Search Results

Search found 46973 results on 1879 pages for 'return path'.

Page 57/1879 | < Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >

  • IAuthenticationRequest.RedirectToProvider is not supposed to return, yet it does

    - by ripper234
    The method DotNetOpenAuth.OpenId.RelyingParty.IAuthenticationRequest.RedirectToProvider() is documented never to return: Redirects the user agent to the provider for authentication. Execution of the current page terminates after this call. However, it does return under the latest implementation (3.4.3). I'm using the following code: using (var relayingParty = new OpenIdRelyingParty()) { var response = relayingParty.GetResponse(); if (response == null) { // Stage 2: user submitting Identifier var openId = Request.Form["openId"]; relayingParty.CreateRequest(openId).RedirectToProvider(); throw new Exception("Never gets here"); } ... } (The line with "Never gets here" is reached). I need to return an ActionResult from this method ... Is this a known bug? Is there a aorkaround? Should I return EmptyResult? As far as I understand this is a bug - I submitted it in the project issue tracker.

    Read the article

  • return new string vs .ToString()

    - by Leroy Jenkins
    Take the following code: public static string ReverseIt(string myString) { char[] foo = myString.ToCharArray(); Array.Reverse(foo); return new string(foo); } I understand that strings are immutable, but what I dont understand is why a new string needs to be called return new string(foo); instead of return foo.ToString(); I have to assume it has something to do with reassembling the CharArray (but thats just a guess). Whats the difference between the two and how do you know when to return a new string as opposed to returning a System.String that represents the current object?

    Read the article

  • How return 304 status with FileResult in ASP.NET MVC RC1

    - by Maysam
    As you may know we have got a new ActionResult called FileResult in RC1 version of ASP.NET MVC. Using that, your action methods can return image to browser dynamically. Something like this: public ActionResult DisplayPhoto(int id) { Photo photo = GetPhotoFromDatabase(id); return File(photo.Content, photo.ContentType); } In the HTML code, we can use something like this: <img src="http://mysite.com/controller/DisplayPhoto/657"> Since the image is returned dynamically, we need a way to cache the returned stream so that we don't need to read the image again from database. I guess we can do it with something like this, I'm not sure: Response.StatusCode = 304; This tells the browser that you already have the image in your cache. I just don't know what to return in my action method after setting StatusCode to 304. Should I return null or something?

    Read the article

  • homebrew path issue

    - by Shaun Stanislaus
    Master:~ shaunstanislaus$ ruby <(curl -fsSkL raw.github.com/mxcl/homebrew/go) ==> This script will install: /usr/local/bin/brew /usr/local/Library/... /usr/local/share/man/man1/brew.1 Press enter to continue ==> Downloading and Installing Homebrew... remote: Counting objects: 82368, done. remote: Compressing objects: 100% (39323/39323), done. remote: Total 82368 (delta 56782), reused 65301 (delta 42220) Receiving objects: 100% (82368/82368), 11.68 MiB | 1.59 MiB/s, done. Resolving deltas: 100% (56782/56782), done. From https://github.com/mxcl/homebrew * [new branch] master -> origin/master HEAD is now at 2ea1a0e smpeg: depends on gtk ==> Installation successful! You should run `brew doctor' *before* you install anything. Now type: brew help Master:~ shaunstanislaus$ brew doctor -bash: /usr/local/bin/brew: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/bin/ruby: bad interpreter: No such file or directory Master:~ shaunstanislaus$ echo $PATH /usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/opt/X11/bin:/Users/shaunstanislaus/Library/Application Support/GoodSync:/opt/local/bin:/opt/local/sbin:/usr/local/sbin:/Users/shaunstanislaus/.ec2/bin:/Users/shaunstanislaus/.rvm/bin /usr/local/bin/brew: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/bin/ruby: bad interpreter: No such file or directory how do i fix this path issue? i can't use brew command and i think i previously symlink to wrong location. please advice, thank you.

    Read the article

  • Best practice in setting return value (use else or?)

    - by Deckard
    Whenever you want to return a value from a method, but whatever you return depends on some other value, you typically use branching: int calculateSomething() { if (a == b) { return x; } else { return y; } } Another way to write this is: int calculateSomething() { if (a == b) { return x; } return y; } Is there any reason to avoid one or the other? Both allow adding "else if"-clauses without problems. Both typically generate compiler errors if you add anything at the bottom. Note: I couldn't find any duplicates, although multiple questions exist about whether the accompanying curly braces should be on their own line. So let's not get into that.

    Read the article

  • F# return type coercion

    - by Alex
    Hi, In F# I have a function that returns System.Linq.Expression instances: and System.Object with member this.ToExpression() = match this with | :? System.Int32 -> Expression.Constant(this) :> Expression | :? System.Boolean -> Expression.Constant(this) :> Expression | :? Tml.Runtime.Seq as s -> s.ToExpression() | _ -> failwith "bad expression" If I omit the type coercions on the return values F# will infer the return type of the function to ConstantExpression. My first thought was to explicitly mark the return type as being : #Expression, but that didn't work. Is there a more elegant way of doing this that doesn't involve manually casting return types to the most generic type? Thanks.

    Read the article

  • Ant fileset's "dir" missing from absolute path when using a mapper

    - by spaaarky21
    I've been trying to write an Ant task to "compile" Sass scripts in my project using the apply task but I kept getting a "No such file or directory" error. I thought it might have been caused by spaces in the buildpath so I went through the trouble of moving the project only to find that Ant seems to omitting the fileset's root directory when it returns the path. This is what the target looks like: <target name="sass-compile" depends="properties"> <apply executable="sass"> <srcfile /> <targetfile /> <fileset dir="${project.src.dir}" includes="**/*.scss" /> <globmapper from="*.scss" to="*.css" /> </apply> </target> To help troubleshoot, I switched the executable from sass to echo and I noticed that the mapper is transforming paths like this... /Users/me/Documents/Programming/workspace/Project/src/java/com/proj/web/page/template/Template.scss ...into this... /Users/me/Documents/Programming/workspace/Project/java/com/proj/web/page/template/Template.css Notice that the src directory is missing from the target file path. Am I seeing a bug here or is this somehow expected? I would love to know what's going on here. I have also tried using a regexpmapper, and a filtermapper with replacestring. The result is the same. I'm running Ant 1.7.1, which comes bundled with Eclipse Helios, which I'm running on a Mac. I also tried Ant 1.8 on both Mac and Linux. Nothing works. Does anyone have any ideas?

    Read the article

  • Conflicting return types

    - by Adi
    I am doing a recursive program and I am getting an error about conflicting types: void* buddyMalloc(int req_size) { // Do something here return buddy_findout(original_index,req_size); // This is the recursive call } void *buddy_findout(int current_index,int req_size) { char *selected = NULL; if(front!=NULL) { if(current_index==original_index) { // Do something here return selected; } else { // Do Something here return buddy_findout(current_index+1,req_size); } } else { return buddy_findout(current_index-1,req_size); } } Error: buddy.c: At top level: buddy.c:76: error: conflicting types for ‘buddy_findout’ buddy.c:72: note: previous implicit declaration of ‘buddy_findout’ was here Please note the file buddy.c in which I am defining this does not contain main and is linked with several other .c files.

    Read the article

  • Vaadin: Downloaded file has whole path as file name

    - by javydreamercsw
    I have a download action implemented on my Vaadin application but for some reason the downloaded file has the original file's full path as the file name. Any idea? You can see the code on this post. Edit: Here's the important part of the code: package com.bluecubs.xinco.core.server.vaadin; import com.bluecubs.xinco.core.server.XincoConfigSingletonServer; import com.vaadin.Application; import com.vaadin.terminal.DownloadStream; import com.vaadin.terminal.FileResource; import java.io.*; import java.net.URLEncoder; import java.util.UUID; import java.util.logging.Level; import java.util.logging.Logger; import java.util.zip.CRC32; import java.util.zip.CheckedInputStream; /** * * @author Javier A. Ortiz Bultrón<[email protected]> */ public class FileDownloadResource extends FileResource { private final String fileName; private File download; private File newFile; public FileDownloadResource(File sourceFile, String fileName, Application application) { super(sourceFile, application); this.fileName = fileName; } protected void cleanup() { if (newFile != null && newFile.exists()) { newFile.delete(); } if (download != null && download.exists() && download.listFiles().length == 0) { download.delete(); } } @Override public DownloadStream getStream() { try { //Copy file to directory for downloading InputStream in = new CheckedInputStream(new FileInputStream(getSourceFile()), new CRC32()); download = new File(XincoConfigSingletonServer.getInstance().FileRepositoryPath + System.getProperty("file.separator") + UUID.randomUUID().toString()); newFile = new File(download.getAbsolutePath() + System.getProperty("file.separator") + fileName); download.mkdirs(); OutputStream out = new FileOutputStream(newFile); newFile.deleteOnExit(); download.deleteOnExit(); byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); out.close(); final DownloadStream ds = new DownloadStream( new FileInputStream(newFile), getMIMEType(), fileName); ds.setParameter("Content-Disposition", "attachment; filename=" + URLEncoder.encode(fileName, "utf-8")); ds.setCacheTime(getCacheTime()); return ds; } catch (final FileNotFoundException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } catch (IOException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } } } I already debugged and verified that fileName only contains the file's name not the whole path.

    Read the article

  • Problem in accessing Windows shared folder on Ubuntu using terminal

    - by vikramtheone
    Hi Guys, Description I have 2 systems with me, one running on Windows(Host) and one on Ubuntu, both on a LAN. On the Windows(Host) I develop software intended for the Linux system and because the Linux system has little external memory, my idea to overcome this is by making the project folder on the Host side a Shared Folder with full access and access it on Ubuntu over the network. To achieve this, I have installed Samba on Ubuntu, when I go to Places -> Network I can see the shared project folder and I simply mount it. A link appears on the desktop. Next, using Nautilus I open the link and I can access the contents of the shared folder. Problem Even though I mount the shared project folder, I don't see it appearing in the /media or the /mnt folder, as a result of this I don't know what path to use to access this folder, from the terminal. For example: When, I mounted my USB stick, as expected, a link for the device appears on the Desktop and I also see a folder in the media folder. So, similarly, a mounted shared folder should have appeared on the /mnt folder, too. Can anyone suggest what I should do now? There are many posts around, but no solid solution for this problem. Help!!! :) Vikram

    Read the article

  • CakePHP based project is throwing error saying " return value of new by Reference is Deprecated"

    - by Bindas
    I have upgraded my Xampp to newer version(1.7.2).But right now when I run my project(done in CakePHP) it is throwing bug saying Deprecated: Assigning the return value of new by reference is deprecated in C:\xampp\htdocs\ebayn\cake\libs\debugger.php on line 99 Deprecated: Assigning the return value of new by reference is deprecated in C:\xampp\htdocs\ebayn\cake\libs\debugger.php on line 108 Deprecated: Assigning the return value of new by reference is deprecated in C:\xampp\htdocs\ebayn\cake\libs\file.php on line 96 Deprecated: Assigning the return value of new by reference is deprecated in C:\xampp\htdocs\ebayn\cake\libs\cache\file.php on line 89 Can anyone help me how can I rectify this stuff....??? Thanks In Advance

    Read the article

  • How can I find out a file's path in the text encoding used by PosteRazor?

    - by ændrük
    PosteRazor uses an apparently outdated GUI that is incapable of properly displaying my filenames: For the sake of convenience, I want to be able to open any file in PosteRazor by copying and pasting its path from Nautilus. This works in other applications, but sadly, PosteRazor in unable to understand the path: How can I convert the path that Nautilus generates into a text encoding that is compatible with PosteRazor?

    Read the article

  • Problem with relative file path

    - by Richard Knop
    So here is my program, which works ok: import java.io.FileReader; import java.io.BufferedReader; import java.io.IOException; import java.util.Scanner; import java.util.Locale; public class ScanSum { public static void main(String[] args) throws IOException { Scanner s = null; double sum = 0; try { s = new Scanner(new BufferedReader(new FileReader("D:/java-projects/HelloWorld/bin/usnumbers.txt"))); s.useLocale(Locale.US); while (s.hasNext()) { if (s.hasNextDouble()) { sum += s.nextDouble(); } else { s.next(); } } } finally { s.close(); } System.out.println(sum); } } As you can see, I am using absolute path to the file I am reading from: s = new Scanner(new BufferedReader(new FileReader("D:/java-projects/HelloWorld/bin/usnumbers.txt"))); The problem arises when I try to use the relative path: s = new Scanner(new BufferedReader(new FileReader("usnumbers.txt"))); I get an error: Exception in thread "main" java.lang.NullPointerException at ScanSum.main(ScanSum.java:24) The file usnumbers.txt is in the same directory as the ScanSum.class file: D:/java-projects/HelloWorld/bin/ScanSum.class D:/java-projects/HelloWorld/bin/usnumbers.txt How could I solve this?

    Read the article

  • How to determine the path of the current web site

    - by Velika2
    I wanted to create a function which would return the path of the current web site. This is what I thought was working while running in the IDE: Public Shared Function WebsiteAbsoluteBaseUrl() As String Dim RequestObject As System.Web.HttpRequest = HttpContext.Current.Request Return "http://" & RequestObject.Url.Host & ":" & _ RequestObject.Url.Port & "/" & _ RequestObject.Url.Segments(1) End Function Does this seem like it should work? Is there a more straight forward way?

    Read the article

  • Why is my .htaccess file redirecting to full server path instead of relative path?

    - by death.au
    I've never had a problem with cakePHP before, but something's odd about this server and is causing the redirects in the .htaccess files to behave oddly. CakePHP uses mod_rewrite in .htaccess files to redirect requests to its own webroot folder. The problem is that the redirects are listing the wrong path and causing a 404 error. My CakePHP application, which is stored in the listings directory, has a .htaccess file as follows: <IfModule mod_rewrite.c> RewriteEngine on RewriteRule ^$ app/webroot/ [R=301,L] RewriteRule (.*) app/webroot/$1 [R=301,L] </IfModule> (*note that the R=301 causes an external redirect so we can see what is going on from our end. It should really omit this flag and do the redirect internally, transparent to end-users) This is supposed to redirect any request from http://hostname.com/~username/listings/ to http://hostname.com/~username/listings/app/webroot/ However, rather than simply adding “app/webroot/” to the end as it is supposed to, it is adding the full server path ( /home/username/public_html/listings/app/webroot/ ) resulting in the final URL http://hostname.com/home/username/public_html/listings/app/webroot/ which is obviously incorrect and triggers a 404 error. The hosting is on a shared hosting account, so that limits what I can do with the settings. I've never seen this happen before, and I'm thinking it's something wrong from the hosting side of things, but if anyone has some helpful suggestions then I can put them to the hosting company as well.

    Read the article

  • finally and return

    - by abson
    In the below example, class ex8 { public void show() { try { int a=10/0; return;} catch(ArithmeticException e) { System.out.println(e); return ;} finally { System.out.println("Finally"); } } public static void main(String[] args) { new ex8().show(); } } the output is: java.lang.ArithmeticException: / by zero Finally How is it that Finally gets printed in spite of return statement in catch?

    Read the article

  • Rewrite SQL Fulltext Function to return Table only

    - by Alex
    I have a MS SQL Fulltext Function like this: (...) RETURNS TABLE AS RETURN SELECT * FROM fishes INNER JOIN CONTAINSTABLE(fishes, *, @keywords, @limit) AS KEY_TBL ON fishes.id = KEY_TBL.[KEY] When I use this function in LINQ, it generates a special return type which includes all fields of my "fishes" table, plus Key and Rank. How could I rewrite above query, or change something in LINQ, to omit Key and Rank and just return my "fishes" results (and to have the fulltext search result objects be of type Fish, which is what I really care about, so I don't have to cast)?

    Read the article

  • Puzzle: Overload a C++ function according to the return value

    - by Motti
    We all know that you can overload a function according to the parameters: int mul(int i, int j) { return i*j; } std::string mul(char c, int n) { return std::string(n, c); } Can you overload a function according to the return value? Define a function that returns different things according to how the return value is used: int n = mul(6, 3); // n = 18 std::string s = mul(6, 3); // s = "666" // Note that both invocations take the exact same parameters (same types) You can assume the first parameter is between 0-9, no need to verify the input or have any error handling.

    Read the article

  • Return in catch block?

    - by lowlyintern
    Is is wrong to have a return statement in a catch block? What are the alternatives? i.e: public bool SomeFunction() { try { //somecode return true; } catch(Exception ex) { MessageBox.Show(ex.message); return false; } }

    Read the article

  • How to return a string literal from a function

    - by skydoor
    Hi I am always confused about return a string literal or a string from a function. I was told that there might be memory leak because you don't know when the memory will be deleted? For example, in the code below, how to implement foo() so that make the output of the code is "Hello World"? void foo ( ) // you can add parameters here. { } int main () { char *c; foo ( ); printf ("%s",c); return 0; } Also if the return type of foo() is not void, but you can return char*, what should it be.

    Read the article

< Previous Page | 53 54 55 56 57 58 59 60 61 62 63 64  | Next Page >