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  • General name for Macs' operating system

    - by andy124
    First of all, I hope that my question is fairly suitable for this site. I have a website where I would like to write articles about some operating systems. Therefore, I have created a main category called "Operating systems". Within a subcategory, I would like to write articles about Apple's operating system that is running on Macs. However, I do not know what to name this category. I have always thought the name was just OS X, but come to think about it, the "X" is actually part of the version (10). Therefore I cannot exactly call my category OS X, because what about when OS 11 is released in a few years? And since Apple has gone from Mac OS X to just OS X, then I cannot use "Mac OS". And, if I remove the X from OS X, then I only have "OS" left, which does not seem so proper. I am really looking for a meaningful all-round name for the Macs' operating system that does not involve the versioning. I was thinking about just calling the category "Mac", but that is not precise either - but perhaps the closest I can get?

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  • Changing The Underlying Background Color Of A Swing Window

    - by dimo414
    As discussed here, when resizing a Swing application in Vista (and Windows 7, which is what I'm using) you get a black background in the right/bottom corner while Swing's repaint catches up to the changes. Playing with other applications (Windows Explorer (Native), Firefox (C++?), and Eclipse (Java)) I notice that they all have this same problem - contrary to what the folks in the link above say - but they minimize the problem by having a grey fill color, which is far less visually jarring than the black that appears in Swing. I'm wondering if there's some way to change this so that Swing behaves like these other applications? I tried setting the background color of the JFrame, but to no avail.

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  • jquery - Create a List of all LIs Name's

    - by nobosh
    Given the following block of HTML: <ul id="taglist"> <li><a name="45" href="">Product 1</a></li> <li><a name="1146" href="">Product 2</a></li> <li><a name="13437" href="">Product 3</a></li> <li><a name="51" href="">Product 4</a></li> </ul> Is it possible for JQUERY to return a STRING, one variable with the name values: alert(tagliststring); Would alert: 45,1146,13437,51 Thanks

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  • How to get field name......

    - by user229538
    Recently i have implemented django-sphinx search on my website. It is working fine of each separate model. But now my client requirement has changed. To implement that functionality i need field name to whom search is made. suppose my query is: "select id, name,description from table1" and search keyword is matched with value in field "name". So i need to return that field also. Is it possible to get field name or any method provided by django-sphinx which return field name. Please help me...

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  • Set button content in a label (custom control)

    - by user1881207
    Instead of voting negative this question, answer to tell me what's wrong! I want to set the Button Content in a label in the custom control, because when I use it, the Content property is not visible and the button is empty (no text). <Button x:Class="WpfApplication1.UserControl1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" mc:Ignorable="d" d:DesignHeight="35" d:DesignWidth="273" Content="Button"> <Button.Template> <ControlTemplate> <Grid> <Rectangle Name="rGridBack" StrokeThickness="1"> <Rectangle.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF4D4D4D" Offset="1" /> <GradientStop Color="#FF404040" Offset="0" /> </LinearGradientBrush> </Rectangle.Fill> <Rectangle.Stroke> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF4F4F4F" Offset="0" /> <GradientStop Color="#FF5B5B5B" Offset="1" /> </LinearGradientBrush> </Rectangle.Stroke> </Rectangle> <Rectangle Fill="#FF1E1E1E" Margin="1,1,1,1" Name="rThickness" /> <Rectangle Margin="2,2,2,2" Name="rGridTop" StrokeThickness="1"> <Rectangle.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF68686C" Offset="0" /> <GradientStop Color="#FF474747" Offset="1" /> </LinearGradientBrush> </Rectangle.Fill> <Rectangle.Stroke> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF7F7F7F" Offset="0" /> <GradientStop Color="#FF575757" Offset="1" /> </LinearGradientBrush> </Rectangle.Stroke> </Rectangle> <!--This label is where I want to set the Button.Content property--> <Label FontWeight="Normal" Foreground="White" HorizontalContentAlignment="Center" Name="tblckStep1Desc" Padding="0" VerticalContentAlignment="Center"> <Label.Effect> <DropShadowEffect BlurRadius="2" Color="Black" Direction="330" Opacity="0.7" ShadowDepth="1.5" /> </Label.Effect> </Label> </Grid> <ControlTemplate.Triggers> <Trigger Property="Button.Content" Value=""> <Setter Property="Content" TargetName="tblckStep1Desc"> </Setter> </Trigger> <Trigger Property="UIElement.IsMouseOver" Value="True"> <Setter Property="Shape.Fill" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF838383" Offset="0" /> <GradientStop Color="#FF545454" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF595959" Offset="1" /> <GradientStop Color="#FF929292" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridBack"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF414141" Offset="0" /> <GradientStop Color="#FF565656" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Fill" TargetName="rThickness"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF181818" Offset="1" /> <GradientStop Color="#FF181818" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> </Trigger> <Trigger Property="UIElement.IsEnabled" Value="False"> <Setter Property="Shape.Fill" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF68686C" Offset="0" /> <GradientStop Color="#FF474747" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF7F7F7F" Offset="0" /> <GradientStop Color="#FF575757" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridBack"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF4F4F4F" Offset="0" /> <GradientStop Color="#FF5B5B5B" Offset="1" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Fill" TargetName="rThickness"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF1E1E1E" Offset="1" /> <GradientStop Color="#FF1E1E1E" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Control.Foreground" TargetName="tblckStep1Desc"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF898989" Offset="1" /> <GradientStop Color="#FF898989" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> </Trigger> <Trigger Property="ButtonBase.IsPressed" Value="True"> <Setter Property="Shape.Fill" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF313131" Offset="1" /> <GradientStop Color="#FF2E2E2E" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridTop"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF1F1F1F" Offset="1" /> <GradientStop Color="#FF1F1F1F" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Stroke" TargetName="rGridBack"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF414141" Offset="1" /> <GradientStop Color="#FF565656" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Shape.Fill" TargetName="rThickness"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF0C0C0C" Offset="1" /> <GradientStop Color="#FF0C0C0C" Offset="0" /> </LinearGradientBrush> </Setter.Value> </Setter> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Button.Template> The button is based on Adobe CS5 suite on dialog forms, because a lot of code.

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  • jQuery get value from checked element with a given name

    - by Travis Leleu
    I've got an input like so: I'd like to use jQuery to grab that element, and add the function call foo() to the change event. Currently I can get it done, but there are two hacks involved. My (working) code: $(":input[name*=myfield]").change( function( $(":input[name*=myfield]") ) { foo(); }); )}; There are two hacks in there I'd like to eliminate. Keeping in mind that the input names are multidimensional arrays, how can I use the :input[name=somename], versus [name*=someone]? I'd imagine it's faster using an exact name rather than *=, but I can't get the escape sequence correct for the brackets on the multidimensional arrays. Can I chain the call together so that I don't have to select the element twice? Is the standard practice for that to select the HTML element into a var, then use that var? Or can I chain it together? Thanks for the help. Still working on getting my footing in JS/JQ.

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  • finding out Class Name

    - by Aviral
    Hi.. From ApplicationInfo we can get the name of the package of the apk running. For example I have in my code { ApplicationInfo xyz; String abc= xyz.packageName; } This would return the name of the package of the application running. But can we find out the name of the class as well from the name of the .apk running or the one we are trying to access. I want to know how to get the name of the main class of the apk at the run time. Thanks a lot Aviral

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  • MSSQL 2005: Rename DB Server Instance Name?

    - by Code Sherpa
    Hi, Can somebody tell me how to rename the DB server instance name and a DB name in MSSQL 2005? Right Now I Have SERVER/OLDNAME -- oldnameDB I want to change the server instance and also change the db name. I have tried: EXEC sp_renamedb 'oldName', 'newName' and that has changed the dbname as it appers in the tree directory. But, when I do "select @@servername" it is the old name. Also, the MDF and LDF files are still the old name. How do change instance and db names as a clean sweep across the server? Thanks.

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  • XNA .FBX Vertex Color Missing

    - by Alex
    When I vertex paint and export my models from Blender (or Maya) for use in my XNA 4.0 project, I somehow lose the vertex color channel for the model. I use no custom model object or content pipelines and my own shader throws me the error: The current vertex declaration does not include all the elements required by the current vertex shader. Color0 is missing. I tryed to reopen the model in other modeling tools and the vertex colors are there. What could cause the vertex color channel to not get loaded in XNA 4.0? Here's a temporary link to the FBX file(server refuses to send a fbx, so rename the .jpg file to .fbx after downloading) http://resources.gamestack.org/BananaBush.jpg

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  • Dynamically changing background color of specific text without changing other attributes

    - by gsingh2011
    I've written a chrome extension to find text on a page based on a regex query. When text is matched, I wrap the matched text in a <span> tag that has the class highlight where highlight only changes the background color to yellow. The issue is that sometimes there are already styles applied to <span> tags in a webpage. For example, the webpage might have this defined: span { font-size: 200%; } So when I insert my <span> tag in another <span> tag, the font-size is actually 400%. Is there an easy way for my code to just change certain properties of the text, like the background color, without applying the webpage's styles twice?

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  • What's the most effective way to interpolate between two colors? (pseudocode and bitwise ops expecte

    - by navand
    Making a Blackberry app, want a Gradient class. What's the most effective way (as in, speed and battery life) to interpolate two colors? Please be specific. // Java, of course int c1 = 0xFFAA0055 // color 1, ARGB int c2 = 0xFF00CCFF // color 2, ARGB float st = 0 // the current step in the interpolation, between 0 and 1 /* Help from here on. Should I separate each channel of each color, convert them to decimal and interpolate? Is there a simpler way? interpolatedChannel = red1+((red2-red1)*st) interpolatedChannel = interpolatedChannel.toString(16) ^ Is this the right thing to do? If speed and effectiveness is important in a mobile app, should I use bitwise operations? Help me! */

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  • IE - Color transparent not working

    - by poru
    Hello, I have a problem with the IE (what else?): I generate content with CSS which has also a background-image. I looks like that: #nav ul li:after { content: "--"; position: relative; z-index: 99; background: transparent url(image.png); color: transparent; } The text color is in non-IE-browsers transparent, but in all IE browsers it's black and you could see it. How could I make the text transparent/unvisible? I tried already: visibility - opacity - filter - text-indent ... But none did his job right, either it disappears (with it background which I need) or the attribute doesn't apply.

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  • call value inside a JS variable as a JS function name

    - by user1640668
    Hello I have a function to perform actions but name of the function is inside a variable... below code will get the URL's hashed part example: #JHON and remove # and store it inside URLHASH variable..example: JHON var urlhash = document.location.hash; urlhash = urlhash.replace(/^.*#/, ''); always there is a function name from that value inside variable and i want to call value inside that variable as a function name window.onload=function() { Value inside URLHASH variable should run as a name of a variable. example: jhon(); }; Is it possible ? I tried some codes but it calls variable name as a function not value inside the variable..help me..

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  • UITableView - Color a selectede cell in table (remain colored)

    - by Liron Loop
    Hi In my app i'm using a UITableViewController ("grouped style") which in one of its section I want the user to be able to see what he had selected by making this cell colored and other "uncolored". Doing it by updating all cells' background color and reloading table data, each time user touches a cell (in didSelectRowAtIndexPath:) Problem is that there is some processing made in the didSelectRowAtIndexPath: so the color doesn't get changed right a way, rather in a bit delay after touch was made. (I gusse the processing is the resone for the tiny delay) Is there a better way of doing it? Any help will be appreciated Liron P.S. I'm new to all of this...

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  • How to change the size and color of Petrel "Attributes Labels" using Ocean

    - by Nautilus
    I add a property to a PolylineSet using the code below (In the Petrel UI they are named “Attribute labels”) using (ITransaction trans = DataManager.NewTransaction()) { trans.Lock(polylineSet); PolylinePropertyCollection ppc = polylineSet.CreatePropertyCollection(); trans.Lock(ppc); property = ppc.CreateProperty(PetrelProject.WellKnownTemplates.MiscellaneousGroup.General, name); trans.Commit(); } I would like to change the size and color. Does anyone know if this is possible via Ocean? I want to do this because these labels have a size of 1 and color black and it isn't a good default for me. Thanks in advance

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  • Active links' color change in IE6 and FireFox

    - by aladine
    Hi, I make link buttons on sidebar of a web page. It will change color if I click the button. It works well in IE6 but not Firefox. Anyone can advise me how to make it on in FF. Million thanks. Here are parts in css and html body: .sidenav li a:active { background: #cff; color: blue; } .... <div class="sidenav"> <ul> <li><a href="..." ></a></li> </ul>

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  • jquery issue if checked change bg color

    - by user3058067
    Hello i made a script that is supposed to change background when radio is selected. It works but when another radio is selected the previous still remains with the selected color. It works for checkboxes but not for radio. <script type="text/javascript"> $(".table").change(function(){ var c = this.checked ? "#18b9e7" : "#b6bf34"; $(this).parent().css("background-color", c); }); </script> Here is a jsfiddle

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