preventDefault(); form.removeData("validator"); form.removeData("unobtrusiveValidation"); $.validator.unobtrusive.parse(form); var val = form.validate(); if (val.numberOfInvalids() == 0) { $.blockUI({ fadeIn: 1000 }); AjaxRequest({ data: $(this).serializeArray(), success: function (data, status, xhr) { alert('sucess save or submit, use "'); }, complete: function () { $.unblockUI(); } }); } });

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  • fancybox - passing 'this' to onClosed function

    - by Phil Jackson
    Hi this is probly really simple but I juast cant seem to figure it out! if( is_logged_out( html ) ) { var throughClick = $(this); $.fancybox( html, { 'autoDimensions' : false, 'width' : 'auto', 'height' : 'auto', 'transitionIn' : 'none', 'transitionOut' : 'none', 'hideOnOverlayClick' : false, 'showCloseButton' : false, 'onClosed' : function( throughClick ) { alert(throughClick.attr('name')); throughClick.trigger('click'); } }); }else{ All i want to do is pass the object of whichever button or link that was clicked, so once the user has logged back in it will process again. Any help is much appreciated.

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  • Client side validation script dissapears with $.ajax()

    - by boris callens
    In my javascript file I'm getting the content of a partial with the following call: $.ajax({ type: "GET", url: value.href.replace(actionType, actionType + 'Partial'), dataType: "html", success: function(result) { $("#DepartmentsAction").html(result); alert(result); } }); Because the partial has the call Html.EnableClientValidation() the resulting html has a static script in it. In the result variable in the ajax call this script is present. In the page where the html gets inserted (#DepartmentsAction) the script has dissapeared. What am I doing wrong?

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  • Question about JavaScript syntax

    - by Sakti
    $(document).ready(function(){ var date = new Date(); var d = date.getDate(); var m = date.getMonth(); var y = date.getFullYear(); var month = new array("January","February","March","April","May","June","July","August","September","October","November","December"); var mon; mon = month(m); var today = m+"/"+d+"/"+y $('#calendar').append('<div id="today">Today is'+' '+mon+'/'+d+'/'+y+'.'); });

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  • Submit multiple forms as one

    - by Stephen Sarcsam Kamenar
    I have two forms on the page. To the user it looks like 1 form, and I actually wish it was one form. But the way I'm trying to reuse code and include things, I can't avoid two forms in the source code... trying to act as one. I don't want to do ajax submit, I want a normal post submit, my form handler has redirects in it. How can I submit both of these, and get values that make sense on the server side. something like $_POST['form1]['whatever'] $_POST['form2]['thing'] Maybe take all the inputs from form 2, rename all of them with a prefix, and append them to form 1? I can't find a non-messy way of doing this. I don't think I need code, just a plan. Least messy idea wins.

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  • default menu option

    - by phillip morris
    how can I make this menu here have the default be the "about" tab? http://www.sohtanaka.com/web-design/examples/horizontal-subnav/ so when your mouse isnt hovering over any of them, its on the about tab?

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  • Fancybox: Get id of clicked anchor/element

    - by kastru
    I am trying to get the id of the clicked/shown element in fancybox. I have tried both "this.id" and "this.attr("id")" - but none of them works. $("a.lightbox_image").fancybox({ 'transitionIn': 'elastic', 'transitionOut': 'elastic', 'speedIn': 600, 'speedOut': 200, 'content': 'Id of element clicked'+this.attr("id") }); Any suggestions?

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  • how to call the javscript funtion on table row click

    - by kumar
    hi, I have a javascript function.. <script type="text/javascript"> var RowClick = function() { $("#mytable").click( $("#showgrid").load('/Products/List/Items/')); }; </script> Can I call this function on onclick event on tr? I am calling something like this? <tr class="something" onclick="javascript:RowClick()');"> can i call like this? if I call its not loading the URL? can anybody help me out? thanks

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  • How to convert a string to variable name

    - by p1xelarchitect
    I'm loading several external JSON files and want to check if they have been successfully cached before the the next screen is displayed. My strategy is to check the name of the array to see if it an object. My code works perfectly when I check only a single array and hard code the array name into my function. My question is: how can i make this dynamic? not dynamic: (this works) $("document").ready(){ checkJSON("nav_items"); } function checkJSON(){ if(typeof nav_items == "object"){ // success... } } dynamic: (this doesn't work) $("document").ready(){ checkJSON("nav_items"); checkJSON("foo_items"); checkJSON("bar_items"); } function checkJSON(item){ if(typeof item == "object"){ // success... } } here is the a larger context of my code: var loadAttempts = 0; var reloadTimer = false; $("document").ready(){ checkJSON("nav_items"); } function checkJSON(item){ loadAttempts++; //if nav_items exists if(typeof nav_items == "object"){ //if a timer is running, kill it if(reloadTimer != false){ clearInterval(reloadTimer); reloadTimer = false; } console.log("found!!"); console.log(nav_items[1]); loadAttempts = 0; //reset // load next screen.... } //if nav_items does not yet exist, try 5 times, then give up! else { //set a timer if(reloadTimer == false){ reloadTimer = setInterval(function(){checkJSON(nav_items)},300); console.log(item + " not found. Attempts: " + loadAttempts ); } else { if(loadAttempts <= 5){ console.log(item + " not found. Attempts: " + loadAttempts ); } else { clearInterval(reloadTimer); reloadTimer = false; console.log("Giving up on " + item + "!!"); } } } }

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  • how can i do pagination without reaload page in wordpress

    - by Swap
    how can i do pagination without reaload page in wordpress. i have use following code for the pagination but here page is reaload for each pagination. what can i do to stop realod page???please suggest me. <?php $page = (get_query_var('page')) ? get_query_var('page') : 1 $limit=10; $offset = ( $page - 1 ) * $limit; $data = $wpdb->get_results("select * from wp_products order by product_id $sort_by LIMIT $offset,$limit "); $total=$wpdb->get_results("select * from wp_products "); $pages = COUNT($total); $pages = ceil($pages / $limit); $querystring = ""; foreach ($_GET as $key => $value) { if ($key != "page") $querystring .= "$key=$value&amp;"; } // Pagination ?> <div class="pagination"> <?php if( $pages > 1) { $range=1; $showitems = ($range * 2)+1; $page1=$page; $prev=$page1-1; if($page > 1) { echo "<a class=\"page gradient\" "; echo "href=\"?{$querystring}page=$prev"; echo "\">Previous</a> "; } for ($i = 1; $i <= $pages; $i++) { if (1 != $pages &&( !($i >= $page+$range+1 || $i <= $page-$range-1) || $pages <= $showitems )) { if($i == $page) { echo "<span class=\" page active\">".$i."</span>"; } else { echo "<a class=\"page gradient\""; echo "href=\"?{$querystring}page=$i"; echo "\">$i</a> "; } } } if($page!=$pages) { if($showitems < $pages) { echo "..... "; } $page1=$page; $next=$page1+1; echo "<a " . ($i == $page ? "class=\"page active\" " : "class=\"page gradient\""); echo "href=\"?{$querystring}page=$next"; echo "\">Next</a> "; } } ?> </div>

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  • How do I show the selected item in an HTML <select> at the top

    - by Michael Meadows
    I have an HTML select that looks something like this (values are fake) <select size="40"> <option value="1">What would you do if I sang out of tune,</option> <option value="2">Would you stand up and walk out on me?</option> ... more <option value="156">Lend me your ears, and I'll sing you a song,</option> <option selected="selected" value="157">I will try not to sing out of key.</option> <option value="158">Oh, I get by with a little help from my friends.</option> ... more <option value="507">I get high with a little help from my friends.</option> <option value="509">Gonna' try with a little from my friends.</option> </select> The problem that I have is that when displaying the list after loading the page and the selected option is in the middle of the very long list, IE scrolls the selected option to the top of the list (which is what I want). Firefox, Chrome, Opera, and Safari show it at the bottom (which I don't want). I have to assume that IE is doing it wrong since everyone else shows it at the bottom. How can I force the browsers to display the selected item at the top of the list. I do not want to put it at the top of the list, I just want it to scroll such that the selected option is at the top. bonus, it would be even better if I can put it fourth from the top, but I can live without that if it's too difficult.

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