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  • Sql query problem

    - by LiveEn
    I have the below sql query that will update the the values from a form to the database $sql="update leads set category='$Category',type='$stype',contactName='$ContactName',email='$Email',phone='$Phone',altphone='$PhoneAlt',mobile='$Mobile',fax='$Fax',address='$Address',city='$City',country='$Country',DateEdited='$today',printed='$Printed',remarks='$Remarks' where id='$id'"; $result=mysql_query($sql) or die(mysql_error()); echo '<h1>Successfully Updated!!.</h1>'; when i submit I dont get any errors and the success message is displayed but the database isnt updated . When i echo the $sql, all the values are set properly. and when i ech the $result i get the value 1. can someone please tell me what am i doing wrong here??

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  • Django: How do I add arbitrary html attributes to input fields on a form?

    - by User
    I have an input field that is rendered with a template like so: <div class="field"> {{ form.city }} </div> Which is rendered as: <div class="field"> <input id="id_city" type="text" name="city" maxlength="100" /> </div> Now suppose I want to add an autocomplete="off" attribute to the input element that is rendered, how would I do that? Or onclick="xyz()" or class="my-special-css-class"?

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  • how to create a 2 column to seperate label and input element in a form

    - by Blankman
    My form looks like: ** <p><label>first name</label><input type=text name=fn /></p> <p><label>last name</label><input type=text name=ln /></p> </div> <div id="rightform"> <p><label>state</label><input type=text name=state /></p> <p><label>city</label><input type=text name=city /></p> </div> ** I want the layout so all the labels line up on the left (with the label text right-aligned), and the input box all lined up, floating to the left. So the form should look like: asdf-label INPUTBOX 123-label INPUTBOX yet-another-label INPUTBOX There will be another form on the right side of the above form (with the id=#rightform) Really confused how to do this properly...

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  • properly setting email subject line delivered from email form

    - by DC1
    I have a email form for my website but here is the issue: when i receive an email, the subject line in my inbox shows whatever the user inputted as subject in the form. id like to override that so that whenever an email comes in. the subject in the email header is always "an inquiry from your website". In the message body, sure i don't mind their specific subject they entered but when I receive an email, id like consistency in my inbox. this is the current code: <?php session_start(); if(isset($_POST['Submit'])) { if( $_SESSION['chapcha_code'] == $_POST['chapcha_code'] && !empty($_SESSION['chapcha_code'] ) ) { $youremail = 'xxxxxxxxx'; $fromsubject = 'An inquiry from your website'; $title = $_POST['title']; $fname = $_POST['fname']; $lname = $_POST['lname']; $mail = $_POST['mail']; $address = $_POST['address']; $city = $_POST['city']; $zip = $_POST['zip']; $country = $_POST['country']; $phone = $_POST['phone']; $subject = $_POST['subject']; $message = $_POST['message']; $headers = "From: $nome <$mail>\r\n"; $to = $youremail; $mailsubject = 'Message received from'.$fromsubject.' Contact Page'; $body = $fromsubject.' The person that contacted you is '.$fname.' '.$lname.' Address: '.$address.' '.$city.', '.$zip.', '.$country.' Phone Number: '.$phone.' E-mail: '.$mail.' Subject: '.$subject.' Message: '.$message.' |---------END MESSAGE----------|'; echo "Thank you for inquiring. We will contact you shortly.<br/>You may return to our <a href='/index.html'>Home Page</a>"; mail($to, $subject, $body, $headers); unset($_SESSION['chapcha_code']); } else { echo 'Sorry, you have provided an invalid security code'; } } else { echo "You must write a message. </br> Please visit our <a href='/contact.html'>Contact Page</a> and try again."; } ?>

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  • Lost in UTF-8 hell. (Django and Python)

    - by user140314
    I am working through the Django RSS reader project here. The RSS feed will read something like "OKLAHOMA CITY (AP) — James Harden let". The RSS feed's encoding reads encoding="UTF-8" so I believe I am passing utf-8 to markdown in the code snippet below. The em dash is where it chokes. I get the Django error of "'ascii' codec can't encode character u'\u2014' in position 109: ordinal not in range(128)" which is an UnicodeEncodeError. In the variables being passed I see "OKLAHOMA CITY (AP) \u2014 James Harden". The code line that is not working is: content = content.encode(parsed_feed.encoding, "xmlcharrefreplace") I am using markdown 2.0, django 1.1, and python 2.4. What is the magic sequence of encoding and decoding that I need to do to make this work? Thanks.

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  • jqGrid editForm problem

    - by PaulStanek
    Hi, I have simply jqgrid definitions like this: jQuery("#C2").jqGrid({ url: '/Customers.mvc/GetGridData/', datatype: 'json', autowidth: 'true', mtype: 'GET', colNames: ['Nazwa', 'Symbol', 'Status', 'Miasto', 'Ulica', 'Budynek', 'Mieszkanie', 'Koda pocztowy', 'Domena', ' '], colModel: [ { name: 'Name', index: 'Name', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Symbol', index: 'Symbol', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Status', index: 'Status', align: 'left', editable: 'true', edittype: 'text' }, { name: 'City', index: 'City', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Street', index: 'Street', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Building', index: 'Building', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Flat', index: 'Flat', align: 'left', editable: 'true', edittype: 'text'}, { name: 'PostalCode', index: 'PostalCode', align: 'left', editable: 'true', edittype: 'text' }, { name: 'Domain', index: 'Domain', align: 'left', editable: 'true', edittype: 'text'}, { name: 'ExtId', index: 'ExtId', align: 'left', editable: 'true', edittype: 'text'}, ], pager: jQuery('#C2_p'), rowNum: 30, rowList: [20, 30, 50], sortname: 'Name', sortorder: 'Asc', viewrecords: 'true', width: '80%', height: '100%', editurl: '/Customers.mvc/SaveCustomer/', postData: { gridId: 'Customers' }, caption: 'Klienci2' }).navGrid('#C2_p', { edit: true, add: true, del: true, search: false, refresh: false }, {},//Options for the Edit Dialog {},//Options for the Add Dialog {}//Options for D ); }); And when i call edit/add form it's appears without text edit inputs. I'm using jquery 1.3.2 and jqgrid 3.6.4 Any help will be appreciated.

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  • populating a list from another worksheet with 1 criteria

    - by Arcadian
    Hello, here is my dilemma. I have two worksheets one that has the name of clients and one that i want to copy the names to depending on the city. For instance: associated to each column is last name, first name and city. i have hundreds of names associated to different cities and what i would like is from worksheet1.xls to copy all the New York clients to worksheet2.xls either when i open worksheet2 or via macro what ever is easier and because last name is in one cell and the first name is in the other i would have to copy both. I saw that its possible to link cells from one worksheet to another and then do a vlookup depending on the criteria. Is that the best easiest way or is there another? thanks in advance and cheers oleg

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  • How do you attract programmers in rural areas?

    - by Reed Copsey
    I run a software development group for a very small, but stable and established company in a small town, somewhat outside of the "big city". Unfortunately, the "programmer" labor pool is much smaller due to the size of the city. There are many positives to working in this area, especially in terms of quality of life (particularly for people interested in outdoor activities), lower cost of living, great schools and neighborhoods, etc. However, I've always had difficulty attracting high-qualtiy, experienced developers. For those of you who hire developers outside of large cities: Where do you advertise to find good developers? Many of the large sites are very focused in certain metropolitan areas, and seem inappropriate places to advertise if you're outside of that main region. How do you attract quality developers to rural (or at least less metropolitan) locations? Do you find that you make more sacrifices in your hiring due to a smaller labor pool? Or do you just wait, and take extra time to attract people? What sacrifices do you expect to make if you are outside of the main developer-rich cities? For all of the developers out there... What would entice you to working in a smaller town? Are there things that would stand out and make you willing to relocate or at least apply to a position that was not nearby? What specific qualities would help you want to move outside of the city? In the past, I've had difficulty with finding good people. Most of the people who've applied and been willing to move out to a more rural location seem like the types that can't keep a quality job elsewhere. I'd like to know what advice people have to attracting quality technical staff. I don't believe its the work itself that's been the problem - The work is both interesting and challenging, and nearly 100% new development. The developers I have seem very happy with their situation - they love the work, the atmosphere, etc. It's more a matter of finding willing, able developers. Edit: More info after the first couple of answers: Right now, some of my best developers telecommute (some work from overseas); however, for this question, I'm trying to figure out how to get people who want to live and work full time locally. I need some people with whom I interact every day.

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  • C# LINQ XML Query with duplicate element names that have attributes

    - by ncain187
    <Party id="Party_1"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>John Doe</FullName> <GovtID>123456789</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <ResidenceState tc="35">New Jersey</ResidenceState> <Person> <FirstName>Frank</FirstName> <MiddleName>Roberts</MiddleName> <LastName>Madison</LastName> <Prefix>Dr.</Prefix> <Suffix>III</Suffix> <Gender tc="1">Male</Gender> <BirthDate>1974-01-01</BirthDate> <Age>35</Age> <Citizenship tc="1">United States of America</Citizenship> </Person> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <Line2></Line2> <Line3></Line3> <Line4></Line4> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> </Party> <!-- *********************** --> <!-- Insured Information --> <!-- *********************** --> <Party id="Party_2"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>Dollie Robert Madison</FullName> <GovtID>123956239</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <Person> <FirstName>Dollie</FirstName> <MiddleName>R</MiddleName> <LastName>Madison</LastName> <Suffix>III</Suffix> <Gender tc="2">Female</Gender> <BirthDate>1996-10-12</BirthDate> <Citizenship tc="1">United States of America</Citizenship> </Person> <!-- Insured Address --> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> <Risk> <!-- Disability Begin Effective Date --> <DisabilityEffectiveStartDate>2006-01-01</DisabilityEffectiveStartDate> <!-- Disability End Effective Date --> <DisabilityEffectiveStopDate>2008-01-01</DisabilityEffectiveStopDate> </Risk> </Party> <!-- ******************************* --> <!-- Company Information --> <!-- ****************************** --> <Party id="Party_3"> <PartyTypeCode tc="2">Organization</PartyTypeCode> <Organization> <DTCCMemberCode>1234</DTCCMemberCode> </Organization> <Carrier> <CarrierCode>105</CarrierCode> </Carrier> </Party> Here is my code which doesn't work because party 3 doesn't contain FullName, I know that partyelements contains 3 parties if I only return the name attribute. Is there a way to loop through each tag seperate? var partyElements = from party in xmlDoc.Descendants("Party") select new { Name = party.Attribute("id").Value, PartyTypeCode = party.Element("PartyTypeCode").Value, FullName = party.Element("FullName").Value, GovtID = party.Element("GovtID").Value, };

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  • database for streets world wide?

    - by fayer
    i use the downloadable geonames database for all countries, states, counties and cities in the world. but i wonder if there is a database for streets? so you could pick: country - state/department/district - (county/region) - city - street in whatever country you like? cause when i do a search for a street in google map i can see all the upper levels (country/region/city). is there a database you could download for mysql for this? there has to be a database for this, cause there are always national companies that provide this kind of information. where did they get it from? thanks in advance!

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  • [change] Vlookup onto another workbook

    - by Arcadian
    Hello, here is my dilemma. I have two worksheets one that has the name of clients and one that i want to copy the names to depending on the city. For instance: associated to each column is last name, first name and city. i have hundreds of names associated to different cities and what i would like is from worksheet1.xls to copy all the New York clients to worksheet2.xls either when i open worksheet2 or via macro what ever is easier and because last name is in one cell and the first name is in the other i would have to copy both. I saw that its possible to link cells from one worksheet to another and then do a vlookup depending on the criteria. Is that the best easiest way or is there another? thanks in advance and cheers oleg

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  • Convert json to a string using jquery

    - by becomingGuru
    I have a nested json. I want to post it as a form input value. But, seems like jquery puts "Object object" string into the value. It seems easier to pass around the string and convert into the native form I need, than dealing with json as I don't need to change anything once it is generated. What is the simplest way to convert a json var json = { "firstName": "John", "lastName": "Smith", "age": 25, "address": { "streetAddress": "21 2nd Street", "city": "New York", "state": "NY", "postalCode": "10021" }, "phoneNumber": [ { "type": "home", "number": "212 555-1234" }, { "type": "fax", "number": "646 555-4567" } ], "newSubscription": false, "companyName": null }; into its string form? var json = '{ "firstName": "John", "lastName": "Smith", "age": 25, "address": { "streetAddress": "21 2nd Street", "city": "New York", "state": "NY", "postalCode": "10021" }, "phoneNumber": [ { "type": "home", "number": "212 555-1234" }, { "type": "fax", "number": "646 555-4567" } ], "newSubscription": false, "companyName": null }' Following doesn't do what I need: Json.stringify()

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  • SQL: How to join a view with a table?

    - by gamerzfuse
    CREATE VIEW qtyorderedview AS SELECT titleditors.title_id, titleditors.ed_id, salesdetails.title_id, salesdetails.qty_shipped FROM titleditors, salesdetails WHERE titleditors.title_id = salesdetails.title_id I am using the above SQL statement to create a view. I need to show Editors First Name, Last Name, City where they shipped more than 50 books. The three tables I have are: create table editors ( ed_id char(11), ed_lname varchar(20), ed_fname varchar(20), ed_pos varchar(12), phone varchar(10), address varchar(30), city varchar(20), state char(2), zip char(5), ed_boss char(11)); create table titleditors ( ed_id char(11), title_id char(6), ed_ord integer); create table salesdetails ( sonum integer, qty_ordered integer, qty_shipped integer, title_id char(6), date_shipped date); Can anyone tell me what the second Join code would be to create this result? My first view works fine, but I don't know how to join it to the second table to achieve this result? I didn't make the tables, I just have to work with what I was given. Thanks in advance!

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  • rails accessing value from facebooker hash/array

    - by Ben
    This is my first time using the facebooker plugin with rails, and I'm having trouble accessing user info. The website uses FB connect to authenticate users. I am trying to get the name of the university that the logged in user attends. When I use the command <%= facebook_session.user.education_history[:name] %>, I get an error "Symbol as array index". I have also tried using education_history[1], but that just returns "# Facebooker::EducationInfo:<some sort of alphanumeric hash value>" When I use something like <%= facebook_session.user.relationship_status %> , it returns the relationship status just fine. Similarly, <%= facebook_session.user.hometown_location.city %> returns the city name just fine. I've checked out the documentation for facebooker, but I can't figure out the correct way to get the values I need. Any idea on how to get this to work? Thanks!

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  • sqlite select query round of double value

    - by Scorpion
    I have stored location in my sqlite database. CREATE TABLE city ( latitude NUMERIC, longitude NUMERIC ) Below are the value :- latitude = 41.0776605;//actual value in db - NUMERIC stored as DB longitude = -74.170086;//actual value in db - NUMERIC stored as DB final String query = "SELECT * FROM city"; cursor = myDataBase.rawQuery(query, null); if (null != cursor) { while (cursor.moveToNext()) { Log.i(TAG, "Latitude == " + cursor.getDouble(cursor.getColumnIndex("latitude"))); Log.i(TAG, "Longitude == " + cursor.getDouble(cursor.getColumnIndex("longitude"))); } } Result :- Latitude = 40.4127 Longitude = -74.25252 I don't want round off this values. Is there any way to solve this problem.

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  • Why doesn't this Perl array sort work?

    - by Luke
    Why won't the array sort? CODE my @data = ('PJ RER Apts to Share|PROVIDENCE', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Condo|WEST WARWICK', 'PJ RER Condo|WARWICK'); foreach my $line (@data) { $count = @data; chomp($line); @fields = split(/\|/,$line); if ($fields[0] eq "PJ RER Apts to Share"){ @city = "\u\L$fields[1]"; @city_sort = sort (@city); print "@city_sort","\n"; } } print "$count","\n"; OUTPUT Providence Johnston Johnston Johnston 6

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  • Should we put <input> inside <label>?

    - by metal-gear-solid
    I saw 2 example: on http://www.alistapart.com/articles/prettyaccessibleforms/ why they are using 2 method in first fieldset they are keeping input after labeland in 2nd fieldset they are keeping input after label. Why? <fieldset> <legend>Delivery Details</legend> <ol> <li> <label for="name">Name<em>*</em></label> <input id="name" /> </li> <li> <label for="address1">Address<em>*</em></label> <input id="address1" /> </li> <li> <label for="address2">Address 2</label> <input id="address2" /> </li> <li> <label for="town-city">Town/City</label> <input id="town-city" /> </li> <li> <label for="county">County<em>*</em></label> <input id="county" /> </li> <li> <label for="postcode">Postcode<em>*</em></label> <input id="postcode" /> </li> <li> <fieldset> <legend>Is this address also your invoice » address?<em>*</em></legend> <label><input type="radio" » name="invoice-address" /> Yes</label> <label><input type="radio" » name="invoice-address" /> No</label> </fieldset> </li> </ol> </fieldset> why they are sometime keeping input after label and sometime inside?

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  • SQL Join a View with a Table

    - by gamerzfuse
    CREATE VIEW qtyorderedview AS SELECT titleditors.title_id, titleditors.ed_id, salesdetails.title_id, salesdetails.qty_shipped FROM titleditors, salesdetails WHERE titleditors.title_id = salesdetails.title_id I am using the above SQL statement to create a view. I need to show Editors First Name, Last Name, City where they shipped more than 50 books. The three tables I have are: create table editors ( ed_id char(11), ed_lname varchar(20), ed_fname varchar(20), ed_pos varchar(12), phone varchar(10), address varchar(30), city varchar(20), state char(2), zip char(5), ed_boss char(11)); create table titleditors ( ed_id char(11), title_id char(6), ed_ord integer); create table salesdetails ( sonum integer, qty_ordered integer, qty_shipped integer, title_id char(6), date_shipped date); Can anyone tell me what the second Join code would be to create this result? My first view works fine, but I don't know how to join it to the second table to achieve this result? I didn't make the tables, I just have to work with what I was given. Thanks in advance!

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  • Searches (and general querying) with HBase and/or Cassandra (best practices?)

    - by alexeypro
    I have User model object with quite few fields (properties, if you wish) in it. Say "firstname", "lastname", "city" and "year-of-birth". Each user also gets "unique id". I want to be able to search by them. How do I do that properly? How to do that at all? My understanding (will work for pretty much any key-value storage -- first goes key, then value) u:123456789 = serialized_json_object ("u" as a simple prefix for user's keys, 123456789 is "unique id"). Now, thinking that I want to be able to search by firstname and lastname, I can save in: f:Steve = u:384734807,u:2398248764,u:23276263 f:Alex = u:12324355,u:121324334 so key is "f" - which is prefix for firstnames, and "Steve" is actual firstname. For "u:Steve" we save as value all user id's who are "Steve's". That makes every search very-very easy. Querying by few fields (properties) -- say by firstname (i.e. "Steve") and lastname (i.e. "l:Anything") is still easy - first get list of user ids from "f:Steve", then list from "l:Anything", find crossing user ids, an here you go. Problems (and there are quite a few): Saving, updating, deleting user is a pain. It has to be atomic and consistent operation. Also, if we have size of value limited to some value - then we are in (potential) trouble. And really not of an answer here. Only zipping the list of user ids? Not too cool, though. What id we want to add new field to search by. Eventually. Say by "city". We certainly can do the same way "c:Los Angeles" = ..., "c:Chicago" = ..., but if we didn't foresee all those "search choices" from the very beginning, then we will have to be able to create some night job or something to go by all existing User records and update those "c:CITY" for them... Quite a big job! Problems with locking. User "u:123" updates his name "Alex", and user "u:456" updates his name "Alex". They both have to update "f:Alex" with their id's. That means either we get into overwriting problem, or one update will wait for another (and imaging if there are many of them?!). What's the best way of doing that? Keeping in mind that I want to search by many fields? P.S. Please, the question is about HBase/Cassandra/NoSQL/Key-Value storages. Please please - no advices to use MySQL and "read about" SELECTs; and worry about scaling problems "later". There is a reason why I asked MY question exactly the way I did. :-)

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  • mysql partitioning

    - by Yang
    just want to verify that database partition is implemented only at the database level, when we query a partitioned table, we still do our normal query, nothing special with our queries, the optimization is performed automatically when parsing the query, is that correct? e.g. we have a table called 'address' with a column called 'country_code' and 'city'. so if i want to get all the addresses in New York, US, normally i wound do something like this: select * from address where country_code = 'US' and city = 'New York' if now the table is partitioned by 'country_code', and i know that now the query will only be executed on the partition which contains country_code = US. My question is do I need to explicitly specify the partition to query in my sql statement? or i still use the previous statement and the db server will optimize it automatically? Thanks in advance!

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  • Visual Studio ReportViewer repeating data block on every page

    - by muhan
    I am using Reportviewer to generate a sales invoice to be printed by the user. How can I get databound fields to be printed on every page of a multi page invoice? The invoice is printed on a pre-printed form. I want the printed form to look roughly like: page 1 customer john smith 123 main st. city, CA 90000 some item1 $100 some item2 $150 some item3 $150 page 2 customer john smith 123 main st. city, CA 90000 some item4 $500 some item5 $250 some item6 $950 Total $2100 Using 1 list which contains databound textbox fields for the customer info, and a table for the items. The problem is if there are many items such that the items flow over to page 2, the next page only contains items, and not the customer info which needs to be printed on second page as well. I tried using page header, but I can't use databound items in page header. Please Help!

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  • mysqli insert problem

    - by Simon
    Hello i have this error: Warning: mysqli_stmt::bind_param() [mysqli-stmt.bind-param]: Number of elements in type definition string doesn't match number of bind variables in E:\wamp\www\classes\UserLogin.php on line 31 and i dont know what it is :/ here is my code function createUser($username, $password) { $mysql = connect(); if($stmt = $mysql->prepare('INSERT INTO users (username, password, alder, hood, fornavn, efternavn, city, ip, level, email) VALUES (?,?,?,?,?,?,?,?,?,?)')) { $stmt->bind_param($username,$password, $alder, $hood, $fornavn, $efternavn, $city, $ip, $level, $email); $stmt->execute(); $stmt->close(); } else { echo 'error: ' . $mysql->error; } then my user create the user they only need to type username and password, and later they can edit the profile and edit, email,alder,hood and like that :). Thanks for helping me

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  • Using type aliases to Java enums

    - by oxbow_lakes
    I would like to achieve something similar to how scala defines Map as both a predefined type and object. In Predef: type Map[A, +B] = collection.immutable.Map[A, B] val Map = collection.immutable.Map //object Map However, I'd like to do this using Java enums (from a shared library). So for example, I'd have some global alias: type Country = my.bespoke.enum.Country val Country = my.bespok.enum.Country //compile error: "object Country is not a value" The reason for this is that I'd like to be able to use code like: if (city.getCountry == Country.UNITED_KINGDOM) //or... if (city.getCountry == UNITED_KINGDOM) Howver, this not possible whilst importing my type alias at the same time. Note: this code would work just fine if I had not declared a predefined type and imported it! Is there some syntax I can use here to achieve this?

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  • asp.net labels and asp.net textboxes are not lining up correctly?

    - by Xaisoft
    My Registration page currently looks like the following: The current styling I have for the above is image is: <style type="text/css"> #contactinfo label { float: left; width: 10em; margin-right: 0.5em; text-align: right; font-size: 14px; } #contactinfo p { padding: 5px; } #contactinfo input[type="text"], input[type="password"] { height: 1.5em; } #contactinfo select { padding: 0.25em; } #contactinfo input[type="text"]:focus, input[type="password"]:focus { background-color: #FFFFE0; } #contactinfo .update { margin-left: 12.5em; } #contactinfo .error { background-color: transparent; } #contactinfo .longtextbox { width: 20em; } #contactinfo .shorttextbox { width: 5em; } </style> and the markup is <div id="contactinfo"> <p> <asp:Label runat="server" AssociatedControlID="txtEmail">Email </asp:Label> <asp:TextBox ID="txtEmail" runat="server" CssClass="longtextbox" /> </p> <p> <asp:Label runat="server" AssociatedControlID="txtFirstName">First Name </asp:Label> <asp:TextBox ID="txtFirstName" runat="server" ValidationGroup="AccountValidation" /> <asp:RequiredFieldValidator runat="server" ControlToValidate="txtFirstName" Text="First Name is required." ValidationGroup="AccountValidation" CssClass="error"> </asp:RequiredFieldValidator> </p> <p> <asp:Label runat="server" AssociatedControlID="txtLastName">Last Name </asp:Label> <asp:TextBox ID="txtLastName" runat="server" ValidationGroup="AccountValidation" /> <asp:RequiredFieldValidator runat="server" ControlToValidate="txtLastName" Text="Last Name is required." ValidationGroup="AccountValidation" CssClass="error"> </asp:RequiredFieldValidator> </p> <p> <asp:Label runat="server" AssociatedControlID="txtBusinessName">Business Name </asp:Label> <asp:TextBox ID="txtBusinessName" runat="server" CssClass="longtextbox" ValidationGroup="AccountValidation" /> <asp:RequiredFieldValidator runat="server" ControlToValidate="txtBusinessName" Text="Business Name is required." ValidationGroup="AccountValidation" CssClass="error"> </asp:RequiredFieldValidator> </p> <p> <asp:Label runat="server" AssociatedControlID="txtPhone">Phone </asp:Label> <asp:TextBox ID="txtPhone" runat="server" ValidationGroup="AccountValidation" /> </p> <p> <asp:Label runat="server" AssociatedControlID="txtAddress">Address </asp:Label> <asp:TextBox ID="txtAddress" runat="server" CssClass="longtextbox" ValidationGroup="AccountValidation" /> <asp:RequiredFieldValidator runat="server" ControlToValidate="txtAddress" Text="Address is required." ValidationGroup="AccountValidation" CssClass="error"></asp:RequiredFieldValidator> </p> <p> <asp:Label runat="server" AssociatedControlID="txtCity">City </asp:Label><asp:TextBox ID="txtCity" runat="server" ValidationGroup="AccountValidation" /> <asp:RequiredFieldValidator ID="RequiredFieldValidator4" runat="server" ControlToValidate="txtCity" Text="City is required." ValidationGroup="AccountValidation" CssClass="error"> </asp:RequiredFieldValidator> </p> <p> <asp:Label runat="server" AssociatedControlID="ddlState">State </asp:Label> <asp:DropDownList ID="ddlState" runat="server" DataSourceID="dsStates" DataTextField="Name" DataValueField="Id"> </asp:DropDownList> </p> <p> <asp:Label runat="server" AssociatedControlID="txtZipcode">Zipcode</asp:Label> <asp:TextBox ID="txtZipCode" runat="server" CssClass="shorttextbox" ValidationGroup="AccountValidation" /> </p> </div> As you can see from above, I have every label field pair wrapped in a p tag so it breaks to the next line, but I am not sure if I need to do this. I want to get city, state, and zip all on the same line, but as soon as I move all the labels and inputs for city,state,zip into one p tag, it looks like the following and I don't know how to fix it.

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  • Why wont this perl array sort work?

    - by Luke
    Why wont the array sort? CODE my @data = ('PJ RER Apts to Share|PROVIDENCE', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Condo|WEST WARWICK', 'PJ RER Condo|WARWICK'); foreach my $line (@data) { $count = @data; chomp($line); @fields = split(/\|/,$line); if ($fields[0] eq "PJ RER Apts to Share"){ @city = "\u\L$fields[1]"; @city_sort = sort (@city); print "@city_sort","\n"; } } print "$count","\n"; OUTPUT Providence Johnston Johnston Johnston 6

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