Search Results

Search found 25852 results on 1035 pages for 'linq query syntax'.

Page 563/1035 | < Previous Page | 559 560 561 562 563 564 565 566 567 568 569 570  | Next Page >

  • sql select with php variable

    - by user1572526
    I'm trying to print out a html-table from db-table 'dimensions'. I only want dimensions from the selected pipetype which I get from a dropdownbox. For now I just put in "Steel" manually. Steel has pipe_id = 2 in db-table 'pipes'. I've run the first query in my db-tool and it returns 2 so there's nothing wrong there. The second query returns nothing. But when I manually set $wq = 2 (which I comment out below) it prints out the html-table perfectly. What am I doing wrong here? $wq="SELECT pipe_id FROM pipes WHERE title_en = 'Steel'"; //$wq = '2'; $sql="SELECT * FROM dimensions WHERE pipe_id = '".$wq."'";

    Read the article

  • mysql joining three specific tables

    - by sam lim
    Here what i would like to pull date from this three table. Table users i have three columns uid, username , data(text) Table users_order i have three columns uid, orders_id , users_email Table order_products i have three columns orders_id, product_id, product_name I would like to use product_id as the ref/search to pull the user info from those three tables. If product_id = 5 The query will display uid; username; users_email; orders_id; product_name; data (text) how would i right the sql query for this situation. Thanks,

    Read the article

  • How can I run everything as root

    - by Hermione
    I have dual booted to lubuntu (with Windows XP) and everytime and then I'm getting asked for my password. How do I run everything as root and not ask a password again? Ideally I wanted to run nginx but it has permission denied issues: apathetic@ubuntu:~$ service nginx start Starting nginx: nginx: [alert] could not open error log file: open() "/var/log/nginx/error.log" failed (13: Permission denied) 2012/08/03 20:06:25 [warn] 4762#0: the "user" directive makes sense only if the master process runs with super-user privileges, ignored in /etc/nginx/nginx.conf:1 nginx: the configuration file /etc/nginx/nginx.conf syntax is ok 2012/08/03 20:06:25 [emerg] 4762#0: open() "/var/run/nginx.pid" failed (13: Permission denied) nginx: configuration file /etc/nginx/nginx.conf test failed

    Read the article

  • Separate Datasource for Gridview Footer

    - by Mike Keller
    I need to able to display the results from a seperate query in the footer of a gridview. What is the best way to go about this? I did some google searches and what I found pretty much revolves using the original datasource and doing something like addition to display the information in the footer. However I really need to be able to display this single line of information from a seperate query. Any direction given would be appreciated. Links, tips, tricks, etc. Thanks.

    Read the article

  • Basic class returns object reference instead of Array

    - by php-b-grader
    I have very basic class: class Customer { protected $id; protected $customer; public function __construct($customer_id) { $this->id = $customer_id; return $this->set_customer(); } protected function set_customer() { $query = mysql_query("SELECT * FROM customer WHERE id = '$this->id'"); $this->customer = mysql_fetch_row($query); return $this->customer; } } $customer = new Customer($order->customer->id); print_r($customer); This is not doing what I want it to but I understand why... $customer returns a reference to the Customer Object... What I want is the MySQL row array from the mysql_fetch_row() - How do I return the array? What am I missing?

    Read the article

  • running a stored procedure inside a sql trigger

    - by Ying
    Hi all, the business logic in my application requires me to insert a row in table X when a row is inserted in table Y. Furthermore, it should only do it between specific times(which I have to query another table for). I have considered running a script every 5 minutes or so to check this, but I stumbled upon triggers and figured this might be a better way to do it. But I find the syntax for procedures a little bewildering and I keep getting an error I have no idea how to fix. Here is where I start: CREATE TRIGGER reservation_auto_reply AFTER INSERT ON reservation FOR EACH ROW BEGIN IF NEW.sent_type = 1 /* In-App */ THEN INSERT INTO `messagehistory` (`trip`, `fk`, `sent_time`, `status`, `message_type`, `message`) VALUES (NEW.trip, NEW.psk, 'NOW()', 'submitted', 4, 'This is an automated reply to reservation'); END; I get an error in the VALUES part of the statmenet but im not sure where. I still have to query the other table for the information I need, but I can't even get past this part. Any help is appreciated, including links to many examples..Thanks

    Read the article

  • create temporary table from cursor

    - by Claudiu
    Is there any way, in PostgreSQL accessed from Python using SQLObject, to create a temporary table from the results of a cursor? Previously, I had a query, and I created the temporary table directly from the query. I then had many other queries interacting w/ that temporary table. Now I have much more data, so I want to only process 1000 rows at a time or so. However, I can't do CREATE TEMP TABLE ... AS ... from a cursor, not as far as I can see. Is the only thing to do something like: rows = cur.fetchmany(1000); cur2 = conn.cursor() cur2.execute("""CREATE TEMP TABLE foobar (id INTEGER)""") for row in rows: cur2.execute("""INSERT INTO foobar (%d)""" % row) or is there a better way? This seems awfully inefficient.

    Read the article

  • PHP - How to retrieve session in php

    - by Klaus Jasper
    I created a table that contains id - names - jobs and page that shows the names only and beside each name there is button Job and session that contains the id. this is my code $query = mysql_query("SELECT * FROM table"); while($fetch = mysql_fetch_array("$query")){ $name = $fetch['names']; $id = $fetch['id']; echo '</br>'; echo $name; $_SESSION['name'] = $id; echo "<button>Job</button>"; } I want when the user click on button Job redirect to a page that contains the job of that session. so how can I do it?

    Read the article

  • Getting Popular Topics on a Custom Made Forum

    - by Navarr
    For this website we're working on, we're trying to get the most popular topics (based on how many posts have been made in them within the last 24 hours). We have a medium to large based forum, and the current MySQL query looks like this: SELECT `forums_topics`.*, ( SELECT COUNT(`id`) FROM `forums_posts` WHERE `postdate` > (UNIX_TIMESTAMP()-60*60*24) AND `topicid`=`forums_topics`.`id` ) AS `trendy_threads` FROM `forums_topics` WHERE `deleted`=0 ORDER BY `trendy_threads` DESC,`postdate` DESC LIMIT 3 This unfortunately causes an SQL timeout with just one query and Error 500's. How can we get this information as quickly and as efficiently as possible?

    Read the article

  • More complex learning source for C# .NET [closed]

    - by Leron
    By complex I don't mean more difficult but including a larger area of possibilities cover. I've started a few years ago with PHP and the transition from learning the syntax of the language and the basic logical structures to working with databases, including JavaScript and so on was very short. And now I'm more interested in studying working with languages like Java/C#. Recently I spend a lot of time reading and writing some simple console applications, I've read almost 2K pages for C# programming and still don't know how to connect to database for example. Just for info I'm interested in web development, socket programing and live streaming, don't know if I'm exceeding myself too much writing that but despite that I want to find some books/internet sources where I can extend my current knowledge of C#/.NET, start using database queries, maybe try something more complicated webwise.

    Read the article

  • Hibernate not Loading a class

    - by Noor
    Hi, I have a class Auction that contains a Class Item and Users but when I am getting the class, the class item and Users are not being loaded. Auction Class Mapping File: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Dec 28, 2010 9:14:12 PM by Hibernate Tools 3.4.0.Beta1 --> <hibernate-mapping> <class name="com.BiddingSystem.Models.Auction" table="AUCTION"> <id name="AuctionId" type="long"> <column name="AUCTIONID" /> <generator class="native" /> </id> <property name="StartTime" type="java.util.Date"> <column name="STARTTIME" /> </property> <property name="EndTime" type="java.util.Date"> <column name="ENDTIME" /> </property> <property name="StartingBid" type="long"> <column name="STARTINGBID" /> </property> <property name="MinIncrement" type="long"> <column name="MININCREMENT" /> </property> <many-to-one name="CurrentItem" class="com.BiddingSystem.Models.Item" fetch="join" cascade="all"> <column name="ItemId" /> </many-to-one> <property name="AuctionStatus" type="java.lang.String"> <column name="AUCTIONSTATUS" /> </property> <property name="BestBid" type="long"> <column name="BESTBID" /> </property> <many-to-one name="User" class="com.BiddingSystem.Models.Users" fetch="join"> <column name="UserId" /> </many-to-one> </class> </hibernate-mapping> When I am doing this: Query query=session.createQuery("from Auction where UserId="+UserId); List <Auction> AllAuctions= new LinkedList<Auction>(query.list()); The Users and Item are null

    Read the article

  • How to be a pro in several programming languages? [on hold]

    - by trerums
    I love PHP and C# languages and i want to be excellent in both. I like to develop PHP applications using MySQL, Nginx, Memcached and so on technologies. I also like ASP.NET MVC stack and think it's great tools. But each technology requires a lot of time to master it. The same is true for C# web stack - there is a huge amount of things to be mastered like Azure, LINQ, Entity Framework ets. Mastering PHP means knowing how it works under the hood. Mastering C# means knowing CLR implementations on a deep level, knowing MSIL etc/ Where to get time for all this? Maybe this is "jack of all trades"? What can you advice?

    Read the article

  • Great F# getting started online book

    - by MarkPearl
    So I have been battling around with F# for a few weeks and it has been frustrating just getting my brain around the syntax etc. Then someone put a comment on my blog that I should check out the following online book called the F# Survival Guide. I highly recommend those wanting to get into the basics of the language to go through this resource. It is easy to understand, especially for someone coming from a C# background. Give it a read… it gets a two thumbs up from me!

    Read the article

  • sqlite error :/* SQL error or missing database */

    - by user262325
    Hello everyone I have a project in which I stored sqlite database file "data.sqlite3" to 'Group'&files'-'resource' Below are my viewcontroller source codes //-myviewcontroller.h #import "sqlite3.h" #define kFilename @"data.sqlite3" //myviewcontroller.m -(NSString *)dataFilePath { NSArray *paths = NSSearchPathForDirectoriesInDomains( NSDocumentDirectory, NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; return [documentsDirectory stringByAppendingPathComponent:kFilename]; } -(void)f { if (sqlite3_open([[self dataFilePath] UTF8String],&database)!=SQLITE_OK) //dataFilePath returns ///Users/interdev/Library/Application Support/iPhone Simulator/User/Applications/095C6E05-4EAE-4817-883E-A72E39D439E0/Documents/data.sqlite3 { sqlite3_close(database); NSAssert(0,@"Failed to open database");//no problem } NSString *query = @"SELECT * FROM table1 ORDER BY ROW";//table1 is table name sqlite3_stmt *statement; NSInteger v=sqlite3_prepare_v2( database, [query UTF8String], -1, &statement, nil); NSString *zs= [NSString stringWithFormat:@"%d",v]; NSLog(@" The buttontitile is %@ ",zs); if ( v == SQLITE_OK) { // ... } I checked value of v in log, it always is 1 #define SQLITE_ERROR 1 /* SQL error or missing database */ I do not know why this happened.

    Read the article

  • How to display mysql records as preselected checkboxes?

    - by Jennifer
    I have a table column called post_tags within a table called posts where assigned tags are stored separated by the @ symbol. I also have a table called tags where all tag names are stored. I would like to design my database in a more normalized way but for the purpose I am trying to achieve this is the easiest option. Anyway, I want to display on the screen all the entries from the tags table as checkboxes, so I do: $query = mysql_query("SELECT * FROM tags ORDER BY name"); while ($row = mysql_fetch_assoc($query)) { $tag = $row['name']; echo "<input type='checkbox' name='tags[]' value='$tag' />\n"; } Next I want to have the tags that are assigned to a particular post be preselected. For example, if I have a post with the following in it's post_tags column: party@beaches@dolphins@ I want the "party", "beaches" and "dolphin" checkboxes to be checked by default (while the checkboxes for the other options are unchecked). How can this be done?

    Read the article

  • Passing a column name instead of index in sqlite3

    - by user271753
    The problem code: NSString *query = @"SELECT Name FROM Category"; sqlite3_stmt *statement; if (sqlite3_prepare_v2(database, [query UTF8String], -1, &statement, nil) == SQLITE_OK) { while (sqlite3_step(statement) == SQLITE_ROW) { char *row =(char *)sqlite3_column_text(statement,0); char *rowData = (char *)sqlite3_column_text(statement,1); NSString *fieldName = [[NSString alloc] initWithUTF8String:row]; NSString *fieldValue = [[NSString alloc] initWithUTF8String:rowData]; NSLog(@"%@",fieldName); NSLog(@"%@",fieldValue); [fieldName release]; [fieldValue release]; } sqlite3_finalize(statement); } char *row =(char *)sqlite3_column_text(statement,0); In the above code instead of 0 can't I just pass a column name? How can I do that ?

    Read the article

  • Simulating python's With statement in java

    - by drozzy
    Is there something like Python with context manager in Java? For example say I want to do something like the following: getItem(itemID){ Connection c = C.getConnection(); c.open(); try{ Item i = c.query(itemID); }catch(ALLBunchOfErrors){ c.close(); } c.close(); return c; } where in python I just have: with( C.getConnection().open() as c): Item i = c.query(itemID); return i;

    Read the article

  • How to replace avconv with (the real) ffmpeg and have it work right?

    - by u2n
    Anyone know how to install the real, current ffmpeg (not the older version by avconv that comes w/ Ubuntu) without having the problems mentioned here? Reasons: Everything works (or so many have written), Use the new syntax, and After some research -- and without getting into the controversy -- I simply believe the packagers made a mistake going with avconv. This is a fix. Apparently this isn't as easy as it should be due to versioning conflicts, and that avconv and ffmpeg can't coexist on the same machine (noted in the above post). Though at least one guide mentions installing ffmpeg locally (~) to achieve coexistence. My release is Precise 12.04.3 LTS, but it appears this would apply to newer ones also.

    Read the article

  • MySQL SELECT WHERE returning empty with long numbers, although they are there

    - by brybam
    Alright, so basically the most simple query ever... I've done this a million times... SELECT * FROM purchased_items WHERE uid = '$uid' if $uid == 123 It works fine and returns all data in rows where uid is 123 if $uid == 351565051447743 It returns empty... I'm positive 351565051447743 is a possible uid in some rows, i literally copied and pasted it into the table. $uid is a string, and is being passed as a string. This is something i've done a million times, and i've never had this simple query not work. Any ideas why this is not working?

    Read the article

  • What will happen if I change the type of a column from int to year?

    - by MachinationX
    I have a table in MySQL 4.0 which currently has a year field as a smallint(6) type. What will happen if I convert it directly to a Year type with a query like the following: ALTER TABLE t MODIFY y YEAR(4) NOT NULL DEFAULT CURRENT_TIMESTAMP; When the current members of column y have values like 2010? I assume that because the year type is technically values from 1-255, values above that will be truncated or broken. So if MySQL isn't smart enough to realize that 2010(int) = 110(year), what would be the simplest query or queries to convert the values? Thanks for your help!

    Read the article

  • response.sendRedirect not working

    - by Amar
    response.sendRedirect method is not working in my program. String id="java"; try { query = "select Id from Users where Id= ?"; ps =Database.getConnection().prepareStatement(query); ps.setString(1, id); rs = ps.executeQuery(); if(rs.next()){ out.println(rs.getString(1)); }else { //out.println("wrong user"); response.sendRedirect("www.google.com"); } rs.close(); }catch(Exception e){ //e.printStackTrace(); System.out.print(e); } form the above i commented "out.println("wrong user");". when i remove this comment it works. but no redirect to the google page. Any answers?

    Read the article

  • Win32_PageFileUsage WMI call returning 0 for CurrentUsage

    - by Ryan Duffield
    I am querying for the current page file usage on Windows-based systems. This is meant to run on the .NET Framework, version 2.0 SP1 and has been tested (and works!) on Windows Vista, Windows 7, Windows Server 2003 R2 and Windows Server 2008. On Windows Server 2003 SP2 (original release, not R2) it appears to return 0: using (var query = new ManagementObjectSearcher("SELECT CurrentUsage FROM Win32_PageFileUsage")) { foreach (ManagementBaseObject obj in query.Get()) { uint used = (uint)obj.GetPropertyValue("CurrentUsage"); return used; } } This is simply returning the results from the first row returned for the WMI call. Even when a page file is being used, it returns 0. What causes the result to be 0 when it should be returning a larger value? It may be something specific to the machine in question, and could have nothing to do with the operating system version. I've also tried this with and without elevated privileges with the same results.

    Read the article

  • Are these 2 sql queries equivalent in all respects (e.g. estimated and actual execution plan)?

    - by Xerion
    Are query 1) == 2) in terms of estimated query plan AND actual plan? (can statistics affect the actual plan here, ever?) declare @cat int -- input param from prc ... 1) select * from A as a join B as b on b.id = a.id on b.cat = @cat join C as c on c.fid = b.fid on c.cat = @cat where a.cat = @cat 2) select * from A as a join B as b on b.id = a.id on b.cat = a.cat join C as c on c.fid = b.fid on c.cat = b.cat where a.cat = @cat It seems to me that these should logically be equivalent and the execution plan should always be the same regardless of actual difference in tables. And adding more conditions either in join, or where, or add more tables to join shouldn't change this. Are there cases this is not true?

    Read the article

< Previous Page | 559 560 561 562 563 564 565 566 567 568 569 570  | Next Page >