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  • Linking to a C library compiled as C++

    - by Jacob
    I'm in linker paradise now. I have a C library which only compiles in Visual C++ (it probably works in gcc) if: I compile it as C++ code Define __cplusplus which results in all the declarations being enclosed in extern "C" { } So, by doing this I have a static library called, say, bsbs.lib Now, I have a C++ project called Tester which would like to call function barbar in declared in bsbs.h. All goes fine, until I try to link to bsbs.lib where I get the all-too-familiar: Tester.obj : error LNK2001: unresolved external symbol _foofoo And it always seems to be foofoo which cannot be resolved regardless of which function I call in Tester (barbar or anything else).

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  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

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  • Generating two thumbnails from the same image in Django

    - by Titus
    Hello, this seems like quite an easy problem but I can't figure out what is going on here. Basically, what I'd like to do is create two different thumbnails from one image on a Django model. What ends up happening is that it seems to be looping and recreating the same image (while appending an underscore to it each time) until it throws up an error that the filename is to big. So, you end up something like: OSError: [Errno 36] File name too long: 'someimg________________etc.jpg' Here is the code: def save(self, *args, **kwargs): if self.image: iname = os.path.split(self.image.name)[-1] fname, ext = os.path.splitext(iname) tlname, tsname = fname + '_thumb_l' + ext, fname + '_thumb_s' + ext self.thumb_large.save(tlname, make_thumb(self.image, size=(250,250))) self.thumb_small.save(tsname, make_thumb(self.image, size=(100,100))) super(Artist, self).save(*args, **kwargs) def make_thumb(infile, size=(100,100)): infile.seek(0) image = Image.open(infile) if image.mode not in ('L', 'RGB'): image.convert('RGB') image.thumbnail(size, Image.ANTIALIAS) temp = StringIO() image.save(temp, 'png') return ContentFile(temp.getvalue()) I didn't show imports for the sake of brevity. Assume there are two ImageFields on the Artist model: thumb_large, and thumb_small. If this isn't the correct way to do it, I'd appreciate any feedback. Thanks!

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  • Getting unpredictable data into a tabular format

    - by Acorn
    The situation: Each page I scrape has <input> elements with a title= and a value= I don't know what is going to be on the page. I want to have all my collected data in a single table at the end, with a column for each title. So basically, I need each row of data to line up with all the others, and if a row doesn't have a certain element, then it should be blank (but there must be something there to keep the alignment). eg. First page has: {animal: cat, colour: blue, fruit: lemon, day: monday} Second page has: {animal: fish, colour: green, day: saturday} Third page has: {animal: dog, number: 10, colour: yellow, fruit: mango, day: tuesday} Then my resulting table should be: animal | number | colour | fruit | day cat | none | blue | lemon | monday fish | none | green | none | saturday dog | 10 | yellow | mango | tuesday Although it would be good to keep the order of the title value pairs, which I know dictionaries wont do. So basically, I need to generate columns from all the titles (kept in order but somehow merged together) What would be the best way of going about this without knowing all the possible titles and explicitly specifying an order for the values to be put in?

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  • Scrapy Not Returning Additonal Info from Scraped Link in Item via Request Callback

    - by zoonosis
    Basically the code below scrapes the first 5 items of a table. One of the fields is another href and clicking on that href provides more info which I want to collect and add to the original item. So parse is supposed to pass the semi populated item to parse_next_page which then scrapes the next bit and should return the completed item back to parse Running the code below only returns the info collected in parse If I change the return items to return request I get a completed item with all 3 "things" but I only get 1 of the rows, not all 5. Im sure its something simple, I just can't see it. class ThingSpider(BaseSpider): name = "thing" allowed_domains = ["somepage.com"] start_urls = [ "http://www.somepage.com" ] def parse(self, response): hxs = HtmlXPathSelector(response) items = [] for x in range (1,6): item = ScrapyItem() str_selector = '//tr[@name="row{0}"]'.format(x) item['thing1'] = hxs.select(str_selector")]/a/text()').extract() item['thing2'] = hxs.select(str_selector")]/a/@href').extract() print 'hello' request = Request("www.nextpage.com", callback=self.parse_next_page,meta={'item':item}) print 'hello2' request.meta['item'] = item items.append(item) return items def parse_next_page(self, response): print 'stuff' hxs = HtmlXPathSelector(response) item = response.meta['item'] item['thing3'] = hxs.select('//div/ul/li[1]/span[2]/text()').extract() return item

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  • I am currently serving my static files in Django. How do I use Apache2 to do this?

    - by alex
    (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT}), As you can see, I have a directory called "media" under my Django project. I would like to delete this line in my urls.py and instead us Apache to serve my static files. What do I do to my Apache configs (which files do I change) in order to do this? By the way, I installed Apache2 like normal: sudo aptitude install apache2

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  • matplotlib.pyplot, preserve aspect ratio of the plot

    - by Headcrab
    Assuming we have a polygon coordinates as polygon = [(x1, y1), (x2, y2), ...], the following code displays the polygon: import matplotlib.pyplot as plt plt.fill(*zip(*polygon)) plt.show() By default it is trying to adjust the aspect ratio so that the polygon (or whatever other diagram) fits inside the window, and automatically changing it so that it fits even after resizing. Which is great in many cases, except when you are trying to estimate visually if the image is distorted. How to fix the aspect ratio to be strictly 1:1? (Not sure if "aspect ratio" is the right term here, so in case it is not - I need both X and Y axes to have 1:1 scale, so that (0, 1) on both X and Y takes an exact same amount of screen space. And I need to keep it 1:1 no matter how I resize the window.)

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  • Search for a String and replace it with a variable

    - by chrissygormley
    Hello, I am trying to use regular expression to search a document fo a UUID number and replace the end of it with a new number. The code I have so far is: read_file = open('test.txt', 'r+') write_file = open('test.txt', 'w') r = re.compile(r'(self.uid\s*=\s*5EFF837F-EFC2-4c32-A3D4\s*)(\S+)') for l in read_file: m1 = r.match(l) if m1: new=(str,m1.group(2)) new?????? This where I get stuck. The file test.txt has the below UUID stored in it: self.uid = '5EFF837F-EFC2-4c32-A3D4-D15C7F9E1F22' I want to replace the part D15C7F9E1F22. I have also tried this: r = re.compile(r'(self.uid\s*=\s*)(\S+)') for l in fp: m1 = r.match(l) new=map(int,m1.group(2).split("-") new[4]='RHUI5345JO' But I cannot seem to match the string. Thanks in advance for any help.

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  • How can I lookup an attribute in any scope by name?

    - by Wai Yip Tung
    How can I lookup an attribute in any scope by name? My first trial is to use globals() and locals(). e.g. >>> def foo(name): ... a=1 ... print globals().get(name), locals().get(name) ... >>> foo('a') None 1 >>> b=1 >>> foo('b') 1 None >>> foo('foo') <function foo at 0x014744B0> None So far so good. However it fails to lookup any built-in names. >>> range <built-in function range> >>> foo('range') None None >>> int <type 'int'> >>> foo('int') None None Any idea on how to lookup built-in attributes?

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  • Multiprocessing Bomb

    - by iKarampa
    I was working the following example from Doug Hellmann tutorial on multiprocessing: import multiprocessing def worker(): """worker function""" print 'Worker' return if __name__ == '__main__': jobs = [] for i in range(5): p = multiprocessing.Process(target=worker) jobs.append(p) p.start() When I tried to run it outside the if statement: import multiprocessing def worker(): """worker function""" print 'Worker' jobs = [] for i in range(5): p = multiprocessing.Process(target=worker) jobs.append(p) p.start() It started spawning processes non-stop, without any way of to terminating it. Why would that happen? Why it did not generate 5 processes and exit? Why do I need the if statement?

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  • Sqlalchemy complex in_ clause

    - by lostlogic
    I'm trying to find a way to cause sqlalchemy to generate sql of the following form: select * from t where (a,b) in ((a1,b1),(a2,b2)); Is this possible? If not, any suggestions on a way to emulate it? Thanks kindly!

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  • Application closes on Nokia E71 when using urllib.urlopen

    - by sammr
    Hello, Im running the following code on my Nokia E71. But after the text input, the program closes abruptly. I have a GPRS connection on my phone,but i still seem to be having some problem with urllib.urlopen The code is as follows : import appuifw,urllib amountInDollars = appuifw.query(u"Enter amount in Dollars","text") data=urllib.urlopen("http://www.google.com").read() appuifw.note(u"Hey","info") Any way to fix this problem ? Thank You

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  • How small is *too small* for an opensource project?

    - by Adam Lewis
    I have a fair number of smaller projects / libraries that I have been using over the past 2 years. I am thinking about moving them to Google Code to make it easier to share with co-workers and easier to import them into new projects on my own environments. The are things like a simple FSMs, CAN (Controller Area Network) drivers, and GPIB drivers. Most of them are small (less than 500 lines), so it makes me wonder are these types of things too small for a stand alone open-source project? Note that I would like to make it opensource because it does not give me, or my company, any real advantage.

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  • How to make scipy.interpolate give a an extrapolated result beyond the input range?

    - by Salim Fadhley
    I'm trying to port a program which uses a hand-rolled interpolator (developed by a mathematitian colleage) over to use the interpolators provided by scipy. I'd like to use or wrap the scipy interpolator so that it has as close as possible behavior to the old interpolator. A key difference between the two functions is that in our original interpolator - if the input value is above or below the input range, our original interpolator will extrapolate the result. If you try this with the scipy interpolator it raises a ValueError. Consider this program as an example: import numpy as np from scipy import interpolate x = np.arange(0,10) y = np.exp(-x/3.0) f = interpolate.interp1d(x, y) print f(9) print f(11) # Causes ValueError, because it's greater than max(x) Is there a sensible way to make it so that instead of crashing, the final line will simply do a linear extrapolate, continuing the gradients defined by the first and last two pouints to infinity. Note, that in the real software I'm not actually using the exp function - that's here for illustration only!

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  • simplejson double escapes data causing invalid JSON string

    - by mike_hornbeck
    I have a simple form for managing manufacturers in my shop. After posting form, ajax call returns json with updated data to the form. Problem is, that the returned string is invalid. It looks like it was double-escaped. Strangely similar approach across the whole shop works without any problems. I'm also using jquery 1.6 as javascript framework. Model contains of 3 fields : char for name, text for description and image field for manufacturer logo. The function : def update_data(request, manufacturer_id): """Updates data of manufacturer with given manufacturer id. """ manufacturer = Manufacturer.objects.get(pk=manufacturer_id) form = ManufacturerDataForm(request.FILES, request.POST, instance=manufacturer) if form.is_valid(): form.save() msg = _(u"Manufacturer data has been saved.") html = [ ["#data", manufacturer_data_inline(request, manufacturer_id, form)], ["#selectable-factories-inline", selectable_manufacturers_inline(request, manufacturer_id)], ] result = simplejson.dumps({ "html": html }, cls=LazyEncoder) return HttpResponse(result) The error in console : error with invalid JSON : uncaught exception: Invalid JSON: {"html": [["#data", "\n<h2>Dane</h2>\n<div class="\&quot;manufacturer-image\&quot;">\n \n</div>\n<form action="\&quot;/manage/update-manufacturer-data/1\&quot;" method="\&quot;post\&quot;">\n \n <div class="\&quot;field\&quot;">\n <div class="\&quot;label\&quot;">\n <label for="\&quot;id_name\&quot;">Nazwa</label>:\n </div>\n \n \n <div class="\&quot;error\&quot;">\n <input id="\&quot;id_name\&quot;" name="\&quot;name\&quot;" maxlength="\&quot;50\&quot;" type="\&quot;text\&quot;">\n <ul class="\&quot;errorlist\&quot;"><li>Pole wymagane</li></ul>\n </div>\n \n </div>\n\n <div class="\&quot;field\&quot;">\n <div class="\&quot;label\&quot;">\n <label for="\&quot;id_image\&quot;">Zdjecie</label>:\n </div>\n \n \n <div>\n <input name="\&quot;image\&quot;" id="\&quot;id_image\&quot;" type="\&quot;file\&quot;">\n </div>\n \n </div>\n\n <div class="\&quot;field\&quot;">\n <div class="\&quot;label\&quot;">\n <label for="\&quot;id_description\&quot;">Opis</label>:\n </div>\n \n \n <div>\n <textarea id="\&quot;id_description\&quot;" rows="\&quot;10\&quot;" cols="\&quot;40\&quot;" name="\&quot;description\&quot;"></textarea>\n </div>\n \n </div>\n \n <div class="\&quot;buttons\&quot;">\n <input class="\&quot;ajax-save-button" button\"="" type="\&quot;submit\&quot;">\n </div>\n</form>"], ["#selectable-factories-inline", "\n <div>\n <a class="\&quot;selectable" selected\"\n="" href="%5C%22/manage/manufacturer/1%5C%22">\n L1\n </a>\n </div>\n\n <div>\n <a class="\&quot;selectable" \"\n="" href="%5C%22/manage/manufacturer/4%5C%22">\n KR3W\n </a>\n </div>\n\n <div>\n <a class="\&quot;selectable" \"\n="" href="%5C%22/manage/manufacturer/3%5C%22">\n L1TA\n </a>\n </div>\n\n"]]} Any ideas ?

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  • Most efficient way to update attribute of one instance

    - by Begbie00
    Hi all - I'm creating an arbitrary number of instances (using for loops and ranges). At some event in the future, I need to change an attribute for only one of the instances. What's the best way to do this? Right now, I'm doing the following: 1) Manage the instances in a list. 2) Iterate through the list to find a key value. 3) Once I find the right object within the list (i.e. key value = value I'm looking for), change whatever attribute I need to change. for Instance within ListofInstances: if Instance.KeyValue == SearchValue: Instance.AttributeToChange = 10 This feels really inefficient: I'm basically iterating over the entire list of instances, even through I only need to change an attribute in one of them. Should I be storing the Instance references in a structure more suitable for random access (e.g. dictionary with KeyValue as the dictionary key?) Is a dictionary any more efficient in this case? Should I be using something else? Thanks, Mike

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  • Programmatically sync the db in Django

    - by Attila Oláh
    I'm trying to sync my db from a view, something like this: from django import http from django.core import management def syncdb(request): management.call_command('syncdb') return http.HttpResponse('Database synced.') The issue is, it will block the dev server by asking for user input from the terminal. How can I pass it the '--noinput' option to prevent asking me anything? I have other ways of marking users as super-user, so there's no need for the user input, but I really need to call syncdb (and flush) programmatically, without logging on to the server via ssh. Any help is appreciated.

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