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  • MySQL my.cnf file not being read, Ubuntu 10.04 64bit

    - by reallyordinary
    I've been researching this for a few hours with no luck. Basically it looks like my server's my.cnf file isn't being read at all. I've searched my server, and there's only one my.cnf file on it, located at /etc/mysql/my.cnf. Its ownership is root:root. I'm running Ubuntu 10.04 64bit on a Linode.com server. I have the latest versions of MySQL and PHP installed. I've edited the my.cnf file, commented out "skip-innodb", and have set innodb to be the default storage engine using default-storage-engine = innodb And then restarted mysql. But when I do show engines, MyISAM is still coming up as the default engine. Also - none of the innodb settings I've added to the my.cnf file are being read. For example, I have this in my.cnf: innodb_buffer_pool_size=4G But in phpmyadmin, InnoDB is showing as having a buffer pool size of 8,192 KiB. Similarly, I have this in the my.cnf: innodb_data-file_path = ibdata1:500M:autoextend But in phpmyadmin, it's reading as ibdata1:10M:autoextend. It doesn't look like MyISAM info is being read from the my.cnf file either. The my.cnf file has skip-external-locking queried out, but it's showing as "on" in phpmyadmin. So - yeah, it looks like nothing in the my.cnf file is being read at all. But the server still works. I'm running a Drupal site on it and it seems to operate fine. So mysql seems to be drawing default settings from... some mysterious secret location. Any idea how I can make mysql see and use this my.cnf file? Actually, wait - it looks like it may be being read, not sure. I checked the error.log and found this: 101128 4:28:52 [ERROR] Cannot find or open table databasename/cache_apachesolr from the internal data dictionary of InnoDB though the .frm file for the table exists. Maybe you have deleted and recreated InnoDB data files but have forgotten to delete the corresponding .frm files of InnoDB tables, or you have moved .frm files to another database? or, the table contains indexes that this version of the engine doesn't support. See http://dev.mysql.com/doc/refman/5.1/en/innodb-troubleshooting.html how you can resolve the problem. InnoDB: Error: auto-extending data file ./ibdata1 is of a different size InnoDB: 640 pages (rounded down to MB) than specified in the .cnf file: InnoDB: initial 32000 pages, max 0 (relevant if non-zero) pages! InnoDB: Could not open or create data files. InnoDB: If you tried to add new data files, and it failed here, InnoDB: you should now edit innodb_data_file_path in my.cnf back InnoDB: to what it was, and remove the new ibdata files InnoDB created InnoDB: in this failed attempt. InnoDB only wrote those files full of InnoDB: zeros, but did not yet use them in any way. But be careful: do not InnoDB: remove old data files which contain your precious data! 101128 4:28:52 [ERROR] Plugin 'InnoDB' init function returned error. 101128 4:28:52 [ERROR] Plugin 'InnoDB' registration as a STORAGE ENGINE failed. 101128 4:28:52 [ERROR] /usr/sbin/mysqld: unknown variable 'innodb_lock_wait_timout=50' 101128 4:28:52 [ERROR] Aborting 101128 4:28:52 [Note] /usr/sbin/mysqld: Shutdown complete

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  • mysql connection error 1045 on windows vista

    - by Namrata
    Environment mysql-essential-5.1 mysql-workbench-oss-5.1.18a windows vista asmin account, UAC off windows firewall exception- add port- mysql 3306 tcp is set I unstalled mysql from installer remove option which delete all related folder and reinstalled it I need to connect mysql from nebeans 6.8 All good tutorials, blogs not really helping much can anybody help me.

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  • MySQL Cursor Issue

    - by James Inman
    I've got the following code - this is the first time I've really attempted using cursors. DELIMITER $$ DROP PROCEDURE IF EXISTS demo$$ DROP TABLE IF EXISTS temp$$ CREATE TEMPORARY TABLE temp( id INTEGER NOT NULL AUTO_INCREMENT, start DATETIME NOT NULL, end DATETIME NOT NULL, PRIMARY KEY(id) ) $$ CREATE PROCEDURE demo() BEGIN DECLARE done INT DEFAULT 0; DECLARE a, b DATETIME; DECLARE cur1 CURSOR FOR SELECT MAX(end) AS end FROM ( SELECT id, start, end, @r := @r + (start > @edate) AS num, @edate := GREATEST(@edate, end) FROM ( SELECT @r := 0, @edate := '0001-01-01' ) vars, student_lectures WHERE ( student_id = 1 AND start >= '2010-04-26 00:00:00' AND end <= '2010-04-30 23:59:59' ) ORDER BY start ) q GROUP BY num; DECLARE cur2 CURSOR FOR SELECT MIN(start) AS start FROM ( SELECT id, start, end, @r := @r + (start > @edate) AS num, @edate := GREATEST(@edate, end) FROM ( SELECT @r := 0, @edate := '0001-01-01' ) vars, student_lectures WHERE ( student_id = 1 AND start >= '2010-04-26 00:00:00' AND end <= '2010-04-30 23:59:59' ) ORDER BY start ) q GROUP BY num LIMIT 1, 18446744073709551615; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; OPEN cur1; OPEN cur2; REPEAT FETCH cur1 INTO a; FETCH cur2 INTO b; IF NOT done THEN INSERT INTO temp(start, end) VALUES(a,b); END IF; UNTIL done END REPEAT; CLOSE cur1; CLOSE cur2; END $$ SELECT * FROM temp; I'm not getting anything outputted into the temp table. Running the following query gives me output, so I know there's rows it should be matching - but I imagine I've made some obvious mistake. SELECT MAX(end) AS end FROM ( SELECT id, start, end, @r := @r + (start > @edate) AS num, @edate := GREATEST(@edate, end) FROM ( SELECT @r := 0, @edate := '0001-01-01' ) vars, student_lectures WHERE ( student_id = 1 AND start >= '2010-04-26 00:00:00' AND end <= '2010-04-30 23:59:59' ) ORDER BY start ) q GROUP BY num; The output this query returns: +---------------------+ | end | +---------------------+ | 2010-04-26 13:00:00 | | 2010-04-26 18:15:00 | | 2010-04-27 11:00:00 | | 2010-04-27 13:00:00 | | 2010-04-27 18:15:00 | | 2010-04-28 13:00:00 | | 2010-04-29 13:00:00 | | 2010-04-29 18:15:00 | | 2010-04-30 13:00:00 | | 2010-04-30 15:15:00 | | 2010-04-30 17:15:00 | +---------------------+ 11 rows in set (0.02 sec)

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  • Meaning of Execute_priv on mysql.db table

    - by Ben Reisner
    I created user 'restriceduser' on my mysql server that is 'locked down'. The mysql.user table has a N for all priveledges for that account. The mysql.db table has Y for only Select, Insert, Update, Delete, Create, Drop; all other privileges are N for that account. I tried to create a stored procedure and then grant him access to run only that procedure, no others, but it does not work. The user receives: Error: execute command denied to user 'restricteduser'@'%' for routine 'mydb.functionname' The stored procedure: CREATE DEFINER = 'restriceduser'@'%' FUNCTION `functionname`(sIn MEDIUMTEXT, sformat MEDIUMTEXT) RETURNS int(11) NOT DETERMINISTIC CONTAINS SQL SQL SECURITY DEFINER COMMENT '' BEGIN .... END; The grant statement I tried: GRANT EXECUTE ON PROCEDURE mydb.functionname TO 'restricteduser'@'%'; I was able to work around by modifying his mysql.db entry with update mysql.db set execute_priv='Y' where user='restricteduser' This seems to be more then I want, because it opens up permissions for him to run any stored procedure in that database, while I only wanted him to have permissions to run the designated function. Does anyone see where my issue may lie?

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  • Adding one subquery makes query a little slower, adding another makes it way slower

    - by Jason Swett
    This is fast: select ba.name, penamt.value penamt, #address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id #join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 And this is fast: select ba.name, #penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id #join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 But this is slow: select ba.name, penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 Why is it fast when I include just one of the two subqueries but slow when I include both? I would think it should be twice as slow when I include both, but it takes a really long time. On on MySQL.

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  • MySQL Error 2013

    - by kova
    I am facing connection failure to MySQL problem when I run my program for more than couple of days.MySQL Error Code is 2013 while connecting to Database. MySQL server and client programs are both on same machine. I am using FC5 as my OS and MySQL version is 5.0.18. Can anybody throw some light on this? I am getting mysql error 2013 while calling mysql_real_connect()... Any help is appreciated. Thanks in Advance k o v a

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  • SQL Queries SELECT IN and SELECT NOT IN

    - by Sequenzia
    Does anyone know why the results of the following 2 queries do not add up to the results of the 3rd one? SELECT COUNT(leadID) FROM leads WHERE makeID NOT IN (SELECT uploadDataMapID FROM DG_App.dbo.uploadData WHERE uploadID = 3 AND uploadRowID = 1) AND modelID NOT IN (SELECT uploadDataMapID FROM DG_App.dbo.uploadData WHERE uploadID = 3 AND uploadRowID = 2) SELECT COUNT(leadID) FROM Leads WHERE makeID IN (SELECT uploadDataMapID FROM DG_App.dbo.uploadData WHERE uploadID = 3 AND uploadRowID = 1) OR modelID IN (SELECT uploadDataMapID FROM DG_App.dbo.uploadData WHERE uploadID = 3 AND uploadRowID = 2) SELECT COUNT(leadID) FROM Leads The first query is the count I need. The second one is to tell the user how many records were suppressed based on the contents of the DG_App.dbo.uploadData table. The third query is just a straight count of all the records. When I run these the results of query 1 + the results of query 2 comes up about 46K records less than the count of the entire table. I have played with grouping the WHERE statements with () but that did not change the counts at all. This is MSSQL Server 2012. Any input on this would be great. Thanks

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  • White Label Ecommerce app. Shared or Individual dbs

    - by MetaDan
    Currently I'm working with an in house white label cms that we resell to multiple clients and it all runs from the same box/db. I'm just looking at converting this to have an ecommerce version that we'll run alongside it. I'm wondering whether there will be an issue keeping all the products/categories/orders in one db or whether it would be advisory to separate each instance of the site into its own db for this. These white label instances will only be sold to smaller companies that probably wont have masses of traffic/products and are looking for a simple ecommerce site. Anything larger will definitely get its own hosting and db. But for smaller scale stuff do you think a single db will be ok?

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  • MySQL & PHP: auto connect to DB or to properly way to pass host/db to MySQL methods

    - by SODA
    Hi, does anyone know of a known method in PHP to auto connect to MySQL db/table in case an app is using multiple databases on multiple hosts? Question 1: are there scripts around that allow to auto connect to necessary host/DB based on query? Question 2: if above is not possible, is there a known approach to properly passing host/DB info to make sure app is properly connected before executing the query?

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  • web page db query optimisation

    - by morpheous
    I am putting together a web page which is quite 'expensive' in terms of Db hits. I dont want to start optimizing at this stage - though with me trying to hit a deadline, I may end up not optimising at all. Currently the page requires 18 (thats right eighteen) hits to the db. I am already using joins, and some of the queries are UNIONed to minimize the trips to the db. My local dev machine can handle this (page is not slow) however, I feel if I release this into the wild, the number of queries will quickly overwhelm my database (mySQL). I could always use memcache or something similar, but I would much rather continue with my other dev work that needs to be completed before the deadline - at least retrieving the page work, its simply a matter of optimization. My question therefore is - is 18 db queries for a single page retrieval completely outrageous - (i.e. I should put everything on hold and optimize the hell of the retrieval logic), or shall I continue as normal, meet the deadline and release on schedule and see what happens?

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  • Access denied for user 'root@localhost' (using password:NO)

    - by Nasser Hajloo
    I'm new to mysql, I'm trying to run Wordpress inmy windows desktop and it need Mysql. I install everything with Web Platform Installer which provided by microsoft. I never seta root password for mysql and in final step of installing wordpressit askfor root password of mysql. What is the default password for root (if there is one) and how to change it? I try mysql -u root password '123' but it show me Access denied for user 'root@localhost' (using password:NO) after this I try mysql -u root -p but it ask for a password which I don't have Thank you in advance

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  • Databases: Migrate data between MS Access DB and MYSQL

    - by Dean
    Hello, I have 2 databases, one is MS Access DB from an old website, and the other one is MYSQL from the new Joomla+VirtueMart based website. I need to migrate existing products from MS Access to MYSQL. I thought of putting both on server and writing SQL queries in MYSQL workbench, untill I have a good script for that, but I'm very new to SQL, so I'd rather avoid that. I there a better way and more efficient for that?

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  • performance issue: difference between select s.* vs select *

    - by kamil
    Recently I had some problem in performance of my query. The thing is described here: poor Hibernate select performance comparing to running directly - how debug? After long time of struggling, I've finally discovered that the query with select prefix like: select sth.* from Something as sth... Is 300x times slower then query started this way: select * from Something as sth.. Could somebody help me, and asnwer why is that so? Some external documents on this would be really useful. The table used for testing was: SALES_UNIT table contains some basic info abot sales unit node such as name and etc. The only association is to table SALES_UNIT_TYPE, as ManyToOne. The primary key is ID and field VALID_FROM_DTTM which is date. SALES_UNIT_RELATION contains relation PARENT-CHILD between sales unit nodes. Consists of SALES_UNIT_PARENT_ID, SALES_UNIT_CHILD_ID and VALID_TO_DTTM/VALID_FROM_DTTM. No association with any tables. The PK here is ..PARENT_ID, ..CHILD_ID and VALID_FROM_DTTM The actual query I've done was: select s.* from sales_unit s left join sales_unit_relation r on (s.sales_unit_id = r.sales_unit_child_id) where r.sales_unit_child_id is null select * from sales_unit s left join sales_unit_relation r on (s.sales_unit_id = r.sales_unit_child_id) where r.sales_unit_child_id is null Same query, both uses left join and only difference is with select.

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  • connect to mysql using c++

    - by hero
    is it possible to connect to an mysql database and issue queries using c++? i found some sample code from the internet but they all use mysql! so u need to install mysql first on the computer. what i want is to use a program from different locations where i don't have mysql installed to access a remote mysql database. is this possible?

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  • Mysql without installer is not working

    - by yyy i 777
    I have downloaded MYSQL without installer suppourt in my windows 64 bit machine . I have followed the guidelines mentioned in this website http://dev.mysql.com/doc/refman/5.0/en/windows-install-archive.html i have installed it inside c: mysql directory . As first step i navigated to c:\mysql\binmysqld , as shown in picture below . This started the Database Then i opened another command Prompt Window and navigated to c:\mysql\bin and typed show databases; With this it it showing an Error in Command Prompt saying

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  • MySQL Privileges required to GRANT EVENT, EXECUTE, LOCK TABLES, and TRIGGER

    - by Brad
    I have an account, user_a, and I would like to grant all available permissions on some_db to user_b. I have tried the following query: GRANT ALTER, ALTER ROUTINE, CREATE, CREATE ROUTINE, CREATE TEMPORARY TABLES, CREATE VIEW, DELETE, DROP, EVENT, EXECUTE, INDEX, INSERT, LOCK TABLES, REFERENCES, SELECT, SHOW VIEW, TRIGGER, UPDATE ON `some_db`.* TO 'user_b'@'%' WITH GRANT OPTION The result: Access denied for user 'user_a'@'%' to database 'some_db' Some experimentation has shown me that the only permissions my account (user_a) is unable to grant are EVENT, EXECUTE, LOCK TABLES, and TRIGGER. What privileges are required for my account to GRANT these privileges to another user? If I run SHOW GRANTS, I get this output: "GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, SHOW DATABASES, SUPER, CREATE TEMPORARY TABLES, REPLICATION SLAVE, REPLICATION CLIENT, CREATE VIEW, SHOW VIEW, CREATE ROUTINE, ALTER ROUTINE, CREATE USER ON *.* TO 'user_a'@'%' IDENTIFIED BY PASSWORD '1234567890abcdef' WITH GRANT OPTION" "GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `some_other_unrelated_db`.* TO 'user_a'@'%'" "GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES, EXECUTE, CREATE ROUTINE, ALTER ROUTINE ON `another_unrelated_db`.* TO 'user_a'@'%' WITH GRANT OPTION"

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  • How to turn off the binary log for mysqld_multi instances?

    - by netvope
    MySQL supports running multiple mysqld on the same server. One of the ways is to use mysqld_multi. If the default MySQL server instance (as configured in the [mysqld] section in my.cnf) uses log-bin, it enables the binary log for all the other instances ([mysqld1], [mysqld2], etc). How can we override the setting for the other instances? We tried putting log-bin= or log-bin=OFF under [mysqld1], but that won't disable the binary log.

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