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  • how to select distinct rows for a column

    - by Satoru.Logic
    Hi, all. I have a table x that's like the one bellow: id | name | observed_value | 1 | a | 100 | 2 | b | 200 | 3 | b | 300 | 4 | a | 150 | 5 | c | 300 | I want to make a query so that in the result set I have exactly one record for one name: (1, a, 100) (2, b, 200) (5, c, 300) If there are multiple records corresponding to a name, say 'a' in the table above, I just pick up one of them. In my current implementation, I make a query like this: select x.* from x , (select distinct name, min(observed_value) as minimum_val from x group by name) x1 where x.name = x1.name and x.observed_value = x1.observed_value; But I think there may be some better way around, please tell me if you know, thanks in advance.

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  • Mysql select most frequent and sort alphabetically

    - by user2605793
    I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

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  • Getting records from a table based on a filter field and Between but also having the OR login for mu

    - by Pentium10
    I have a this table, where I store multiple ids and an age range (def1,def2) CREATE TABLE "template_requirements" ("_id" INTEGER NOT NULL, "templateid" INTEGER, "def1" VARCHAR(255), "def2" VARCHAR(255), PRIMARY KEY("_id")) Having values such as: templateid | def1 | def2 100 | 7 | 25 200 | 40 | 90 300 | 7 | 25 300 | 40 | 60 as you see for templateid 300 we have an or logic: age between 7 and 25 or age between 40 and 60. I want to get all the template ids that are not for a certain age like 25... What's the problem? If I run a query like this one: SELECT group_concat(templateid) FROM template_requirements where and '25' not between cast(def1 as integer) and cast(def2 as integer) it returns 200, 300, which is wrong, as the 300 matched on row 40 to 60, but shouldn't be included in the result as we have a condition with same templateid 7 to 25 that fails the not beetween stuff. How would be the correct query in SQLite, I would like to keep the group_concat stuff.

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  • Java - learning with a simple project

    - by phodu_insaan
    I remember when I learnt PHP, it was suggested that I code a simple blog or a forum after reading the language fundamentals and syntax. I was told/read that this would cover everything that I would learn about PHP in a beginners book. This advice was out there in a number of places, and after following and working with PHP it seems quite good advice. I am now learning Java, and reading the book Thinking in Java by Bruce Eckel. I wonder if there is any such set of similar, small projects that I could take up, that would cover all the essentials and most of what is covered in the book. Thanks.

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  • 1054 - Unknown column 'apa_calda' in 'where clause'

    - by sebastian
    Hi, I keep getting this error in mysql. Here is the query: SELECT user_id FROM detalii_contor WHERE tip_contor=apa_calda i want to use this query in a php file but it doesn't give any result. so i tried to write it in the sql command prompt. here is what i tried in the php file: $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='".$contor."'"; $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='$contor'"; even without "" or without '' i wanted to get $contor from a form, i also tried with $_POST['util'] and {$_POST['util']} i've also tried to set $contor the value i need, but no result. please help. thanks, Sebastian

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  • Need a field / flag / status number for mutliple use ?

    - by Jules
    I want to create a field in my database which will be easy to query. I think if I give a bit of background this will make more sense. My table has listings shown on my website. I run a program which looks at the listings a decides whether to hide them from being shown on the site. I also hide listings manually for various reasons. I want to store these reasons in a field, so more than one reason could be made for hiding. So I need some form of logic to determine which reasons have been used. Can anyone offer me any guidance on what will be future-proof aka new reasons and what will be quick and easy to query upon ?

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  • Displaying Data from a Join in Codeigniter

    - by Brad
    I am using a simple join to pull data from two databases. This is the join in the model function com_control(){ $this->db->select('*'); $this->db->from('comments'); $this->db->join('posts', 'comments.entry_id = posts.id'); $query = $this->db->get(); return $query->result; } My desired method of display is going to be in a table so I am starting out to use like this foreach($comm_control as $row){ $this->table->add_row( $row->entry_id, $row->comments.id, $row->comment, $row->title ); }//end of foreach My problem is the display of data from comments.id. What is the proper format to add the comment.id into the table rows? I need the ID from both tables for display, edit and delete further on in the table. The only display I get at this time for "comment.id" is the word id. The Any help would be appreciated.

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  • Getting Data Specific to Logged in user

    - by user1770470
    I need to list logged in users active leads,and allow paging and selectable sorting, I cant use the grid because of the layout requirement. I have been searching the web for the last 2 days and cant find any viable solution Any help or direction would be greatly appreciated. var query = db.Query("SELECT a.listingId, a.datetime, c.details, c.buycommercial, c.buyindustrial, c.buyretail, c.buyland, c.tencommercial, c.tenindustrial, c.tenretail, c.tenland, c.investor, c.developer, d.companyname, d.firstname, d.lastname, d.tel, d.cell, d.email FROM dbo.tblactivebroker a JOIN dbo.tblActiveListing b ON a.ListingId = b.ListingId JOIN dbo.tblListings c ON b.ListingId = c.ListingId JOIN dbo.tblContact d ON c.crmid = d.id WHERE b.active = 'True' AND a.ActiveBrokerID = @0",brokerid);

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  • How to make URL pattern like app.example.com?

    - by abc
    I have my domain say "example.com" (java, GlassFish Web Server) Now I have 3 application.. say A,B,C. Now what I want is, if user hit a.example.com OR example.com/X then A application should get invoked. similarly for B and C. b.example.com or example.com/B, c.example.com or example.com/C. like mail.google.com news.google.com. How to configure this? I couldn't query it in Google as I didn't know how to query for this exactly. So posted here. Thankx guyz in advance.

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  • Setting an empty default value for a char-column in MySQL?

    - by user281434
    Hi In phpMyAdmin I have a char(32) column that has no default value(ie. Default: None). When I try to insert data through a SQL query, it throws out an error saying that the column "doesn't have a default value". I need it to be empty, so instead I've just set it's default value as "As defined: " and then nothing in the value field. Is this a bad idea? And is it any better than simply throwing in an empty value for the column in the SQL query? Thanks for your time.

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  • php and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • Optimal search queries

    - by Macros
    Following on from my last question http://stackoverflow.com/questions/2788082/sql-server-query-performance, and discovering that my method of allowing optional parameters in a search query is sub optimal, does anyone have guidelines on how to approach this? For example, say I have an application table, a customer table and a contact details table, and I want to create an SP which allows searching on some, none or all of surname, homephone, mobile and app ID, I may use something like the following: select * from application a inner join customer c on a.customerid = a.id left join contact hp on (c.id = hp.customerid and hp.contacttype = 'homephone') left join contact mob on (c.id = mob.customerid and mob.contacttype = 'mobile') where (a.ID = @ID or @ID is null) and (c.Surname = @Surname or @Surname is null) and (HP.phonenumber = @Homphone or @Homephone is null) and (MOB.phonenumber = @Mobile or @Mobile is null) The schema used above isn't real, and I wouldn't be using select * in a real world scenario, it is the construction of the where clause I am interested in. Is there a better approach, either dynamic sql or an alternative which can achieve the same result, without the need for many nested conditionals. Some SPs may have 10 - 15 criteria used in this way

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  • "Remember" last three MySql queries; Cookie, passed variable or other method?

    - by Camran
    I have a classified website, with pretty sophisticated searching, and I am about to implement a function where the last three queries is displayed for the user, so that the user can go back easier through the queries. This because for each query the user has to provide a lot of input. I have four questions for you: I wonder, how can I save the actual query (SELECT * FROM etc etc)...? Do I need to add some form of encryption to be on the safe side? How will this affect performance? (I don't like the fact that cookies slow websites down) Anything else to think about? If you need more input, let me know... Btw, the website is PHP based. Thanks

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  • Deprecated: Function eregi() is deprecated, how to solve this error ?

    - by Jitendra Vyas
    I'm using this php code. but it's giving error Deprecated: Function eregi() is deprecated in C:\xampp\htdocs\fuel\emailcheck.php on line 7 <? include_once("mastersecure.php"); $emailcheck=$_POST["member_name"]; function isValidEmail($email){ $pattern = "^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$"; if (eregi($pattern, $email)){ return true; } else { return false; } } if (!isValidEmail($_POST['member_name'])){ echo "The email is invalid!"; } else { $query="select email from fuel where email='$_POST[member_name]'"; $res=mysql_query($query); $rowcount=mysql_num_rows($res); if($rowcount!=0) { echo "This mail is already exits"; } } ?> Any solution for this?

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  • What do you need to master a language and its technology? [closed]

    - by LongTTH
    Possible Duplicate: how to really master a programming language Let say about Java(just a sample, you can talk about C#, PHP, C++ ... it's just similar) and 10 (ten) levels, 1 is newbie and 10 is master. How can you identify someone at which level based on his knowledge? I do not tend to compare languages, I do tend to know what indicate a master or a newbie in a language and its (language's) based technology. Yeah, I know there aren't on earth a language stand alone, it always come with a technology with it. Let say in Java, you can memorize all of its keyword and syntax in just few days, but to know it (I mean do something with it effectively), you must read the Oracle (Sun) javadoc many many times (I'm not mention the 3rd party product yet).

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  • How do you manage all of the information you have learned and found? [closed]

    - by B Seven
    Possible Duplicate: How do you manage your knowledge base? What do you use for personal note taking to keep track of everything you learn? Are you always Googling or searching StackOverflow to answer the same questions? Or searching for and copying and pasting existing code? I feel like I have a poor memory, especially remembering things like syntax. Are there any knowledge management systems that would work well for a programming language or operating system? It would be great if there were a way to save everything I learn in an easy to search system. Does such a thing exist? Maybe you would be able to search by question (How to sort an array?, How to set static IP?), or by tag (sort, array, enumeration, iterator, IP). I know it would be easy to develop my own system, but I thought it would be great to learn what works for other people.

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  • Why is Hibernate not loading a column?

    - by B.R.
    I've got an entity with a few properties that gets used a lot in my Hibernate/GWT app. For the most part, everything works fine, but Hibernate refuses to load one of the properties. It doesn't appear in the query, despite being annotated correctly in the entity. The relevant portion of the entity: @Column(name="HasSubSlots") @Type(type="yes_no") public boolean hasSubSlotSupport() { return hasSubSlotSupport; } And the generated SQL query: Hibernate: /* load entities.DeviceModel */ select devicemode0_.DevModel as DevModel1_0_, devicemode0_.InvModelName as InvModel2_1_0_ from DeviceModels devicemode0_ where devicemode0_.DevModel=? Despite the fact that I refer to that property, it's never loaded, lazily or not, and the getter always returns false. Any ideas on how I can dig deeper into this, or what might be wrong?

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  • Using calculated fields over and over again with a new table

    - by Sin5k4
    I'm fairly new to SQL and i had to do some calculations using a table.Imagine we have a table with fields : ID - Name - Val1 - Val2 ; Lets say i want to add up 2 values and add it to my query result.I can do that easily with a sub query such as: select val1+val2 as valtotal,* from my table. Now if i want to do some more process on valtotal, i use a derived table such as; select valtotal*3 as ValMoreCalculated,* from (select val1+val2 as valtotal,* from my table) AS A A bit more code maybe?? select ValMoreCalculated/valtotal as ValEvenMoreCalc ,* from (select valtotal*3 as ValMoreCalculated,* from (select val1+val2 as valtotal,* from my table) AS A)AS B So if i want to do more calculations with the ValMoreCalculated do i have to go through another derived table? Name it as B for example? Is there an easier way to achieve this in SQL? PS:the title is a bit off i know,but couldn't figure out what to name it :P

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  • Is there a way to update a database when installing/upgrading an app?

    - by Adam
    I have a main application, and a bunch of sub-applications (they are separate apps, which do not appear on the android home dashboard). I was planning on having a SQLite DB which the main app maintains, and get a list of available sub-apps from. Is there a way to update this main database as the user installs the sub-apps? Two alternative I was thinking of include: User installs the sub-apps via the main app, which would then update the DB. Rather than use the DB to find all installed sub-apps, have each sub-app declare a category, and use intents to query for all applications which match that query (is this even possible? if so, advice is welcomed). Thanks!

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  • C# WPF to Embedded programming transition

    - by Cheltoonjr
    I've been learning C# .NET Framework for around 4-6 months (still starting) using some books, and have currently made my way up to Collections and Generics. I'll probably spend the next two months covering the rest up to LINQ and/or Garbage Collections. The thing is, I started to get interested in embedded systems and found out that you can use C# to code it through .NET MF, which mean I wouldn't have to learn C or C++. So, I would like to know if the knowledge I'll have by that time (2 months) will be enough to start working on Embedded (using C# .NET Micro Framework and Netduino) or I should probably see more about plain C# like Multithreading, async and other advanced features ? I want use embedded just as a hobby, at least by now, as I'll still have a long way through university. Although, I'll probably pick it as a career then. Thanks in advance!

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  • How can I avoid the engineering mistakes of PDT?

    - by ashy_32bit
    As a developer with enough experience to evaluate a tool, I may say that PDT is very huge in size and slow in performance for a PHP IDE. It gets bigger by release and exponentially slower by the size of the projects. Add some extra syntax coloring rules and it literally crawls, code completion works randomly and building workspace takes like forever. Java black magic (-Xmx etc) eases the pain a little but that's it. So my questions are: Why is PDT like this? What design or engineering factors led to its poor performance? How can I avoid making these same mistakes in my own products?

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  • MySQL GROUP BY with three tables

    - by Psaniko
    I have the following tables: posts (post_id, content, etc) comments (comment_id, post_id, content, etc) posts_categories (post_category_id, post_id, category_id) and this query: SELECT `p`.*, COUNT(comments.comment_id) AS cmts, posts_categories.*,comments.* FROM `posts` AS `p` LEFT JOIN `posts_categories` ON `p`.post_id = `posts_categories`.post_id LEFT JOIN `comments` ON `p`.post_id = `comments`.post_id GROUP BY `p`.`post_id` There are three comments on post_id=1 and four in total. In posts_categories there are two rows, both assigned to post_id=1. I have four rows in posts. But if I query the statement above I get a result of 6 for COUNT(comments.comment_id) at post_id=1. How is this possible? I guess the mistake is somewhere in the GROUP BY clause but I can't figure out where. Any suggestions?

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  • Problem carrying Session over to other pages

    - by AAA
    I am able to login a user, but while processing to the next page (memebers area) I can't display any user info let alone print the $_SESSION[email]. I am not sure what's up. Below is the login code and the testing members are page. Login page: session_start(); //also in a real app you would get the id dynamically $sql = "select `email`, `password` from `accounts` where `email` = '$_POST[email]'"; $query = mysql_query($sql) or die ("Error: ".mysql_error()); while ($row = mysql_fetch_array($query)){ $email = $row['email']; $secret = $row['password']; //we will echo these into the proper fields } mysql_free_result($query); // Process the POST variables $email = $_POST["email"]; //Variables $_SESSION["email"] = $_POST["email"]; $secret = $info['password']; //Checks if there is a login cookie if(isset($_COOKIE['ID_my_site'])) //if there is, it logs you in and directes you to the members page { $email = $_COOKIE['ID_my_site']; $pass = $_COOKIE['Key_my_site']; $check = mysql_query("SELECT email, password FROM accounts WHERE email = '$email'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if (@ $info['password'] != $pass) { } else { header("Location: home.php"); } } } //if the login form is submitted if (isset($_POST['submit'])) { // if form has been submitted // makes sure they filled it in if(!$_POST['email'] | !$_POST['password']) { die('You did not fill in a required field.'); } // checks it against the database if (!get_magic_quotes_gpc()) { $_POST['email'] = addslashes($_POST['email']); } $check = mysql_query("SELECT email,password FROM accounts WHERE email = '".$_POST['email']."'")or die(mysql_error()); //Gives error if user dosen't exist $check2 = mysql_num_rows($check); if ($check2 == 0) { die('That user does not exist in our database. <a href=add.php>Click Here to Register</a>'); } while($info = mysql_fetch_array( $check )) //gives error if the password is wrong if (@ $_POST['password'] != $info['password']) { die('Incorrect password, please try again'); } else { // if login is ok then we add a cookie $_POST['email'] = stripslashes($_POST['email']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['email'], $hour); setcookie(Key_my_site, $_POST['password'], $hour); //then redirect them to the members area header("Location: home.php"); } } } else { // if they are not logged in ?> <?php } ?> home.php session_start(); if(!isset($_SESSION['email'])) { header('Location: login_test3.php'); die('<a href="login_test3.php">Login first!</a>'); } //Variables $_SESSION["email"] = $email; print $_SESSION['name']; UPDATE Just realized the existing code gets in to the home.php file but will not echo anything. But as soon as you hit refresh the session is gone.

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  • Parsing timestamps - do it in MySQL or in PHP?

    - by Andrew Heath
    Let's say you've got a table with a timestamp column, and you want to parse that column into two arrays - $date and $time. Do you, personally: a) query like this DATE(timestamp), TIME(timestamp) , or perhaps even going as far as HOUR(timestamp), MINUTE(timestamp b) grab the timestamp column and parse it out as needed with a loop in PHP I feel like (a) is easier... but I know that I don't know anything. And it feels a little naughty to make my query hit the same column 2 or 3 times for output... Is there a best-practice for this?

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  • SQL Server 2005 Reporting Services: How to count rows that are not null? Any hints for calculating t

    - by user329266
    Is there a way to count only records that are not null; similar to "COUNTA" in Excel? I would think this would be very simple process, but nothing I have tried has worked. If necessary, I can try to work this into my SQL query, but the query is already incredibly complicated. Also, I've found very little documentation for how to calculate report totals, and how to total from groups. Would anyone have any recommendations on what to use as a reference?

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